Answer:
this is your answer i hope it will help you if this answer is right then folow meChromatography can be quantitatively found by the retention factor. Therefore, the important criterion to use chromatography for separating components of a mixture is the difference in solubility of the liquids.
. Which substance corrodes steel wool the most?
A. salt
B. acid
C. base
D. tap water
Answer:
A. Salt, hope its helped
ionisation potential of the element increases across a period from left to right
Answer:
False
Explanation:
It actually decreases.
Which statement is the best description of a chemical bond
Liquid octane (CH3(CH2)CH3) reacts with gaseous oxygen gas(O2) to produce gaseous carbon dioxide(CO2) and gaseous water (H2O). What is the theoretical yield of carbon dioxide formed from the reaction of 27.4g of octane and 77.8g of oxygen gas?
Answer:
The theoretical yield of carbon dioxide formed is 68.4 grams CO2
Explanation:
Step 1: Data given
Liquid octane = C8H18
gaseous oxygen gas = O2
gaseous carbon dioxide = CO2
gaseous water = H2O
Mass of octane = 27.4 grams
Molar mass of octane = 114.23 g/mol
Mass of oxygen = 77.8 grams
Molar mass of oxygen = 32.0 g/mol
Step 2: The reaction
2C8H18(l) + 25O2(g) → 16CO2(g) + 18H2O(g)
Step 3: Calculate number of moles
Moles = mass / molar mass
Moles of octane = 27.4 grams / 114.23 g/mol
Moles of octane = 0.240 moles
Moles of oxygen = 77.8 grams / 32.0 g/mol
Moles of oxygen = 2.43 moles
Step 4: Calculate the moles of the products
For 2 moles of octane we need 25 moles of O2 to produce 16 moles of CO2 and 18 moles H2O
O2 is the limiting reactant. It will completely react. (2.43 moles).
There will react 2.43/12.5 = 0.194 moles
There will remain 0.240 - 0.194 = 0.046 moles of octane.
There will be produced:
16/25 * 2.43 = 1.555 moles of CO2
18/25 * 2.43 = 1.750 moles of H2O
This is:
1.56 moles * 44.01 g/mol = 68.4 grams CO2
1.750 moles * 18.02 g/mol = 31.5 grams H2O
The theoretical yield of carbon dioxide formed is 68.4 grams CO2
If the elements W, X, Y, and Z have electronegativity values of 1.0, 2.0, 2.5, and 3.5, respectively, which bond is the least polar
Answer:
XY bond is the least polar
Explanation:
Given
[tex]W = 1.0[/tex]
[tex]X = 2.0[/tex]
[tex]Y = 2.5[/tex]
[tex]Z = 3.5[/tex]
Required
The least polar bond
First, we calculate the difference in the electronegativities
[tex]WX = X - W[/tex]
[tex]WX = 2.0 - 1.0[/tex]
[tex]WX = 1.0[/tex]
[tex]WY = Y - W[/tex]
[tex]WY =2.5 - 1.0[/tex]
[tex]WY =1.5[/tex]
[tex]WZ =Z-W[/tex]
[tex]WZ =3.5 - 1.0[/tex]
[tex]WZ =2.5[/tex]
[tex]XY = Y -X[/tex]
[tex]XY = 2.5 -2.0[/tex]
[tex]XY = 0.5[/tex]
[tex]XZ = Z -X[/tex]
[tex]XZ = 3.5 -2.0[/tex]
[tex]XZ = 1.5[/tex]
[tex]YZ = Z - Y[/tex]
[tex]YZ = 3.5 - 2.5[/tex]
[tex]YZ = 1.0[/tex]
The least of the above calculations will be the least polar.
Hence, XY is the least polar
Which of the following is the empirical formula for C4H8?
