Answer:
[tex]\rm 2Co^{3+}+3S^{2-} \rightarrow Co_2S_{3\,(s)}[/tex]
Net Ionic Equation:If we write a balanced molecular equation as:
[tex]\\ \rm 2CoBr_{3\,(aq)}+3K_2S_{\,(aq)} \rightarrow Co_2S_{3\,(s)}+6KBr_{\,(aq)}\\[/tex]
Then the corresponding ionic equation is:
[tex]\rm 2Co^{3+}+6Br^-+6K^++3S^{2-} \rightarrow Co_2S_{3\,(s)}+6K^++6Br^-[/tex]
If you look carefully at the ionic equation, you may notice that the potassium ion and the bromide ion appear unchanged on both sides of the equation. When the two solutions are mixed, neither the [tex]\rm 6K^+[/tex] nor the [tex]\rm 6Br^-[/tex] ions participate in the reaction. They can be eliminated from the reaction.
These ions that are eliminated are known as spectator ions. A spectator ion is one that does not take part in the reaction, and are essentially, 'spectators'.
In the above reaction, the potassium ion and the bromide ion are both spectator ions. The equation can now be written without the spectator ions:
[tex]\rm 2Co^{3+}+3S^{2-} \rightarrow Co_2S_{3\,(s)}[/tex]
The net ionic equation is the chemical equation that shows only those elements, compounds, and ions that are directly involved in the chemical reaction.
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What is the pH of a 0.040 M Ba(OH)2 solution?
A) 1.10
B) 1.40
C) 12.60
D) 12.90
The pH of a 0.040 M Ba(OH)2 solution can be found by calculating the pOH first, and then using the relationship pH + pOH = 14.
Ba(OH)2 dissociates into Ba2+ and 2 OH- ions. The concentration of OH- ions can be found by multiplying the initial concentration by 2, since each Ba(OH)2 molecule dissociates into 2 OH- ions.
[OH-] = 2 x 0.040 M = 0.080 M
Next, use the expression for the ion product constant of water (Kw = [H+][OH-] = 1.0 x 10^-14) to find the concentration of H+ ions:
Kw = [H+][OH-]
1.0 x 10^-14 = [H+][0.080]
[H+] = 1.3 x 10^-13
Finally, calculate the pOH:
pOH = -log[OH-] = -log(0.080) = 1.10
Using the relationship pH + pOH = 14:
pH = 14 - pOH = 14 - 1.10 = 12.90
Therefore, the pH of a 0.040 M Ba(OH)2 solution is D) 12.90.
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Determine the number of calories required for 47.5g of Al to go from 25 to 62. The specific heat of Al is 0.900 J/g C.
The number of calories required for 47.5g of Al to go from 25°C to 62°C is approximately 381.1 calories.
What is specific heat?The concept of specific heat is rooted in the amount of heat energy needed to increase the temperature of a single unit mass of a substance by one degree Celsius (or one Kelvin). This measurement is commonly denoted in units of joules per gram per degree Celsius (J/g°C) or joules per gram per Kelvin (J/gK).
Equation:
q = m × c × ΔT
Plugging the given values, we get:
q = 47.5 g × 0.900 J/g°C × (62°C - 25°C)
q = 47.5 g × 0.900 J/g°C × 37°C
q = 1595.25 J
To convert this to calories, we divide by the conversion factor of 4.184 J/cal:
q = 1595.25 J ÷ 4.184 J/cal
q = 381.1 cal
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what is ionization energy? what is its trend on the periodic table? How does it change for the second and third ionization energy.
Ionization energy refers to the amount of energy required to remove an electron from an atom or ion. The trend of ionization energy on the periodic table is that it generally increases from left to right across a period and decreases from top to bottom within a group. This is due to the increasing number of protons in the nucleus and the increasing distance between the outermost electrons and the nucleus.
The second ionization energy is always higher than the first ionization energy, as it requires more energy to remove a second electron from a positively charged ion.
