What is the measure of each angle in a regular 18-gon? If necessary, round your answer to the nearest tenth.

The completed statements with regards to the projectile motion of the football are presented as follows;

This graph is a nonlinear function

The hang time of the football is 3 seconds

The football reaches its maximum height when t = 1.5 seconds

The maximum height is about 11 meters

For t between t = 0 and t = 1.5, the height is increasing

The motion of a projectile is one that involves an object thrown into the air or into space, which is acted upon by only gravitational force.

The graph in the question, showing the scale on the x-axis obtained from a similar question on the internet, indicates that we get;

The x-intercept of the graph are; (0, 0), and (3, 0)

Therefore;

The time the football is in the air, which is the hang time of the football can be obtained from the difference between the x-values of the x-intercept as follows;

Hang time = 3 - 0 = 3

The graph indicates that the coordinates of the maximum height is (1.5, 11). Therefore;

The height at t = 0 is 0 meters, and the height at t = 1.5 seconds is 11 meters, therefore; the height is increasing between t = 0 and t = 1.5 seconds

For t between t = 0 and t = 1.5, the height is increasing

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Answer:

Nonlinear

3

1.5

11

increasing

Step-by-step explanation:

The values of f and g based on the given diagram ABCE is 6cm and 8cm respectively.

Area of ABCE = 60cm²

Area of ABCD = 48cm²

Area of ADE = Area of ABCE - Area of ABCD

= 60 cm² - 48 cm²

= 12 cm²

Area of ADE = 1/2 × base × height

12 = 1/2 × 4 × h

12 = 4/2h

12 = 2h

divide both sides by 2

h = 12/2

h = 6 cm

AD = height = BC = 6 cm

Area of ABCD = length × width

48 = l × 6

48 = 6l

l = 48/6

l = 8 cm

In conclusion, f and g are 6cm and 8cm respectively.

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Answer: To solve this problem, we can use the formula for calculating the future value of an investment:

FV = PV * (1 + r/n)^(nt)

where:

FV is the future value of the investment

PV is the present value of the investment (the initial amount Louise has to invest)

r is the annual interest rate (4.28%)

n is the number of times the interest is compounded in a year

t is the number of years the investment is made

Since the interest is compounded monthly, we need to convert the annual interest rate to a monthly rate:

r/12 = 4.28% / 12 = 0.3566666666666667%

Now, we can use the formula to calculate the future value of Louise's investment:

FV = $20,000 * (1 + 0.3566666666666667%)^(12t)

We can use trial and error or iterative methods to find the value of t that satisfies the condition: FV = $30,000.

A quick approximation is to use the formula for simple interest:

FV = PV * (1 + r * t) = $20,000 * (1 + 0.0428 * t)

t = ($30,000 - $20,000) / ($20,000 * 0.0428) = 2.857142857142857 years, or approximately 2.9 years.

This is an approximation, but it should be close to the actual answer. To get a more accurate answer, we can use an iterative method, such as Newton-Raphson or bisection, to solve for t in the formula above.

Step-by-step explanation:

Answer:

2 • (10ab + 35a - 12b2 - 42b)

Step-by-step explanation:

(20ab + 70a - 84b) - (23•3b2)

20ab + 70a - 24b2 - 84b =

2 • (10ab + 35a - 12b2 - 42b)

The length of B'C' after the translation of the original object is; B'C' = 3 units

Translation in transformation is simply defined as the displacement of a figure or a shape from one place to another. In translation, a figure can move upward, downward, right, left or anywhere in the coordinate system. In translation, only the position of the object changes, its size remains the same.

Now, from the attached image, we see that;

AB = 7 units

BC = 3 units

CD = 4 units

DA = 5 units

Now, by virtue of the definition of translation, it means that the translated object will retain the same dimensions. Thus;

B'C' = 3 units

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To convert milligrams per liter (mg/L) to micrograms per fluid ounce (µg/fl oz), we can use the conversion factor of 29.5735.

This conversion factor takes into account the difference in volume between a liter and a fluid ounce.

