what is it called when the right side of a design is reflected across a central axis and mirrored on the left side of the design?

Answers

Answer 1

When the right side of a design is reflected across a central axis and mirrored on the left side of the design is called vertical symmetry.

What is the reflection of light?

Whenever light bounces off something, that is reflection. The light will be reflected in the same direction from a smooth, shining surface, such as glass, water, or polished metal. The term for this is specular reflection. When light strikes a smooth surface, it bounces back at the same angle.

What are the laws of reflection of light?The incident ray's angle with the normal is the same as the reflected ray's angle with the normal.All three rays—the incident, normal, and reflected—are in the same planes.The incident ray and the refracted are on opposite sides of the baseline.

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A hockey puck with a mass of 0.16 kg travels at a velocity of 40m / s toward a goalkeeper. The goalkeeper has a mass of 120 kg and is at rest. Assuming a closed system, find the total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper. In 3-4 sentences, identify the object with the greater momentum after the puck is caught and explain your reasoning. (4 points)

Answers

(a) The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is 6.4 kgm/s.

(b) The goalkeeper has greater momentum after the puck is caught because  of the conservation of linear momentum. The initial momentum of the hockey puck of 6.4 kgm/s was transferred to the goalkeeper which increased his initial zero momentum to approximately final momentum of 6.4 kgm/s.

What is the total moment of the goalkeeper and puck?

The total momentum of the goalkeeper and puck after the puck is caught by the goalkeeper is calculated by applying the principle of conservation of linear momentum.

m₁u₁ + m₂u₂ = v (m₁ + m₂)

where;

m₁ is the mass of the hockey puckm₂ is the mass of the goalkeeperu₁ is the initial velocity pucku₂ is the initial velocity of the goalkeeperv is the final velocity of the goalkeeper and puck after the collision

0.16(40) + 120(0) = v (0.16 + 120)

6.4 = 120.16v

v = (6.4) / (120.16)

v = 0.053 m/s

The final momentum of the hocky puck after the collision is calculated as;

Pf₁ = 0.16 kg   x   0.053 m/s

Pf₁ = 0.0085 kgm/s

The final momentum of the goalkeeper after the collision is calculated as;

Pf₂ = 120 kg   x   0.053 m/s

Pf₂ = 6.36 kgm/s

The total momentum = 0.0085 kgm/s  + 6.36 kgm/s = 6.4 kgm/s

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find the area of the surface. the helicoid (or spiral ramp) with vector equation r(u, v) = u cos(v) i u sin(v) j v k, 0 ≤ u ≤ 1, 0 ≤ v ≤ 3.

Answers

The area of Surface = [tex]{ }^3 k \pi\left[\frac{\ln (1+\sqrt{2})+\sqrt{2}}{x}\right]=3 \pi[\ln (\sqrt{2}+1)+\sqrt{2}] \\[/tex]

What is a vector equation ?

A vector equation is a linear combination of vectors with possibly unknown coefficients.

What is vector ?

Vectors are defined as quantities that have both magnitude and direction. Examples include weight, acceleration, force, displacement, and velocity. Scalar quantities are those that merely have magnitude and no direction.

According to the given information

r(u, v) =[tex]\langle u \cos v, u \sin v[/tex], [tex]v\rangle \quad 0 \leqslant u \leqslant 1[/tex]

[tex]0 \leqslant v \leqslant 6 \pi \\[/tex]

[tex]& \gamma_u=\langle\cos v, \sin v, 0\rangle \\[/tex]

[tex]& r_v=\langle-u \sin v, u \cos v, 1\rangle \\[/tex]

[tex]& r_u \times r_v[/tex] = [tex]\left|\begin{array}{ccc}\hat{i}_i & \hat{j} & \hat{k} \\\cos v & \sin v & 0 \\-u \sin v & u \cos v & 1\end{array}\right| \\[/tex]

= [tex]\hat{\imath}[\sin v-0]-\hat{\jmath}[\cos v]+\hat{k}\left[u \cos ^2 v+u \sin ^2 v\right] \\[/tex]

[tex]& =\langle\sin v,-\cos v, u\rangle \\& \left\|\gamma_u \times \gamma_v\right\|=\sqrt{\sin ^2 v+\cos ^2 v+u^2}=\sqrt{1+u^2} \\[/tex]

