The acceleration of an object with mass of 42.6kg when an unbalanced force of 112 N is applied to it is 2.63m/s² (option B).
How to calculate acceleration?Acceleration in physics is the amount by which a speed or velocity increases (and so a scalar quantity or a vector quantity).
The acceleration of a moving body can be calculated by dividing the force applied to move the object by its mass as follows:
a = F/m
According to this question, an object with mass of 42.6kg was moved by an unbalanced force of 112 N. The acceleration required can be calculated as follows;
a = 112N ÷ 42.6kg
a = 2.63m/s²
Therefore, 2.63m/s² is the acceleration of the object.
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A 0. 0850-kg arrow is fired horizontally. If the bowstring exerts an average force of 89. 0 n on the arrow over a distance of 0. 782 m, with what speed does the arrow leave the bow?.
The arrow leaves the bow at a speed of 40.47 m/s.
When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma
m = mass of the arrow (kg) = 0.0850 kga = acceleration of the arrow (m/s²)F = force (N) = 89.0 N[tex]a \:=\: \frac{F}{m}[/tex]
[tex]a \:=\: \frac{89.0}{0.0850}[/tex]
a = 1,047.059 m/s²
When the object has acceleration, the object will move in a non-uniform motion. The formula
v = u+atv² = u² + 2ad[tex]d \:=\: v_0 \times t \:+\: \frac{1}{2} \times a \times t^2[/tex]u = initial speed (m/s) = 0 m/s (arrow stationary in bowstring)v = final speed (m/s) a = acceleration (m/s²) = 1,047.059 m/s²t = interval (s)d = distance (m) = 0.782 mv² = u² + 2ad
v² = 0² + (2×1,047.059×0.782)
v² = 1,637.6
[tex]v_t \:=\: \sqrt{1,637.6}[/tex]
[tex]v_t[/tex] = 40.47 m/s
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a track star runs a 230 m race on a 230 m circular track in 26 s. what is his angular velocity (in rad/s) assuming a constant speed? (enter the magnitude.)
Using the concepts of angular displacement, we got that 0.241 rad/s is the angular velocity of track star which runs a 230 m race on a 230 m circular track in 26 s.
We know very well that angular velocity is given by change in angular displacement per unit time.
Here, we can see that a truck distance covered and length of circular track is same.
Perimeter of circular track is equal to the distance covered by the truck.
It means, truck rounds a full circle in 26 sec
So, the angle covered by truck is 360° or 2π radian.
Initially angle is 0 radian and final angle is 2π radian
Therefore, angular velocity =(θ[tex]_f_i_n_a_l[/tex] -θ[tex]_i_n_i_t_i_a_l[/tex])/time
=> ω=(2π-0)/26
=>w=(2π/26)
=>w=(2×3.14)/26
=>ω=6.28/26
=>w=0.241 rad/sec.
Hence, when a track star runs a 230 m race on a 230 m circular track in 26 s, the angular velocity assuming a constant speed is 0.241 rad/sec.
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if an alpha particle (2 protons) experiences an electric force of 0.250 n at a point in space, what electric force would a proton experience at the same point?
electric force would a proton experience at the same point is .156 × 10⁻¹⁹ N/C.
Electric field :
The electric field is the amount of electric force per charge, and the electric force on a charge at a given point in space is the amount of charge multiplied by the electric field at that location.
E = F/q
where,
E = electric field
F = force
q = charge
A force experienced by an alpha particle = 0.250N
E = F/q
E = 0.250 /1.6 × 10⁻¹⁹
E = 0.156 × 10⁻¹⁹ N/C
electric force would a proton experience at the same point is .156 × 10⁻¹⁹ N/C.
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a car company wants to ensure its newest model can stop in 50 m when traveling at 30 m/s (which is about 108 km/h). if we assume constant deceleration, find the value of deceleration that accomplishes this
A decrease in velocity is referred to as deceleration. If car is moving at 30 m/s and stop in 50 m .The value of deceleration is 11.56 ms−2.
