what is the magnitude of a point charge that would create an electric field of 1.20 n/c at points 1.60 m away?

The frictional force acting on the box is just opposite to the normal force acting on the box by its weight. Here, the frictional force is,

Friction is a kind force that opposes the normal force acting on an object. The frictional force, is a resistive force having a negative sign always. The frictional force increases as the roughness of the surface through which the object is moving.

Here, the mass of the box m = 11.54 kg

angle of sliding  = 31.04 °

acceleration due to gravity of earth = 9.8 m/s²

The frictional force that opposes the motion of the box sliding down the surface is just opposite to the normal force on the box by its own weight.

F = - mg cosθ

  = - 11.54 kg ×  9.8 m/s² × 31.04°

  = -105.9 N

Therefore, the frictional force acting on the box is -105.9 N.

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We can solve this problem by using the principle of conservation of momentum, which states that the total momentum of a system of objects remains constant unless an external force acts on it. By using this the mass of the first car is 2053 kg.

A fundamental tenet of physics is the conservation of momentum, which holds that unless an outside force occurs on an isolated system of objects, its overall momentum will not change. As long as there are no outside forces acting on the system, this indicates that the total momentum of a system prior to a collision or interaction is equal to the total momentum of the system following the collision or interaction.

To calculate the mass of the first car:

The momentum of a car is given by its mass times its velocity. So, we can write:

The momentum of first car before collision + momentum of the parked car before collision = momentum of both cars after collision

Let the mass of the first car be m1, and let the velocity of the first car before the collision be v1. We can convert the given speeds from km/h to m/s, since the units need to be consistent for the calculation:

69.3 km/h = 19.25 m/s

35.7 km/h = 9.92 m/s

Using the principle of conservation of momentum, we can write:

m1 * v1 + 0 = (m1 + 1250 kg) * 9.92 m/s

Simplifying and solving for m1, we get:

m1 * v1 = (m1 + 1250 kg) * 9.92 m/s

m1 * v1 = 9.92 m/s * m1 + 9.92 m/s * 1250 kg

m1 * v1 - 9.92 m/s * m1 = 9.92 m/s * 1250 kg

m1 * (v1 - 9.92 m/s) = 9.92 m/s * 1250 kg

m1 = (9.92 m/s * 1250 kg) / (v1 - 9.92 m/s)

We don't know the value of v1, but we can find it by using the fact that the two cars slide together after the collision. The velocity of the two cars after the collision is given by:

35.7 km/h = 9.92 m/s

Using the principle of conservation of momentum again, we can write:

m1 * v1 + 0 = (m1 + 1250 kg) * 9.92 m/s

m1 * v1 = 9.92 m/s * (m1 + 1250 kg)

v1 = 9.92 m/s * (m1 + 1250 kg) / m1

Substituting this expression for v1 into the earlier equation, we get:

m1 = (9.92 m/s * 1250 kg) / (9.92 m/s * (m1 + 1250 kg) / m1 - 9.92 m/s)

Simplifying this equation and solving for m1, we get:

m1 = 2053 kg

Therefore, the mass of the first car is 2053 kg.

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The given assertion 'In a series circuit, the current is constant throughout the electric circuit' is correct but the reason 'All electric devices need equal currents to operate properly' is incorrect.

A circuit is said to be connected in series when the same current flows through all the components in the circuit. The current in these circuits only travels along one route.

A higher total voltage is produced by series-connected cells than by single cells. Voltage increases if the number of cells increases. Series circuits do not overheat easily.

All the electrical devices do not require equal amount of current for their functioning. For example, an electric heater and an electric fan do not require the same amount of current.

In a series combination, if one component fails, all other components stop working.

Series connection is not suitable for domestic circuits.

Therefore, while the assertion is true, the reason is false.

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For a direct TV satellite dish with a diameter of roughly 50cm and frequency around 18 GHz, an accuracy of about 0.2 degrees of 0.0035 radians is required for reliable reception.

To accurately point a satellite dish the dish needs to be pointed in the direction of the satellite and at the correct angle to reciterecieve the signal. The accuracy required depends on the size of the dish , the frequency of the signal and the distance to the satellite.

For a direct TV satellite dish with a diameter of roughly 50cm and frequency around 18 GHz, an accuracy of about 0.2 degrees of 0.0035 radians is required for reliable reception. This level of accuracy is necessary to ensure that the dish is aimed at the satellite and is able to recieve the signal with enough power to provide a clear and stable picture.

While it is technically possible for a homeowner to install a satellite dish with this level of accuracy, it can be challenging for those without experience. There are many factors that can affect the installation, such as the location of the dish the mounting system and the cable routing. In addition, weather conditions such as wind and rain can affect the allignment of the dish.