[tex]& A_{r e}=\iint\left\|r_u \times r_v\right\| d A \\& =\int_0^1 \int_0^{6 \pi} \sqrt{1+u^2} d v d u \quad=\int_0^1 \sqrt{1+u^2} d u[v]_0^{6 \pi} \\& =6 \pi \int_0^1 \sqrt{1+u^2} d u=\frac{6 \pi}{2^2}\left[\frac{1}{2}\left(x \sqrt{1+u^2}+\ln \left(\sqrt{1+u^2}+1\right)\right]_0^1\right. \\& ={ }^3 k \pi\left[\frac{\ln (1+\sqrt{2})+\sqrt{2}}{x}\right]=3 \pi[\ln (\sqrt{2}+1)+\sqrt{2}] \\[/tex]

So

The area of Surface = [tex]{ }^3 k \pi\left[\frac{\ln (1+\sqrt{2})+\sqrt{2}}{x}\right]=3 \pi[\ln (\sqrt{2}+1)+\sqrt{2}] \\[/tex]

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n a double slit experiment light of wavelength 585.0 nm is used, the separation of the slits is 0.100 mm and the viewing screen is 21.0 cm from the slits. on this screen, what is the separation between the fifth maximum and seventh minimum from the central maximum?

Answers

The separation between the fifth maximum and seventh minimum from the central maximum is 2.457mm

Seperation between 5th and 7th minima

=2X(wavelength)x(Distance of screen) / (slit seperation)

=(2x 585x10^-9 x21x10^-2 )/ 0.1x10^-3 =2.457mm

The double-slit experiment shows that light and matter can exhibit properties of both classically defined waves and particles. Furthermore, it demonstrates the fundamental stochastic nature of quantum mechanical phenomena. This kind of experiment was first performed by Thomas Young in 1802 to demonstrate the wave behavior of visible light [1]. At the time, light was thought to consist of waves or particles. With the advent of modern physics about 100 years later, it was recognized that light can indeed exhibit behavior characteristic of both waves and particles. We have demonstrated that it exhibits the same behavior as extended to molecules . Thomas Young's light experiments were part of classical physics long before the concept of quantum mechanics and wave-particle duality was developed. He believes that this proves that the wave theory of light is correct, and his experiment is sometimes called Young's experiment  or Young's slit.

This experiment belongs to the general class of "double-path" experiments, in which a wave is split into two separate waves (a wave usually consists of many photons and is better known as a wavefront). .The wave properties of a single photon ), which later combine into a single wave. Changes in the path length of both waves lead to phase shifts that create interference patterns. Another version is a Mach-Zehnder interferometer that splits the beam with a beam splitter.

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this problem occurs in petroleum firefighting when fire streams are applied to the burning liquid surface at such an angle that hot and / or burning oil is forced over the edge of the tank. the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank. this best defines which problem?

Answers

Petroleum has less density than water. So, when fire streams are applied to the burning liquid surface at such an angle that hot and / or burning oil is forced over the edge of the tank, the oil then flows down the side of the tank and you are now confronted with a fire on the ground as well as the one in the tank.

What are the reasons not to use fire streams during deal with  burning oil?

When you spray water on a regular fire, you're attempting to lower the flame's temperature and contain the fire.

Fuel for an oil fire is oil. Temperature and oxidizer are present in a fire (oxygen). Due to the fact that oil is lighter than water, an explosion may result if it floats above water while water sinks beneath oil.

Consequently, water shouldn't be used to put out oil fires.

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a 1,800 kg car is parked on a road that has an elevation angle of 7?. suppose the coefficient of static friction of the kinds of rubber and asphalt involved is 0.65. which is approximately the force of static friction between the tires and the road?

Answers

A car weighing 1,800 kg is parked on a road with an elevation angle of 7, and Fn = 17526.4 N

Explain about the force?

The definition of force in physics states that when an object with mass is pushed or pulled, it alters its velocity. A body's resting or moving status can be changed by an external agent known as force. It has both size and motion.

It takes force to push or pull something. Pushing, tugging, picking, hitting, lifting, running, and bending are examples of actions that involve the application of force. The movement or stopping of a body, as well as changes to an object's shape or motion, are a few examples of actions that show the usage of force.

