What is the image of (-5, -1) after a reflection over the x-axis?​

Answer:x=45

Step-by-step explanation:

Answer:

59.5 feet

Step-by-step explanation:

The second tree is 59.5 feet tall.

Two trees are growing in a clearing.

The first tree is 17 feet tall and casts a 10-foot shadow.

The second tree casts a 35-foot shadow.

Let x be the tall is the second tree.

Then,

The ratio of the height of the tree is;

[tex]\rm \dfrac{17}{10} = \dfrac{x}{35}\\\\17 \times 35 = x \times 10\\\\595 = 10x\\\\x = \dfrac{595}{10}\\\\x = 59.5 \ feet[/tex]

Hence, the second tree is 59.5 feet tall.

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Answer:

27.89 hours.

Step-by-step explanation:

I hope this helps! If you would like an explanation, let me know!

Answer:

First question, 28 hours

Second question, 20 minutes

Step-by-step explanation:

$9.50 for each hour + $75 for showing up on time

Let's say the employee showed up on time

(340 - 75) ÷ 9.5 = 28 hours approximately

120 ÷ 6 = 20 minutes

Answer:

Yes

Step-by-step explanation:

Because 12/18 = 2/3..(cancel 12 and 18 by 6)

Answer:

yes

Step-by-step explanation:

2x6=12

3x6=18

6 is the multiplying number

( the 2 equations are the same amount )

Answer:

  lies in the shaded regions of both the top and bottom inequalities

Step-by-step explanation:

For a point to be a solution of two inequalities, it must lie in both solution sets. It ...

  lies in the shaded regions of both the top and bottom inequalities

We want to define when a point is a solution of a system of inequalities, we will see that the correct option is: "lies in the shaded regions of both the top and bottom inequalities."

Just like in a system of equations, a solution of the system is must be a solution of both equations.

Here, a solution ot the system of inequalities must be at the same time a solution of each inequality.

Remember that the solutions of the inequalities are represented by shaded regions, so the point must belong to the intersection of the two shaded regions.

So the correct option is:

"lies in the shaded regions of both the top and bottom inequalities."

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Answer:

The correct option is;

B. N'(1, 0), U'(3, 5), L'(5, 2), H'(3, -2)

Step-by-step explanation:

The coordinates of the pre-image are given as follows;

H(1, -5), N(-1, -3), U(1, 2), and L(3, -1)

The required transformation is T₍₂, ₃₎,which is a translation of (two) 2 units right and an additional  translation of (three) 3 units up, which gives the coordinates of the image as follows;

N(-1, -3) transformed by N(-1 + 2, -3 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] N'(1, 0)

U(1, 2) transformed by U(1 + 2, 2 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] U'(3, 5)

L(3, -1) transformed by L(3 + 2, -1 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] L'(5, 2)

H(1, -5) transformed by H(1 + 2, -5 + 3)  [tex]\overset{T_{(2,\, 3)}}{\rightarrow}[/tex] H'(3, -2)

The coordinates of the vertices of the given figure after the given transformation, T₍₂, ₃₎, are N'(1, 0), U'(3, 5), L'(5, 2), and H'(3, -2).

Therefore, the correct option is N'(1, 0), U'(3, 5), L'(5, 2), H'(3, -2).

Answer:

Step-by-step explanation:

[tex]x^{2} -x-x<[/tex] 0

[tex]x^{2} -2x[/tex] < 0

x^2-2x+1<1

(x-1）^2<1

-1<x-1<1

0<x<2

[tex](x-1)^{2}[/tex][tex](x-1)^{2}[/tex]

domain: (−∞,∞)

range: [−9,∞)

=========================================

Explanation:

The graph extends forever to the left and right. This means any x value can be plugged into the function to get some y value output. The domain is the set of all real numbers in which we write (−∞,∞)  when using interval notation. This is the interval from negative infinity to positive infinity. We exclude both endpoints as we cannot reach infinity.

The smallest y value possible is y = -9 as shown by the vertex point (1, -9) being the lowest point on the parabola. The range is the set of y values such that [tex]y \ge -9[/tex] so we say [−9,∞) in interval notation. This is the interval from -9 to infinity. The square bracket says to include -9 as part of the interval.

Answer: It is A, I did this question many times before.

