What is the maximum velocity (in m/s) of electrons ejected from a material by 85 nm photons, if they are bound to the material by 4. 66 ev?

The electric potential at certain point is given by,v=-7.5x²-3x ,where v is in volts and x is in meters. then the electric field at that point is -(15x+3).

Given,

The electric potential at certain point is given by,

v=-7.5x²-3x .

where v is in volts and x is in meters.

We know,

electric potential (v) =electric field ×radius

Electric potential is defined as the amount of work needed to move a charge from reference point to the specific point against an electric field.

Also, electric field (E) =dv/dx

Electric field at a point is the force experienced by the unit positive charge placed at that point.

E=d(-7.5x²-3x)/dx=-15x-3

Thus ,the electric field at that point is given by -(15x+3 ).

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Disclaimer:the data in the question is incorrect .here is the complete question .

Question: the electric potential at a certain point is given by v=-(7.5x²+3x).where v is in volts and x is in meters.what is the electric field at that point?

A small fly of mass 0. 30 g is caught in a spider's web. the web oscillates predominantly with a frequency of 4.3 Hz. The value of the effective spring stiffness constant k for the web is 0.21 N/m

Frequency of the oscillation is the number of oscillation in per unit time. It's SI unit is Hertz or s⁻¹.

Spring stiffness constant k is a measure of the stiffness of spring.

The Frequency of the oscillation is given by the following formula:

f = [tex]\sqrt{k/4\pi m}[/tex]

where, f is the frequency of web

           k is the stiffness constant of web

            m is the mass of small fly

On rearranging the above equation,

k = 4π²f²m

⇒ k = 4 (3.14)² (4.3)² 0.0003

⇒ k = 0.21 N/m

Hence, the Stiffness constant k for the web is 0.21 N/m

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From the calculation, the horizontal distance is 310 m.

A projectile has to do with an object that is thrown at an angle. Now we know that the range of the projectile is given by the formula; R = u^2sin2θ/g

We we know that;

g = acceleration due to gravity

θ = angle

u = velocity

R = (60)^2 sin2(30)/10

R = 310 m

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The metallic radius (r) of au is 144.2pm

A face-centered cubic unit cell structure is made up of atoms arranged in a cube with six additional whole atoms placed in the centre of each cube face and a fraction of an atom at each of the cube's four corners. Eight additional unit cells share the atoms at the cube's corner.

Atoms in an FCC crystal are in contact along the unit cell's diagonal.          4r = √2 a, where r is the radius of an atom and a is the edge length of a unit cell.

Putting the values in the above expression,we get

r = √2×408 / 4

r = [tex]\frac{1.414*408}{4}[/tex]

r = [tex]\frac{576.9}{4}[/tex]

r = 144.2 pm

Therefore, The metallic radius (r) of au is 144.2pm

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The shortest wavelength in the paschen series= [tex]8.2\times 10^{-7}[/tex] m.

Emission lines for hydrogen occur when electrons drop from some energy level to a lower energy level. To calculate the shortest wavelength in the paschen series we are using the formula,

[tex]\frac{1}{\lambda} =R_{H} (\frac{1}{n_{f}^{2} }-\frac{1}{n^{2} } )[/tex]

Here, we are given,

[tex]R_{H}[/tex]= Rydberg constant=[tex]1.09737 \times 10^{7} m^{-1}[/tex]

[tex]n_f[/tex]= The lower energy level quantum number.=3 (for the paschen series).

n= The quantum number of whichever state the transitions occur from = (for this case of the paschen series).

We have to find the wavelength associated with the photon emitted = [tex]\lambda[/tex] m.

