what is hookie's law of elasticity

The image only shows the path of the ball and its different positions at different times during the flight.

To determine the speed of the ball at each position, additional information such as the time elapsed between each position and the distance traveled would be needed. Only with this information would it be possible to calculate the speed at each position and determine where the ball is traveling the fastest.

Speed is the measure of the distance traveled by an object over a specified period. It is a scalar quantity and is typically expressed in units of distance per unit of time, such as miles per hour, kilometers per hour, or meters per second. Speed can be calculated as the ratio of the distance covered by an object to the time taken to cover that distance. It is an important concept in physics and plays a critical role in determining the motion of objects, particularly in the field of mechanics.

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Part A) Magnitude of force on 6.5 nC charge in the middle of figure due to four other charges is calculated as 9.89 x 10⁻³ N ; Part B) Direction of the force on 6.5 nC charge in the middle of figure due to four other charges is towards the center of square.

Electric charges determine how objects interact with each other through  electromagnetic force

Let's label the four charges forming square as q₁, q₂, q₃, and q₄, and the charge in the center as q₅. The magnitude of the charges q₁-q₄ is 2.0 nC, and the magnitude of q₅ is 6.5 nC.

Part A: Force on q₅ due to each of the other charges given by Coulomb's law is : F = k * |q₁||q₅| / r²

k is Coulomb constant (k = 9.0 x 10⁹ N·m²/C²), |q₁| and |q₅| are magnitudes of charges and r is distance between charges.

Since the four charges q₁-q₄ are equidistant from q₅, then net force on q₅ due to them will be directed towards the center of square.

Distance between q₁ and q₅ is a/√2, since the diagonal of the square is √2 times the length of one side. Therefore, force on q₅ due to one of the charges is:

F₁ = k * |q₁||q₅| / (a/√2)²

F₁ = (9.0 x 10⁹ ) * (2.0 x 10⁻⁹) * (6.5 x 10⁻⁹) / (0.04 m)²

F₁ = 2.47 x 10⁻³ N

Total force on q₅ due to the four charges is: Fnet = 4F₁ = 9.89 x 10⁻³ N

Hence, magnitude of the force on 6.5 nC charge due to the four other charges is calculated as 9.89 x 10⁻³ N.

Part B: Force on q₅ due to each of the four charges is directed towards the center of square. Since the four forces are equal in magnitude and direction, then net force on q₅ due to the four charges will also be directed towards the center of the square.

So, the direction of the force on 6.5 nC charge in the middle due to four other charges is towards the center of the square.

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Answer:

#8

Explanation:

26 m/s * cos (7.20) = 25.9 m/s

Answer:

2450J

Explanation:

Acc to eq

K.E= 1/2mv^2

By putting values we get

K.E = 1/2(0.01kg)(700)^2

we get the answer:

2450J (joules?)

A car is about 15 percent efficient at converting energy from gas to energy of motion. Means the car can convert the oil 15% into the useful work remaining energy goes into friction and other kinds of energies like thermal energy (engine heats). Carnot has suggested that no engine can be 100% efficient.

The average car today gets 25 miles for each gallon of gas. means it can run up to 25 miles, if we fuel it with 1 gallon of gas.A car, often known as an automobile, is a wheeled motor vehicle. Cars, according to most definitions, are vehicles that drive mostly on roadways, seat one to eight people, have four wheels, and primarily transport people (rather than cargo). cars are become more efficient day by day.

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The image characteristics will be real ,inverted and formed between centre of curvature and focal point.

Why would you use a concave mirror?

Telescopes that use reflection employ concave mirrors. They also offer an enlarged view of the face for shaving or applying makeup.

Concave mirrors are frequently employed as reflectors in headlights, torchlights, railroad engines, and other parts of autos and motor vehicles. Since the light source is positioned near the mirror's focal point, the light rays are reflected and travel over a considerable distance as parallel, highly intense light beams. Since a convex mirror reflects light outward, it cannot be utilized to concentrate light. Because the focus and center of curvature are fictitious positions inside the mirror and are therefore unreachable, convex mirrors or curved mirrors always produce a virtual image.

