The last valid host on the subnet 172.29.72.0/23 is 172.29.73.254.
To determine the last valid host on the subnet 172.29.72.0/23, we need to understand the concept of subnetting and how it affects the range of available host addresses.
In IPv4, subnetting allows for the division of a network into smaller subnetworks, each with its own range of usable host addresses.
The subnet 172.29.72.0/23 has a subnet mask of 255.255.254.0. The subnet mask determines the size of the network and the number of host addresses it can accommodate.
In this case, the /23 notation indicates that the first 23 bits are used to represent the network address, while the remaining 9 bits are available for host addresses.
To find the last valid host on this subnet, we need to determine the maximum number of hosts it can support. With 9 bits available for host addresses, we have 2^9 (512) possible combinations.
However, two of these combinations are reserved, one for the network address (172.29.72.0) and one for the broadcast address (172.29.73.255). Therefore, the actual number of usable host addresses is 512 - 2 = 510.
To find the last valid host address, we subtract 1 from the broadcast address.
In this case, the broadcast address is 172.29.73.255, so the last valid host address would be 172.29.73.254.
This is because the last address is reserved for the broadcast address and cannot be assigned to a specific host.
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