In mechanics, a force is any action that aims to maintain, alter, or deform a body's motion.

   =mgcosФ

   =1,800 (9.81)cos7

   =17526.4 N

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a spider can tell when its web has captured, say, a fly because the fly's thrashing causes the web threads to oscillate. a spider can even determine the size of the fly by the frequency of the oscillations. assume that a fly oscillates on the capture thread on which it is caught like a block on a spring. what is the ratio of oscillation frequency for a fly with mass m to a fly with mass 4.6m?

Answers

The ratio of oscillation frequency for a fly with mass m to a fly with mass 4.6m is 2.14 : 1.

The formula to calculate the frequency of oscillation for a block on a spring
[tex]\omega = \sqrt{\frac{k}{m}}[/tex]
ω²m = k

ω = the frequency of oscillation (rad/s)k = the constant from the spring (N/m)m = the mass of the block (kg)

If two flies are caught in similar threads, then the magnitude of k or the constant from the threads is the same. The oscillation frequency ratio is the ratio of the inverse of the root mass.

m₁ = mm₂ = 4.6m

[tex]\frac{\omega_1}{\omega_2} = \frac{\sqrt{m_2}}{\sqrt{m_1}}[/tex]

ω₁² : ω₂² = m₂ : m₁

ω₁² : ω₂² = 4.6m : m

ω₁² : ω₂² = 4.6 : 1

[tex]\omega_1 \::\: \omega_2 = \sqrt{4.6} \::\: \sqrt{1}[/tex]

ω₁ : ω₂ = 2.14 : 1

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a 0.341-g wire is stretched between two points 70.5 cm apart. if the tension in the wire is 578 n, find the frequencies of the wire's (a) first, (b) second, and (c) third harmonics. for the first harmonic, the length of the wire is a half wavelength.

Answers

The frequencies of the wire's first, second, and third harmonics are 755 Hz, 1550 Hz, and 4650 Hz respectively.

What is the fundamental frequency?

The fundamental frequency can be described as the lowest frequency of a periodic waveform. In terms of a superposition of sinusoids, the fundamental frequency can be defined as the lowest frequency sinusoidal in the sum of harmonic frequencies.

Given the mass of the wire, m = 0.341 g = 3.41 × 10⁻⁴ kg

The length of the wire, L 70.5 cm = 0.705 m

The tension in the wire, T = 578 N

The frequency of the fundamental vibration can be calculated as:

[tex]\displaystyle \nu =\frac{1}{2} \sqrt{\frac{T}{mL} }[/tex]

[tex]\displaystyle \nu =\frac{1}{2} \sqrt{\frac{578}{3.41 \times 10^{-4}\times 0.705} }[/tex]

ν = f₁ = 755 Hz

Second harmonic, f₂ = 2f₁ = 2 × 775 = 1550 Hz

Third Harmonic, f₃ = 3 f₂ = 3 ×1150 = 4650 Hz

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In a classic Simpsons episode, Abe Simpson states "My car gets 40 rods to the hogshead, and that's the way I like it!" To describe the gas mileage of a modern car to Abe Simpson, construct a method to convert 51.5 miles per gallon to rods per hogshead. For this calculation, use the two following conversion factors: 1 mile = 320.0 rods 1 hogshead = 85.7 gallons What is the gas mileage of the car in rods per hogshead? (Note: Report your value in decimal notation, not scientific notation.)

Answers

The gas mileage of the car in rods per = 1412336rogs/

We have been given:

quantity= 51.5miles per

1 mile = 320.0 rods

1 = 85.7

51.5miles/ = 51.5×1mile/1 ×320.0 rods/1mile×85.7/

= (51.5×320.0×85.7)rods/

= 1412336 rods/

hence, the final answer will be 1412336rods/.

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An 3.1 kg bowling ball rolls with a velocity of 1.1 m/s and strikes a stationary 2.2 kg bowling ball. The first ball stops after the collision. How fast does the second bowling ball roll away after the collision?

use units and work out

Answers

The speed of the second bowling ball after collision is 1.55 m/s

What is speed?

Speed can be defined as the ratio of distance to time of a body.