Now we substitute the known values in the above equation, we can find that,

[tex]\frac{1}{\lambda} =1.09737 \times 10^{7} (\frac{1}{3^2 }-\frac{1}{\infty^{2} } )[/tex]

Or,[tex]\frac{1}{\lambda} =1.09737 \times 10^{7}\times \frac{1}{9 }[/tex]

Or,[tex]\frac{1}{\lambda} =1,219,300[/tex]

Or,[tex]\lambda= 8.2\times 10^{-7}[/tex] m

From the above calculation we can conclude that the shortest wavelength in the paschen series is [tex]8.2\times 10^{-7}[/tex] m

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The magnitude of this vector is 15

A vector is a quantity or phenomenon that has two independent properties: magnitude and direction. The term also denotes the mathematical or geometrical representation of such a quantity. Examples of vectors in nature are velocity, momentum, force, electromagnetic fields, and weight.

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

Let vector be = a

component of vector in x direction = 10 i

component of vector in y direction = 10 j

component of vector in z direction = 5 z

vector a = 10 i + 10 j + 5 z

magnitude of vector a = |a| = [tex]\sqrt{10^{2} +10^{2} + 5^{2} }[/tex]

                                             = 15

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Moped riding represent angry customers in the model from the lesson.

Moped riding refers to the riding of a special type of small motorcycle, generally having a less stringent licensing requirement than full motorcycles or automobiles.

Generally, the word "moped riding" describes any two-wheeledth with a step-through chassis and footrest platform. These two-wheeled vehicle are usually equipped with bicycle-like pedals that the rider uses to propel the vehicles.

Although motorcycles are usually very harder to learn to ride

The following are other types of riders:

So therefore, moped riding represent angry customers in the model from the lesson.

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The annual cost of electricity is $28.908 .

work done is equal to energy consumed

therefore total energy is calculated as power times the duration of operation .

[tex]W=P.t[/tex]

where W= work done

            P=power

            t= time of operation

therefore,

total work done (W)=0.06×12×365 kw

=262.8 kw

so total annual electricity bill = 262.8×0.11

=$28.908

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A piece of purple plastic is charged with 3. 13×106 extra electrons compared to its neutral state, then the net electric charge in coulomb would be - 5.008×10⁻¹³ coulombs.

Charged material experiences a force when it is exposed to an electromagnetic field due to the physical property of electric charge. You can have a positive or negative electric charge (commonly carried by protons and electrons respectively). Unlike charges attract one another while like charges repel one another. We refer to an object as neutral if it has no net charge.

The charge on one electron is -1.6 ×10⁻¹⁹ coulomb.

Then the charge on the 3.13×10⁶ extra electrons compared to its neutral state

=-1.6×10⁻¹⁹ ×(3.13×10⁶)

As given in the problem A piece of purple plastic is charged with 3.13×10⁶ extra electrons compared to its neutral state then the net electric charge in coulombs would be - 5.008×10⁻¹³ coulombs.

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adp and pi are added to the external medium and the vesicles are exposed to light, The DNP will collapse the H+ gradient that ATP synthase uses to generate ATP.

ATP synthase is the enzyme that makes ATP molecules. It is a multi-part complex that straddles the inner membrane of mitochondria, the energy factories in cells. The enzyme complex interacts with fatty molecules in the mitochondrial inner membrane, creating a curvature that is required to produce ATP more efficiently.

ATP can be hydrolyzed to ADP and Pi by the addition of water, releasing energy. ADP can be "recharged" to form ATP by the addition of energy, combining with Pi in a process that releases a molecule of water.

The DNP will collapse the H+ gradient that ATP synthase uses to generate ATP. Each of the three respiratory enzyme complexes includes metal atoms that are tightly bound to the proteins.

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The wind velocity of the plane in discuss can be evaluated by means of the air velocity if the plane and the observed velocity is; 20.98m/s.

It follows from the task content that the air velocity of the plane in discuss is; 55.0 m/s [35o N of W] while the observed velocity is; 40.0 m/s [53o N of W].

Hence, the components of both velocities can be evaluated as follows;

55.0 m/s [35o N of W] = (55cos35, 55sin35) = (45.05, 31.55)

40.0 m/s [53o N of W] = (24.07, 31.95)

Hence, the wind velocity can then be evaluated as follows;

Wind velocity = (24.07 - 45.05, 31.95- 31.55)

Wind velocity = (-20.98, 0.40)

The wind velocity would therefore have a magnitude of; √(-20.98)² + (0.40)²

= 20.98 m/s.

