What is the next term in the sequence below?
24, 12, 6, 3, . . .
A. 0.5
B. 1.5
C. 1.75
D. 2.5

Answers

Answer 1

Answer:

1.5(B)

Step-by-step explanation:

This is a geometric sequence where each number is 1/2 times the last. So 3/2 is 1.5.


Related Questions

4.5 as a complex fraction

Answers

Answer:

9/2

Step-by-step explanation: I think it is the answer? I really don't know.

What is a set ? Give an example of a set .​

Answers

Answer: 24

Step-by-step explanation:

what is the x-intercept of the line shown below enter your answer as a coordinate pair

Answers

Answer: (-2, 0)

Step-by-step explanation: The x-intercept is the point where a line crosses or intersects the x-axis. In this case, the point is intersecting the x-axis 2 units to the left of the origin or at the point (-2, 0).


6. Write an equation of a line that is Parallel to the line: y = 3x -3

Answers

Answer:

3x - y -6 = 0

Step-by-step explanation:

We need to find the Equation of the line parallel to the given equation of line . The given equation of the line is ,

[tex]\rm\implies y = 3x - 3 [/tex]

Slope Intercept Form :-

[tex]\rm\implies y = mx + c [/tex]

where ,

m is slopec is y intercept .

Therefore , the Slope of the line is 3 . Let the parallel line passes through ( 3,3) . We know that the parallel lines have same slope . Therefore the slope of the parallel line will also be 3 .

Using point slope form :-

[tex]\rm\implies y - y_1 = m ( x - x_1) \\\\\rm\implies y - 3 = 3( x - 3 ) \\\\\rm\implies y -3 = 3x -9 \\\\\rm\implies 3x -y -9+3=0\\\\\rm\implies \boxed{\rm\red{ 3x -y -6=0}}[/tex]

Through any two points there is exactly one _____

space.

plane.

line.

point.

Answers

Answer:

C. Line

Is the correct answer

Given ACM, angle C=90º. AP=9, PM=12. Find AC, CM, AM.

Answers

Answer:

AM = 25, AC = 15, CM = 20

Step-by-step explanation:

The given parameters are;

In ΔACM, ∠C = 90°, [tex]\overline{CP}[/tex] ⊥ [tex]\overline{AM}[/tex], AP = 9, and PM = 16

[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = [tex]\overline{AM}[/tex]²

[tex]\overline{AM}[/tex] = [tex]\overline{AP}[/tex] + PM = 9 + 16 = 25

[tex]\overline{AM}[/tex] = 25

[tex]\overline{AC}[/tex]² = [tex]\overline{AP}[/tex]² + [tex]\overline{CP}[/tex]² = 9² +  [tex]\overline{CP}[/tex]²

∴ [tex]\overline{AC}[/tex]² = 9² +  [tex]\overline{CP}[/tex]²

Similarly we get;

[tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]²

Therefore, we get;

[tex]\overline{AC}[/tex]² + [tex]\overline{CM}[/tex]² = 9² +  [tex]\overline{CP}[/tex]² + 16² + [tex]\overline{CP}[/tex]² = [tex]\overline{AM}[/tex]² = 25²

2·[tex]\overline{CP}[/tex]² = 25² - (9² + 16²) = 288

[tex]\overline{CP}[/tex]² = 288/2 = 144

[tex]\overline{CP}[/tex] = √144 = 12

From [tex]\overline{AC}[/tex]² = 9² +  [tex]\overline{CP}[/tex]², we get

[tex]\overline{AC}[/tex] = √(9² +  12²) = 15

[tex]\overline{AC}[/tex] = 15

From, [tex]\overline{CM}[/tex]² = 16² + [tex]\overline{CP}[/tex]², we get;

[tex]\overline{CM}[/tex] = √(16² + 12²) = 20

[tex]\overline{CM}[/tex] = 20.

Write the product as a single power. 6^(5) * 6^(2) * 6^(5)

Answers

Answer:

6^12

Step-by-step explanation:

add up all the exponents

[tex]\displaystyle\bf \boxed{a^m\cdot a^n=a^{m+n}}\\\\6^5\cdot 6^2\cdot6^5=6^{5+2+5}=\boxed{6^{12} }[/tex]

Length of a rope is 5 metre. What does it mean?

