The maximum angle between a light ray and the wall of the core for it to remain inside the core is the critical angle, which depends on the refractive indices of the core and surrounding medium.
This question seems incomplete, as there is no context or information provided about what "the core" refers to. Without knowing what type of core is being referred to, it is impossible to provide a meaningful explanation. If the question is referring to the core of an optical fiber, then the maximum angle between a light ray and the wall of the core is determined by the critical angle of the material surrounding the core. This critical angle is defined as the angle at which light is refracted at an angle of 90 degrees with respect to the normal to surface. Any angle larger than the critical angle will result in total internal reflection, which means that the light ray will remain inside the core. The exact value of the critical angle depends on the refractive indices of the materials involved, but it can be calculated using Snell's law.
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Part A - Average normal strain along AC
Determine the average normal strain (ϵAC)avg along AC after the load has been applied.
Express the average normal strain in millimeters per millimeter to three significant figures.
(ϵAC)avg = mm/mm
To determine the average normal strain (ϵAC)avg along AC, we need to use the formula: (ϵAC)avg = ΔL/Lo, where ΔL is the change in length along AC and Lo is the original length along AC.
Assuming that AC is a straight line, we can measure the length of AC as the distance between A and C, which is 100 mm.
After the load has been applied, we can measure the new length of AC using a strain gauge or similar device. Let's say we measure the new length of AC as 101.5 mm.
Therefore, ΔL = 101.5 mm - 100 mm = 1.5 mm
Using the formula, we can calculate the average normal strain along AC as follows:
(ϵAC)avg = ΔL/Lo = 1.5 mm/100 mm = 0.015 mm/mm
Expressing this answer to three significant figures gives us:
(ϵAC)avg = 0.0150 mm/mm
Therefore, the average normal strain along AC after the load has been applied is 0.0150 mm/mm.
Hi! To determine the average normal strain (ϵAC)avg along AC after the load has been applied, you'll need to follow these steps:
1. Identify the change in length of AC (ΔL) in millimeters.
2. Determine the original length of AC (L₀) in millimeters.
3. Calculate the average normal strain using the formula: (ϵAC)avg = ΔL / L₀
The average normal strain will be expressed in millimeters per millimeter (mm/mm) to three significant figures. Unfortunately, I cannot provide a specific value for (ϵAC)avg without knowing the change in length and the original length of AC. Please provide the necessary information, and I'd be happy to help you calculate the average normal strain.
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an individual is nearsighted; his near point is 17.0 cm and his far point is 65.0 cm. (a) what lens power is needed to correct his nearsightedness?
To correct the nearsightedness of an individual with a near point of 17.0 cm and a far point of 65.0 cm, a lens power of -1.54 diopters is needed.
What is Lens?
A lens is a curved piece of transparent material, usually made of glass or plastic, that can refract or bend light. Lenses are used in many optical devices such as cameras, telescopes, microscopes, eyeglasses, and binoculars.
First, we need to find the focal length of the corrective lens. To do this, we will use the formula: 1/f = 1/u - 1/v, where f is the focal length, u is the object distance (far point), and v is the image distance (near point).
Convert the given distances to meters: u = 0.65 m and v = 0.17 m.
Plug the values into the formula: 1/f = 1/0.65 - 1/0.17. 4.
Calculate the value of 1/f: 1/f = -0.021538. 5. Now, find the focal length (f) by taking the reciprocal of the calculated value:
f = -1/-0.021538
= 46.4 cm.
To find the lens power (P), use the formula P = 1/f (in meters). Convert the focal length to meters:
f = 0.464 m. 7.
Calculate the lens power:
P = 1/0.464
= -1.54 diopters.
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What happens to the voltage over the inductor due to Faraday’s law in the steady state?
For steady state, the equation for the voltage over the inductor is VL = i*RL = (V*RL)/(RL + R)
In steady state, the voltage over the inductor remains constant due to Faraday's law. Faraday's law states that a changing magnetic field induces an electromotive force (EMF) in a circuit. In the case of an inductor in steady state, the current flowing through the inductor is constant, so the magnetic field produced by the current is also constant. Therefore, there is no changing magnetic field to induce an EMF, and the voltage over the inductor remains constant.
The equation for the voltage over the inductor in steady state (VL = i*RL = (V*RL)/(RL + R)) shows that the voltage is determined by the current flowing through the inductor and the resistance of the circuit. Since the current is constant in steady state, the voltage over the inductor will also be constant. In the steady state, the voltage across the inductor drops to zero due to Faraday's law.
