What is the constant in 12r + r/2-19

By using the given functions, each output value are as follows;

a. f(-5) = -13.

b. g(3) = -18.

c. 3g(1) - 4 = -10.

d. 2f(3) + g(2) = 14.

e. x = ±√8i or ±2√2i.

In this scenario and exercise, we would determine the corresponding output value for the functions f(x) under the given mathematical operation and independent variable.

Part a.

When x = -5, the output value for f(-5) is given by;

f(x) = 3x + 2

f(-5) = 3(-5) + 2

f(-5) = -13.

Part b.

When x = 3, the output value for g(3) is given by;

g(x) = -2x²

g(3) = -2(3)²

g(3) = -18.

Part c.

3g(1) - 4

3[-2(1)²] - 4

-6 - 4 = -10

Part d.

2f(3) + g(2)

2[3(3) + 2] + [-2(2)²]

22 - 8 = 14

Part e.

g(x) = 16

-2x² = 16

x² = -8

x = ±√8i or ±2√2i.

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Answer:

2.5

Step-by-step explanation:

We Know

You buy 4 5/8 blue fabric and 2 1/8 green fabric .

4 5/8 = 37/8 = 4.625 blue fabric

2 1/8 = 17/8 = 2.125 green fabric

How much blue than green did you buy?

We Take

4.625 - 2.125 = 2.5

So, you buy 2.5 blue more than green.

The slope-intercept equation of the line with a slope of 8 and a y-intercept of (0, 9) is y = 8x + 9.

To find the slope-intercept equation of a line, we use the form y = mx + b, where m represents the slope and b represents the y-intercept.

Given:

Slope (m) = 8

Y-intercept (0, 9)

We can substitute these values into the slope-intercept form:

y = mx + b

y = 8x + 9

Consequently, y = 8x + 9 represents the slope-intercept equation for the line with a slope of 8 and a y-intercept of (0, 9).

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The missing parts of the proof of supplementary angles are:

Supplementary; ∠2 and ∠3; substitution; 2.

Supplementary angles are defined as angles whose measures sum to 180°.  Thus this is the first answer.  

Since we are told that ∠2 and ∠3 are supplementary, their measures sum to 180° and they are the second answer.

We know that m∠1 + m∠2 = 180° and m∠2 + m∠3 = 180°.  We can substitute "m∠2 + m∠3" for 180° in the first equation; this is the substitution property.

To isolate m∠1 on the right, we will subtract m∠2 from each side, and get that m∠1 = m∠3 and the angles are congruent.

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Using angle rules, the values of angles 1 to 6 are 64, 53, 116, 89, 32 and 44 respectively.

Angle 1 + 69 + 47 = 180 (sum of angles on a straight line)

Angle 1 = 180 - (69+47)

Angle 1 = 64°

Angle 2 + 64 + 63 = 180 (sum of angles in a triangle)

Angle 2 = 180 - (64+63)

Angle 2 = 53°

Angle 1 + Angle 3 = 180 (sum of angles in a triangle)

Angle 3 = 180 - 64

Angle 3 = 116°

Angle 6 + 136 = 180 (sum of angles on a straight line)

Angle 6 = 180 - 136

Angle 6 = 44°

Angle 5 + Angle 3 + 32 = 180 (sum of angles in a triangle)

Angle 5 + 116 + 32 = 180

Angle 5 = 180 - (116 + 32)

Angle 5 = 32°

47 + Angle 6 + Angle 4 = 180

47 + 44 + Angle 4 = 180

Angle 4 = 180 - 91

Angle 4 = 89°

Therefore, the values of angles 1 to 6 are 64, 53, 116, 89, 32 and 44 respectively.

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To calculate how much Naruto spends on ramen in 15 days, we need to determine the total cost of ramen per day and then multiply it by 15.

Since Naruto receives a 33.33% discount, he pays 100% - 33.33% = 66.67% of the original price.

66.67% of 45 cents is (66.67/100) * 45 = 30 cents.

So, Naruto spends 30 cents on ramen per day.

To find out how much he spends in 15 days, we multiply the daily cost by the number of days:

30 cents * 15 = 450 cents.

Therefore, Naruto spends 450 cents, which is equivalent to $4.50, on ramen in 15 days.