Similarly, the third ionization energy is even higher than the second ionization energy, as it becomes more difficult to remove electrons from a positively charged ion with each subsequent removal.
This trend continues for each subsequent ionization energy.
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Calculate the mass of lithium fluoride (LiF) in 496 mL of a 0.8 M solution.
Taking into account the definition of molarity and molar mass, the mass of lithium fluoride in 496 mL of a 0.8 M solution is 7.6388 grams.
Definition of molarityMolarity is the concentration of a solution and indicates the number of moles of solute that are dissolved in a given volume.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
molarity= number of moles÷ volume
Molarity is expressed in units moles/L.
Definition of molar massThe molar mass is the amount of mass that a substance contains in one mole.
Concentration in this caseIn this case, you know:
molarity= 0.8 Mnumber of moles=?volume= 496 mL= 0.496 L (being 1000 mL= 1 L)Replacing in the definition of molarity:
0.8 M= number of moles÷ 0.496 L
Solving:
0.8 M× 0.496 L= number of moles
0.2968 moles= number of moles
Now, you know:
molar mass of LiF= 26 g/molemass of LiF= ?number of moles= 0.2968 molesReplacing in the definition of molar mass:
26 g/mole= mass of LiF÷ 0.2968 moles
Solving:
26 g/mole ×0.2938 moles= mass of LiF
7.6388 grams= mass of LiF
Finally, the mass of LiF is 7.6388 grams.
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hermochemical analysis for a new rocket engine design using lox and rp-1 predicts that the combustion temperature will be 3415k with a ratio of specific heats, \gamma, of 1.225. if the molecular mass of the combustion products is 21.79 kg/kmole, what is the theoretical characteristic exhaust velocity, c*, and specific impulse, isp, for this new engine?
The theoretical characteristic exhaust velocity, c* is 2850.7 m/s, and specific impulse Isp is 2556.5s for this new engine.
Using the following formula, the theoretical typical exhaust velocity, c*, can be determined:
sqrt(2 * * R * Tc / M) = c*.
where Tc is the combustion temperature in Kelvin, M is the molecular mass of the combustion products, and is the ratio of specific heats. R is the universal gas constant (8.314 J/mol.K).
Inputting the values provided yields:
c*= sqrt(2 * 1.225 * 8.314 * 3415 / 21.79), which equals 2850.7 m/s.
The following formula can be used to determine the particular impulse, Isp:
Isp equals c* * ln(m0/mf).
where the rocket's beginning mass is m0 and its ultimate mass, after the propellant has been burned, is mf.
Let's suppose that the mass ratio of the rocket to the propellant is 3:1 since we don't know the rocket's mass. The mass of propellant would then equal 3/4 of the rocket's original mass.
As a result, we get:
Isp = 2556.5 * ln(m0 / (3/4 * m0)) = 2850.7 * ln(4/3)
Therefore, the particular impulse, Isp, is 2556.5 s, and the predicted typical exhaust velocity, c*, is 2850.7 m/s.
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If a 2000 block of metal lost 3120 j of heat as it cooled from 212c to 200 what is the specific heat of the metal
Answer:
130J/Kg/K
Explanation:
since it is equals to mass multiply the specific heat capacitance Multiply by the change in temperature.
Do carboxylic acids usually have a higher or lower pKa compared to other ORGANIC compounds? Do they have high levels of hydrogen bonding? What affect does this have on melting/boiling points? How does this compare to alcohols.
Carboxylic acids usually have a lower pKa compared to other organic compounds. Carboxylic acids have high levels of hydrogen bonding. This results in higher boiling/melting points of carboxylic acids.
Carboxylic acids usually have a lower pKa compared to other organic compounds. This is because they have a carboxyl group (-COOH) which can donate a proton (H+) to form a negatively charged carboxylate ion (-COO-). This ion is stabilized by resonance, making it more stable than other organic acid ions.
Carboxylic acids have high levels of hydrogen bonding due to the presence of the polar carboxyl group. Hydrogen bonding occurs between the hydrogen atom of one molecule and the oxygen atom of another molecule. This results in a network of intermolecular hydrogen bonds, which leads to higher melting/boiling points compared to other organic compounds.
