What is the area of the trapezoid shown below?

Answer:

Hey there!

We can write an equation:

x+x+1+x+2=7

3x+3=7

3x+4

x=4/3

The lines are 4/3, 7/3, and 10/3.

Let me know if this helps :)

Answer:

Cada uno de ellos gana:

S/. 24

S/. 36

Step-by-step explanation:

Planteamiento:

a + b = 60

a = 12 + b

Desarrollo:

sustituyendo el valor de la segunda ecuación del planteamiento en la primer ecuación del planteamiento:

(12+b) + b = 60

2b + 12 = 60

2b = 60 - 12

2b = 48

b = 48/2

b = 24

de la segunda ecuación del planteamiento:

a = 12 + b

a = 12 + 24

a = 36

Check:

24 + 36 = 60

Answer: 4/15

Step-by-step explanation:

Answer:

[tex]\frac{4}{15}[/tex]

Step-by-step explanation:

Number sentence: [tex]30x^{2}[/tex] = [tex]8x[/tex]

You can start by applying algebra to the left side of the equation by dividing each side by x. This should be how it looks now: 30x = 8

Now divide each side by 30 to keep reducing it: [tex]x = \frac{8}{30}[/tex]

Now that we have [tex]\frac{8}{30}[/tex], we can reduce that by dividing the top and bottom by 2:

[tex]\frac{8}{30} = \frac{4}{15}[/tex].

Therefore, the number is [tex]\frac{4}{15}[/tex].

Work Shown:

1 square yard = 15.40 dollars

45.5*1 square yard = 45.5*15.40 dollars

45.5 square yards = 700.70 dollars

In the second step, I multiplied both sides by 45.5 to turn the "1 square yard" into "45.5" square yards.

Answer: $160,000

Step-by-step explanation:

Given the following :

Earning per share (EPS) = $0.55

Number of outstanding shares = 200,000

Preferred dividend = $50,000

EPS = (NET INCOME - PREFERRED DIVIDEND) / NUMBR OF OUTSTANDING SHARES

0.55 = ( NET INCOME - 50000) / 200000

200000 × 0.55 = NET INCOME - 50000

110,000 = NET INCOME - 50000

NET INCOME = 110,000 + 50,000

NET INCOME = $160,000

Answer:

HOME CARE & WELLNESS BASIC PET CARE HOW LONG CAN YOU SAFELY LEAVE A CAT ALONE?

BASIC PET CARE

How Long Can You Safely Leave a Cat Alone?

How Long Can You Safely Leave a Cat Alone?

People who live with cats know that they're not nearly as aloof or independent as alleged. Although cats don't require daily walks like dogs, your presence matters to them… and not only because you have the ability to open a can, fill a water bowl and clean a litter box.

Still, there may be times when you must leave your adult cat for overnight or longer. (Kittens younger than four months should not be left alone for more than four hours. Older than that, they can handle another hour or so. When they reach six months, they can tolerate an eight-hour day without company.)

The length of time you can leave a grown-up cat alone depends on the cat, his diet and your environment. Cats who eat dry food that you can make readily available may be left on their own for 24-48 hours as long as fresh water is accessible as well. Beyond that time frame, water may get too dirty to drink and the litter box full.

To prepare for leaving your cat alone, take steps to make your absence as low‐stress on him as possible. This should include a conversation with your veterinarian.

Answer:

31

Step-by-step explanation:

multiple 5 into 7 that is equal to I week than find the answer that is equal to 35 and minas it by 4 that is equal to 31

Hi there! :)

Answer:

[tex]\huge\boxed{\frac{1}{25}}[/tex]

When evaluating an expression with a negative exponent, the reciprocal will need to be taken. Therefore:

[tex]5^{-2} = \frac{1}{5^{2} } = \frac{1}{25}[/tex]

Answer:

0

Step-by-step explanation:

The numerical coefficient of the linear term of the quadratic equation is 0 because there is no linear term, and 0 times any number or term is 0, or nothing.

