Another way to express 11 + 77 is to using absolute values making it equal to
|-11 + -77|How to find another way to express equationThe use of equality sign introduces a number or equation which is equal and hence can be used to replace another item
solving this expression gives 11 + 77 = 88
The equation can also be replace in equation terms using absolute values
where it can be written as
|-11 + -77|
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How do you tell if a function is a power function?.
A power function is the function that is defined with equation consisting of one variable of a fixed power, where all the number and coefficients of the variables belong to real numbers.
Then, let f(x) be a function that defines the variable x;
say, f(x) = 4x³ + 5x² + 7x + 10.
For f(x) to be a power function; f(x) = xⁿ
Then f(x) is a power function with the highest power being 3 of the variable 'x'.
Linear and Quadratic equations are both power functions of power 1 and 2 respectively in the variable x.
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a sample of 400 observations will be taken from an infinite population. the population proportion equals 0.8. find the probability that the sample proportion will be greater than 0.74.
The probability is 99.87 that the sample proportion will be greater than 0.74.
Define the term Normal probability distribution?The z-score of such a measure X in a collection with mean μ and standard deviation σ is given by:z = (x - μ)/σ
The Z-score calculates the deviation of the measure from the mean in standard deviations. We examine now at z-score table after determining the Z-score to determine the p-value connected to it. The likelihood that the measure's value is less than X, or the percentile of X, is represented by this p-value. The likelihood that the value of both the measure exceeds X is calculated by deducting 1 from the pvalue.μ = E(X)
σ = √V(X)
n = 400 ; p = 0.8
Thus,
μ = E(X) = np = 400 x 0.8 = 320
σ = √V(X) = √np(1 - p) = √(400 x 0.8 x 0.2) = 8
The probability that given sample proportion would be greater than 0.74.
= 74% of the 400
= 0.74 x 400 = 296
Thus, p -value when x = 296
z = (x - μ)/σ
x = (296 - 320)/8
z = -3
p value = 0.0013
probability = 0.13
Thus, greater than 0.74.
1 - 0.0013 = 0.9987
Thus, the probability is 99.87 that the sample proportion will be greater than 0.74.
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you have weekly store-level unit sales data as well as binary promotion information about if the product was on display or not. you run a linear regression model (yunit.sales
~ xdisplay.promotion. This means that the promotion has a positive effect on unit sales, and the model can accurately predict unit sales based on whether the promotion is present or not.
What are regression models?Regression models are statistical models that are used to forecast a continuous result information based on one or more predictor variables. These models are employed to comprehend how the predictor and outcome variables relate to one another as well as to forecast the result variable. In disciplines like economics, finance, and psychology, regression models are frequently employed to forecast variables like future sales or psychological health. Regression models can be either linear or nonlinear, and they can also have numerous predictor variables. These models typically include an intercept and a slope for each predictor variable, which are used to calculate the predicted outcome.
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a triangular parcel of land has sides of lengths 590 feet, 980 feet and 1423 feet. a) what is the area of the parcel of land? area
The area of the parcel of land is 226934.799 square feet.
Given:
a triangular parcel of land has sides of lengths 590 feet, 980 feet and 1423 feet.
a).
Let a = 590 , b = 980, c = 1423 lengths
s = semi-perimeter
= 1/2(a+b+c)
= 1/2(590+980+1423)
= 1496.5
s-a = 1496.5-590
= 906.5
s-b = 1496.5-980
=516.5
s-c = 1496.5-1423
= 73.5
Heron's formula for area:
A = [tex]\sqrt{(s(s-a)(s-b)(s-c))}[/tex]
= √1496.5(906.5)(516.5)(73.5)
= √51499402997.4
≈ 226934.799
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A plant nursery is having a sale. potted begonias are marked down 27%, and tomato seedlings are marked down 35%. if you pay $6.57 each for two potted begonias and $2.60 each for three tomato seedlings, how much did you save? please select the best answer from the choices provided a b c d
The amount of money saved from the marked down prices at the plant nursery is $7.46 .