To calculate the speed of the second bowling ball after collision, we use the formula below

Formula:

v = mu/m'................ Equation 1

Where:

m = Mass of the first bowling ballm' = Mass of the second bowling ballu = Initial speed of the first bowling ballv = Final speed of the second bowling ball

From the question,

Given:

m = 3.1 kgm' = 2.2 kgu = 1.1 m/s

Substitute these values into equation 1

v = (3.1×1.1)/2.2v = 1.55 m/s

Hence, the second bowling ball is 1.55 m/s fast.

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given an electron beam that is aimed west at the equator, what was the direction of the magnetic force on the electrons due to the earth's magnetic field? hint: the earth's magnetic field is directed north at the equator.

Answers

Answer:

magnetic force F = q

Explanation:

8.a bowling ball rolls up a ramp 0.5 m high without slipping to storage. it has an initial velocity of its center of mass of 3.0 m/s. (a) what is its velocity at the top of the ramp? (b) if the ramp is 1 m high does it make it to the top?

Answers

(a) The velocity at the top of the ramp is 1.41 ms⁻¹. (b) The ball does not make it to the top as the value of the square root is negative.

Given:

Height of the ramp (h) = 0.5 m

Initial velocity (v₀) = 3.0 m/s

Acceleration due to gravity (g) = 9.8 m/s²

(a) From the conservation of energy:

Total Mechanical Energy at the bottom = Total Mechanical Energy at the top

The potential and kinetic energy is given by:

Kinetic Energy at the bottom = 0.5 × m × v₀²

Potential Energy at the top = m × g × h

Kinetic Energy at the top = 0.5 × m × v²

Equating potential and kinetic energy:

(0.5) ×  m ×  v₀² = m ×  g ×  h + (0.5) ×  m × v²

v² = v₀² - 2 * g * h

v = √(v₀² - 2 ×  g ×  h)

v = √(3.0² - 2 ×  9.81 ×  0.5)

v  =  1.41 ms⁻¹

Hence, the velocity at the top of the ramp is  1.41 ms⁻¹.

(b)

The speed at a height of 1 m is given by:

v = √(v₀²×g×h)

v = √(3²×-9.8×1)

v = √(-5)

Since the square root cannot be negative.

Hence, the ball does not make it to the top.

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Hypothesis (one or 2 paragraphs)
Should be on the form
‘An increase in the independent variable will cause the dependent variable to …’.
You could also suggest a mathematical or graphical relationship between the variables.
Explain why you think your hypothesis is true using scientific ideas.
The hypothesis should follow from the introduction - no new information added.
Include references to any sources of information and to your own introduction..

The IV is the Mass of the coffee filter and the DV is The terminal velocity.

Answers

‘An increase in the independent variable (the Mass of the coffee filter) will cause the dependent variable (The terminal velocity) to decrease.

How does mass affect terminal velocity Experiment?

This relationship demonstrates the way that a mass-dependent relationship exists between an object's terminal velocity and mass. The faster an object descends through a fluid, the heavier it is.

The values of the variables shift in the opposite directions when there is an inverse or negative relationship. In other words, if the value of the independent variable rises, the dependent variable falls; if the value of the independent variable falls, the dependent variable rises.

Therefore, for coffee filters, the force of air resistance is related to the square of the fall speed, therefore it too increases as speed increases. To reach terminal velocity, a heavier filter with a same area must fall more quickly than a lighter one.

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what frequency is received by a person watching an oncoming ambulance moving at 130 km/h and emitting a steady 800-hz sound from its siren? the speed of sound on this day is 341 m/s.

Answers

The frequency received by the person is 643 Hz.

The Doppler effect states that the frequency of a sound wave is changed due to the motion of the source and the observer. The frequency of the sound wave will decrease as the source moves away from the observer and increase as it approaches.

The frequency received by the person can be calculated using the following formula:

F = (V + v) / (V - v) * F0

Where F is the frequency received by the observer, V is the speed of sound, v is the speed of the source and F0 is the frequency of the sound emitted by the source.

In this case, V = 341 m/s, v = 130 km/h = 36.1 m/s, F0 = 800 Hz.

Substituting these values into the formula, we get:

F = (341 + 36.1) / (341 - 36.1) * 800 = 643 Hz.