A. CH4
B. C6H6
C. C2H2
D. CH2
describe the formation of ionic bonds in potassium chloride compound (5 marks)
Answer:
When the two atoms are in contact, potassium readily transfers its outer electron to chlorine which readily accepts it, resulting in both atoms achieving a state of eight outermost electrons. With this electron transfer, the ionic bond in KCl is formed.
convert 256 ml to kl
Answer:
0.000256
Explanation:
Formula:
Divide the value volume by 1e+6
1 kl equal to 1000000ml
Read the temperatures shown to the nearest 0.5°C.
I’ll mark you as brainlister
Answer:
The temperature to the nearest 0.5°C is 98.5°C
Calculate the average atomic mass element X
Answer:
39.02 amu
Explanation:
The average atomic mass of an element can be calculated as follows :
[tex]X=\dfrac{9.67\times 38+78.68\times 39+11.34\times 40+0.31\times 41}{100}\\\\X=\dfrac{3902.29}{100}\\\\X=39.02\ amu[/tex]
So, the atomic mass of the element X is 39.02 amu.
Calculate the average atomic mass for element X
Answer:
39.02amu
Explanation:
According to this question, there are four (4) isotopes for element X with the following relative abundance:
Isotope 1 = 9.67%, mass no: 38
Isotope 2 = 78.68%, mass no: 39
Isotope 3 = 11.34%, mass no: 40
Isotope 4 = 0.31%, mass no: 41
To find the average atomic mass of element X, we multiply each isotopes' relative abundance by its mass no and find the sum as follows:
We convert each percentage to decimal abundance:
Isotope 1 = 9.67% = 0.0967
Isotope 2 = 78.68% = 0.7868
Isotope 3 = 11.34% = 0.1134
Isotope 4 = 0.31% = 0.0031
(0.0967 × 38) + (0.7868 × 39) + (0.1134 × 40) + (0.0031 × 41)
3.6746 + 30.6852 + 4.536 + 0.1271
Average atomic mass = 39.02amu
need help w the questions in the pic! thankyouu
Answer: Here are the answers
Explanation:
7a) Calcium Chloride +water+carbon dioxide
b)Calcium Oxide +Carbon dioxide
8a) zinc + carbon monoxide
b) Aluminum + Carbon dioxide
c) Lead + carbon dioxide
classify each of the following solids as ionic,metallic, molecular, network (covalent)or amorphous?
1) Tetra phosphorous deicide(P4O10)
2)Graphite
3) Ammonium phosphate (NH4)3po4
4) Brass
5)SiC
6)Rb
7)l2
8)LiBr
9)P4
10) Plastic
11)Si
Answer;
P4O10 - molecular solid
Graphite - network solid
Ammonium phosphate - ionic
Brass - metallic
SiC - network solid
Rb- metallic
I2 - molecular
LiBr- ionic
P4 - molecular
Plastic - amorphous
Si - network
Explanation:
An ioinc solid is made up of a pair of oppositely charged ion held together by electrostatic interaction between the bonding species.
A covalent solid is a solid in which the atoms involved in the solid are bonded together by covalent bonds. Covalent solids are also molecular.
Metals are held together by interaction of metal ions and a sea of electrons. This is called the metallic bond.
A network solid is composed of covalently bonded atoms that repeat itself in a definite manner. E.g SiC
¿Cuáles son las características del átomo de carbono?
HELP PLSSS WOOT WOOT
Stoichiometry - Chemistry
Answer:
C
Explanation:
in the option C when we rearrange it then it will he C3H6O2
Answer:
yes its C
Explanation:
correct me if iam wrong
according to the article, which of the following may be affected by a scientists bias?
Glycerin, , is a nonvolatile liquid. What is the vapor pressure of a solution made by adding glycerin to at
Complete question is;
Glycerin, C3H8O3, is a nonvolatile liquid. What is the vapor pressure of a solution made by adding 164 g glycerin to 338 mL H2O at 39.8°C?
The vapor pressure of pure water at 39.8°C is 54.74 torr and its density is 0.0992 g/cm³
Answer:
28 torr
Explanation:
Let's first find the number of moles of water in 338 mL.