Answers

Step-by-step explanation:

Length of a rope is 5 meter. it means the rope is 5 meter long..

hope it helps.stay safe healthy and happy...

Carla packed this box with one centimeter cubes what is the volume of the box plus is it cubic centimeters or just centimeters or is it square centimeters​ pls help you'll get brainlist

Answers

Cubic centimetres since they are cubes. Did you add any picture of the question? There seems to be none.

the answer is cubic centimeters

Please help me here. I've tried this one over and over and I'm unable to get the answer that was given. How do I find the area of this triangle?

Answers

Answer:

jjdjdjdj and technology and technology and technology and technology and technology

Solve 4x + 11 = k for x.
O A. x= -11
O B. x=-11
O C. x = 4k - 44

D. x= k-7

Answers

Answer:

4x + 11 = k

<=> 4x = k - 11

<=>

[tex]x = \frac{k - 11}{4} [/tex]

Calculate cos (theta) to two decimal places. PLS HELP ASAP

Answers

Answer:

B. -0.07

Step-by-step explanation:

Apply the Law of signs find θ.

Cos θ = (a² + b² - c²)/2ab

Where,

a = 7

b = 8

c = 11

Plug in the values

Cos θ = (7² + 8² - 11²)/2*7*8

Cos θ = (49 + 64 - 121)/112

Cos θ = -8/112

Cos θ = -0.0714285714

Cos θ = -0.07 (to 2 decimal places)

The answers to this question make no sense please help

Answers

Answer:

Step-by-step explanation:

each die has numbers 1-6 thus there are 36 (6*6) possible outcomes

a) 18 of the 36 are even = 1/2 = .5 = 50%

b) (1,2) and (2,1) are the only 3's 2/36 = 1/18 = .055

c) there are 10 combos that are LESS THAN 6 (2,3,4,5)

   10/36 = .277 = 27.7%

2 3 4 5 6 7

3 4 5 6 7 8

4 5 6 7 8 9

5 6 7 8 9 10

6 7 8 9 10 11

7 8 9 10 11 12

Find the midpoint of the line segment with end coordinates of:
(

2
,

4
)
and
(

1
,

5
)

Give coordinates as decimals where appropriate

Answers

Answer:

Step-by-step explanation:

The Midpoint formula is

[tex]M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})[/tex] where the x's and y's come from the coordinates of the endpoints. Filling in:

[tex]M=(\frac{-2+(-1)}{2},\frac{-4+(-5)}{2})=(\frac{-3}{2},\frac{-9}{2})=(-1.5,-4.5)[/tex]

Using the number line below, draw a box and whisker plot for the following data: 12,18,18,20,22,22,25,26,30,30,32,32,35,35,38,49,42

Answers

Answer:

Step-by-step explanation:

Population size: 17

Median: 30

Minimum: 12

Maximum: 49

First quartile: 21

Third quartile: 35

Interquartile Range: 14

Outliers: none

how do you find the arc length of a semi-circle?

Answers

the arc length is calculated by the formula                                                                    [tex]\displaystyle\bf C=\frac{2\pi r}{360} \cdot\alpha[/tex]   then   [tex]\displaystyle\bf C=\frac{2\cdot 8 \pi }{360} \cdot180=8\pi=3,14\cdot8=25.12[/tex]   or it can be calculated using the circumference of the circle since we have a semicircle the circumference 2πr must be divided by 2  С=2πr:2=πr =8π=25,12

algebra 2 help pls answer

Answers

Answer:

The volume of this rectangular prism equals [tex]V = 20x^{4} + 20x^{3} + 40x^{2}[/tex]

Step-by-step explanation:

In order to solve this question, we have to use the formula provided in the question to find out the volume of the rectangular prism. The formula goes as follows...

V = l × w × h   (where "l" is the length, "w" is the width, and "h" is height.

From the question, we know that...

l = 4x

w = 5x

h = [tex]x^{2} + x + 2[/tex]

Now we just have to substitute all of these values into the equation and we get that...

