What is the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25
s with 7,500 N of force?
128 kg
3991 kg
0.017 kg
14,091 kg

Answers

Answer 1

The mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

HOW TO CALCULATE MASS:

The mass of an object can be calculated by dividing the force applied to the object by its acceleration.

According to this question, a bus can accelerate from rest to 15.5 m/s over 8.25s. The acceleration can be calculated as follows:

a = (v - u)/t

a = 15.5 - 0/8.25

a = 15.5/8.25

a = 1.88m/s²

The mass of the bus = 7500N ÷ 1.88m/s²

The mass of the bus = 3989.4kg

Therefore, the mass of a school bus if it can accelerate from rest to 15.5 m/s over 8.25s with 7,500 N of force is 3989.4kg.

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Related Questions

What is the object' velocity between O s and 2 s?

Answers

Answer:

Explanation:

Acceleration b/c 0m/s/2s =0m/s²

A 2 kg object being pulled across the floor with a speed of 10 m/sec is suddenly
released and slides to rest in 5 sec. What is the magnitude of the frictional force
producing this deceleration?

Answers

Answer:

The frictional force producing this deceleration would have a magnitude of [tex]4\; \rm N[/tex].

Explanation:

The velocity of this object changed by [tex]\Delta v = (-10\; \rm m\cdot s^{-1})[/tex] in [tex]\Delta t = 5\; \rm s[/tex]. The acceleration of this object would be:

[tex]\begin{aligned}a &= \frac{\Delta v}{\Delta t} \\ &= \frac{-10\; \rm m\cdot s^{-1}}{5\; \rm s} = -2\; \rm m\cdot s^{-2}\end{aligned}[/tex].

Let [tex]m[/tex] denote the mass of this object. By Newton's Second Law of Motion, the net force on this object would be:

[tex]\begin{aligned}F &= m \, a \\ &= 2\; \rm kg \times (-2\; \rm m\cdot s^{-2}) \\ &= -4\; \rm N\end{aligned}[/tex].

([tex]1\; {\rm kg \cdot m \cdot s^{-2} = 1\; {\rm N}[/tex].)

If the floor is level, friction would be the only unbalanced force on this object. Thus, the magnitude of the frictional force on this object would also be [tex]4\; {\rm N}[/tex], same as the magnitude of the net force on this object.

When a baseball curves to the right (a curveball) , air is flowing faster over the right side than over the left side. at the same speed all around the baseball, but the ball curves as a result of the way the wind is blowing on the field. faster over the left side than over the right side. faster over the top than underneath.

Answers

Answer:

faster over the left side than over the right side.

Explanation:

due to ball rotation, the right side is more closely matched to the speed of the air passing by as the ball progresses. This causes the air to stick more closely to the right side of the ball and that air stays with the ball surface as the spin moves it to the back of the ball and therefore leftward. As every action has an equal and opposite reaction the leftward force moving air causes the ball to experience an equal rightward force.

When the baseball curves to the right (a curveball), then the ball moves faster over the left side than over the right side.

What direction does a curveball move?

The ball, which is thrown with a spin, is curve in the direction in which the front of the ball turns.

When a baseball curves to the right (a curveball),

For this condition, the pressure of air should be high on the left side than the pressure on right side.Molecules of the air on right side pushed backward by this spinning ball.The left side with high pressure push the ball towards right side where the pressure is low.Due to higher pressure, the ball move faster on the left side than the right side.

Hence, when the baseball curves to the right (a curveball), then the ball moves faster over the left side than over the right side.

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Three particles are placed in the xy plane. A 30-g particle is located at (3, 4) m, and a 40-g particle is located at (-2, -2) m. Where must a 20-g particle be placed so that the center of mass of the three-particle system is at the origin?

Answers

Answer:

Explanation:

30(3) + 40(-2) + 20(x) = 0(20 + 30 + 40)

x = -0.5

30(4) + 40(-2) + 20(y) = 0(20 + 30 + 40)

y = -2

(-0.5, -2)

A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?(1 point)

Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.
Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move.

There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.
There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.

There is a balanced force on the child, and the child’s motion will change direction or increase speed.
There is a balanced force on the child, and the child’s motion will change direction or increase speed.

Because of equal and opposite reactions, the child will move in the opposite direction to the force.

Answers

A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.

A child on ice skates is given a small push from behind by a parent. How are forces used to describe the resulting motion?

