Given:
The graph of a quadratic function.
To find:
The equation of the quadratic function in factored form.
Solution:
From the given graph it is clear that the graph of the function intersect the x-axis at point (-3,0) and (2,0).
Since -3 and 2 are the zeros of the function, therefore (x+3) and (x-2) are the factors of the required quadratic function.
Now, the function can be written as:
[tex]f(x)=a(x+3)(x-2)[/tex] ...(i)
The graph of the function intersect the y-axis at (0,-6). Substituting [tex]x=0,f(x)=-6[/tex] in (i), we get
[tex]-6=a(0+3)(0-2)[/tex]
[tex]-6=a(3)(-2)[/tex]
[tex]-6=-6a[/tex]
[tex]\dfrac{-6}{-6}=a[/tex]
[tex]1=a[/tex]
Substituting [tex]a=1[/tex] in (i), we get
[tex]f(x)=1(x+3)(x-2)[/tex]
Therefore, the required function is [tex]f(x)=1(x+3)(x-2)[/tex].
find the discriminantof the quadratic equation root 2 X square + 7 x + 5 root 2
[tex]\displaystyle\ 2x^2+7x+5\sqrt{2} =0 \\\\\boxed{D=7^2-4\cdot2\cdot 5\sqrt{2} =49-40\sqrt{2} }[/tex]
pplied for a job as a cashier at a hardware store. As part of her employment screening, she was asked to take an exam that had general mathematical aptitude questions in it. This type of selection test is referred to as a
Answer:
cognitive ability
Step-by-step explanation:
Randy walks his dog each morning. he walks 7/12 of a mile in 7 minutes how many miles does he walks in 1 minutes
Answer:
1/12 mile
Step-by-step explanation:
We can use a ratio to solve
7/12 miles x miles
---------------- = ---------------
7 minutes 1 minute
Using cross products
7 /12 * 1 = 7x
Divide each side by 7
7/12 * 1/7 = x
1/2 = x
[tex]\sf{\bold{\blue{\underline{\underline{Given}}}}}[/tex]
⠀Randy walks his dog each morning. he walks 7/12 of a mile in 7 minutes ⠀⠀⠀[tex]\sf{\bold{\red{\underline{\underline{To\:Find}}}}}[/tex]
⠀how many miles does he walks in 1 minutes⠀⠀⠀[tex]\sf{\bold{\purple{\underline{\underline{Solution}}}}}[/tex]
⠀
Randy walks 7/12 miles in 7 minutes
Sooo
He walks in one minutes is
7/12 miles in 7 minutes one minutes is [tex]\sf{\dfrac{\dfrac{7}{12}}{7} }[/tex] one minute =[tex]\sf{\dfrac{7}{12}×\dfrac{1}{7} }[/tex] one minute=[tex]\sf{\dfrac{1}{12} }[/tex][tex]\sf{\bold{\green{\underline{\underline{Answer}}}}}[/tex]
Hence,
he walks in 1 minutes is 1/12 miles.
[tex]factorise \: \\ \\ r {}^{2} - 10r + 21[/tex]
[tex]\implies {\blue {\boxed {\boxed {\purple {\sf { \: (r - 7)(r - 3) }}}}}}[/tex]
[tex]\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}[/tex]
[tex] {r}^{2} - 10r + 21[/tex]
[tex] = {r}^{2} - 7r - 3r + 21[/tex]
Taking [tex]r[/tex] as common from first two terms and [tex]3[/tex] from last two terms, we have
[tex] = r(r - 7) - 3(r - 7)[/tex]
Taking the factor [tex](x-7)[/tex] as common,
[tex] = (r - 7)(r - 3)[/tex]
[tex]\bold{ \green{ \star{ \orange{Mystique35}}}}⋆[/tex]
Step-by-step explanation:
Your Answer with
Explanation is given in the attachment
Hope it is helpful to you
✌️✌️✌️✌️✌️✌️✌️
1.the graph of y = x² is moved five units upward
2.the graph of y = 5x² is moved six units to the left
3.the graph of y = -2x² is moved seven units downward
4.the graph of y = -x² is moved two units to the left and four units downward
5.the graph of y = -3x² is moved two units to the right
Answer:
I guess that we want to find the equation for each case.
First, let's define the translations:
Horizontal translation.
For a function f(x), an horizontal translation of N units is written as:
g(x) = f(x + N)
if N > 0, the translation is to the left
if N < 0, the translation is to the right.
Vertical translation:
For a function f(x), a vertical translation of N units is written as:
g(x) = f(x) + N
if N > 0, the translation is upwards
if N < 0, the translation is downwards.
