What is the electron configuration of a potassium ion when it has formed an ionic bond with a bromine ion?

To produce a mass of 6. 38 g al using a current of 12. 50 amps the time required would be 7207.4 minutes.

It states that the chemical which is getting decomposed because of the flow of current within an electrolyte is directly proportional to the quantity of electricity passing through it.

                        W= Z × I × t    Z = 1 coulomb

                                               I = current

                                                t = time

substituting the values

                           Z= 96500/Eq.wt

​Al 3+ +3e − →Al n= 3

so, Eq= 27 / 3 = 9

t = W × Z / I

t = 9 × 96500 / 12.50

t = 7207.4 minutes.

Therefore the time required would be, 7207.4 minutes.

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Answer:

Ag+ (aq) + Cl- (aq) --> AgCl (s)

Explanation:

[tex] {\qquad\qquad\huge\underline{{\sf Answer}}} [/tex]

Sodium is a highly reactive alkali metal and it looses an electron to gain a positive charge on it and bromine is a halogen that is highly resctive as well and it gains a negative charge by doing so.

And hence they form ionic bond, and the compound is held together by the attraction between the two charged ions.

So, correct choice is : A. oppositely charged ion attract.

Answer:

Atoms are made up of protons, neutrons, and electrons. The mass of an atom is determined by the total number of neutrons and protons in the nucleus. The difference between an atom and an ion is the number of electrons. The change of electrons does not change the mass because electrons have a negligible mass. In other words, the mass of electrons is so small, it is considered insignificant.

The molarity of the solution is 0.32 M

Calculation,

Molarity of the solution is the total number of moles present in volume in liter.

molarity = number of moles/volume in liter = n/V                  ...(i)

Number of moles of sulfuric acid = given mass/molar mass

Number of moles of sulfuric acid (n) = 16g/98.079g/mol = 0.16 mole

Volume of the solution (V) = 0.5 L

Putting the value of volume and number of moles in equation (i) we get,

molarity = 0.16 mol/0.5 L = 0.32 mol/L = 0.32 M

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The name of CuO is copper II oxide and its bond type is ionic or electrovalent bond.

An ionic or electrovalent bond is the type of chemical bond where two atoms or molecules are connected to each other by electrostatic attraction.

This electrostatic attraction is as a result of the transfer of electrons from the metallic element to the non-metal.

According to this question, CuO is a chemical compound consisting of two elements namely; copper and oxygen. The compound name is copper II oxide.

Copper as a metal transfers electrons to oxygen atoms, hence, an ionic bond is formed between the molecules.

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A mass spectrum for propane will have its largest peak at 44 number.

Mass spectrum

.An analytical method for determining the mass-to-charge ratio of ions is mass spectrometry (MS). The findings are displayed as a mass spectrum, which is a plot of intensity against the mass-to-charge ratio. Mass spectrometry is utilized in a wide range of disciplines and can analyze both pure materials and intricate mixtures. A visualization of the ion signal as a function of the mass-to-charge ratio is known as a mass spectrum. The masses of particles and molecules in a sample, as well as the chemical identity or structure of molecules and other chemical compounds, are all determined using these spectra.

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Abiotic factors are the physical and chemical compounds of an environment, being able to influence the living beings present in the ecosystem so that plants and animals have to adapt to survive and develop.

The biotic components are all the living things that live in a certain place, while the abiotic components are all the physical, chemical and geological factors of the environment such as

With this information, we can conclude that An abiotic factor is a non-living part of an ecosystem that shapes its environment.

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Answer:

29 mL

Explanation:

The question needs us to find the volume of the liquid. The equation for volume using density and mass is:

Volume = Mass / Density

We can substitute the given values for density and mass into the equation:

[tex]V=\frac{25\ g}{0.87\ g/ml}[/tex]

[tex]V\approx29\ mL[/tex]

The answer we obtained (29 mL) is rounded to two significant figures. When multiplying or dividing, the amount of significant figures in the final answer is always the least amount of significant figures in one of the values.

Below are the significant figure rules:

Nonzero digits will always be significant (eg. 54 --> 2 significant figures)

Zeroes at the beginning of a number will never be significant (eg. 0.1 --> 1 significant figure)

Zeroes between two nonzero digits will always be significant (eg. 504 --> 3 significant figures)

Zeroes following a number will always be significant if the number contains a decimal point (eg. 40.0 --> 3 significant figures)

pH value of a 0. 011 m naf solution is 8.57.

