What is the magnitude of the gravitational force acting on the car?
A) 14700N
B)13690N
C)5800N
D)775N

Answer:

[tex]Density = 33835kg/m^3[/tex]

Explanation:

Given

[tex]Mass = 67.67g[/tex]

[tex]Volume = 2mL[/tex]

Required

Determine the density

[tex]Density = \frac{Mass}{Volume}[/tex]

First, we need to convert mass to kg

[tex]Mass = 67.67g[/tex]

[tex]Mass = \frac{67.67kg}{1000}[/tex]

[tex]Mass = 0.06767kg[/tex]

Next, we need to convert volume to m^3

[tex]Volume = 2mL[/tex]

[tex]Volume = 2 * 10^{-6}m^3[/tex]

Density is then calculated as follows:

[tex]Density = \frac{0.06767}{2 * 10^{-6}}[/tex]

[tex]Density = \frac{0.06767 * 10^6}{2}[/tex]

[tex]Density = \frac{67670}{2}[/tex]

[tex]Density = 33835kg/m^3[/tex]

Answer:

I believe it d I'm not completely sure but yeah

In the F-K domain, ground roll cannot be separated from reflectors as it refers to the low-frequency noise or energy that is associated with seismic waves propagating through the near-surface layers of the Earth.

It typically appears as a coherent and continuous signal in the seismic data. In the F-K domain, which represents the data in terms of frequency and wavenumber, the ground roll and the reflectors share similar characteristics in terms of their frequency content and wavenumber distribution. As a result, it becomes challenging to separate the ground roll from the reflectors based solely on their F-K domain representation.

The F-K domain provides information about the frequency and spatial characteristics of the seismic data. However, it does not provide direct information about the physical properties or origins of the seismic energy. Both ground roll and reflectors can have similar frequency-wavenumber signatures, making it difficult to distinguish between them in this domain. Additional processing techniques and analysis, such as filtering or velocity analysis, are often required to separate the ground roll from the desired reflectors and enhance the interpretability of the seismic data.

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A radioactive element, also known as a radionuclide or radioisotope, is an element that exhibits radioactivity.

Radioactive elements are the elements that have an unstable nucleus and emit radiation when their nucleus undergoes a process called radioactive decay. Radioactive decay is a random process that occurs in some of the elements with unstable atomic nuclei.

During this process, the nucleus emits alpha, beta, or gamma particles, which transform the nucleus into a more stable state. As a result, these elements are radioactive and can release high-energy particles or electromagnetic waves in the form of radiation, which can be dangerous for living organisms. Radioactive elements are mainly classified into two types: natural radioactive elements and artificially produced radioactive elements.

Natural radioactive elements are those that occur in nature, and their nuclei naturally undergo radioactive decay. For example, Uranium, thorium, and radium are natural radioactive elements. The artificially produced radioactive elements are those that are synthesized through nuclear reactions in a laboratory. For example, technetium and plutonium are artificially produced radioactive elements.

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Answer:  and a theme

Explanation:

Answer:

Newton's second law describes the affect of net force and mass upon the acceleration of an object.

F = force

m = mass of an object

a = acceleration

Explanation:

f=m.a

The magnitude of the force required to slide the lawnmower over the ground at constant speed by pushing the handle is given by Fh = mg * μ * sin(θ).

To determine the force required, we consider the forces acting on the lawnmower. The force of gravity pulling the lawnmower downward can be represented by mg, where m is the mass of the lawnmower and g is the acceleration due to gravity. The normal force exerted by the ground balances out the force of gravity in the vertical direction.

In the horizontal direction, the force required to overcome the frictional force is given by F_friction = μ * N, where μ is the coefficient of friction and N is the normal force. The normal force can be calculated as N = mg * cos(θ).

Since the lawnmower is pushed at constant speed, the applied force Fh must exactly balance the frictional force. Therefore, Fh = F_friction = μ * N = μ * mg * cos(θ).

Simplifying the equation, we have Fh = mg * μ * cos(θ). However, we are given that Fh is parallel to the handle, which means it is in the horizontal direction. Thus, we need to consider the horizontal component of the force, which is Fh = mg * μ * sin(θ).

