Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.
Characteristics of sound wavesFrequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).
Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.
Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.
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Select the correct answer.
F₁ = 70 N
F₂ = 15 N
8
F₁
W = 80 N
Use this free body diagram to help you find the magnitude of the force F₁ needed to keep this block in static equilibrium.
Explanation:
F1 will have to have 65 N vertical up force to balance the net 65 N down on the body AND it will have to have 70 N horizontal to the right to balance the 70 N force that is acting to the left
Magnitude = sqrt ( 65^2 + 70^2) = 95.5 N
a sprinter accelerates from rest to 14m/s in 1.38 s. what is her acceleration in km/h^2
The acceleration of the sprinter is approximately 131,426 km/h^2.
To find the acceleration in km/h^2, we need to convert the units from meters per second (m/s) to kilometers per hour (km/h) and adjust the time units accordingly. Here's the step-by-step calculation:
1. Convert the final velocity from m/s to km/h:
14 m/s * (3.6 km/h) / (1 m/s) = 50.4 km/h
2. Convert the time from seconds (s) to hours (h):
1.38 s * (1 h) / (3600 s) = 0.0003833 h
3. Calculate the acceleration using the formula:
Acceleration = (Final velocity - Initial velocity) / Time
Since the initial velocity is 0 m/s (rest), we have:
Acceleration = (50.4 km/h - 0 km/h) / 0.0003833 h
Acceleration = 131425.955 km/h^2
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how much energy is possessed by 1 mole of nitrogen atoms moving at 35.0 m/s ?
1 mole of nitrogen atoms moving at 35.0 m/s possesses approximately 27.8 joules of energy.
To calculate the energy possessed by 1 mole of nitrogen atoms moving at 35.0 m/s, we need to consider both the kinetic energy and the molecular mass of nitrogen.
The kinetic energy (KE) of an object is given by the equation KE = 1/2 * m * v^2, where m is the mass and v is the velocity.
The molar mass of nitrogen (N₂) is approximately 28.0134 g/mol, which can be converted to kilograms by dividing by Avogadro's number (6.022 × 10^23). This gives us a mass of approximately 4.65 × 10^(-26) kg for one nitrogen atom.
Plugging in the values, we have KE = 1/2 * (4.65 × 10^(-26) kg) * (35.0 m/s)^2.
Evaluating the equation, we find that the kinetic energy possessed by one nitrogen atom is approximately 4.62 × 10^(-23) joules.
Since we are considering 1 mole of nitrogen atoms, we need to multiply this value by Avogadro's number to get the energy possessed by 1 mole. Avogadro's number is 6.022 × 10^23, so the total energy is approximately 2.78 × 10^1 joules, or 27.8 J.
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