what is the average power necessary to move a 35 kg block up a frictionless 30º incline at 5 m/s? group of answer choices 68 w 121 w 343 w 430 w 860 w

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Answer 1

The average power necessary to move a 35 kg block up a frictionless 30° incline at 5 m/s is 121 W.

To calculate the average power required, we can use the formula: Power = Work / Time. The work done in moving the block up the incline can be determined using the equation: Work = Force * Distance. Since the incline is frictionless, the only force acting on the block is the component of its weight parallel to the incline. This force can be calculated using the formula: Force = Weight * sin(theta), where theta is the angle of the incline and Weight is the gravitational force acting on the block. Weight can be determined using the equation: Weight = mass * gravitational acceleration.

First, let's calculate the weight of the block: Weight = 35 kg * 9.8 m/s² ≈ 343 N. Next, we calculate the force parallel to the incline: Force = 343 N * sin(30°) ≈ 171.5 N. To determine the distance traveled, we need to find the vertical displacement of the block. The vertical component of the velocity can be calculated using the equation: Vertical Velocity = Velocity * sin(theta). Substituting the given values, we get Vertical Velocity = 5 m/s * sin(30°) ≈ 2.5 m/s. Using the equation for displacement, we have Distance = Vertical Velocity * Time = 2.5 m/s * Time.

Now, substituting the values into the formula for work, we get Work = Force * Distance = 171.5 N * (2.5 m/s * Time). Finally, we can calculate the average power by dividing the work done by the time taken: Power = Work / Time = (171.5 N * (2.5 m/s * Time)) / Time = 171.5 N * 2.5 m/s = 428.75 W. Therefore, the average power necessary to move the 35 kg block up the frictionless 30° incline at 5 m/s is approximately 121 W.

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Related Questions

puck 1 is moving 10 m/s to the left and puck 2 is moving 8 m/s to the right. they have the same mass, m.

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If the two pucks, which have the same mass, are moving towards each other, the speed and direction of their movements can be used to calculate the final velocity of both pucks.The law of conservation of momentum states that the momentum of an isolated system remains constant if no external forces act on it.

The momentum before the collision is equal to the momentum after the collision in an isolated system.Considering the given values, if Puck 1 is moving to the left at 10 m/s and Puck 2 is moving to the right at 8 m/s, their velocities are opposite. Therefore, they are moving towards each other.When two pucks with the same mass collide, their velocities and momenta are conserved. If both pucks stick together after the collision, their final velocity can be calculated using the following equation:m1u1+m2u2=(m1+m2)vwhere m1, u1, m2, and u2 are the masses and initial velocities of the pucks, and v is their final velocity.

The final velocity of the combined pucks can be found by dividing the total momentum by their combined mass, which is given by:v = (m1u1 + m2u2) / (m1 + m2)In this case, the momentum of Puck 1 is:momentum1 = m x v1where v1 = -10 m/s (because Puck 1 is moving to the left)Similarly, the momentum of Puck 2 is:momentum2 = m x v2where v2 = 8 m/s (because Puck 2 is moving to the right)

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(ii) an audience of 1600 fills a concert hall of volume 22,000 m3. if there were no ventilation, by how much would the temperature of the air rise over a period of 2.0 h due to the metabolism of the people (70 w>person)?

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The temperature of the air in the concert hall would rise by approximately 30.53 degrees Celsius over a period of 2.0 hours due to the metabolism of the people.

To calculate the temperature rise due to the metabolism of the people in the concert hall, we need to use the formula:

ΔQ = mcΔT

where ΔQ is the heat energy generated, m is the mass of the air, c is the specific heat capacity of air, and ΔT is the change in temperature.

First, let's calculate the mass of the air in the concert hall. We can use the formula:

m = ρV

where ρ is the density of air and V is the volume of the concert hall.

The density of air at room temperature is approximately 1.2 kg/m³. So, the mass of the air in the concert hall is:

m = 1.2 kg/m³ * 22,000 m³ = 26,400 kg

Next, we can calculate the heat energy generated by the metabolism of the people:

ΔQ = (number of people) * (metabolic rate) * (time)

Given that there are 1600 people and the metabolic rate is 70 W/person, and the time is 2.0 hours:

ΔQ = 1600 * 70 W/person * 2.0 h = 224,000 W·h

Now we can calculate the temperature rise using the formula ΔQ = mcΔT:

ΔT = ΔQ / (mc)

ΔT = 224,000 W·h / (26,400 kg * specific heat capacity of air)

The specific heat capacity of air is approximately 1005 J/kg·K.

ΔT = 224,000 W·h / (26,400 kg * 1005 J/kg·K)

Now we need to convert the heat energy from watt-hours to joules:

1 W·h = 3600 J

ΔT = (224,000 W·h * 3600 J/W·h) / (26,400 kg * 1005 J/kg·K)

Calculating the numerical value:

ΔT ≈ 30.53 K (rounded to two decimal places)

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For an isolated system, the total magnitude of the momentum can change. By that, we mean the sum of the magnitudes of the momentums of each component of the system. O True O False

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False.

The statement, "For an isolated system, the total magnitude of the momentum can change. By that, we mean the sum of the magnitudes of the momentums of each component of the system" is false.

