Answer:
[tex]28m-35=7\mleft(4m-5\mright)[/tex]Explanation:
Given the expression:
28m - 35
To write this in factored form, note that
[tex]\begin{gathered} 28=7\times4 \\ \text{and} \\ 35=7\times5 \end{gathered}[/tex]So
[tex]28m-35=(7\times4m)-(7\times5)[/tex]Because 7 is common to both 28m and 35, we factor out 7, to have
[tex]7\mleft(4m-5\mright)[/tex]PLEASE HELP ME!!!
How would I find the perimeter of this shape?
Explain your process and all steps
required.
Answer:
6x+8
Step-by-step explanation:
2 x 2x+3 = 4x+6
2 x x+1 = 2x+2
4x+6 + 2x+2 = 6x+8
Amortize Premium by Interest Method
Shunda Corporation wholesales parts to appliance manufacturers. On January 1, Year 1, Shunda Corporation issued $22,000,000 of five-year, 9% bonds at a market (effective) interest rate of 7%, receiving cash of $23,829,684. Interest is payable semiannually. Shunda Corporation’s fiscal year begins on January 1. The company uses the interest method.
a. Journalize the entries to record the following:
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1. Sale of the bonds. Round amounts to the nearest dollar. For a compound transaction, if an amount box does not require an entry, leave it blank.
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2. First semiannual interest payment, including amortization of premium. Round to the nearest dollar. For a compound transaction, if an amount box does not require an entry, leave it blank.
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3. Second semiannual interest payment, including amortization of premium. Round to the nearest dollar. For a compound transaction, if an amount box does not require an entry, leave it blank.
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b. Determine the bond interest expense for the first year. Enter amounts as positive numbers. Round amounts to the nearest dollar.
Annual interest paid $
fill in the blank 6502c1ff4fd7045_1
Premium amortized
fill in the blank 6502c1ff4fd7045_2
Interest expense for first year $
fill in the blank 6502c1ff4fd7045_3
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c. Explain why the company was able to issue the bonds for $23,829,684 rather than for the face amount of $22,000,000.
The bonds sell for more than their face amount because the market rate of interest is
the contract rate of interest. Investors
willing to pay more for bonds that pay a higher rate of interest (contract rate) than the rate they could earn on similar bonds (market rate).
The journal entries for the bonds transactions of Shunda Corporation are as follows:
Journal Entries:1. Debit Cash $23,829,684
Credit Bonds Payable $22,000,000
Credit Bonds Premium $1,829,684
2. Debit Interest Expense $834,039
Debit Bonds Premium $155,961
Credit Cash $990,000
3. Debit Interest Expense $828,580
Debit Bonds Premium $161,420
Credit Cash $990,000
b. Bond Interest Expense for the first year is as follows:
Annual interest paid = $1,980,000
Premium amortized = $317,381
Interest Expense = $1,662,619
c. The bonds sell for more than their face amount because the market rate of interest is less than the contract interest rate. Investors are willing to pay more for bonds that pay a higher rate of interest (contract rate) than the rate they could earn on similar bonds (market rate).
Transaction Analysis:Face value of bonds = $22,000,000
Bonds Proceeds = $23,829,684
Bonds Premium = $1,829,684 ($23,829,684 - $22,000,000)
Coupon interest rate = 9%
Semi-annual interest payment = $990,000 ($22,000,000 x 9% x 1/2)
Effective market interest rate = 7%
1. Cash $23,829,684 Bonds Payable $22,000,000 Bonds Premium $1,829,684
2. Interest Expense $834,039 Bonds Premium $155,961 Cash $990,000
3. Interest Expense $828,580 Bonds Premium $161,420 Cash $990,000
1st Semiannual Interest Payment:Interest Payment at 4.5% $990,000
Interest Expense = $834,039 ($23,829,684 x 3.5%)
Amortized Premium = $155,961
Bond's carrying value = $23,673,723 ($23,829,684 - $155,961)
2nd Semiannual Interest Payment:Interest Payment at 4.5% $990,000
Interest Expense = $828,580 ($23,673,723 x 3.5%)
Amortized Premium = $161,420
Bond's carrying value = $23,512,303 ($23,673,723 - $161,420)
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1....
