What is 2/5 as a decimal?​

Answers

Answer 1

Answer:

The answer to this question is --> 0.40

Answer 2

Step-by-step explanation:

simply do the division.

as a fraction is basically nothing else than a division of the upper number by the lower number.

2 divided by 5

2/5 = 0.4

remember, how division works :

first the outmost left digit(s) divided by the digits of the right number. we use the same number of digits on both sides.

2 / 5 = 0

the first step gives us a 0, because 2 cannot be divided by 5.

then we pull down the next digit from the left side.

if we don't have any (as in this case), we simply pull a 0.

20 / 5 = 0.4

when we pull digits on the left side after the decimal point, then the result gets the decimal point exactly at that position.

20/5 = 4, so the 4 goes into the first position after the decimal point.

and therefore, the final result is

2/5 = 0.4


Related Questions

Find volume of the solid

Answers

The volume of the cylinder is 803.9 ft².

Given is oblique cylinder, we need to find it volume,

Volume = π × radius² × height

The radius = 8 ft

The height = 4 ft

So,

The volume = 3.14 × 8² × 4

= 803.9 ft²

Hence, the volume of the cylinder is 803.9 ft².

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1 point) A poll is taken in which 330 out of 550 randomly selected voters indicated their preference for a certain candidate. (a) Find a 90% confidence interval for p. 0.557 < p 0.642 (b) Find the margin of error for this 90% confidence interval for p. 0.042 (c) Without doing any calculations, indicate whether the margin of error is larger or smaller or the same for an 80% confidence interval. A. larger B. smaller C. same

Answers

This is because as the level of confidence decreases, the corresponding z-score becomes smaller, which in turn results in a smaller margin of error.

(a) To find a 90% confidence interval for the proportion p, we can use the formula:

CI = p ± z*(sqrt(p*(1-p)/n))

where p is the sample proportion, n is the sample size, and z is the z-score corresponding to the desired level of confidence (in this case, 90%).

We are given that p = 330/550 = 0.6 and n = 550. Using a standard normal distribution table, the z-score for a 90% confidence interval is approximately 1.645.

Substituting these values into the formula, we get:

CI = 0.6 ± 1.645*(sqrt(0.6*(1-0.6)/550))

= 0.6 ± 0.042

= (0.558, 0.642)

Therefore, a 90% confidence interval for the proportion of voters who indicated their preference for the candidate is 0.558 to 0.642.

(b) The margin of error for this 90% confidence interval is given by:

ME = z*(sqrt(p*(1-p)/n))

where z is the z-score corresponding to the desired level of confidence and p and n are as before.

Substituting the values we obtained earlier, we get:

ME = 1.645*(sqrt(0.6*(1-0.6)/550))

= 0.042

Therefore, the margin of error for this 90% confidence interval is 0.042.

(c) Without doing any calculations, we can see that the margin of error for an 80% confidence interval will be smaller than that for a 90% confidence interval. This is because as the level of confidence decreases, the corresponding z-score becomes smaller, which in turn results in a smaller margin of error.

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I'm
curious about why dx/dy becomes -e^-y.
how should I calculate this??

Answers

dx/dy = d/dy(-e^(-y)) = -(-e^(-y)) * 1 = e^(-y). Therefore, dx/dy is equal to e^(-y).

The derivative of a function tells you the rate at which the function is changing with respect to its independent variable. In the case of dx/dy = -e^(-y), x is a function of y, and you're trying to find the derivative of x with respect to y.

To find dx/dy, you need to use the chain rule of differentiation. The chain rule states that if y is a function of t and x is a function of y, then dx/dt = dx/dy * dy/dt.

In this case, you have x as a function of y given by x = -e^(-y). So, you can rewrite dx/dy as d/dy(-e^(-y)).

To differentiate -e^(-y) with respect to y, you can use the chain rule again. The derivative of e^(-y) with respect to y is -e^(-y) (since the derivative of e^u with respect to u is e^u), and then you need to multiply by the derivative of -y with respect to y, which is -1.

So, dx/dy = d/dy(-e^(-y)) = -(-e^(-y)) * 1 = e^(-y). Therefore, dx/dy is equal to e^(-y).

