Q 1 equals 4 Q 3 because Q 2 equals Q 3. The sum of the forces acting on q2 determines its magnitude. F = k q a q b r 2 is the formula we use to compute each individual force.
The right answer is D) Q 2 and Q 3 have the same magnitude but the opposite sign.∴
Due to their mutual attraction, Q 2 and Q 3 feel an attractive force. Now, Q 1 must have a sign from Q 3 to repel it so that the net force on Q 3 is zero r 2.
−kQ \s2 \s \s Q \s3
\s = \s(2r) \s2
k(Q \s1 \s \s )Q \s3
⇒Q \s1 \s \s =−4Q \s2
Q 1 equals 4 Q 3 because Q 2 equals Q 3.
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Going downhill a driver applies brakes to keep a constant speed. The potential energy of the car is decreasing while the kinetic energy is constant. Explain where the energy is going?
The potential energy of a car moving with constant speed during downhill converts into heat energy or sound energy during braking.
What is law of conservation of energy?Energy cannot be created or destroyed, according to the law of conservation of energy. However, it is capable of change from one form to another.
When a car goes downhill, its potential energy decreases but as the driver applied braking, the gain in potential energy lost during work against the frictional force applied by the brake and converts into heat energy or sound energy during braking.
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when the motorcyclist is at a , he increases his speed along the vertical circular path at the rate of v˙=(0.04s)ft/s2 where s is in ft . take rho = 300 ft . determine the magnitude of his velocity when he reaches B. Also, what is his initial acceleration?
The magnitude of his velocity when he reaches at B is 15 ft/s, and his initial acceleration of the motorbike is 0.00013333 ft/s^2.
Given that :-
The radius of the circular path is r = 300 ft,
and the rate of increase of speed is v˙ = 0.04s ft/s^2.
The initial acceleration a_0 of the motorcyclist can be determined by using the formula:-
=> a = v˙ / r,
Hence,
=> a_0
= v˙ / r
= 0.04 s ft/s^2 / 300 ft
= 0.00013333 ft/s^2
At point B, the magnitude of velocity v can be determined by using the formula:-
v = sqrt(v_0^2 + 2 x a_0 x r),
here v_0 is initial velocity.
Since the initial velocity is not given,
let's assume,
v_0 = 0.
Hence,
=> v = sqrt(v_0^2 + 2 x a_0 x r)
= sqrt(0^2 + 2 x 0.00013333 x 300)
= 15 ft/s
Therefore, the magnitude of the velocity at point B is 15 ft/s, and the initial acceleration of the motorcyclist is 0.00013333 ft/s^2.
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Determine the magnitude of the Coulomb force on the tape using the value of tan θ and your equation from the previous exercise for FCoulomb.FCoulomb = .40 x 10^-3 N
The magnitude of the Scotch tape is 13 0.05 cm, and the linear mass density (d) is 1.44 0.01 g/m.
Given that the length of the Scotch tape is 13 0.05 cm and the linear mass density (d) is 1.44 0.01 g/m, the answers to the following questions calculate the coulomb force, the number of atoms, and the elementary charges.
where r is the distance between the charges, Q1 and Q2 are the magnitudes of the charges on the two pieces of tape, and k is Coulomb's constant. Given that F Coulomb is equal to 0.40 x 10-3 N, we can use the following equation to find the charge, Q: where is the static friction coefficient, which was determined in the preceding exercise.
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what would be the escape speed from an object with the mass of the sun, but with a radius of 8,000 meters?
The sun's escape velocity is roughly 618 km/s.
What is the Sun's escape velocity? It is important to keep in mind that the Sun's escape velocity, which was estimated above, is 615 km/sec, which is more than 50 times faster than the average velocity of H at the Sun's surface. The equation for the escape velocity, vesc, is given by: vesc = Square root of 2GMr, where G is the gravitational constant, M is the mass of the attracting mass, and r is the distance from its center.Deflection Speed.Energy conservation is used to determine the escape velocity:I + k = u + kf.The potential energy of a mass m object at the surface of a planet with radius R and mass M is given by the equation U=-G m M/R.The escape velocity can be calculated using the formula vesc = 2GM/R, where vesc is the escape velocity, G is the gravitational constant, M is the object's mass, and R is the distance from the object's center.To learn more about Sun's escape velocity refer
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a light bulb requires a current of 0.70 a to emit a normal amount of light. if the light is left on for 1.0 h, what is the number of electrons that pass through the bulb?