Answer:

Below

Step-by-step explanation:

For a given shape to be a rhombus, it should satisfy these conditions:

● The diagonals should intercept each others in the midpoint.

● The diagonals should be perpendicular.

● The sides should have the same length.

We will prove the conditions one by one.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let's prove that the diagonals are perpendicular:

To do that we will write express them as vectors

The two vectors are EG and DF.

The coordinates of the four points are:

● E(0,2c)

● G (0,0)

● F (a+b, c)

● D (-a-b, c)

Now the coordinates of the vectors:

● EG (0-0,0-2c) => EG(0,-2c)

● DF ( a+b-(-a-b),c-c) => DF (2a+2b,0)

For the diagonals to be perpendicular the scalar product of EG and DF should be null.

● EG.DF = 0*(2a+2b)+(-2c)*0 = 0

So the diagonals are perpendicular.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let's prove that the diagonals intercept each others at the midpoints.

The diagonals EG and DF should have the same midpoint.

● The midpoint of EG:

We can figure it out without calculations. Since G is located at (0,0) and E at (0,2c) then the distance between E and G is 2c.

Then the midpoint is located at (0,c)

● The midpoint of DF:

We will use the midpoint formula.

The coordinates of the two points are:

● F (a+b,c)

● D(-a-b,c)

Let M be the midpoint of DF

●M( (a+b-a-b,c+c)

● M (0,2c)

So EG and DF have the same midpoint.

■■■■■■■■■■■■■■■■■■■■■■■■■■

There is no need to prove the last condition, since the two above guarante it.

But we can prove it using the pythagorian theorem.

Answer:

he invented the point

he was a German mathematician

he  Hilbert's improvements to geometry are still used in textbooks today

he developed Hilbert's axioms

Step-by-step explanation:

Answer:

He was a German mathematician.

If only one is true then you're good to go.

Whoops never mind.. :/

Answer:

The answer is A pls mark me brainly

Answer:

C

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

The lower quartile range is shown by the bottom of the box which is at 10.

The median is shown in the middle line, which is closer to 18 than 18.5.

The upper quartile range in the end of the box, which is at 22!

(You can also look at the picture attached if that helps.)

Answer:

Step-by-step explanation:

[tex]\sin \left(30^{\circ \:}\right)+\cos \left(60^{\circ \:}\right)-1\\\\\mathrm{Use\:the\:following\:trivial\:identity}:\\\quad \sin \left(30^{\circ \:}\right)=\frac{1}{2}\\\\\mathrm{Use\:the\:following\:trivial\:\\identity}:\\\quad \cos \left(60^{\circ \:}\right)=\frac{1}{2}\\\\=\frac{1}{2}+\frac{1}{2}-1\\\\=0[/tex]

[tex]\\\cos \left(60^{\circ \:}\right)+\tan \left(30^{\circ \:}\right)-1\\\\\mathrm{Use\:the\:following\:trivial\:identity}:\\\quad \cos \left(60^{\circ \:}\right)=\frac{1}{2}\\\mathrm{Use\:the\:following\:trivial\:identity}:\\\quad \tan \left(30^{\circ \:}\right)=\frac{\sqrt{3}}{3}\\\\=\frac{1}{2}+\frac{\sqrt{3}}{3}-1\\\\=-\frac{1}{2}+\frac{\sqrt{3}}{3}[/tex]

Answer:

This is multiplicative identity in which 4✖️1=4

Step-by-step explanation:

Hope it will help you:)

Answer:

-11 and -10

Step-by-step explanation:

● -√120 = -1 × √120

● -√120 = -1 × 2√30

● 30 is close to 25 so √30 is close to five but greater than it.

Multiplying 5 by -2 gives -10

Multipluing √30 by -2 gives you a number that is close to -10 but smaller than it.