V = l × w × h

V = 4x × 5x × [tex](x^{2} + x +2)[/tex]

[tex]V = (20x^{2})(x^{2} + x + 2)\\V = 20x^{4} + 20x^{3} + 40x^{2}[/tex]

Therefore, The volume of this rectangular prism equals [tex]V = 20x^{4} + 20x^{3} + 40x^{2}[/tex]

Write 8 as the ratio of two integer

Answers

Answer:

Step-by-step explanation:   7  1  16   37

8/1     8 divided by 1

16/2   16 divided by 2

24/3   24 divided by 3       I could go on, but won't

Which expression has a solution of 11, if m = 1?

m - 11
11 + m
14 - m
m + 10

Answers

Answer:

m+10 has the solution of 11

2√4^3
find the rationalizing factor

Answers

Hello!

2√4³ =

2 × √4 ³ =

2 × 2³ =

2 × 8 = 16

Good luck! :)

instructions: state what additional information is required in order to know that the triangle in the image below are congruent for the reason given.

Given: SAS

Answers

Answer:

please I don't know can u please help me out

Answer:

The answer to your question where SAS is given  

∠T ≈∠ W

The local library lends an average of 68.24 books to readers each day. What is the average number of books lent to readers in a week?

Answers

Answer:

Step-by-step explanation:

Set this up as a proportion and solve. The ratios are books:day, so keep in mind that a week is 7 days because your values have to be the same

[tex]\frac{books}{day}:\frac{68.24}{1}=\frac{x}{7}[/tex] and cross multiply to solve for x, the number of books lent out in a week:

x = 68.24(7) so

x = 477.68 books in a week

4 Two number cubes are rolled. The faces have the numbers 1-6 on them. The number that shows on top is recorded. What is the probability that
the same number shows on both number cubes?
OF
OS

Answers

Of is a answer isn’t

You're working as a floor rep in the local home improvement store. The store wants to increase its inventory. Last year, 40 lawn mowers cost $4,776. At the same cost, how much will 120 lawn mowers cost this year?

Answers


To set up this problem first you'll need to find out the price of one lawn mower.
Divide the amount if lawn mowers bought last year with the cost to get the cost of one lawn mower
Take the number you get and multiply that bu the amount of lawn mowers this year (120)

answer: $14,328

álgebra 1 solve -2 + 11(17y + 15)

Answers

Answer:   187y + 163

Work Shown:

-2 + 11(17y + 15)

-2 + 11(17y) + 11(15) .... distributive property

-2 + 187y + 165

187y + (-2+165)

187y + 163

8. Write the equation for a line that has a slope of 5 and a y-intercept of
negative 12.

Answers

Answer:

[tex]y=5x-12[/tex]

Step-by-step explanation:

This is in slope-intercept form, [tex]y=mx+b[/tex] where [tex]m[/tex] stands for the slope and [tex]b[/tex] stands for the y-intercept.

Hope this is helpful.

Step-by-step explanation:

equation of the line is given by the equation

y=mx+c

in this question you are given the slope (m) as 5 and the y intercept (c) as -12

therefore the equation will be

y=5x+(-12)

y=5x-12

La potencia que se obtiene de elevar a un mismo exponente un numero racional y su opuesto es la misma verdadero o falso?

Answers

Answer:

Falso.

Step-by-step explanation:

Sea [tex]d = \frac{a}{b}[/tex] un número racional, donde [tex]a, b \in \mathbb{R}[/tex] y [tex]b \neq 0[/tex], su opuesto es un número real [tex]c = -\left(\frac{a}{b} \right)[/tex]. En el caso de elevarse a un exponente dado, hay que comprobar cinco casos:

(a) El exponente es cero.

(b) El exponente es un negativo impar.

(c) El exponente es un negativo par.

(d) El exponente es un positivo impar.

(e) El exponente es un positivo par.

(a) El exponente es cero:

Toda potencia elevada a la cero es igual a uno. En consecuencia, [tex]c = d = 1[/tex]. La proposición es verdadera.

(b) El exponente es un negativo impar:

Considérese las siguientes expresiones:

[tex]d' = d^{-n}[/tex] y [tex]c' = c^{-n}[/tex]

Al aplicar las definiciones anteriores y las operaciones del Álgebra de los números reales tenemos el siguiente desarrollo:

[tex]d' = \left(\frac{a}{b} \right)^{-n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{-n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{(-1)\cdot n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{(-1)\cdot n}[/tex]

[tex]d' = \left[\left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]y [tex]c' = \left[(-1)^{-1}\cdot \left(\frac{a}{b} \right)^{-1}\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c = (-1)^{n}\cdot \left(\frac{b}{a} \right)^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{b}{a} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{b}{a} \right)\right]^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = - \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' \neq c'[/tex], la proposición es falsa.