Faraday's law states that the voltage induced in a circuit is proportional to the rate of change of magnetic flux. In the steady state, the current through the inductor becomes constant, meaning the rate of change of magnetic flux is zero. Therefore, the induced voltage across the inductor is also zero. In the steady state, the equation for the voltage over the inductor is VL = i*RL = (V*RL)/(RL + R). However, since the rate of change of magnetic flux is zero, the voltage across the inductor becomes zero (VL = 0). This means that the voltage across the inductor is negligible in the steady state due to Faraday's law.
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An alpha particle (a helium nucleus, containing 2 protons and 2 neutrons) starts out with kinetic energy of 10 MeV (10 × 106 eV), and heads in the +x direction straight toward a gold nucleus (containing 79 protons and 118 neutrons). The particles are initially far apart, and the gold nucleus is initially at rest. Assuming that all speeds are small compared to the speed of light, answer the following questions about the collision. (a) What is the final momentum of the alpha particle, long after it interacts with the gold nucleus? (b) What is the final momentum of the gold nucleus, long after it interacts with the alpha particle? (c) What is the final kinetic energy of the alpha particle? (d) What is the final kinetic energy of the gold nucleus? (e) Assuming that the movement of the gold nucleus is negligible, calculate how close the alpha particle will get to the gold nucleus in this head-on collision.
(a) The momentum of the alpha particle is conserved, so the final momentum is also 2mv, where m is the mass of the alpha particle and v is its final velocity. Therefore, we need to find the final velocity. The initial kinetic energy of the alpha particle is all converted to potential energy when it is very close to the gold nucleus. Using conservation of energy, we have:
Initial KE = Final PE + Final KE
(1/2)mv2 = kq1q2/r + (1/2)mv2f
where k is Coulomb's constant, q1 and q2 are the charges on the alpha particle and gold nucleus (2e and 79e, respectively), r is the distance of closest approach, and v2f is the final velocity of the alpha particle after the collision. We can rearrange this equation to solve for v2f:
v2f = sqrt[(mv2)2 + 2kq1q2/mr - (2kq1q2/r)]
Plugging in the values given, we get:
v2f = 2.37 x 106 m/s
So the final momentum is:
p = 2mv2f = 9.48 x 10-22 kg m/s
(b) Since the gold nucleus is initially at rest, the final momentum of the gold nucleus is also equal to the momentum of the alpha particle. Therefore:
p = mv
where m is the mass of the gold nucleus and v is its final velocity. Solving for v, we get:
v = p/m = (2mv2f)/m = 3.39 x 104 m/s
(c) The final kinetic energy of the alpha particle is:
KE = (1/2)mv2f = 5.60 x 10-14 J = 350 keV
(d) The final kinetic energy of the gold nucleus is:
KE = (1/2)mv2 = 1.45 x 10-19 J = 9.03 keV
(e) At the point of closest approach, the potential energy between the alpha particle and gold nucleus is converted entirely into kinetic energy. Therefore, we can equate the potential energy to the initial kinetic energy of the alpha particle:
kq1q2/r = (1/2)mv2i
Plugging in the values given, we get:
r = kq1q2/(mv2i) = 7.09 x 10-15 m
Therefore, the alpha particle will get as close as 7.09 x 10-15 m to the gold nucleus in this head-on collision.
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Which property of the lens describes its ability to show two adjacent objects as discrete entities?A) Resolving power. B) Illumination. C) Magnification. D) Par focal
The property of the lens that describes its ability to show two adjacent objects as discrete entities is A) Resolving power.
Resolving power refers to the ability of a lens to distinguish between closely spaced objects, allowing the viewer to see them as separate entities. This property is crucial in microscopy and imaging systems, as it ensures that fine details of a specimen can be observed.
The other options are incorrect because B) Illumination relates to the amount of light provided to the specimen, which is important for visibility but does not directly affect the ability to distinguish between adjacent objects. C) Magnification refers to the enlargement of an object's image, but without adequate resolving power, increasing magnification will not improve the clarity of closely spaced objects. D) Parfocal describes a set of lenses that maintain focus when their magnification is changed, which is a convenience feature but does not influence the ability to distinguish between adjacent objects.
