Answer:
C.) Fluorine
Explanation:
A period describes a row on the periodic table.
Halogens are located in the 17th column on the periodic table.
As such, the element located in the second row in the 17th column is fluorine.
For the following questions state the oxidation number of the element in the given compound.
1. sul fur in Li2SO#3
2. chlorine in MgCl2
3.Silicon in SiO2
4.sul fur in H2SO4
5.Sulfur in SO4^2-
6. manganese in MnO4^-
7. Cr in Cr2O7^2-
in the periodic tables
elements in the same column have the same charge
in a compound oxidation numbers have to equal 0
1.
sulfur in Li2SO3
charges :
Li = +1 S = +4 O = -2
multiply the charge with the subscripted number next to the element
Li = +1
Li2 = +2
O = -2
O3 = -8
in a compound oxidation numbers have to equal 0
+2 S -6 = 0
S -4 = 0
S = +4
Sulfur = +4
2.
MgCl2
Mg = +2
+2 Cl2 = 0
Cl2 = -2
Cl by itself = -2 divided by 2 = -1
Chlorine = -1
3.
SiO2
Silicon = +4
4.
Sulfur in H2SO4
H: +1 S: +6 O: -2
H2SO4
H2 : +2 O4: -8
+2 +S -8 = 0
S - 6 = 0
S = +6
Sulfur = +6
5.
Sulfur in SO4^2-
Sulfur in SO4
Sulfur = +4
6.
Manganese in MnO4^-
Manganese in MnO4
Manganese = +4
7.
Cr2O7^2-
Dichromate
Cr in Cr2O7^2- or Cr2O7-2-
Cr: +6 O: -2
Based on periodic trends and the data in the table above, which of the following is the most probable value for the ionic radius of K+?
Based on periodic trends, the most probable value for the ionic radius of K⁺ is 133 pm.
What are periodic trends?
Periodic trends are the observation which are seen in the chemical and physical elements found in the periodic table.
Periodic trends is based on the periodicity of elements.
Periodicity is the variation seen in the chemical and physical properties of the elements in the period table in a regular pattern, both down the groups and across the periods.
The periodic trends observed in metallic ions is that ionic radius of metallic ions increase down a group but decreases across a period.
Based on this periodic trend, the most likely size of the potassium ion, K⁺ is 133 pm.
In conclusion, the ionic radius of metallic ions increase down a group and decrease across a period.
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Amount of H2SO4 in 2 litres, having 28% concentration solution
Answer:
The amount of H2SO4 in 2 litres is 560gm.
Explanation:
Given,
mass of sulphuric acid / volume of solution =28%
Therefore, mass of sulphuric acid in 100 ml solution is 28 grams.
We know that,
volume of solution is 2000ml.
Thus,
mass of sulphuric acid in 2000ml is
(28/100) ×2000
=28×20
=560gm
Thus, the mass of sulphuric acid is 560gm.
Definition
a visual representation of data that uses unconnected plotted points
How many molecules of H₂S are required to form 79.0 g of sulfur according to the following reaction? Assume excess SO2.
2 H₂S(g) + SO2(g) → 3 S(s) + 2H₂O(1)
Answer:
9.89 x 10²³ molecules H₂S
Explanation:
To find the molecules of H₂S, you need to (1) convert grams S to moles S (via the atomic mass of sulfur), then (2) convert moles S to moles H₂S (via the mole-to-mole ratio from equation coefficients), and then (3) convert moles H₂S to molecules H₂S (via Avogadro's Number). It is important to arrange the ratios/conversions in a way that allows for the cancellation of units. The final answer should have 3 sig figs to match the sig figs of the given value.