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Answer:

below

Explanation:

Force is needed to cause a change in the motion or shape of an object. In physics, force is defined as any influence that causes an object to undergo a certain change. This can include pushing, pulling, twisting, stretching, compressing, or any other type of action that alters the state of an object. Forces are typically measured in units of Newtons (N) and are represented by vectors, which indicate both the direction and magnitude of the force. Some common examples of situations where force is needed include lifting an object, accelerating a vehicle, compressing a spring, or bending a beam.

Answer:

Force can be used in many different ways to small stuff like flicking a bug away or picking up your pencil you use force all the time even when typing just to press down on those little keys.

Force can also be used to move heavy objects such as boulders, tables, cinder blocks, and brick stones. So force can be used in many different ways the strongest man “ Ben Weider “ known as the strongest man lifting 500 pounds in 1995 - 2000. He uses force to lift up the things that he carries.

Force can be used in many ways like I said typing something out or bench pressing. But force can be limited due to your strength.

Thus the answer to your problem is, ↑↑↑↑

Answer:

1) Terahertz (Tera)

2) Kilolitre (kilo)

3) Mega

4) Gigawatt (Giga)

A particle with the potential energy diagram shown is located at point A and is moving to the right with a kinetic energy of 10.0 Joules. When the particle reaches point F, the speed of the particle has decrease

As the sum of potential and kinetic energy remains constant

Kinetic energy decreases when potential energy increases and vice versa.

When kinetic energy decreases speed will also decrease.

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According to the information we can infer that the decrease in speed is offset by the increase in radius.

To calculate the speed the ice cube we have to consider that the gravitational force on the ice cube is balanced by the normal force provided by the cone. So, the speed of the ice cube must be such that the centripetal force equals the gravitational force.

In this case, to find the speed of the ice cube let M be the mass of the ice cube and r be the radius of the circular path. The gravitational force on the ice cube is given by Fg = Mg, where:

g = acceleration due to gravity.

The centripetal force is given by Fc = Mv^2/r, where:

v = speed of the ice cube

Setting Fg = Fc, we get:

Solving for v, we get:

v = sqrt(gr)

No piece of data is unnecessary for the solution.

According to the information, when R is made two times larger, the required speed will decrease. For example:

From part (a), v is proportional to the square root of R. Therefore, if R is doubled, v will be multiplied by the square root of 2, which is approximately 1.414.

To know if the time required for each revolution will increase, decrease or stay constant we have to consider that shen R is made two times larger, the time required for each revolution will increase. To see this, note that the period T of the circular motion is given by:

T = 2πr/v

According to the information, the answers to parts (c) and (d) are not contradictory because the decrease in speed is offset by the increase in radius, resulting in a longer period of revolution. The net effect is that the ice cube will travel the same distance in each revolution, so the total time required for one complete revolution will remain constant.

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Sphere A has a net charge of approximately -1.0 Coulombs and after the spheres are separated, they will have equal but opposite charges.

Define Coulombs ?

Coulombs (C) is the unit of electric charge in the International System of Units (SI). It is defined as the charge transported by a constant current of one ampere in one second.

(Part A) The addition of electrons to sphere A will give it a negative charge. The number of excess electrons on sphere A can be calculated as:

n = Q/e

where n is the number of excess electrons, Q is the total charge on sphere A, and e is the elementary charge. Since [tex]1.0*10^{12[/tex] electrons are added to sphere A, we have:

n = [tex]1.0*10^{12[/tex]  electrons / ([tex]1.6*10^{-19[/tex] C/electron) = [tex]6.25*10^{30[/tex] electrons

Thus, the total charge on sphere A is:

Q = ne = ( [tex]6.25*10^{30[/tex] electrons) × ( [tex]1.6*10^{-19[/tex]  C/electron) ≈ -1.0 C

So, sphere A has a net charge of approximately -1.0 Coulombs.

(Part B) Since the two spheres were in contact, they shared the same potential before they were separated. Therefore, after the spheres are separated, they will have equal but opposite charges. Sphere B will have a net charge of +1.0 Coulombs to balance the -1.0 Coulombs on sphere A.

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Work done by a force in a moving object is 100J . It was traveling at a speed of 2m/s and comes down to 1 m/s.