Now that we know these, we can find the equations for each case:
1. the graph of y = x² is moved five units upward
the graph is given by a vertical translation of 5 units upward.
y = x^2 + 5
2 the graph of y = 5x² is moved six units to the left
this is:
y = 5*(x + 6)^2
3: the graph of y = -2x² is moved seven units downward
this is:
y = -2x^2 - 7
4: the graph of y = -x² is moved two units to the left and four units downward
now we have two translations, first 4 units to the left and then 4 units downwards, this gives:
y = -(x + 4)^2 - 4
5: the graph of y = -3x² is moved two units to the right
Remember that to move the graph to the right, we need to have N negative, then:
y = -3(x - 2)^2
Please look at picture answer and explain work
Answer: The answer is D. 240 grams
Step-by-step explanation:
1. Find the volume.
2cm×3cm×5cm=30 cubic centimeters
2. Find the volume of the other box.
4cm×9cm×5cm=180 cubic centimeters.
3. Divide. 180÷30=6
4. 6 times the amount it can hold, 40=240 grams of clay.
Hope that helped!
Answer:
Step-by-step explanation:
we are told that the box is 2 cm high, 3 cm wide 5 cm long and holds 40 grams of clay
so 2*3*5 = 30 [tex]cm^{3}[/tex]
so the 30 cubic centimeter volume holds 40 grams ( it would have been nice if they had let the box hold 30 grams but, no :(
40/30 = 1.333333 or 1 and [tex]\frac{1}{3}[/tex] of a gram okay, sooooo now we know each cubic centimeter holds that much clay, now let's solve for how many cubic centimeters are in the bigger box, you can try to solve it 1st if you'd like to practice, below I solve it
twice the height so 2(2)=4 high
3 times the width , so 3(3) = 9 wide
same length, so 5 long
4*9*5 = 180
180*1.33333333333 = 240 grams of clay in 2nd bigger box :)
I'm sure there is a funny box joke in there some where :DDDD
do you get the math? :)
help please
1 2 3 4 5 6 7 8 9 10
Answer:
place it 2 3 4 5 6 7 8 9 10 1 then is come 18
Answer:
2 3 4 5 6 7 8 9 10 1 then come 18
Find the surface area of the pyramid
❊ Simplify :
[tex] \large{ \bf{ \frac{x - 1}{ {x}^{2} - 3x + 2} + \frac{x - 2}{ {x}^{2} - 5x + 6 } + \frac{x - 5}{ {x}^{2} - 8x + 15 } }}[/tex]
[tex] \large{ \tt{ans : \bf{ \frac{3x - 7}{(x - 2)(x - 3)} }}}[/tex]
- Show your workings *
- Irrelevant / Random answers will be reported!
[tex]\red{\frak{Given}}\Bigg\{ \sf \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } [/tex]
[tex]\rule{200}4[/tex]
[tex]\sf\longrightarrow \small \dfrac{x - 1}{ {x}^{2} - 3x + 2} + \dfrac{x - 2}{ {x}^{2} - 5x + 6 } + \dfrac{x - 5}{ {x}^{2} - 8x + 15 } \\\\\\\sf\longrightarrow \small \dfrac{ x-1}{x^2-x -2x +2} +\dfrac{ x-2}{x^2-3x-2x+6} +\dfrac{ x -5}{x^2-5x -3x + 15 } \\\\\\\sf\longrightarrow\small \dfrac{ x -1}{ x ( x - 1) -2(x-1) } +\dfrac{ x-2}{x ( x -3) -2( x -3)} +\dfrac{ x -5}{ x(x-5) -3( x -5) } \\\\\\\sf\longrightarrow \small \dfrac{ x -1}{ ( x-2) (x-1) } +\dfrac{ x-2}{( x -2)(x-3) } +\dfrac{ x -5}{ (x-3)(x-5) } \\\\\\\sf\longrightarrow\small \dfrac{ 1}{ x-2} +\dfrac{ 1}{ x -3} +\dfrac{1}{ x -3} \\\\\\\sf\longrightarrow \small \dfrac{1}{x-2} +\dfrac{2}{x-3} \\\\\\\sf\longrightarrow \small \dfrac{ x-3 +2(x-2)}{ ( x -3)(x-2) } \\\\\\\sf\longrightarrow \small \dfrac{ x - 3 +2x -4 }{ (x-3)(x-2) } \\\\\\\sf\longrightarrow \underset{\blue{\sf Required \ Answer }}{\underbrace{\boxed{\pink{\frak{ \dfrac{ 3x -7}{ ( x -2)(x-3) } }}}}}[/tex]
[tex]\rule{200}4[/tex]
Answer:
Your solution ..................
pa answer naman po!!!
[tex]\bold{{Answer:}}[/tex]
Tropical Rain Forest
1.B
2.A
3.Di ko alam
Coral Reefs
1.C
2.E
3.I
Mangrove Swamps
1.D
2.H
3.G
pa tama nalang kung mali ah
tao lang nag kakamali rin hehe
[tex]\bold\blue{{Answer:}}[/tex]
Tropical Rain Forest
1.B
2.A
3.F
Coral Reefs
1.C
2.E
3.I
Mangrove Swamps
1.D
2.H
3.G
Taga Pilipinas ka din ba o hindi?