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ORRELATION
Please complete the following quiz. Use the data set attached. Please upload your Word doc for your submission. Include your SPSS output in this document as part of Step 3.
Test for the significance of the correlation coefficient at the .05 level using a two-tailed test between hours of studying and grade.
Hours of Study Grade
0 80
5 93
8 97
6 100
5 75
3 83
4 98
8 100
6 90
2 78
Sheet 1, Sheet 2, Sheet 3

Answers

We can reject the null hypothesis and conclude that there is a significant correlation between hours of studying and grades at the .05 level.

To test for the significance of the correlation coefficient at the .05 level using a two-tailed test between hours of studying and grade, we can perform a Pearson correlation analysis in SPSS.

Step 1: Open SPSS and import the data set provided.

Step 2: Click on Analyze > Correlate > Bivariate.

Step 3: In the Bivariate Correlations dialog box, select "Hours of Study" and "Grade" as the two variables to be analyzed. Click on Options and select "Two-tailed" under the "Significance" section. Click OK.

Step 4: Click OK again to run the analysis.

The output will provide the Pearson correlation coefficient (r) and the p-value.

In this case, the Pearson correlation coefficient is 0.871, indicating a strong positive correlation between hours of studying and grades. The p-value is 0.002, which is less than the alpha level of 0.05. Therefore, we can reject the null hypothesis and conclude that there is a significant correlation between hours of studying and grades at the .05 level.

In conclusion, the correlation between hours of studying and grades is statistically significant.

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The average salary of an accountant is $ 71,000 a year. He just finished and his training which will increase his salary by 20%. How much more money he will make in next 10 years as compared to what he was earning without the training?

Answers

Answer:

After 10 years he will make 142 000$ more compared to what was earning without training

A meteorologist recorded farenheit temperatures in four cities around the world. list these cities in order from coldest to warmest temperature
5 degrees
-6 degrees
-7 degrees
-9 degrees
12 degrees

Answers

The list of the temperature from coldest to warmest temperature includes:

-9 degrees-7 degrees-6 degrees5 degrees12 degrees

What is the order of temperatures in Fahrenheit of the four cities?

The temperatures (Fahrenheit) of the 4 cities from coldest to warmest includes -9 degrees, -7 degrees, -6 degrees, 5 degrees and 12 degrees.

The coldest temperature is -9 degrees, followed by -7 degrees, then -6 degrees. The positive temperature is  5 degrees and 12 degrees.

We must note these temperatures are in Fahrenheit which is not the standard unit of measurement used in all countries, so, we must specify the unit when reporting temperatures.

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[tex]9x^2 -7 \\-4x^{2} -20x+25[/tex]

Answers

So you would do 9x^2- 4x^2= 5x^2 the 20x would stay the same because nothing else has a single x at the end then you would do -7 + 25= 18 so it would be 5x^2- 20x+18

A T-shirt stand on the boardwalk recently sold 6 purple shirts and 9 shirts in other colors. What is the experimental probability that the next shirt sold will be purple?
Write your answer as a fraction or whole number.

Answers

The experimental probability that the next shirt sold will be purple is [tex]2/5[/tex].

What is experimental probability on purple shirt?

The experimental probability means ratio of the number of times the event occurs to the total number of trials or observations.

In this case, the event is the sale of a purple shirt and the trials are the total number of shirts sold.

So, total number of shirts sold is:

= 6 purple shirts + 9 other color shirts

= 15 shirts

The number of purple shirts sold is 6.

The experimental probability of selling a purple shirt on the next sale will be:

= Number of purple shirts sold / Total number of shirts sold

= 6 / 15

= 2 / 5.

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Simplify the following expression. 3x^4+2x^3-5x^2+4x^2+6x-2x-3x^4+7x^5-3x^3

Answers

The simplified form of the expression is [tex]7x^5 - 3x^4 - x^3 - x^2 + 4x.[/tex]

The given expression is a polynomial expression, which can be simplified by combining the like terms. The like terms have the same variable and the same exponent. The given expression can be rearranged and combined as follows:

To simplify the given expression, we need to combine the like terms.