Therefore, the frequency received by the person is 643 Hz.

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an object is acted on by a single nonzero force of magnitude f. (a) is it possible for the object to have zero acceleration a? (b) is it possible for the object to have zero angular accelera- tion a? (c) is it possible for the object to be in mechanical equilibrium?

Answers

An object is acted on by a single non zero force of magnitude f will have zero acceleration , angular acceleration and also in mechanical equilibrium.

The force adds velocity per unit of time in the force's direction, accelerating the object in proportion to its inertial mass. The acceleration that results depends on the object's mass: the less massive the object, the greater the acceleration; the more massive the object, the less the acceleration. One kilogram of mass is affected by a force of one newton, which on Earth results in an acceleration of 9.8 meters per second. However, if the object weighs twice as much (2 kg), a force of 1 Newton only generates 4.9 m/s2, or half as much acceleration.The initial motion of the object is altered by this force in accordance with the force. When this force is applied for the first time to an object that was at rest, the object accelerates in the force's direction. When a force is applied to an object that is already moving at some speed in a particular direction (and there is no other force at that time), depending on how the force's direction compares to the direction of motion already being carried out, the object's velocity will either increase or decrease.

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consider the above graphs of the hip sagittal angle during the stance phase of running and answer the following questions a. what is the angular displacement for the hip joint from on to off? b. what is the largest angular velocity of the hip joint and is it a flexion or extension velocity? c. what is the largest extension torque of the hip and where in the movement does this occur? d. what is the largest flexion torque of the hip and where in the movement does this occur? e. at the peak extension torque, what muscles produce this torque and is it a concentric or eccentric contraction? f. at the peak flexion torque, what muscles produce this torque and is it a concentric or eccentric contraction?

Answers

a. The hip joint's angular displacement from on to off is 49.1°.

b. The hip joint's maximum angular velocity is 55.4°/s, and it is a flexion velocity.

c. The muscles gluteus medius, gluteus maximus, and semitendinosus provide the maximum extension torque of the hip at 50% of the movement. It is a concentric contraction.

d. The muscle known as biceps femoris long head produces the maximum flexion torque of the hip at the 75% mark of the exercise. It's an eccentric contraction.

e. The gluteus medius, gluteus maximus, and semitendinosus all contribute to the peak extension torque, which is a concentric contraction.

F. Eccentric contraction of the biceps femoris long head causes the maximum flexion torque.

What is angular velocity?

Angular velocity is the rate of change in the angle between two bodies or the pace at which an item revolves or rotates around an axis. This displacement in the illustration is shown as the angle between a line on one body and a line on the other.

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suppose a woman does 500 j of work and 9500 j of heat transfer occurs into the environment in the process. what is the change in her internal energy, assuming no change in temperature or consumption of food? (that is, there is no other energy transfer.)

Answers

The change in internal energy is 10,000 J.

Given that, Work = 500 J

Heat Transfer = 9500 J

Internal energy can be altered by the temperature difference between a system and its surroundings.

We need to calculate the change in internal energy.

Let us use the equation of internal energy of a system,

ΔU = Q - W

where, Q is heat

W is work done

Let us put the values in the formula,

ΔU = -9500 - 500 = -10,000 J

Negative sign of heat is taken as the heat is lost in the process.

Thus, the change in internal energy is 10,000 J.

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Matter can undergo chemical reactions and nuclear reactions. Which
statement is true for both types of reactions?
O A. Atoms are rearranged.
B. New types of compounds are formed.
C. The products are different from the reactants.
OD. New types of atoms are formed.
SU

Answers

The statement that is true if matter undergoes both chemical and nuclear reaction is that atoms are rearranged (option A).

What is a chemical reaction?

A chemical reaction is a process, typically involving the breaking or making of interatomic bonds, in which one or more atoms or substances are changed into others.

Also, a nuclear reaction is a process such as the fission of an atomic nucleus, or the fusion of one or more atomic nuclei and/or subatomic particles in which the number of protons and/or neutrons in a nucleus changes.

In a nuclear reaction, the products may contain a different element or a different isotope of the same element.

This suggests that are atoms are rearranged in both chemical and nuclear reactions.