How to calculate deceleration ?While acceleration is motion in which an object's speed varies every second, deceleration is motion that causes an object to slow down.
We are aware that acceleration refers to an object's rate of increase in speed, and deceleration refers to an object's rate of decrease in speed. For instance, when we apply the brakes while driving, we benefit from the vehicle's ability to decelerate and slow down.
The Deceleration Formula is the final velocity minus the initial velocity, with a negative sign in the result because the velocity is decreasing, if starting velocity, final velocity, and time taken are given.
velocity of car = 30 m/s
car need to stop in 50m
Deceleration a = v^2 – u^2 / 2s
= 0^2 - 50^2 / 2*30
= 11.56
Deceleration of the care = 11.56 ms−2
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A 440 hz tuning fork is used with a resonting colum to detemine the velocity of sound in helium gas . if the spacing between resonances in 110cm , what is the velocity of sound in helium gas?
The velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.
We have to go from antinode to antinode. In an air column, the spacing between resonance is wavelength /2 as we have to go from antinode to antinode.
wavelength = 220 cm = 2.2m
As we know the velocity formula
Then Velocity = f * λ
Where f is the frequency and λ is the wavelength.
So Velocity of wave = 440 * 2.2 = 968m/s
Hence, the velocity of sound in helium gas is 968 m/s if the spacing between resonances is 110cm.
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how would stellar parallax observed from saturn differ from the stellar parallax we observe from earth?
Saturn is undergoing an apparent retrograde movement period as the Earth moves closer to Saturn in its orbit and then both planets are located on the side of the Sun. Stars that are nearer to us will exhibit higher parallax, similar to how it occurs on Earth.
The star parallax of the Earth is quite modest, barely 0.03 seconds of arc. It would be difficult to see against the backdrop of stars, even with a good telescope.
The angle between the Earth's place at a single time of year and the Earth 6 months later, as determined from a nearby star, is known as the parallax angle. This angle is used by astronomers to calculate how far away that star is from Earth.
We may calculate the distance to a nearby planet using the method described before, s. Now, measuring from an observation point O, we determine the angle the planet occupies, which is. Therefore, P1P2=d, where d is the planet's diameter. As a result, we may use the parallax method to calculate the radius of a neighboring planet.
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Question 1 of 10
What type of diagram is used to show all of the forces acting on an object?
A. Stability diagram
B. Algebraic diagram
C. Free-body diagram
D. Potential energy diagram
Answer:
c. Free body diagram
Explanation:
Free-body diagrams are diagrams used to show the relative magnitude and direction of all forces acting upon an object in a given situation.
PLEASE ASAP HELP, ILL GIVE WHATEVER POINTS I CAN BUT PLEASE HELP ASAP ASAP
Paul was kicking around a soccer ball with his friend Leo the Lion. Paul decided to kick the ball off a 9.63 m tall cliff and lands on the ocean, 8.85 m away from the edge of the cliff.
Th ball is in the air for S._______m/s
The horizontal velocity of the ball as it rolls off the table is_________m/s
The vertical velocity of the ball right before it hits the ground is________m/s
The horizontal velocity of the ball right before it hits the ground is___________m/s
The initial vertical velocity as soon as the ball comes of the cliff is________m/s
(1) The ball is in the air for 1.4 seconds.
(2) The horizontal velocity of the ball as it rolls off the table is 6.32 m/s.
(3) The vertical velocity of the ball right before it hits the ground is 13.72 m/s.
(4) The horizontal velocity of the ball right before it hits the ground is 6.32 m/s.
(5) The initial vertical velocity as soon as the ball comes of the cliff is 13.72 m/s.