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х Y bid mo Figure 1 xhelll Y 20 mo Figure 2 In Figure 1, cart Y is connected to cart X by a tight string and is also connected to the hanging block of mass mo by a light string that passes over a pulley. Figure 2 shows a system that is identical except for one change: cart Y and X are connected by a spring at its equilibrium length. Both systems are released from rest. Is the hanging block's acceleration as a function of time the same in both systems, and why or why not? Figure 2 In Figure 1, cart Y is connected to cart X by a tight string and is also connected to the hanging block of mass mo by a light string that passes over a pulley. Figure 2 shows a system that is identical except for one change: cart Y and X are connected by a spring at its equilibrium length. Both systems are released from rest. Is the hanging block's acceleration as a function of time the same in both systems, and why or why not? А. Yes, because the net external force exerted on both systems is the same. B Yes, because the tension in the string connecting the block to cart Y is determined by the masses of cart Y and the block. No, because the net external force exerted on each system is different. D No, because the tension in the string connected to the block is constant in one system but not in the other.
D. No, because the tension in the string connected to the block is constant in one system (Figure 1) but not in the other (Figure 2). In Figure 1, the tight string maintains a constant tension, while in Figure 2, the spring at its equilibrium length causes the tension to vary as the spring expands and contracts, affecting the hanging block's acceleration as a function of time.
The hanging block's acceleration as a function of time is not the same in both systems. In Figure 1, the tension in the light string that passes over the pulley is constant and determined by the masses of cart Y and the block, so the net external force exerted on the system remains constant. In Figure 2, the spring connecting cart Y and X provides a variable tension force, which changes as the spring stretches or compresses from its equilibrium length. Therefore, the net external force exerted on the system varies with time, leading to a different acceleration of the hanging block compared to Figure 1. So, the correct answer is D: No, because the tension in the string connected to the block is constant in one system but not in the other.
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the length of a vibrating air column is shortened the sound wave produced by the shortened air column will have an increase in
The sound wave produced by the shortened air column will increase in frequency.
The length of a vibrating air column affects the wavelength of the sound wave it produces. When the length of the air column is shortened, the effective length of the vibrating portion decreases, resulting in a shorter wavelength. According to the wave equation, the speed of sound remains constant in a given medium. Since the speed of sound is constant and the wavelength decreases, the frequency of the sound wave must increase to maintain this relationship (frequency = speed/wavelength). Thus, when the length of the vibrating air column is shortened, the sound wave produced will increase in frequency. This change in frequency affects the perceived pitch of the sound, with a higher frequency corresponding to a higher pitch.
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The inside of a Carnot refrigerator is maintained at a temperature of 277 K, while the temperature in the kitchen is 287 K. Using 2250 J of work, how much heat can this refrigerator remove from its inside compartment?
|QC| = ? J
The Carnot refrigerator operates on the principle of transferring heat from a cooler region to a hotter region with the help of external work. The amount of heat that the refrigerator can remove from its inside compartment can be determined using the equation:
QC = W*(TC/TH - 1)
Efficiency (η) = (Tc / (Th - Tc))
Where Tc is the cold temperature (inside the refrigerator) and Th is the hot temperature (kitchen temperature). In this case, Tc = 277 K and Th = 287 K.
First, calculate the efficiency:
η = 277 / (287 - 277) = 277 / 10 = 0.277
Next, we can use the formula for the heat removed from the inside compartment, which is given by:
Qc = W / η
Where Qc is the heat removed and W is the work done. In this case, W = 2250 J.
Finally, calculate the heat removed:
Qc = 2250 / 0.277 ≈ 8103 J
So, the refrigerator can remove approximately 8103 Joules of heat from its inside compartment using 2250 Joules of work.
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a chevy camera engine exerts 650 hp to move the car. how many watts of power does the engine exert
a Chevy camera engine exerts 650 hp to move the car. then 4.8 × 10⁵ Watt.of power does the engine exert .
Power is the rate of doing work. Power is also defined as work divided by time. i.e. Power = Work ÷ Time. Its SI unit is Watt denoted by letter W. Watt(W) means J/s or J.s-1. Something makes work in less time, it means it has more power. Work is Force times Displacement. Dimension of Power is [M¹ L² T⁻³].
Just multiply the horsepower with 745.7 that will convert into watt.
Watt = 650 hp × 745.7 = 4.8 × 10⁵ watt.
a Chevy camera engine exerts 650 hp to move the car. then 4.8 × 10⁵ Watt.of power does the engine exert.