When compared with alcohols, carboxylic acids generally have higher melting/boiling points due to their stronger intermolecular hydrogen bonding. However, alcohols with higher molecular weights may have higher melting/boiling points than smaller carboxylic acids due to their greater van der Waals forces.
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This question is about zinc and compounds of zinc.
A student produces pure crystals of zinc chloride by reacting zinc oxide with
hydrochloric acid.
The equation for the reaction is:
ZnO(s) + 2HCl(aq)=ZnCl₂(aq) + H₂O(l)
The student adds zinc oxide to hydrochloric acid until the zinc oxide is in excess.
Give one observation that the student could make to show that the zinc oxide is
in excess.
[1 mark]
Why is excess zinc oxide used rather than excess hydrochloric acid?
[1 mark]
Name one other compound that the student could add to hydrochloric acid to produce
zinc chloride.
[1 mark]
Describe how the student should obtain crystals of zinc chloride from a solution of
zinc chloride.
[2 marks]
Observation to show excess zinc oxide:
If the student observes that there is some undissolved solid zinc oxide remaining in the reaction mixture even after stirring for a long time, it indicates that zinc oxide is in excess.
Reason for using excess zinc oxide:
Excess zinc oxide is used rather than excess hydrochloric acid because zinc oxide is insoluble in water, while hydrochloric acid is soluble. Therefore, adding excess hydrochloric acid would result in excess acid remaining in the solution and contaminating the pure crystals of zinc chloride.
Another compound that could be added to hydrochloric acid to produce zinc chloride:
Zinc sulfate (ZnSO4) could be added to hydrochloric acid to produce zinc chloride.
Obtaining crystals of zinc chloride from a solution:
The student can obtain crystals of zinc chloride from a solution by evaporating the solvent, typically water, to a smaller volume, allowing the solute to become more concentrated. The solution should then be left to cool slowly to allow the crystals of zinc chloride to form. The crystals can be separated from the solution by filtration, washed with cold water, and dried to obtain pure crystals of zinc chloride.
how does the density of the rock compare to the density of the water? give your answer as a cer, using observations from the video as your evidence.
Astronomy, the Evolving Universe by Zeilik Rocks: 2 to 4 g/cm3, water (liquid): 1.0 g/cm3, and so on. Earth has a density that is 5.58 x 109 times that of water, or 5.58 x 10 9 times as dense.
Consequently, the earth has a density of 5.58 1012 kg/m3. The density of air is 5.58 10 12 k g / m3, or 5.58 109 5.58 10 9 times that of water. For instance, the majority of rock on Earth's surface has a density of about 3000 kg/m3, whereas the planet as a whole has an average density of 5515 kg/m3.
Therefore, the earth's iron core, which is significantly denser, is inside. The volume of a substance directly affects its density; the smaller the volume, the higher the density.
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what is the percent yield when a reaction vessel that initially contains 60.5 kg ch4 and excess steam yields 16.2 kg h2?
When the reaction vessel that is initially contains the 60.5 kg CH₄ and the excess steam yields 16.2 kg H₂. The percent yield is 50 %.
The chemical reaction is as :
CH₄ + 2H₂O ---> CO₂ + 4H₂
The mole ratio of the methane to the steam is 1:4.
The Moles of 60.5 kg of methane = 60500 / 16.0
The Mole of 60.5 kg of methane = 3781.25 mol
The Equivalent mole of moles H₂ = 16200 mol
The mass of the moles H₂ = 16200 × 2
The mass of the moles H₂ = 32400 g
The mass of the moles H₂ = 32.4 kg
The percent yield = (16.2 / 32.4 ) 100 %
The percent yield = 50 %.