The total momentum of an isolated system, which means that there are no external forces acting on it, remains constant over time. The principle of conservation of momentum applies to all isolated systems, which means that the total momentum before a collision or interaction is equal to the total momentum after the collision or interaction.

The total momentum of an isolated system is calculated by summing the momentum of each individual component of the system. However, the sum of the individual momenta of the components can't be altered once the system is closed.

So, the statement given above is not true, it is false and the sum of individual momenta will always remain the same in an isolated system. Therefore, the answer is False.

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Problem #1: Energy Storage A robot battery is rated at 90 A-h, meaning that under certain test conditions it can output 2A at 6V for 45 hours. a) How much energy is stored in the battery (in Joules)?

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The energy stored in the battery can be calculated by multiplying the voltage, current, and time. Given that the battery can output 2A at 6V for 45 hours, we can calculate the energy as follows: a) The energy stored in the battery is 3,240 Joules.

To calculate the energy, we can use the formula: Energy (Joules) = Voltage (V) × Current (A) × Time (s) First, we convert the given time of 45 hours to seconds by multiplying it by 3600 (60 seconds × 60 minutes): Time (s) = 45 hours × 3600 seconds/hour = 162,000 seconds

Next, we substitute the values into the formula: Energy (Joules) = 6V × 2A × 162,000 seconds = 3,240 Joules. Therefore, the energy stored in the battery is 3,240 Joules. This represents the total amount of energy that the battery can provide when discharged at the specified voltage and current for the given time period.

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Angular momentum of the particle rotating with a central force is constant due to.

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The angular momentum of a particle rotating with a central force is constant due to the conservation of angular momentum. This principle states that the total angular momentum of a system remains constant if no external torque acts on it.

When a particle is rotating with a central force, such as in the case of an object moving in a circular orbit under the influence of gravitational force, the net external torque acting on the particle is zero. This means that there are no external forces causing the object to rotate faster or slower.

The angular momentum of a rotating particle is given by the product of its moment of inertia (a measure of its resistance to rotation) and its angular velocity. Since the net external torque acting on the particle is zero, the angular momentum remains constant.

In simple terms, this means that as the particle moves in its orbit, its angular velocity may change, but the product of its moment of inertia and angular velocity remains the same. For example, if a planet moves closer to the sun, its angular velocity increases to compensate for the decrease in its distance from the sun.

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If you have a resistor with a brown band, a black band, a brown band and a gold band, what value of resistance does this represent? O a. 1 ohm O b. 10 ohms O c. 100 ohms O d. 1K ohms O e. 10K ohms O f. 100K ohms O g. 1MEG ohms

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The resistor with a brown band, black band, brown band, and gold band represents a resistance value of 100 ohms. Therefore, the correct answer is c. 100 ohms.

The color coding on resistors is a standardized system used to represent their resistance values. Each color corresponds to a specific number, and the overall combination of colors determines the resistance value.

In the given resistor with the color bands brown, black, brown, and gold, we can determine the resistance value as follows:

- The brown band represents the first significant digit: 1.

- The black band represents the second significant digit: 0.

- The third band (brown) represents the multiplier : 10¹, or 10.

- The fourth band (gold) represents the tolerance, which indicates the acceptable range of deviation from the nominal value.

In this case, gold represents a tolerance of ±5%.

Combining these values, we have 10 x 1 with a tolerance of ±5%, resulting in a resistance value of 100 ohms.

Therefore, the correct answer is c. 100 ohms.

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a rope is used to pull a 10 kg block across the floor with an acceleration of 3 m/s2. if the frictional force acting on the block is 49 n, what is the tension in the rope?

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The tension in the rope is 79 N.

To determine the tension in the rope, we need to consider the forces acting on the block. We know the block has a mass of 10 kg and is being pulled with an acceleration of 3 m/s². Additionally, there is a frictional force of 49 N opposing the motion.

First, let's calculate the net force acting on the block. We can use Newton's second law of motion, which states that the net force is equal to the mass of an object multiplied by its acceleration (F = m * a). Plugging in the given values, we have:

Net force = (10 kg) * (3 m/s²) = 30 N

Now, the tension in the rope is responsible for providing this net force. However, we also need to consider the opposing force of friction. The tension in the rope can be split into two components: one that overcomes friction and the other that accelerates the block.

Since the frictional force is given as 49 N, the tension in the rope must be at least 49 N to overcome friction. Therefore, the tension in the rope responsible for accelerating the block can be calculated by subtracting the frictional force from the net force:

Tension = Net force - Frictional force = 30 N - 49 N = -19 N

However, tension is a positive quantity, so we take the absolute value:

Tension = |-19 N| = 19 N

Therefore, the tension in the rope is 19 N.

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a rocket is used to place a synchronous satellite in orbit about the earth. what is the speed of the satellite in orbit? 4070 m/s 2070 m/s 3070 m/s

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The speed of the satellite in orbit is given by 3070 m/s.

We have given that a rocket is used to place a synchronous satellite in orbit about the earth.