1) 3х = 27
2) 5х-2 = 25
3) (1/7)х = 49
4) 2х+8 = 1/32
5) 6х-4 = 36
6) 3х+2+3х = 90
2...
1) 2х = 32
2) 6х-3 = 36
3) (2/3)х = 1,5
4) 52х-1 = 0,2
5) 9х-1 = 81
6) 2х+1+2х = 96
Answer:
Step-by-step explanation:
3x=27
Consider the function:f(x) = -5x + 5Step 1 of 2: Find the value of f(-2).
Given:
[tex]f(x)=-5x+5[/tex][tex]f(-2)=-5(-2)+5[/tex][tex]f(-2)=10+5[/tex][tex]f(-2)=15[/tex][tex]f(5)=-5(5)+5[/tex][tex]f(5)=-25+5[/tex][tex]f(5)=-20[/tex]how do I find the correct answer?Use deductive reasoning to show that angle A is congruent to angle E.
We know that O is midpoint of BF, which means OF is equal to OB by definition of midpoint.
Also, angles FOE and BOA are congruent by vertical angles theorem. Angles B and F are congruent by given, both are right angles.
We can deduct that triangles EFO and ABO are congruent by ASA postulate of congruence.
From the congruence between triangles, we deduct that angles A and E are congruent.Help please I’m kinda confused
If the original price of suitcase is $62 and sale price is 51.99 amount of
markdown is $ 10.01 and markdown % is 16.14.
Mark down = original price - sale price
= 62 -51.99
= $ 10.01
Mark down % = [tex]\frac{mark down}{original selling price} \times 100[/tex]
= [tex]\frac{ 10.01}{62} \times 100[/tex]
= 16.14%
What is markdown?markdown is the amount by which you reduce the selling price. The amount by which you reduce the price can be expressed as a percentage of the sale price, or the discount rate.
To calculate markdown percentage Divide the price difference by the actual selling price. Then multiply that result by 100. The result is a markdown percentage.
For example, suppose a broker sells XYZ stock to his clients at $20 per share. He originally bought the stock in the brokerage market at $0 per share. Therefore, the discount on the stock he sells is -$20 ($20 - $0)
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A ball is thrown in the air. Its path is modeled by the equation ℎ(t) =− 16t^2 + 56t, where h represents the height of the ball in cm and t represents time in seconds since the ball was thrown. When is the ball at its highest point? What is the highest point?
Check the picture below.
[tex]\textit{vertex of a vertical parabola, using coefficients} \\\\ h(t)=\stackrel{\stackrel{a}{\downarrow }}{-16}t^2\stackrel{\stackrel{b}{\downarrow }}{+56}t\stackrel{\stackrel{c}{\downarrow }}{+0} \qquad \qquad \left(-\cfrac{ b}{2 a}~~~~ ,~~~~ c-\cfrac{ b^2}{4 a}\right)[/tex]
[tex]\left(-\cfrac{ 56}{2(-16)}~~~~ ,~~~~ 0-\cfrac{ (56)^2}{4(-16)}\right) \implies \left( - \cfrac{ 56 }{ -32 }~~,~~0 - \cfrac{ 3136 }{ -64 } \right) \\\\\\ \left( \cfrac{7}{4}~~,~~49 \right)\implies \stackrel{seconds\qquad feet}{\left(1\frac{3}{4} ~~ ~~,~ ~~ ~49 \right)}[/tex]
Suppose that the value of a stock varies each day from $10.82 to $20.17 with a uniform distribution.Find the third quartile; 75% of all days the stock is below what value? (Enter your answer to thenearest cent.)
start by subtracting the maximum and the minimun vaue
[tex]\max -\min =9.35[/tex]now divide that into 4
[tex]\frac{9.35}{4}=2.3375[/tex]since is the third quartile mutipli that by 3
[tex]2.3375\cdot3=7.0125[/tex]round to 7.01
add that to the minimun value
10.82+7.01=17.83
use the product to sum formula to help me solve this problem in trig
Explanation
The product-to-sum formula can be seen below.