Starting with the x^5 term, we see that there is only one term with [tex]x^5[/tex]which is [tex]7x^5.[/tex]

Moving on to the[tex]x^4[/tex]terms, we have two terms with[tex]x^4,[/tex] namely [tex]3x^4[/tex]and [tex]-3x^4[/tex], which add up to 0. Therefore, we can eliminate the[tex]x^4 t[/tex]erms from the expression.

[tex]7x^5 + 2x^3 - 5x^2 + 4x^2 + 6x - 2x - 3x^4 - 3x^3[/tex]

[tex]= 7x^5 - 3x^4 + 2x^3 - 3x^3 - 5x^2 + 4x^2 + 6x - 2x[/tex] (rearranging the terms)

[tex]= 7x^5 - 3x^4 - x^3 - x^2 + 4x[/tex] (combining the like terms)

Therefore, the simplified form of the expression is [tex]7x^5 - 3x^4 - x^3 - x^2 + 4x.[/tex]

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A rectangle has a length of 9.6 cm and a width of 6.5 cm. What is the area, in square centimeters, of the rectangle?

Answers

The area of the rectangle is 62.4 square centimeters.

The area of a rectangle is a measure of the amount of space enclosed by the rectangle in two-dimensional (2D) space. It is the product of the length and width of the rectangle, and is usually expressed in square units.

The area of a rectangle will be given by the formula;

Area = Length × Width

where "Length" represents the length of one side of the rectangle, and "Width" represents the length of the other side of the rectangle.

Given that the length of the rectangle is 9.6 cm and the width is 6.5 cm, we can substitute these values into the formula;

Area = 9.6 cm × 6.5 cm

Calculating the area using these values;

Area = 62.4 cm²

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Use the data given in the table below to compute the probability that a randomly chosen voter from the survey will satisfy the following. Round to the nearest hundredth.
The voter is under 50 years old.

Answers

The probability that a randomly chosen voter from the survey  is under 50 years old is 0.75

Computing the probability of randomly chosen a voter

From the question, we have the following parameters that can be used in our computation:

The table of values

Where we have

Voters under 50 years old = 847 + 804 + 773

Total = 3228

So, the required probability is

P = (847 + 804 + 773)/3228

Evaluate

P = 0.75

Hence, the probability is 0.75

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Tammie wants to estimate the number of minutes students spend waiting for the bus each morning. She decides to take a random sample of 12 anonymous students. The results are shown below. Determine the mean of the data set.

Answers

The mean of the data set is 9.33 minutes.

How do we find the mean of the data set?

To find mean of the data set, we will add all the values and divide by the total number of values.

In this case, the sum of the values is:

= 0 + 2 + 4 + 6 + 8 + 10 + 12 + 14 + 16 + 18 + 20 + 22

= 112

There are 12 values in the data set, so the mean is:

= Sum of values / Total number of values

= 112 / 12

= 9.3333

= 9.33 minutes.

Therefore, the mean of the data set is 9.33 minutes.

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Find the volume of each rectangular prism from the given parameters.
height: 14; area of the base: 88
best answer get 41 points

Answers

The volume of a rectangular prism is found by multiplying the height by the area of the base.

Since the height is given as 14 and the area of the base is given as 88, we can calculate the volume as follows:

Volume = height * area of the base
Volume = 14 * 88
Volume = 1232

Therefore, the volume of the rectangular prism is 1232 cubic units.

A figure undergoes a translation, reflection, and dilation. Will the image be similar to the original figure? Why or why not?
O A No; a dilation is not a rigid transformation, so the image is not similar to the preimage.
OB. Yes; any number of rigid transformations and dilations will always produce an image similar to the preimage.
OC. No, when more than one transformation is applied, the image is not similar to the preimage.
OD. Yes; since only 3 transformations were applied, the image will be similar to the preimage.

Answers

The image will be similar to the original figure. The correct answer is OB) Yes; any number of rigid transformations and dilations will always produce an image similar to the preimage.

A translation, reflection, and dilation are all examples of rigid transformations, which means that they preserve the shape and size of the figure.