Atomic Mass (S): 32.065 g/mol
2 H₂S(s) + SO₂(g) -----> 3 S(s) + 2 H₂O(l)
Avogadro's Number:
6.022 x 10²³ molecules = 1 mole
79.0 g S 1 mole 2 moles H₂S 6.022 x 10²³ molecules
--------------- x --------------- x ---------------------- x ------------------------------------- =
32.065 g 3 moles S 1 mole
= 9.89 x 10²³ molecules H₂S
What volume, in liters, of 0.023 M NH4NO3 solution can be made using 25 g NH4NO3
The molar mass of NH4NO3 is 80.043 g/mol
Answer:
14 L
Explanation:
To find the volume, you need to (1) convert grams to moles (via molar mass) and then (2) calculate the volume (via molarity equation). The final answer should have 2 sig figs to match the sig figs of the given values.
(Step 1)
Molar Mass (NH₄NO₃): 80.043 g/mol
25 grams NH₄NO₃ 1 mole
------------------------------- x ------------------------- = 0.312 moles NH₄NO₃
80.043 grams
(Step 2)
Molarity = moles / volume
0.023 M = 0.312 moles / volume <----- Insert values
(0.023 M) x volume = 0.312 moles <----- Multiply both sides by volume
volume = 14 L <----- Divide both sides by 0.023
Volume, in liters, of 0.023 M NH₄NO₃ solution can be made using 25 g NH₄NO₃ are 13.47L.
What is Molarity?Molarity of a given solution is known as the total number of moles of solute per litre of the solution. A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.
Molarity = (No. of moles of solute ÷ Volume of solution in liters)
The unit of molarity is mol L⁻¹.
Molarity is temperature dependent because as temperature changes, volume of the solution also changes.
No. of moles of solute = Mass / Molar mass
No. of moles of solute = 0.31
Hence,
Volume of solution in liters = No. of moles of solute ÷ molarity
= 13.47 litres
Therefore, Volume, in liters, of 0.023 M NH₄NO₃ solution can be made using 25 g NH₄NO₃ are 13.47L.
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Which element has an electron configuration of 1s22s22p63s23p3 ?
Group of answer choices
A. Silicon
B. Nitrogen
C. Arsenic
D. Phosphorus
Answer:
D. phosphorusExplanation:
Greetings !
The electronic configuration 1s²,2s²,2p⁶,3s²,3p³ represents phosphorus with atomic number 15.
The electron configuration 1s², 2s², 2p⁶, 3s², 3p³ corresponds to the element phosphorus. The first two shells are full, with 2 electrons in each shell. The third shell has 2 electrons in the 3s subshell and 3 electrons in the 3p subshell. Hence option D is correct.
Phosphorus is a chemical element with the symbol P and atomic number 15. It belongs to Group 15 (or Group V) of the periodic table, which is also known as the nitrogen group. Here are some key features and characteristics of phosphorus:
Phosphorus is a non-metal, and at room temperature, it exists in several allotropes. The most common forms are white phosphorus, red phosphorus, and black phosphorus.
White phosphorus is a highly reactive and toxic waxy solid, while red phosphorus is less reactive and is often used in safety matches. Black phosphorus is a semiconductor material with interesting electronic properties.
Therefore option D) phosphorous is correct.
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If you do a lab that burns Magnesium in pure Oxygen what would the empirical formula of the compound be if you started with 0.6 g Magnesium and 0.4 g of Oxygen?
Group of answer choices
A. Mg2O2
B. Mg2O3
C. Mg3O2
D. MgO
Answer:
Empirical Formula = MgO
Kindly award branliest
Explanation:
Elements = Mg O
Mass/ 0.6g/ 0.4g/
RAM 24 16
= 0.025 0.025
Divide by
the smallest = 0.025/ 0.025/
value. 0.025 0.025
Mole ratio = 1 : 1
Empirical Formula = MgO
What volume of hydrogen (in L) is produced
from the complete reaction of 56.49 g of
magnesium metal at STP?
(Mg = 24.30 g/mol)
Mg(s) + 2HCl(aq) → MgCl₂(aq) + H₂(g)
Hint: 1 mole of gas at STP occupies 22.4 L
Answer:
52.07 L H₂
Explanation:
Before you can find the volume of H₂, you need to find the moles of H₂. To do this, you need to (1) convert grams Mg to moles (via the atomic mass) and then (2) convert moles Mg to moles H₂ (via the mole-to-mole ratio from equation coefficients).
