What is the final temperature in °C of 680.1 g of water (specific heat
= 4.184 J/g °C) at 24.20°C that absorbed 950.0 J of heat?

answer and e explanation

0.5L of nitrogen are needed

because the mol ratio between nitrogen and ammonia is 1:2

The name of the given compound is aluminum cyanide . and the molecular mass of the compound Al(CN)3 is 104.98g .

A metallic cyanide is aluminum cyanide. Al(CN)3 is the chemical formula. By reacting aluminum metal and mercuric cyanide in liquid ammonia, aluminum cyanide was created as an ammoniate. Water breaks down aluminum cyanide to produce aluminum hydroxide.

The mass of a given molecule is its molecular mass (m), which is expressed in daltons (Da or u). Because they contain various isotopes of an element, multiple molecules of the same substance can have distinct molecular weights. According to IUPAC, the related quantity relative molecular mass is a unitless comparison between the mass of a molecule and the unified atomic mass unit (also called the dalton). The molar mass is unrelated to, but distinct from, the molecular mass and relative molecular mass. The molar mass, which is stated in g/mol, is defined as the mass of a specific material divided by the amount of a substance. As a result, the molar mass represents the average of several molecules or particles.

Molecular mass of Al(CN)3 = 26.98 + 3×12 + 3×14 = 104.98g

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Answer: 11.1 L.

Explanation: A balloon filled with helium gas at 1.00 atm occupies 11.1 L.

Consider the gas is taken at STP. Thus at standard temperature and pressure of 1 atm where one mole of any gas contains 22.41 L. Thus helium gas at 1 atm pressure contains 22.414 L/mol

Helium is 2nd element in periodic table. It is a noble gas ncluded in the 18th group. Helium is the second most abundant element in the universe. Stars including sun is made of helium gas and hydrogen gas.

The condition at which the temperature is 298 K and pressure of 1 atm is called standard temperature and pressure or STP condition. At STP one mole pf every substance contains 22.414 liter of the gas.This is called molar volume.

Therefore, the volume of helium gas at 1 atm pressure by considering the condition of STP and the gas if taken is one moles will be 22.414 liter. This is the volume of one mole of all gas at stp.

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Answer:

b) Pine Tree

Pine trees need wind for fertilization to occur.

Answer:

Gymnosperm, So in reality its Pine Tree. ;):)

Explanation:

Gymnosperm Fertilization The female gametophyte contains several archegonia, where the egg cells originate and develop. Fertilization occurs when pollen grains (male gametophytes) are carried by the wind to the open end of an ovule, which contains the eggs, or female gametophyte.

Answer:

B: 10 g/ml

Explanation:

The formula for density is mass/volume.

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Answer:

1)

Required moles = Given mass / Molar mass

Required moles = 482.3/97.9

Required moles = 4.92 moles

2)

Required mass = Moles x Molar mass

Required mass = 0.739 x 120.743

Required mass = 89.229g

3)

Required atoms = Moles x Avogadro's number

Required atoms = 1.85 x 6.02x10²³

Required atoms = 1.114x10²⁴ atoms

4)

Required moles = Molecules / Avogadro's number

Required moles = 3.9x10¹⁸ / 6.02x10²³

Required moles = 6.478x10¯⁶ moles

5)

Required molecules = Moles x Avogadro's number

Required molecules = (Given mass / Molar mass) x Avogadro's number

Required molecules = (85.46 / 23.95) x 6.02x10²³

Required molecules = 3.56 x 6.02x10²³

Required molecules = 21.4x10²³ molecules

6)

Required mass = Given molecules x Molar mass / Avogadro's number

Required mass = 4.63x10²⁴ x 80 / 6.02x10²³

Required mass = 370.4x10²⁴ / 6.02x10²³

Required mass = 615.28g

Humans and other mammals breathe in oxygen from the air for respiration. the number of moles of air in one breath at the top of Mt Everest  is 0.0128 mol

The expression for ideal gas equation is :

PV = n RT

P is pressure = 0.500 atm

V is volume = 0.500 L

R is gas constant = 0.08206 L atm / mol K

T is temperature = -35 °C = 238 K

n is no. of moles

substituting the values in formula , we get :

PV = nRT

n = PV / RT

n = ( 0.500 × 0.500 ) / (0.08206 × 238)

n = (0.25 / 19.53 ) mol

n = 0.0128 mol

Thus, Humans and other mammals breathe in oxygen from the air for respiration. the number of moles of air in one breath at the top of Mt Everest. assume the atmospheric pressure is 0.500 atm and the temperature is -35.0°C.   is 0.0128 mol

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Answer:

The concentration of HCl is 0.0467 M.

Explanation:

What is given?