Can someone help me with this math homework please!
Answer:
x = 12.5
Step-by-step explanation:
Explanation in progress ;-)
Please help me with this problem
Answer:
6a = 6 * a
2a * b = 2ab
Step-by-step explanation:
2a * 2b = 4ab not 2ab
6 * a is the same as 6a
5a = 5 * a not 5 + a
3ab has different variables then 3c therefore the expression cannot be true
2ab is the same as 2a * b
does anyone know how to solve this ?
Answer:
D) 144π sq. units
Step-by-step explanation:
The formula for finding the surface area of a sphere is 4π
Substitute 6 in for r. 4π = 144π
Answer:
144π sq. units
Step-by-step explanation:
The formula to determine the surface area of a sphere is: 4πr^2
But there’s no digit of pi given. Therefore we will use the formula but ignoring pi:
4πr^2
= 4r^2
= 4(6^2)
= 4(36)
= 144
Surface area is measured in square units.
Therefore the answer is 144π. The answer will be the true answer surface area once we know what π to use. For now, π will be just a variable next to 144 and will be later multiplied to it.
I hope you understand this! Hope I helped!
Helpppp someone please
Given:
The graph of system of inequalities.
To find:
The system of inequalities.
Solution:
From the given graph it is clear that the shaded region is lies below the line y=10 and the boundary line y=10 is a solid line. So, the sign of inequality must be [tex]\leq[/tex].
[tex]y\leq 10[/tex].
The shaded region lies on the right side of the y-axis. So, [tex]x\geq 0[/tex].
Another boundary line passes through the point (0,1) and (1,2). So, the equation of the line is:
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-1=\dfrac{2-1}{1-0}(x-0)[/tex]
[tex]y=1(x)+1[/tex]
[tex]y=x+1[/tex]
The boundary line [tex]y=x+1[/tex] is a dotted line and the shaded region lies above the boundary line, so the sign of inequality must be [tex]>[/tex].
[tex]y> x+1[/tex]
So, the required system of inequalities is:
[tex]y> x+1[/tex]
[tex]y\leq 10[/tex]
[tex]x\geq 0[/tex]
Therefore, the correct option is B.
Helppppp and explain thankyouuuu
Answer:
whats the question sir
Step-by-step explanation:
can you show me it like type it for me
WILL MAKE BRAINLIEST IF CORRECT!!
What is the equation of the line? *easy*
Answer:
y = - 7
Step-by-step explanation:
The equation of a horizontal line parallel to the x- axis is
y = c
where c is the value of the y- coordinates the line passes through.
The line passes through all points with a y- coordinate of - 7, then
y = - 7 ← equation of line
common factors of 8xy⁴,6x²y,10x²y²
Answer:
[tex]2^{3}[/tex]×5×3×[tex]x^{2}[/tex]×[tex]y^{4}[/tex]
Step-by-step explanation:
[tex]8xy^{4}[/tex]= [tex]2^{3}[/tex]×[tex]x[/tex]×[tex]y^{4}[/tex]
6[tex]x^{2} y[/tex]= 2×3×[tex]x^{2}[/tex]×[tex]y^{}[/tex]
10[tex]x^{2} y^{2}[/tex] = 2×5×[tex]x^{2}[/tex]×[tex]y^{2}[/tex]
[tex]2^{3}[/tex]×5×3×[tex]x^{2}[/tex]×[tex]y^{4}[/tex]
Flying against the wind, a jet travels miles in hours. Flying with the wind, the same jet travels miles in hours. What is the rate of the jet in still air and what is the rate of the wind
Answer:
Velocity in still air: 760 mi/ hr
Velocity against the wind: 210 mi/ hr
Step-by-step explanation:
Given
See attachment for complete question
Required
The rate in still air
The rate of the wind
From the question, the velocity (v) against the wind is:
[tex]v =\frac{distance}{time}[/tex]
[tex]v =\frac{3040}{4}[/tex]
[tex]v_1 =760mi/hr[/tex]
The velocity with the wind is:
[tex]v_2 = \frac{8260}{7}[/tex]
[tex]v_2 = 1180mi/hr[/tex]
Let:
[tex]x \to[/tex] velocity in still air
[tex]y \to[/tex] velocity of the wind
So, we have:
[tex]x - y = 760[/tex]
[tex]x + y = 1180[/tex]
Add both equations
[tex]x + x -y + y = 760 + 1180[/tex]
[tex]2x = 1940[/tex]
Divide by 2
[tex]x = 970[/tex]
Substitute [tex]x = 970[/tex] in [tex]x - y = 760[/tex]
[tex]970 - y= 760[/tex]
Make y the subject
[tex]y = 970 - 760[/tex]
[tex]y = 210[/tex]
I got stuck but if someone could help me with this question it’d be greatly appreciated!