Let's derive the equation for the speed of the satellite in orbit about the earth:

We know that the acceleration due to gravity (g) at a height (h) above the earth's surface is given by,

                   g = GM / (R + h)²Here,M = Mass of the earthR = Radius of the earthG = Gravitational constanth = Height above the surface of the earth

Now, the force of gravity acting on the satellite is given by,

                          F = m gwhere m is the mass of the satellite

As the satellite is in circular motion, there is a centripetal force that is given by,

                              F = m v² / R

 where v is the speed of the satellite in orbit and R is the distance of the satellite from the center of the earth.

The above two equations are equal to each other,m g = m v² / Rg = v² / Rv = √(g R)

Now, substituting the values of R and g, we getv = √(GM / (R + h))

Putting values,G = 6.67 × 10⁻¹¹ N m² / kg²M = 5.97 × 10²⁴ kgR = 6371 km = 6371000 mh = 0 (as the synchronous satellite orbits the earth at the same angular rate as the earth rotates)

On substituting the above values, we getv = √(6.67 × 10⁻¹¹ × 5.97 × 10²⁴ / (6371000))v = 3070 m/s

Therefore, the speed of the satellite in orbit is 3070 m/s.

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A ma current flows through both a diode and a resistor what is the net current noise assume a bandwidth of which of the two components is responsible for producing the most noise?

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When a current flows through both a diode and a resistor, the net current noise is determined by the combination of the noise generated by each component. The noise in a diode can be due to thermal noise or shot noise, while the noise in a resistor is primarily due to thermal noise.



Thermal noise, also known as Johnson-Nyquist noise, is generated by the random motion of charge carriers in a conductor. It is directly proportional to the resistance and temperature of the component. Shot noise, on the other hand, is caused by the discrete nature of electrical charge and is related to the current flow through the diode.

To calculate the net current noise, you need to consider the noise generated by each component separately. The total noise can be approximated by summing the power spectral densities (PSDs) of the individual noise sources.

In general, the resistor contributes more to the overall current noise compared to the diode. This is because resistors typically have higher thermal noise levels compared to diodes. However, the exact contribution of each component depends on various factors such as their respective resistance values, temperatures, and the bandwidth over which the noise is measured.

To determine which component is responsible for producing the most noise, you would need specific values for the resistances and temperatures, as well as the bandwidth of interest. These values can be used to calculate the PSDs and compare the noise contributions of the diode and the resistor.

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The average distance between the Sun and the Earth's is
R = 1.5 * 108 km. Calculate the distance traveled and
the displacement of the planet after exactly:
-6 months
-1 year

Answers

The distance traveled by the Earth after 6 months or 1 year is equal to the circumference of its orbit (2πR), and the displacement is zero for both time periods. To calculate the distance traveled and the displacement of the Earth after a certain time period, we can use the formula:

Distance = Speed * Time In this case, the speed of the Earth's revolution around the Sun is constant, so we can use the average distance between the Sun and the Earth (R) as the value for speed. Distance traveled after 6 months: The time period is 6 months, which is equal to 0.5 years.

Distance = R * Time

Distance = (1.5 * 10^8 km) * (0.5 years)

Distance = 7.5 * 10^7 km Displacement after 6 months: Displacement refers to the change in position, so we need to consider the direction as well. After 6 months, the Earth would have completed half of its revolution around the Sun, so the displacement is zero. This is because the Earth ends up in the same position relative to the Sun after half a year. Distance traveled after 1 year:

The time period is 1 year.

Distance = R * Time

Distance = (1.5 * 10^8 km) * (1 year)

Distance = 1.5 * 10^8 km

Displacement after 1 year: Similar to the previous case, the Earth completes one full revolution around the Sun in one year, so the displacement is zero. The Earth returns to its initial position after a complete revolution. Therefore, the distance traveled by the Earth after 6 months or 1 year is equal to the circumference of its orbit (2πR), and the displacement is zero for both time periods.

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A 45 cm3 block of iron is removed from an 800∘C furnace and immediately dropped into 200 mL of 20∘C water.
What percentage of the water boils away?

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A negligible amount, approximately 0.0185%, of the water evaporates or boils away when the 45 cm³ block of iron is dropped into the 200 mL of water.

To calculate the percentage of water that boils away when the hot block of iron is dropped into it, we need to consider the energy transferred from the iron to the water.

Given information:

Volume of the iron block (V_iron) = 45 cm³

Initial temperature of the iron block (T_iron) = 800°C

Volume of water (V_water) = 200 mL

Initial temperature of the water (T_water) = 20°C

To find the energy transferred from the iron block to the water, we can use the equation:

Q = m × c × ΔT,

where Q is the heat transferred, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature.

First, let's convert the volumes to liters:

V_iron = 45 cm³ = 45 mL = 0.045 L

V_water = 200 mL = 0.2 L

Next, we need to determine the masses of the iron block (m_iron) and the water (m_water) using their densities and volumes. The density of iron is approximately 7.86 g/cm³.

m_iron = V_iron × density_iron = 0.045 L × 7.86 g/cm³ = 0.3537 kg

m_water = V_water × density_water = 0.2 L × 1 g/cm³ = 0.2 kg

Now, we can calculate the heat transferred from the iron block to the water:

Q = m_water × c_water × ΔT_water

The specific heat capacity of water (c_water) is approximately 4.18 J/(g°C).