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The force required to slide the lawnmower over the ground at constant speed can be calculated using the formula Fh = μ * m * g, where Fh is the force exerted by the handle, μ is the coefficient of friction, m is the mass of the lawnmower, and g is the acceleration due to gravity.

In this problem, we need to consider two directions; the horizontal (x-direction) and the vertical (y-direction). In the horizontal direction, we know that the force exerted by the handle must overcome the frictional force on the lawnmower. Since the lawnmower moves at a constant speed, the net force in the horizontal direction is zero (0).

Thus, Fh * cosθ (component of the handle's force in the x-direction) = μ * m * g * cosθ (friction).

Through this we establish that Fh = μ * m * g.

Where:
Fh is the force exerted by the handle.
μ is the coefficient of friction.
m is the mass of the lawnmower.
g is the acceleration due to gravity.

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Answer:

(a) The total weight of the climber is equal to her mass multiplied by the acceleration due to gravity. Therefore, W = mg = 62 kg x 10 m/s^2 = 620 N.

(b) The two conditions needed for equilibrium are that the net force acting on the climber is zero and the net torque acting on the climber is zero.

(c)(i) The moment about her feet due to her weight is equal to the weight of the climber multiplied by the distance between her feet and the cliff. Therefore, M = W x d = 620 N x 0.9 m = 558 Nm.

(ii) To determine the tension in the rope, we need to resolve the forces acting on the climber in the horizontal and vertical directions. In the horizontal direction, the tension in the rope is balanced by the force of friction between the climber's feet and the cliff. Therefore, T = F.

In the vertical direction, the climber's weight is balanced by the normal force of the cliff and the tension in the rope. Therefore, N + Tcos(60) = W.

Since the climber is in equilibrium, the net torque acting on her must be zero. Therefore, the torque due to the tension in the rope must be equal and opposite to the torque due to the climber's weight. Therefore, Tsin(60) x 1.2 = M.

Substituting the values we have, we get:

N + Tcos(60) = W

Tsin(60) x 1.2 = M

Solving for T, we get:

N = W - Tcos(60) = 620 N - T(0.5)

Substituting this into the second equation, we get:

Tsin(60) x 1.2 = M

Tsin(60) = M / 1.2 = 558 Nm / 1.2 m = 465 N

Substituting this value of T into the first equation, we get:

N = 620 N - T(0.5) = 620 N - 465 N(0.5) = 388 N

Therefore, the tension in the rope is 465 N and the normal force of the cliff on the climber is 388N

The magnitude of the final velocity of the bowling ball is 4.31 m/s.ExplanationAccording to the Law of Conservation of Momentum, the initial momentum of the system is equal to the final momentum of the system before and after the collision.

This can be mathematically represented as:Initial momentum of the system = Final momentum of the systemInitially, the bowling ball is moving with a velocity of 9.00 m/s and has a mass of 5.50 kg. The bowling pin has a mass of 0.850 kg, and its velocity after the collision is 15.0 m/s.

Let v be the velocity of the bowling ball after the collision, then applying the law of conservation of momentum;5.5 kg × 9.0 m/s + 0.85 kg × 0 = (5.5 kg + 0.85 kg) × vfinal = 4.31 m/sTherefore, the magnitude of the final velocity of the bowling ball is 4.31 m/s.

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Answer:

B cause u need to find the total range

Explanation:

A. The average drift speed of the electrons in the wire is  1.19 x [tex]10^{-3}[/tex]cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x [tex]10^{5}[/tex]sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per [tex]cm^{3}[/tex]
A is the cross-sectional area of the wire in [tex]cm^{2}[/tex]
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x [tex]10^{-19}[/tex] Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π[tex]r^{2}[/tex]

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = [tex]π(0.0815 cm)^{2}[/tex] = 0.0209 [tex]cm^{2}[/tex]