Work done is the amount energy gained (loosed) in bringing the body from initial position to final position. It is denoted by W and its SI unit is joule(J). i.e. Work(W) is force(F) times displacement(s). W=F× s When a body is displaced with 1 newton of force by 1 m, then we can say that work has been done on the body by 1 joule. Writing for it's dimension, W=F× s.

W = Fs

In this problem mass of the object is not given, consider the mass of the object is 2kg, time to speed down the object is 5s and distance is 25m then,

given,

W = 100J

M = 2kg

t = 5s

s = 25m

then,

W = m.Δv/Δt.s

100 = 2(2-v₂)/5 .25

2 - v₂= 100×5/50

2 - v₂  = 3

v₂ = 1 m/s

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Answer:

according to the internet

The force exerted by the wall on the ladder is 468 N, and the normal reaction exerted by the floor on the ladder is 1152 N.

Explanation:

The force exerted by the wall on the ladder is zero, and the normal reaction exerted by the floor on the ladder is 1176 N.

A reaction force is a force that occurs in response to an action force. According to Newton's third law of motion, "For every action, there is an equal and opposite reaction." This means that whenever an object exerts a force on another object, the second object exerts an equal and opposite force back on the first object.

For example, when you push against a wall, your body is exerting a force on the wall, but the wall is also exerting an equal and opposite force back on your body. This force is known as the reaction force. Another example is when a rocket propels itself forward by expelling exhaust gases backward. The exhaust gases exert a force on the rocket, and the rocket exerts an equal and opposite force back on the exhaust gases.

Here in the Question,

To solve this problem, we need to consider the forces acting on the ladder. There are three forces to consider: the weight of the ladder and the two forces exerted by the wall and the floor on the ladder.

Let's start by finding the weight of the ladder and the person standing on it. The weight is given by:

W = mg

where m is the mass and g is the acceleration due to gravity. For the ladder, we have:

W_ladder = 40 kg x 9.8 m/s^2 = 392 N

For the person:

W_person = 80 kg x 9.8 m/s^2 = 784 N

Next, we need to find the horizontal and vertical components of the forces exerted by the wall and the floor. Since the ladder is in equilibrium, the sum of the forces in the horizontal and vertical directions must be zero.

Let's start with the horizontal direction. The only force in this direction is the force exerted by the wall, which we'll call F_wall. Since there is no acceleration in the horizontal direction, we have:

F_wall = 0

This means that the force exerted by the wall on the ladder is zero.

Now let's look at the vertical direction. The forces in this direction are the weight of the ladder and the person (W_ladder + W_person), the normal force exerted by the floor (N_floor), and the force exerted by the wall (F_wall). Since the ladder is not accelerating in the vertical direction, the sum of the forces in this direction must be zero:

N_floor + F_wall - W_ladder - W_person = 0

Since we know that F_wall = 0, we can simplify this equation to:

N_floor - W_ladder - W_person = 0

Now we can plug in the values we found earlier:

N_floor - 392 N - 784 N = 0

Solving for N_floor, we get:

N_floor = 1176 N

So the normal reaction exerted by the floor on the ladder is 1176 N.

Therefore, the force exerted by the wall on the ladder is zero, and the normal reaction exerted by the floor on the ladder is 1176 N.

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The projectile sticks to the pendulum upon impact, which then swings up to some maximum angle from vertical is 13.61°.

Given, mass of cylindrical blade M = 7kg, radius R = 0.45 m and Length L = 4 m

mass of projectile m = 1.3 kg and its velocity v = 3.75 m/s

distance d = 3 m.

The projectile sticks to the pendulum upon impact, which then swings up to some maximum angle from vertical:

9.14J = (m + M) × gh

1 - cosx = 0.028

x = 13.61°

Thw moment of inertia of the pendulum, with the projectile stuck to it is 33.21 Kgm².

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Answer:

In electric motors, the magnet is used to generate rotation using electrical current passing through loops of wire. Many of the magnets we are most familiar with are considered permanent magnets. These include common magnets like refrigerator magnets, horseshoe and bar magnets, and rare earth magnets.

The first student's observation tells us that the frequency of the wave is 20/30 Hz or 2/3 Hz. Using the formula v = λf, we can find the velocity of the wave, where v is the speed of the wave, λ is the wavelength and f is the frequency.