ΔT_water = T_final_water - T_initial_water = 100°C

Q = 0.2 kg × 4.18 J/(g°C) × 100°C = 83.6 J

Assuming all the heat transferred from the iron block is used to boil the water, we can calculate the energy required to boil the water using the heat of vaporization of water (L_water) which is approximately 2.26 x 10^6 J/kg.

Energy required to boil the water = m_water × L_water = 0.2 kg × 2.26 x 10⁶ J/kg = 452,000 J

Now, we can calculate the percentage of water that boils away:

Percentage = (Q / Energy required to boil the water) × 100

Percentage = (83.6 J / 452,000 J) × 100 ≈ 0.0185%

Therefore, approximately 0.0185% of the water evaporates or boils away.

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Making use of the Friis equation determine the power received (in dBm) for a transmit power of 1W assuming a distance of 10 miles and receive and transmit antenna gains of 0dB and 10dB, respectively. Assume a frequency of 1GHz.

Answers

The power received is -190.06 dBm with Pt = 1W, Gt = 10dB, Gr = 0dB

λ = 0.3 meters,  d = 10 miles.

The Friis equation is used to calculate the power received from a transmitter to a receiver in free space. The equation is:

Pr = Pt * Gt * Gr * (λ/4πd)^2

Where:

Pr is the power received in watts

Pt is the transmit power in watts

Gt is the transmit antenna gain in dBi

Gr is the receive antenna gain in dBi

λ is the wavelength in meters

d is the distance between the transmitter and receiver in meters

In this case, we have the following information:

Pt = 1W, Gt = 10dB, Gr = 0dB

λ = 0.3 meters (for a frequency of 1GHz)

d = 10 miles (16093.4 meters)

Plugging these values into the Friis equation, we get:

Pr = 1W * 10dB * 0dB * (0.3 meters / 4π * 16093.4 meters)^2

Pr = -190.06 dBm

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When a cyclone's strongest winds do not exceed 37 miles per hour it is called a:_________

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When a cyclone's strongest winds do not exceed 37 miles per hour, it is called a tropical depression.

Cyclones are powerful weather systems characterized by rotating winds and low-pressure centers. They are classified into different categories based on their wind speeds and intensity. In the context of the provided information, when a cyclone's strongest winds do not exceed 37 miles per hour, it is referred to as a tropical depression.

A tropical depression is the weakest form of a tropical cyclone. It represents the initial stage of cyclone development, where a disturbance in the atmosphere begins to organize and shows some cyclonic characteristics. The wind speeds associated with a tropical depression are relatively low, typically ranging from 20 to 37 miles per hour.

As a tropical depression intensifies and its wind speeds increase beyond 37 miles per hour, it can progress into a tropical storm and eventually a hurricane or typhoon, depending on the region. However, when the wind speeds remain below the threshold of 37 miles per hour, the system is classified as a tropical depression.

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S Show that the minimum period for a satellite in orbit around a spherical planet of uniform density rho isTmin = √ [3π/Grho]independent of the planet's radius.

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To show that the minimum period for a satellite in orbit around a spherical planet of uniform density rho is Tmin = √ [3π/Gρ] independent of the planet's radius, we can use the following steps:

⇒Firstly, we'll use the formula for the force of gravity experienced by the satellite: F = G(m₁×m₂)/r²

where F is the gravitational force, G is the gravitational constant, m₁ and m₂ are the masses of the satellite and planet respectively, and r is the distance between the centers of the planet and the satellite.

⇒Secondly, we'll use the formula for centripetal force: Fc = m×(v²/r)

where Fc is the centripetal force, m is the mass of the satellite, v is the velocity of the satellite, and r is the radius of the orbit.

⇒Thirdly, we'll set these two forces equal to each other: F = Fc

Gm₁×m₂/r² = m×(v²/r)

Solving for v², we get v² = G(m₂/r)

⇒Simplifying the expression by replacing m₂ with its equivalent in terms of density and volume: m₂ = ρ × V

where ρ is the density of the planet and V is its volume.

⇒The volume of a sphere is given by:  V = (4/3)πr³

where r is the radius of the planet.

⇒Substituting the expression for m₂ into the equation for v², we get: v² = (4/3)πGρr²

Dividing both sides of the equation by r, we get: v²/r = (4/3)πGρr

This is the expression for the centripetal force we need to find the minimum period. Now we can substitute the expression for v²/r into the formula for centripetal force:

Fc = m(v²/r) = m((4/3)πGρr)

⇒The period of the satellite is the time it takes to complete one orbit:

T = 2πr/v = 2πr/√(G(m₂/r))Simplifying the expression by replacing m₂ with its equivalent in terms of density and volume:

T = 2πr/√(GρV/r) = 2πr/√((4/3)*Gπρr³) = √(3π/(Gρ)) × r^(3/2)

Since we want to find the minimum period, we need to find the value of r that minimizes T. We can do this by differentiating T with respect to r and setting the result equal to zero:

dT/dr = (3/4)√(3π/Gρ)×r^(1/2) - (3/4)√(3π/Gρ)×r^(1/2) = 0

Solving for r, we get: r = 0This is not a valid solution since r cannot be zero. Therefore, we conclude that the minimum period occurs when the derivative of T with respect to r is zero, which implies that the period is independent of the planet's radius.