1 fl oz = 29.5735 mL

1 L = 1000 mL

So, to convert from milligrams per liter to micrograms per fluid ounce, we divide by 29.5735 and multiply by 1000:

(mg/L) * 1000 / 29.5735 = (µg/fl oz)

Therefore, to convert a value x from milligrams per liter to micrograms per fluid ounce:

x (µg/fl oz) = x (mg/L) * 1000 / 29.5735

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The scale factor is found dividing one side length of the right triangle on the right by the equivalent side length on the right triangle on the left.

A dilation happens when the coordinates of the vertices of an image are multiplied by the scale factor, changing the side lengths of a figure.

For this problem, we have that the original and the dilated figures are given as follows:

Hence the scale factor is found dividing one side length of the right triangle on the right by the equivalent side length on the right triangle on the left.

The problem is incomplete, hence the general procedure to obtain the scale factor was presented.

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The length of the hypotenuse BC in right  angled triangle ABC is 3.605 units.

A triangle is said to be right angled if one of its inner angles is 90 degrees, or if any one of its angles is a right angle. Consequently, other names for this triangle include the right triangle and 90-degree triangle.

In right angle triangle if 90 degree angle is A then

[tex]AB^{2} +AC^{2} = BC^{2}[/tex]

And here length of altitude AB equals to 3 units and length of base  AC equals to 2 units And here length of hypotenuse BC equals to [tex]\sqrt{13}[/tex] units

[tex]AB^{2} +AC^{2} = BC^{2}[/tex]

[tex]3^{2} +2^{2} = \sqrt{13}[/tex]

[tex]\sqrt{13}[/tex]= 3.60555 unit

And here ans [tex]\sqrt{13}[/tex] is already give what we have to do just calculate the value of [tex]\sqrt{13}[/tex] which is = 3.605

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By knowing the five number summary of a data set, we can make inferences about the location of specific percentiles within the data.

The five number summary is a way to summarize the distribution of a set of data by providing information about its minimum, first quartile (25th percentile), median (50th percentile), third quartile (75th percentile), and maximum. Using this summary, we can infer information about the location of specific percentiles.

For the 20th percentile, we can conclude that it lies between the minimum and the first quartile. The 20th percentile represents the value below which 20% of the data falls, so it must be less than or equal to the first quartile, which is the value below which 25% of the data falls. It must also be greater than or equal to the minimum.

For the 90th percentile, we can conclude that it lies between the third quartile and the maximum. The 90th percentile represents the value below which 90% of the data falls, so it must be less than or equal to the maximum, which is the largest value in the data set. It must also be greater than or equal to the third quartile, which is the value below which 75% of the data falls.

In conclusion, by knowing the five number summary of a data set, we can make inferences about the location of specific percentiles within the data.

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The dilated quadrilateral is A' ( -2 , 4 ) , B' ( 4 , 4 ) , C' ( 6 , -2 ) and D' ( 0 , -2 )

Resizing an item uses a transition called Dilation. Dilation is used to enlarge or contract the items. The result of this transformation is an image with the same shape as the original. However, there is a variation in the shape's size. Dilation transformations ensure that the shape will stay the same and that corresponding angles will be congruent

Given data ,

Let the quadrilateral be represented as ABCD

Now , the coordinates of ABCD is given as

A ( -1 , 2 ) , B ( 2 , 2 ) , C ( 3 , -1 ) and D ( 0 , -1 )

Now , when the dilation is of the scale of (x,y) → (2x, 2y) about the origin

Substituting the values in the equation , we get

A' ( x , y ) = A ( 2 ( -1 ) , 2 ( 2 ) )

On simplifying the equation , we get

The coordinates of A' is = A' ( -2 , 4 )

The coordinates of B' is = B' ( 4 , 4 )

The coordinates of C' is = C' ( 6 , -2 )

The coordinates of D' is = D' ( 0 , -2 )

Hence , the dilated figure is solved

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Answer:

Below

Step-by-step explanation:

rate X time = distance

rate  = distance / time    <=====we want minimum of this so make denominator as large as possible and numerator as small as possible

      distance = 595  KM    ( rounds up to 600 km)

        time = 8 hr 44 min  rounds down to 8 :40    you could make it 8:44.99)

595 km / (8 + 44.99/60) hr  = 68 km/hr

The arrow labeled C represents a transfer of chemical energy to mechanical energy. False, this is because, the gas released does not do any work.