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Smoke detectors are based on the radioactive decay of Americium-241. Since multiple detectors are placed in a typical home, which type of radiation would you expect the source to emit? a) alpha. b) beta. c) gamma
Smoke detectors that are based on the radioactive decay of Americium-241 emit alpha radiation. The correct option is a.
Radioactive decay -The spontaneous breakdown of unstable radioactive substances into stable components and releasing energy in the form of radiation.
Smoke detectors that are based on the radioactive decay of Americium-241 emit alpha radiation. This type of radiation is relatively safe because it cannot penetrate most materials, including human skin. However, if ingested or inhaled, alpha particles can cause damage to living tissue. Since multiple detectors are placed in a typical home, it is important to dispose of them properly to prevent any potential health hazards.
Therefore the source to emit is alpha,(option a).
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if the frequency of the motion of a simple harmonic oscillator is increased by a factor of 4, by what factor does the maximum speed of the oscillator change?
Increasing the frequency of a simple harmonic oscillator by a factor of 4 while keeping the amplitude constant will result in a factor of 2 increase in the maximum speed of the oscillator.
What is Speed?
Speed is a scalar physical quantity that describes the rate at which an object covers a distance in a given amount of time. It is calculated as the distance traveled by an object divided by the time taken to cover that distance.
the maximum speed of the oscillator will increase by a factor of 4. However, this factor is due to the combined effect of both increasing the frequency and the amplitude of the motion. Since we are only interested in the effect of the change in frequency, we need to divide the factor of 4 by the factor by which the amplitude changes.
For a simple harmonic oscillator, the amplitude is directly proportional to the frequency, so if the frequency is increased by a factor of 4, the amplitude must decrease by a factor of 4 to keep the energy constant. Therefore, the factor by which the amplitude changes is 1/4.
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if i stood on the surface of pluto, observing its big moon, i would see that moon:
If you were standing on the surface of Pluto, observing its big moon Charon, you would see Charon appearing much larger in the sky compared to how our moon appears from Earth.
Charon is about half the size of Pluto itself, whereas our moon is only about 1/4 the size of Earth. Therefore, Charon would appear much closer and larger in the sky than our moon does.
If you stood on the surface of Pluto, observing its big moon (Charon), you would see that moon:
1. Locate Charon in the sky, as it is the largest and closest moon to Pluto.
2. Observe its movement in the sky, which would appear to be locked in a mutual tidal lock with Pluto, meaning both bodies always show the same face to each other.
3. Notice that Charon would appear to be much larger than our Moon from Earth, due to its close proximity to Pluto.
4. Be aware that Charon's illumination would be much weaker than the Moon's on Earth, as the sunlight reaching Pluto and its moons is much dimmer due to their distance from the Sun.
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If I stood on the surface of Pluto, observing its big moon, I would see that moon: d. remain in the same place in the sky
What would happenTidal locking is the result of gravitational interaction between two celestial bodies, such as Pluto and its moon Charon. Over time, the gravitational pull between the two bodies causes them to fall into a state where they each take exactly as long to rotate around their own axis as they do to revolve around each other.
For example, our Moon is tidally locked to the Earth, which is why we always see the same "face" or "side" of the Moon from our perspective on Earth.
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Question
If I stood on the surface of Pluto, observing its big moon, I would see that moon:
a. rise in the east
b. rise in the west
c. get smaller day by day
d. remain in the same place in the sky
e. Come on! Pluto has no moons!
Why did the terrestrial planets lose the majority of the gas in their primary atmospheres?
a. They were too hot and their escape velocities too low to hold onto them.
b. The solar wind was too strong and blew these gases off the planets.
c. Their high surface temperatures made the gas chemically react with the rock.
d. The initial gases were so heavy when the planet differentiated that they sank to the core.
The terrestrial planets lost the majority of the gas in their primary atmospheres because they were too hot and their escape velocities too low to hold onto them.
The terrestrial planets, including Earth, Mars, Venus, and Mercury, were formed from the accretion of dust and gas in the early solar system. During their formation, they accumulated gas in their atmospheres, which were primarily composed of hydrogen and helium. However, due to their high surface temperatures, which were caused by the heat of their formation and radioactive decay, and their low escape velocities, which are the speeds required for gas particles to escape from a planet's gravitational pull, the majority of the gas in their primary atmospheres was lost.
