What is the classification of AABC with vertices A(0, 0), B(4, 3), and C(4, -3) by
its sides?
(A) equilateral
(B) isosceles
(C) scalene
(D) right

By simplifying the fraction 10/28 ÷ 32/49 exists 35/64.

The first stage of dividing fractions exists to estimate the reciprocal (reverse the numerator and denominator) of the second fraction. Subsequently, multiply the two numerators. Then, multiply the two denominators. Finally, simplify the fractions if required.

To find the reciprocal of the divisor

Reciprocal of 32/49 = 49/32

Now, multiply it by the dividend, then we get

So, 1028 ÷ 3249 = 10/28 × 49/32

= (10 × 49)/(28 × 32) = 490/896

After decreasing the fraction, the answer exists at 35/64.

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Answer:

[tex]\frac{2}{25}[/tex]

Step-by-step explanation:

Each "place" in the decimal, can be represented with a base 10 in the numerator.

For example the "tenths" place can be represented as: [tex]\frac{a}{10^1}[/tex] where a=decimal.

The hundredths place can be represented as: [tex]\frac{a}{10^2}[/tex]

The thousandths place can be represented as: [tex]\frac{a}{10^3}[/tex]

and so on...

In this case, we have a decimal in the hundredths place which can be represented as: [tex]\frac{8}{10^2} = \frac{8}{100}[/tex]. Now to simplify this fraction, you simply divide both sides by 4 (greatest common factor of 8 and 100), or in other words multiply it by 0.25/0.25 which is just 1, so the value is the same. [tex]\frac{8}{100} * \frac{0.25}{0.25} = \frac{2}{25}[/tex]

The solution to the given differential equation is yp=−14xcos(2x)

The characteristic equation for this differential equation is:

P(s)=s2+4

The roots of the characteristic equation are:

s=±2i

Therefore, the homogeneous solution is:

yh=c1sin(2x)+c2cos(2x)

Notice that the forcing function has the same angular frequency as the homogeneous solution. In this case, we have resonance. The particular solution will have the form:

yp=Axsin(2x)+Bxcos(2x)

If you take the second derivative of the equation above for  yp , and then substitute that result,  y′′p , along with equation for  yp  above, into the left-hand side of the original differential equation, and then simultaneously solve for the values of A and B that make the left-hand side of the differential equation equal to the forcing function on the right-hand side,  sin(2x) , you will find:

A=0

B=−14

Therefore,

yp=−14xcos(2x)

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The solution to the product of 8 and three-seventh is 2 2/7. According to Laura, she made mistake in step 2 by adding 8 and 3 instead of multiplying

Multiplication of fractions and integers

Fractions are written as a ratio of two integers. For instance a/b is a fraction where a and b are integers.

Given the following equation

Multiply 3/7 and 8

This is expressed mathematically as;

3/7 * 8

Step 1: Swap to have;

8 * 3/7

Step 2: Group the numerator

(8*2)/7

Step 3; Simplify

16/7

Step 4; Convert to mixed fraction

16/7=  2 2/7

The solution to the product of 8 and three-seventh is 2 2/7. According to Laura, she made mistake in step 2 by adding 8 and 3 instead of multiplying

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The probability of drawing a red card from a standard deck of cards is 1/2.

Given that there is a standard deck of cards.

We are required to find the probability of drawing a rd card from a standard deck of cards.

Probability is the calculation of chance of happening an event among all the events possible. It lies between 0 and 1. It cannot be negative.

Probability=Number of items/Total items.

Total number of cards=52

Number of red cards =26

Number of black cards=26

Probability of drawing a red card =Number of red cards/ Total cards.

=26/52

=1/2

Hence the probability of drawing a red card from a standard deck of cards is 1/2.

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The other names used to identify the transformation of geometric figures is translation or reflection and rotation.

Given that the types of transformations of geometric figures in the coordinate plane can be described as a slide, a flip, or turn.

We are required to find the other names used to identify the above transformations.

The other names used to identify the transformation of geometric figures is translation or reflection and rotation.

Translation means the displacement of a figure from one place to another. In translation a figure can move upward, downward,right , Iift or anywhere in the coordinate system. In translation, the position of the object changes, its size remains the same.

Reflection is a type of transformation that flips a shape in a mirror line so that each point is the same distance from the mirror line as its reflected point.

Rotation is a motion of a  space that preserves at least one point.

Hence the other names used to identify the transformation of geometric figures is translation or reflection and rotation.