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the glowing filament in a lamp is radiating energy at a rate of 60 w. at the filament’s temperature of 1500∘c, the emissivity is 0.23. what is the surface area of the flament

Answers

The surface area of the flament is -4 m square feet.

What is surface?

Surface means an outside part of an body or object.

We are asked to find the surface area. So we have to use the equation that relates power and surface area. So power is :

H= Ae σ T⁴

Where, H= power (60 watts)

A=area

σ=universal constant (5.67×10⁻⁸ w/m²)

T=Temperature(1773k)

So our surface area is just our area. A. So A. Is equal to power divided by the emissivity times of the  Stefan bolts, mons, constant to the  times the temperature to the fourth of  power.

So now we can the  substitute our values

(60/600.23)×5.67×10⁻⁸×1773⁴=4.65×10⁻⁴m²

Area of the filament is 4.65×10⁻⁴m²

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two rollerbladers face each other and stand at rest on a flat parking lot. tracey has a mass of 32 kg, and jonas has a mass of 45 kg. when they push off against one another, jonas acquires a speed of 0.35 m/s .what is tracey's speed?

Answers

Since the momentum remains same before and after push-off, therefore Tracey's speed will be 0.492 m/s.

Momentum is a product of mass and the velocity of a body.

The SI unit for momentum is kg-m/sIt is a vector quantity and has the direction same as that of the velocity of the object.It is represented by M and mathematically, M = Mass * Velocity

The initial momentum is always equal to the final momentum during collisions between two bodies.

Therefore; M₁U₁ +M₂U₂ = M₁V₁+ M₂V₂,

where M₁ is the mass of Tracey

M₂ is the mass of Jonas,

U is the initial velocity

V is the final velocity.

(32 ×0)+ (45×0) = (32 × V₁) + (45 × 0.35)

0 = 32V₁ + 15.75

32 V₁ = - 15.75

V₁ = - 0.492 ( negative sign indicates difference in direction)

There, Tracey's speed will be 0.492 m/s.

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For a planet with a roughly circular orbit, how does the planet's velocity change when the orbital radius increases or
decreases?

Answers

Answer: increases

Explanation:

"when the frequency of an ac circuit is increased, the current in the circuit does not change. which combination of elements is most likely to comprise the circuit?"

Answers

The elements are inductor , capacitor and resistors.

An LCR circuit, also known as a resonant circuit, tuned circuit, or an RLC circuit, is an electrical circuit consisting of an inductor (L), capacitor (C) and resistor (R) connected in series or parallel. The LCR circuit analysis can be understood better in terms of phasors. A phasor is a rotating quantity.Impendence (Z) of an LCR circuit is given by [tex]Z = \sqrt{R^{2} + (X_{l} - X_{c} )^{2} }[/tex]

Here , [tex]X_{l} =[/tex] reactance and [tex]X_{c} =[/tex] capacitance

At resonance frequency, Z is minimum and current is maximum. For any other value of frequency, the value of current will decrease (when compared to current at resonance).Clearly, the circuit must have inductor and capacitor. However, it may be possible that the circuit also has a resistor besides inductor & capacitor.

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part e the sum of the electrical and magnetic energies in an l - c circuit is 0.800 j . at a certain instant the energy is exactly half electrical and half magnetic, the capacitor charge is 5.30 mc , and the current is 8.00 a . find the capacitance.

Answers

The magnetic energy that is created around the inductor is where this energy is actually kept. Again, think about the circuit we created with two coils wound on base of one another.

The electrical energy is created by the motion of negative charge to and fro and this flow of electrons create electrical energy.

Given,

sum of magnetic and electric energy = 0.800 J

Capacitor charge = 5.50 mc

Current = 8 A

V = 10

Capacitance = 8 * 10 = 80

Therefore the capacitance of the energized capacitor is 80 F

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a car starting at rest accelerates at 20 ft/s2 for 5 seconds on a straight road. how far does it travel during this time?

Answers

Distance travelled during this time is 250 ft.

Solution:

s = ut + 1/2 a[tex]t^{2}[/tex]

s = distance travelled

t = time taken, given = 5 s

a = acceleration, given = 20 ft/[tex]s^{2}[/tex]

Put these values in formula, s = ut + 1/2 a[tex]t^{2}[/tex]

s = ut + 1/2 a[tex]t^{2}[/tex]   , Here, initial velocity is taken zero, so ut= 0.

s = 1/2 × 20× 5×5

s = 250 ft

Hence, distance travelled during this time is 250 ft.