The arrow labeled A represents a transfer of solar energy to chemical energy. True, chemical energy is stored in starch molecules

The arrows that represent the release of carbon dioxide is C. This is combustion and it occurs in nonliving things. The process involves the burning of carbon materials.

The conservation energy is demonstrated by arrow A since we can show it by a chemical reaction.

The carbon cycle is the process by which carbon atoms circulate through the Earth's atmosphere, oceans, and landmasses. In the carbon cycle, carbon is exchanged between the atmosphere, biosphere, hydrosphere, and geosphere. The main components of the carbon cycle include photosynthesis, cellular respiration, decomposition, and combustion.

In photosynthesis, plants take in carbon dioxide from the atmosphere and convert it into organic compounds, which serve as food for the plants and are stored in their tissues.

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(a) The number of possible schedules that the student can create from the offerings is 96.

(b) the number of possible schedules that the student can create from the offerings if two of the math 100 sections are closed is 48.

(c) the number of possible schedules that the student can create from the offerings if two of the math 100 sections and four of the English 105 sections are closed is 4.

(a) To find the total number of possible schedules, we need to multiply the number of choices for each class:

Number of schedules = 4 x 2 x 3 x 4 = 96

So, there are 96 possible schedules that the student can create from the offerings.

(b) If two of the math 100 sections are closed, then there are only two choices for that class. So, we have:

Number of schedules = 2 x 2 x 3 x 4 = 48

So, there are 48 possible schedules that the student can create from the offerings with two of the math 100 sections closed.

(c) If two of the math 100 sections and four of the English 105 sections are closed, then there are only two choices for math 100 and one choice for English 105. So, we have:

Number of schedules = 2 x 2 x 1 x 1 = 4

So, there are 4 possible schedules that the student can create from the offerings with two of the math 100 sections and four of the English 105 sections closed.

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The expression equivalent to  -2x +3+ 7y + 4x -5 is 2x+7y-2.

What exactly are expressions?

Expressions in mathematics are mathematical assertions that comprise at least two phrases that contain numbers, variables, or both, and are connected by an operator in between. Addition, subtraction, multiplication, and division are examples of mathematical operators. For example, x + y is an expression in which x and y are terms separated by an addition operator. There are two sorts of expressions in mathematics: numerical expressions, which include simply numbers, and algebraic expressions, which contain both numbers and variables.

e.g. A number is 6 more than half of another number, which is x. In a mathematical expression, this proposition is expressed as x/2 + 6. Complex riddles are solved using mathematical expressions.

Now,

Given expression is   -2x +3+ 7y + 4x -5

writing same terms together

=4x-2x+7y+3-5

=2x+7y-2

hence,

             The expression equivalent to  -2x +3+ 7y + 4x -5 is 2x+7y-2.

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Answer:

13 situps per day

Step-by-step explanation:

To find the number of situps per day, take the total number of situps and divide by the number of days.

39/3

13 situps per day

Shawna's new score can be represented by the equation is New Score = Current Score + (Result of Black Cube) + (Result of Red Cube). So, Shawna's new score is 2.

In the game that Shawna is playing, rolling the black cube results in a positive number, while rolling the red cube results in a negative number. We are told that Shawna's current score is 4, which means that she has accumulated 4 points up to this point in the game.

Next, we are told that Shawna rolls a red 5 and a black 3. This means that the red cube resulted in a negative 5 and the black cube resulted in a positive 3.

To calculate Shawna's new score, we can add the results of these two rolls to her current score. However, we need to be careful to subtract the negative number, rather than adding it. This is because a negative number is actually a decrease in score.

Therefore, we can use the following equation to calculate Shawna's new score:

New Score = Current Score + (Result of Black Cube) + (Result of Red Cube)

Substituting in the values that we know, we get:

New Score = 4 + 3 + (-5)

Simplifying, we can combine the positive and negative numbers:

New Score = 4 - 2

Therefore, Shawna's new score is 2. This means that after rolling a red 5 and a black 3, her score has decreased by 2 points from her original score of 4.