Atomic Mass (Mg): 24.30 g/mol
1 Mg(s) + 2 HCl(aq) ---> MgCl₂(aq) + 1 H₂(g)
^ ^
56.49 g Mg 1 mole 1 mole H₂
------------------- x ----------------- x -------------------- = 2.32 moles H₂
24.30 g 1 mole Mg
Now that you know the moles of H₂, you need to determine the volume at STP. To do this, you need to set up a proportion comparing the mole value versus the volume. Then, you can cross-multiply to solve for the unknown volume. The final answer should have 4 sig figs to match the given values.
1 mole 2.32 moles
-------------- = -------------------- <----- Set up proportion
22.4 L ? L
(1 mole) x ? L = 52.07 <----- Cross-multiply
? L = 52.07 <----- Divide both sides by 1 mole
A mixture of 0.600 mol of bromine and 1.600 mol of iodine is placed into a rigid 1.000-L container at 350°C.
Br2(g) + I2(g) ↔ 2IBr(g)
When the mixture has come to equilibrium, the concentration of iodine monobromide is 1.190 M. What is the equilibrium constant for this reaction at 350°C?
Show step-by step explanation.
A) 3.55 × 10^3
B) 1.24
C) 1.47
D) 282
E) 325
The equilibrium constant of the reaction is 282. Option D
What is equilibrium constant?The term equilibrium constant refers to the number that often depict how much the process is able to turn the reactants in to products. In other words, if the reactants are readily turned into products, then it follows that the equilibrium constant will be large and positive.
Concentration of bromine = 0.600 mol /1.000-L = 0.600 M
Concentration of iodine = 1.600 mol/1.000-L = 1.600M
In this case, we must set up the ICE table as shown;
Br2(g) + I2(g) ↔ 2IBr(g)
I 0.6 1.6 0
C -x -x +2x
E 0.6 - x 1.6 - x 1.190
If 2x = 1.190
x = 1.190/2
x = 0.595
The concentrations at equilibrium are;
[Br2] = 0.6 - 0.595 = 0.005
[I2] = 1.6 - 0.595 = 1.005
Hence;
Kc = [IBr]^2/[Br2] [I2]
Kc = ( 1.190)^2/(0.005) (1.005)
Kc = 282
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2C2H2(g)+5O2(g)=4CO2(g)+2H2O(g)
How many liters of C2H2 are required to product 12.0 moles CO2, assuming the reaction is at STP?
The volume of ethyne, C₂H₂ required to produce 12 moles of CO₂ assuming the reaction is at STP is 134.4 L
Balanced equation2C₂H₂(g) + 5O₂(g) --> 4CO₂(g) + 2H₂O(g)
From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
How to determine the mole of C₂H₂ needed to produce 12 moles of CO₂From the balanced equation above,
4 moles of CO₂ were produced by 2 moles of C₂H₂
Therefore,
12 moles of CO₂ will be produce by = (12 × 2) / 4 = 6 moles of C₂H₂
How to determine the volume (in L) of C₂H₂ needed at STPAt standard temperature and pressure (STP),
1 mole of C₂H₂ = 22.4 L
Therefore,
6 moles of C₂H₂ = 6 × 22.4
6 moles of C₂H₂ = 134.4 L
Thus, we can conclude that the volume of C₂H₂ needed for the reaction at STP is 134.4 L
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How many isomers does propane have?
01
02
03
05
Answer:
A.) 1
Explanation:
Propane only exists in one conformation. It does not have enough carbons to form branches, and there are only hydrogens attached to each carbon. Furthermore, there is no way to twist the carbon or change its orientation (ex. cis- and trans-) to result in a different structure of propane. There is no other way to represent the molecule without drawing a different molecule.
Which Inorganic Substance has a melting point of -101°C and a boiling point of -35°C?