Let the cost of the potted begonias be x.
They are marked down 27%
Price at which they are sold = 0.73 x
Therefore : 0.73x = 6.57 or, x = 9
Money saved = (9 - 6.57) × 2 = $4.86
Let the cost of the tomato be x.
They are marked down 35%
Price at which they are sold = 0.65 x
Therefore : 0.65x = 2.60 or, x = 4
Money saved = (4 - 2.60) × 3 = $4.20
Total money saved = $ (4.20 + 4.86 ) = $9.06
Discounts are price cuts made by store owners on goods or services that would otherwise be sold for the indicated price. Usually, this portion of the rebate is given to increase sales or get rid of extra inventory.
The List Price or Marked Price is the cost of a product as declared by the seller or manufacturer, exclusive of any discounts. The selling price is really the final price at which an item is sold after any discounts or price drops from the list price.
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How do you determine if a graph crosses or touches the x-axis?.
Answer:The zeros of a function f correspond to the x-intercepts of its graph. If f has a zero of odd multiplicity, its graph will cross the x-axis at that x value. If f has a zero of even multiplicity, its graph will touch the x-axis at that point.
what is a perpendicular
Answer:
at an angle of 90° to a given line, plane, or surface.
"dormers and gables that extend perpendicular to the main roofline
Step-by-step explanation:
How many solutions does this linear system have Y =- 6x 2?.
The linear system of equation y =-6x+2 has infinitely many solutions.
The linear equation is y = -6x+2 .
Now for any value of x we find the value of y ,
at x=0 ,y = 2
at x=1 , y = -4
at x=-2 , y = 14
Hence there are infinitely many solutions on the line . All points on the straight line are solutions.
The collection of variable values in a linear equation that yields every feasible solution is referred to as the "solution of a linear equation." In order to model real-world issues, linear equations include unknown quantities as one or more variables.
The locations where the lines or planes used to illustrate the linear equations intersect or meet are known as the solutions. The set of values for each variable in a system of linear equations is known as the solution set.
Disclaimer: the complete question is :
How many solutions does this linear system have Y =- 6x + 2?.
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What are prime multiples of 10?.
2, 5 are prime multiples of 10 .
What is a number's prime multiple?
Prime numbers can only be divided by one and by themselves and are therefore never less than one. They can't be produced by adding the number to itself or by multiplying it by two additional whole numbers that aren't 1.What are multiples and prime factors?
A number is said to be prime if it only has the factors 1 and itself. Multiple: A number from the provided times table of numbers. Factor: A number that exactly divides another number. The smallest number that appears in the times tables of the given numbers is known as the LCM.Learn more about prime multiple
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suppose i have an orgnization that has 60 members, i'm going to pick one person at random to be the president, another person to be the vice president, and a third person to be the treasurer. how many ways can this be done
There are [tex]\frac{60!}{57!}[/tex] ways we can do it.
Since organization has 60 members from which we haveto pick one person at random to be the president, another person to be the vice president and a third person to be the transformer,
the president can be select in 60c1 = [tex]\frac{60!}{1! 59!}[/tex]
= [tex]\frac{60 *59!}{1*59!}[/tex]
= 60 ways
After this for vice president we have 59 members from which vice president can be select in 59c1 = 59 ways.
and for treasure we have 58 members from which treasure can be select in 58c1 = 58 ways.
∴ No. of ways in which we can select president, vice president and treasure = 60 × 59 × 58
= [tex]\frac{60 * 59 * 58 * 57!}{57!}[/tex]
= [tex]\frac{60!}{57!}[/tex]
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which of the following techniques is used in predictive analytics? a. optimization models b. data visualization c. data dashboards d. linear regression
Option d is correct that is linear regression. So, linear regression is used in predictive analytics.
Given that,
We have to find which of the following techniques is used in predictive analytics.
We know that,
What is predictive analytics?Predictive analytics, a subset of advanced analytics, employs historical data, statistical modeling, data mining, and machine learning to forecast future outcomes. Businesses utilize predictive analytics to find opportunities and threats by analyzing trends in this data.