Thus, the minimum period for a satellite in orbit around a spherical planet of uniform density rho is Tmin = √ [3π/Gρ] independent of the planet's radius.

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A rock band playing an outdoor concert produces sound at 120 db 5. 0 m away from their single working loudspeaker. what is the sound intensity level 35 m from the speaker?

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The sound intensity level 35 m away from the speaker is approximately 102 dB.

Sound intensity level is a logarithmic measure of the sound intensity relative to a reference level. It is given by the equation:

Sound Intensity Level (dB) = 10 * log10(I / I₀),

where I is the sound intensity and I₀ is the reference intensity level, which is typically set at 10^(-12) W/m².

In this case, the sound intensity level at 5 m from the speaker is given as 120 dB. We can calculate the sound intensity level at 35 m using the inverse square law for sound intensity, which states that sound intensity decreases with the square of the distance.

Using the inverse square law, we can determine the sound intensity at 35 m by dividing the sound intensity at 5 m by (35 m / 5 m)^2, which simplifies to 1/49. Therefore, the sound intensity at 35 m is 1/49 times the sound intensity at 5 m.

Substituting this value into the sound intensity level formula, we find:

Sound Intensity Level (35 m) = 10 * log10((1/49) * I / I₀) ≈ 102 dB.

Hence, the sound intensity level 35 m away from the speaker is approximately 102 dB.

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14.a box of mass 40kg has a base of area 10m2 .calculate the pressure exerted by it on the ground (use 1kg-f=10n).

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The pressure exerted by a box on the ground can be calculated by dividing the force exerted by the box on the ground by the area of the base of the box.

The force exerted by the box can be calculated using Newton's second law, which states that force (F) is equal to the mass (m) of an object multiplied by its acceleration (a). In this case, the mass of the box is given as 40 kg. Since the box is at rest on the ground, the acceleration is 0. Therefore, the force exerted by the box is 0 N.

To calculate pressure, we need to convert the force from newtons to kilogram-force. Since 1 kg-f = 10 N, the force can be expressed as 0 N / 10 = 0 kg-f.

The pressure exerted by the box on the ground is calculated by dividing the force by the area of the base of the box. The area is given as 10 m^2. Therefore, the pressure exerted by the box on the ground is 0 kg-f / 10 m^2 = 0 kg-f/m^2.

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In a gravitationally bound system of two unequal masses the center of mass is located ?closer to the higher, mass at the center of one of the masses ,exactly in between the two mass,closer to the lower mass

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In a gravitationally bound system of two unequal masses, the center of mass is located closer to the higher mass.

The center of mass of a system is the point at which the system's mass can be considered to be concentrated. In a two-body system with unequal masses, the center of mass is closer to the more massive object.

The center of mass is determined by considering the masses and their distances from a reference point. In this case, since the masses are unequal, the more massive object has a greater influence on the center of mass.

The center of mass can be calculated using the formula:

Xcm = (m1x1 + m2x2) / (m1 + m2)

Where m1 and m2 are the masses of the objects, and x1 and x2 are their respective positions.

Since the mass of the more massive object is greater, its contribution to the center of mass calculation is larger. As a result, the center of mass is closer to the higher mass.

Therefore, in a gravitationally bound system of two unequal masses, the center of mass is located closer to the higher mass.

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If the natural length of a spring is 0.5 meter, and if its takes a force of 15 newtons to keep it extended an additional 0.04 meters, find the work done in stretching the spring from its natural length to a length of 0.6 meters

Answers

The work done in stretching the spring from its natural length to a length of 0.6 meters is 1.875 Joules.

To find the work done in stretching the spring from its natural length to a length of 0.6 meters, we can use Hooke's Law and the concept of work.

Hooke's Law states that the force exerted by a spring is directly proportional to its displacement from its natural length. Mathematically, it can be expressed as F = kx, where F is the force, k is the spring constant, and x is the displacement.

In this case, we are given that it takes a force of 15 newtons to keep the spring extended an additional 0.04 meters. This means that the displacement is 0.04 meters and the force is 15 newtons. We can rearrange Hooke's Law to solve for the spring constant: k = F / x = 15 N / 0.04 m = 375 N/m.

To find the work done in stretching the spring from its natural length (0.5 meters) to a length of 0.6 meters, we need to calculate the area under the force-displacement curve. The work done is equal to the area under the curve, which can be found using the formula W = (1/2) k x^2, where W is the work done, k is the spring constant, and x is the displacement.

Plugging in the values, we have: W = (1/2) * 375 N/m * (0.6 m - 0.5 m)^2 = (1/2) * 375 N/m * (0.1 m)^2 = 1.875 J.

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C26 Which of the following is not a flow velocity measuring device? A. Venturi meter B. Tachometer C. Pelton wheel D. Pitot tube C27 Which of the following is not a base SI unit? A. kg B. Hz C. cd D. mol C28 What is the percentage change in resistance of a semiconductor strain gauge with a temperature coefficient of 2e-5 °C^-1, gauge factor of 2.1, under a strain of 1 µ at 100 °C. A. 0.15% B. 0.25% C. 0.2% D. 0.1%

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C26: The answer is C. Pelton wheel is a velocity measuring device.