[tex]cosAsinB=\frac{1}{2}(sin(A+B)-sin(A-B))[/tex]Therefore, we can insert the values of the angles into the formula
[tex]\begin{gathered} Cos37.5sin7.5=\frac{1}{2}(sin(37.5+7.5)-sin(37.5-7.5)) \\ =\frac{1}{2}(sin45-sin30) \\ =\frac{1}{2}(\frac{\sqrt{2}}{2}-\frac{1}{2}) \\ =(\frac{\sqrt{2}}{4}-\frac{1}{4}) \\ =\frac{\sqrt{2}-1}{4} \end{gathered}[/tex]Answer:
[tex]\begin{gathered} A=2 \\ B=1 \end{gathered}[/tex](Find the sum of the infinite geometric series 3 + 12 + 48 + 192 + ...
Given the Infinite Geometric Series:
[tex]3+12+48+192+...[/tex]You can find its sum by using this formula:
[tex]S=\frac{a_1}{1-r}[/tex]Where "r" is the common ratio and the first term is:
[tex]a_1[/tex]In this case, you can identify that each term is obtained by multiplying the previous term by 4. Therefore:
[tex]r=4[/tex]You can identify that:
[tex]a_1=3[/tex]Therefore, you can substitute values into the formula and evaluate:
[tex]S=\frac{3}{1-4}[/tex][tex]\begin{gathered} S=\frac{3}{-3} \\ \\ S=-1 \end{gathered}[/tex]Hence, the answer is: Option B.
Cathan and Jakove went out to eat, and the bill for their food was $24.50. If theyleft their server a 20% tip, what was the total cost of their dining experience? *
And the cost is $29,40
What is the volume of the sphere shown below with a radius of 6?617.8--A. 2885 cu. unitsB. 1625 cu unitsC. 485 cu. unitsD. 1445 cu units
The radius of sphere is r = 6.
The formula for the volume of sphere is,
[tex]V=\frac{4}{3}\pi r^3[/tex]Substitute the value in the formula to determine the volume of sphere.
[tex]\begin{gathered} V=\frac{4}{3}\pi\cdot(6)^3 \\ =\frac{4}{3}\pi\cdot216 \\ =288\pi \end{gathered}[/tex]Answer: Option A
In the diagram below, GPK = 18x + 5 and KPH = 14x + 15. Solve for the measure of angleGPK.PH
We can say that the two triangles are identical, then, the angle GPK is equal to the angle KPH, then we write the following equation:
[tex]\begin{gathered} \angle GPK=\angle KPH \\ \\ 18x+5=14x+15 \\ \\ 4x=10 \\ \\ x=\frac{10}{4}=\frac{5}{2}=2.5 \end{gathered}[/tex]Now we know the value of x, we can return to the equation and find the value of the angle GPK
[tex]\begin{gathered} \angle GPK=18x+5 \\ \\ \operatorname{\angle}GPK=18\cdot\frac{5}{2}+5 \\ \\ \operatorname{\angle}GPK=9\cdot5+5 \\ \\ \operatorname{\angle}GPK=45+5 \\ \\ \angle GPK=50 \end{gathered}[/tex]Therefore, the measure of the angle GPK is equal to 50 degrees
POSSIBLThe midpoint of FG is M(1,0). One endpoint is F(8,-2).Find the coordinates of endpoint G.GO
The formula for determining the midpoint of a line is expressed as
(x1 + x2)/2 , (y1 + y2)/2
x1 and y1 represents the coordinates of the starting point of the line
x2 and y2 represents the coordinates of the end point of the line
The given line is FG. It means that the starting point is F and the end point is G. From the information given,
x1 = 8, y1 = - 2
x2 = ?, y2 = ?
For Midpoint coodinates, x = 1, y = 0
Therefore,
(8 + x2)
Explain how to evaluate f(2) to a student that is absent today.
Answer:
f(x) is a function. For example f(x) = 2x + 1
If you were to say evaluate f(2), you would plug in the '2' to 'x'.