We get,
The predictive analysis technique that is most frequently used is linear regression. By using linear relationships between a dependent variable and one or more independent variables, it makes predictions about the target's future.
Therefore, Option d is correct that is linear regression. So, linear regression is used in predictive analytics.
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let x be the distance from the foot of the ladder to the wall and lket y be the distance from the top of the ladder to the ground. write an equation relating to x and y
The equation which relates the x and y will be x² = 169 - y² according to the given triangle formed.
What is a triangle?A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices.
Triangle is a very common figure to deal with our daily life for example in our daily life to measure the height of any tower then there is a huge application of the right angle triangle.
As per the given,
Length of ladder = 13 foot
By Pythagoras's theorem,
x² + y² = 13²
x² = 169 - y²
Hence "The equation which relates the x and y will be x² = 169 - y² according to the given triangle formed".
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Complete data of the question follows,
inductive or deductive all numbers divisible by 6 are also divisible by 3. 36 is divisible by 6. so, 36 is divisible by 3.
Answer:
deductive
Step-by-step explanation:
two-thirds of the global population within an eight-hour flight distance and have captured a significant market share over the last few years
The findings indicate that just 11% of the world's population used air travel in 2018, with less than 4% of those trips being international. In developed nations alone, about half of the population travels by air at least once a year.
Believe it or not, less than 20% of people on the planet have ever taken a single trip. In Asia alone, 100 million individuals will take their first flight this year alone.
Keep in mind that flights more than 6 hours are considered long-range, while trips longer than 10 hours are also not unusual. In the event of unforeseen turbulence, it's crucial to always have your seat belt secured.
Flight durations during the duty periods are limited to a maximum of 8 hours for one-pilot flight crews and 10 hours for two-pilot flight crews. Any additional commercial flying that the flight crew does during the allotted 8 or 10 hours of flight time is included.
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Is it possible to have a triangle with 3cm 5cm 8cm?.
No, it is not possible to have a triangle with 3cm 5cm 8cm because the total of the triangle's two sides, 3 cm and 5 cm, is not greater than the third side, 8 cm.
Define triangle.A triangle is a polygon with three vertices and three sides. The angles of the triangle are formed by the connection of the three sides end to end at a point. The triangle's three angles add up to 180 degrees in total.
Given,
Sides 3cm, 5cm and 8 cm
Three sides are provided, measuring 3 cm, 5 cm, and 8 cm. We are aware that the third side is always greater than the sum of any two triangle sides. The triangle cannot exist because the total of the triangle's two sides, 3 cm and 5 cm, is not greater than the third side, 8 cm.
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A highly risk-averse investor is considering adding one additional stock to a 3-stock portfolio, to form a 4-stock portfolio. The three stocks currently held all have b = 1.0, and they are perfectly positively correlated with the market. Potential new Stocks A and B both have expected returns of 15%, are in equilibrium, and are equally correlated with the market, with r = 0.75. However, Stock A's standard deviation of returns is 12% versus 8% for Stock B. Which stock should this investor add to his or her portfolio, or does the choice not matter?
Either A or B, i.e., the investor should be indifferent between the two.
Stock A.
Stock B.
Neither A nor B, as neither has a return sufficient to compensate for risk.
Add A, since its beta must be lower.
As per the standard deviation, The B stock portfolio is more risk-efficient in simple words.
Standard deviation:
Basically, standard deviation means the measure of how dispersed the data is in relation to the mean.
And the low standard deviation means data are clustered around the mean, and high standard deviation indicates data are more spread out.
Given,
A highly risk-averse investor is considering adding one additional stock to a 3-stock portfolio, to form a 4-stock portfolio. The three stocks currently held all have b = 1.0, and they are perfectly positively correlated with the market. Potential new Stocks A and B both have expected returns of 15%, are in equilibrium, and are equally correlated with the market, with r = 0.75. However, Stock A's standard deviation of returns is 12% versus 8% for Stock B.
Here we need to find in which stock should this investor add to his or her portfolio, or does the choice not matter.