Volume 1 (V1) = 0.621 L,

Concentration 1 (C1) = 0.7 M,

Volume 2 (V2) = 9.3 L.

What do we need? Concentration 2 (C2).

Step-by-step solution:

To solve this problem we have to use the following formula:

Where in this case, concentration and volume 1 correspond to NaOH, and concentration and volume 2 correspond to HCl.

We want to find the concentration of HCl so we have to solve for 'C2' and replace the given data in the formula, like this:

The answer would be that the concentration of HCl is 0.0467 M.

Answer: False

Explanation:

For this question we will make use of the Combined Gas Law:

Answer to part A)

Given:

P2:660 mmHg

T2:

The correct answer is used, transform. Option D.

The word used means to control and use and the word transform means to change or transform. The other options are incorrect because they have different meanings than bind and convert. Adjective superlative of good better than comparative Highest Quality Excellence or Reputation Best Work best student.

Most Advantageous Most Suitable, or Most Desirable Best Way. Replace something or put something or someone in place of something or someone else Factories have replaced most of their workers with robots. Best can be a noun. Marilyn only wanted the best for herself and her family. As an adverb, it's best to modify a verb. is the best. The noun best may or may not be countable.

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The pressure and work done is Atm = -177.275 J. Workdone = 1.75 L.

Given,

5 atm of external pressure

Volume initial = V(initial) = 0.160 L

Volume final = V(final) = 0.510 L

The piston pushes back against the constant 5.00 atmospheres of external pressure. Volume increases from 0.160 L to 0.510 L.

W = -PΔV

P = 5.00 atm

V = V(initial) - V(final) = 0.510 - 0.160 = 0.35 L

W = - 5 × 0.35 = - 1.75 L.atm

Then, this effort may be represented in Joules.

1 L.atm = 101.3 J

-1.75 L.atm = -1.75 × 101.3 = -177.275 J

Keep in mind that the work done is negative since the system affects the environment in this expansion scenario, which caused a volume rise.

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The percent ionic character of this molecule is 1.29 %

This is further explained below.

[tex]\begin{aligned}\mu(\text { dipole moment })=1.100 \\d \text { (bond length) }=177 \mathrm{Pm} &=177 \times 10^{-12} \mathrm{~m} \\&=177 \times 10^{-12} \times 100 \mathrm{~cm} \\&=177 \times 10^{-10} \mathrm{~cm} \\\therefore \text { charge }=1.6 \times 10^{-19} \mathrm{C} &=4.8 \times 10^{-10} \text { es } \\\therefore \text { Ionic character }=\frac{\mu \text { observed }}{\mu \text { Ionic }(100 \%)} \times 100\end{aligned}[/tex]

[tex]\begin{aligned}\mu(100 \% \text { Ionic }) &=9 \times d \\&=4.8 \times 10^{-10} \times 177 \times 10^{-10} \mathrm{esucm} \\&=849.6 \times 10^{-20} \mathrm{esucm} \\&=8.496 \times 10^{-18} \mathrm{esucm} \end{aligned}[/tex]

because & 18=10^{-18}escecm

u =8.4960

Now Ionic character[tex]=\frac{r_{\text {obs. }}}{r(100 \% \text { Tonic })} \times 100[/tex]

[tex]&=\frac{1.10}{8.5} \times 100 \\\\&=\frac{110}{85}=1.29[/tex]

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Number of moles is 0.56 moles glucose.

calculation:-

We are given;

Mass of glucose solute is 50.50 g

Volume of solution is 500 mL

We are required to calculate the concentration of glucose.

We need to know that, molarity is the concentration of a solution in moles per liter.

Molarity = Number of moles ÷ Molar mass

Blood sugar, or glucose, is the primary sugar found in your blood. It comes from the food you devour, and is your body's foremost supply of strength. Your blood includes glucose to all your frame's cells to apply for energy. Diabetes is a sickness in which your blood sugar ranges are too excessive.

Glucose is the principle sort of sugar to your blood and your primary supply of energy in your frame's cells. Glucose comes from the foods you devour and is carried on your cells thru your bloodstream. Numerous hormones, such as insulin produced for your pancreas manage glucose tiers inside the blood.

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The percentage of CO₂ in the given mixture is 44.87%.

A mixture is a substance that is composed of two or more substances physically combined together.

The percentage of CO₂ in the given mixture is calculated as follows:

In the mixture, CO₂ is produced from the decomposition of MgCO₃ and CaCO₃ only.

Decomposition of  MgCO₃ and CaCO₃ is shown below:

MgCO₃ ---> MgO + CO₂

CaCO₃ ----> CaO + CO₂

Molar mass of MgCO₃ and CaCO₃ is 84 g/mol and 100 g/mol respectively.