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By combining the additional resistors in a certain combination that is then placed in series with the original resistor, he achieves the desired resistance which is expressed as follows:

1- Resistors in series: when  [tex]R_{1}, R_{2}, R_{3}[/tex]​, ...... several resistors when are connected in series, the sum of the individual resistances gives the equivalent resistance [tex]R_{eq}[/tex]​:

​[tex]R_{eq}[/tex] = [tex]R_{1} + R_{2} + R_{3} + ........[/tex]

2- Resistors in Parallel: when [tex]R_{1}, R_{2}, R_{3}[/tex]​​, ...... several resistors when connected in parallel, the sum of the reciprocals of the individual resistances is the reciprocal of the equivalent resistance​ [tex]R_{eq}[/tex] :

[tex]\frac{1}{R_{eq} } = \frac{1}{R_{1} } +\frac{1}{R_{2} } + \frac{1}{R_{3} } +.... (2)[/tex]

There are four​ ways to connect the three additional resistors in series with the original resistor.

The first way​ is if all the resistors are in series. The equivalent resistance of the new circuit is then found in Equation (1):

[tex]R_{eq} = R+R + R + R \\ = 4R[/tex]

The second way​ is if all the additional resistors are in parallel. The three resistors in the blue rectangle are in parallel and their equivalent resistance is from Equation(2):

[tex]\frac{1}{R_{eq} } = \frac{1}{R} + \frac{1}{R} + \frac{1}{R} \\ R_{eq} = \frac{R}{3}[/tex]

The R/3 and R resistors are in series and their equivalent resistance is ind from Equation (1):

[tex]R_{eq} = \frac{R}{3} + R\\ = \frac{4}{3} R[/tex]

The third way is if two resistors from the additional resistors are in parallel and the third one is in series with the combination. The two resistors in the blue rectangle are in parallel and their equivalent resistance is found in Equation (2):

          [tex]\frac{1}{ R_{eq}} = \frac{1}{R} + \frac{1}{R} \\ R_{eq} = \frac{5}{2} R[/tex]

The two R resistors and the R/2 resistor  are in series and their equivalent resistance is found in Equation(1):

[tex]R_{eq} = \frac{R}{2} + R + R\\ = \frac{5}{2}R[/tex]

The fourth way is if two resistors from the additional resistors are in series and the third one is in parallel with the combination. The two resistors in the blue rectangle are in series and their equivalent resistance is ind from Equation(1):

[tex]R_{eq} = R + R\\ = 2R[/tex]

The 2R and R resistors are in parallel and their equivalent resistance is found in Equation (2):

[tex]\frac{1}{R_{eq} } = \frac{1}{2R} + \frac{1}{R}\\ R_{eq} = \frac{(2R)R}{2R + R}\\[/tex]

[tex]= \frac{2R^{2} }{3R} \\ =\frac{2}{3} R[/tex]

The 2R/3 and R resistors are in series and their equivalent resistance is found in Equation (1):

[tex]R_{eq} = \frac{2R}{3} + R\\ = \frac{5}{3}R[/tex]

Therefore, there is no combination possible that would make the equivalent resistance of the circuit [tex]\left \ {{7} \atop {3}} \right. R[/tex]  and the expressed situation is impossible.

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Answer:

style

Explanation:

The mass of an atom is less than the sum of the masses of its component protons, neutrons and electrons. The mass defect is 0.0423 amu. The correct option is B.

The mass defect is equal to the mass lost as an equivalent amount of energy during the formation of a given nucleus from the component nucleons.

Δm = M°- M

Δm = Mass defect

M° = Expected total mass

M = Experimentally determined mass

Here 'Li' has 3 protons and 4 neutrons.

The mass of proton = 3 × 1.0073 = 3.0219 amu

The mass of neutron = 4 × 1.0087 = 4.0348 amu

The sum of masses of protons and neutrons = 7.0567

Mass defect = 7.0567 - 7.0144 = 0.0423 amu

Thus the correct option is B.

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The Momentum is the product of mass and velocity.

Momentum is a measure of an object's motion. It is defined as the product of an object's mass and its velocity. In physics, momentum is a conserved quantity, which means that the total momentum of a closed system remains constant unless acted upon by an external force.