Here we know that either of these shares would yield the same expected return for the entire portfolio if added to the same share of the portfolio.
So, if stock B is included in the portfolio, the expected standard deviation for the portfolio will be lower, since the standalone deviation is lower.
And therefore, lower risk or volatility, or standard deviation of the portfolio for the same level of the expected return on the new portfolio.
Therefore, the ratio of Sharpe to stock B will be higher. The B stock portfolio is more risk-efficient in simple words.
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How do you write three consecutive even numbers?.
Three consecutive even integers can be written with difference of two.
The even integers are defined as the numbers that are completely divisible by two. The complete division means that the result of division will be zero. The even integers are always present after a gap of one number in between.
This means that there is a difference of two numbers between integers. Firstly of all, the first even number is two. Following it four. There is a gap of number that is three. Hence, to find the consecutive even integers, add number two to the number.
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In triangle ABC points X and Z are in AB and Y is on AC such that XY and BC are parallel and ZY and XC are parallel. If AZ=8, ZX=4, then what is XB?
If length of AZ=8 units and the length of ZX=4, then the length of the side XB is 6 units
Consider the triangle ABC
The points X and Y are on the line AB and Y is on the line AC
The lines XY and BC are parallel
Therefore
AX / XB = AY / YC
Similarly, the lines ZY and XC are parallel
AZ / ZX = AY / YC
Therefore the the proportion will be
AX / XB = AZ / ZX
The length of the line AX = AZ + ZX
= 8 + 4
= 12 units
Then the proportion will be
12 / XB = 8 / 4
Cross multiply the terms
12 × 4 = 8 × XB
XB = (12 × 4) / 8
XB = 48 / 8
XB = 6 units
Hence, the length of the side XB is 6 units
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Does an X or y-axis scale have to always start at zero?.
No, X or y-axis scale does not have to always start at zero. In a line chart, it's OK to start the axis at a number other than zero
Define axis.A line that is used to take or mark measurements is known as an axis in mathematics. Two crucial axes of the coordinate plane are the x and y axes. A horizontal number line is the x-axis, while a vertical number line is the y-axis. The coordinate plane is created by the perpendicular intersection of these two axes.
Given,
No, X or y-axis scale does not have to always start at zero.
A line chart encodes data using location (x, y coordinates), whereas a bar chart represents data using length. In a line chart, it's OK to start the axis at a number other than zero despite many claims that they are always misleading since this minute difference influences how a reader utilizes the chart.
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jalen has columbian coffee worth $3 per pound that he wishes to mix with 30 pounds of brazilian coffee worth $8 per pound to get a mixture/blend that he would sell for $4 per pound. how many pounds of the cheaper coffee should he use?
120 pounds of the cheaper coffee should be use to get a mixture/blend that he would sell for $4 per pound.
How to solve an equation?An equation is an expression that can be used to show the relationship between variables and numbers.
Let x represent the amount of cheaper coffee.
Jalen has columbian coffee worth $3 per pound that he wishes to mix with 30 pounds of brazilian coffee worth $8 per pound to get a mixture/blend that he would sell for $4 per pound.
Hence:
3x + 8(30) = 4(x + 30)
3x + 240 = 4x + 120
x = 120
120 pounds of the cheaper coffee should be use
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case sales price per unit variable costs per unit total fixed costs break-even in units 1 $20 $16 $40,000 2 25 5 5,000 3 30 81,000 9,000 4 4 48,000 8,000
Case 1: Break-even units are 10000
Case 2: Fixed cost is $1,00,000
Case 3: Variable cost is $20
Case 4: The sale price is $15
Break-even in units = Fixed cost/Selling price - Variable cost
Case 1:
Sales price = $20
Variable cost = $16
Fixed cost = $40,000
Break-even point = 40000/20-16
= 10000 units
Case 2:
Sales price = $25
Variable cost = $5
Break-even units = 5000
Finding fixed cost:
5000 = Fixed cost/25-5
Fixed cost = 5000* 20
= 1,00,000
Case 3:
Sales price = $29
Fixed cost = 81000
Break-even units = 9000
Finding variable cost:
9000 = 81000/29-variable cost
2,61,000 - 9000*Variable cost = 81000
Variable cost = 20
Case 4:
Variable cost = $9
Fixed cost = $48000
Break-even units = 8000
Finding sales price:
8000 = 48000/Sales price - 9
8000*Sales price - 72000 = 48000
Sale price = $15
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find the 3x3 matrix that corresponds to the composite transformation of a scaling by 2, a rotation of 90o about the origin
The 3x3 matrix after composite transformation of scaling by 2, a rotation of 90° about origin is [tex]\left[\begin{array}{ccc}2c&2d&2i\\2b&2e&2h\\2a&2d&2g\end{array}\right][/tex].