Answer:
In step 1 she multiplied the numerators together and denominators together instead she should have done this
30*5 = 12*x
150=12x
150÷12=x
12.5=x
Write an
equivalent expression by distributing the
"---"
sign outside the parentheses:
-(3.9d + 10)
Answer of this question
-3.9d-10the a oranial price of a skate broad was reduced by 15 dollars .the new price is 49 dollars if p=the stakebroads oranail price in dollars what mathematical sentence expresses the information
a.49-p=15
b.15-p=49
c.15+p=49
d.p-15=49
Answer:
d)
Step-by-step explanation:
We will get the new price by subtracting the reduction price from the original price.
Original price - reduced price = New price
p - 15 = 49
Answer:
Option D
Step-by-step explanation:
p - 15 = 49
Option D is correct answer
S.p=315 loss percent =10% c.p=rs=xc.p=?
Given:
S.P. = 315
Loss percent = 10%
To find:
The C.P.
Solution:
Let x be the C.P.
We have,
S.P. = 315
Loss percent = 10%
[tex]S.P.=C.P.-10\%\text{ of }C.P[/tex]
[tex]315=x-\dfrac{10}{100}x[/tex]
[tex]315=x-0.1x[/tex]
[tex]315=0.9x[/tex]
Divide both sides by 0.9.
[tex]\dfrac{315}{0.9}=x[/tex]
[tex]350=x[/tex]
Therefore, the cost price (C.P.) is 350.
If g(x) = 2 |x| − 1, what is g(−2.3)?
Answer:
g(-2.3) = 3.6
General Formulas and Concepts:
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightAlgebra I
FunctionsFunction NotationStep-by-step explanation:
Step 1: Define
Identify
g(x) = 2|x| - 1
Step 2: Evaluate
Substitute in x [Function g(x)]: g(-2.3) = 2|-2.3| - 1Absolute values: g(-2.3) = 2(2.3) - 1Multiply: g(-2.3) = 4.6 - 1Subtract: g(-2.3) = 3.6F= P(1 + r)!
Rearrange the formula to highlight the present value.
P=
[tex]\tt\displaystyle\ P(1+r)!= r*(r-1) *(r-2)*(r-3) ..... *1[/tex]
Can someone please help?
Answer:
f(x) = (x + 4)^2 - 5
Step-by-step explanation:
Parent function: f(x) = x^2
To show this in a way that may look more familiar, f(x) = 1(x - 0)^2 + 0
Vertex form: f(x) = a(x - h)^2 + k
We know a = 1, because the slope is the same as the parent function.
Vertex: (h,k)
We can see that the vertex of the graph is (-4, -5)
So h = -4 and k = -5
Now all we need to do is plug the variables into our equation.
f(x) = a(x - h)^2 + k
f(x) = 1(x + 4)^2 - 5
f(x) = (x + 4)^2 - 5
If f(x)=5X-2 and g(x) = x+1, find (f -g)(x)
Answer:
Step by step explanation
a
What is the answer 1/3 of 12 = 1/4
Step-by-step explanation:
1/3*12=1/4
1/4=1/4
=1/4÷1/4
=0 answer
Simplify: 4y2 + 5y + 2 + 8y2 + 4y + 5.
Answer:
12y² + 9y + 7
General Formulas and Concepts:
Algebra I
Terms/CoefficientsStep-by-step explanation:
Step 1: Define
Identify
4y² + 5y + 2 + 8y² + 4y + 5
Step 2: Simplify
Combine like terms (y²): 12y² + 5y + 2 + 4y + 5Combine like terms (y): 12y² + 9y + 2 + 5Combine like terms: 12y² + 9y + 7Answer:
12y² + 9y + 7
Step-by-step explanation:
4y² + 5y + 2 + 8y² + 4y + 5
Simplify :-
4y² + 5y + 2 + 8y² + 4y + 5
arranging like terms4y² + 8y² + 5y + 4y + 2 + 5
Combine like terms12y² + 9y + 7
Given: P (-4; 7), Q ( 3;0) and R (-1;-4).
Determine:
1.1.1
the gradient of QR
the first 4 questions
Answer:
(3)(4)(4)(2)Step-by-step explanation:
1.
7 > 0.7 > 0.07 > 0.007
2.
5h - 15hg
taking 5h common
5h (1 - 3g)
3.
5(2x- 1) = 35
dividing both sides by 5
2x - 1 = 7
2x = 7 + 1
2x = 8
x = 4
4.
if x is an odd number x + 2 will also be odd.
for example
11 is an odd number
on adding 2 we get 13 which is also an odd number.