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Drag the tiles to the correct boxes to complete the pairs.
Drag the tiles to the correct boxes to complete the pairs.
Match the descriptions to the processes.
Ice cream starts dripping down the sides of an ice cream cone.
Fog is created by using dry ice.
Frost forms on trees on a very cold day.
The mirror gets fogged up when you breathe on it.
Your wet hair dries after a few minutes.
Liquid glass cools and hardens.

Answers

Each of the descriptions should be matched to the processes as follows;

Sublimation → Fog is created by using dry ice.

Deposition → Frost forms on trees on a very cold day.

Condensation → The mirror gets fogged up when you breathe on it.

Melting → Ice cream starts dripping down the sides of an ice cream cone.

Evaporation → Your wet hair dries after a few minutes.

Freezing → Liquid glass cools and hardens.

What is a phase change?

In Science, a phase change can be defined as the change in the state (phase) of matter of a given chemical compound or substance. Additionally, some examples of a phase change include the following;

Solid to liquidLiquid to gasGas to solidLiquid to solid

Generally speaking, a change in the state (phase) of matter that results in the release of energy is known as an exothermic reaction and they include the following:

Deposition: such as when frosts are formed on a tree due to low temperatures.Condensation: such as the fog that is formed on a mirror when it is breathed upon.Freezing: such as when a liquid is converted from a liquid state to solid state.

In conclusion, other processes that are associated with a change in the state (phase) of matter are sublimation, melting, and evaporation.

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Ttile: "The Impact of Gadgets in Learning Among Grade CSS-12 Students"
Need to answer: Sample and Sampling Procedure
Respondents
Participants

Answers

Answer:

A sample is a subset of a population that is selected for study in order to represent the larger group. The sampling procedure is the method used to select the sample from the population.

In a study examining the impact of gadgets in learning among grade CSS-12 students, the sample could consist of a specific number of grade CSS-12 students who are representative of the larger population of all grade CSS-12 students. The sampling procedure could involve selecting a random sample of grade CSS-12 students from a list of all grade CSS-12 students at a particular school or group of schools, or it could involve using a stratified sampling method where the grade CSS-12 students are divided into subgroups (strata) based on certain characteristics (such as gender or socio-economic status) and then a sample is selected from each stratum.

The respondents in this study would be the grade CSS-12 students who are participating in the study and providing data through surveys, interviews, or other methods of data collection. The participants in this study would be the grade CSS-12 students who are actively engaged in the study and may be asked to use gadgets in a learning environment as part of the research.

Explanation:

you attach a block to the bottom end of a spring hanging vertically. you slowly let the block move down and find that it hangs at rest with the spring stretched by 13.0 cm. next, you lift the block back up and release it from rest with the spring unstretched. what maximum distance does it move down? 6.5 cm 13.0 cm 26.0 cm 52.0 cm the distance cannot be determined without knowing the mass and spring constan

Answers

Maximum distance that it moves down is 26 cm, when block hangs at rest with the spring stretched by 13.0 cm.

How to calculate the change in spring length?

In the formula, F = -k x :  k is called the spring constant and is a measure of the spring's stiffness. When a spring is stretched or compressed,  its length changes by an amount x from  equilibrium length, and then it exerts a force F = -kx in a direction towards the equilibrium position.

Given that the equilibrium position is 13 cm below the starting point. As motion is symmetric about the equilibrium position, so the two turning points are 26 cm apart.

13 *2 = 26cm

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6. a 5 kg cylinder with a 50 cm radius is attached to the wall by an axis through its center and set into motion with an angular speed of 5 rad/sec. a force f is then applied to the edge of the cylinder as shown. the cylinder completes 6 full rotations before coming to a stop. what is the value of the force f?

Answers

The value of force is 211N.  Thus, the cylinder undergoes through 6 rotations with a force is 211N

How to calculate force of a cylinder?

A cylinder of mass 5 kg and radius 50cm is rotating at angular speed of 5 rad/sec.