So in the example I gave, f(2) = 2(2) + 1
f(2) = 4 + 1
f(2) = 5
What is the estimated probability that at least two of the puppies will befemale?A. 6/10 = 60 %B. 5/10 = 50 % C. 7/10 = 70 % D. 4/10 = 40 %
Answer:
C. 7/10 = 70 %
Explanation:
We are asked to find the total number of outcomes that give us at least 2 female puppies.
Now outcomes 1,2,4,5,7,9, and 10, which are 7 outcomes in total, give us at least two female puppies. Therefore, we can say 7 out of 10 times we get at least 2 female supplies and hence the probability is
[tex]\frac{7}{10}=70\%[/tex]Name the order pair that is solution set in the following system.
Answer:
(1, 2)
Explanation:
The solution of the system is the intersection point of the lines. In this case, the intersection point is (1, 2), so the solution set is the order pair (1, 2)
x-y=3, 2x-y=5 what’s the solution
Answer:
x = 2, y = -1
Solve the following system:
{-y + x = 3 | (equation 1)
-y + 2 x = 5 | (equation 2)
Swap equation 1 with equation 2:
{2 x - y = 5 | (equation 1)
x - y = 3 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{2 x - y = 5 | (equation 1)
0 x - y/2 = 1/2 | (equation 2)
Multiply equation 2 by 2:
{2 x - y = 5 | (equation 1)
0 x - y = 1 | (equation 2)
Multiply equation 2 by -1:
{2 x - y = 5 | (equation 1)
0 x + y = -1 | (equation 2)
Add equation 2 to equation 1:
{2 x + 0 y = 4 | (equation 1)
0 x + y = -1 | (equation 2)
Divide equation 1 by 2:
{x + 0 y = 2 | (equation 1)
0 x + y = -1 | (equation 2)
Collect results:
Answer: |
| {x = 2
y = -1
I believe that this is truly the answer.
5.(A.3A) The table represents some points on the graphof a linear function. What is the slope of thisfunction?х у-6-70-106-1312-16
The slope of a linear function can be obtained as:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]Where (x1,y1) and (x2,y2) are points of the line.
For this problem we just have to pick 2 points from the table (they don't have to be consecutive). I'll pick:
• x1 = 0
,• y1 = 4
,• x2 = 2
,• y2 = 14
And now we compute the slope:
[tex]m=\frac{14-4}{2-0}=\frac{10}{2}=5[/tex]The slope is 5 (third option)
A sound receiving dish used at outdoor sporting events is constructed in the shape of a paraboloid, with its focus 5 inches from the vertex. Determine the exact width (in inches) of the dish if the depth is to be 2 feet.
First, lets remember that a paraboloid is just a parabola that was rotated around the Y axis. So lets find the equation from our parabola that is been rotated. We know that the focus is in the point (0,5), so we can find our equation:
[tex]y=\frac{x^2}{4\times5}\rightarrow y=\frac{x^2}{20}[/tex]Just to remember, a parabola that has focus in (0,P) has equation as:
[tex]y=\frac{x^2}{4\times p}[/tex]We can draw our parabola:
So we want to find the width knowing that the depth is 2 feet our 24 inches. That means that he wants to know the X that make the Y be 24, so lets find it:
[tex]y=\frac{x^2}{20}\rightarrow x^2=24\times20\rightarrow x=\pm\sqrt[]{480}\rightarrow x^{\prime}\cong21.908\text{ and }x\~\~^{}\cong-21.908[/tex]DIRECTIONS: Use this information to answer Parts A and B.
Marisol deposits $5,000 in a savings account earning 5.75% simple interest per year.
Part A
How much interest will Marisol earn for a period of 5 years?
Part B
Marisol receives 8,450 when she close her savings account if she made no changes to the account, for how many years did Marisol keep the account open?
Answer: 287.&. Multiply 365 x 10 Great, you get 3650 . . . Multiply 287 by 3650 which then equals 1049375 . . . Wow! The interest will then be a total of 60929$ with the 8450 that she recieved that should equal 3 years total keeping it open . . .