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Hi there! Your answer is below.

Pulley sizes, cylinder size ratios, screw pitch, leverage, gear ratios, and pulley sizes

The MA increases yet the work takes longer to complete the farther the applied effort goes relative to the load. An excessive increase in the MA may be counterproductive.

Bicycle derailleurs are the most obvious example of variable MA.

Choose a low gear to climb hills more easily, but if you don't switch to another one on the flat, you'll be pedaling frantically and quickly getting nowhere. (Of course, you progress, but slowly.)

I frequently use bicycles as illustrations of intricate mechanics. They aren't actually toys at all!

Thank you,

Eddie

A passenger car traveling at 55 mph will take approximately 130 - 140 feet to brake to a complete stop.

Indiana is one of the states that compose the United States of America. We know that in the United States, the laws are different depending on the state in which a person resides and so does the the traffic laws and the driver's manual.

Generally, a driver ought to apply the brake a good distance away from the obstacle depending on the speed of the driver. We know that a higher speed immediately implies that the driver must start braking early enough.

Hence, according to the Indiana driver’s manual, a passenger car traveling at 55 mph will take approximately 130 - 140 feet to brake to a complete stop.

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The speed of light in crown glass with the index of refraction is 1.97×10^8 m/s.

Given index of refraction= 1.52

          speed of light in vaccum= 3×10^8 m/s

           speed of light in medium=c/n= 3×10^8/1.52= 1.97×10^8 m/s  

About  index of refraction:

The ratio of the speed of light in a vacuum to that in a second medium with a higher density is used to compute the refractive index (also known as the index of refraction). In mathematical formulae and descriptive writing, the letter n or n' is most frequently used to represent the refractive index variable.

The index of refraction controls how much light is refracted or twisted when it enters a substance.

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An ECG does not show atria repolarization.

To find the answer, we need to know more about the electrocardiogram.

Thus, we can conclude that, the option d is correct.

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The angular momentum of the tire is 0.394KGm^2/s.

To find the answer, we have to know more about the angular momentum.

                             [tex]L=mvr[/tex]

where, m is mass of th body, v is the linear velocity and r is the radius of the circular orbit.

                 [tex]m=1.4kg\\r=33*10^{-2}m\\w=155rpm=2.58rps[/tex]

                   [tex]v=rw=33*10^{-2}*2.58=0.85m/s[/tex]

                  [tex]L=mvr=1.4*0.85*33*10^{-2}=0.394Kgm^2/s[/tex]

Thus, we can conclude that, the angular momentum of the tire is 0.394KGm^2/s.

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The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m

Explanation:

Let's solve this problem in parts

let's start by finding the intensity of the sound in each observer

observer A β = 59 db

            β = [tex]10 log\frac{I_a}{I_o}[/tex]

where I₀ = [tex]1 \times 10^{-12}[/tex]  W / m²

             [tex]I_a = I_b \times 10 ^{ \frac{\beta}{10} }[/tex]

             [tex]I_a = 1\times 10 ^{-12} \times 10 ^{ \frac{59}{10} }[/tex]

             [tex]I_a[/tex] = [tex]2.51 \times 10 ^{-6}[/tex] W / m²

Similarly for Observer b [tex]I_b = 3.16 \times 10 ^ {-4}[/tex]

now we use that the emitted power that is constant is the intensity over the area of ​​the sphere where the sound is distributed

P = I A

therefore for the two observers

the area of ​​a sphere is

[tex]A= 4\pi \times r^2[/tex]

we substitute the above formula, we get

Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute

            [tex]I_a (35 -x) ^2 = I_b x^2[/tex]

after solving the above equation we get  x = 28.64 m

This is the distance of observer A

similarly The distance from observer B is 35 - x

= 40 - 28.64

= 11.36m

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The wavelengths of these signals is between  187.50m to 2.77 m.

