What is 1.186 written in expanded notation?

Answer:

if the first and fourth are swapped, then the teacher graphed x, -y vs x,y

Step-by-step explanation:

Answer:

The value of 2 in 2000 is 10 times greater than the value of 2 in 200

Step-by-step explanation:

from the value of 2 in 200 to reach 2000, it takes 10 times as much because we're moving only one place (which is the thousand's digit).

Answer:

[tex]x+y=19500,\:0.08x+0.15y=2400\quad :\quad x=7500,\:y=12000[/tex]

Step-by-step explanation:

x + y = 19500

.08x + .15y = 2400

Answer:

10%

Step-by-step explanation:

495-450=45

45x100/450=10

Answer:

Profit made by reselling = 495 - 450 = ₹45

So, percentage =

[tex] \frac{45}{450} \times 100 = 10\%[/tex]

So, gain percentage is 10%

twenty four and nineteen twentieths

Answer:

I do not understand this question

Answer:

the last one

Step-by-step explanation:

because it is the right answer

and it answer is 100000

and it is very easy

Answer:

reflection

Step-by-step explanation:

a.reflection

Answer:

is the answer

Step-by-step explanation:

Answer:

Let the required number be x

The quotient of a number and -7, decreased by 2, is 10

According to the above problem, we get

[tex] \frac{x}{( -7)} - 2 = 10 \\ \frac{x}{( - 7)} = 10 + 2 \\ \frac{x}{( - 7)} = 12 \\ x = ( - 7) \times 12 \\ \boxed{x = - 84}[/tex]

Therefore, the required number is -84.

--------------------

Step-by-step explanation:

Answer:

I am almost positive that the answer is 64 miles in one hour.

Step-by-step explanation:

In an hour the truck driver will cover the distance of 64 miles.

Speed is defined as the ratio of the time distance traveled by the body to the time taken by the body to cover the distance. The speed is a scalar quantity and does not require direction to represent it.

Given that a truck driver drove 48 miles in 45 minutes. The distance covered by the truck in an hour will be calculated as below:-

45 minutes ⇒ 48 miles

1 minute ⇒ 48 / 45

60 minute ⇒ ( 48 x 60 ) / 45

1 hour ⇒ 64 miles

Therefore, in an hour the truck driver will cover the distance of 64 miles.

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Answer:

(FoG) -1 (x) = x/5 + 26/5

Step-by-step explanation:

Answer:-14

Step-by-step explanation:

/A/= (3 x-1)- (1 x 11)

= -3 -11= -14

answer:

a. -14

explanation: 3dg3

First, let's declare some variables.

x = # of sticker packs

y = total # of stickers

Now, let's create an equation to model the problem.

y = 21x + 8

Let's plug in 50 for y and solve for x.

50 = 21x + 8

Subtract 8 from both sides.

42 = 21x

Divide both sides by 21

2 = x

Anthony will have to buy 2 sticker packs to have a total of 50 stickers.

Answer:

2 packs.

Step-by-step explanation:

Each sticker pack is 21 stickers and you would want to get 50 in total.

Since he already has 8 stickers, the initial value is 8.

So, 50-8 is 42. That means Anthony would need 42 more stickers to reach 50.

At this point, you can do division [tex]\frac{42}{21}[/tex] and that would give you 2.

You can check your work by working backwards and seeing that 2(21)=42.

42+8=50.

Answer:

g will be shifted down 5 units and right 1 unit on the x- y plane

Answer:r+(2r+7)

Step-by-step explanation:

Answer:

Step-by-step explanation:

ten students are chosen from a statistics class of 300 let x be the number who got an a in the class

Parameterize S by

[tex]\vec r(s, t) = (1-s)(1-t)\,\vec\imath + 6s(1-t)\,\vec\jmath + 6t\,\vec k[/tex]

with 0 ≤ s ≤ 1 and 0 ≤ t ≤ 1.

Take the normal vector to S to be

[tex]\vec n = \dfrac{\partial\vec r}{\partial s}\times\dfrac{\partial\vec r}{\partial t} = (36-36t)\,\vec\imath+(6-6t)\,\vec\jmath+(6-6t)\,\vec k[/tex]

with magnitude

[tex]\|\vec n\| = 6\sqrt{38}(1-t)[/tex]

Then the surface integral is

[tex]\displaystyle \iint_S xy\,\mathrm dS = 6\sqrt{38} \int_0^1\int_0^1 (1-t)\,\mathrm dt\,\mathrm ds = \boxed{3\sqrt{\frac{19}2}}[/tex]

Answer:

6-2×n=22

2×n=22

Since it is multiplication we have to take opposite side which is Division

So We divide both sides with 2

2÷2×n=22÷2

n=11

Answer:

Required expression would be:

For different values of n we get:

Lets find f(n) formula

[tex]\boxed{\sf f(n)=\dfrac{1680}{n}}[/tex]

Now

[tex]\\ \sf\longmapsto f(10)=\dfrac{1680}{10}=168[/tex]

[tex]\\ \sf\longmapsto f(12)=\dfrac{1680}{12}=140[/tex]

[tex]\\ \sf\longmapsto f(16)=\dfrac{1680}{16}=105[/tex]

[tex]\\ \sf\longmapsto f(14)=\dfrac{1680}{14}=120[/tex]

Answer:

101. NVM

Step-by-step explanation:

23 X 101= 2323

Echoing a two-digit number to make it a four-digit number is equivalent to multiplying the two-digit number by 101.

Echoing a number means repeating the digits of that number to create a new number with a different number of digits. For instance, echoing a one-digit number once turns it into a two-digit number, and echoing a two-digit number once turns it into a four-digit number. In this explanation, we'll explore the relationship between echoing and multiplication to better understand this concept.

Let's consider a one-digit number, say "n." Echoing "n" once will result in a two-digit number "nn." We can express this as:

n → nn

To understand the relationship between echoing and multiplication, let's see what happens when we echo "n" twice:

nn → nnnn

Notice that "nn" is repeated twice to create a four-digit number. We can represent this as:

n → nn → nnnn

To find the relationship between echoing a two-digit number and multiplication, let's take a two-digit number "ab" (where "a" represents the tens digit and "b" represents the ones digit). Echoing "ab" once will give us the four-digit number "abab":

ab → abab

Now, let's echo "ab" again:

abab → abababab

Observe that "ab" is repeated three more times to form an eight-digit number. We can represent this as:

ab → abab → abababab

To generalize this pattern, we can say that echoing a two-digit number "ab" once turns it into a four-digit number "abab," echoing it twice turns it into an eight-digit number "abababab," and so on.

Now, let's examine the relationship between the number of digits in the echoed number and the number of times we echoed it:

- Echoing once: 2 digits

- Echoing twice: 4 digits

- Echoing three times: 8 digits

Notice that the number of digits in the echoed number doubles every time we echo the two-digit number.

Now, consider the powers of 10. Multiplying a number by 10 moves the decimal point one place to the right, while multiplying by 100 moves the decimal point two places to the right.

To make a two-digit number into a four-digit number, we need to multiply it by a value that moves the digits two places to the right. And this value is 100, which is equal to 10².

So, echoing a two-digit number to make it a four-digit number is equivalent to multiplying the two-digit number by 100.

To summarize: ab → abab (echoing once, equivalent to multiplying by 10²)

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