So -√120 lies between -11 and -10

Answer:

331 the biggest possible number

Answer:

Linear f(x) = 2·x + 3

Quadratic f(x) = x² + 2·x - 3

Exponential f(x) = 3ˣ - 2

Step-by-step explanation:

1) Linear function

The general form of the linear equation is of the form, f(x) = y = m·x + c

Where;

m = The slope

c = y-intercept (Constant)

The linear function is therefore, f(x) = 2·x + 3

2) Quadratic function

The general form of the quadratic function is f(x) = a·x² + b·x + c

Where;

a, and b are the coefficients of x² and x respectively and c is the constant term

Therefore,  f(x) = x² + 2·x - 3, is a quadratic function, with a = 1, b = 2, and c = -3

3) Exponential function

The general form of the exponential function is f(x) = a·bˣ + k

Where;

a = The initial

b = The multiplier (growth or decay value)

k = vertical shift

Therefore, the function f(x) = 3ˣ - 2 is an exponential function with the initial = 1, b= 3, and k = -2

Answer:

grade point average​ (GPA) as a weighted mean = 3.14

Yes, student makes the Dean's list.

Step-by-step explanation:

Since the data is not given I will explain the question with a relevant example:

For example

Data:

Students grades are:  A, C, B, A, D

The corresponding number of credit hours: 3, 3, 3, 4, 1

The grading system assigns quality points to letter grades as​:

A = 4

B = 3

C = 2

D = 1

F = 0

To find:

grade point average​ (GPA) as a weighted mean

If the​ Dean's list requires a GPA of 3.00 or​ greater, did this student make the​ Dean's list?

Solution:

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]

Here

Using the earned grades of A, C, B, A, D and corresponding quality points to these letter grades we get:

A = 4

C = 2

B = 3

A = 4

D = 1

So the values in x[tex]_{i}[/tex] are:

x

4

2

3

4

1

Now the number of credit hours are represented as weights w[tex]_{i}[/tex] :

w

3

3

3

4

1

In order to calculate weighted mean first multiply x[tex]_{i}[/tex] with w[tex]_{i}[/tex]

x[tex]_{i}[/tex] w[tex]_{i}[/tex]

4 * 3 = 12

2 * 3 = 6

3 * 3 = 9

4 * 4 = 16

1 * 1 = 1

The sum of x[tex]_{i}[/tex] w[tex]_{i}[/tex] is :

Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] = 12 + 6 + 9 + 16 + 1 = 44

Σx[tex]_{i}[/tex] w[tex]_{i}[/tex]  =  44

Now compute the sum of w[tex]_{i}[/tex]

Σw[tex]_{i}[/tex] = 3 + 3 + 3 + 4 + 1 = 14

Σw[tex]_{i}[/tex] = 14

Putting the values in the weighted mean formula:

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex]

                           =  44 / 14

                           = 3.1429

Weighted Mean =   Σx[tex]_{i}[/tex] w[tex]_{i}[/tex] / Σw[tex]_{i}[/tex] = 3.14

Since the​ Dean's list requires a GPA of 3.00 or​ greater and the grade point average​ (GPA) as a weighted mean of the student is 3.14 so the student makes the​ Dean's list because his/her GPA is higher than 3.00

Answer:

This is because there are equal counts of both even and odd numbers

Step-by-step explanation:

Here in this question, we are concerned with stating the reason why it is likely that a standard number cube have the same probability for showing an even number as well as an odd number.

In the number cube, the odd numbers are 1,3 and 5. While the even numbers are 2,4 and 6.

From here, we can see that there are three set of each number types. What this automatically means is that the probability of selecting an even number will be equal to the probability of selecting an odd number. Thus, we can say that it is just as likely that the cube will show an even number as an odd number because each of the type of numbers have 3 values each.

Answer:

18

Step-by-step explanation:

3⋅6−2+2​

Use PEMDAS = Parentheses, Exponent, Multiplication, Division, Addition, Subtraction

First we multiply, then add or subtract so,

18 - 2 + 2

Now we subtract,

16 + 2

Now we add,

18

Company a samples 16 workers, and their average time with the company is 5.2 years with a standard deviation of 1.1. Company b samples 21 workers and their average time with the company is 4.6 years with a standard deviation 4.6 years

The populations are normally distributed.  Determine the:

Hypothesis in symbolic form?