Solution

This problem uses the relationship between Kb and the dissociation constants which is expressed as Kw = KaKb. Calculations are as follows:

Kb = KaKb

1.00 x 10^-14 = 7.2 x 10^-4(x)

x = 1.39 x 10^-11

We now need to calculate the [OH¯] using the Kb expression:

1.39 x 10^-11 = x^2 / (0.30 - x)

The denominator can be neglected. Thus, x is 3.73 x 10^-6.

pOH = -log 3.73 x 10^-6 = 5.43

pH = 14-5.43 = 8.57

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When an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.

The energy of the electron drops when it transitions levels, as well as the atom releases photons. The emission of the photon occurs as the electron transitions from an energy state to a lower state. The photon energy represents precisely the energy that would be lost when an electron moves to a level with less energy.

When such an excited electron transitions from one energy level to another, this could emit a photon. The energy drop would be equivalent to the power of the photon that is released. In electron volts, the energy of an electron, as well as its associated photon (emitted or absorbed) has been stated.

Therefore, when an electron in a quantum system drops from a higher energy level to a lower one, the system emit a photon.

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The molecular formula of a monosaccharide characterized as an aldotetrose is [tex]C_{5}H_{10} O_{5}[/tex].

Any monosaccharide, often known as simple sugar, is one of the fundamental substances that forms the basis of carbohydrates.

Some features of monosaccharide are-

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Using 1h nmr spectroscopy, the difference between an aldehyde and a ketone is predicted as an aldehyde contains two C-H stretches ranging between 2700-2850 cm⁻¹.

Spectroscopy is the study of how light as well as other radiation are absorbed and emitted by materials, and how this depends just on wavelength of that radiation.

Some characteristics of spectroscopy are-

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Answer:

80 m/hr

Explanation:

Changes from 20 to 100 meters in ONE Hour

    changes  80 meters in one hour    = 80 m/hr

In the above question the probability the electron will tunnel through the barrier is 0.011%.

An electron volt is the amount of energy required to move a charge equal to 1e⁻ across a potential difference of 1eV.

To calculate the probability the electron will tunnel through the barrier is calculated as -

Energy of electron

E=80eV

=80×1.6×10⁻¹⁹

=128×10⁻¹⁹

Height of the barrier U=100 eV

=100×1.6×10⁻¹⁹J

Thickness L=0.2×10⁻⁹m

Probability T=e⁻²cl

C=√2m(U-E)/h

=√[2×1.67×10⁻²⁷(160-128)×10⁻¹⁹] / 1.055×10⁻³⁴

=10.34×10⁻²³/1.055×10⁻³⁴

=9.8×10¹¹

2CL=2×9.8×10¹¹×0.2×10⁻⁹

=3.92×10²

T=e⁻²cl

= 1/e⁻³⁹²/¹⁰⁰⁰⁰

=0.0198%

=0.011%

Hence ,the probability the electron will tunnel through the barrier is 0.011%.

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The elements of group IA have been termed alkali metals because of their oxides and hydroxides form alkaline.

An element can be defined as a substance which cannot be split into simpler units by ordinary chemical process

Below are some examples of elements:

Alkali metals refers to any of the soft, light, reactive metals of Group 1 of the periodic table.

Periodic table refers to a tabular chart of the chemical elements according to their atomic numbers so that elements with similar properties are in the same column.

So therefore, the elements of group IA have been termed alkali metals because of their oxides and hydroxides form alkaline.

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Gasoline is refined petroleum used in engines as a fuel. It contains octane that can be converted to isooctane by adding catalysts like platinum and palladium.

Catalysts are substances that raise the reaction rate by decreasing the activation energy but do not get consumed themselves in a reaction.

Platinum and palladium metals can be used as a catalyst to convert the octane of the gasoline into isooctane as they are oxidation catalyst that converts the fuel components into water and carbon dioxide.

Therefore, platinum and palladium are used as catalysts in converting octane.

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The volume of the gas sample will be 1.79 L.

A liquid, solid, or gas's volume represents the amount of three-dimensional space it occupies. Although there are many additional units that can be used to indicate volume, the most used ones are liters, cubic meters, gallons, milliliters, teaspoons, as well as ounces.

Given data :

Mass of [tex]O_{2}[/tex] = 1.20 g

Mass of [tex]N_{2}[/tex] = 1.43 g

Number of moles can be calculated by suing the formula:

Number of moles of [tex]O_{2}[/tex] = Mass / molar mass = 1.20 / 32 = 0.03 mol

Number of moles of [tex]N_{2}[/tex] =  Mass / molar mass  = 1.43 / 28 = 0.05 mol

So, the total count of moles can be calculated by :

Total moles = moles of [tex]O_{2}[/tex]  +  moles of [tex]N_{2}[/tex]

Total moles = 0.03  + 0.05 = 0.08 mol

The volume of the gas at STP can be calculated as:

Volume = 0.08 mol × 22.4 mol/L

Volume = 1.79 L

Therefore, the volume of the gas sample will be 1.79 L.