Molar mass of water = 18 g/mole
Formula for number of moles = mass/molar mass.
Mass = density × volume = 0.0992 × 338 = 33.5296 g
Thus;
Number of moles = 33.5296/18 = 1.863 moles.
Let's use the same procedure to find the Number of moles of glycerine.
Molar mass of glycerine from online values = 92.1 g/mol
Thus;
n_glycerine = (mass)/92.1
We have mass and density as 164 g and 0.0992 g/cm³ respectively.
n_glycerine = 164/92.1
n_glycerine = 1.78
Total moles of solution = 1.863 + 1.78 = 3.643 moles
We are told that The vapor pressure of pure water at 39.8°C is 54.74 torr
Thus, since water dominates, then vapour pressure of solution = (1.863/3.643) × 54.74 ≈ 28 torr
A train is accelerating at a rate of 2 m/s. If its intital velocity is 20 m/s,what is its veolcity after 30 seconds
Answer:
80 m/s.
Explanation:
NOTE: This is a physics question. However, the solution to the question given below:
From the question given above, the following data were obtained:
Acceleration (a) = 2 m/s²
Initial velocity (u) = 20 m/s
Time (t) = 30 s
Final velocity (v) =?
The final velocity of the train can be obtained as shown below:
v = u + at
v = 20 + (2 × 30)
v = 20 + 60
v = 80 m/s
Therefore, the final velocity of train is 80 m/s.
I am doing a lab and I am not sure how to calculate the concentration of the chemical formulas used in the lab. Would I need to use the 15ml and add it to the 10 ml of the first solution to find the concentration. Thank you
Answer:
C = m/V
Explanation:
In order to calculate the concentration of a mixture you would need to use the formula for concentration, which is the following...
C = m/V
In this formula C is the concentration, m is the mass of the compound that is being added and mixed into the solution, and V is the total volume of the mixture. The mass of m is in terms of number of moles. Therefore, we would need more information in order to calculate the actual concentration of the mixture that you are trying to find in this scenario. Using the formula above should be enough using the values that you have in your actual workbook.
You burn a log on a fire. You use fire to warm yourself and help you see to read a book. What energy transformation is taking place?
Answer:
heat energy to keep you warm and light energy to be able to read your book
Explanation:
calculate the final pressure of a gas that is expanded from 725cm³ at 30C and 1.19 atm to 1.12cm³ at 43C
Answer:
Final pressure, P2 = 1088.89 atm
Explanation:
Given the following data;
Initial volume, V1 = 725 cm³Initial temperature, T1 = 30°CInitial pressure, P1 = 1.19 atmFinal volume, V2 = 1.12 cm³Final temperature, T2 = 43°CTo find the final pressure (P2), we would use the combined gas law.
Mathematically, the combined gas law is given by the formula;
[tex] \frac {PV}{T} = k [/tex]
[tex] \frac {P_{1}V_{1}}{T_{1}} = \frac {P_{2}V_{2}}{T_{2}} [/tex]
Substituting into the formula, we have;
[tex] \frac {1.19*715}{30} = \frac {P_{2}*1.12}{43} [/tex]
[tex] \frac {850.85}{30} = \frac {P_{2}*1.12}{43} [/tex]
[tex] 28.3617 = \frac {P_{2}*1.12}{43} [/tex]
Cross-multiplying, we have;
[tex] 28.3617 * 43 = 1.12P_{2} [/tex]
[tex] 1219.5531 = 1.12P_{2} [/tex]
[tex] P_{2} = \frac {1219.5531}{1.12} [/tex]
Final pressure, P2 = 1088.89 atm
Please a little help in this I will really appreciate it
Answer:
b is your answer...........
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen atoms and 2 oxygen atoms
Answer:
What period is the atom in?
1.
What group is the atom in?
What is the name of this atom?
What other atom would have similar
properties to the atom?