What is the time of motion of the ball?The time of motion of the ball is calculated by applying the following equation.
t = √(2h/g)
where;
h is the height of the cliffg is acceleration due to gravityt = √(2h/g)
t = √(2 x 9.63 / 9.8)
t = 1.4 seconds
The horizontal velocity of the ball is calculated as follows;
v = d/t
where;
d is the horizontal distance travelled by the ball = 8.85 mv = 8.85 m / 1.4 s
v = 6.32 m/s
The vertical velocity of the ball before it hits the ground is calculated as;
vf = vi + gt
vf = 0 + 9.8 x 1.4
vf = 13.72 m/s
The horizontal velocity of the ball right before it hits the ground is calculated as;
the initial velocity of a projectile = final horizontal velocity
vxf = vxi = 6.32 m/s
The initial vertical velocity as soon as the ball comes off the cliff = final vertical velocity = 13.72 m/s
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Jamari is doing a project on the levels of the rain forest. Which would be the most useful visual display to help make his information clear?(1 point)
Responses
a map of where rain forests are located
a map of where rain forests are located
a diagram with the parts of the rainforest labeled
a diagram with the parts of the rainforest labeled
a video of a nature photographer walking in a rain forest
a video of a nature photographer walking in a rain forest
a picture of ants on the rainforest floor
It is a diagram with the parts of the rainforest labeled
A ball rolls down a ramp for 5 seconds. If the ball started with no speed and ended with a speed of 15 m/s, what was the acceleration of the ball?
Answer:
3 m/s^2
Explanation:
Acceleration = change in speed / change i time
= 15 m/s / 5 s = 3 m/s^2
It is typical for people in hypnotic trances to temporarily __________. a. begin speaking languages they do not know b. lose track of their immediate surroundings c. become aware of past lives and buried memories d. feel completely paralyzed and unable to act please select the best answer from the choices provided a b c d
It is typical for people in hypnotic trances to temporarily begin speaking languages they do not know .
Option a is correct
Who are people when they are hypnotized?Although hypnosis is frequently described as a sleep-like condition, it is actually better described as a state of sharpened focus, increased suggestibility, and vivid fantasies. People who are hypnotized frequently appear tired and disoriented, yet they are actually hyperaware.
What transpires while a person is tranced?Our brain waves must slow down in order to enter a trance. Throughout the course of the day, people alternate between several brain wave states. Different stages of the brain wave include sleeping, daydreaming, and being fully alert and focused.
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a car, initially moving with some initial velocity, accelerates until its momentum has increased by a factor of 2.39. by what factor has its kinetic energy increased?
Since the kinetic energy equation squares velocity, velocity increases have exponential effects: while doubling an object's mass doubles its kinetic energy, doubling its velocity quadruples it!
Definition and examples of kinetic energyThe energy of motion, or kinetic energy, is manifested in the motion of a particle, an object, or a group of particles. Kinetic energy is used by any moving thing, including people moving, baseballs being thrown, table crumbs falling, and charged particles in electric fields.
What 3 types od kinetic energy are there?Kinetic energy is divided into three subtypes: vibrational, rotational, or translational. Unsurprisingly, items that vibrate produce vibrational kinetic energy. Moving objects generate rotational kinetic energy, whereas object collisions generate translational kinetic energy.
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Mars has an orbital period of 4333 earth days, find the semi major axis of it's orbit
Answer:372
Explanation:
x. a 0.015-kg marble moving to the right at 0.40 m/s has a head-on, elastic collision with a 0.045-kg marble sitting at rest on a smooth, level surface. a) what are the magnitudes and directions of the velocities of the two marbles after the collision? b) show that the ke is conserved.
The magnitudes and directions of the velocities of the two marbles after the collision is: v1f is left and v2f is right.
What is collision?The initial marble weighs m1 = 0.015 kg.
Second marble's mass is m2=0.045kg.
The first marble's initial velocity is v1i=0.40m/8 before to contact.
The second marble's initial velocity is v2i=0m/8 prior to impact.
After the impact, the first marble's final speed is v1f.
Following the collision, the initial marble's final velocity is v2f.
If the collision is elastic, the kinetic energy is preserved.