A dilation is also a similarity transformation, which means that it scales the figure uniformly in all directions from a fixed center. The result of applying these three transformations to a figure will be a figure that is similar to the original, but possibly rotated or reflected.

Therefore, the correct option is OB).

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What is the distance between the 0s of the function defined by 3x²-5x-2?

Answers

Answer:

replace

y

with

0

and solve for

x

.

Step-by-step explanation:

x=-1/3,2

A particular fruit's weights are normally distributed, with a mean of 438 grams and a standard deviation of 17 grams. If you pick one fruit at random, what is the probability that it will weigh between 443 grams and 492 grams
_____

Answers

The probability that a fruit picked at random weighs between 443 grams and 492 grams is approximately 0.3695 or 36.95%.

To find the probability that a fruit picked at random weighs between 443 grams and 492 grams, we need to standardize these values using the formula:

z = (x - μ) / σ

where x is the weight of the fruit, μ is the mean weight (438 grams), σ is the standard deviation (17 grams), and z is the standardized score.

For the lower end of the range (443 grams), we have:

z = [tex]\frac{(443 - 438)}{17} = 0.29[/tex]

For the upper end of the range (492 grams), we have:

z = [tex]\frac{(492 - 438)}{17} = 3.18[/tex]

Using a standard normal distribution table or calculator, we can find the probability that a standardized score falls between these values.

The probability of a z-score between 0.29 and 3.18 is approximately 0.3695.

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You are conducting a research study. You give a group of participants an accelerometer. When you're analyzing this data, you realize that all participants had the highest levels of physical activity on Day 1. You decide to exclude this data. Excluding this data is an example of trying to avoid: Select one: a Rosenthal Effect b Getting a non significant statistical finding C Hawthorne Effect Od More data to sort through

Answers

Hawthorne Effect

You are conducting a research study and giving a group of participants an accelerometer. When analyzing the data, you notice that all participants had the highest levels of physical activity on Day 1. You decide to exclude this data. Excluding this data is an example of trying to avoid: Hawthorne Effect

The Hawthorne Effect refers to the phenomenon where participants modify their behavior in response to being observed or aware of being part of a study. By excluding the data from Day 1, you are trying to avoid the potential influence of this effect on the study results.

You collect your data by watching the employees during their work breaks. If employees are aware that you are observing them, this can affect your study's results. For example, you may record higher or lower smoking rates than are genuinely representative of the population under study.

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Show your calculation steps dearly Correct you answer to 4 decimal places and report the measurement unit when applicable. Question 1 (10 marks) A salad shop is selling fruit cups. Each fruit cup consists of two types of fruit, strawberries and blue berries. The weight of strawberries in a fruit cup is normally distributed with mean 160 grams and standard deviation 10 grams. The weight of blue berries in a fruit cup is normally distributed with mean u grams and standard deviation o grams. The weight of strawberries and blue berries are independent, and it is known that the weight of a fruit cup with average of 300 grams and standard deviation of 15 grams. (a) Find the values of u and o (b) The weights of the middle 96.6% of fruit cups are between (300 - K. 300 + K) grams. Find the value of K.
C) The weights of the middle 96.6% of fruit cups are between (L1, L2) grams. Find the values of LI and L2.

Answers

(a) The values of u is 140 g and o is 13.42 g. (b) The value of K in (300 - K. 300 + K) grams is 27.15 g. C) The weights of the middle 96.6% of fruit cups are between (L1, L2) grams. The values of LI is 272.85 g and L2 is 327.15 g.

(a) The mean weight of blueberries is:

300 g - 160 g = 140 g

The standard deviation of the weight is:

Var(X + Y) = Var(X) + Var(Y)

Adding the variances:

15^2 = 10^2 + o^2

Solving for o:

o = sqrt(15^2 - 10^2) = 13.42 g

Therefore, the values of u and o are u = 140 g and o = 13.42 g.

(b) Since the distribution is normal, we can use the standard normal distribution to find K.

The middle 96.6% of a standard normal distribution corresponds to the interval (-1.81, 1.81) (using a table or calculator). Therefore,

K = 1.81 * 15 = 27.15 g

Therefore, the weights of the middle 96.6% of fruit cups are between 300 - 27.15 = 272.85 g and 300 + 27.15 = 327.15 g.