Group of answer choices
A. Chlorine
B. Hydrogen
C. Hydrogen Sulfide
D. Hydrogen Chloride
The inorganic substance that has a melting point of -101°C and a boiling point of -35°C is chlorine (option A).
What is melting and boiling point?Melting point is the temperature at which the solid and liquid phases of a substance are in equilibrium.
On the other hand, the boiling point is the temperature at which a liquid boils, with the vapor pressure equal to the given external pressure.
Chemical elements and compounds have specific boiling and melting points that distinguishes them chemically.
The following are the melting and boiling point of the given compound and elements respectively;
Chlorine - -101°C and -35°CHydrogen: -259.2°C and -252.9 °CHydrogen sulfide: -85.5 °C and -60°CHydrogen chloride: -114.2 °C and - 85°CTherefore, the inorganic substance that has a melting point of -101°C and a boiling point of -35°C is chlorine.
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How could you prepare 4-methyl-3-hexanone from ketone containing no more than six carbon atom?
First base abstract a proton from acidic hydrogen gives carbanion.
What is a carbon atom?
A carbon chain's fundamental carbon atoms are those at each end. For instance, butane contains two basic carbon atoms. A secondary carbon atom, represented by the symbol 2°, is a carbon atom joined to two more carbon atoms.The first electron shell of carbon has two electrons, whereas the second one contains four of the available eight spaces. Carbon has two electron shells. Atoms share their outermost shell's electrons when they combine to form bonds. Since the outer shell of carbon has four vacant spaces, it can form bonds with four additional atoms.The first two electrons fill the inner shell, which is the conduction (inner) shell, and the remaining four are left in the second shell, which is the valence (outer) shell because carbon has an atomic number of six (six protons and six electrons in a neutral atom).Here First base abstract, a proton from acidic hydrogen gives carbanion
Which undergoes enolate form, then it reacts with CH3I, gives4-methyl-3-hexanone as below:
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The compound iron oxide can exist with either iron(II) ions or iron(III) ions. Conduct Internet research to learn about the differences between iron(II) oxide and iron(III) oxide. Give the chemical formula for each compound. Describe their appearance and uses. Based on your findings, are these two forms of the same compound, or are they two completely different compounds?
(What goes in the 6 empty spaces?)
Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
What is Iron (II) Oxide ?The formula of the Iron II oxide is FeO. Common name of Iron (II) Oxide is Ferrous Oxide. Iron (II) Oxide is a black colored powder. The mineral form of Iron (II) oxide is known as Wustite. Iron (II) Oxide is used as a pigment. It is also used to make dyes.
What is Iron (III) Oxide ?The formula of the Iron (III) Oxide is Fe₂O₃. Common name of Iron (III) Oxide is Ferric oxide. Iron (III) Oxide appears as Red-Brown solid. It is also known as Hematite. Iron (III) oxide is used as pigments. It is used in dental composites , cosmetics. It is also used to apply the final polish on metallic jewellery.
Thus from the above conclusion we can say that Based on our finding these two compounds are not same they are completely different from each other as Formula of both compounds are different, their appearance is also different from each other.
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The equilibrium expression for the the reaction:
H2(g) + I2(g) <--> 2HI(g) would be:
Group of answer choices
A. K = 2[HI] / [H2][I2]
B. K = [H2][I2] / [HI]2
C. K = [H2][I2] / 2[HI]
D. K = [HI]2 / [H2][I2]
Answer:
D.) [tex]K = \frac{[HI]^{2} }{[H_{2} ] [I_{2} ] }[/tex]
Explanation:
The general equilibrium expression looks like this:
[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex]
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = formulas
-----> lowercase letters = balanced equation coefficients
In this case, all of the reactants and products are gases, so they should all be included in the expression. The products are in the numerator and the reactants are in the denominator. This makes the correct expression:
[tex]K = \frac{[HI]^{c}}{[H_{2} ]^{a} [I_{2} ]^{b} }[/tex] <----- Insert formulas
[tex]K = \frac{[HI]^{2}}{[H_{2} ] [I_{2} ] }[/tex] <----- Insert coefficients
QUESTION 16
What is the product of the following reaction?