Frequency describes the number of waves that skip a set region in a given quantity of time. There are two forms of frequency desk - Grouped Frequency Distribution and Ungrouped Frequency Distribution.

Wavelength is normally denoted with the aid of the Greek letter lambda (λ); it is identical to the velocity (v) of a wave train in a medium divided by means of its frequency (f)= λ = v/f.

Part A)

λ max = v / f

= 3 x 10^8 / 550x10^3 =545.45 m

λmin = 3 x 10^8 / 1600x10^3 = 187.50m

Part B)

λ max = v / f

= 3 x 10^8 / 88x10^6

 = 3.41 meters

λmin = 3 x 10^8 / 108x10^6 = 2.77 m

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The vector u represents the sum of two orthogonal vectors, and which can be written as,

[tex]u=Proj_vu+(u-Proj_vu)[/tex].

To find the answer, we have to know about the projection of vectors.

                               [tex]Proj_v u=\frac{u.v}{v.v} v[/tex]  (inner product)

              [tex]u=(u_1,u_2)\\v=(v_1,v_2)[/tex]    then, projection of u on v is,

                              [tex]Proj_vu=\frac{u_1v_1+u_2v_2}{v_1v_1+v_2v_2} (v_1,v_2)[/tex]

                 [tex]u=Proj_vu+(u-Proj_vu)[/tex]

Thus, we can conclude that, the vector u represents the sum of two

orthogonal vectors, and which can be written as,

[tex]u=Proj_vu+(u-Proj_vu)[/tex].

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The value is equal to 18.26*10^6 dollars/ounces.  

To find the answer, we have to know about the Cullinan diamond.

                     [tex]21.9 Ounce= 621.35g=400*10^6 dollars\\\\value=\frac{400}{21.9} *10^6dollars/ounce=18.26*10^6dollars/ounce[/tex]

Thus, we can conclude that, the value is equal to 18.26*10^6dollars/ounces.                  

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kinetic energy 8.0 s later will be 11.35 joules

Given:

inertia,I=0.034kgm²

torque,τ=0.11nm

time,t=8.0s

To find:

kinetic energy,KE

we can find the kinetic energy by using

[tex]k = \frac{1}{2} iω {}^{2} [/tex]

so firstly we will find ω by finding α

α=τ/I

α=0.11/0.34

=3.23

then we find ω

ω=α×t

=3.23×8

=25.84

[tex]k = \frac{1}{2}iω {}^{2} [/tex]

k=1/2×0.34×(25.84)2

=1/2×22.70

k=11.35

so kinetic energy is 11.35 joules

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The separation between the two slits, d is related to the wavelength, and angle using the formula below. Hence, the value of d is 1.22 x 10⁻⁶ m.

For ease of calculations we take 29.8° = 30°

Using the relation :

[tex]\frac{m * λ }{sin\theta}[/tex]

where :

d = distance between the slits

θ = 30°

λ = wavelength of light = 617 nm = 6.17 x 10⁻⁷ m

m = 1

Substituting the values into the equation :

d = 1 x 6.17 x 10⁻⁷ / 0.5 = 0.00000122 = 1.22 x 10⁻⁶ m

Therefore, the seperation between the two slits is 1.22 x 10⁻⁶ m.

The double-slit experiment is a demonstration that light and matter can display characteristics of both classically defined waves and particles; moreover, it displays the fundamentally probabilistic nature of quantum mechanical phenomena.

This type of experiment was first performed, using light, by Thomas Young in 1802, as a demonstration of the wave behavior of light. At that time it was thought that light consisted of either waves or particles.

With the beginning of modern physics, about a hundred years later, it was realized that light could in fact show behavior characteristic of both waves and particles. Young's experiment with light was part of classical physics long before the development of quantum mechanics and the concept of wave–particle duality.

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Overhead is applied to work in process based on the predetermined rate times standard activity allowed in a standard costing system.

A standard cost is a fixed price per unit of direct materials, fixed price per direct labour hour, and fixed price per hour of overhead that is based on predicted quantities of direct materials and projected direct labour time.