Therefore, it can be concluded that the primary reason for the loss of gas in the terrestrial planets' atmospheres was their high surface temperatures and low escape velocities, which made it easy for the gas to escape into space.
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a well in which the water rises on its own to a level above its aquifer choose one: a. is the result of pressure within a confined aquifer that creates a potentiometric surface. b. always pushes water higher than the ground surface.
A well in which the water rises on its own to a level above its aquifer "is the result of pressure within a confined aquifer that creates a potentio-metric surface." (Option D)
What is an aquifer?An aquifer is a subterranean layer of porous, water-bearing rock, rock fissures, or unconsolidated materials. A water well can be used to obtain groundwater from aquifers. The features of aquifers vary widely.
Aquifers are bodies of rock and/or sediment that contain groundwater. The term "groundwater" refers to rainwater that has entered the soil under the surface and accumulated in voids underground. Aquifers are classified into two types: confined and unconfined.
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Full Question:
A well in which the water rises on its own to a level above its aquifer Choose one: A. is called a successful well. B. always pushes water higher than the ground surface. C. cannot be used for commercial or public use; the water is under too much pressure. D. is the result of pressure within a confined aquifer that creates a potentiometric surface.
the schmidt corrector plate largely cures spherical aberration, giving a wide, flat field of view. T/F?
True. The Schmidt corrector plate is designed to largely cure spherical aberration, which is a type of optical distortion that can occur in spherical lenses. This correction allows for a wider, flatter field of view. To know more about schmidt please check the following link
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a frictionless piston-cylinder device initially contains 200 l of saturated liquid refrigerant-134a at 100 kpa. heat is added until the temperature reaches 700c.
the refrigerant undergoes an isothermal phase change from a saturated liquid to a saturated vapor as the temperature increases.
The addition of heat to the frictionless piston-cylinder device causes the temperature of the saturated liquid refrigerant-134a to increase from its initial state of 100 kPa to 700C. The piston-cylinder device remains frictionless throughout this process, meaning that there is no loss of energy due to friction between the piston and cylinder walls. As a result, the refrigerant undergoes an isothermal phase change from a saturated liquid to a saturated vapor as the temperature increases.
During the heating process, the refrigerant absorbs heat from the surroundings, causing its temperature to rise. Once the temperature reaches 700C, the refrigerant has completely evaporated and the piston-cylinder device now contains 200 L of saturated vapor refrigerant-134a at 100 kPa. Overall, the process can be considered a constant-pressure heating process, as the pressure remains constant throughout the heating process.
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The longest wavelength of a photon that can be emitted by a hydrogen atom, for which the initial
state is n = 3, is closest to:
A) 550 nm B) 625 nm C) 575 nm D) 600 nm E) 650 nm
The Rydberg formula for hydrogen, which relates the wavelengths of emitted photons to the initial and final energy levels:
1/λ = R_H * (1/n_final^2 - 1/n_initial^2)
Here, λ is the wavelength, R_H is the Rydberg constant for hydrogen (approximately 1.097 x 10^7 m^(-1)), n_initial is the initial energy level (n = 3), and n_final is the final energy level.
For the longest wavelength photon, the final energy level will be the one just below the initial level (n = 2), because the photon's energy and wavelength are inversely proportional.
Using the formula, we have:
1/λ = (1.097 x 10^7) * (1/2^2 - 1/3^2)
1/λ = (1.097 x 10^7) * (1/4 - 1/9)
1/λ ≈ (1.097 x 10^7) * (5/36)
λ ≈ 1 / (1.097 x 10^7 * 5/36) ≈ 6.564 x 10^(-7) m
Converting this to nanometers, we get:
λ ≈ 656.4 nm
Hence, The closest option to this value is E) 650 nm.
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Tyler is a corn farmer. The price of corn is $5. 00 per hundred weight (cwt). The fixed cost of growing one acre of corn is $45. The variable costs of growing one acre of corn is $155
Tyler's cost to grow one acre of corn is $200 ($45 fixed + $155 variable). If he produces 100 cwt of corn per acre, he earns $500. His profit would be $300 per acre ($500 revenue - $200 cost).
Tyler earns a profit of $300 per acre of corn. This is calculated by subtracting the total cost of $200 (fixed cost of $45 + variable cost of $155) from the revenue earned of $500 (100 cwt of corn at $5.00 per cwt). The fixed cost is the cost that remains constant, while the variable cost changes with the level of production.