(−∞,∞)

Step-by-step explanation:

Answer:

First. 115°

Second. 65°

Third. 65°

Fourth. 7

Fifth. 425.25

First

angle DAB = angle ADC (since this is an isosceles trapezoid)

Second

In a trapezoid adjacent angle are supplmentary (that is their sum is 180°)

180-115 is 65°

Third

(Same reason as second)

Fourth

The side 3x+4 is same as the opposite side

So 3x + 4 = 25

on solving you get x = 7 in

Fifth

[tex]area \: = \frac{1}{2} \times length \: of \: the \: perpendicular \: (b1 + b2)[/tex]

area = 1/2 × 13.5 (20+43)

area = 1/2 × 13.5 × 63

Thus area is 425.25

Answer:

Step-by-step explanation:

1)As ABCD is isosceles trapezium,

∠ADC= ∠DAB

∠ADC = 115°

2) AD //BC

∠ADC + ∠DCB = 180°   {co interior angles}

115 + ∠DCB = 180

 ∠DCB = 180 - 115

 ∠DCB = 65°

3) As ABCD is isosceles trapezium,

∠CBA = ∠DCB

∠CBA = 65°

4) As ABCD is isosceles trapezium, non parallel sides are congruent.

AB = DC

3x + 4 = 25 in

3x = 25 - 4

3x = 21

x = 21/3

x = 7 in

5) height = 13.5 in

a= 43 in

b= 20 in

Area of trapezium = [tex]\frac{(a+b)*h}{2}\\[/tex]

                   [tex]= \frac{(43 +20)*13.5}{2}\\\\=\frac{63*13.5}{2}\\\\\\= 425.25 in^{2}[/tex]

Answer:

Total distance = 6,540,000 km

Step-by-step explanation:

Given

Number of bicycles = 9,000,000

Average Distance = 6.5 km (to 1 d.p)

Required

Calculate the upper bound of all bicycle distance

First, we need to determine the range of the distance traveled by each bicycle;

Since, the average distance is approximated, then the Range is:

[tex]Range = (6.45km\ to\ 6.54km)[/tex]

All number in this range approximate to 6.5km

Note that the upper bound of the range is 6.54km;

Hence, total distance is calculated as thus;

[tex]Total\ distance = Number\ of\ bicycle * upper\ bound[/tex]

[tex]Total\ distance = 1,000,000 * 6.54km[/tex]

[tex]Total distance = 6,540,000km[/tex]

Answer:

[tex]\dfrac{1}{6561}[/tex]

Step-by-step explanation:

Given the expression [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex], Using the laws of indices to simplify the expression. The following laws will be applicable;

[tex]a^m*a^n = a^{m+n}\\(a^m)^n = a^{mn}\\[/tex]

[tex]a^{-m} = 1/a^m[/tex]

Given [tex][(2^{-2})(3^{4})]^{-3} * [(2^{-3})(3^2)]^{2}[/tex]

open the parenthesis

[tex]= (2^{-2})^{-3}(3^{4})^{-3}* (2^{-3})^2(3^2)^2\\\\= 2^{-2*-3}* 3^{4*-3} * 2^{-3*2} * 3^{2*2}\\\\= 2^6 * 3^{-12} * 2^{-6} * 3^4\\\\collecting \ like \ terms\\\\= 2^6 * 2^{-6} * 3^{-12} * 3^4\\\\= 2^{6-6} * 3^{-12+4}\\\\= 2^0 * 3^{-8}\\\\= 1 * \frac{1}{3^8}\\ \\= \frac{1}{6561}[/tex]

Answer: C.The result is a composite number.

Step-by-step explanation:

A prime number has only 2 factors ( '1' and itself). For example : 2,3,5,..

A composite number has more than 2 factors. For example : 4, 6, 8...

The given expression: [tex]9x-3[/tex]

When x= 7 , the value of the expression will be

[tex]9(7)-3= 63-3=60[/tex]

Since 60 is a composite number [ it is divisible by 2,3,4,5,6,10,12,30,60]

Hence, the correct statement is C.The result is a composite number.

Answer:

C. The result is a composite number.

Sorry! I'm in a rush but I hope you do well on your quiz! Stay brainly :)

Answer:

The number of seedlings the three boys planted together is 560 seedlings

Step-by-step explanation:

The possible information in the question are;

Percentage of the seedlings planted by Ali = 40%

Percentage of the seedling planted by Ben = 45%

The percentage of the seedling planted by Cliff = The rest of the seedling

The number of seedling planted by Cliff = 84 siblings

Therefore, the percentage of the seedling planted by Cliff = 100% - 45% - 40% = 15%

Given that Cliff planted 15% of the seedlings, we have;

15% of seedlings Cliff planted = 84

Let X = the total number of seedlings

15/100 × X = 0.15×X = 84

X = 84/0.15 = 560

The total number of seedlings = The number of seedlings the three boys planted together = 560 seedlings.