+ H₂(g) → ?
Answer:
n2(g)+3h2(g)→2nh3(g) balanced
Explanation:
Wayne Breslyn
10 Points
The International Commission of Radiological Protection has set the limit for yearly radiation exposure at 1000 uSv. What is the risk
associated with this dose?
A. No risk at this limit or below.
OB. 1/2400 chance of cancer over a 40 year period.
OC. 1/1000 chance of cancer over a 40 year period.
OD. 1/100,000 chance of cancer over a 40 year period.
The maximum allowable annual dose of radiation has been set at 1000 uSv by the worldwide commission on radiological protection. At this threshold or lower, there is no risk.
What is S(sievert)?
The sievert, a measurement used to measure radiation, is used to calculate how much radiation is taken in by human tissues.1000 millisieverts are equal to one sievert (mSv) [ 1 Sv= 1000 mSv]. There are 1,000 microsieverts in a millisievert[ 1 mSv = 1000 uSv]Here are some details concerning the risks increasing radiation levels cause to our health:
Yukio Edano, Japan's Chief Cabinet Secretary, had said that radiation levels near the damaged facility on the northeast coast may rise to 400 millisieverts (mSv) per hour.The lowest dose of exposure that causes any rise in cancer probability is readily visible is 100 mSv per year. Five out of every 100 people exposed to a cumulative 1,000 mSv (1 sievert) may likely get a deadly malignancy several years later.The central nervous system, as well as the red and white blood cells, are destroyed by high radiation doses or acute radiation exposure. This impairs the immune system, making it difficult for the sufferer to fight off diseases.One sievert (1,000 mSv), for instance, only results in radiation sickness, which includes nausea, vomiting, and bleeding, but not death. About half of individuals exposed to a single dose of 5 sieverts would perish within a month.Therefore the correct choice is an option (A).
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Answer:
Answer D
Explanation:from founders Edtell :
A dose of 1000 uSv is believed to carry a 1/100,000 risk of getting cancer over 40 years due to your exposure to radiation. The average dose is around 2400 uSv.
Given the reaction: A + B <--> C + D
The concentrations at equilibrium are [A] = 1 M, [B] = 1 M, [C] = 2 M, and [D] = 2 M. What is the value of the equilibrium constant (K)?
Group of answer choices
A. 4.0
B. 2.0
C. 1.0
D. 0.25
Answer:
A.) 4.0
Explanation:
The general equilibrium expression looks like this:
[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex]
In this expression,
-----> K = equilibrium constant
-----> uppercase letters = molarity
-----> lowercase letters = balanced equation coefficients
In this case, the molarity's do not need to be raised to any numbers because the coefficients in the balanced equation are all 1. You can find the constant by plugging the given molarities into the equation and simplifying.
[tex]K = \frac{[C]^{c} [D]^{d} }{[A]^{a} [B]^{b} }[/tex] <----- Equilibrium expression
[tex]K = \frac{[2 M] [2 M]}{[1 M] [1 M] }[/tex] <----- Insert molarities
[tex]K = \frac{4}{1 }[/tex] <----- Multiply
[tex]K = 4[/tex] <----- Divide
Assuming ideal solution behavior, what is the boiling point of a solution of 115.0 g of nonvolatile sucrose (table sugar), C₁₂H₂₂O₁₁ (342.300 g/mol), in 350.0 g of water (Kb = 0.512 °C m⁻¹; boiling point = 100.0 °C)?
The boiling point of the solution will be 100.97 ° C.
[tex]T_f[/tex], pure water = 0.00 ° Celsius.
[tex]T_b[/tex] , pure water = 100° Celcius
[tex]K_b[/tex] = 0.512 C kg/mol
[tex]K_f[/tex] = -1.86 C kg/mol.