To find the force that must be applied tangentially to the cylinder to bring it to rest in 6 revolutions

Calculation :

As per the given criteria

Rotation if the wheel =  5 rad/ sec

Now, total rev = 6

We know

0 = (10/6) ² - 2 lamda × 6

= 100/36=12 lamba

Lamda= 33.33 rev/sec

Lamda = 2π×33.33 rad/sec²

Now the moment of inertia

I=1/2mr²

=1/2 (0.5) ²× 5

=0.625 kgm²

Since the force F, now torque

F=F.r=0.62 F

Now, torque = I × lamda

= 0.625×33.33×2π

Or 0.62 F= 130.82

F= 211 N  

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Light rays are:

running out, expensive, spread thinly

please help me I'm really struggling

Answers

Answer:

running out, expensive, spread thinly

Explanation:

you have a pendulum clock made from a uniform rod of mass m and length l pivoting around one end of the rod. its frequency is 1 radian/sec. the pivot breaks. though the mass change is negligible, you need to rehang the rod halfway between the old pivot point and the middle of the rod. the new oscillation frequency is:

Answers

The new oscillation frequency is 1.07 rad/sec when the pendulum is rehanged to the rod halfway between the old pivot point and the middle of the rod.

What is the Period of oscillation?

The period of oscillation is the shortest amount of time after which the motion of the particle repeats. The period of oscillation is the length of time it takes for a particle to complete its to-and-fro motion.

What is a pendulum?

A body suspended from a fixed point so that it can move back and forth while being pulled by gravity is called a pendulum. A pendulum's whole back-and-forth oscillation has a consistent time interval.

Calculations:

Period of pendulum T = 2 × √I/mgd

Where,

I = moment of inertia

L = length of the pendulum

m = mass

d = distance or L/2

g = acceleration due to gravity.

When pivoted at one end = I = 1/3mL²

When pivoted at other end = f = 1/2π × √mgd/I

f= 1/2π × √(mgL/2)/(1/3 mL²)

f= 1/2π × √ (3g)/(2L) -------------------- (i)

Now when pivoted mid way

I' = mL²/12 + m (L/4)²

I' = mL²/12 + m L²/16

I' = 7mL²/48

Thus here d= L/4

f' = 1/2π × √(mgL/4)/(7/48mL²)

1/2π × √(12g/7L) ----------------------(ii)

Then, f'/I = {1/2π × √(12g/7L)}/{1/2π × √ (3g)/(2L)}

= √ 1.14

~ 1.07 rad/sec.

Hence, the new oscillation frequency is 1.07 rad/sec when the pendulum is rehanged to the rod halfway between the old pivot point and the middle of the rod.

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Label the structures of a typical vertebra. Pedicle ook Body of vertebra rences Lamina Vertebral arch Articular facet Vertebral foramen Transverse process Spinous Name the large bony area. process ME M < Prev 10 of 13 Next

Answers

Answer: i love you babe

Explanation:

The structure of a typical vertebra includes Pedicle, body, vertebral arch, etc. These are discussed in the section below.

Pedicle: The sides of the vertebral arch are formed by a pair of short, thick bony structures that protrude from the back of the vertebral body.

The thick, anterior section of the vertebra known as the "body" is what supports and supports the weight of the vertebral column.

Lamina: A pair of flat plates that combine to create the back of the vertebral arch and extend posteriorly from the pedicles.

The vertebral arch, which is made up of the pedicles and laminae, forms the posterior opening of the vertebra and surrounds and shields the spinal cord.

Articular facet: The superior and inferior portions of the vertebral arch's smooth, flat surfaces that form the facet joints when they articulate with the surrounding vertebrae.

The spinal cord goes through the vertebral foramen, which is the vertebral arch's main aperture.

Transverse process: Laterally extending bony projections from the sides of the vertebral arch that act as points of attachment for ligaments and muscles.

Spinous process: A single, posterior bony projection that arises from the laminae's junction and serves as a point of attachment for ligaments and muscles.

Thus, the vertebral body is the broad bone region that the question alludes to.

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Your question seems incomplete, the probable complete question is:

Label the structures of a typical vertebra. Pedicle ook Body of vertebra rences Lamina Vertebral arch Articular facet Vertebral foramen Transverse process Spinous Name the large bony area. process ME M < Prev 10 of 13 Next

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