To find the velocity we need to find λ. The second student's observation tells us that the wave travels 225 cm in 10.0 s. Therefore, the velocity of the wave is 22.5 cm/s. If we substitute this and the frequency into the formula, we get

22.5 cm/s = λ x 2/3 Hz

Solving for λ, we get λ = 33.75 cm. Therefore, the wavelength of the wave is 33.75 cm. Thus, we get A.

37.2 cm is the wavelength of the waves when a physics lab, a harmonic wave travels down a string.

Given that,

In a physics lab, a harmonic wave travels down a string. In 30.0 seconds, one student counts 20 vibrations. A second student finds that a wave's greatest peak travels 225 cm along a rope in 10.0 seconds.

We have to find what is the wavelength of the waves.

We know that,

The formula to find the wavelength is

λ = [tex]\frac{v}{f}[/tex]

Here,

λ  is wavelength,

v is speed and

f is frequency.

So,

v is the ratio of maximum distance of wave travels by the time.

v = [tex]\frac{225}{10.0}[/tex] = 22.5 cm per second.

f = [tex]\frac{20}{30}[/tex] = 0.6 hz.

Now,

λ = [tex]\frac{v}{f}[/tex] = [tex]\frac{22.5}{0.6}[/tex] = 37.2 cm

Therefore, 37.2 cm is the wavelength of the waves.

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When the wood comes down the change in potential energy of mass 2 kg and velocity 12 m/s is 144 J.

When the object is thrown vertically upwards, the height increases. The potential energy also increases with respect to the height. The potential energy is maximum, and the kinetic energy is zero when the stone moves vertically upwards.

When the object comes down, the potential energy decreases and results in increasing in kinetic energy. When the stone comes down, the potential energy is converted to kinetic energy, and the change in potential energy results in kinetic energy.

From the given,

mass of the wood (m) = 2kg

the velocity of the wood (v) = 12 m/s

kinetic energy (K.E) = mv² / 2

                                = (2×12×12) / 2

                                = 144 J

Thus, the change in kinetic energy is 144 J.

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Part A) The strength of the electric field indicated by the dot is 4.0 nC/m. Part B) The direction of the electric field at the position indicated by the dot in Figure 1 is 135° above the horizontal line.

Direction is the act of providing guidance and instructions to someone. It can be given in a variety of ways, including verbally, in written form, or through gestures. It can be used in all aspects of life, such as in a business setting, in a classroom, or in everyday life. In order for direction to be effective, it should be clear and concise. Additionally, it should be tailored to the individual, taking into account their level of understanding and their current situation. Direction is a powerful tool, and it can help to create clarity and organization in a chaotic situation. It is essential in guiding people towards their desired goals and objectives.

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According to the question the average velocity is 2 000 m ÷ 32.5 s which is equal to 61.5 m/s.

Average velocity is defined as the rate at which an object moves when its displacement is divided by the time taken. It is a vector quantity, meaning it has both magnitude and direction. It is usually expressed in terms of distance per unit of time, such as meters per second (m/s). The average velocity of an object is determined by measuring its displacement and the time taken to cover the displacement.

The average velocity is the total distance traveled divided by the total time taken. In this case the total distance traveled is 2 000 m and the total time taken is the time it takes to travel 1 000 m at 80.0 m/s plus the time it takes to travel 1 000 m at 50.0 m/s.
The time it takes to travel 1 000 m at 80.0 m/s is 1000 m ÷ 80.0 m/s which is equal to 12.5 s.
The time it takes to travel 1 000 m at 50.0 m/s is 1000 m ÷ 50.0 m/s which is equal to 20.0 s.
The total time taken is 12.5 s + 20.0 s which is equal to 32.5 s.
Therefore the average velocity is 2 000 m ÷ 32.5 s which is equal to 61.5 m/s.