Given,
[tex]K_b = \frac{0.512 C kg}{mol}[/tex]
[tex]m = \frac{115g \frac{mol }{342.300g} }{0.35 kg}[/tex]
m = 0.95
i = 2 ( assuming no ion pairing)
Now, recall,
Δ[tex]T_b[/tex] =[tex]iK_bm[/tex]
Hence,
Δ[tex]T_b[/tex] = [tex]iK_bm[/tex]
= 2 × 0.512 × 0.95
= 0.97 °C
Therefore, the boiling point of the solution will be 100.97 °C.
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Which of the following properties allows water molecules to stick to othe types of molecules?
A) Viscosity
B) Adhesion
C) Surface Tension
D) Density
Answer:
B.) Adhesion
Explanation:
A.) is incorrect. Viscosity is a measure of internal friction that affects the fluidity of a liquid.
B.) is correct. Adhesion is the ability of water to stick to other substances (which are not water).
C.) is incorrect. Surface tension is the tension created by the bonds of the surface particles.
D.) is incorrect. Density is a ratio that compares mass to volume.
An oven-cleaning solution is 40.0% (by mass) NaOH.
If one jar of this product contains 458 g of solution, how much NaOH (by mass) does it contain?
The amount of NaOH by mass the jar contains will be 183.2 g
Percent compositionThe percent by mass of NaOH in the oven-cleaning solution is 40.0%.
This means that for every 100 g of the cleaning solution, there would be 40 g of NaOH.
Now, the jar in question contains 458 g of this solution which is 40.0% NaOH by mass.
The amount of NaOH in the jar can be calculated as:
40/100 x 458 = 183.2 g
This means that 458 g of the oven-cleaning solution that is present in the jar contains 183.2 g of NaOH.
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What is the [OH-] if the [H3O+] is 1 x 10 -6?
The answer is [OH⁻] = 1 x 10⁻⁸.
To find OH⁻, divide the ionic product of water by [H₃O⁺] as :
OH⁻ + H₃O⁺ = H₂O
[OH⁻] = 1 x 10⁻¹⁴ / 1 x 10⁻⁶[OH⁻] = 1 x 10⁻⁸How much heat is added if .1915g of water increases in temperature by .592 degrees C
Based upon the ion charge of the following polyatomic ions, predict the formula for the following compounds.
sulfate = SO42
phosphate = PO43
hydroxide OH-
sodium hydroxide
O Na(OH)2
O Na(OH)3
O Na₂OH
O NaOH
Answer:
D.) NaOH
Explanation:
Sodium always forms the cation, Na⁺.
Hydroxide is always written as OH⁻.
The compound should have an overall charge of 0 (be neutral). As you can see, the charges perfectly balance out (+1 + (-1) = 0). Therefore, there only needs to be one atom of each ion. The ionic compound is thus NaOH.
The Haber process is a method to produce ammonia from hydrogen and nitrogen gases. The reaction is:
N2(g) + 3 H2(g) <--> 2 NH3(g)
If hydrogen gas is added after the reaction has reached equilibrium, the reaction will:
Group of answer choices
A. Need more information
B. Stop. All of the nitrogen gas has been used up.
C. Shift to the left to produce more reactants
D. Shift to the right to produce more product
Answer:
D.) Shift to the right to produce more product
Explanation:
When more reactants are added to a reaction, the equilibrium will shift to the product side to restore the balance.
As such, when H₂ (a reactant) is added, the reaction will shift to the product side, resulting in an increase of NH₃.
For the reaction: 3 H2(g) + N2(g) <--> 2 NH3(g), the concentrations at equilbrium were [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M. What is the equilibrium constant (K)?
Group of answer choices
A. K = 3.1 x 105
B. K = 560
C. K = 5.6 x 10-4
D. K = 1.8 x 10-3
The equilibrium constant, k of the reaction in which case, the concentrations of the given reactants and products are as indicated is; Choice A; K = 3.1 x 10⁵
What is the equilibrium constant , k of the reaction as described in the task content?It follows from above that the concentrations of the reactants and products are as follows; [H2] = 0.10 M, [N2] = 0.10 M, and [NH3] = 5.6 M at equilibrium.