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x [tex]10^{24}[/tex]electrons per [tex]cm^{3}[/tex], we can substitute these values into the equation:

v = 20 A / (8.47 x [tex]10^{24}[/tex] electrons per cm^3 * 0.0209 cm^2 * 1.6 x [tex]10^{-19}[/tex] C)

Simplifying the expression:

v = 1.19 x [tex]10^{-3}[/tex] cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x [tex]10^{-3}[/tex] cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x [tex]10^{-3}[/tex] cm/s * 0.01 m/cm = 1.19 x [tex]10^{-5}[/tex] m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x [tex]10^{-5}[/tex]m/s

Simplifying the expression:

t = 7.43 x [tex]10^{5}[/tex]s

Therefore, it would take approximately 7.43 x [tex]10^{5}[/tex] seconds for an electron to travel a distance of 8.84 m.

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It will takes approximately 0.165 seconds for the ball to reach the floor after it has been gently pushed off the table top from a height of 1.3 m above the floor.

When an object is dropped from a height, it falls to the ground due to the force of gravity.

When an object is released from a height of 1.3 m above the ground, the time it takes to reach the ground is calculated using the formula:

h = 0.5gt²  where h is the height of the object, g is the acceleration due to gravity and t is the time taken for the object to reach the ground.

Rearranging this formula to solve for t, we have: [tex]t = \sqrt{(2h/g)}[/tex]

Substituting the values we have: [tex]h = 1.3 mg = 9.81 m/s^{2} t = \sqrt{(2 \times 1.3 / 9.81)t} = \sqrt{(0.265 / 9.81)t} = \sqrt{0.027t } = 0.165 seconds[/tex]

Therefore, it takes approximately 0.165 seconds for the ball to reach the floor after it has been gently pushed off the table top from a height of 1.3 m above the floor.

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Answer:

The molecular magnets are arranged in an open chain so that the north pole or the south pole of the molecular magnets lie in the same direction which gives strong force at the poles whereas two opposite poles are arranged at the middle and the force cancel each other. So, poles have more force than the middle portion.

The magnet has stronger force of attraction at the poles than in middle, because, the at the poles they are attracted to the opposite poles. Whereas at the middle, the magnetic dipoles are cancelled each other and have no more force of attraction.

A magnet is a material made of metals which are of ferromagnetic nature. Thus, produce permanent magnetic dipoles. The magnetic field lines produced from a permanent magnet is strong at can fluctuate with the presence of an electric field.

A bar magnet have two poles namely a south pole and north pole. Like two the electric charges, where two like charges repel each other and unlike charges attracts, two like poles of a magnet repels and unlike poles attracts each other.

Therefore, at the two poles the magnetic field lines towards the opposite poles will be more stronger whereas at the middles the field lines merges and are oriented randomly and have no strong magnetic effect.

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A photographer focuses his camera on his subject. The subject then moves closer to the camera. To refocus, the lens should be moved further from the detector.

When the subject is moved closer to the camera, the camera's lens should be moved away from the detector. As the subject moves closer to the camera, the distance between the lens and the detector decreases, causing the camera to lose focus.

Therefore, in order to refocus the camera and capture a clear image of the subject, the lens must be moved further away from the detector, increasing the distance between the lens and the detector and reestablishing the proper focal length.

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During a contact push/pull interaction between two objects, the quantity that is transferred from one object to the other is force.

When an object exerts a force on another object, that force is transmitted through the contact point, causing the second object to experience an equal and opposite force. This transfer of force allows for the interaction and results in the acceleration or movement of the objects.

By examining a speed-time graph, we can infer something about the force acting on the object. If the graph shows a steep upward slope, it indicates that the object is experiencing a large acceleration and therefore a significant force is being applied to it. On the other hand, a flat line on the graph suggests that the object is moving at a constant speed, indicating a balance between the forces acting on it.

Similarly, by looking at a force-time graph, we can infer something about how the speed of the object is changing. If the graph shows a sudden increase or decrease in force, it indicates a change in the object's acceleration. This change in acceleration will, in turn, affect the object's speed. For example, a sudden increase in force would imply an increase in acceleration and therefore an increase in speed, while a decrease in force would suggest a decrease in acceleration and a decrease in speed.