Let A=[tex]\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right][/tex] be a 3x3 matrix
scaling the matrix A by 2 then the result will be
[tex]2A=2\left[\begin{array}{ccc}a&b&c\\d&e&f\\g&h&i\end{array}\right]\\\\=\left[\begin{array}{ccc}2a&2b&2c\\2d&2e&2f\\2g&2h&2i\end{array}\right][/tex]
now, rotating the resultant matrix by 90° in counterclockwise direction about the origin, we get
[tex]=\left[\begin{array}{ccc}2c&2d&2i\\2b&2e&2h\\2a&2d&2g\end{array}\right][/tex]
Thus, a 3x3 matrix after composite transformation of scaling by 2, a rotation of 90° about origin is [tex]\left[\begin{array}{ccc}2c&2d&2i\\2b&2e&2h\\2a&2d&2g\end{array}\right][/tex]
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The um of firt 11 term of an A. P i 19 and the um of firt 19 term i 11. Find the um of the firt 30 term
The sum of the first 30 terms of this arithmetic expression (A.P) will be -30.
Let the first term of the Arithmetic progression be a
And the common difference of this progression be d
An be the nth term of the progression
Sn be the sum of the first nth term of the progression
As we know,
Sn = n/2( 2a + (n-1)d)
S11 = 11/2(2a + (11-1)d)
S11 = 11/2(2a + 10d) = 11(a + 5d)
As S11 = 19
Therefore, 19 = 11(a + 5d)
19 = 11a + 55d………….(i)
Again, S19 = 11 = 19/2 ( 2a + 18d )
11 =19( a + 9d)
11 = 19a + 171d………(ii)
Now, multiplying equation (i) by 19 and (ii) by 11 and then subtracting them, we get
361 = 209a + 1045d
121 = 209a + 1881d
240 = -836d
d = -240/836 = -60/209
Putting the value of d in equation (i), we get
11a - 55x60/209 = 19
11a = 3300/209 + 19
11a = 7271/209
a = 661/209
Therefore sum of first 30 terms are S30 = 30/2(2(661/209)+29(-60/209))
S30 = 15(1322/209 -1740/209) = 15 (-418/209) = 15(-2) = -30
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Where is the outlier in a data set?.
Answer:
It is data outside what you would expect.
Step-by-step explanation:
An example would be if I asked everyone is a class how many dogs they dad living with them. I would expect to get answers like 0, 1, 2, 3 or 4. If someone answered 115 that would be be an outlier, it is outside all of the data that I have collected.
A random sample of 49 statistics examinations was taken. The average score, in the sample, was 84 with a variance of 12.25. The 95% confidence interval for the average examination score of the population of the examinations is
76.00 to 84.00
77.40 to 86.60
83.00 to 85.00
68.00 to 100.00
The 95% confidence interval for the average examination score of the population of the examinations is (82.99, 85.01).