The number of electrons that pass through the bulb is 0.4375 x 10^19C when a light bulb requires a current of 0.70 a to emit a normal amount of light.
Given the current required for a light bulb (I) = 0.7A
Time for which light is left on (t) = 1h = 3600s
Let the number of electrons that pass through the bulb = n
We know that I = Q/t where Q is the charge flowing through the bulb.
Current is expressed as charge per unit time.
So, Q = I x t = 0.7 x 3600s = 2520C
We know that the charge on an electron (qe) = 1.6X10^-19C
Then, n = I/ 1electron charge = 0.70 / 1.6X10^-19
n = 0.4375 x 10^19C
Hence, the number of electrons that pass through the bulb is 0.4375 x 10^19C.
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if an astronaut throws a ball in space with the initial velocity of 3.0 meters per second to the west, what will the ball's velocity be in a year?
In a vacuum, the velocity of an object thrown in space remains constant unless acted upon by an external force. Thus, the ball's velocity will still be 3.0 meters per second to the west after a year.
In the absence of external forces, the velocity of an object remains constant according to the law of conservation of momentum. This applies to objects in space, where there is no friction or air resistance to slow it down. Therefore, if an astronaut throws a ball with an initial velocity of 3.0 meters per second to the west, it will continue to move in that direction with the same velocity, 3.0 meters per second, one year later. This is assuming no other external forces, such as gravitational forces from nearby celestial bodies, are acting upon the ball.
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They continue the discussion, and Imad makes several comments. Which of Imad's comments is false?A. "Electric field lines never cross each other."B. "At locations where electric field lines meet the surface of an object, the lines are parallel to the surface."C. "Electric field lines always extend from a positively charged object to a negatively charged object, from a positively charged object to Infinity, or from Infinity to a negatively charged object."D. "Electric field lines are most dense around objects with the greatest amount of charge."
The false statement among Imad's comments is D. "Electric field lines are most dense around objects with the greatest amount of charge." Therefore, option D is correct.
The density of electric field lines does not indicate the amount of charge on an object. The density of electric field lines represents the strength or intensity of the electric field at a given point. Electric field lines are closer together where the electric field is stronger, and farther apart where the electric field is weaker.
The density of electric field lines depends on factors such as the magnitude of the charge and the distance from the charged object.
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Which one does NOT force air parcels to rise? orographic processes advection frontal movement convection
Orographic processes are the ones which does not force the air parcels to rise up.
Orographic processes refer to how mountains and hills affect regional and global weather patterns. Mountains can considerably increase precipitation locally and produce a wide range of intricate flows, a few of which are accompanied by dangerous winds and violent turbulence.
Advection is the movement of a fluid in a bulk manner to transfer a substance or amount in the fields of physics, engineering, and earth sciences. It carries the characteristics of that substance with it. The bulk of the advected substance is often a fluid as well.
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why do your hands not get warm when rubbing them with soapy water?
Answer:
Explanation:
because you are rubbing the soap not your hands so the soap takes up the energy rahter than the hands
a 12-volt electric motor has 1,000 watts input and 1 horsepower output. maintaining the same efficiency, how much input power will a 24-volt, 1-horsepower electric motor require? (note: 1 horsepower
The electric motor will require 1,000 watts input power. The result is obtained by comparing the formula for efficiency.
What is efficiency?Efficiency of an engine can be expressed as
η = P out/ P in
Where
P out = output powerP in = input powerPower is the amount of energy per unit of time.
An electric motor has
V = 12 VoltP₁ in = 1,000 wattsP₁ out = 1 horsepowerWith the same efficiency, the electric motor has
V = 24 voltP₁ out = 1 horsepowerFind output power! (P₂ in = ?)
1 horsepower = 746 watts
The efficiency is the same
η₁ = η₂
P₁ out/ P₁ in = P₂ out/ P₂ in
1 hp/ 1,000 watts = 1 hp/ P₂ in
P₂ in = 1,000 watts
Hence, the required input power of the electric motor is 1,000 watts.
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Which is the formula that describes the magnitude of an
momentum?
object's
Answer:
The magnitude of the momentum of an object is p = mv.
Explanation:
Here, m is the mass of the object and v is the velocity of the object. This quantity attributes both quantities, and is defined by Newton as the product of them.
if light from one star is 15.8 times brighter (has 15.8 times more flux) than light from another star, what is their difference in magnitudes?