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The temperature required to double the volume of an ideal gas originally at STP if the pressure decreased by 25% would be 546K. STP stands for Standard Temperature and Pressure. It is a standard set of conditions for measuring and comparing gases.

The standard temperature is 0°C or 273K, and the standard pressure is 1 atm or 101.325 kPa. STP is frequently utilized in scientific research and industry to guarantee that data can be compared. Charles' law is a gas law that states that the volume of a given mass of an ideal gas at constant pressure is directly proportional to its temperature in Kelvin. It is stated mathematically as V / T = constant. Where V is the volume of the gas, and T is its temperature in Kelvin. Charles' law may be used to calculate the volume of a gas when the temperature changes if the initial and final temperatures are known.

Charles' law may be written as V₁ / T₁ = V₂ / T₂, where V₁ and T₁ are the initial volume and temperature, and V₂ and T₂ are the final volume and temperature. PV = nRT is the formula for the ideal gas law. Where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of the gas, T is the temperature of the gas in Kelvin, and R is the universal gas constant.

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The mass is displaced 10.0 cm and released. We will use the formula for the total energy of the mass.Total energy of a mass-energy system is the sum of potential energy and kinetic energy. Mathematically, it is given as:Etotal = Ep + Ekwhere,

Etotal = Total energy of the systemEp = Potential energy of the systemEk = Kinetic energy of the systemGiven,Mass of the system = 500 g = 0.5 kgSpring constant of the spring, k = 1.85 N/mDisplacement, x = 10.0 cm = 0.1 mWe can find the potential energy of the mass using the formula for potential energy stored in a spring as,Ep = (1/2)kx²Putting the values,Ep = (1/2) × 1.85 N/m × (0.1 m)²Ep = 0.00925 JThe mass is displaced and released, so the potential energy of the mass converts into kinetic energy at the maximum displacement.

Therefore, we can find the kinetic energy of the mass using the formula,Ek = (1/2)mv²where, v is the velocity of the mass at maximum displacement. We can find the velocity using the conservation of energy principle that is total energy of the system is equal to kinetic energy at the maximum displacement.Etotal = EkUsing the values,0.00925 J + Ek = EkEk = 0.00925 JThe kinetic energy is also given asEk = (1/2)mv²Putting the values,0.00925 J = (1/2) × 0.5 kg × v²v² = 0.0185 m²/s²v = 0.136 m/sNow, we can calculate the kinetic energyEk = (1/2)mv²Putting the values,Ek = (1/2) × 0.5 kg × (0.136 m/s)²Ek = 0.00587 JTherefore, the total energy of the mass attached to the spring is,Etotal = Ep + Ek= 0.00925 J + 0.00587 J= 0.01512 JHence, the total energy of the mass is 0.01512 J.

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The position an object moving along x-axis is given by x=a+bt², where a=38m and b=29m/s². The velocity at t = 10 s is 580 m/s, at t = 50 s is 2900 m/s, and between 20 s and 28 s is 1392 m/s.

To find the velocity of the object at different time intervals, we need to take the derivative of the position equation with respect to time.

Given the position equation x = a + bt², where a = 38 m and b = 29 m/s², let's calculate the velocity at different time points.

Taking the derivative of the position equation, we get:

v = dx/dt = 2bt.

Substituting the given values of a and b, we have:

v = 2(29 m/s²)t.

Now we can calculate the velocity at specific time points:

a) At t = 10 s:

v = 2(29 m/s²)(10 s) = 580 m/s.

b) At t = 50 s:

v = 2(29 m/s²)(50 s) = 2900 m/s.

c) Between t = 20 s and t = 28 s:

To find the velocity between these time intervals, we need to find the difference in position and divide it by the difference in time.

Position at t = 20 s:

x1 = a + b(20 s)² = 38 m + (29 m/s²)(400 s²) = 38 m + 11600 m = 11638 m.

Position at t = 28 s:

x2 = a + b(28 s)² = 38 m + (29 m/s²)(784 s²) = 38 m + 22736 m = 22774 m.