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why are fossils from the phanerozoic the best preserved? give 2 reasons
The fossils from the Phanerozoic era are the best preserved due to the following reasons:
the development of hard skeletal structures by many organismsthe presence of sedimentary rocks that offer protection and preservation.What makes fossils from Phanerozoic era the best preserved?These fossils spans from about 541 million years ago to the present day and are considered the best preserved because many organisms developed hard skeletal structures such as shells and bones that are more likely to be preserved as fossils than soft tissue.
Also, the sedimentary rocks are formed by the accumulation and compression of sediment which offer protection and preservation for fossils by preventing decay and erosion. These factors contributed to the high quality and abundance of fossils from the Phanerozoic era.
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If a sample of dna has 14 guanine and 37 thymine, how many adenine should it also have?
If a sample of DNA has 14 guanine and 37 thymine, then it must have an equal number of cytosine and adenine. This is due to Chargaff's rule; Chargaff's rules state that in the DNA of any species and any organism, the amount of guanine should be equal to the amount of cytosine and the amount of adenine should be equal to the amount of thymine. Further a 1:1 stoichiometric ratio of purine and pyrimidine bases (i.e., A+G=T+C) should exist. This pattern is found in both strands of the DNA. They were discovered by Austrian-born chemist Erwin Chargaff, in the late 1940s.
This is because DNA base pairing is always adenine with thymine, and cytosine with guanine. Therefore, the sample of DNA must have 14 cytosine, and since the total number of bases is 105 (14+37+14+40), the number of adenine must also be 40 (105-14-37-14). So, the answer is that the sample of DNA should also have 40 adenine.
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What is the pH of a 0.350 M solution of NaHCO3 , given that the Kb of HCO−3 is 2.3×10−8 ? 10.5 8.4 11 9.9
The pH value of 0.350 M solution of NaHCO₃ is found to be 10.5, hence option A is correct.
NaHCO₃ is a salt that can undergo hydrolysis in water to form a basic solution, as the HCO₃⁻ ion is a weak base. The reaction is as follows:
HCO₃⁻ + H₂O ⇌ H₂CO₃ + OH⁻
Since the Kb of HCO₃⁻ is given as 2.3×10⁻⁸, we can find the concentration of OH⁻ ion produced by using the Kb expression,
Kb = [H₂CO₃][OH⁻]/[HCO₃⁻]
Assuming that the concentration of H₂CO₃ is negligible, as it is a weak acid that dissociates only slightly in water, we can simplify the expression to,
Kb = [OH⁻][HCO₃⁻]
[OH⁻] = Kb/[HCO₃⁻]
= (2.3×10⁻⁸)/[HCO₃⁻]
Now, we need to find the concentration of HCO₃⁻ in the 0.350M solution of NaHCO₃. NaHCO₃ dissociates in water to give Na⁺ and HCO₃⁻ ions,
NaHCO₃ ⇌ Na⁺ + HCO₃⁻
The concentration of HCO₃⁻ ion in solution will be equal to the initial concentration of NaHCO₃, since the dissociation is 1:1. Therefore, [HCO₃⁻] = 0.350M.
Substituting into the expression we obtained earlier,
[OH⁻] = (2.3×10⁻⁸)/0.350
= 6.57×10⁻⁸ M
The pH of the solution can be calculated as follows,
pH = 14 - pOH
= 14 - (-log[OH⁻])
= 14 - (-log6.57×10⁻⁸)
= 10.5
Therefore, the pH of the 0.350M solution of NaHCO₃ is 10.5, which corresponds to option A.
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Complete question - What is the pH of a 0.350M solution of NaHCO₃ , given that the Kb of HCO⁻³ is 2.3×10⁻⁸ ?
A. 10.5
B. 8.4
C. 11
D. 9.9
what does an element look like on the atomic level?
They appear to be blobs, and that is all that can be seen. Beyond that, visible light wavelengths are longer than the structures you're interested in.
What is the definition of an Atom?An atom is a fundamental particle of matter that contains at least one proton. An atom is the lowest amount of a substance capable of participating in a chemical reaction.
An atom is made up of a central nucleus and one or more negatively charged electrons. The nucleus is positively charged and contains one or more protons and neutrons, which are relatively heavy particles.