Determine the value of the test statistic?

Find the critical value or value?

determine if you should reject null hypothesis or fail to reject?

write a conclusion addressing the original claim?

Answer:

Step-by-step explanation:

GIven that :

Company A

Sample size n₁ = 16 workers

Mean [tex]\mu[/tex]₁ = 5.2

Standard deviation [tex]\sigma[/tex]₁ = 1.1

Company B

Sample size n₂ = 21 workers

Mean [tex]\mu[/tex]₂ = 4.6

Standard deviation [tex]\mu[/tex]₂ = 4.6

The null hypothesis and the alternative hypothesis can be computed as follows:

[tex]H_o : \mu _1 = \mu_2[/tex]

[tex]H_1 : \mu _1 > \mu_2[/tex]

The value of the test statistics can be determined by using the formula:

[tex]t = \dfrac{\overline {x_1}- \overline {x_2}}{\sqrt{\sigma p^2( \dfrac{1}{n_1}+\dfrac{1}{n_2})}}[/tex]

where;

[tex]\sigma p^2= \dfrac{(n_1 -1) \sigma_1^2+ (n_2-1)\sigma_2^2}{n_1+n_2-2}[/tex]

[tex]\sigma p^2= \dfrac{(16 -1) (1.1)^2+ (21-1)4.6^2}{16+21-2}[/tex]

[tex]\sigma p^2= \dfrac{(15) (1.21)+ (20)21.16}{35}[/tex]

[tex]\sigma p^2= \dfrac{18.15+ 423.2}{35}[/tex]

[tex]\sigma p^2= \dfrac{441.35}{35}[/tex]

[tex]\sigma p^2= 12.61[/tex]

Recall:

[tex]t = \dfrac{\overline {x_1}- \overline {x_2}}{\sqrt{\sigma p^2( \dfrac{1}{n_1}+\dfrac{1}{n_2})}}[/tex]

[tex]t = \dfrac{5.2- 4.6}{\sqrt{12.61( \dfrac{1}{16}+\dfrac{1}{21})}}[/tex]

[tex]t = \dfrac{0.6}{\sqrt{12.61( \dfrac{37}{336})}}[/tex]

[tex]t = \dfrac{0.6}{\sqrt{12.61(0.110119)}}[/tex]

[tex]t = \dfrac{0.6}{\sqrt{1.38860059}}[/tex]

[tex]t = \dfrac{0.6}{1.178388981}[/tex]

t = 0.50917

degree of freedom df = ( n₁ + n₂ - 2 )

degree of freedom df = (16 + 21 - 2)

degree of freedom df = 35

Using Level of  significance ∝ = 0.05, From t-calculator , given that t = 0.50917 and degree of freedom df = 35

p - value =  0.3069

The critical value [tex]t_{\alpha ,d.f}[/tex] = [tex]t_{0.05 , 35}[/tex] = 1.6895

Decision Rule: Reject the null hypothesis if the test statistics is greater than the critical value.

Conclusion: We do not reject the null hypothesis because, the test statistics is lesser than the critical value, therefore we conclude that there is  no sufficient information that the claim that company a retains it workers longer than more than company b.

Answer:

Hey... Ans is in the pic..

Hope it helped u if yes mark me mark me BRAINLIEST!

Tysm!

:)

1: 8 faces and 9 with the base 9 vertices and 16 edges

2: 3 faces and 5 with the bases 6 vertices and 9 edges

3: 3 faces and 4 with the base 4 vertices and 6 edges

Hope this can help you.

Answer:

Step-by-step explanation:

A pyramid has twice as many edges as faces, and 1 more vertex than faces.

Octa- means 8.

Tri- means 3.

a) An octagonal pyramid has 8 faces, 16 edges, and 9 vertices.

b) A triangular pyramid has 3 faces, 6 edges, and 4 vertices.

__

A triangular prism will have 3 additional edges for the second "base", and 2 additional vertices.

c) A triangular prism has 3 faces, 9 edges, and 6 vertices.