You can pick one or the other to have as your answer

===========================

Explanation:

The formula you use is

A = pi*r^2

The radius is r = d/2 = 10/2 = 5

So,

A = pi*r^2 = pi*5^2 = pi*25 = 25pi

is the exact area

Replace pi with 3.14 to get 25*pi = 25*3.14 = 78.5

which is the approximate area

To get a better approximation, you would use more decimal digits of pi.

Answer: Width= 7 in.

               Length= 10 in.

Step-by-step explanation:

[tex]l=w+3[/tex]

The perimeter of the rectangle is 34 inches.

[tex]2(w+l)=34[/tex]

substitute

[tex]2(w+w+3)=34[/tex]

[tex]2(2w+3)=34[/tex]

distributive property [tex]a(b+c)=ab+ac[/tex]

[tex]2\cdot 2w+2\cdot 3=34[/tex]

[tex]4w+6=34[/tex]

[tex]4w+6-6=34-6[/tex]

[tex]4w=28[/tex]

divide 4 on both sides

[tex]w=7[/tex]

Width is 7 inches

substitute w=7 in equation [tex]l=w+3[/tex]

[tex]l=7+3[/tex]

[tex]l=10[/tex]

Length is 10 inches

Answer:

2.75+11.50S[tex]\leq[/tex]55

4

Step-by-step explanation:

The Total amount of money Alonso went to the market with is: = $55

Items to be bought includes:

Alonso knows that:

Requirement for his taste for sugar:

From this information, the objective would be to determine the number of sugar he can purchase with the money left after he has already bought the eggs.

To start with, the amount of money left after buying the eggs is:

= $55 - $2.75

= $52.25

Now, if a box of sugar he likes cost = $11.50

Then he will be able to purchase (x( bost of sugar with = $52.50

Now, to determine the number of boxes of sugar he can purchase, we have:

1 box of sugar = $11.50

x(box) of sugar = $52.25

∴

[tex]\mathbf{x (box) of sugar = \dfrac{\$52.25 \times 1 box of sugar }{\$11.50}}[/tex]

x = 4.5 box of sugar

Therefore, after buying a pack of 12 eggs for = $2.75, Alonso will be able to buy [tex]\mathbf{ 4\dfrac{1}{2}}[/tex]  or 4.5 boxes of sugar.

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Answer:

As x decreases in value.f(x) decreases in value.......

(x-p)(x-q)

y(x-q) .... let y = x-p

yx - yq ... distribute

x(y) - q(y)

x(x-p) - q(x-p) ... replace y with x-p

x^2 - px - qx + pq .... distribute

x^2 + (-p-q)x + pq

The last expression is in the form ax^2+bx+c with a = 1, b = -p-q and c = pq

The constant term is the term without any variable x attached to it (either x or x^2), so the constant term is pq

Answer:

  $562.75

Step-by-step explanation:

The future value formula is good for this.

  FV = P(1 +r/n)^(nt)

where principal P is invested at annual rate r compounded n times per year for t years.

Using your numbers, we find the account value to be ...

  FV = $500(1 +.06/2)^(2·2) = $500·1.03^4 ≈ $562.75

There will be $562.75 in the account after 2 years.

Answer:

£ 87.00

Step-by-step explanation:

52.20*2/3=52.20/3*2=17.4*2=34.8

52.20+34.80=87.00

Answer:

r = 1

Step-by-step explanation:

2πr = x

πr² = y

x = 2y

2πr = 2πr²

r = 1

?????????????????????????????????????

Answer:

Hey there!

1) To solve this, we want to know the volume of the first cylinder, which using the cylinder volume formula, we find is roughly 3079 cm^3. If the water is poured into the second cylinder, we find that the height is about 9.8 cm.

2) First, we should know that 1000 cm^3=1 liter. Volume of 1 cm tank height: 3848 cm^3, or 3.848 l. Volume for 20  cm tank height= 76.96 l. It takes about 7.7 hrs for the water level to fall 20 cm.

3) Cylinder volume formula gives us the answer to be 176 m^3 as the volume.

Hope this helps :)

Answer:

C

Step-by-step explanation:

let hypotenuse of triangle with 60°=y

[tex]\frac{8\sqrt{2}}{y} =sin ~60\\8 \sqrt{2}=y \times \frac{\sqrt{3}}{2} \\y=\frac{16 \sqrt{2}}{\sqrt{3}} =\frac{16 \sqrt{6}}{3}[/tex]

Answer:

-14

Step-by-step explanation:

Observe first that $x=0$ is not a solution to the equation since it makes the denominator of $\frac{1}{2x}$ equal to 0. For $x\neq 0$, we may multiply both sides by both denominators and move all the resulting terms to the left-hand side to get $2x^2-2rx+7=0$. Observe that there are two ways the original equation could have exactly one solution. Either $2x^2-2rx+7=0$ has two solutions and one of them is 0, or else $2x^2-2rx+7=0$ has exactly one nonzero solution. By trying $x=0$, we rule out the first possibility.