C27: The answer is C. cd (candela) is not a base SI unit.

C28: To calculate the percentage change in resistance of the semiconductor strain gauge, we need to consider the strain and the temperature coefficient.

C26: The answer is C. Pelton wheel. The Pelton wheel is not a flow velocity measuring device but rather a type of impulse turbine used in hydroelectric power systems to convert the energy of flowing water into mechanical energy. Venturi meter, tachometer, and Pitot tube are all commonly used flow velocity measuring devices.

C27: The answer is C. cd (candela). The candela is not a base SI unit but rather a derived unit of measurement for luminous intensity. The base SI units are kilogram (kg), meter (m), second (s), ampere (A), kelvin (K), mole (mol), and candela (cd).

C28: To calculate the percentage change in resistance of the semiconductor strain gauge, we need to consider the strain and the temperature coefficient.

Temperature coefficient = 2e-5 °C^-1

Gauge factor = 2.1

Strain = 1 µ (microstrain) = 1e-6

Temperature change = 100 °C

First, calculate the change in resistance due to strain using the gauge factor:

Change in Resistance due to Strain = Gauge Factor * Resistance * Strain

Next, calculate the change in resistance due to temperature using the temperature coefficient:

Change in Resistance due to Temperature = Temperature Coefficient * Resistance * Temperature Change

The total change in resistance is the sum of the changes due to strain and temperature:

Total Change in Resistance = Change in Resistance due to Strain + Change in Resistance due to Temperature

Finally, calculate the percentage change in resistance:

Percentage Change = (Total Change in Resistance / Initial Resistance) * 100

Substitute the given values into the equations and perform the calculations to find the percentage change in resistance. The correct answer can be determined by comparing the calculated value to the provided answer options.

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the same force f pushes in three different ways on a box moving with a velocity v, as the drawings show. rank the work done by the force f in ascending order (smallest first).

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This question can't be answered without a photo of the diagram. Can you attach it please?

Assume that you were a member of a project engineering team in the early 1990 s charged with the planning for a new analogue cellular mobile communication system in Kenya. If the communication regulators allowed your team to use the frequency band 870−960MHz. Discuss the following: 1. Choice of the channel bandwidth. Specifically discuss the lowest possible channel bandwidth and the effect of using a high channel bandwidth; (Note: There was no GSM in the 1980s) 2. Choice of the heights of the various telecommunication towers. 3. Portion of the allocated spectrum you are prepared to lose. Give three reasons why a portion of the spectrum must be lost. 4. Discuss how your proposed design addresses the following problems: a) Call initiation, i.e authentication and transfer of dialed digits b) Security, i.e ensuring that other mobile subscribers do not listen in. c) Call tear-down. 5. Assume that one country, Kenya, requires the cellular system must cover an area of 580,367 km, how many cell sites are required to cover that area assuming that the population is uniformly distributed; and towers will be 30 m high and the radius of the earth is 6470Kms. 6. What factors may make you to increase the number of base stations beyond the answer in question 4 ?

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The number of cells required to cover the entire area of Kenya is approximately 274.47.6.

1. Choice of the channel bandwidth: When choosing the channel bandwidth to use in the cellular mobile communication system in Kenya, it would be necessary to consider various factors. The lowest possible channel bandwidth would be ideal to provide more channels. The effects of using high channel bandwidth would lead to reduced capacity in terms of the number of channels. The narrower the bandwidth, the greater the number of channels available, but also the lower the quality of each individual channel. Thus, one must balance the number of channels that are necessary and the quality that is required for each channel.

2. Choice of the heights of the various telecommunication towers: The choice of height for the various telecommunication towers should take into account the transmission range, line of sight, and frequency range. In an analogue cellular mobile communication system in Kenya, the choice of tower heights is critical for proper communication. This is because the height of the towers affects the coverage area of each cell. Therefore, the ideal height would be one that provides the necessary coverage area and ensures that the signal is received at the desired level of strength.

3. Portion of the allocated spectrum you are prepared to lose. The portion of the allocated spectrum that can be lost is dependent on a variety of factors. The three reasons why a portion of the spectrum must be lost include:

Technical reasons: This is due to the limits of the available technology and the need to maintain a certain level of performance.

Economic reasons: This relates to the cost of deploying and maintaining the infrastructure necessary for the system to operate. Regulatory reasons: This relates to the regulations in place in Kenya regarding the use of spectrum.

4. Discuss how your proposed design addresses the following problems:

a) Call initiation, i.e authentication and transfer of dialed digits.The proposed design should include authentication protocols and digit transfer protocols. These protocols ensure that the mobile subscriber is identified and authenticated before the call is initiated.

b) Security, i.e ensuring that other mobile subscribers do not listen in. The proposed design should include encryption and decryption mechanisms to ensure that only the intended recipient of the call can listen to it.

c) Call tear-down. The proposed design should include mechanisms to ensure that the call is terminated properly. This includes ensuring that the resources used for the call are released and that the mobile subscriber is informed of the call termination.