Molar mass of CO₂ is 44.0 g/mol

Percentage of CO₂ in MgCO₃ and CaCO₃ is 52.38% and 44.0% respectively.

Percentage of CO₂ in 20.94% MgCO₃ = 52.38 * 20.94% = 10.97%

Percentage of CO₂ in 77.06% CaCO₃ = 44.0% * 77.06% = 33.90 %

Total percentage of CO₂ = 44.87%

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The number of moles in 1.8 x 10^23 molecules is 0.299 moles.

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• To determine whether a particular solution is ,concentrated ,or ,diluted

• To determine the ,actual concentration ,of a solution

When a chemical is added to a solution, chemical solutions are formed. Molarity is used in expressing the concentration of a solution. Molarity is the ratio of the number of moles of a solute to the volume of its solution.

Molarity is important to determine whether a particular solution is concentrated or diluted. It is also used to determine the actual concentration of a solution

Hence, to determine the concentration of any solution, the moles of the element and its volume in solution are required.

Taking into account the reaction stoichiometry, 2.95 grams of MgO from 1.78 g of Mg and 2.36 g of O₂.

In first place, the balanced reaction is:

2 Mg + O₂  → 2 MgO

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 32 grams of O₂ reacts with 48.62 grams of Mg, 2.36 grams of O₂ reacts with how much mass of Mg?

mass of Mg= (2.36 grams of O₂× 48.62 grams of Mg)÷ 32 grams of O₂

mass of Mg= 3.586 grams

But 3.586 grams of Mg are not available, 1.78 grams are available. Since you have less mass than you need to react with 2.36 grams of O₂, Mg will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 48.62 grams of Mg form 80.62 grams of MgO, 1.78 grams of Mg form how much mass of MgO?

mass of MgO= (1.78 grams of Mg× 80.62 grams of MgO)÷ 48.62 grams of Mg

mass of MgO= 2.95 grams

Finally, 2.95 grams of MgO can be produced.

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A single replacement reaction, is a type of reaction in which we have the following set up:

A + BC -> AC + B

As we can see, an element will react and switch places in a molecule, forming a new molecule and a lone element as products, and according to this set up, we don't have two ionic reactants as characteristic for a single replacement reaction, therefore letter C is the incorrect option.

2 moles of excess reagent will be left over 2H2 + O2 = 2H20 when 2 moles of H2 and 1.55 moles of oxygen react.

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Answer:

a: Tendency to break rather than bend

b: Ability to be stretched without breaking

c: Ability to move heat or charge

d: Ability to be bent or flattened

Answer:

Nitrogen atom has 5 electrons in the outer shell so it needs 3 more electrons. Therefore a triple covalent bond will form between 2 nitrogen atoms

Explanation:

Answer: 1.61g of H2O would be necessary to produce 1 L of O2 at STP

Explanation:

The question requires us to calculate the mass of water (H2O) that must be decomposed in order to produce 1 liter of oxygen gas (O2) at STP, considering the following chemical reaction:

To solve this problem, we'll need to:

1) balance the chemical equation;

2) calculate the molar mass of H2O;

3) calculate the number of moles of O2 that correspond to 1 L of this gas at STP;

4) using the balanced chemical equation, calculate the amount of moles of H2O that would be necessary to produce the required amount of O2;

5) using the molar mass of H2O, determine the mass of H2O necessary to produce 1 L of O2.

1) Balancing the chemical equation

In the given chemical equation, we can see that there are 2 O atoms on the products' side, but only 1 O atom on the reactants side. We can adjust the coefficient of H2O from 1 to 2 in order to have the same amount of O on both sides:

Next, we need to adjust the amount of H atoms: there are 4 H atoms on the reactants side, and only 2 H atoms on the products side, thus we can adjust the coefficient of H2 from 1 to 2. The balanced chemical equation for the decomposition of H2O to H2 and O2 can be written as:

2) Calculating the molar mass of H2O

We'll need the molar mass of H2O to determine its required mass, and we can determine the molar mass from the atomic masses of H and O:

O = 15.99 amu

H = 1.008 amu

We can calculate the molar mass of H2O as:

Therefore, the molar mass of H2O is 18.01 g/mol.

3) Calculating the number of moles of O2

Under standard temperature and pressure conditions (STP), 1 mol of any gas corresponds to 22.4 L of this gas. Knowing that 1 L of O2 must be produced, we can calculate the number of moles of O2 as:

22.4 L O2 ----------------------------- 1 mol O2

1 L O2 ----------------------------------- x

Solving for x, we'll have:

Therefore, 1 L of O2 corresponds to 0.00446 moles of this gas at STP.