The difference in magnitude of the two stars where one star has 15.8 times more flux than the other star is 2.975.
Luminosity of a star is the rate at which the star radiates energy into the space. Apparent brightness is the rate at which a star's radiated energy into the space reaches an observer on the Earth. Apparent brightness depends on both the luminosity of the star and distance from the star.
Difference in magnitude of stars in terms of luminosity is given by
m₂ - m₁ = -2.5 log (I₂/ I₁)
m₂ - m₁ = -2.5 log (1/ 15.8)
m₂ - m₁ = -2.5(log 1 - log 15.8)
m₂ - m₁ = -2.5 (0 - 1.19)
m₂ - m₁ = -2.5 (-1.19)
m₂ - m₁ = -2.5 × -1.19
m₂ - m₁ = 2.975
Therefore, the difference in magnitude of the two stars is 2.975.
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a solution is made by diluting 37 ml of a 10.25 mol/l standard solution to a volume of 2.40 l. what is the concentration of the resulting solution?
After dilution the concentration of the resulting solution will become 0.1621875 mol/l.
To find the concentration of the resulting solution, we need to calculate the number of moles of solute in the final solution and then divide by the total volume of the solution.
First, we find the number of moles of solute in the original 37 ml solution:
moles = concentration x volume
moles = 10.25 mol/l x (37 ml / 1000 ml/l)
moles = 0.39225
Next, we use the volume of the final solution to find the new concentration:
concentration = moles / volume
concentration = 0.39225 / (2.40 l)
concentration = 0.1621875 mol/l
The concentration of the resulting solution is 0.1621875 mol/l.
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A baseball is thrown up in the air from an initial height of 6 feet. Its height above the ground (in feet) t seconds after being thrown is given by the function h(t)=-16t²+46t+6. How long will it take (in seconds) for the baseball to hit the ground? a) 4 seconds b) 5/2 seconds
c) 2 seconds
d) 3 seconds
From a starting height of six feet, a baseball is hurled upward. Its height above the ground (in feet) t seconds after being thrown is given by the function h(t)=-16t²+46t+6. It take 2 seconds for the baseball to hit the ground. Hence, the correct option is (c).
The baseball hits the ground when the height is 0. Thus, solving h(t)=-16t^2 + 46t + 6 = 0:
-16t^2 + 46t + 6 = 0
Using the quadratic formula:
t = (-b ± √(b^2 - 4ac)) / 2a
Where a = -16, b = 46, c = 6
t = (-46 ± √(46^2 - 4 x -16 x 6)) / 2 * -16
t = (-46 ± √(46^2 + 384)) / -32
t = (-46 ± 2√190) / -32
t = (46 ± 2√190) / 32
t ≈ 2 seconds
So, the baseball will hit the ground approximately 2 seconds after it was thrown.
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explain the arrangements of molecular magnets in a magnet and in a magnetic substance
: Molecular magnet can refer to : molecular based magnet . An unconventional magnetic material that consists of organic molecules cordination compounds and combination
determine the proper units for momentum using dimensional analysis. (b) the unit of force is the newton n, where 1 n 5 1 kg ? m/s2 . what are the units of momentum p in terms of a newton and another fundamental si unit?
The unit of momentum is kg-m/sec, and the unit of momentum in terms of Newton is N-s.
The momentum of an object is the vector product of the mass of the object and its velocity. It is denoted by P. It is a vector quantity.
P = mv
So its unit will be (kg) × (m/s) = kg-m/s
We also know that the time rate of change of momentum is called force,
F = ΔP/Δt
ΔP = FΔt = Force × change in time
So the SI unit of momentum in terms of Newton will be, N × Sec = N-s
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the net electric flux crossing an open surface is never zero. true or false?
The given statement that net electric flux crossing an open surface is never zero, is false.
The net electric flux of an electric field through a closed surface is equal to the enclosed charge, divided by the permittivity of the free space. Where charge is taken in the unit of coulombs.
The net electric flux cross an open surface can also be zero if the is perpendicular to the direction of the field. In other word if the field lines are parallel to the surface. Electric flux is a scaler quantity. The SI unit of electric flux is N-m²/C.
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explain why only a handful of solids exhibit ferromagnetic or ferrimagnetic behavior
Ferromagnetic or ferrimagnetic behavior is exhibited by only few solids because of the strong exchange interaction and high concentration of unpaired electrons required, as well as low temperature to prevent thermal disruptions.