Velocity between 20 s and 28 s:

v = (x2 - x1) / (t2 - t1) = (22774 m - 11638 m) / (28 s - 20 s) = 11136 m / 8 s = 1392 m/s.

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The electric field created by a point charge is given by the equation E = k * (Q / [tex]r^{2}[/tex]).The charge of object A is -1.11 × [tex]10^{-9}[/tex] C (option b).

In this case, the electric field at point P is 40.0 N/C directed to the south. Since the field is directed towards the south, the charge of object A must be negative. Plugging the given values into the equation, we have:

40.0 N/C = (9 × [tex]10^{9}[/tex] N [tex]m^2/C^2[/tex]) * (Q / (0.250 [tex]m)^2)[/tex]

Simplifying the equation, we can solve for Q:

Q = (40.0 N/C) * (0.250 [tex]m)^2[/tex] / (9 × 10^9 N [tex]m^2/C^2)[/tex]

Calculating the expression, we find Q ≈ -1.11 × [tex]10^{-9}[/tex] C. Therefore, the charge of object A is approximately -1.11 × [tex]10^{-9}[/tex] C, which corresponds to option b.

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The frequency and energy increases while the wawelength decreases on  moving from left to right.

Since the energy of the wave is directly proportion to the frequency and indirectly proportionl to the wavelength.

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Answer:

In a series circuit, the equivalent resistance is the algebraic sum of the resistances. The current through the circuit can be found from Ohm's law and is equal to the voltage divided by the equivalent resistance. The potential drop across each resistor can be found using Ohm's law.

Answer:

Ok, so the car has traversed a total of 2 + 4 + 2 + 6 = 14 miles.

That's the car's distance! :)

For the displacement, you can draw out a diagram. I'll try my best to make one using a keyboard xDDD

 -    -   -   -    |

 |                  |

 |    -   -    -  start  -   end!

So, this is the journey of the car: Going two up, 4 left, 2 down, and 6 right.

This ends up 2 to the right of the beginning!

That's a 2 mile displacement :)

Can you give me brainliest for my splendid diagram? xD

The most probable speed for nitrogen molecules at 295K can be found using the Maxwell-Boltzmann distribution of speeds equation. The equation is as follows:f(v) = 4π(\frac{m}{2πkT})^{\frac{3}{2}}v^2e^{\frac{-mv^2}{2kT}}$$where,m = \text{mass of one molecule of nitrogen}T = \text{temperature in Kelvi k = \text{Boltzmann constant}

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The most probable speed for nitrogen molecules at 295 K can be calculated using the formula: VMP  = √(2kT/m) T is the temperature in Kelvin,  and m is the mass of the molecule in kilograms.

For nitrogen (N2),

m = 28 g/mol or 0.028 kg/mol. Now, let's plug in the values:

vmp = [tex]√(2(1.38 × 10^-23 J/K)(295 K)/(0.028 kg/mol)[/tex]

)vmp = [tex]√(8.038 × 10^-21 J/kg)[/tex]

vmp =[tex]8.96 × 10^2 m/s[/tex]

Therefore, the most probable speed for nitrogen molecules at 295 K is approximately 896 m/s.  the most probable speed for nitrogen molecules at 295 K" is 896 m/s.

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a) The length of time required for the total pressure to rise from 0.110 atm to 0.145 atm is approximately 35.2 seconds.

b) The length of time required for the total pressure to rise from 0.110 atm to 0.220 atm is approximately 92.9 seconds.

c) Pf ≈ 0.054 atm

The total pressure after 110 seconds of reaction is approximately 0.054 atm.