(c) El exponente es un negativo par.

Si [tex]n[/tex] es par, entonces:

[tex]d' = \left(\frac{b}{a} \right)^{n}[/tex] y [tex]c' = \left(\frac{b}{a} \right)^{n}[/tex]

Puesto que [tex]d' = c'[/tex], la proposición es verdadera.

(d) El exponente es un positivo impar.

Considérese las siguientes expresiones:

[tex]d' = d^{n}[/tex] y [tex]c' = c^{n}[/tex]

[tex]d' = \left(\frac{a}{b}\right)^{n}[/tex] y [tex]c' = \left[-\left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left[(-1)\cdot \left(\frac{a}{b} \right)\right]^{n}[/tex]

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = (-1)^{n}\cdot \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es impar, entonces:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = - \left(\frac{a}{b} \right)^{n}[/tex]

(e) El exponente es un positivo par.

Considérese las siguientes expresiones:

[tex]d' = \left(\frac{a}{b} \right)^{n}[/tex] y [tex]c' = \left(\frac{a}{b} \right)^{n}[/tex]

Si [tex]n[/tex] es par, entonces [tex]d' = c'[/tex] y la proposición es verdadera.

Por tanto, se concluye que es falso que toda potencia que se obtiene de elevar a un mismo exponente un número racional y su opuesto es la misma.

Battle is making fruit baskets, which include apples and bananas to send to some of her real estate clients. She wants each basket to have at least 12 pieces of fruit but the fruit should weigh no more than 80 ounces total. On average each apple weighs 5 ounces and each banana weighs 7 ounces.

Answers

Answer:

there are 2 apples in the basket

there are 10 banana in the basket

Step-by-step explanation:

According to the Question,

We have, Battle is making fruit baskets, which include apples and bananas to send to some of her real estate clients. She wants each basket to have at least 12 pieces of fruit.

let x for apple And y for banana So, x+y=12---Equation 1

And, the fruit should weigh no more than 80 ounces total. On average each apple weighs 5 ounces and each banana weighs 7 ounces.

Thus, 5x+7y=80 ----Equation 2

Now, (Equation 1) × 5 Subtract with (Equation 2) We get,

2y = 20 ⇒ y=10 (there are 10 banana in basket)

Put value of y=10 in Equation 2 we get

5x+70=80 ⇔ x=2(there are 2 apples in basket)

Evaluate the function. f(x)=3x^2 −4x Find f(−1)

Answers

Answer:

7

Step-by-step explanation:

evaluate the function means substitute x=-1 and calculate

f(x) = 3x²-4x

f(-1) =f(x=-1) = 3(-1)²-4(-1) =3+4 =7, because (-1)²=1 and -4(-1) =4

The temperature of a chemical solution is originally 21^\circ\text{C}21 ∘ C21, degrees, start text, C, end text. A chemist heats the solution at a constant rate, and the temperature of the solution is 75^\circ\text{C}75 ∘ C75, degrees, start text, C, end text after 121212 minutes of heating. The temperature, TTT, of the solution in ^\circ\text{C} ∘ Cdegrees, start text, C, end text is a function of xxx, the heating time in minutes. Write the function's formula. T=

Answers

Answer:

T(x) = 21 + 4.5x

Step-by-step explanation:

Given :

Original temperature = 21°C

Final temperature = 75°C

Time, x = 12 minutes

The temperature, T as a function of x, heating time in minutes :

We need to obtain the constant heating rate per minute :

Final temperature = initial temperature + (constant rate change,△t * time)

75 = 21 + 12△t

75 - 21 = 12 △t

54 = 12 △t

△t = 54 / 12

△t = 4.5°C

Hence, temperature change is 4.5°C per minute.

Hence,

T(x) = 21 + 4.5x

Answer:

T= 21+4.5x

Step-by-step explanation:

I got it right on Khan Academy

PLEASE MARK BRAINLIEST

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