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Tom bikes 5 km south, 2 km east, 2 lom south 2 km east, 6 km north, and then 3 kom east. How many mis he from where he started? Or your paper provide a sketch of the Situation and show how you calculated your answer. If you need to round your answer round to 2 decimal places He is kilometers from where he started,
To solve this problem, we can use the Pythagorean theorem and some basic geometry. Let's first draw a sketch of Tom's route:
```
N
|
2 km |
E | 3 km
|
W --------+-------- E
|
2 km |
S | 6 km
|
S
```
Tom started at the point marked "W" and then followed the path indicated by the arrows. We can see that his route is made up of several segments, each of which goes either north/south or east/west. To calculate the total distance he traveled, we can break down each segment into its north/south and east/west components and then add them up.
Here's a table that shows the breakdown:
| Segment | Direction | Distance | North/South Component | East/West Component |
|---------|-----------|----------|----------------------|---------------------|
| 1 | South | 5 km | -5 km | 0 km |
| 2 | East | 2 km | 0 km | 2 km |
| 3 | South | 2 km | -2 km | 0 km |
| 4 | East | 2 km | 0 km | 2 km |
| 5 | North | 6 km | 6 km | 0 km |
| 6 | East | 3 km | 0 km | 3 km |
To calculate the total north/south and east/west components, we can simply add up the values in the corresponding columns:
- North/South component: -5 km + 0 km - 2 km + 0 km + 6 km + 0 km = -1 km
- East/West component: 0 km + 2 km + 0 km + 2 km + 0 km + 3 km = 7 km
Now we can use the Pythagorean theorem to calculate the total distance:
```distance = sqrt((-1 km)^2 + (7 km)^2)
= sqrt(50 km^2)
= 7.07 km (rounded to 2 decimal places)
```
Therefore, Tom is 7.07 kilometers from where he started.
I hope that helps! Let me know if you have any further questions.
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Convert the following from time domain to phasor domain. V2(50) sin wt
Given the expression V2(50) sin wt, you can represent it in the phasor domain as follows:
Your expression: V2(50) sin wt
Phasor domain representation: 50∠0° V
In the phasor domain, we express the function as a complex number with magnitude (50 in this case) and phase angle (0° for a sine function).
To convert V2(50) sin wt from time domain to phasor domain, we need to represent it as a complex number using phasors. In the time domain, V2(50) sin wt represents a sinusoidal waveform with a frequency of w Hz and an amplitude of 50 volts.
In the phasor domain, we represent sinusoidal waveforms using complex numbers with a magnitude (amplitude) and a phase angle. The phasor equivalent of V2(50) sin wt can be written as V2 = 50 ∠θ, where θ is the phase angle of the waveform.
To determine the phase angle θ, we need to know the relationship between the voltage waveform and the current waveform in the circuit. Assuming that V2 is the voltage across a resistor R, we can use Ohm's law to find the current waveform.
If I is the current through the resistor, then V2 = IR. In the phasor domain, this becomes V2 = IZ, where Z is the impedance of the resistor (which is just R for a purely resistive element).
Since V2 and I are in phase (i.e., they have the same phase angle), we can use the relationship V2 = 50 ∠θ to find the phase angle θ.
Therefore, the phasor equivalent of V2(50) sin wt is V2 = 50 ∠θ, where θ is the phase angle of the waveform determined by the relationship V2 = IZ.
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In gradation, the higher the angle of the comb, the greater the amount of: a) work b) space c) length d) transparency.
In gradation, the higher the angle of the comb, the greater the amount of work. The correct option is a).
In gradation, the angle of the comb refers to the degree of incline or slope of its teeth. The higher the angle of the comb, the greater the amount of space between the teeth of the comb. This increased space allows for a greater amount of work to be done while combing, as it allows for more hair to be lifted and separated.
Therefore, the correct answer is (a) work. The angle of the comb is an important factor in determining the amount of work that can be done while combing, as it determines the amount of space available for the hair to be lifted and separated.
Additionally, a higher angle of the comb can also result in longer and more gradual transitions between the lengths of hair, which can help to create a more natural and blended look. Transparency, on the other hand, is not affected by the angle of the comb, and therefore option (d) is not correct.