Ferromagnetic or ferrimagnetic behavior is a rare phenomenon that is only exhibited by a few solids. This is due to a number of conditions that must be met in order for the material to exhibit this behavior, such as a strong exchange interaction, a high concentration of unpaired electrons, and low temperature to prevent thermal disruptions.
All of these conditions need to be met in order for the ferromagnetic or ferrimagnetic behavior to be present. Therefore, it is important to understand the physics and materials behind this behavior in order to better understand and utilize this phenomenon.
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A sample of argon gas occupies a volume of 950 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant?
The required volume of the gas when pressure remains constant is calculated to be 1029.65 ml.
Charles law gives the relation between temperature and volume when the pressure of the gas is kept constant.
Mathematically, it is given as,
V₁/T₁ = V₂/T₂
It is given that the sample of argon gas occupies 950 mL at 25°C.
So, V₁ = 950 ml
T₁ = 25°C = 25 + 273.15 = 298.15 K
The volume of the gas occupied at 50°C is to be found out.
V₂ = ?
T₂ = 50°C = 50 + 273.15 = 323.15 K
Placing all the values in the above equation, we have,
V₁/T₁ = V₂/T₂
950/298.15 = V₂/ 323.15
V₂ = 950/298.15 × 323.15 = 1029.65 ml
Thus, the required volume is calculated to be 1029.65 ml.
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a lightning bolt strikes a tree, moving 23.36 c of charge through a potential difference of 142 mv. what energy was dissipated? 1mv
Without knowing t, we cannot calculate the current, and thus the energy dissipated.
When a current of I coulombs per second flows across a potential difference of V volts, the rate of energy dissipation is IV, which may alternatively be represented as I2R or V2/R (using Ohm's law).
The energy dissipated by a lightning bolt can be calculated using the equation P = IV,
where P is the power (energy per unit time),
I is the current, and
V is the potential difference.
Given that the lightning bolt moved 23.36 coulombs of charge through a potential difference of 142 millivolts,
we can calculate the current as follows:
I = Q / t
where t is the time it takes for the charge to flow, which is not specified.
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For an infinitely large plane wall with thickness L, assuming 1D heat transfer, what can you say about the rate of heat conduction?
A. It is a constant everywhere.
B. It is a constant along the plane normal to the direction of heat transfer, but varies along the direction of heat transfer.
C. It varies in time.
D. None of the above.
None of the given option is correct about the rate of heat transfer through an infinitely large plane wall of length L.
The rate of heat transfer is directly proportional to the area of the surface and the temperature different between the two sides of the object.
Q/t = -KAdT/dx
Here K is the constant depends upon the type of material, A is the area of surface, and dT/dx is the temperature gradient. So we cannot say that it is constant everywhere, because as the heat getting transfer other side the temperature gradient will go on decreasing. In addition to this it is not constant along the plane. Also it does not varies with time. So option D is correct.
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How high would you have to lift a 1000 kg car to give it a potential energy of: a. 2,000 J (b) 200,000 J
Given:
a. 2,000J
b. 200,000 J
Answer:
a. 0.204 m, b. 20.408 m
Explanation:
We know that Potential energy is given by
[tex]U = mgh[/tex]
Rearranging this, we have:
[tex]h=U/mg[/tex]
a. 2000 J = 2000 kgm/s²
h = 2000/(1000*10) (Taking g = 10 m/s²)
= 0.2 m
If we took g as 9.8 m/s²,
h = 0.204 m (Marginal error)
b. 200,000 J = 200,000 kgm/s²
h = 200,000/(1000*10) (Taking g = 10 m/s²)
= 20 m
If we took g as 9.8 m/s²,
h = 20.408 m
Show how to balance 3 masses hanging from a force table. (There is not a fourth mass to add). The masses are 3 kg, 4 kg, and 6 kg. You need to indicate the angles between the strings that will cause all of the masses to be all be in equilibrium.
Assuming the force table is set up so that the masses are placed at the vertices of an equilateral triangle, the angles between the strings should be 60 degrees.