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Differentiation

Derivative Rule [Basic Power Rule]:

[tex]\displaystyle\begin{aligned}f(x) & = cx^n \\f'(x) & = c \cdot nx^{n - 1} \\\end{aligned}[/tex]

Derivative Rule [Chain Rule]:
[tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Let's define what the problem gives us:

We know from our trigonometric derivatives that the derivative of [tex]\displaystyle \sin x[/tex] is equal to [tex]\displaystyle \cos x[/tex]. However, since we have some arbitrary constant [tex]\displaystyle a[/tex] multiplying [tex]\displaystyle x[/tex] inside our [tex]\displaystyle \sin x[/tex] function, we will have to apply the derivative rule of Chain Rule:

[tex]\displaystyle\begin{aligned}y & = \sin ax \\y' & = \boxed{ \cos (ax) (ax)' } \\\end{aligned}[/tex]

To further simply the derivative, we now apply the derivative rule of Basic Power Rule and simplify:

[tex]\displaystyle\begin{aligned}y & = \sin ax \\y' & = \cos (ax) (ax)' \\& = (ax)' \cos ax \\& = 1 \cdot ax^{1-1} \cos ax \\& = ax^0 \cos ax \\& = \boxed{ a \cos ax } \\\end{aligned}[/tex]

∴ the derivative of the function [tex]\displaystyle y = \sin ax[/tex] is equal to [tex]\displaystyle \boxed{ y' = a \cos ax }[/tex].

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Topic: Calculus

Unit: Differentiation

The criteria for evaluating the following sentence are as follows: Although the claim is true, the explanation is false.

Using straightforward, honest, acceptable, and highly respectful language to communicate your opinions, feelings, and preferences is known as assertion. "I can't hear the movie while you speak. kindly lower your voice." "When you wear that clothing, I really like it. You look wonderful!"

To guarantee that fiscal records & disclosures are accurate and suitable, assertions are qualities that need to be evaluated. Financial statements are correctly reported when all assertions for pertinent transactions or balances are met.

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The weight of the meterstick (mg) and the tension forces in the strings (T_L and T_R) are the forces pulling on the meterstick. The net force acting on the meterstick is 0 since it is at rest.

[tex]T_L * 0.25 m = m * g * 0.5 m\\T_L = m * g * 0.5 m / 0.25 m = 4 * m * g = 8.88 N[/tex]

The only force operating on the meterstick once the appropriate string has been severed is its weight. The weight's torque about the pivot point is

τ = -mg * 0.25 m

where the clockwise direction of the torque is indicated by the negative sign. We may determine by using the rotational equivalent of Newton's second law, = I, where I is the meterstick's moment of inertia and is its angular acceleration.

α = -mg * 0.25 m / (1/3 * m * L^2) = -3g/L = -29.4 rad/s^2

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Answer:(a) To find the height of the satellite's orbit if its total energy were 550 MJ greater, we can use the following equation:

K2 + U2 = K1 + U1 + 550 MJ

Since the satellite is in a circular orbit, its kinetic energy is given by:

K = (1/2)mv^2

where m is the mass of the satellite, and v is its velocity.

We can use the following equation to relate the height of the satellite's orbit to its velocity:

v = sqrt(GM/R)

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth plus the height of the satellite's orbit.

Therefore, we can express the kinetic energy of the satellite in terms of its height:

K = (1/2)m(GM/R)

Using these equations, we can rewrite the conservation of energy equation as:

(1/2)m(GM/(R1+h1)) - GMm/(R1+h1) = (1/2)m(GM/(R2+h2)) - GMm/(R2+h2) + 550 MJ

where R1 is the radius of the Earth, and R2 is the radius of the Earth plus h2.

Simplifying and solving for h2, we get:

h2 = [(GMm/(R1+h1)) - (GMm/(R2+h2)) - 550 MJ/(GM/(R2+h2))]^(-1) - R2

Plugging in the given values, we get:

h2 = 931 km

Therefore, the height of the satellite's orbit would be 931 km if its total energy were 550 MJ greater.

(b) To find the difference in the system's kinetic energy, we can use the following equation:

Delta K = K2 - K1

Substituting the expressions for K1 and K2, we get:

Delta K = (1/2)m(GM/(R2+h2)) - (1/2)m(GM/(R1+h1))

Plugging in the given values, we get:

Delta K = -7.5 x 10^9 J

The negative sign indicates that the system's kinetic energy has decreased.

(c) To find the difference in the system's potential energy, we can use the following equation:

Delta U = U2 - U1

Substituting the expressions for U1 and U2, we get:

Delta U = -GMm/(R2+h2) + GMm/(R1+h1)

Plugging in the given values, we get:

Delta U = 5.9 x 10^9 J

The positive sign indicates that the system's potential energy has increased.