Top management may find a standard cost system useful for planning and decision-making. easier and more reasonable inventory measurements. Compared to an actual cost system, a standard cost system makes inventory valuation simpler. Unit costs for batches of identical products may differ significantly under an actual cost system.

Therefore,Overhead is applied to work in process based on the predetermined rate times standard activity allowed in a standard costing system.

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Answer:

focal length

Explanation:

This describes focal length of the beam

Homo erectus’s cranial capacity -  ranges from 650 cc to 1,200 cc.

Homo erectus, an extinct species of Pleistocene archaic human, first appeared about 2 million years ago. The earliest known early human with dimensions similar to modern humans, including relatively long legs and small arms compared to the size of the torso, is Homo erectus. An extinct species of hominin that existed between 1.9 million and 135,000 years ago is known as homo Erectus.

The Homo erectus had certain ape-like characteristics, including huge teeth and a hefty jaw. They hunted and ate cooked meat, and they used fire. After closer inspection, it was discovered that the species' teeth showed signs of a diversified diet that included meat intake.

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The optimum wavelength is 450 nm because that is the wavelength of maximum absorbance by FeSCN2+(aq)

you should choose a wavelength with maximum absorbance. In this case, you are using the scattered light, not the absorbed light as your signal. So you should avoid wavelengths where there are absorption peaks.

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in metres (m), centimetres (cm), or millimetres (mm) (mm).

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Its average speed will be 25 m/s approximately. The correct answer is option C

Average speed is the ratio of total distance travelled to the total time taken. It is a scalar quantity and the S.I unit is m/s

Given that a car travels one third of a path with speed of 50 m/s and two third of path with 20m/s.

If the car travels one third of a path with speed of 50 m/s, then the time taken will be

Speed = distance / time

Time = distance / speed

Time = 1/3 ÷ 50

Time = 6.67 x [tex]10^{-3}[/tex] s

If the car travels the remaining two third of a path with speed of 20 m/s, then, the time taken will be

Time = distance / speed

Time = 2/3 ÷ 20

Time = 0.0333

Total time = 0.03333 + 0.00667

Total time = 0.04

The total distance travelled = 1

Average speed = Total distance travelled ÷ Total time

Average speed = 1/0.04

Average speed = 24.99979 m/s

Therefore, its average speed will be 25 m/s approximately.

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The Inverse Square Law applies to Radiation. It states that the intensity of any radiation source is inversely proportional to the square of the distance from the source.

I would rather call it “an inverse square law”. Some things vary inversely as the square of something (usually distance) and some things don’t.

For instance, the quantity of light energy per second falling on a tiny area* is inversely related to the square of the distance from the source if a point light source emits light uniformly in all directions. The energy per second will decrease by four times with every twofold increase in distance for a certain area, and nine times with every threefold increase in distance. (Ideally, the area should be a sphere centered on the point source to make the distance clear; nonetheless, an approximate solution is a tiny plane area perpendicular to the line from the point source.) Therefore, light obeys the inverse square law (at least in Euclidean space).

The gravitational and electrical forces are some examples of entities that adhere to the inverse square law. On the other hand, gravitational and electrical potentials adhere to an inverse rule, whereby the potential must be reduced by a factor of two times the distance.

Thank you,

Eddie

The inverse square law states that the intensity or strength of a physical quantity decreases in proportion to the square of the distance from the source.

The inverse square law is expressed as:

Intensity = k / (distance)²

As you walk further from the source, the light from a point source loses intensity as it spreads out across a wider region.

The square of the distance between two objects' centers determines how much gravity there is between them. The gravitational pull between two things lessens as they are pulled apart more.

As you get further from the source of the music, the sound waves become less intense.

Inverse square law governs the strength of the magnetic and electric fields surrounding a charged particle or a wire carrying current.

An important tenet of physics is the inverse square law, which can be used to explain a variety of natural events.

Therefore,  the intensity or strength of a physical quantity decreases in proportion to the square of the distance from the source.

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Answer:

300 Pa

Explanation:

P=F/A

= 900/3

= 300 Pa