How to balance 3 masses hanging from a force table?This will cause all of the masses to be in equilibrium.The angles between the strings can be calculated using the following formula:Angle = arccos ((m1*m2) / (m3*(m1+m2))) For this problem, the angles between the strings will be:Angle 1 = arccos ((3*4) / (6*(3+4))) = arccos (0.8) = 61.93° Angle 2 = arccos ((3*6) / (4*(3+6))) = arccos (0.75) = 56.31°Angle 3 = 180° - (Angle 1 + Angle 2) = 180° - (61.93° + 56.31°) = 61.76°Assuming the force table has four support points, the three masses can be balanced by adjusting the angles between the strings. To do this, the three masses must be arranged as far as possible from one another, with the 3 kg mass in the center and the other two masses, 4 kg and 6 kg, on the outside. To begin, the 4 kg mass should be suspended to the left of the 3 kg mass, and the 6 kg mass should be suspended to the right. The angle between the strings should be adjusted so that the 4 kg mass is suspended at an angle of 25 degrees, and the 6 kg mass is suspended at an angle of 155 degrees. This will ensure that the three masses are balanced, with the force exerted by the 4 kg mass equal to the force exerted by the 6 kg mass. To achieve equilibrium, the 3 kg mass should be suspended at an angle of 90 degrees from the 4 kg mass, and the 6 kg mass should be suspended at an angle of 90 degrees from the 3 kg mass. This will ensure that the forces acting on the 3 kg mass are equal, and the forces acting on the 4 kg and 6 kg masses are equal. This will result in a balanced system.To learn more about the force table refer to:
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an airplane flies eastward and always accelerates at a constant rate. at one position along its path, it has a velocity of 33.3 m/s . it then flies a further distance of 49700 m , and afterwards, its velocity is 43.5 m/s . find the airplane's acceleration. acceleration: m/s2 calculate how much time elapses while the airplane covers those 49700 m.
The acceleration of the airplane is [tex]7.88\times 10^{-3} m/s^2[/tex] and the time elapsed while the airplane covers [tex]49700[/tex] [tex]m[/tex] is [tex]1294.42s[/tex].
Let us consider the value of acceleration is [tex]a[/tex] [tex]m/s^2[/tex] and the time elapsed while the airplane covers [tex]49700[/tex] [tex]m[/tex] is [tex]t[/tex] [tex]s[/tex].
It is given that,
The initial velocity of the airplane, [tex]u=33.3 m/s[/tex].
The final velocity of the airplane, [tex]v=43.5m/s[/tex].
The distance covered by the airplane, [tex]s=49700 m[/tex].
It is known that, [tex]v^2=u^2+2as[/tex].
[tex]\Rightarrow (43.5)^2=(33.3)^2+2a(49700)[/tex]
[tex]\Rightarrow 1892.25=1108.89+99400a[/tex]
[tex]\Rightarrow 1892.25-1108.89=99400a[/tex]
[tex]\Rightarrow 783.36=99400a[/tex]
[tex]\Rightarrow a=\frac{783.36}{99400}[/tex]
[tex]a=7.88\times 10^{-3} m/s^2[/tex]
Hence, the acceleration of the airplane is [tex]7.88\times 10^{-3} m/s^2[/tex].
It is known that, [tex]v=u+at[/tex].
[tex]\Rightarrow 43.5=33.3+(7.88\times10^{-3})t[/tex]
[tex]\Rightarrow 43.5-33.3=(7.88\times10^{-3})t[/tex]
[tex]\Rightarrow 10.2=(7.88\times10^{-3})t[/tex]
[tex]\Rightarrow t=\frac{10.2}{7.88\times10^{-3}}[/tex]
[tex]\Rightarrow t=1294.42 s[/tex]
Hence, the time elapsed while the airplane covers [tex]49700[/tex] [tex]m[/tex] is [tex]1294.42s[/tex].
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Which would the community health nurse be least likely to include when designing a community-based program within the context of a global framework?
A) Population
B) Provider
C) Procedure
D) Physician
Physician community health nurse be least likely to include when designing a community-based program within the context of a global framework. Correct option is A.
The community health nurse, when designing a community-based program within the context of a global framework, is least likely to include the physician. Community health nurses work with individuals, families, and communities to promote health and prevent disease. They focus on educating and empowering people to make informed health decisions, and engage in activities such as disease screening, health promotion, and environmental health assessments. Community health nurses may collaborate with other healthcare providers, including public health departments, community organizations, and schools, but physicians are typically not involved in the design and implementation of community-based health programs. The focus of a community health nurse's work is on the community, not individual medical care.
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pavlina does not consider the other cars that she has seen speeding when she says that people in red cars are much more likely to speed.