We'll write 1/2 m1 for KE = 1/2 mv2 (v1i)
2 + 1/2 m2(vi) (vi)
2 = 1/2 m1(v1f)2 + 1/2 m2 (v2f) (v2f)
2.
Using this equation, we can establish a new relationship between velocities and determine each marble's post-collision velocity:
v1f=(m1-m2)/(m1+m2)
v1\sv1f=(0.015kg-0.045kg)/(0.015kg+0.045kg)
0.40m/s\s=-0.20m/s
First marble is moving leftward at 0.20 m/s, as indicated by the negative sign.
Find the second marble's final velocity.
v2f=2m1v1/(m1+m2)\s
v2f=2⋅0.015kg⋅0.40m/s/(0.015kg+0.045kg)\s
v2f=0.20
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what is the final velocity (in m/s) of a hoop that rolls without slipping down a 5.00-m-high hill, starting from rest?
The final velocity (in m/s) of a hoop that rolls without slipping down a 5.00-m-high hill, starting from rest will be 31.30 m/s
given
initial velocity = 0
displacement = s = 50 m
using kinematics equation
2as = [tex]v^{2} - u^{2}[/tex]
2* (g) * s = [tex]v^{2}[/tex] - 0
[tex]v^{2}[/tex] = 2 * (9.8) * 50
v = 31.30 m/s
The final velocity will be v = 31.30 m/s
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the spectrum of a very distant galaxy shows features due to carbon, silicon, and sulfur. the presence of these elements in the spectrum tells astronomers that
The spectrum of a very distant galaxy shows features due to carbon, silicon, and sulfur. the presence of these elements in the spectrum tells astronomers that the galaxy must have had an entire generation of stars that was born, lived, and died.
Absorption lines, not emission lines, were discovered in investigations of the Sun's spectrum (dark lines against the brighter continuum). Until Gustav Kirchhoff revealed in 1859 that the same substance can either create emission lines (when a hot gas emits its own light) or absorption lines, the precise origin of these "Fraunhofer lines," as we now refer to them, was unknown for a long time (when a light from a brighter, and usually hotter, source is shone through it). With that finding, spectroscopy became a viable method for analyzing the chemical makeup of stars.
Chemical elements can be found in other things besides stars. We can search for the signatures of elements in any spectrum from any object. Nebula and supernova leftovers are among.
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an inelastic collision between two objects is characterized by the following a) total momentum of the system is conserved b) total energy of the system is conserved c) total kinetic energy of the system remains constant d) both a and b are true e) both a and c are true
An inelastic collision between two objects is characterized by the fact that a) the total momentum of the system is conserved. Choice A is correct
Inelastic collisions are the collisions in which the kinetic energy is lost. The momentum of the system is conserved in inelastic collisions, but kinetic energy is not. This is because some of the kinetic energy was transferred to another.
Suppose two similar cars are approaching. They collide, but the sled is equipped with a magnetic clutch so that when they collide they combine into a single agglomerate. This type of collision is completely inelastic as the maximum possible kinetic energy is lost. This does not mean that the final kinetic energy of the system is necessarily zero. Momentum is not yet maintained.
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a bullet fired from a rifle begins to fall when?
Answer: As soon as it leaves the barrel.
Explanation:
A bullet fired from a rifle begins to fall immediately upon leaving the barrel. Despite its initial forward momentum, the bullet is subject to the force of gravity.
The gravitational force acts vertically downward and causes the bullet to accelerate downward due to its free fall. However, due to its initial high velocity, the bullet's downward acceleration is minimal compared to its forward motion. As a result, the bullet follows a curved trajectory known as a ballistic trajectory.
Over time, the effects of gravity become more significant, causing the bullet to gradually descend and eventually hit the ground, following a parabolic path.
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A source vibrating at constant frequency generates a sinusoidal wave on a string under constant tension. If the power delivered to the string is quadrupled, by what factor does the amplitude change?.
If the power is quadrupled, The amplitude changes by factor of 2 means double.