We have given that,
Sample mean{[tex]\overline x[/tex]} = 84
Sample standard deviation(S) =3.5
Sample size(n) =49
Level of significance=1-0.95=0.05
Degree of freedom =48
t critical value is (by using t table)(t)= 2.011
Confidence interval formula is
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}[/tex]
Now putting the value
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}=84\pm 2.011\times\frac{3.5}{\sqrt{49}}[/tex]
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}[/tex] = 84 ± 2.011 × 3.5/7
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}[/tex] = 84 ± 2.011 ×0.5
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}[/tex] = 84 ± 1.01
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}[/tex] = (84-1.01, 84+1.01)
[tex]\overline{x}\pm t\times\frac{S}{\sqrt{n}}[/tex] = (82.99, 85.01)
Lower confidence limit= 82.99
Upper confidence limit=85.01
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You are shopping for a new computer monitor. It is regularly priced at $200 but it is now on sale for 25% off. After the sale discount is applied, you can also use your 20% off coupon. What is the final price?.
After calculating the individual discount and coupon percentages of the actual price, we find out that the final price of the new computer monitor is $40.
It is given to us that -
The new computer monitor is regularly priced at $200
It is now on sale for 25% off
After the sale discount, we can also use 20% off coupon
We have to find out the final price of the computer monitor.
The initial price of the new computer monitor = $200
After the sale discount of 25% off is applied to the product, the new price of the monitor can be calculated by finding out
25% of $200 = 0.25 * 200 = $50
Now, after calculating the price of the monitor after the sales discount, we have to find out the final price after the 20% off coupon is applied.
So, 20% of $50 = 0.20 * 50 = $10
So, we can conclude that after the sales discount and after a coupon of $10 off is applied, the final price of the computer monitor is -
$50 - $10
= $40
Thus, calculating the individual discount and coupon percentages of the actual price, we find out that the final price of the new computer monitor is $40.
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1. robin works as a server in a small restaurant, where she can earn a tip (extra money) from each customer she serves. the histogram below shows the distribution of her 60 tip amounts for one day of work.
The histogram below shows the distribution of her 60 tip amounts for one day of work.
a) The tips distribution is severely skewed to the right and unimodal. There is a large spread and high variability with a range of $22.50.b) The median is the average of the 30 th and 31st values, and a change in data value from $8 to $18 will not move the middle number.How to interpret Histogram?a) The distribution of tips is skewed right, whith a gap betwen 15 to 20 and a posible out lier at or above 20. The mean will be larger than the median, and the median will be in the $2,5 to $5 bar. Most tips are $5 or less, but there is some high variability with a range of $22.50.
b) The mean would increase because $18 is farther from the mean than $8. Also, more skew is added to the grapht $18 may be an out lier. This results in a larger mean.
The median: Should not change very much. The median is the average of the 30 th and 31st values, and a change in data value from $8 to $18 will not move the middle number.
Your question is incomplete, but most probably the complete question can be seen in the attachment.
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As part of a study of corporate employees, the director of human resources for PNC Inc. wants to compare the distance traveled to work by employees at its office in downtown Cincinnati with the distance for those in downtown Pittsburgh. A sample of 35 Cincinnati employees showed they travel a mean of 370 miles per month. A sample of 40 Pittsburgh employees showed they travel a mean of 380 miles per month. The population standard deviations for the Cincinnati and Pittsburgh employees are 30 and 26 miles, respectively. At the 0.05 significance level, is there a difference in the mean number of miles traveled per month between Cincinnati and Pittsburgh employees? a. Is this a one-tailed or a two-tailed test? O One-tailed test O Two-tailed test b. State the decision rule. (Negative values should be indicated by a minus sign. Round your answers to 2 decimal places.) c. Compute the value of the test statistic. (Negative value should be indicated by a minus sign. Round your answer to 2 decimal places.)
1) Given data information.