Pavlina does not consider the other cars that she has seen speeding when she says that people in red cars are much more likely to speed. This illustrate Present or Present bias.
Speed is a scalar quantity, whereas velocity, which includes both magnitude and direction definitions, is speed's vector form. Speed is expressed as either the average speed for the entire distance travelled or the instantaneous speed at that specific moment.
Speed can also be described in terms of a period of time or a distance, and it can change with time. Speed is defined as the rate at which an object's position changes.
In everyday usage, we refer to speed as the amount by which an object moves, while in science, speed is defined as the rate at which an object changes its location in relation to time.
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Complete Question:
Pavlina does not consider the other cars that she has seen speeding when she says that people in red cars are much more likely to speed. What type of bias does this illustrate?
describe how an electron can move to a higher energy state by absorbing a fixed quantum of energy. describe how an electron can move to a lower energy state by releasing a fixed quantum of energy.
Bohr proposed a concept in which electrons would move around in shells, with each shell containing a different number of electrons with a fixed amount of energy. Energy is lower in the lower shell and more in the upper shell. When an electron moves from a lower shell to a higher shell, it loses energy in the process. It must absorb energy.
The ground state is the lowest energy level an electron can have. An increased number of orbitals indicates a more excited state. The greater the electron's excitation state, the greater its energy. An electron will "jump" to a higher orbital when it absorbs enough energy. In this form, the system is said to be in an excited state. An electron in an excited state can "fall" to a less excited state by releasing energy. In doing so, it emits a photon, a discrete packet of electromagnetic energy. The energy of that photon is proportional to the gap between the electron's two states. The electron loses its ability to emit photons when it enters the ground state, but it retains the ability to absorb energy quanta and enter higher excitation states (higher orbitals).
The electron's freedom of motion is proportional to the number of energy levels it can experience. There is exactly one potential state transition between a single ground state and a single excitation state. Electrons can gain enough energy to enter the excited state by absorbing a single quantum of energy. Upon decaying from its excited state, the electron releases a photon of a constant energy equal to the energy it lost upon entering the lower orbital.
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a car is traveling at a speed of 34 m/s. (a) what is its speed in kilometers per hour? km/h
The car is traveling at a speed of 34 m/s. Its speed in kilometres per hour is calculated to be 122.4 km/h.
Speed is the rate at which an object's position shifts in any direction.
By dividing the distance by the time, one may calculate speed. Calculating the units for speed requires knowledge of the units for both time and distance. The units in this example will be meters per second (m/s), due to the fact that the distance is expressed in metres (m) and the time is expressed in seconds (s).
1 h = 3600 s
1 km = 1000 m
s₂ = (34 m/s) × (60×60)/1000
⇒ 122.4 km/h
s₂ = 122.4 km/h
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in a collision between 2 and equal masses, how does the impulse imparted to the smaller mass by the larger mass compare with the impulse imparted to the larger mass by the smaller one? compared to magnitudes of impulses only.
The impulse imparted to the smaller mass by the larger mass will be equal to the impulse imparted to the larger mass by the smaller mass.
Impulse is the change in momentum. We know the time rate of change of momentum is defined as the force. And force times change in time is impulse. Mathematically,
[(m₁v₁ + m₂v₂) - (m₃v₃ + m₄v₄)]/Δt = F
Impulse = FΔt = (m₁v₁ + m₂v₂) - (m₃v₃ + m₄v₄)
According to Newton's third law, every action has an equal reaction but in the opposite direction. So the force and thereby impulse imparted by the smaller mass to the larger mass will be equal to the impulse imparted by the larger mass to the smaller mass. However after collision velocity will be different for both the masses to conserve the momentum.
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A gas with initial state variables p1, V1, and T1 expands isothermally until V2=2V1.By what factor does the temperature change?By what factor does the pressure change?
The pressure changes by a factor of 2. The initial pressure (p1) is twice the final pressure (p2).
For an isothermal process, the temperature remains constant. Therefore, the factor by which the temperature changes is 1. There is no change in temperature (T2 = T1).
To determine the factor by which the pressure changes, we can use the ideal gas law equation:
pV = nRT
Where:
p = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
Since the process is isothermal, we can rearrange the equation as:
p1V1 = p2V2
Given that V2 = 2V1, we can substitute this into the equation:
p1V1 = p2(2V1)
Simplifying the equation:
p1 = 2p2
Therefore, the pressure changes by a factor of 2. The initial pressure (p1) is twice the final pressure (p2).
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