Will this atom conduct electricity well
Explanation:
How many of each kind of atom is in one molecule of water? 1 hydrogen atom and 2 oxygen atoms 1 hydrogen atom and 1 oxygen atom 2 hydrogen atoms and 1 oxygen atom 2 hydrogen
and 2 oxygen atoms
In a few sentences, describe the molecular polarity and the intermolecular forces present in ammonium lauryl sulfate.
The description of the molecular polarity and the intermolecular forces present in ammonium lauryl sulfate should be explained below.
What is ammonium lauryl sulfate?The common name of it should be likely ammonium lauryl sulfate (ALS) and its molecular formula should be (CH3(CH2)10CH2OSO3NH4).
Also, one intermolecular formula that should be presented in the molecule should be considered as the electrostatic forces of attraction that lies between the non-polar chain and the polar ending group.
Learn more about forces here: https://brainly.com/question/23196146
How to work out the amount of carbon dioxide that is released when fully combusted with 4kg of ethanol?
Answer:
There is 7642 grams of CO2 released
Explanation:
Step 1: Data given
carbon dioxide = CO2
Molar mass of carbon dioxide = 44.01 g/mol
Mass of ethanol = 4 kg = 4000 grams
Molar mass of ethanol = 46.07 g/mol
Step 2: The reaction
Combustion of ethanol means there is oxygen (O2) added. The products are CO2 and H2O.
C2H5OH + 3O2 → 2CO2 + 3H2O
Step 3: Calculate number of moles of ethanol
Moles ethanol = mass ethanol / molar mass ethanol
Moles ethanol = 4000 grams / 46.07 g/mol
Moles ethanol = 86.82 moles
Step 4: Calculate number of moles CO2
For 1 mol ethanol we need 3 moles to produce 2 moles CO2 and 3 moles H2O
For 86.82 moles of ethanol we'll have 2*86.82 = 173.64 moles CO2
Step 5: Calculate mass of CO2
Mass CO2 = moles CO2 * molar mass CO2
Mass CO2 = 173.64 moles * 44.01 g/mol
Mass CO2 = 7642 grams
There is 7642 grams of CO2 released
Using the balanced equation below, how many grams of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride?
CSF + XeF6 → CsXeF7
Answer: A mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
Explanation:
Given: Mass of cesium xenon heptafluoride = 73.1 g
The molar mass of cesium xenon heptafluoride is 131.3 g/mol. So, moles of [tex]CsXeF_{7}[/tex] is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{73.1 g}{131.3 g/mol}\\= 0.556 mol[/tex]
According to the given equation, 1 mole of CsF yields 1 mole of [tex]CsXeF_{7}[/tex].
Hence, moles of CsF reacting will also be equal to 0.556 mol. As molar mass of CsF is 151.9 g/mol so its mass is calculated as follows.
[tex]Moles = \frac{mass}{molarmass}\\0.556 mol = \frac{mass}{151.9 g/mol}\\mass = 84.46 g[/tex]
Thus, we can conclude that a mass of 84.46 g of cesium fluoride would be required to make 73.1 g of cesium xenon heptafluoride.
what are condition for formation of electrovalent bond
Answer:
The conditions for the formation of an electrovalent bond are as follows: The atom which changes into cation (+ ive ion) should possess 1,2 or 3 valency electrons. It will loose these electrons to form cation with +1,+2 or +3 charge
¿Cuántos ml de alcohol contiene una lata de cerveza de 375 ml si tiene una concentración 4% v/v?
Answer:
15 mL
Explanation:
El valor de concentración de 4% v/v nos dice que de cada 100 mL de cerveza, 4 mL son de alcohol.
Con eso en mente podemos calcular los mL de alcohol presentes en 375 mL, de la siguiente forma:
375 mL * 4/100 = 15 mLEn 375 mL de cerveza de concentración 4% v/v, hay 15 mL de alcohol.
What do we need in order to obtain energy?
Explanation:
hope it helps thanks ❤
brainliest please
Answer:
Explanation:
human obtains energy by eating food. as food is digested n broken down in our digestive system, energy is released to our body.