Here are some atom examples: hydrogen (H) and neon (Ne).
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3) How much heat is needed to increase 186 grams of water from 21.0°C to 69.9°C?
22.0°C
Answer:
it would take 36,893.71 joules of heat to increase 186 grams of water from 21.0°C to 69.9°C.
Explanation:
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g what happens to amount of daughter isotope over time? group of answer choices it stays the same it decreases it increases
The amount of the daughter isotope over the time is it increase.
For the each parent isotope and that will decays, the daughter isotope will takes the place. While over the time, the number of the parent isotopes will be decreases and the number of the daughter isotopes increase.
Radioactive isotopes will be break down over the time, and changing the from the parent isotopes to the daughter isotopes to the steady rate. The original unstable isotope is termed as the parent isotope, and the one which is more stable form is termed as the daughter isotope. The daughter isotopes will increases.
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2.
Aluminum bromide and sodium hydroxide react to
form aluminum hydroxide and sodium bromide.
How many moles of sodium bromide can be formed from 1.55
moles of aluminum bromide?
Using the equation from the "I do" section, find the number of
moles of aluminum hydroxide may be formed from 4.65 moles
of sodium hydroxide?
How many moles of H₂ are needed to react with 2.0 moles of nitrogen gas?
N2 + 3 H2 -> 2 NH3
The number of moles of the sodium bromide that is produced is 4.65 moles .
What is the stoichiometry?The law of conservation of mass, which states that the total mass of the reactants in a chemical reaction must equal the total mass of the products, is the foundation for stoichiometric calculations.
We know that in the case of a problem like this, we would have to look up at the stoichiometry of the reaction as that would give the lead as to how we can be able to approach the problem that we have at hand.
We know that;
AlBr3 + 3NaOH → Al(OH)3 + 3NaBr
1 mole of AlBr3 produces 3 moles of NaBr
1.55 moles of AlBr3 will produce 1.55 * 3/1
= 4.65 moles
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if 6.5 moles of copper metal was deposited from a solution of cu(no3)2, how many electrons were involved?
Total, 13 electrons were involved in the depletion of 6.5 moles of Cu²⁺ ions to copper metal.
The balanced reaction for the depletion of Cu²⁺ ions (from Cu(NO₃)₂) to copper metal can be represented as;
2 Cu²⁺ + 4 e⁻ → 2Cu
From the equation, it can be seen that 2 moles of Cu²⁺ ions require 4 moles of electrons to be reduced to 2 moles of copper atoms.
Given that 6.5 moles of copper metal was placed, we can use the mole ratio from the balanced equation to determine the number of electrons involved;
6.5 moles of copper metal x 4 moles of electrons/2 moles of copper
= 13 moles of electrons
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Which of the following is NOT a way to satisfy the octet rule?
a
transferring inner electrons to fill the outer electron
shell
b transferring valence electrons in an ionic bond
c having a full outer electron shell
d sharing valence electrons in a covalent bond
Transferring inner electrons to fill the outer electron shell is not a way to satisfy the octet rule is NOT a way to satisfy the octet rule. Option A is correct
The octet rule states that atoms tend to gain, lose, or share electrons in order to acquire a full outer electron shell with 8 electrons. In some cases, such as with elements in period 3 and beyond, it is possible for an atom to have more than 8 electrons in its outer shell. However, transferring inner electrons to fill the outer electron shell is not a valid way to satisfy the octet rule, as it would require significant energy input and is not a stable configuration for an atom.
Option A is correct
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what is a proper big-o notation of below statement ? finding a name in a phone book (select more than one answer, no partial point). a. o(1) b. o(n) c. o(2 n) d. o(log2n) e. o(n2) n. o(log2 n)
The proper big-o notation of for the finding the name in the phone book is O(log2n). The correct option is d.
The Big O notation is the one of the very most fundamental the tools for the computer scientists to the analyze and the cost of the algorithm. This is the good practice for the software engineers and to understand the in-the depth as well.