Step-by-step explanation: Hope This Helps! Pls mark Branliest!
The system of inequalities, r+ y > 10 * + y 2 Select the region that contains solutions to the system of inequalities modeled in the graph below O Region A Solutions to the system of inequalities lie in one ofthe regions shown on the coordinate plane. O Region B Region O Region D B A С Previous
we know that
inequality 1
The solution is the shaded area above the solid line x+y=10
Inequality 2
The solution is the shaded area below the solid line -x+y=-2
therefore
the solution of the system of inequalities is the region C
BRAINLIST TO BEST ANSWER
solve these problems
Answer:
11: 4.64 m
12: 61.6 in
Step-by-step explanation:
formula for an area of a triangle is base times height divided in half and 2.9 times 3.2 is 9.28 and divided by 2 you get 4.64
formula for a trapezoid is base 1 plus base 2 in half times height and 12 plus 10 is 22 divided by 2 it is 11 and 5.6 times 11 is 61.6
Let p(x)=3x – 2 and q(x) = 2x + 5. Finda. p(x) – Q(x) =b. p(x) + q(x) =c. p(x)q(x) =
We are given the following functions;
[tex]\begin{gathered} p(x)=3x-2 \\ q(x)=2x+5 \end{gathered}[/tex]We shall find the values of the following;
[tex]p(x)-q(x)[/tex]We substitute for the values of each function and we'll have;
[tex]\begin{gathered} p(x)-q(x)=(3x-2)-(2x+5) \\ p(x)-q(x)=3x-2-2x-5_{} \end{gathered}[/tex]Take note that the negative sign in front of the parenthesis affects both values. Hence negative +5 becomes -5. We now have;
[tex]\begin{gathered} p(x)-q(x)=3x-2-2x-5 \\ p(x)-q(x)=3x-2x-5-2 \\ p(x)-q(x)=x-7 \end{gathered}[/tex](B):
[tex]p(x)+q(x)[/tex]Just like in part (a), we shall substitute for the value of each of the functions, as follows;
[tex]\begin{gathered} p(x)+q(x)=(3x-2)+(2x+5) \\ p(x)+q(x)=3x-2+2x+5 \\ p(x)+q(x)=3x+2x+5-2 \\ p(x)+q(x)=5x+3 \end{gathered}[/tex](C):
[tex]p(x)q(x)[/tex]In this case, we calculate the product of both functions, and we start by substituting for the value of each;
[tex]\begin{gathered} p(x)q(x)=(3x-2)(2x+5) \\ p(x)q(x)=3x\cdot2x+3x\cdot5-2\cdot(+2x)-2\cdot(+5) \end{gathered}[/tex]We can now simplify the above and we'll have;
[tex]\begin{gathered} p(x)q(x)=6x^2+15x-4x-10 \\ p(x)q(x)=6x^2+11x-10 \end{gathered}[/tex]ANSWER:
[tex]\begin{gathered} (a)=x-7 \\ (b)=5x+3 \\ (c)=6x^2+11x-10 \end{gathered}[/tex](sorry the picture is sideways, i couldn’t type in the problem directly hopefully this will do)
The angle can be expressed as,
[tex]\begin{gathered} \frac{13\pi}{6}=(2\pi+\frac{\pi}{6}_{}) \\ \end{gathered}[/tex]So, the angle can be drawn as,
To find the reference angle if the angles is greeter than 2π, we first subtract 2π from the angle(here 13π/6) until it is below 2π.
[tex]\frac{13\pi}{6}-2\pi=\frac{\pi}{6}[/tex]So, the reference angle is π/6.
Determine whether the value is from a discrete or continuous data set.Number of members present at a meeting is 6Is the value from A) discrete B) continuous
To answer this question we need to understand the difference between discrete and continous data:
• Discrete data can only take certain values along some interval.
,• Continuous data can take any value along some interval.
In this case we know that there will always be a integer number of people in the meeting, that is, we can only have certain values (we can't have 6.5 people in a meeting).
Therefore, this is a discrete data set.