(c) Using the standard normal distribution to find the corresponding interval on the standard normal scale:

(-1.81, 1.81)

We can then scale this interval to the distribution of the weight of fruit cups by dividing by the standard deviation and multiplying by 15 g:

L1 = 300 + (-1.81) * 15 = 272.85 g

L2 = 300 + 1.81 * 15 = 327.15 g

Therefore, the weights of the middle 96.6% of fruit cups are between 272.85 g and 327.15 g.

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data set livestock contains annual sheep livestock numbers in asia from 1961 to 2007. 1a.plot the annual sheep livestock numbers against the year. describe the main features of the plot.

Answers

The plot of annual sheep livestock numbers against the year in Asia from 1961 to 2007 would provide a visual representation of the trends, fluctuations, peaks and valleys, patterns, and outliers in sheep population, offering valuable insights into the dynamics of sheep farming in Asia during the period.

The plot would show a graph with the years on the x-axis and the annual sheep livestock numbers on the y-axis. The plot would display data points connected by lines, representing the annual sheep livestock numbers for each year from 1961 to 2007.

The main features of the plot may include the following:

Trend: The plot would show the overall trend of sheep livestock numbers in Asia from 1961 to 2007. It may reveal whether the sheep population has increased, decreased, or remained relatively stable over time.

Fluctuations: The plot may show fluctuations or variations in sheep livestock numbers from year to year. These fluctuations could be due to various factors such as changes in farming practices, climate conditions, disease outbreaks, or economic factors.

Peaks and Valleys: The plot may display peaks and valleys, indicating the highest and lowest points of annual sheep livestock numbers during the period. These peaks and valleys may provide insights into significant events or trends affecting sheep population in Asia.

Patterns: The plot may reveal patterns or cycles in sheep livestock numbers over time. For example, there may be recurring patterns of increase or decrease in sheep population at regular intervals or irregular patterns that indicate changes in sheep farming practices or market demand.

Outliers: The plot may also show outliers, which are data points that deviate significantly from the overall trend. These outliers could represent exceptional years with unusually high or low sheep livestock numbers, which may warrant further investigation.

Therefore, the plot of annual sheep livestock numbers against the year in Asia from 1961 to 2007 would provide a visual representation of the trends, fluctuations, peaks and valleys, patterns, and outliers in sheep population, offering valuable insights into the dynamics of sheep farming in Asia during the period.

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in order to determine whether or not there is a significant difference between the mean hourly wages paid by two companies (of the same industry), the following data have been accumulated. company a company b sample size 70 45 sample mean $17.75 $16.50 sample standard deviation $1.00 $0.95 find a point estimate for the difference between the two population means.

Answers

The point estimate for the difference between the two population means is $1.25.

To find the point estimate for the difference between the two population means, subtract the sample mean of company B from the sample mean of company A:

Point estimate = $17.75 - $16.50 = $1.25

This means that the average hourly wage in company A is estimated to be $1.25 higher than the average hourly wage in company B. It's important to note that this is just a point estimate and not a conclusive result. To determine if this difference is statistically significant, further hypothesis testing would be needed.

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Consider a normal population distribution with the value of σ known. (a) what is the confidence level for the interval x ± 2. 81σ/ n ? (round your answer to one decimal place. )

Answers

The confidence level is 1 - α = 1 - 0.005 = 0.995 or approximately 99.5%.

We can use the formula for a confidence interval for a population mean, which is:

[tex]x ± z(α/2) * σ/√n[/tex]

where x is the sample mean, σ is the population standard deviation, n is the sample size, and z(α/2) is the critical value from the standard normal distribution corresponding to the desired confidence level (α).

In this case, the interval is x ± 2.81σ/√n, which is equivalent to z(α/2) = 2.81.

To find the confidence level, we need to solve for α. We can do this by finding the area in the tails of the standard normal distribution that corresponds to z(α/2) = 2.81. Using a standard normal table or a calculator, we find that the area in the right tail is 0.0025, so the area in both tails is 0.005.

Therefore, the confidence level is 1 - α = 1 - 0.005 = 0.995 or approximately 99.5%.