The Big O notation is the mathematical notation which will describes the limiting the behavior of the function and when the argument will tends towards the particular value or the infinity. The O(log2n) is the proper big-o notation of the finding the name in the phone book. The option d is correct.
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The acid dissociation constant K_a of carbonic acid (H_2CO_3) is 4.5 times 10^-3. Calculate the pH of 0.93 M solution of carbonic acid.
The acid dissociation constant K_a of carbonic acid (H_2CO_3) is 4.5 times 10^-3. The pH of 0.93 M solution of carbonic acid is 1.35.
To solve this problem, we first need to write out the chemical equation for the dissociation of carbonic acid:
H₂CO₃ ⇌ H+ + HCO3-
The acid dissociation constant (Ka) for this reaction is 4.5 x 10^-3. This means that the equilibrium constant for the forward reaction (the dissociation of H₂CO₃ into H+ and HCO3-) is 4.5 x 10^-3. We can use this information to calculate the pH of a 0.93 M solution of carbonic acid.
We start by writing out the expression for the acid dissociation constant:
Ka = [H+][HCO3-]/[H₂CO₃]
We can assume that the initial concentration of H+ and HCO3- is zero, and the initial concentration of H₂CO₃ is 0.93 M. At equilibrium, the concentration of H+ and HCO3- will be x M (since they are produced in a 1:1 ratio). The concentration of H₂CO₃ will be 0.93 - x M (since some of it will have dissociated into H+ and HCO3-).
Substituting these values into the expression for Ka, we get:
4.5 x 10^-3 = x^2/(0.93 - x)
Solving for x using the quadratic formula, we get:
x = 0.045 M
So the concentration of H+ (and HCO3-) in the solution is 0.045 M. To calculate the pH, we use the formula:
pH = -log[H+]
pH = -log(0.045)
pH = 1.35
Therefore, the pH of a 0.93 M solution of carbonic acid is 1.35.
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(ethanol , ethane , dymethyl ether , Ethylene) which of the following compounds have hydrogen bonds ?
Answer:
Ethanol
Explanation:
All four of these compounds are organic chemicals that occupy the capacity to withhold different intermolecular forces, commonly known as bonds. There are three main types of intermolecular forces, called London Dispersion, dipole dipole, and hydrogen bonding.
What are hydrogen bonds?Hydrogen bonds are a different kind of dipole dipole bonding that is relatively strong and involves an electronegative atom (only Nitrogen, Oxygen, and Fluorine) causing a force of attraction with a Hydrogen.
Hydrogen bonds are created when there are partial positive charge on the Hydrogen atom, and a partial negative charge on the electronegative atom.
In other words, we are looking for a Hydrogen attached to a Nitrogen, Oxygen, or Fluorine.
◾ Ethanol's structure: [tex]\\~~~~~~~H~~~~H\\~~~~~~~~|~~~~~|\\H-C-C-O-H\\~~~~~~~~|~~~~~|\\~~~~~~~H~~~~H\\[/tex]
→ A clear hydroxyl group (O-H) at the right hand side of the Lewis structure is shown, which means it possesses a hydrogen bond.
◾ Ethane's structure: [tex]\\~~~~~~~H~~~~H\\~~~~~~~~|~~~~~|\\H-C-C-H\\~~~~~~~~|~~~~~|\\~~~~~~~H~~~~H\\[/tex]
→ Does not have any hydrogens attached to the electronegative atoms listed above. Therefore, this does not possess a hydrogen bond.
◾ Dimethyl ether's structure: [tex]\\~~~~~~~H~~~~~~~~~~H\\~~~~~~~~|~~~~~~~~~~~~|\\H-C-O-C-H\\~~~~~~~~|~~~~~~~~~~~~|\\~~~~~~~H~~~~~~~~~~H\\[/tex]
→ Has the necessary electronegative atom, which is the oxygen, inside the structure. However, it does not obtain any bonding through hydrogens and instead attaches to the carbons, concluding that dimethyl ether does not contain any hydrogen bonding.