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In gradation, the higher the angle of the comb, the greater the amount of length, specifically arc length. This impacts the path lengths of waves passing through a diffraction grating, intensifying their diffraction.
Explanation:In the context of gradation, the higher the angle of the comb, the greater the amount of length, in terms of the arc length. The arc length is inversely proportional to the angle of rotation, meaning as the angle of rotation increases, so does the arc length.
In addition, this principle aligns with the properties of a diffraction grating, often used in Physics to study wave interactions. The slits in a diffraction grating are narrower, with space them that changes based on their angle. As the angle increases, the distance between the slits increases too, affecting the path length of the waves passing through them, and thus, intensifying the diffraction impacts.
For instance, this is represented in Figure 27.18 showing the intensity of light passing through a double slit and a diffraction grating for monochromatic light. Here, the maxima become narrower and the regions between darker as the number of slits increases, a result of increased lengths due to gradation angle.
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For a nova to occur, the system must have already been a(n): a. White dwarf b. Black hole c. Red giant d. Supernova
For a nova to occur, the system must have already been a c. red giant. A nova is a sudden brightening of a star that occurs due to a thermonuclear explosion on its surface.
This explosion happens when a white dwarf star in a binary system accretes matter from its companion star, which causes the white dwarf to become hotter and denser. When the temperature and pressure at the surface of the white dwarf reach a critical point, a thermonuclear explosion occurs, causing the star to brighten significantly.
However, in order for the white dwarf to accrete matter from its companion star, the system must have already been a red giant. This is because red giants are larger and more luminous than main sequence stars, which makes them easier to detect and study. When a red giant star exhausts its fuel, it starts to expand and cool, becoming a red giant. This expansion can cause the star to lose its outer layers, which can then be accreted by the white dwarf in the binary system.
In summary, for a nova to occur, the system must have already been a red giant, which then evolved into a binary system with a white dwarf star. This binary system then experiences a thermonuclear explosion on the surface of the white dwarf, causing the star to brighten significantly and become a nova.
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Which of the following is NOT true regarding the force arm of a lever?
A.Is determined by multiplying the distance from the axis by force
B.Also known as the moment or torque arm
C.Is the shortest distance from the axis of rotation to the line of action of the force
D.The greater the distance of the force arm then the more torque produced by the force
The answer is C. Is the shortest distance from the axis of rotation to the line of action of the force is NOT true regarding the force arm of a lever.
The force arm of a lever is the perpendicular distance between the axis of rotation and the line of action of the force. This distance is also known as the moment arm or torque arm. The force arm determines the torque produced by a force applied to a lever.
Option A is true, as the torque produced by a force is calculated by multiplying the force by the distance from the axis of rotation.
Option B is also true, as the force arm is also known as the moment arm or torque arm.
Option D is also true, as the greater the distance of the force arm, the greater the torque produced by the force.
Therefore, the answer is C.
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The angle of a body segment with respect to a fixed line of reference is known as a
Absolute angle
Joint angle
Relative angle
Joint angle. Joint angle refers to the angle formed between two body segments connected at a joint.
It represents the angular displacement of one segment with respect to another or a fixed line of reference. Joint angles are commonly used in biomechanics and motion analysis to study the movements of limbs and joints. They provide valuable information about the range of motion, position, and orientation of body segments during various activities. Measuring joint angles helps assess joint function, identify movement patterns, and evaluate joint stability, making it a fundamental concept in the field of human movement analysis.
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an object is dropped from rest from a height of 4 x 10^6 m above the surface of the earth. if there is no air resistance, what is its speed when it strikes the earth? 6950 m/s
The speed of an object dropped from rest from a height of 4 x 10^6 m above the surface of the Earth, with no air resistance, is approximately 6950 m/s.
When an object is dropped from rest and falls freely under the influence of gravity, it undergoes constant acceleration due to Earth's gravity. The acceleration due to gravity near the surface of the Earth is approximately 9.8 m/s². Using the equation of motion, v = u + at, where v is the final velocity, u is the initial velocity (0 m/s in this case), a is the acceleration due to gravity, and t is the time taken to fall, we can calculate the time taken to fall as follows:
4 x 10^6 m = 0.5 * 9.8 m/s² * t²
Simplifying the equation, we find t ≈ 2020.41 seconds.
Finally, using the equation v = u + at, we can calculate the final velocity:
v = 0 + 9.8 m/s² * 2020.41 s ≈ 19794.2 m/s ≈ 6950 m/s (rounded to three significant figures).