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The volume of ethyl alcohol overflow will be 9.265mL.

To calculate the volume of ethyl alcohol overflow, we will use

∆V=V(á∆T)

Where,

∆V=volume expand

á=volumetric expansion Coefficients =0.00109/°C

V=initial volume =500ml

T'=final temp. =22°C

T=initial temp=5°C

Now,

∆V=500×(0.00109/°C) ×(22-5)

=500×(0.00109) (17)

=9.265ml

Thus, we find that the volume of ethyl alcohol overflow will be 9.265 mL.

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The 6 M solution NaOH solution diluted before titrating the vinegar sample because pH at the equivalence point changes very rapidly . It is very useful to have dilution solution , so that number of moles that are transferred per drop of the solution is low . So, pH change smaller amount per drop. Having more dilute solution also allows the titration to use volume that is easier to work with.

If you used the 6 M solution was used then the volume required for titration would go down by a factor of 6/0.3 = 20

This means that if a titration took 20ml of the 0.3 M solution then it would take 1ml of the NaOH solution.

Titration consists of adding a controlled and known amount of standard solution with an unknown until the reaction to be complete.

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The covenant of further assurances requires the grantor to execute any necessary legal documents (within his power) necessary to fix title defects discovered after closing.

A warranty deed is typically signed by both parties when a seller transfers real estate to a buyer. According to Deed Claim, this document certifies that the seller is the legitimate owner of the property and is selling it free of any liens while transferring the legal title to the buyer. The assurances made by the seller are represented by the six covenants of title. Three covenants are regarded as existing covenants, and as such, they are applicable to the parties to the most recent transfer. The other three are future covenants, and if they are broken, any owner may bring a claim against any prior grantor.

Covenant of Seisin

The seller's rightful ownership of the property is guaranteed by the present covenant of seisin.

No Encumbrances

The seller guarantees that the property is possessed free and clear by making the current covenant against encumbrances.

Right to Convey

According to TheLaw.com, having the right to convey indicates that the seller is legally permitted to transfer the property to the buyer.

Quiet Enjoyment

The future covenant of quiet enjoyment guarantees that a third party's legal claim to title won't affect the buyer's right to possession.

Covenant of Warranty

The warranty covenant and the quiet pleasure covenant are extremely similar.

Further Assurances

This prospective covenant is a guarantee that, should the need ever arise, the grantor will take all reasonable steps to assist the grantee in perfecting the title.

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The lead (Pb) in the lead storage battery act as an anode

What is Voltaic Cell?

A voltaic cell or galvanic cell is an electrochemical cell that uses chemical reactions to produce electrical energy.

Parts of voltaic cell

In lead storage battery, the following reactions occur:

At anode:

[tex]Pb(s) + H_2SO_{4} + H_2O(l) \rightarrow2e^- + PbSO_{4} (s) + H_3O^+(aq)[/tex]

At Cathode:

[tex]PbO_2(s) + H_2SO_4(aq) + 3H_3O+(aq) + 2e^- \rightarrow PbSO_4(s) + 5H_2O(l)[/tex]

Overall reaction:

[tex]Pb(s) + PbO_2(s) + 2H_2SO_4 (aq.) \rightarrow PbSO_4(s) + 2H_2O(l)[/tex]

Hence, Pb acts as an anode and [tex]PbO_2[/tex] as a cathode.

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If you purchase two new tires instead of four, you should put them on the rear means back side.

If you are here for a short answer on where the two new tires should be installed, always place the new tires on the rear when buying two tires instead of four. This is because more weight of car comes on the back tires so the new tires should be installed on the back tires of the car.

So we can conclude that If you purchase two new tires instead of four, you should put them on the rear means back side.

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The R was found to be = 0.6711 L atm/mol.K

The percent error was found to be =18.22 %

The three elements that form magnesium a metal are as follows: It effectively conducts electricity. An electropositive element is magnesium. Magnesium has a relatively low ionization enthalpy.

In the crust of the planet, magnesium is the seventh most prevalent element. It is found in huge amounts as magnesite, dolomite, and other minerals but does not naturally occur uncombined.

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2.3352 g of PbCl₂ are formed when 50. 0 ml of 0. 336 m KCl react with pb(no3)2.