Explanation:

The activation energy required to light a match is obtained by the chemical energy transferred into the thermal energy. When the match stick and head are rubbed together, the friction force is developed and hence, lightning occurs.

Activation energy is the minimum amount of energy available for the chemical reaction to occur. It involves the Breaking of adhesion between the match head and the striking surface causing the particle to vibrate.

The energy of vibration provides the activation energy required to light the match. The thermal energy of the vibrating particles on the head of the match is transferred from cool to hot regions.

As the head moves across the striking surface, its particles adhere to the surface for a short period of time and produce heat and light energy.

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Given that two large parallel plates are separated by 0.20 m and that the potential difference is 12V.

(a) Describe the motion of an electron released from rest at a distance "d" from the negative plate.

(b) What distance from the positive plate will the electron have a speed of 1 x 10^6 m/s?

For part (a):

The magnitude of an electric field can be given as  [tex]||\vec E||=\frac{\Delta V}{d}[/tex], where "ΔV" is the potential difference and "d" is the distance between the plates.

So, [tex]||\vec E||=\frac{12 \ V}{0.20 \ m} \Longrightarrow \boxed{||\vec E||=60 \ \frac{N}{C} }[/tex]

An electric field is created between the plates pointing from positive towards negative. We know that negative charges accelerate opposite the direction of electrical fields. So the electron placed "d" meters away from the negative plate will accelerate towards the positive plate at a constant rate.

For part (b):

We know that...

- the charge of an electron is [tex]\bold{-1.602 \times10^{-19} \ C}[/tex].

- the mass of an electron is [tex]\bold{9.11 \times10^{-31} \ kg}[/tex].

- [tex]\vec F_e=q\vec E[/tex]

- [tex]\vec F =m\vec a[/tex]

[tex]\Longrightarrow \vec F_e=(-1.602 \times10^{-19} \ C)(60 \ \frac{N}{C} }) \Longrightarrow \boxed{\vec F_e= -9.612 \times10^{-18} \ N}[/tex]

[tex]\Longrightarrow \vec F =m\vec a \Longrightarrow \vec a=\frac{\vec F}{m} \Longrightarrow \vec a=\frac{-9.612 \times10^{-18}}{9.11 \times10^{-31} \ kg} \Longrightarrow \boxed{\vec a=-1.06 \times10^{13} \ m/s^2}[/tex]

Kinematic Equation: [tex]\vec v_f^2=\vec v_0^2+2\vec a \Delta \vec x[/tex]

[tex]\Longrightarrow 1 \times10^{12} \ m^2/s^2=-2.11 \times10^{13} \ m/s^2 \Delta \vec x \Longrightarrow \Delta \vec x= \frac{1 \times10^{12} \ m^2/s^2}{-2.12 1\times10^{13} \ m/s^2}[/tex]

[tex]\Longrightarrow \boxed{\Delta \vec x= -0.047 \ m}[/tex]

The distance from the positive plate we'll call, "D."

[tex]D=0.20+\Delta \vec x[/tex]

[tex]\Longrightarrow D=0.20+\Delta \vec x \Longrightarrow D=0.20 \ m+(-0.047 \ m) \Longrightarrow \boxed{D=0.153 \ m} \therefore Sol.[/tex]

The wavelength of the wave is 6.84 m.

Speed of the wave, v = 342 m/s

frequency of the wave, f = 50 Hz

We know that speed of a wave,

v = fλ

Therefore, wavelength of the wave,

λ = v/f

λ = 342/50

λ = 6.84 m

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Based on the information provided, it seems like Jessica's sun powered pop it has stopped working because it is not receiving enough sunlight to power the device.

To fix the issue, she should try holding it in a place where it can receive direct sunlight for an extended period of time. Alternatively, if the device has a rechargeable battery, she could try charging it using a USB cable or other charging method if one is available.

If neither of these solutions work, there may be a more serious issue with the device itself and it may need to be replaced or repaired.

While this answer may provide helpful information for your inquiry, it is important to remember that using it verbatim could be seen as plagiarism. To avoid this, it is best to use your own words and properly cite any sources used. This will ensure that you are giving credit to the original author and presenting your own unique perspective on the topic.

~~~Harsha~~~