What is meant by Amplitude?The greatest displacement or distance moved by a point on a vibrating body or wave from its equilibrium position. It is one-half of the length of the vibration path.
Given,
If the amount of power applied to the string is quadrupled.
The power transmitted by a sinusoidal wave on a stretched string formula is,
P=[tex]1/2[/tex](μω²A²v)
Where μ mass per unit length
ω=angular speed
A= amplitude
v=wave speed
P=power delivered.
We only need two terms in this case: power and amplitude.
P∝ A²
For our problem, all other quantities are constant.,
A= k √P
Where k= constant
Power is quadrupled here, which means four times.,
A=√4P
A=2√P
Changing the amplitude by a factor of two means doubling.
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a baseball and a bowling ball with the same momentum are rolling toward you. which one needs more efforts (either longer time or larger force) to be stopped?
The baseball will require longer time and the bowling ball will require more effort to be stopped.
The bowling ball and baseball is moving with same momentum.
Let us say the momentum of the bowling ball is MV and the momentum of the baseball is mv.
According to second law of newton,
F = ΔMV/Δt
F = MΔv/Δt
So, the force is directly proportional to the speed of the object.
The speed of the bowling ball will be less than that of the baseball because the mass of the bowling ball is more and the mass of the baseball is less.
So, a greater force will be required to stop the baseball ball,
F = mΔv/Δt
v is more and the contact period Δt of the transfer of momentum is less so baseball will require longer time and a grater force will be required to stop the bowling ball because the speed is less.
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Calculate the efficiency of a machine that requires 20 J of input work to do 10 J of output work. What is the efficiency of the machine? (in percent, but write the number only)
The efficiency of the machine is ξ= 50%.
Given - 20 joules and 30 joules are input and output work of the system respectively.
To find the efficiency of the system.
principle ;- Efficiency represents the capability of a system to do work .
Mathematically , efficiency has an equation that relates the input and output work and accurately provides the result.
Formula - ξ= οₙ/Iₙ x 100
οₙ = output work , Iₙ= input work
Calculations :- ξ= { 10/20 }x 100
ξ= 50%
Result- The Efficiency of the machine is 50%.
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if at a particular instant and at a certain point in space the electric field is in the x-direction and has a magnitude of 5.00 v/m , what is the magnitude of the magnetic field of the wave at this same point in space and instant in time? express your answer in teslas.
The magnitude of the magnetic field of the wave at this same point in space and instant in time is 1.67 × 10 ⁻⁸ T
The direction of the electric field is pointing in the positive x direction and the direction of propagation of the wave is in the positive z direction. Therefore, the direction of the magnetic field is in the positive y direction. Because in an electromagnetic wave, the direction of the electric field, the direction of wave propagation, and the magnetic field all lie perpendicular to each other.
According with the right-hand rule, the thumb points within the route of the current, the hands factor inside the course of the magnetic subject, and the resulting pressure at the charge points outwards from the palm. The pressure on a negatively charged particle is inside the opposite path.
Calculation:-
B₀ = E₀/c
= 5 / 3 × 10⁸
The magnitude of the magnetic field is equal to = 1.67 × 10 ⁻⁸ T
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the picture tube in a television uses magnetic deflection coils rather than electric deflection plates. suppose an electron beam is accelerated through a 55.0 -kv potential difference and then through a region of uniform magnetic field 1.00 cm wide. the screen is located 6.0 cm from the center of the coils and is 60.0 cm wide. when the field is turned off, the electron beam hits the center of the screen. what field magnitude is necessary to deflect the beam to the side of the screen? ignore relativistic corrections.
The field magnitude required to divert the beam away from the screen is 3.1588 × [tex]10^{-4}[/tex].
A magnetic force is applied to a charged particle when it enters a magnetic field. This force's strength is determined by the particle's speed, magnetic field, and charge density. Fleming's Left Hand Rule determines the force's direction. The component of the velocity transverse to the magnetic field provides the required centripetal force if the charged object arrives at an angle.