Final momentum of Ax = 1 * 2 * cos 30 = 1.73 Kgm/s

Final momentum of Ay =  1 * 2 * sin 30 =1 Kg m/s

Final momentum of Bx = 1 * Vs * cos 30

Final momentum of By = 1 * Vy * sin 30

The velocity is then;

1 * 5 + 0 = (1 * 2) + (1 * vs)

5 = 2 + vs

Vs = 3 m/s

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Answer:

Explanation:

Nichrome wire is generally used as a heating element in heating appliances because it has the following features: It offers a very large resistance. So a large amount of electric energy is converted into a large amount of heat energy. It has a high melting point such that it can be heated till red hot without melting.

The electric field generated when a current of 10 A flows through a resistor depends on the resistance and length of the resistor. Without knowing these factors, we cannot determine the exact electric field.

However, we can use Ohm's law to calculate the voltage drop across the resistor, which is directly proportional to the electric field. Ohm's law states that the voltage drop across a resistor is equal to the product of the current and the resistance.

Assuming a resistance of 5 ohms, the voltage drop across the resistor would be 50 volts (10 A x 5 ohms = 50 V). This means that the electric field generated would be 50 V/m, assuming a length of 1 meter. The direction of the electric field would be from the positive end of the resistor to the negative end, following the direction of current flow.

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When the ball returns to his hands 0.6 seconds later, Low speeds have very little air friction. Youngster playing catch with himself while wearing a large baseball cap.

What is an object's speed?

The speed by which an object moves a distance could be thought of just like its speed. A slow-moving object travels a relatively short distance in a given length of time, whereas a fast-moving object travels a big distance in a short amount of time.

What does speed look like mathematically?

Speed is mathematically represented as follows: Distance dimension formula: M0L1T0 Time has the following dimensions: M 0 H 0 T 1. By dividing the dimensional formulas for time and distance, we arrive to the following result:

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The conclusion about the direction of motion of the object after the application of the additional force is the object will not move in either the left or right direction, because the net force will be zero.

In physics, a force is an influence that can change the motion of an object.

The object initially encountered unbalanced forces of 10 N from the right and 17 N from the left, resulting in a net force of 7 Netwons, which caused the object to travel in the direction of the right.

The object ceased to move in either direction when a force of 7 Newtons was added from the right, as the net force decreased to zero, creating balanced forces from both directions.

Therefore, the object will continue to move with a constant velocity.

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Yes, there is a force of friction acting on the car at the point pictured. The force of friction acts in the direction opposite to the direction of motion of the car, so it would be pointing towards the center of the curve (which is towards the left in this case).

What is Constant Speed?

Constant speed refers to the situation where an object is moving with a consistent or uniform velocity in a straight line. It means that the object is moving at the same rate and in the same direction for the entire duration of its motion.

For example, if a car is traveling at a constant speed of 60 miles per hour, it will travel 60 miles in one hour, 120 miles in two hours, and so on. In contrast, an object that is not moving at a constant speed is said to have a variable speed, meaning its velocity changes over time.

The car is moving at a constant speed, which means that the net force acting on it must be zero. In order for this to be the case, the force of friction must be present to counteract the centripetal force that is required to keep the car moving in a circular path. This centripetal force is provided by the normal force of the road pushing up on the tires of the car, and the force of friction must be present to counteract it so that the net force on the car is zero. Therefore, the correct answer is (c) yes, pointing left.

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A positive test particle released from rest would move towards a region of lower electric potential (compared to the electric potential at the point where it is released).

It is because of the fact that  positive test particle is attracted to regions of higher electric potential and repelled by regions of lower electric potential. Since the particle is released from rest, it has no kinetic energy to overcome the potential energy barrier and move against the direction of the electric field. Therefore, it will move in the direction of decreasing electric potential, which is towards the region of lower electric potential.

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We cannot calculate the charge on the C2 capacitor without knowing the capacitance of the capacitor.

To determine the charge present on the C2 capacitor, we need to know the capacitance of the capacitor and the potential difference across it.

Assuming that the circuit is in steady state and neglecting any resistive losses, the potential difference across both capacitors will be equal to the applied potential difference of 6.11 V.

Let's call the capacitance of C2 as C2.

Then the charge present on the C2 capacitor can be calculated using the formula:

Q = C2 * V

where Q is the charge on the capacitor,

C2 is the capacitance of the capacitor, and

V is the potential difference across the capacitor.

Plugging in the values,

we get:

Q = C2 * V = C2 * 6.11 V

We cannot calculate the charge on the C2 capacitor without knowing the capacitance of the capacitor.