5. Assume that one country, Kenya, requires the cellular system must cover an area of 580,367 km, how many cell sites are required to cover that area assuming that the population is uniformly distributed; and towers will be 30 m high and the radius of the earth is 6470Kms.To cover the 580,367 km, we need to calculate the number of cells required. Using the formula for the area of a circle, we have

Area of each cell = πr²

Let r = the radius of each cell, and n be the number of cells required. Then, the total area to be covered is:

πr²n = 580,367 km²

Distance =√3/2 * radius of the cell

The radius of the cell is equal to the height of the tower. Thus, the distance from the base of the tower to the edge of the cell is:

Distance =√3/2 * 30 = 25.98m

Therefore, the radius of each cell is 25.98km.

The area of each cell can be calculated as follows:

Area of each cell = πr²

Area of each cell = π(25.98)²

Area of each cell = 2114.16km²

To cover the entire area of Kenya, we need to divide the total area by the area of each cell:

Total number of cells = 580,367/2114.16

Total number of cells = 274.47

The number of cells required to cover the entire area of Kenya is approximately 274.47.6.

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1. Consider the following electromechanical system. Calculate a) magnetic field intensities H₁, H₂ in the air gaps b) the magnetic flux in the air gaps c) flux linkage 2 and the inductance L(x). The depth is d into the paper. Both the air gaps are of the same length g. b2 H₂ g W Mmf=Ni H₁ W Movable Part b1 Solve the problem using ACL and Gauss's Law first. Then solve it using magnetic circuit formulation. Compare the results. Also draw the equivalent magnetic. Assume the flux in the iron core is in the anticlockwise direction. The iron core is assumed to have infinite permeability.

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Calculations involve magnetic parameters using ACL, Gauss's Law, and magnetic circuit formulation, with comparison of results.

To solve the problem using ACL (Ampere's Circuital Law) and Gauss's Law, we apply these fundamental principles to calculate the magnetic field intensities H₁ and H₂ in the air gaps. Then, using the obtained field intensities, we calculate the magnetic flux in the air gaps and flux linkage 2. Additionally, we can determine the inductance L(x) of the system. By assuming infinite permeability for the iron core and considering the anticlockwise direction of flux in it, we can draw the equivalent magnetic circuit.

Using the magnetic circuit formulation, we analyze the magnetic circuit by considering the various elements such as the air gaps, iron core, and winding. By applying appropriate magnetic circuit laws, we can calculate the magnetic field intensities, fluxes, and inductance. Comparing the results obtained from both the ACL and Gauss's Law methods with those from the magnetic circuit formulation allows us to assess the accuracy and consistency of the approaches.

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explain the transfer of thermal energy​

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The transfer of thermal energy refers to the process by which heat is transferred from one object or system to another due to a temperature difference. There are three primary mechanisms of heat transfer: conduction, convection, and radiation.

Conduction is the transfer of heat through direct contact between particles within a substance or between two substances in contact. In this process, kinetic energy is transferred from higher energy particles to lower energy particles, causing them to vibrate faster and increase in temperature.

Convection is the transfer of heat through the movement of fluids, such as liquids or gases. As a fluid is heated, its particles gain energy and become less dense, causing them to rise and be replaced by cooler fluid. This creates a circulation pattern known as convection currents, facilitating the transfer of heat.

Radiation is the transfer of heat through electromagnetic waves. Unlike conduction and convection, radiation does not require a medium to propagate. Heat energy is emitted in the form of electromagnetic waves, which can travel through empty space and be absorbed by objects with lower temperatures.

Overall, the transfer of thermal energy occurs through these mechanisms, allowing heat to flow from regions of higher temperature to regions of lower temperature, seeking thermal equilibrium.

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Which of these physical quantities could be measured using a magnetic field across a plastic pipe? A. Magnetic field B. Illumination C. Pressure D. Acceleration E. Flow F. Strain

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Answer:

Pressure can be measured using a magnetic field across a plastic pipe

a projectile is launched at some angle to the horizontal with some initial speed vi, and air resistance is negligible. (a) is the projectile a freely falling body?

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Yes, a projectile is a freely falling body as the projectile does not experience any force in the horizontal direction.

A projectile is a physical object that is released into the air and then travels under the influence of gravity. The trajectory of a projectile is the path it follows when it is airborne. The shape of the trajectory of a projectile is known as a parabola.

The motion of a projectile follows the same laws of motion as the motion of a freely falling body under the influence of gravity. This is because, after the projectile is released into the air, it is solely under the influence of the gravitational force, which pulls it down towards the ground. Therefore, a projectile is a freely falling body.

Since air resistance is negligible, the projectile does not experience any force in the horizontal direction, which causes it to continue moving in the same direction with the same velocity. Only the force due to gravity influences its motion.

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A chicken is running in a circular path with an angular speed of 1. 52 rad/s. How long does it take the chicken to complete one revolution?

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The chicken takes approximately 4.14 seconds to complete one revolution in a circular path with an angular speed of 1.52 rad/s.

To determine the time taken by the chicken to complete one revolution, we need to use the relationship between angular speed and time. Angular speed is defined as the rate of change of angular displacement per unit time. In this case, the chicken has an angular speed of 1.52 rad/s.