2) z = (Xcin -Xpit)/ (σ^2cin/n[tex]c_i_n[/tex] + σ^2pit/n[tex]p_i_t[/tex] ) ...(1)
3) [tex]z = \frac{370-380}{\sqrt{\frac{30^2}{35} -\frac{26^2}{40} } } = -1.532[/tex]
[tex]P_v[/tex] = 2 × P(Z < -1.532) = 0.126
4) Comparing the p value with the significance level α = 0.05 we see that
[tex]P_v[/tex] > α so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a wouldn't be a significant difference in the average of the two groups
Given,
In the question:
1) Data given and notation
[tex]X_c_i_n[/tex] = 370 represent the mean for the sample of Cincinnati
[tex]X_p_i_t[/tex] = 380represent the mean for the sample Pittsburgh
σ[tex]_c_i_n[/tex] = 30represent the population standard deviation for the sample Cincinnati
σ[tex]p_i_t[/tex] = 26 represent the population standard deviation for the sample Pittsburgh
[tex]n_c_i_n[/tex] = 35 sample size for the group Cincinnati
[tex]n_p_i_t[/tex] = 40 sample size for the group Pittsburgh
z would represent the statistic (variable of interest)
2) Concepts and formulas to use
We need to conduct a hypothesis in order to check if the means for the two groups are the same, the system of hypothesis would be:
Null hypothesis: μ[tex]c_i_n[/tex] = μ[tex]p_i_t[/tex]
Alternative hypothesis: μ[tex]c_i_n\neq[/tex] μ[tex]p_i_t[/tex]
We have the population standard deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:
z = (Xcin -Xpit)/ (σ^2cin/n[tex]c_i_n[/tex] + σ^2pit/n[tex]p_i_t[/tex] ) ...(1)
z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.
3) Calculate the statistic
With the info given we can replace in formula (1) like this:
[tex]z = \frac{370-380}{\sqrt{\frac{30^2}{35} -\frac{26^2}{40} } } = -1.532[/tex]
4) Statistical decision
Since is a bilateral test the p value would be:
[tex]P_v[/tex] = 2 × P(Z < -1.532) = 0.126
Comparing the p value with the significance level α = 0.05 we see that
[tex]P_v[/tex] > α so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and a wouldn't be a significant difference in the average of the two groups.
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Prove the theorem by first setting up a one-to-one correspondence between permutations of nn objects with nini indistinguishable objects of type ii, ii=1, 2, 3, ..., kk, and the distributions of nn objects in kk boxes such that nini objects are placed in box ii, ii=1, 2, 3, ..., kk and then applying that the number of different permutations of nn objects, where there are n1n1 indistinguishable objects of type 1, n2n2 indistinguishable objects of type 2, ...., and nknk indistinguishable objects of type kk is n!n1!n2!...nk!n1!n2!...nk!n!.Theorem: The number of ways to distribute nn distinguishable objects into kk distinguishable boxes so that nini objects are placed into box ii, ii=1,2,...,kk, equals
In every distribution of k boxes containing n distinct objects, where box i receives ni. Let Si stand for the set that includes those ni identifiable items for i = 1, 2,..., k.
Given,
he collection of objects can be expressed equivalently as k, i = 1 Si has the following object types: left| S 1 |right| = n 1S number of items of type 1, left |S2| right| = n 2S number of objects of type 2, and so on.
In this case, type i denotes objects that fit into box i and are therefore interchangeable. By simply permuting these sets, one can obtain all conceivable distributions of objects. kS I 1, 2, and S i
The number of distribution options is equal to the number of these permutations for i=1, 2,..., k.
n!/(n₁!,n₂!...nₐ!)
That is,
In every distribution of k boxes containing n distinct objects, where box i receives ni. Let Si stand for the set that includes those ni identifiable items for i = 1, 2,..., k.
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Given that the polynomial f(x) has 5 intercepts, which of the following most accurately describes the degree of f(x)? Select the correct answer below: O The degree of f(x) is at most 5. O The degree of f(x) is at least 4. O The degree of f(x) is at most 4 O The degree of (x) is at most 2 O The degree of (x) is at least 2. O The degree of f(x) is at least 5.
The solution is the degree of f(x) is at least 5.
Given info,
The polynomial f(x) has 5 intercepts.
The solution required,
The polynomial f(x) has 5 intercepts.
→ if the function has n intercept then the polynomial function has at least n degrees.
→ There is 5 intercept, then the polynomial function has at least 5 degrees.
→ The degree of f(x) is at least 5.
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