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To calibrate the volumetric pipet, you can use the following formula:

[tex]V = (m2 - m1) / ρ[/tex]

where V is the volume of the pipet, m2 is the mass of the beaker and water, m1 is the mass of the beaker, and ρ is the density of water at the given temperature. First, you need to find the density of water at 24.0°C. You can use a table of densities of water or use the following formula:

[tex]ρ = ρ0 × [1 - β × (T - T0)][/tex]

where ρ0 is the density of water at 4.0°C (which is 1.0000 g/mL), β is the coefficient of volume expansion (which is 0.00021 1/°C for water), T is the temperature of the water, and T0 is the reference temperature (which is 4.0°C).

Substituting the values, you get:

[tex]ρ = 1.0000 g/mL × [1 - 0.00021 1/°C × (24.0°C - 4.0°C)][/tex]

[tex]= 0.9978 g/mL[/tex]

Now, you can calculate the volume of the pipet:

[tex]V = (m2 - m1) / ρ[/tex]

[tex]= (85.2236 g - 60.1324 g) / 0.9978 g/mL[/tex]

[tex]= 25.15 mL[/tex]

The volume you obtained is slightly larger than the nominal volume of the pipet (which is 25.00 mL), indicating that the pipet is delivering slightly more volume than expected. To adjust the pipet, you can repeat the calibration process with a larger or smaller amount of water until you obtain a volume closer to the nominal value.

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The friction force will be ZERO. because friction force act only on relative motion. but here is no motion.

In physics, pressure is an influence that may exchange the motion of an item. A force can purpose an object with mass to alternate its velocity (e.g. moving from a nation of relaxation), i.e., to boost up.  its miles are measured inside the SI unit of newton (N). force is represented with the aid of the symbol F (formerly P).

The unique form of Newton's 2d regulation states that the net pressure appearing upon an object is identical to the fee at which its momentum modifications with time. If the mass of the item is steady, this regulation implies that the acceleration of an item is immediately proportional to the internet force appearing on the object, is within the direction of the internet force, and is inversely proportional to the mass of the object.

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The water level is not rising at t=0, then we need to add a phase shift term to formula to account for initial position of oscillation.

Depth of water in tank oscillates sinusoidally once every 6 hours and the smallest depth is 7.6 feet and largest depth is 10.4 feet,

d(t) = A sin (ωt + φ) + C

[tex]A = (10.4 - 7.6)/2 = 1.4[/tex]

[tex]C = (10.4 + 7.6)/2 = 9[/tex]

Substituting these values:

d(t) = 1.4 sin (π/3 t) + 9

d(t) = 1.4 sin (π/3 t) + 9

This formula assumes that water level is at the average of the depth and rising at t=0, as stated in the problem. If water level is not rising at t=0, then we would need to add a phase shift term to the formula to account for the initial position of the oscillation.

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Junita will do more work on the square box. when Junita lifts an object to a shelf, she does work on the object, which increases its gravitational potential energy (GPE).

The amount of work done on an object is equal to the increase in its GPE.

Junita lifted a round box and a square box to a shelf. She did work on the boxes, increasing their GPE. The round box's GPE increased by 50 J, meaning Junita exerted 50 J of work.

The square box's GPE increased by 100 J, meaning Junita did 100 J of work on it.

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To prevent the kid from slipping, static friction needs to be at least 1 coefficient.

A force called static friction prevents an object from moving along the path. This friction happens when two materials are slid over one another. Conflict is there all around us. For instance, when we walk, our feet are in contact with the ground.

Newton's second rule of motion can be used to calculate the amount of force needed to prevent the kid from slipping:

ΣF = ma

where ΣF is the sum of the forces acting on the child, m is the mass of the child, and a is the acceleration of the child. Since the child is not slipping, the force of static friction f must equal the force of gravity on the child Fg:

f = Fg

where Fg = mg, and g is the acceleration due to gravity.

The acceleration of the child can be expressed in terms of the angular acceleration of the merry-go-round, α, using the formula:

a = rα

where r is the distance of the child from the center of the merry-go-round.

The angular acceleration can be found from the time it takes for the merry-go-round to make one complete revolution, T, using the formula:

α = 2π / T

Substituting these values into the equations above, we get:

f = Fg

μs N = mg

μs mg = mg

μs = 1

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Answer:

both questions are B

Explanation:

I observed the photo and I saw two Bs circled in the photo. Hope this helps!

The automobile may slide or skid sideways off the road if the road is covered with ice and the vehicle is being driven at a slower rate of speed than the indicated bank angle.

A vehicle is kept driving in a circular path without sliding by the centripetal force created by the bank angle of a road bend.

This force is produced by the tire-perpendicular normal force of the road, which acts on the tire.

The bank angle is intended to boost the normal force to counteract the centrifugal force that seeks to pull the automobile away from the curve as speed rises.

On an ice road, however, there is a considerable reduction in the coefficient of friction between the tires and the surface, which also affects the normal force.