Considering the expression $\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ for the solutions of $ax^2+bx+c=0$, we find that there is exactly one solution if and only if the discriminant $b^2-4ac$ is zero. Setting $(-2r)^2-4(2)(7)$ equal to 0 gives $4r^2-4(14) = 0$. Add 4(14) and divide by 4 to find $r^2=14$. The two solutions of this equation are $\sqrt{14}$ and $-\sqrt{14}$, and their product is $\boxed{-14}$.

The value of r from the given equation is r=(2x²+7)/2x.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is [tex]\frac{1}{2x}=\frac{r-x}{7}[/tex].

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

By cross multiplication, we get

7=2x(r-x)

7=2rx-2x²

2rx=7+2x²

r=(2x²+7)/2x

Therefore, the value of r from the given equation is r=(2x²+7)/2x.

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Answer:

a=(29-2)*(12-3)

Step-by-step explanation:

a=LW

a=(L-2)*(W-3)

a=(29-2)*(12-3)

a=27*9

a=243ft²

Answer:

[tex]\Large \boxed{A = (29 - 2) \times (12 - 3)}[/tex]

Step-by-step explanation:

The length of the whole rectangle is 29 feet.

The width of the whole rectangle is 12 feet.

The length of the shaded region is 2 feet less than the length of the whole rectangle.

The width of the shaded region is 3 feet less than the width of the whole rectangle.

The area of a rectangle is length × width.

So we can create a formula to solve for the area of the shaded region:

A = (29 - 2) × (12 - 3)

Solving for the area.

A = 27 × 9

A = 243

The area of the shaded region is 243 feet².

Answer:

this glizzy

Step-by-step explanation:

blow this glizzy u madd u wrong answer

Answer:

  4

Step-by-step explanation:

Sometimes when evaluating polynomials, it is easier if you write them in Horner form:

  (y +5)y -2

For y = -6, this is ...

  (-6 +5)(-6) -2 = (-1)(-6) -2 = 6 -2 = 4

The value of your expression is 4.

Answer:

Approximately [tex]58.28\; \rm m \cdot s^{-1}[/tex].

Step-by-step explanation:

The velocity of an object is the rate at which its position changes. In other words, the velocity of an object is equal to the first derivative of its position, with respect to time.

Note that the arrow here is launched upwards. (Assume that the effect of wind on Mars is negligible.) There would be motion in the horizontal direction. The horizontal position of this arrow will stays the same. On the other hand, the vertical position of this arrow is the same as its height: [tex]y = 62\, t - 1.86\, t^2[/tex].

Apply the power rule to find the first derivative of this [tex]y[/tex] with respect to time [tex]t[/tex].

By the power rule:

Therefore:

[tex]\begin{aligned}\frac{dy}{d t} &= \frac{d}{d t}\left[62 \, t - 1.86\, t^2\right] \\ &= 62\,\left(\frac{d}{d t}\left[t\right]\right) - 1.86\, \left(\frac{d}{d t}\left[t^2\right]\right) \\ &= 62 \times 1 - 1.86\times\left(2\, t) = 62 - 3.72\, t\end{aligned}[/tex].

In other words, the (vertical) velocity of this arrow at time [tex]t[/tex] would be [tex](62 - 3.72\, t)[/tex] meters per second.

Evaluate this expression for [tex]t = 1[/tex] to find the (vertical) velocity of this arrow at that moment: [tex]62 - 3.72 \times 1 =58.28[/tex].

Answer:

58.28 m/s

Step-by-step explanation:

y = 62t - 1.86t²

Speed, S = dy/dt = 62 - 2(1.86)t

S = 62 - 3.72t

When t = 1

S = 62 - 3.72 = 58.28 m/s

Answer:

The equation would be a quadratic trinomial

Step-by-step explanation:

Step 1: Expand the equation to remove the brackets

0 = 8x² + 3x - 12x² + 1

Step 2: Collect like terms

0 = -4x² + 3x + 1

Step 3: Count number of terms

0 = -4x² + 3x + 1

1 2 3

Therefore there are 3 terms and this is a quadratic equation making the answer B, a quadratic trinomial

Answer:

C. 8^20/2^8

Step-by-step explanation:

(8^5/2²)^4

8^20/2^8