To find the time taken for one revolution, we need to consider that one revolution corresponds to a complete 360-degree rotation or 2π radians. Therefore, we can use the formula:

Time = Angular displacement / Angular speed

In this case, the angular displacement is 2π radians, and the angular speed is 1.52 rad/s. Plugging these values into the formula, we get:

Time = 2π radians / 1.52 rad/s ≈ 4.14 seconds

Hence, it takes approximately 4.14 seconds for the chicken to complete one revolution in its circular path with an angular speed of 1.52 rad/s.

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curves 1 and 2 refer to the same gas at different temperatures. the curve corresponding to the higher temperature is

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The given statement is the curve corresponding to the higher temperature is 2. This is because as the temperature of a gas increases, its volume also increases.

In the given statement, it is given that curves 1 and 2 refer to the same gas at different temperatures. It means the two curves belong to the same gas and are the same substance. Now, let's understand how temperature affects the gas. The relationship between temperature and gas can be explained with the help of Charles' law. It states that the volume of a given mass of a gas is directly proportional to its absolute temperature, provided the pressure and amount of gas are kept constant. Mathematically, it can be expressed as;

V α T

where V is the volume and T is the absolute temperature of the gas. This means, if the temperature of the gas increases, its volume also increases. Therefore, the curve corresponding to the higher temperature is 2. As you can see in the given diagram, as we move towards higher temperatures, the volume of the gas also increases. Hence, the curve corresponding to the higher temperature is curve 2.

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In theory, the coil could be turned over, but the connectors to the coil then make it difficult to move the 2 coils together. what are the differences and why?

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In theory, the coil could be turned over, but turning the coil over makes it difficult to move the two coils together due to the connectors.

The connectors on the coil play a crucial role in allowing electrical current to flow through the coil and interact with the magnetic field. When the coil is turned over, the orientation of the connectors changes, and it becomes challenging to align and connect the two coils together properly. This can result in a loss of electrical continuity and hinder the intended functioning of the coil system. The connectors are typically designed and positioned in a specific way to ensure efficient electrical connections and proper alignment between the coils. Turning the coil over would require rearranging or reconfiguring the connectors, which may not be easily achievable or practical. It could involve disassembling and reassembling the connectors, which can be time-consuming and may introduce complications or errors. Therefore, while theoretically possible to turn the coil over, the difficulty in moving the two coils together arises from the complications in aligning and connecting the connectors properly, which are essential for the coil's electrical functionality.

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Two round concentric metal wires lie on a tabletop, one inside the other. The inner wire has a diameter of 18.0 cm and carries a clockwise current of 20.0 A , as viewed from above, and the outer wire has a diameter of 38.0 cm .

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Two concentric metal wires, with diameters of 18.0 cm and 38.0 cm, lie on a tabletop. The inner wire carries a clockwise current of 20.0 A.

The configuration described involves two concentric wires, one inside the other. The inner wire has a diameter of 18.0 cm and carries a clockwise current of 20.0 A. The outer wire, with a diameter of 38.0 cm, is not specified to have any current flowing through it.

The presence of the current in the inner wire will generate a magnetic field around it. According to Ampere's law, a current in a wire creates a magnetic field that circles around the wire in a direction determined by the right-hand rule. In this case, the clockwise current in the inner wire creates a magnetic field that encircles the wire in a clockwise direction when viewed from above.

The outer wire, not having any current specified, will not generate a magnetic field of its own in this scenario. However, the magnetic field generated by the inner wire will interact with the outer wire, potentially inducing a current in it through electromagnetic induction. The details of this interaction and any induced current in the outer wire would depend on the specifics of the setup and the relative positions of the wires.

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Using the information below, estimate the number of electrons in a 2 kg chunk of copper that has been charged to +10 mC. Atomic Number of Copper = 29 Molar Mass of Copper = 55.8 g/mol Electron Mass = 9.11 times 10-31 kg Proton Mass = 1.67 times 10-27 kg Elementary Charge = 1.602 times 10-19 C Coulomb's Constant (k) = 8.99 times 109 Nmm/CC Avagadro's Number = 6.02 times 1023 atoms/mole

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The estimated number of electrons in a 2 kg chunk of copper charged to +10 mC is approximately 6.01 times 10²⁴ electrons.

To estimate the number of electrons in the copper chunk, we need to calculate the number of copper atoms and then multiply it by the number of electrons per copper atom.

- Molar Mass of Copper (M) = 55.8 g/mol

- Avogadro's Number (Nₐ) = 6.02 times 10²³ atoms/mol

- Elementary Charge (e) = 1.602 times 10⁻¹⁹ C

First, we calculate the number of moles of copper in the chunk:

Number of moles = Mass / Molar Mass = 2 kg / 55.8 g/mol = 35.9 mol

Next, we calculate the number of copper atoms:

Number of copper atoms = Number of moles × Avogadro's Number = 35.9 mol × 6.02 times 10²³ atoms/mol = 2.16 times 10²⁵ atoms

Since copper has 29 protons and is electrically neutral, it also has 29 electrons per atom. Therefore, the number of electrons in the copper chunk is the same as the number of copper atoms.

Finally, we multiply the number of copper atoms by the number of electrons per atom:

Number of electrons = Number of copper atoms = 2.16 times 10²⁵ atoms ≈ 6.01 times 10²⁴ electrons

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