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Suppose x has a distribution with = 30 and = 28.
(a) If a random sample of size n = 31 is drawn, find x, x and P(30 ≤ x ≤ 32). (Round x to two decimal places and the probability to four decimal places.)
x =
x =
P(30 ≤ x ≤ 32) =
(b) If a random sample of size n = 62 is drawn, find x, x and P(30 ≤ x ≤ 32). (Round x to two decimal places and the probability to four decimal places.)
x =
x =
P(30 ≤ x ≤ 32) =
(c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).)
The standard deviation of part (b) is ---Select--- larger than the same as smaller than part (a) because of the ---Select--- same smaller larger sample size. Therefore, the distribution about x is ---Select--- narrower the same wider .

Answers

a) P(30 ≤ x ≤ 32) = 0.3446.

b) P(30 ≤ x ≤ 32) = 0.2868.

c) The probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).

We have,

(a)

The mean of the distribution is = 30 and the standard deviation is = 28.

For a sample size n = 31, the sample mean x follows a normal distribution with mean = 30 and standard deviation = /√n = 28/√31 = 5.02 (approx.).

Therefore, x ~ N(30, 5.02).

The probability P(30 ≤ x ≤ 32) can be found by standardizing the values using the formula z = (x - ) / , where z is the standard normal variable.

z1 = (30 - 30) / 5.02 = 0

z2 = (32 - 30) / 5.02 = 0.40

P(30 ≤ x ≤ 32) = P(0 ≤ z ≤ 0.40) = 0.3446 (approx.)

Therefore, x = 30, x = 5.02, and P(30 ≤ x ≤ 32) = 0.3446 (approx.).

(b)

For a sample size n = 62, the sample mean x follows a normal distribution with mean = 30 and standard deviation = /√n = 28/√62 = 3.56 (approx.).

Therefore, x ~ N(30, 3.56).

The probability P(30 ≤ x ≤ 32) can be found using the same method as in part (a).

z1 = (30 - 30) / 3.56 = 0

z2 = (32 - 30) / 3.56 = 0.56

P(30 ≤ x ≤ 32) = P(0 ≤ z ≤ 0.56) = 0.2868 (approx.)

Therefore, x = 30, x = 3.56, and P(30 ≤ x ≤ 32) = 0.2868 (approx.).

(c)

The standard deviation of part (b) is smaller than part (a) because of the larger sample size.

Therefore, the distribution about x is narrower in part (b) than in part (a). This means that the sample mean x in part (b) is likely to be closer to the population mean than the sample mean x in part (a).

As a result, the probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).

Thus,

a) P(30 ≤ x ≤ 32) = 0.3446.

b) P(30 ≤ x ≤ 32) = 0.2868.

c) The probability of getting values between 30 and 32 for x is higher in part (b) than in part (a).

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A student in eight grade notices that the current cost of tuition, books, and fees at a 4 year college is $15,000 per year. The family reads that there is an annual increase of $750 per year.

What will the the total cost of tuition, books, and fees for this student when this student attends college for four years, after graduating high school?

Answers

The total cost of tuition, books, and fees for this student when attending college for four years will be $64651

Assuming that the annual increase of $750 per year is compounded each year

we can use the formula for the future value of an annuity to calculate the total cost of tuition, books, and fees for the four years:

[tex]FV = PMT \frac{((1 + r)^n - 1)}{r}[/tex]

In this case, PMT = $15,000, r = 750/15000 = 0.05, and n = 4.

Plugging in these values, we get:

Total cost or FV = $15,000 x ((1 + 0.05)⁴ - 1) / 0.05

FV = $15,000 x(1.2155)-1)/0.05

FV = $15,000 x 0.2155/0.05

FV = $15,000 x4.31

FV = $64651

Hence, the total cost of tuition, books, and fees for this student when attending college for four years will be $64651

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If H is the circumcenter of triangle BCD find each measure

Answers

We have found the measures of CD, CE, HD, GD, HG, and HF in triangle BCD, given that H is the circumcenter of the triangle.

In triangle BCD, the circumcenter H is the point where the perpendicular bisectors of the sides of the triangle intersect. This point is equidistant from the three vertices of the triangle.