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The solutions of the given equation is x = -8 + 5√2 and  x = -8 - 5√2.

The quadratic formula is used to find the roots of a quadratic equation. This formula helps to evaluate the solution of quadratic equations replacing the factorization method. If a quadratic equation does not contain real roots, then the quadratic formula helps to find the imaginary roots of that equation. The quadratic formula is also known as Shreedhara Acharya’s formula

(x + 2)² + 12(x + 2) – 14 = 0

Replacing x + 2 with u we get,

u² + 12u - 14

using quadratic formula we get

u = (-12 ±√(12² - 4x1 x-14))/2

u =(-12 ±√200)/2

u = -6 ± 5√2

x +2 = u = -6 ± 5√2

x = u = -8 ± 5√2.

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Answer:

D. 25pi

Step-by-step explanation:

"circumscribed" means the rectangle is inside the circle and just the corners (vertices) of the rectangle are touching the circle. This means the diagonal of the rectangle is the diameter of the circle. See image. If the sides of the rectangle are 6 and 8 then the third side that makes the triangle(half the rectangle) is 10. You can find this using Pythagorean Theorem or Pythagorean triples (shortcut)

6^2 + 8^2 = d^2

36 + 64 = d^2

100 = d^2

d = 10

This is the diameter of the circle. The radius would then be 5.

Area of a circle is:

A = pi•r^2

= pi•5^2

= 25pi

The probability distribution of X when X~B(1,1/25) is (Option A)

See the explanation below.

Given X~B(n,p)

P(x=1) = C¹ₙ * P¹ * (1-P)ⁿ⁻¹ (n≥1)

Thus, X~B [1, 1/25]

1/25 = 0.04

hence, p(x=0)

= C⁰₁ * 0.04⁰ (1 - 0.04)¹

= 0.96

P (x=1)

=  C¹₁ 0.04¹ (1-0.04)⁰

= 0.04

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Answer:

10830.87 mm³

Step-by-step explanation:

Hello!

Volume of a cylinder: [tex]V = \pi r^2(h)[/tex]

The radius for this cylinder is 9.525, after dividing 19.05 by 2.

Plug it into the volume formula to solve for the volume.

The volume is approximately 10830.87 cubic millimeters.

Answer:

6.98

Step-by-step explanation:

I think that you are looking for the diameter and you are given the area of a circle.

a =[tex]\pi r^{2}[/tex]  You are given pi, so [tex]r^{2}[/tex] = 72.

That means that r = [tex]\sqrt{72}[/tex] or a rounded answer of 8.49 rounded to the hundreds place.  The diameter is equal to 2 radius, so the diameter rounded is 16.98

The Jacobian for this transformation is

[tex]J = \begin{bmatrix} x_u & x_v \\ y_u & y_v \end{bmatrix} = \begin{bmatrix} 4 & 0 \\ 0 & 3 \end{bmatrix}[/tex]

with determinant [tex]|J| = 12[/tex], hence the area element becomes

[tex]dA = dx\,dy = 12 \, du\,dv[/tex]

Then the integral becomes

[tex]\displaystyle \iint_{R'} 4x^2 \, dA = 768 \iint_R u^2 \, du \, dv[/tex]

where [tex]R'[/tex] is the unit circle,

[tex]\dfrac{x^2}{16} + \dfrac{y^2}9 = \dfrac{(4u^2)}{16} + \dfrac{(3v)^2}9 = u^2 + v^2 = 1[/tex]

so that

[tex]\displaystyle 768 \iint_R u^2 \, du \, dv = 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2 \, du \, dv[/tex]

Now you could evaluate the integral as-is, but it's really much easier to do if we convert to polar coordinates.

[tex]\begin{cases} u = r\cos(\theta) \\ v = r\sin(\theta) \\ u^2+v^2 = r^2\\ du\,dv = r\,dr\,d\theta\end{cases}[/tex]

Then

[tex]\displaystyle 768 \int_{-1}^1 \int_{-\sqrt{1-v^2}}^{\sqrt{1-v^2}} u^2\,du\,dv = 768 \int_0^{2\pi} \int_0^1 (r\cos(\theta))^2 r\,dr\,d\theta \\\\ ~~~~~~~~~~~~ = 768 \left(\int_0^{2\pi} \cos^2(\theta)\,d\theta\right) \left(\int_0^1 r^3\,dr\right) = \boxed{192\pi}[/tex]

Answer:50%

Step-by-step explanation:  It doesn't matter how many questions there are because for each question, you have a 50% chance of getting it right. So, the probability is 50%.