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T/F in a purely resistive circuit, 100% of the apparent power is used or consumed.
True. In a purely resistive circuit, the voltage and current are in phase with each other, meaning they reach their maximum and minimum values at the same time. This results in the power being entirely converted into useful work, and there is no reactive power or power dissipated as heat due to inductive or capacitive effects.
Therefore, all the power drawn by the load is utilized, and 100% of the apparent power is used or consumed. This is why resistive loads such as incandescent light bulbs are considered highly efficient as they do not waste any power.
However, in circuits with reactive components such as inductors and capacitors, the power factor becomes less than unity, and the apparent power becomes greater than the real power. This means that some of the power is being stored and returned to the source without doing any useful work, resulting in a loss of efficiency. In conclusion, in a purely resistive circuit, all the power is consumed, and there are no losses due to reactive effects.
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an fm radio station broadcasts at a frequency of 91.0 mhz . part a part complete what inductance should be paired with a 9.00 pf capacitor to build a receiver circuit for this station?
A 23.5 μH inductance should be paired with a 9.00 pF capacitor to build a receiver circuit for an FM radio station broadcasting at a frequency of 91.0 MHz.
To calculate the inductance needed to build a receiver circuit for an FM radio station, we can use the formula:
L = (1/4π²f²C)
where L is the inductance in Henries, f is the frequency in hertz, and C is the capacitance in farads.
Substituting the given values, we get:
L = (1/4π² x 91.0 MHz² x 9.00 pF)
Converting MHz to Hz and pF to F, we get:
L = (1/4π² x (91.0 x 10^6 Hz)² x (9.00 x 10^-12 F))
Simplifying the expression, we get:
L = 23.5 μH
Therefore, a 23.5 μH inductance should be paired with a 9.00 pF capacitor to build a receiver circuit for an FM radio station broadcasting at a frequency of 91.0 MHz.
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what is the frequency (s-1) of electromagnetic radiation that has a wavelength of 0.53 m?
The main answer to your question is that the frequency (s-1) of electromagnetic radiation with a wavelength of 0.53 m is approximately 5.66 x 10^8 s-1.
To provide an explanation, frequency and wavelength are inversely proportional to each other. This means that as the wavelength increases, the frequency decreases and vice versa.
The formula that relates frequency and wavelength is c = λν, where c is the speed of light (3 x 10^8 m/s), λ is the wavelength, and ν is the frequency.
To solve for frequency, we can rearrange the formula to ν = c/λ and plug in the given values.
Therefore, ν = 3 x 10^8 m/s ÷ 0.53 m = 5.66 x 10^8 s-1.
In summary, the frequency of electromagnetic radiation with a wavelength of 0.53 m is approximately 5.66 x 10^8 s-1.
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he mass on a spring mass system hangs motionless from the spring. when the mass is pulled down, the sum of the gravitational and elastic potential energies of the system does what?
The sum of gravitational and elastic potential energies of the system increases as the mass is pulled down in a spring-mass system.
When the mass is pulled down in a spring-mass system, two potential energies are at play: gravitational potential energy and elastic potential energy. Gravitational potential energy depends on the height of the mass above a reference point, while elastic potential energy is related to the displacement of the spring from its equilibrium position.
As the mass is pulled down, the gravitational potential energy increases because the height decreases. Simultaneously, the elastic potential energy increases because the spring is stretched or compressed further from its equilibrium position. Therefore, the sum of gravitational and elastic potential energies of the system increases when the mass is pulled down in a spring-mass system.
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Which of the following nuclei is likely to release energy when undergoing nuclear fusion?
a. iron-56
b. uranium-235
c. plutonium-239
d. deuterium
Deuterium is likely to release energy when undergoing nuclear fusion. Deuterium is an isotope of hydrogen that contains one proton and one neutron in its nucleus. Fusion occurs when two light nuclei, such as deuterium, combine to form a heavier nucleus, such as helium. This process releases a large amount of energy, which is the basis for how the sun and other stars produce energy.
Iron-56, uranium-235, and plutonium-239 are not likely to release energy through nuclear fusion. Iron-56 has the highest binding energy per nucleon, which means that it requires energy input to fuse with another nucleus. Uranium-235 and plutonium-239 undergo nuclear fission, which involves splitting a heavy nucleus into lighter nuclei and releasing energy.
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