4) Calculating the number of moles of H2O necessary

From the balanced chemical equation, we can see the 2 moles of H2O are necessary to produce 1 mol of O2, thus we can write:

1 mol O2 ------------------------ 2 mol H2O

0.0446 mol O2 --------------- y

Solving for y, we'll have:

Therefore, 0.0892 moles of H2O would be necessary to produce 1 L of O2 at STP.

5) Calculating the mass of H2O

Now that we know the required amount of H2O, in moles, and the molar mass of H2O, we can determine the mass required of H2O using the following equation:

where n is the number of moles, m is the mass of the sample and MM is the molar mass of the compound.

Applying the calculated values of n and M, we'll have:

Therefore, 1.61g of H2O would be necessary to produce 1 L of O2 at STP.

Mass of lead sulphate is 18.195g

Lead sulphate is the odorless and white crystalline powder and it is used to storage batteries as paint pigment and laboratory reagents

Given reaction is

Pb(NO₃)₂ +  H₂SO₄  → PbSO₄  + 2HNO₃

Here given data is

20 g of lead nitrate dissolved in water

And number of moles = mass/molar mass, molar mass = 331.2 g/mol

Number of moles of Pb(NO₃)₂  = 20g/331.2 g/mol

Number of moles of Pb(NO₃)₂  = 0.060g/mol

Therefore, 1 mole of Pb(NO₃)₂ will produce 1 mole of PbSO₄

0.060 mole of Pb(NO₃)₂ = 0.060 mol PbSO₄

Therefore, now we can calculate the mass :

And number of moles = mass/molar mass

Number of moles of  PbSO₄  = 0.060×303.26

Number of moles of  PbSO₄  = 18.195g

Mass of lead(II) sulfate would be produced by the action of excess dilute sulfuric acid on 20 g of lead nitrate dissolved in water is 18.195g

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The time required for the shingles to reach the  ground is t = 1.32s

Given = distance(S) =  8.52 meters

initial velocity = u =0

g  = 9.8

To find the time, use the equation,

S = ut + 1/2at²

8.52= 0(t) + 0.5(9.8)t²

t = 1.32s

The time required for the shingles to reach the  ground is  t = 1.32s

The force that pulls items toward the center of a planet or other entity is called gravity. All of the planets are kept in orbit around the sun by gravity.

The acceleration that gravity gives to objects falling freely serves as a gauge of its strength. The acceleration of gravity at Earth's surface is approximately 9.8 meters (32 feet) per second every second. As a result, during free fall, an object's speed rises by around 9.8 meters per second.

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In the electromagnetic spectrum, the infrared and UV light differ by the fact that infrared light has longer wavelengths than UV light.

The electromagnetic spectrum consists of waves made up of electromagnetic field which are capable of propogating through space and carry the radiant electromagnetic energy.

The radiation are composed of electromagnetic waves which are synchronized oscillations of electric and magnetic fields . They are created due to change which is periodic in electric as well as magnetic fields.

In vacuum ,all the electromagnetic waves travel at the same speed that is with the speed of air.

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Whenever we have a solution with a solvent like water, and a solute that is dissolved in water, we can identify this dissolved solution as an aqueous solution, therefore the symbol will be (aq), letter D

The average atomic mass of element X, given the data is 85.469 amu

How to determine the avaerage atomic mass

From the question above, the following data were obtained:

The average atomic mass of X can be obtained as illustrated below:

Average atomic mass = [(Mass of A × A%) / 100] + [(Mass of B × B%) / 100]

Average atomic mass = [(84.912 × 72.17) / 100] + [(86.909 × 27.83) / 100]

Average atomic mass = 61.282 + 24.187

Average atomic mass = 85.469 amu

Thus, the average atomic mass is 85.469 amu

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To solve this problem we need to use Boyles gas Law:

Given:

V1 = 1212 mL

P1 = 6756 Torr

P2 = 289 Torr

V2= ?

V2 = P1V1/P2

V2 = (6756 torr x 1212 mL)/289 torr

V2 = 28333.12111 mL

The balanced equation is:

Cu + 2AgNO₃ -> 2Ag + Cu(NO₃)₂

The coefficients are: 1, 2, 2, 1

The balancing of chemical equations follows the law of conservation of matter which states that matter can neither be created nor destroyed during a chemical reaction but can be transferred from one form to another.

The equation given from the question can be balanced as follow:

Cu + AgNO₃ -> Ag + Cu(NO₃)₂

There are 2 atoms of N on the right side and 1 atom on the left. It can be balanced by writing 2 before AgNO₃ as s shown below:

Cu + 2AgNO₃ -> Ag + Cu(NO₃)₂

There are 2atoms of Ag on the left side and 1 on the right. It can be balanced by writing 2 before Ag as show below:

Cu + 2AgNO₃ -> 2Ag + Cu(NO₃)₂

Thus, the equation is balanced.

The coeficients are: 1, 2, 2, 1

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