The solutions for the given system are (3,2), (3,-2), (-3,2) and (-3,-2).

The quadratic function can represent a quadratic equation in the Standard form: ax²+bx+c=0 where: a, b and c are your respective coefficients. In the quadratic function the coefficient "a" must be different than zero (a≠0) and the degree of the function must be equal to 2.

The solution of these equations represents the points at which the parabolas intersect.

2x²+8y²=50 (1)

x²  + y²= 13 (2)

Multiplying the equation 2 by -2, you have:

2x²+8y²=50 (1)

-2x² -2 y²= -26(2)

Sum both equations, you have: 6y²= 24. Now, you can find y.

6y²= 24

y²=4

y=±2

If y=2, from equation 2, you have

x²  + y²= 13

x²  + 2²= 13

x²  + 4= 13

x² =13-4

x² =9

x=±3

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Answer:

600 and 200

Step-by-step explanation:

kofi  : kweku     is   3 :1

   so Kofi gets   3 out of ( 3 +1)  = 3/4 of 800  = 3/4 * 800 = 600

         kweku get s the rest   800- 600 = 200  

The remaining value will increase by the value of the slope. Hence the remaining missing values are -47, -44, -41, -38 and -35

The slope of a line is the ratio of the rise to run of a line. It is also defined as the rate of change of coordinate y with respect to x. Mathematically;

slope = change in y/change in x

If the slope of the table given is 3, then using the coordinate points (5, -50)and (6, y)

Substitute

3 = y-(-50)/6-5
3 = y+50/1
y+50 = 3

y = -47

The remaining value will increase by the value of the slope. Hence the remaining missing values are -44, -41, -38 and -35

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Cheese proof:

We can just prove that it is divisible by 3, which means that it is composite. We can use modular exponentiation, where if [tex]a \equiv b \pmod{n}[/tex] then [tex]a^x \equiv b^x \pmod{n}[/tex]. In this case, [tex]{-1}^{8^{2014}} \equiv 20^{8^{2014}} \pmod{3}[/tex]. This is much easier to calculate! Since [tex]8^{2014}[/tex] is even, [tex]-1^{8^{2014}}=1[/tex], meaning that now we only need to prove that [tex]0\equiv(1+113) \pmod{3}[/tex], which is obviously true.

The 15th term in the given A.P. sequence is a₁₅ = 33.

According to the statement

we have given that the A.P. Series with the a = 5 and the d is 2.

And we have to find the 15th term of the sequence.

So, for this purpose we know that the

An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant.

And the formula is a

an = a + (n-1)d

After substitute the values in it the equation become

an = 5 + (15-1)2

a₁₅ = 5 + 28

Now the 15th term is a₁₅ = 33.

So, The 15th term in the given A.P. sequence is a₁₅ = 33.

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Answer:

[tex]p = x \\ r = 6\% \\ t = 2yrs[/tex]

[tex]p = 1600[/tex]

please see the attachment

Answer:

P = $1600

Step-by-step explanation:

We have to use the equation:

[tex]\boxed{I = Prt}[/tex] .

We know that:

• I = $192

• P = ?

• r = 6% = 0.06

• t = 2 years

Substituting these values into the equation:

[tex]192 = P \times 0.06 \times 2[/tex]

Solving for P:

[tex]P = \frac{192}{0.06 \times 2}[/tex]

[tex]P = \bf \$1600[/tex]

The descriptive statistics for the above data is given as follows:
X = 12.5

A set of concise descriptive coefficients that describe a particular data set indicative of a whole or sample population is known as descriptive statistics.

For X (mean) = [tex]{\displaystyle X={\frac {1}{n}}\sum _{i=1}^{n}X_{i}[/tex]

= 300/24

= 12.5

For sample variance = [tex]s^2 = \frac{1}{n-1}\biggl[\, \sum_{i=1}^n X_i^2 - \frac{\Bigl(\,\sum\limits_{i=1}^n X_i\Bigr)^{\!2}}{n} \biggr][/tex]

= (1/(24-1) (4,900 - (300²/24)

= 50

Standard deviation s = √s²

= √50

= 7.0711

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Step-by-step explanation:

i donot know

sorry about this

Answer:

1/8

Step-by-step explanation:

say the bar has 20 pieces. he has 10 pieces. and he gave away 1/4 of those 10

1/4 x 10 = 2.5

20 / 2.5 = 8

So his friend recieved 1/8

you could also just do 1/2 x 1/4 which is 1/8

Answer:

1/8 of the candy bar.