◾ Ethylene's structure: [tex]H~~~~H\\~~|~~~~~|\\~C=C\\~~|~~~~~|\\~H~~~H\\[/tex]
→ Clearly not possessing an electronegative atom bonding with a hydrogen, therefore, does not have any hydrogen bonding.
In summary, the only organic compound that contains a hydrogen bond is ethanol.
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Refer to Animation: Chemical Synapses. Which answer choice determines whether or not an action potential is triggered in the postsynaptic neuron?
the overall net change in membrane potential caused by the combined EPSPs and IPSPs
the magnitude of the depolarizing excitatory postsynaptic potentials (EPSPs)
the magnitude of the hyperpolarizing inhibitory postsynaptic potential (IPSP)
The overall net change in membrane potential caused by the combined EPSPs and IPSPs determines whether or not an action potential is triggered in the postsynaptic neuron in a chemical synapse, as shown in the Animation: Chemical Synapses.
In the context of Animation: Chemical Synapses, the factor that determines whether or not an action potential is triggered in the postsynaptic neuron is:
The overall net change in membrane potential caused by the combined EPSPs and IPSPs.
In this process, both excitatory postsynaptic potentials (EPSPs) and inhibitory postsynaptic potentials (IPSPs) play a role in determining the overall membrane potential of the postsynaptic neuron. If the net change in membrane potential reaches the threshold level, an action potential will be triggered.
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the atom 22387fr 87 223 f r decays to 22388ra 88 223 r a by emitting what kind of nuclear radiation?
The atom ²²³⁸⁷Fr (Francium-223) decays to ²²³⁸⁸Ra (Radium-223) by emitting beta-minus (β-) nuclear radiation.
During alpha decay, an atom emits an alpha particle, which consists of two protons and two neutrons. In this case, the atom 22387fr 87 223 f r has too many protons, making it unstable. To become more stable, it emits an alpha particle, which reduces its atomic number by two and its atomic mass by four. The resulting atom, 22388ra 88 223 r a, has a more balanced number of protons and neutrons, making it more stable.
In this decay process, a neutron in the Francium-223 nucleus is converted into a proton, causing the atomic number to increase by 1, while the mass number remains unchanged. This results in the formation of Radium-223. During this conversion, a beta-minus (β-) particle, which is essentially an electron, is emitted as a form of nuclear radiation.
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3) Dissolved in water to make 600 mL of solution, 32.00 g of CaCl₂ would have a concentration of?
Taking into account the definition of molarity, the concentration of the solution is 0.48 mol/L.
Definition of molarityMolarity is the concentration of a solution expressed in the number of moles dissolved per liter of solution.
The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:
molarity= number of moles÷ volume
Molarity is expressed in units moles/L.
Definition of molar massThe molar mass is the amount of mass that a substance contains in one mole.
Concentration in this caseIn this case, you know:
molar mass of CaCl₂= 110.9 g/molemass of CaCl₂= 32 gnumber of moles= ?Replacing in the definition of molar mass:
110.9 g/mole= 32 g÷ number of moles
Solving:
110.9 g/mole ×number of moles= 32 g
number of moles= 32 g÷ 110.9 g/mole
number of moles= 0.2885 moles
Then, you know:
number of moles= 0.2885 molesvolume= 600 mL= 0.6 L (being 1000 mL= 1 L)Replacing in the definition of molarity:
molarity= 0.2885 moles÷ 0.6 L
Solving:
molarity= 0.48 moles/L
Finally, the molarity of the solution is 0.48 mol/L.
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Calculate the hydronium ion concentration in an aqueous solution with a pH of 11.7 at 25°C.
A) 5.7 × 10^-11 M
B) 1.9× 10^-12 M
C) 5.4 × 10^-2 M
D) 6.4 × 10^-7 M
E) 9.5× 10^-3 M
The hydronium ion concentration in the given solution is B) 1.9× 10^-12 M.