V = 55.0 kV
d = 1.00cm
Tan∅ = ((1 ÷ 2) × 60) ÷ 6.0 = 5
∅ = 26.6°
Sin∅ = 1 ÷ R
R = 1 ÷ Sin(26.6°)
R = 1 ÷ 0.44
R = 2.27
Total work completed equals Kinectic Energy change
1 ÷ 2 mv² = qΔV
0.5 × 9.1 × [tex]10^{-31}[/tex] × v² = 1.6 × [tex]10^{-19}[/tex] × 55.0 × [tex]10^{3}[/tex]
v² = (8.8 × [tex]10^{-15}[/tex]) ÷ (4.55 × [tex]10^{-31}[/tex])
v² = 1.93 × [tex]10^{16}[/tex]
v = √1.93 × [tex]10^{16}[/tex]
v = 138924439
v = 1.3 × [tex]10^8[/tex]
The magnetic force produces the centripetal force.
qvB = mv² ÷ R
B = (mv ÷ qR)
B = (9.1 × [tex]10^{-31}[/tex] × 1.3 × [tex]10^8[/tex]) ÷ (1.6 × [tex]10^{-19}[/tex] × 2.27)
B = (11.83 × [tex]10^{-23}[/tex]) ÷ (3.745 × [tex]10^{-19}[/tex])
B = 3.1588 × [tex]10^{-4}[/tex]
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a roller coaster moves 85 m horizontally, then travels 45 m at an angel of 30 above the horizontal. what is its displacement from its starting point? use graphical techniques.
Explanation:
done with the meeting today so I m ready for bed k tai you
Answer:
Explanation:
Dx = 85 + 45·cos 30° = 85 + 45·(√3 / 2) ≈ 124 m
Dy = 45·sin 30° = 45·(1/2) = 22.5 m
D = √ (Dx² + Dy²) = √ (124² + 22.5²) ≈ 126 m
. suppose that the central diffraction envelope of a double-slit diffraction pattern contains 11 bright fringes and the first diffraction minima eliminate (are coincident with) bright fringes. how many bright fringes lie between the first and second minima of the diffraction envelope?
7 bright fringes lie between the first and second minima of the diffraction envelope.
Diffraction is defined because of the interference or bending of waves around the corners of an obstacle or via an aperture into the vicinity of the geometrical shadow of the impediment/aperture. The diffracting object or aperture correctly becomes a secondary source of the propagating wave.
Refraction is the alternate in direction of waves that takes place whilst waves journey from one medium to another. Refraction is always accompanied by means of a wavelength and speed alternate. Diffraction is the bending of waves around barriers and openings. the amount of diffraction increases with increasing wavelength.
Calculation:-
Here d = 15 a/2(since there are 15 bright fringes ).
Then for the first minimum which occurs at an angle1
then a sin? 1 =? (m=1)
For the second minimum which occurs at an angle= of 2
then a sin?2 = 2? (m=2)
then we calculate the values of m for which
1 < ?< ?2 for sin?1 < sin?< sin?2 ? < 2m?/15 <2?
that is 1<2m/15 <2
Hence, there are 7 bright fringes.
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a ball is kicked with an initial velocity of 23 m/s in the horizontal direction and 14 m/s in the vertical direction. (assume the ball is kicked from the ground. for each answer, enter a number.) (a) at what speed (in m/s) does the ball hit the ground? m/s (b) for how long (in s) does the ball remain in the air? s (c) what maximum height (in m) is attained by the ball?
The speed of the ball is 192m/s. The long of the ball is 2.85s.The height of the ball is 2.13m.
How to calculate speed?A)The speeds at these points are equal since the starting position and the point at which it touches the ground have the same elevation. Solving the product of the horizontal and vertical velocities yields the final speed. Which is
vf=√(V[tex]ox[/tex])²+(V[tex]oy[/tex])²
vf=√(23m/s)²+(14m/s)²
vf=192m/s
How to calculate long?B)Take into account the starting point and the highest point, respectively.