Step-by-step explanation:

Elias has 1/2 of a candy bar.

He gave 1/4 of 1/2 to his friend.

[tex]\sf Friend's s\ share = \dfrac{1}{4} \ of \ \dfrac{1}{2}[/tex]

                      [tex]\sf =\dfrac{1}{4}*\dfrac{1}{2}\\\\=\dfrac{1}{8}[/tex]

The conclusion can be made from the given information

The volume of the triangular prism is equal to the volume of the cylinder

Given that there are two figures

1. A right triangular prism

2. Right cylinder

The area of the cross-section of the prism is equal to the Area of a cross-section of the cylinder.

Let this value be A.

Also given that the Height of prism = Height of cylinder = 6

The volume of a prism is will be :

[tex]V _{prism} = cross section area \times height[/tex]

[tex]V _{prism} = A \times 6 = 6A[/tex]  (1)

The Cross section of the cylinder is a circle.

hence the Area of the circle will be:

Area of cross-section, A = [tex]\pi \times r^2[/tex]

so, the Volume of the cylinder will be :

[tex]V _{cylinder} = \pi \times r^2 \times h[/tex]

[tex]V _{cylinder} = A \times h = A \times 6 = 6A[/tex]  (2)

From equations (1) and (2) we can say that

The volume of the triangular prism is equal to the volume of the cylinder.

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The expression y = α · sin x + β · cos x is a solution of the ordinary differential equations if and only if (α, β) = (0, 0).

According to the statement, we must find in what conditions a given expression may be a solution of an ordinary differential equation. Then, first and second derivatives of the equation are:

y' = α · cos x - β · sin x                 (1)

y'' = - α · sin x - β · cos x              (2)

Then, we substitute on the ordinary differential equation:

(- α · sin x - β · cos x) + (α · cos x - β · sin x) = 0

And by algebraic handling we simplify the resulting expression:

- (α + β) · sin x + (α - β) · cos x = 0

Where each coefficient represents a constant of a linear combination:

α + β = 0

α - β = 0

Then, the solution of the system of linear equations is (α, β) = (0, 0). The expression y = α · sin x + β · cos x is a solution of the ordinary differential equations if and only if (α, β) = (0, 0).

The statement is incomplete and complete form cannot be found, then we decided to create a new statement:

Please prove that y = α · sin x + β · cos x is the solution of the differential equation d²y / dx² + dy /dx = 0 where the following condition is observed, if and only if α = β = 0.

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the petrol cost for the trip is:

C = 2.125*$2.05 = $4.36

After a search online, I've found that the trip is of 25km.

Here we know that the car uses 8.5L per 100km, then in 25 km, the car will use one-fourth of 8.5L, that is:

8.5L/4 = 2.125L

So the volume of petrol that the car uses for the trio is 2.125 liters of petrol.

And each liter costs $2.05, then the petrol cost for the trip is given by the product between the total volume of petrol consumed and the cost per liter.

C = 2.125*$2.05 = $4.36

Thus, we conclude that the petrol cost for the trip is 4.36 dollars.

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Answer:

(0, -5)

Step-by-step explanation:

The two different lines have point (0, -5) in common, so the solution is (0, -5).

The zeros of the given equation are -5  and -7

Quadratic equations are equations that has a leading degree of 2. Given the factors of a quadratic equation as expressed below;

(-3x - 15)(x+7) = 0

The expressions -3x -15 and x + 7 are the factors of the equation. Equating both factors to zero

-3x - 15 = 0

Add 15 to both sides of the equation

-3x -15 + 15 = 0 + 15

-3x = 15

Divide both sides of the equation by -3

-3x/-3 = 15/-3

x = -5

Similarly;

x + 7 = 0

x = -7

Hence the zeros of the given equation are -5  and -7

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The value of the functions f(x) and g(x) will be √(4x + 3) and √2. Then the correct option is B.

A statement, principle, or policy that creates the link between two variables is known as a function. Functions are found all across mathematics and are required for the creation of complex relationships.

If (f g)(x) = h(x) such that h(x) = √(8x + 6). Then we have

(f g)(x) = h(x)

f(x) · g(x) = h(x)

Then put the value of h(x), then we have

f(x) · g(x) = √(8x + 6)

f(x) · g(x) = √2(4x + 3)

f(x) · g(x) = √(4x + 3) × √2

Thus, the value of the functions f(x) and g(x) will be √(4x + 3) and √2.

Then the correct option is B.

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