You are in charge of purchases at the student-run used-book supply program at your college, and you must decide how many introductory calculus, history, and marketing texts should be purchased from students for resale. Due to budget limitations, you cannot purchase more than 1050 of these textbooks each semester. There are also shelf-space limitations: Calculus texts occupy 2 units of shelf space each, history books 1 unit each, and marketing texts 5 units each, and you can spare at most 1,700 units of shelf space for the texts. If the used book program makes a profit of $10 on each calculus text, $4 on each history text, and $8 on each marketing text, how many of each type of text should you purchase to maximize profit?
calculus text(s):
history text(s):
marketing text(s):
What is the maximum profit the program can make in a semester?
Using linear programming, the amounts of each book that you should purchase are given as follows:
Calculus: 850.History: 0.Marketing: 0.The maximum profit will be of $850.
How to maximize a function given it's constraints?To maximize the function, we have to find the numeric values at the intercepts of the most restrictive constraints, as the maximum value is the highest numeric value. This strategy is called linear programming.
In the context of this problem, the variables are given as follows:
Variable x: number of calculus books purchased.Variable y: number of history books purchased.Variable z: number of marketing books purchased.The used book program makes a profit of $10 on each calculus text, $4 on each history text, and $8 on each marketing text, hence the profit function is defined as follows:
P(x,y,z) = 10x + 4y + 8z.
The constraint related to budget limitations, as an equality, is given by:
x + y + z = 1050.
The most restrictive constraint is from shelf-space limitations, and is given as follows:
2x + y + 5z = 1700.
Hence the intercepts are given as follows:
(850, 0, 0) as 2x = 1700 -> x = 850.(0, 1700, 0), as y = 1700.(0, 0, 340), as 5z = 1700 -> z = 340.The numeric value of the profit function at each of these intercepts is:
P(850,0,0) = 10(850) = 8500.P(0, 1700, 0) = 4(1700) = 6800.P(0, 0, 340) = 8(340) = 2720.Hence, due to the maximum numeric value, the maximum profit will be of $850, when 850 calculus books are purchased.
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What’s the correct answer answer asap for brainlist I really need help
Answer:
A. clouds
Step-by-step explanation:
hope it helps :)
Answer to this question
Answer:
A
Y = -4|x+2|+3
Step-by-step explanation:
we can see the graph is heading downwards -> it must be negative coefficient
The graph is going up 3 -> must have a plus 3 in formula outside absolute value
the graph is going to the left 2 -> must have a plus 2 in formula inside absolute value
Erin receives a 20% employee discount at the camera store where she works. She alsoreceives a $10 off the price on Wednesdays.a. Write a function e(p) that calculates Erin's new price after the employee discount(hint: what percent of the original price does she have to pay?)ep) =B. Write a function a(p) that calculates Erin's new price using her Wednesday discountonlya (p) =C. Write the function e(a(p))e a(p)) =D. What would Erin's final price be for a $400 camera she purchases on a Wednesday?
ANSWERS
A. e(p) = 0.8p
B. a(p) = p - 10
C. e(a(p)) = 0.8p - 8
D. $312
EXPLANATION
A. The employee discount is 20%. To the total price, which is 100%, we have to subtract the 20% to find the final price of the product. If the price is p, then the price after the employee discount would be,
[tex]e(p)=(1-0.2)p=0.8p[/tex]Hence, the function is e(p) = 0.8p
B. On Wednesdays, Erin gets a $10 discount on the price p of a product in the store, so if she buys on a Wednesday, she would pay a(p) = p - 10.
C. Now we have to find the function e(a(p)). This is a composition, where we have to replace p with a(p) in function e(p),
[tex]e(a(p))=0.8a(p)=0.8(p-10)=0.8p-0.8\cdot10=0.8p-8[/tex]Hence, the function is e(a(p)) = 0.8p - 8
D. If Erin buys a $400 camera on a Wednesday she will get both discounts: the employee discount and the Wednesdays discount. To find the final price for a selling price of p = 400, we have to use the function found in part C,
[tex]e(a(400))=0.8\cdot400-8=320-8=312[/tex]Hence, the final price for the $400 camera is $312, after both discounts.