Hence, the equilibrium constant of the reaction in discuss is;
K = [5.6]²/[0.10]³[0.10]
k = 5.6² × 10⁴
k = 3.136 × 10⁵
K = 3.1 × 10⁵.
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=> The approximate mss of an electron is 1/10²⁷ g , Calculate the uncertainty in its velocity if the uncertainty in its position were of the order of 1/10¹¹ m ( h = 6.6 × 1/10³⁴ kg m² per sec ) ..
Answer:
Δx(m.Δv)=h/4π
here ,
Δv = uncertainty in velocity
10−11×10−27×Δv=6.626×10−34/4×22/7
=5.25×103ms−1
[tex]{ \qquad\qquad\huge\underline{{\sf Answer}}} [/tex]
Here we go ~
According to Heisenberg's uncertainty principle :
[tex]\qquad \sf \dashrightarrow \: \Delta x \Delta p \geqslant \cfrac{h}{4 \pi} [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta x \cdot m \Delta v \geqslant \cfrac{h}{4 \pi}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{h}{4 \pi \cdot m \Delta x}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 \times 10 {}^{ - 34} }{4 \pi \cdot 10 {}^{ - 27} \times 10 {}^{ - 3} \times 10 {}^{ - 11} }[/tex]
[tex] \textsf{ [ we took } [/tex][tex]{ {10}^{-3} } [/tex][tex] \textsf{because mass of electron is} [/tex][tex] \textsf{ given in grams that need to be converted into kg ]} [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \pi } \times \cfrac{10 {}^{ - 34} } {10 {}^{ (- 27 - 3 - 11)} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times \cfrac{10 {}^{ - 34} } {10 {}^{ - 41} } [/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{4 \times 3.14 } \times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant \cfrac{6.6 }{12.56 } \times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant0.525\times {10 {}^{ 7}}[/tex]
[tex]\qquad \sf \dashrightarrow \: \Delta v \geqslant5.25\times {10 {}^{ 6}} \:\:m/s[/tex]
what is the correct iupac name for the following structure ch3-ch2-ch=ch2
The correct IUPAC name of the following structure CH3-CH2-CH=CH2 is But - 1 - ene
IUPAC rules for alkene nomenclatureThe parent alkene is chosen to have the longest carbon chain containing the carbon-carbon double bond.The alkane's suffix "ane" is changed to "ene." An alkene is referred to as a diene or triene depending on whether a double bond appears twice or three times in the parent chain.the location of side chains or double bonds denoted by the numbers 1, 2, 3, etc.The carbon atom in the double bond, which is written directly before the suffix "ene," receives the lowest number because it is the longest chain and is numbered from that end. If both sides of a double bond receive the same number as the chain is being numbered, the carbon chain is numbered so that the substituent receives the lowest number.Hence the structure CH3-CH2-CH=CH2 is named on the basis of the above rule as but - 1 - ene.
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State whether the following liquids are miscible with hexane (C6H14) by entering "yes" or "no".
Benzene, C6H6
iron (IIl) nitrate, Fe(NO3)3
Sulfuric acid, H2SO4
Benzene, C6H6 is miscible with hexane (C6H14) but iron (IIl) nitrate, and Sulfuric acid, H2SO4Fe(NO3)3 are not miscible with hexane (C6H14)
Since organic or non polar dissolves in nom polar solvent.here both benzene and hexane (C6H14) are non polar solvents.But iron (IIl) nitrate, Fe(NO3)3 and Sulfuric acid, H2SO4 are inorganic and polar, therefore cannot dissolve with non polar solvent like hexane.
Miscible is a flowery heard that oil and water aren't very miscible substances, while seltzer and orange juice are miscible and scrumptious.Miscible beverages are also described as liquids that can blend to form a homogeneous solution. Miscible drinks generally blend with out limit, meaning they may be soluble at all quantities.
Miscible approach the materials blend completely. If substances are miscible, they're also absolutely soluble in each other no matter the order of creation. for example, tetrahydrofuran and water are miscible.
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