Because of equal and opposite reactions, there will be a force opposing the push from the parent, and they will not move. FALSE. According to Newton's third law of motion, if the parent applies force on the child, there will be a reaction applied by the child on the parent. These forces are applied to different objects so they will not cancel and the child will move. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed. TRUE. The child will have an acceleration as a consequence of the unbalanced force. The acceleration will be responsible for the change in the direction or speed of the child. There is a balanced force on the child, and the child’s motion will change direction or increase speed. FALSE. If the forces were balanced, that is, there was no net force, the movement of the child would not change, as stated by Newton's first law of motion. Because of equal and opposite reactions, the child will move in the opposite direction to the force. FALSE. The child will move in the direction of the net force.

A child on ice skates is given a small push from behind by a parent. There is an unbalanced force on the child, and the child’s motion will change direction or increase speed.

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Important parts of stydi g physics

Answers

Answer:

put your question in proper way' i hope you understand.

Explanation:

Colloid - well ______ together but not ______________

Answers

Answer:Colloid - well compacted together but not one

Imagine that there is a small rocky body caught by Earth’s gravity. Draw a comic-strip cartoon

to illustrate its journey as it travels through space toward Earth, enters Earth’s atmosphere, and

lands on Earth. Describe your illustration with narration or speech/thought bubbles. Include the

use of these key terms: atmosphere, meteor, meteoroid, meteorite.

Answers

To create this comic strip you can use a narration describing each step and illustrate each one with one image or drawing.

Creating a comic strip involves using images and short texts to explain a specific idea or phenomenon. In the case of the process for a meteor to enter Earth you can use the following ideas.

A meteoroid approaches the Earth at high speed and draw a meteor traveling near to different planets and approaching Earth.What is that? and draw the Earth wondering who or what is approaching.The meteoroid enters the atmosphere of the Earth and becomes a meteor and draw the rocky body burningThe rocky body crashes with the surface becoming a meteorite and draw the zone where the meteorite crashed.

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Use the circuit diagram to decide if the lightbulb will
light. Justify your answer.

Answers

Answer:

The light bulb will NOT light because the lower switch being closed makes a short circuit. The light will have a high resistance and the electricity will choose to flow the easiest way possible through the low resistance wires.

Explanation:

Marks: 1
What is the power of a light that uses 300 joules of energy in 60
seconds?
18,000 W
50 W
5 W
0.2 W

Answers

Answer:

W = 5W

Explanation:

1W = 1J/s

W = Watts

J = Joules

s = seconds

W = J/s

W = 300J/60s

W = 5W

What is the acceleration due to gravity in a region where a simple pendulum having a length 75.000 cm has a period of 1.7357 s?​

Answers

Answer:

Explanation:

T = 2π[tex]\sqrt{L/g}[/tex]

(T / 2π)² = L/g

g = 4π²L/T²

g = 4π²(0.75000)/(1.7357)²

g = 9.82814766...

g = 9.8281 m/s²

(a / xy=2x+a)does anyone can solve this??
Answer:??​

Answers

Answer:

Explanation:

a / xy = 2x + a

a = 2x²y + axy

a(1 - xy) = 2x²y

a = 2x²y / (1 - xy)

a / xy = 2x + a

a = 2x²y + axy

a = y(2x² + ax)

y = a / (2x² + ax)

a / xy = 2x + a

a = 2x²y + axy

a / xy = 2x + a

0 = 2yx² + ayx - a

x = (-ay ±√((ay)² - 4(2y)(-a))) / (2(2y))

x = (-ay ±√(a²y² + 8ay)) / 4y

When a hot metal cylinder is dropped into a sample of water, the water molecules

Answers

Answer:

I believe the answer is speed up.

Explanation:

this is because when water heats up the molecules move father apart from each other they speed up, eventually causing the water to boll

HELPPP!! Thanks!

If you only wanted to increase the particle motion of a gas without increasing any of its other properties, which would the most correct situation?


a. Keep the gas at a constant pressure and keep the temperature constant, but increase the volume of the gas

b. Keep the gas in a fixed container at constant pressure and increase the temperature

c. Keep the gas in a fixed container at constant pressure and decrease the temperature

d. Keep the gas at a constant volume and keep the temperature constant, but decrease the pressure of the gas

Answers

Answer:c i think

Explanation: not sure

An object following a straight-line path at constant speed

A.) has no forces acting on it.

B.) has a net force acting on it in the direction of motion.

C.) has zero acceleration.