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Susan predicts that private school pupils will perform better than the general populace. The best description for this type of test is a right-tailed test.

In this scenario, Susan is testing the hypothesis that the mean score of the students of the private school is greater than 572, which is the mean score of the general population. This type of test, where the alternative hypothesis is "greater than" a specified value, is known as a right-tailed test or a one-tailed test (since the test is only considering one direction of deviation from the null hypothesis).

So the correct answer is d) a right-tailed test or a one-tailed test.

The complete question is:-

Susan hypothesizes that the students of a private school will score higher than the general population. Susan records a sample mean equal to 578 and states the hypothesis as μ= 572 vs μ>572. Select the best description for this type of test. a.) lower-tailed test b.) left-tailed test c.) two-tailed test d.) right-tailed test.

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For given linear equations, 27hx -9y = -18 and y = 1 - 6x

h will be 2.

What is a linear equation, exactly?

When the greatest power of a variable is 1, the equation is said to be linear. Another term for it is a one-degree equation. The standard form of a linear equation with one variable is Ax + B = 0. There are three variables in this equation: x, A, and B. A denotes a coefficient. A linear equation with only two variables is commonly written as Ax + By = C. There are three more constants in addition to the constant C: the variables x and y, the coefficients A and B, and the variables.

Now,

As general equation of a line is y=mx + c where m=slope and c=constant

and here given lines are  27hx -9y = -18 and y = 1 - 6x

transforming these into general equations

y=-3hx+2 where m=-3h

and y=-6x+1    where m=-6

Now As slope of parallel lines is equal

therefore, -3h=-6

h=6/3

h=2

Hence,

           h will be 2.

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The lower quartile is 2, the median is 5 and the upper quartile is 8.

What are quartiles?

The values that divide a list of numerical data into three quarters are known as quartiles.

We are given a data set as 1, 2, 3, 5, 5, 8, 8

From this, we get the median as 5 as median is the middle number of the data set.

We know that lower quartile is the median of the lower half of the data.

So, lower quartile is 2.

Upper quartile is the median of the upper half of the data.

So, upper quartile is 8.

Hence, the lower quartile is 2, the median is 5 and the upper quartile is 8.

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Events Q and R are not mutually exclusive, thus we are given two probabilities, P(Q) = 0.41 and P(R) = 0.44.

Therefore,

Events Q and R are not mutually exclusive, thus we are given two probabilities, P(Q) = 0.41 and P(R) = 0.44.. In this instance, the likelihood of Q and R is equal to P(Q) × P(R), which is 0.1804. The solution to this issue is this.

The complete question is:

Suppose Q and R are independent events. Find the probability of Q and R when P(Q)=0.41 Ans P(R)=0.44.

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Answer:

true

the t-value does change depending on the number of data points collected.

It is true that the t-value can change depending on the number of data points collected.

The t-value is a statistic used in hypothesis testing to determine whether a sample mean is significantly different from a population mean.

The formula for calculating the t-value includes the sample size (n) in the denominator, which means that as the sample size increases, the t-value decreases (assuming all other factors remain constant).

In other words, a larger sample size will generally result in a smaller t-value, which in turn may affect the interpretation of the results of a hypothesis test. Therefore, the t-value can change depending on the number of data points collected.

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Answer:

60

Step-by-step explanation:

3.92 = (6.56/100) * _

To solve for _, we can multiply both sides by 100:

100 * 3.92 = (6.56/100) * _

100 * 3.92 = 6.56 * _

_ = (100 * 3.92) / 6.56

Therefore, _ = 60.

Answer: 60

Step-by-step explanation:

Answer:

A

Step-by-step explanation:

(f - g)(x)

= f(x) - g(x)

= 3x + 2 - (2x - 2) ← distribute parenthesis by - 1

= 3x + 2 - 2x + 2 ← collect like terms

= x + 4

Shandra is expected to select a pineapple chew about 56 times in the next 400 selections.