We are aware that the vertical velocity is zero at the highest point. Additionally, we are aware that the duration of the flight from start to finish is twice as long.
So, we'll apply the formula t=v[tex]f[/tex]-v[tex]o[/tex]/a
t=2(v[tex]top[/tex]-v[tex]o[/tex])/a
t=2(0m/s-14m/s)/-9.81m/s
t=2.85s
How to calculate height?C)Using the formula, the highest height that can be reached can be determined.(v[tex]f[/tex])²=(v[tex]0[/tex])²+2ay
This is how the maximum height is determined:
(v[tex]f)[/tex]²=(v[tex]0)[/tex]²+2ay
y[tex]max[/tex]=(v[tex]top[/tex])²-(v[tex]o[/tex])²÷2a
y[tex]max[/tex]=(0m/s)²-(14m/s)²÷2(-9.81m/s)²
=2.13m
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at its peak, a tornado is 64.0 m in diameter and carries 100 km/h winds. what is its angular velocity in revolutions per second?
The angular velocity of tornado Which having 64m diameter and having velocity of 100 km/h is 0.138 revolutions per second.
How to calculate angular velocity ?A pseudovector that depicts the rate at which the angular position or orientation of an object varies over time is called an angular velocity or rotational velocity.The pseudovector's direction is normal to the instantaneous plane of rotation or angular displacement, and its magnitude corresponds to the object's angular speed, or the rate at which it rotates or revolves. The right-hand rule is typically used to specify the direction of angular motion.Generally speaking, angular velocity has an angle per unit time dimension. Since the radian is a dimensionless quantity and the SI unit of angular velocity is radians per second, the SI units of angular velocity can be written as s−1. Omega is a common way to represent angular velocity. According to convention, a positive angular velocity denotes a rotation that is counterclockwise and a negative one is clockwise.Angular velocity ω=v/r
Where v is linear velocity
r = radius of circle
ω = 100/32
= 8.29 rpm
Convert to revolutions per second
= 0.138 revolutions per second.
Angular velocity of tornado is 0.138 rps.
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a 1,200 kg car can accelerate with a force of 3,000n. if the car is stopped at a red light and then accelerates for 15 s after the light turns green, how far (in m) will the car be from the light?
Acceleration: the rate at which the speed and direction of a moving object vary over time.A point or object going straight ahead is accelerated when it accelerates or decelerates.
Find the Acceleration ?Three different accelerated motion types exist: average acceleration, non-uniform acceleration, and uniform acceleration.
a = F / m
1 N = 1 kg•m/s²
F = ma; where F = force in newtons (N), m = mass in kg, and a = acceleration in m/s².
Known and Unknown
F = 3000 N = 3000kg•m/s²
m = 1200 kg
a = F/m
a = (3000 kg•m/s²)/(1200 kg)
Kilograms cancel.a = 2.5m/s²
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what is the work done by the force of gravity on the beachball during this process? give your answer with the correct sign (positive or negative).
The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.
Is work done by gravity positive or negative?Work done by a force is defined as the sum of an object's or particle's displacement and the component of the force acting in the direction of the object's motion.The product of an object's displacement and the component of the applied force that is directed in the direction of the object's displacement is known as the work done by a force.Depending on which way an object is going, the amount of work done to overcome gravity can either be negative or positive.The work done by gravity will be negative if the object goes upward since gravity pulls in the opposite direction from the displacement. The work done by gravity will be positive if an object moves downward since both gravity and displacement are moving in the same direction.To Learn more About gravity refer to :
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What is the velocity of a 1.2 kg ball rolling with a momentum of 15.6 kg m/s?
Answer:
Velocity V = 13 m/s
Explanation:
Given:
m = 1.2 kg
p = 15.6 kg·m/s
__________
V - ?
Momentum:
p = m·V
Velocity:
V =p /m = 15.6 / 1.2 ≈ 13 m/s