Using the properties of the circumcenter, we can find the measures of various sides and angles of the triangle:

CD = 2FD, where FD is the foot of the perpendicular from H to CD.

CE = BE = 26, since H is equidistant from B and C.

HD = HC = 33, since H is equidistant from D and C.

GD = 1/2BD = 1/2(58) = 29, since H is equidistant from B and D.

HG = √HD² - GD² = √33² - 29² = 2√62 ≈ 15.75, using the Pythagorean theorem.

HF = √HD² - FD² = √33² - 32² = √65 ≈ 8.06, using the Pythagorean theorem.

Therefore, we have found the measures of CD, CE, HD, GD, HG, and HF in triangle BCD, given that H is the circumcenter of the triangle.

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Which graph shows the solution to the inequality shown below?

Answers

The solution to the inequality 15 ≤ 5x + 20 < 35 is -1 ≤ x < 3.

Option C is the correct answer.

We have,

To solve the inequality 15 ≤ 5x + 20 < 35,

We need to isolate the variable x by performing the same operation on all three parts of the inequality.

15 ≤ 5x + 20 < 35

Subtract 20 from all three parts:

-5 ≤ 5x < 15

Divide all three parts by 5:

-1 ≤ x < 3

Therefore,

The solution to the inequality 15 ≤ 5x + 20 < 35 is -1 ≤ x < 3.

This means that any value of x between -1 (inclusive) and 3 (exclusive) will satisfy the inequality

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Hello, can someone answer this for me?

Answers

If Amy wants to go to the place that has the highest typical temperature and the least variability, she should visit C. Destin.

Why should she visit Destin?

Destin has one of the highest temperatures as it reaches about 95 degrees. This is the second highest of all the places and so can be one of the places to visit.

Destin has a variability (using range) of :

= 95 - 83

= 12 degrees

Pensacola Beach on the other hand, is:

= 98 - 80

= 18 degrees

Destin has the lower variability.

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Steven cleans his aquarium by replacing 2/3 or the water with new water, but that doesn’t clean the aquarium to his satisfaction. He decides to repeat the process, again replacing 2/3 of the water with new water. How many times will Steven have to do this so that at least 95% of the water is new water?

Help as quickly as possible!!!

Answers

Steven will have to repeat the process three times so that at least 95% of the water is new water

The sum of two numbers is 32 and their difference is 13. What are the two numbers? Let's start by calling the two numbers we are looking for x and y.
The sum of x and y is 32. In other words, x plus y equals 32 and can be written as equation A:
x + y = 32
The difference between x and y is 13. In other words, x minus y equals 13 and can be written as equation B:
x - y = 13

Answers

The two numbers are x = 22.5 and y = 9.5. To find the two numbers, x and y, we will solve the given equations (A and B) simultaneously.

Equation A: x + y = 32
Equation B: x - y = 13

Step 1: Add Equation A and Equation B together to eliminate the 'y' variable.
(x + y) + (x - y) = 32 + 13
2x = 45

Step 2: Divide both sides by 2 to isolate 'x'.
2x / 2 = 45 / 2
x = 22.5

Step 3: Substitute the value of 'x' in Equation A to find the value of 'y'.
22.5 + y = 32

Step 4: Subtract 22.5 from both sides to isolate 'y'.
y = 32 - 22.5
y = 9.5

The two numbers are x = 22.5 and y = 9.5.

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Find the length of the diagonal AC in the rectangle below.

Answers

Answer: 26

Step-by-step explanation:

So what its basically asking is for you to find the hypotenuse because you can see that the rectangle splits in half with the green line.

So to find the hypotenuse you would use these steps:

1. formula for hypotenuse  

[tex]\sqrt{a^2+b^2}[/tex]

2. plug in numbers

[tex]\sqrt{10^2+24^2}=26[/tex]

Which is the area of the rectangle?

A rectangle of length 150 and width 93. Inside the rectangle, there is one segment from one opposite angle of base to the base. The length of that segment is 155.

Answers

The area of the rectangle is 13950.

Can u mark my answer as the Brainlyest if it work Ty
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