__

Additional comments

We have not counted the base as a "face." We have only counted those that meet at the point of the pyramid.

There are as many vertices on the base as there are faces, and there is one more vertex where all the faces meet.

There is one edge at the base for each face, and there is one edge from the base vertex to the point of the pyramid for each face--a total of two edges per face.

__

A triangular pyramid is shown in the attachment.

Answer:

x = 7.5

Step-by-step explanation:

Step 1: Create a fraction with the known sides

[tex]\frac{x}{10}[/tex]

Step 2: Set the fraction equal to the scale factor

[tex]\frac{x}{10}=\frac{0.75}{1}[/tex]

Cross multiple to solve for x

[tex]x = 7.5[/tex]

Therefore x is equal to 7.5

Answer:

7.5

Step-by-step explanation:

did it on khan

Answer:

The asnwer is 6.37 y

Step-by-step explanation:

You have to add them sum means addition

I hope this helps

Answer:

-2x

Step-by-step explanation:

-2x-7+9-2

Combine like terms

-2x +0

-2x

Answer:

-2x

Step-by-step explanation:

from the question

-2x-7+9-2=

step 1

collect the like terms

we have,

-2x-7+9-2

-2x + 2 -2

-2x + 0

-2x

therefore the answer to the question -2x-7+9-2 is equal to -2x

Answer:

v = 6

Step-by-step explanation:

3/v = 2/4

We can use cross products to solve

2v = 3*4

2v = 12

Divide each side by 2

2v/2 = 12/2

v =6

Answer:

v=6

Step-by-step explanation:

If this is making them equal, then you should know that 2/4 is 1/2 , so you could just multiply 3 by both the 1 and the 2 in 1/2 and 1 times 3 is 3 which is what we have and 2 times 3 is 6 which is v.

Answer:

[tex]\frac{5}{9}[/tex]

Step-by-step explanation:

Using the rules of exponents/ radicals

[tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex] , [tex]a^{0}[/tex] = 1

[tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

Given

[tex]27^{-\frac{2}{3} }[/tex] × [tex]25^{\frac{1}{2} }[/tex] × [tex]5^{0}[/tex]

= [tex]\frac{1}{27^{\frac{2}{3} } }[/tex] × [tex]\sqrt{25}[/tex] × 1

= [tex]\frac{1}{9}[/tex] × 5 × 1

=[tex]\frac{5}{9}[/tex]

Answer:

Option 1 and option 4

Step-by-step explanation:

The inverse of 12^2 is the √12 so option 4 is correct. 12^1/2 also equals √12 so option 1 is also correct.

Answer:

12 [tex]\frac{2}{1}[/tex]

Step-by-step explanation:

Answer:The first issue one most notice is the words “at least” We are trying to find the probability of at least 2 girls.

The five possible outcomes for girls are 0,1,2,3,4. The odds of 1 girl out of 4 is .25 and the odds of 1 boy out of 4 is .25 (same as the odds of 3 out of 4 girls). Therefore the odds of 1 OR 3 girls must be .5 because 1 girl and 3 girls each has a .25 probability. If the probability of (1 OR 3 girls) equals .5, then the probability of 2 girls must be a different number.

The probability of 2 or more girls, is the sum of the probability of 4 girls (.06125)(—-.5 to the 4th power—— ), plus the probability of 3 girls (.25)——(the same as the probability of 1 boy)—- plus the probability of 2 girls. Since we know the probability of zero boys is .0625 (again, .5 to the 4th power) and the probability of 1 boy is .25 (the same as the probability of 3 girls )———then the probability of 2 girls is ((1 minus (the sum of the probability of 0 OR 1 boys) plus the (sum of the probability of 3 or 4 girls)), or 1-((.0625+.25)+(.0625+.25)), or .375. We had to derive the probability of two from the other known probabilities. Therefore .375+.25+.0625=.6875 is the probability of both AT LEAST 2 girls and also NO MORE than 2 boys. Notice this adds up to 1.375 because the probability of the central number 2 (i.e., .375) appears on both sides.