The balanced equation for the above double displacement reaction is as follows;

2KCl + Pb(NO₃)₂ ---> PbCl₂ + 2KNO₃

Stoichiometry of KCl to PbCl₂ is 2:1

This means that 2 mol of KCl would react with every 1 mol of PbCl₂

The molarity of KCl = 0. 336 M

in 1 L of KCl, there are mol

Therefore in  50. 0 ml of KCl, there are=  [tex]\frac{0. 336 * 50}{1000}[/tex]

Number of KCl moles reacted = 0.0168 mol

according to stoichiometry

number of PbCl₂ moles formed =  1/2 x number of KCl moles reacted

Therefore number of PbCl₂ moles formed = 0.0168 mol/2 = 0.0084 mol

molar mass of PbCl₂ = 278 g/mol

mass of PbCl₂ formed = 278 g/mol x 0.0084 mol = 2.3352 g

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The final answer is 29.8 mL

Molar mass HCl = 36.5 g/mol

Mol HCl in 1.85 g = 1.85 g / 36.5 g/mol = 0.05068 mol

The molarity of the HCl solution is 0.0507 mol /L

Mol HCl in 50 mL = 50 mL / 1000 mL/L * 0.0507 mol /L = 0.002535 mol

This will require 0.002535 mol NaOH

1000 mL contains 0.0850 mol

The volume that contains 0.002535 mol

Volume = 0.002535 mol / 0.0850 mol /L *1000 mL/L = 29.8 mL

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The volume of 0.0850 M NaOH is required to titrate 25.0 ml of 0.0720 M is 21.176 ml.

Normality is defined as the number of equivalents per litre of the solution

It is given by

Normality = number of equivalents / 1 L of solution

Molarity is defined as the number of moles of solute present in one litre of solution

Molarity = moles of solute / 1 litre of solution

Relationship between molarity and normality

Normality = Molarity × Acidity or Basicity of a salt

Here, the Acidity Of NaOH is 1 and the basicity of HBr is also 1.

Thus, Normality = Molarity

We know, N₁V₁ = N₂V₂

We can also write it as M₁V₁ = M₂V₂

V1 = [tex]\frac{M_2V_2}{M_!}[/tex]

Substitute M₁ = 0.0850 M, M₂ = 0.0720 M, V₂= 25 ml

V1 = 21.176 ml

Hence, The volume of 0. 0850 m NaOH are required to titrate 25. 0 ml of 0. 0720 m is 21.176 ml.

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The volume of carbon dioxide that will be produced is 191.4 g.

Calculation:

The following is the balanced equation for the given reaction:

Fe₂O₃(s) + 3CO(g) → 2Fe(s) + 3CO₂(g),

It is obvious that when 1.0 mole of Fe2O3 reacts with 3.0 mole of CO, 2.0 mole of Fe and 3.0 mole of CO2 are produced.

Hence by using cross multiplication:

If 2.0 mol of Fe was produced with → 3.0 mol of CO₂, from stoichiometry.

Then how many moles of CO₂ are produced by 2.9 mol of Fe?

To find the answer we have a formula:

∴ The no. of moles of CO₂ produced = (3.0 mol)(2.9 mol)/(2.0 mol) = 4.35 mol.

∴ The mass of CO₂ produced = no. of moles x molar mass = (4.35 mol)(44.0 g/mol) = 191.4 g.

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The concentration of the hydroxide ion given that the concentration of the hydronium ion 1.0 times 10^-14 M. The reverse mathematical method used to determine the pOH can be used to get the hydroxide ion concentration from the pOH. How many hydroxide ions are there in a solution with a pOH of 5.70, for instance.

Calculate 10-5.70, or "inverse" log, on a calculator (- 5.70). It indicates that one hydroxide ion is produced by one part of the NaOH solution. Because of this, the molar concentration of hydroxide ions in the solution is the same as the molar concentration of the NaOH.

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The most likely reaction product in the monobromination of 2-pentanone by bromine in the presence of acid in the dark is known to be 1-Bromo-2-pentanone

The term is known to be the bringing in of one bromine atom into  what we call an organic compound.

Note that the brominating of benzene is known to be a good example of what we know as electrophilic aromatic substitution reaction. In this kind of reaction, the electrophile (which is bromine) is said to forms a kind of sigma bond to that of the benzene ring, bringing in an intermediate. Then, a proton is said to be deleted from the intermediate to create a substituted of benzene ring.

Hence, The most likely reaction product in the monobromination of 2-pentanone by bromine in the presence of acid in the dark is known to be 1-Bromo-2-pentanone

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See full question below

Identify the most likely reaction product(s) in the monobromination of 2-pentanone by bromine in the presence of acid in the dark.

a.) 1-Bromo-2-pentanone and 3-bromo-2-pentanone

b.) 1-Bromo-2-pentanone, 3-bromo-2-pentanone, and 4-bromo-2-pentanone

c.) 1-Bromo-2-pentanone, 3-bromo-2-pentanone, 4-bromo-2-pentanone, and 5-bromo-2-pentanone

d.) 3-Bromo-2-pentanone

e.)1-Bromo-2-pentanone