To solve this problem, we can use the integrated rate law for a first-order reaction:

ln(Pf/Pi) = -kt

Where:

Pf is the final pressure

Pi is the initial pressure

k is the rate constant

t is the time

Let's solve each part of the problem:

Part A:

Using the given information:

Pi = 0.110 atm

Pf = 0.145 atm

k = 7.48 × 10^-3 s^-1

ln(Pf/Pi) = -kt

ln(0.145/0.110) = -(7.48 × 10^-3 s^-1) * t

0.263 = -7.48 × 10^-3 t

t ≈ 35.2 s

Part B:

Using the given information:

Pi = 0.110 atm

Pf = 0.220 atm

k = 7.48 × 10^-3 s^-1

ln(Pf/Pi) = -kt

ln(0.220/0.110) = -(7.48 × 10^-3 s^-1) * t

0.693 = -7.48 × 10^-3 t

t ≈ 92.9 s

Part C:

Using the given information:

t = 110 s

k = 7.48 × 10^-3 s^-1

We can rearrange the integrated rate law to solve for the final pressure (Pf):

ln(Pf/Pi) = -kt

Pf/Pi = e^(-kt)

Pf = Pi * e^(-kt)

Pf = (0.110 atm) * e^(-(7.48 × 10^-3 s^-1) * (110 s))

Pf ≈ 0.054 atm

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The charge of this cylinder is calculated as 10.2 nC. The formula for the charge of a cylinder with uniform surface charge density is ; Q = (charge density) * (surface area) * (length).

Charge density = σ,

Surface area = 2πrh + 2πr²,

Length = l

Given : Radius, r = 2.33 cm, Length, l = 6.30 cm,

Charge density, σ = 13.8 n c/m²,

Surface area of cylinder = 2πrh + 2πr²  where; h = l (length)

Substitute the value of radius and height in the above formula, we get;

Surface area of cylinder = 2πr(l + r)

Surface area of cylinder = 2π(2.33 cm)(6.30 cm + 2.33 cm)

= 119.38 cm²

Charge density, σ = 13.8 nc/m²

= 1.38 × 10⁻⁵ C/cm²

Now, put the value of σ, surface area, and length in the formula to calculate the charge of cylinder as;

Q = σ * surface area * length

Q = (1.38 × 10⁻⁵ C/cm²) * (119.38 cm²) * (6.30 cm)

Q = 1.02 × 10⁻² C = 10.2 nC

Therefore, the charge of this cylinder is 10.2 nC (nanocoulombs).

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The proof of third equation of motion is determined as  v² = 2as + u².

The proof of third equation of motion is determined as follows;

The first equation is given as;

v = u + at

t = ( v - u ) /a

where;

The formula for the average distance traveled by an object is;

s = (v + u)/2  x  t

Expand the equation above as;

s = (v + u)/2 x  (v - u)/a

s = (v² - u²) / 2a

2as = v² - u²

v² = 2as + u², proved

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Answer:

A, Cirrhosis

Explanation:

Explanation:

Weight=force=300N

height=2m

time=6seconds

power=?

now,

power (p)=f×h÷t

power=300×2÷6

power=100w

therefore,A man develops 100 watt power in 6 seconds.

Answer: a. 70 ft

b. 125 ft

c. 87.2 ft/sec

Explanation:

Here is the complete question:

If the navy pier ferris wheel in chicago has a circumference that is 56% of the circunference of the first ferris wheel built in 1893.

a. What is the radius of the navy pier wheel?

b. what was the radius of the first ferris wheel?

c. The first ferri wheel took nine minutes to make a complete revolution. how fast was the wheel moving?

C=439.6 ft.

a. What is the radius of the navy pier wheel?

Since circumference = 2πr

where π = 3.142

r = radius

Therefore, 2πr = 439.6

(2×3.142×r) = 439.6

6.284r = 439.6

Radius = 439.6/6.284

Radius = 69.9 = 70 feet

b. What was the radius of the first ferris wheel?

Since the Navy Pier Ferris Wheel in Chicago has a circumference that is ​56% of the circumference of the first Ferris wheel. This can be mathematically written as:

56% of f = 439.6

0.56f = 439.6

f = 439.6/0.56

f = 785

The circumference of the first wheel is 785ft

Radius will now be:

2πr = 785

r = 785/2π

r = 785/(2×3.142)

r = 785/6.284

r = 124.9 = 125ft

c. The first ferri wheel took nine minutes to make a complete revolution. how fast was the wheel moving?

= 785/9

= 87.2 ft/sec