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Boyajian was looking at a starlight graph in the summer of 2013 and She noticed two dimming episodes from KIC 8462852 were two important data points in the light curve of star KIC 8462852.

The irregular drop and rise in brightness that does not follow a regular or expected pattern. This shift is caused by dust, which might be the result of a collision between two comets or the bursting of one. Another plausible, although less likely, reason is that the star is through unprecedented internal turmoil.

Boyajian was looking at a starlight graph in the summer of 2013 as part of a big data set acquired by the space-based Kepler telescope during its four-year mission to search for Earth-like planets near other stars. Dips in the quantity of light emitted by a star might signal the passage of a planet in front of it. The greater the size of the planet, the greater the light drop.

Boyajian's graph implied the existence of a planet larger than any scientist has ever seen — or something more crazier.She noticed two dimming episodes from KIC 8462852 during the 800th and 1,500th days of observation, when the star's luminosity reduced by 15% and 22%, respectively. A planet nearly 11 times the size of Jupiter of Earth, would result in a 1% drop — implying that whatever is circling KIC 8462852 is significantly larger than our solar system's greatest planet.

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The surface area each tire have in contact with the ground is 0.11 m².

The weight of the car is evenly distributed on each wheel, so each wheel supports a force of 1000 kg / 4 = 250 kg.

The force on the tire is transmitted to the ground through the tire's contact patch, which is the surface area of the tire in contact with the ground.

The tire's contact patch can be calculated by dividing the total force on the tire by the pressure of the tire:

Contact patch area = Force on tire / Pressure

= 250 kg  x 9.8 N/kg / (2.2 bar  x 10⁵ Pa/bar)

= 0.11 m²

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Two like masses are attracted to one another by gravitational forces.

Is the force of gravitation between two masses always alluring?

Any two bodies in our world will gravitationally attract one another, according to Newton's law of gravitation. Therefore, the gravitational attraction between two masses is constant.

The gravitational force created by one mass would be better represented by the electromagnetic field of a negative charge. This is thus because both the field representation of a negative charge and the gravitational force between two masses are attractive forces. When placed in an electric field, a positive charge will often move in the direction of the electric field lines, while a negative charge would typically move in the opposite way.

When a positive charge and a negative charge interact, their forces move from the positive to the negative charge in the same manner. The electric field and consequent forces produced by two electrical charges of opposing polarity cause opposite charges to attract one another. Compared to gravitational forces, electrostatic forces are substantially stronger. This is due to the fact that gravity is dependent on mass, and since atoms have such little masses, there is almost no gravitational pull between them. The electrostatic force, however, is greater when there are charges present.

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We can determine the time period of oscillation of a known mass using a light spring and a meter scale without the use of a clock.

To find the time period of oscillation of a known mass using a light spring and a meter scale without the use of a clock, we can follow these steps:

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2.34 C corresponds to[tex]2.34 x 10^6[/tex] Coulombs, which is equal to [tex]2.34 x 10^6 x 6.24 x 10^18[/tex]electrons, or 1.44e25 electrons.

Electron is a subatomic particle that is part of the atom. It carries a negative charge and is considered to be the primary carrier of electricity in nature. Electrons are found in the nucleus of an atom, and they are held together by a strong nuclear force. Electrons are also found in the outer shells of atoms, and they can move freely between different shells. Electron is considered a fundamental particle, which means it is not composed of any other particles. Electrons also have a mass of about 1/1836 of the mass of a proton. Electrons are extremely important in everyday life, as they are responsible for the electrical forces that power our devices and make them function. Electrons can also be used in various applications such as semiconductors, which are used in computers, cell phones, and other electronic devices.

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As you circle the speakers, you will come across two areas of beneficial interference.

The scenario described in the question involves two speakers that are releasing sound waves that are 0.5 m apart in wavelength. Constructive interference happens when two waves collide and their combined amplitudes create a wave with a larger amplitude. In this scenario, when the individual moves in a circle with a radius of 2 metres around the speakers, they will come across two locations where the waves from the two speakers will collide in phase and cause constructive interference. On the perpendicular bisector of the line connecting the two speakers, these spots are situated. All other locations on the circle will experience destructive wave interference, producing waves with smaller amplitudes.

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Answer:

kinetic and I think sound energy

Answer:

kinetic energy

Explanation:

An apple falling to the ground has both potential energy and kinetic energy. As the apple falls, its potential energy is converted into kinetic energy, which is the energy an object has due to its motion. The apple gains kinetic energy as it falls and its velocity increases, and at the moment it reaches the ground, all of its potential energy has been converted into kinetic energy.


ALLEN