D.) must be moving in a vacuum.

E.) none of the above

Answers

An object following a straight-line path at constant speed is option C.) has zero acceleration.

Are there any forces acting on a moving item traveling in a straight line at a constant speed?

There are no forces operating on a body if it is travelling straight ahead at a steady speed. There are no forces operating on a body if it is travelling straight ahead at a steady speed.

Note that the physics concept of acceleration measures how quickly an object's motion is changing. An object's speed or velocity is what largely defines its motion.

Therefore, An object is considered to be accelerating when its velocity changes over time and as such  since acceleration of the object is  said to be  zero, one can say that the net force acting on it is also zero.

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Can someone please help me? Please answer the question in the screenshot. Thank you! I need this answered!

Answers

Answer:

Explanation:

Photosynthesis is needed to store energy for the growth of the plant. It is like a factory that uses sunlight energy to convert 6CO₂ and 6H₂O into C₆H₁₂O₆ and 6O₂

Cell respiration is the process of breaking down the glucose and converting it into the other needed components of life. It's the engine that's fueled by the sugar of photosynthesis.

If a particle undergoes SHM with amplitude 0.17 mm , what is the total distance it travels in one period

Answers

Answer:

Particle travels 4 * amplitude in one period = .68 mm

The fastest possible rate of rotation of a planet is that for which the gravitational force on material at the equator just barely provides the centripetal force needed for the rotation. Calculate the minimum rotation period assuming a density of 3.70 g/cm3.

Answers

Answer:

m ω^2 R = centripetal force

G M m / R^2 = gravitational force

ω^2 = G M / R^3    for the forces to be equal

d (density) = M / V = M / (4/3 R^3) = 3/4 M / R^3

or M / R^3 = 4 d / 3

Then

ω^2 = G 4 d / 3

d = 3.7 g/cm^2 = 3700 kg/m*3    converting

ω^2 = 6.67E-11 * 3700 * 4 / 3 = 32.9E-8

ω = 5.74E-4

P = 1 / f = 2 pi / ω = 6.28 / 5.74E-4 = 1.09E4 sec

10900 / 3600 = 3.04 hrs    for the minimum rotation period

Car 1 of mass m1 is waiting at a traffic light.
Car 1 is struck from behind by Car 2 of mass m2.
The two cars stick together after the collision.
Car 2 was traveling at v2i = 30.0 m/s before the collision.

What is the kinetic, in [J], of the system after the collision if m1 = 2500 kg and m2 = 1000 kg?

Answers

Answer:

Explanation:

Conservation of momentum

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

KE = ½(2500 + 1000)8.57² = 128,571.428... = 128 KJ

The kinetic energy of the system after the collision would be 128.5  KJ.

What is momentum?

It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle, and the momentum of any particle is expressed in Kg m/s unit.

As given in the problem Car 1 of mass m1 is waiting at a traffic light.

Car 1 is struck from behind by Car 2 of mass m2. The two cars stick together after the collision. Car 2 was traveling at v2i = 30.0 m/s before the collision.

By using the conservation of the momentum,

2500(0) + 1000(30) = (2500 + 1000)v

v = 8.57 m/s

The final velocity of the system comes out to be  8.57 m/s.

The kinetic energy of the system after the collision,

KE =1/2×(2500 + 1000)×8.57² = 128,571.4

    = 128.5  KJ

Thus, the kinetic energy of the system after the collision would be 128.5  KJ.

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what is the force that every mass experts on every other mass called?

Answers

Answer: The forces of gravity

Explanation:  The consequence of this phenomenon is that every mass exerts a so-called "force of mutual attraction" on every other mass. The attractive force that the celestial bodies exert on other masses by virtue of their total mass is called the force of gravity.

Hope this helps

The part of the circuit that converts electrical energy into other forms

Answers

Answer:

Load

Explanation:

The load in an electric circuit is any device that converts electrical energy into another form of energy.