Based on the given results, Shandra selected a pineapple chew 8 times out of 57 selections. To estimate the expected number of times she would select a pineapple chew in the next 400 selections, we can use the proportion of pineapple chews selected in the first 57 selections:

The proportion of pineapple chews selected = 8/57

To estimate the expected number of pineapple chews in the next 400 selections, we can multiply the proportion by the total number of selections:

Expected number of pineapple chews in the next 400 selections = (8/57) x 400

expected number of pineapple chews in the next 400 selections = 56.14

Rounding to the nearest whole number, we would expect Shandra to select a pineapple chew about 56 times in the next 400 selections.

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A line of reflection in a triangle can be any line that acts as a mirror image, such that the reflected image of the triangle is congruent to the original triangle.

This line is perpendicular to the plane of the triangle and bisects the angle between the two sides that are being reflected.

To be sure that each point was reflected across this line, we apply the reflection rule.

The reflection rule states that the distance from a point to the line of reflection is equal to the distance from its reflection to the line of reflection. This ensures that the reflected image of the triangle is congruent to the original triangle.

In an isosceles right triangle, two of its sides are congruent. This means that it satisfies the Angle-Side-Angle (ASA) congruence theorem. The ASA theorem states that if two triangles have two congruent angles and a congruent side between them, then the two triangles are congruent.

In addition to satisfying the ASA congruence theorem, an isosceles right triangle also satisfies the Pythagorean theorem. The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the side opposite the right angle) is equal to the sum of the squares of the lengths of the other two sides.

Finally, the reflection of a triangle is considered a rigid motion, as it preserves the size and shape of the triangle.

Rigid motions do not change the lengths of the sides or the angles between them. They only change the position of the triangle in space. In the case of reflection, the triangle is flipped over the line of reflection, but its size and shape remain unchanged

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Isosceles Right Triangle Reflection to prove ASA Congruence

Answer the following questions:

What line of reflection did you choose for your transformation?

How are you sure that each point was reflected across this line?

What reflection rule did you apply to your triangle?

What other properties exist in your triangle? Discuss at least two theorems you learned about in this module that apply to your triangle. Make sure to show evidence by discussing your triangle's measurements.

Did your triangle undergo rigid motion? Explain why.

The expression equivalent to (-√8 -√2) + √-36 is -3√2 + 6i.

A real number and an imaginary number are effectively combined to create a complex number. The complex number is written as a+ib, where a and ib are real and imaginary numbers, respectively. Additionally, I = -1 and both a and b are real numbers.

Consequently, a complex number is a straightforward illustration of the addition of two integers, specifically a real number and an imaginary number. It consists of two parts: one that is entirely real, the other entirely fantastical.

The given expression is:

(-√8 -√2) + √-36

The expression can be written as:

(-2√2 - √2) + √(i)²(6)²

Taking the common term:

√2(-2 - 1) + 6i

Simplifying the expression:

-3√2 + 6i

Hence, the expression equivalent to (-√8 -√2) + √-36 is -3√2 + 6i.

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The required, approximate volume of the sphere is 113.04 cubic inches.

Volume is defined as the mass of the object per unit density while for geometry it is calculated as profile area multiplied by the length at which that profile is extruded.

Here,
The formula for the volume of a sphere is V = (4/3)πr³, where r is the radius of the sphere.

If the radius of the sphere is 3 inches, we can substitute this value into the formula and use 3.14 to approximate π,

V = (4/3) x 3.14 x 3³

V = (4/3) x 3.14 x 27

V = 113.04 cubic inches

Therefore, the approximate volume of the sphere is 113.04 cubic inches.

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There are 11 observations in the subset data.e need to count the number of observations in the subset data.

1. First, we need to filter out the observations that have a date on or after May 1, 1975. For this, we can use the following code:

x3[x3$DATE >= "1975-05-01",]

2. Then, we need to count the number of observations in the subset data. We can do this by using the nrow() function:

nrow(x3[x3$DATE >= "1975-05-01",])

The output is 11.

If we wanted to subset the data set to include only observations that have a date on or before February 1, 1985, we can use the following code:

x3[x3$DATE <= "1985-02-01",]

Then, we can count the number of observations in the subset data usingthe nrow() function:

nrow(x3[x3$DATE <= "1985-02-01",])

The output is 19.

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