How to calculate the hydronium ion concentration?The pH of a solution is defined as the negative logarithm (base 10) of the hydronium ion concentration:
pH = -log[H3O+]
To calculate the hydronium ion concentration in an aqueous solution with a pH of 11.7 at 25°C, you can use the following formula:
Hydronium ion concentration (H3O+) = 10^(-pH)
Step 1: Determine the pH value given, which is 11.7.
Step 2: Plug the pH value into the formula:
Hydronium ion concentration (H3O+) = [tex]10^{-11.7}[/tex]
Step 3: Calculate the hydronium ion concentration:
H3O+ ≈ 1.995 × [tex]10^{-12}[/tex] M
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How many grams of H2O will be produced if 750 grams of Fe are produced in the following unbalanced equation? (hint: balance equation first!)
Fe3O4 + H2 → Fe + H2O
Select one:
a.
322 g
b.
17.9 g
c.
241 g
d.
563 g
The correct answer is C. 241 g. The balanced equation is Fe3O4 + 8H2 → 3Fe + 4H2O. Therefore, 750 g of Fe would produce 750/3 = 250 g of H2O, which is 241 g when rounded to the nearest whole number.
can you give me the b mark?
in order for water reabsorption to occur, the solute concentration of the medulla needs to:____
In order for water reabsorption to occur, the solute concentration of the medulla needs to be higher than the solute concentration of the filtrate in the collecting ducts.
This concentration gradient is created by the active transport of ions, such as sodium and chloride, out of the ascending limb of the loop of Henle, which results in the buildup of solutes in the interstitial fluid of the medulla. This concentration gradient then allows for the passive reabsorption of water from the collecting ducts into the interstitial fluid, and eventually into the bloodstream.
The process of water reabsorption in the kidneys involves a complex interplay between various parts of the nephron, including the loop of Henle, the distal tubules, and the collecting ducts. The primary function of these structures is to filter blood and remove waste products, while also maintaining the proper balance of electrolytes and fluids in the body.
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Which combination of aqueous solutions should produce a precipitate?
Question 6 options:
a) NH4F and K2CO3
b) MgCl2 and (NH4)2CO3
c) LiNO3 and Mg(CH3COO)2
d) Ba(NO3)2 and NaCH3COO
e) Na2CO3 and KOH
The combination of aqueous solutions that should produce a precipitate is the correct option b) MgCl2 and (NH4)2CO3.
This combination of aqueous solutions should produce a precipitate because when magnesium chloride (MgCl2) reacts with ammonium carbonate ((NH4)2CO3), it forms magnesium carbonate (MgCO3), which is an insoluble precipitate, along with ammonium chloride (NH4Cl), which remains dissolved in the solution.
This mixture of aqueous solutions ought to result in a precipitate because ammonium carbonate (NH4)2CO3 and magnesium chloride (MgCl2) react to form magnesium carbonate (MgCO3), an insoluble precipitate, and ammonium chloride (NH4Cl), which stays dissolved in the solution. Because of this, option (b) MgCl2 and (NH4)2CO3 is the combination of aqueous solutions that should precipitate.
Hence, The combination of aqueous solutions that should produce a precipitate is the correct option b) MgCl2 and (NH4)2CO3.
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carbon-14 is a radioactive isotope which decays with a half-life of 5730 years. what is the first-order rate constant for its decay?
Carbon-14 is a radioactive isotope which decays with a half-life of 5730 years. The first-order rate constant for its decay is 1.21 x 10⁻⁴ years.
The following equation can be used to get the carbon-14 decay's first-order rate constant:
k = ln(2) / t1/2
where t1/2 is the radioactive isotope's half-life, ln is the natural a logarithm, and k is the first-order rate constant.
Inputting the values provided yields:
k=ln(2)/5730 years
1.21 x 10⁻⁴ years per k
The first-order rate constant for carbon-14 decay is therefore roughly
1.21 x 10⁻⁴ years.
The rate of carbon-14 deterioration over time is represented by this number. It is a crucial factor in radiocarbon dating, a method for figuring out the age of organic materials based on the carbon-14 decay.
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