Two a.c V1=100sin(wt) and V2 = 150cos(wt) are fed into one circuit, determine the combined output of the two as a single a.c

Answers

Answer:

Explanation:

V = 100sin(ωt) + 150cos(ωt)

let x = ωt

V = 100sin(x) + 150cos(x)

a maximum or minimum will occur when the derivative is zero

V' = 100cos(x) - 150sin(x)

0 = 100cos(x) - 150sin(x)

100cos(x) = 150sin(x)

100/150 = sin(x)/cos(x)

0.6667 = tan(x)

x = 0.588 rad

V = 100sin(0.588) + 150cos(0.588)

V = 180.27756

as the maximum will not occur until ωt = 0.588 radians, for a cosine function we subtract that amount as a phase angle φ

V = 180.3 cos(ωt - 0.588)

or as a sine function, the phase angle lags the cosine by a difference of π/2

V = 180.3sin(ωt - (0.588 - π/2)

V = 180.3sin(ωt + 0.983)

One potato plant makes 7.5
potatoes. There are 10.000
people on a ship and 3
potatoes per person. How
many potato plants are
needed per person.

Answers

If all conditions are ideal, you may harvest about five to 10 potatoes per plant for your gardening efforts. Yields are based on both the care your give your plants during the growing season and the variety of potatoes you choose to grow.

answer

7.5×10.000=75÷3=25

Best way to demonstrate that waves transfer energy

Answers

Answer:

Waves can transfer energy over distance without moving matter the entire distance. For example, an ocean wave can travel many kilometers without the water itself moving many kilometers. The water moves up and down—a motion known as a disturbance. It is the disturbance that travels in a wave, transferring energy.

Explanation:

The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.
Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.

Answers

The planar simple harmonic wave travels in the positive direction of x axis with wave velocity u=2m/s, and the vibration curve of the particle at the origin in cosinusoidal form is shown in the figure.

Try to find (1) the vibration function of the particle at the origin, (2) the wave function of the planar simple harmonic wave according to the origin.

Answer:

Figure 16.8 The pulse at time

t

=

0

is centered on

x

=

0

with amplitude A. The pulse moves as a pattern with a constant shape, with a constant maximum value A. The velocity is constant and the pulse moves a distance

Δ

x

=

v

Δ

t

in a time

Δ

t

.

The distance traveled is measured with any convenient point on the pulse. In this figure, the crest is used.

A fan blade Spins at 3,000 revolutions per minute.
How
many degrees does it rotate in one second?

Answers

18,000 degrees in one second i believe

As the amount of charge on either of two charged objects increases, the electric force between the objects decreases.

O True O False​

Answers

Answer:

False.

Explanation:

provided the distance between the forces remains the same, the force will increase with increased charge, whether attractive or repulsive.

You are investigating how objects move when they are dropped from different heights. To collect your data, you drop a 1 kg weight from different heights and record the time it takes for the object to hit the ground when dropped from different heights. The data you collect is shown below:

Height dropped (m)

Time to fall (s)

1.0

0.45

2.0

0.63

3.0

0.78

4.0

0.89



Next, you plan to drop a 5 kg weight from the same heights. How will your time values in your new data table for the 5 kg weight compare to the time values in the old data table for the 1 kg weight?

Answers

The time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

The given parameters;

Mass of the first object, m1 = 1 kg

Mass of the second object, m2 = 5 kg

The final velocity of the objects during the downward motion is calculated as follows;

[tex]v_f = v_0 + gt\\\\v_f = 0 + gt\\\\\v_f = gt[/tex]

The time of motion of the object from the given height is calculated as;

[tex]h = v_0 t + \frac{1}{2} gt^2\\\\h = 0 + \frac{1}{2} gt^2\\\\h = \frac{1}{2} gt^2\\\\gt^2 = 2h\\\\t^2 = \frac{2h}{g} \\\\t = \sqrt{\frac{2h}{g} }[/tex]

The time of motion of each object is independent of mass of the object.

Thus, the time of motion of the 5 kg object will be the same as 1 kg since both objects are dropped from the same height.

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Kyle, a 23-year-old-male, feels as if he is always on the “edge of his seat,” as if something is going to happen. He also has problems sleeping. Kyle feels nervous continuously and cannot seem to relax. When asked if he is nervous about something in particular, he can’t pinpoint the source of his anxiety.

Answers

Based on the information given, it can be posited that Kyle has a general anxiety disorder.

Generalized Anxiety Disorder is a disorder that is characterized by persistent and excessive worry about different things. People with the disorder may anticipate disaster and are concerned about money, health, family, or other issues.

Some of the effective ways of treatment are spending more time with family and friends, doing regular exercises , enough sleeping, etc.

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Answer This!!!!!!
I'll give brainliest to whoever gets it right.

Answers

Answer:

Explanation:

 Gamma can occur at any step in the decay as the remaining protons and neutrons rearrange themselves into their new identity.

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