what is the parent function of g(x) = 3cos (x + 180°) + 1

The answer is J.

The probability of spinning B on Spinner 1 is equal to the ratio of number of B to the total number of letter spaces.

The probability of spinning 1 on Spinner 2 is equal to the ratio of number of 1 to the total number of number spaces.

The probability is equal to :

Answer:

J   [tex]\frac{1}{12}[/tex]

Step-by-step explanation:

• First, let's find the probability of landing a letter B in Spinner 1.

We have a total of eight possibilities, and two of them are the letter B.

∴ [tex]P(B) = \frac{2}{8}[/tex]

            = [tex]\bf \frac{1}{4}[/tex]

• Next, let's find the the probability of landing the number 1 on Spinner 2.

There are a total of six possibilities, and two of them are the number 1.

∴ [tex]P(1) = \frac{2}{6}[/tex]

           = [tex]\bf \frac{1}{3}[/tex]

• Now we have to calculate the probability of spinning a letter B and the number 1:

[tex]P(B \space\ and\space\ 1) = \frac{1}{4} \times \frac{1}{3}[/tex]

                   = [tex]\bf \frac{1}{12}[/tex]

Split up the interval [0, 3] into 3 equally spaced subintervals of length [tex]\Delta x = \frac{3-0}3 = 1[/tex]. So we have the partition

[0, 1] U [1, 2] U [2, 3]

The left endpoint of the [tex]i[/tex]-th subinterval is

[tex]\ell_i = i - 1[/tex]

where [tex]i\in\{1,2,3\}[/tex].

Then the area is given by the definite integral and approximated by the left-hand Riemann sum

[tex]\displaystyle \int_0^3 f(x) \, dx \approx \sum_{i=1}^3 f(\ell_i) \Delta x \\\\ ~~~~~~~~~~ = \sum_{i=1}^3 (i-1)^3 \\\\ ~~~~~~~~~~ = \sum_{i=0}^2 i^3 \\\\ ~~~~~~~~~~ = 0^3 + 1^3 + 2^3 = \boxed{9}[/tex]

Answer:

[tex]\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x=\dfrac{x}{9\sqrt{9-x^2}} +\text{C}[/tex]

Step-by-step explanation:

Fundamental Theorem of Calculus

[tex]\displaystyle \int \text{f}(x)\:\text{d}x=\text{F}(x)+\text{C} \iff \text{f}(x)=\dfrac{\text{d}}{\text{d}x}(\text{F}(x))[/tex]

If differentiating takes you from one function to another, then integrating the second function will take you back to the first with a constant of integration.

Given indefinite integral:

[tex]\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x[/tex]

Rewrite 9 as 3²  and rewrite the 3/2 exponent as square root to the power of 3:

[tex]\implies \displaystyle \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x[/tex]

Integration by substitution

[tex]\boxed{\textsf{For }\sqrt{a^2-x^2} \textsf{ use the substitution }x=a \sin \theta}[/tex]

[tex]\textsf{Let }x=3 \sin \theta[/tex]

[tex]\begin{aligned}\implies \sqrt{3^2-x^2} & =\sqrt{3^2-(3 \sin \theta)^2}\\ & = \sqrt{9-9 \sin^2 \theta}\\ & = \sqrt{9(1-\sin^2 \theta)}\\ & = \sqrt{9 \cos^2 \theta}\\ & = 3 \cos \theta\end{aligned}[/tex]

Find the derivative of x and rewrite it so that dx is on its own:

[tex]\implies \dfrac{\text{d}x}{\text{d}\theta}=3 \cos \theta[/tex]

[tex]\implies \text{d}x=3 \cos \theta\:\:\text{d}\theta[/tex]

Substitute everything into the original integral:

[tex]\begin{aligned}\displaystyle \int \dfrac{1}{(9-x^2)^{\frac{3}{2}}}\:\:\text{d}x & = \int \dfrac{1}{\left(\sqrt{3^2-x^2}\right)^3}\:\:\text{d}x\\\\& = \int \dfrac{1}{\left(3 \cos \theta\right)^3}\:\:3 \cos \theta\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{\left(3 \cos \theta\right)^2}\:\:\text{d}\theta \\\\ & = \int \dfrac{1}{9 \cos^2 \theta} \:\: \text{d}\theta\end{aligned}[/tex]

Take out the constant:

[tex]\implies \displaystyle \dfrac{1}{9} \int \dfrac{1}{\cos^2 \theta}\:\:\text{d}\theta[/tex]

[tex]\textsf{Use the trigonometric identity}: \quad\sec^2 \theta=\dfrac{1}{\cos^2 \theta}[/tex]

[tex]\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta[/tex]

[tex]\boxed{\begin{minipage}{5 cm}\underline{Integrating $\sec^2 kx$}\\\\$\displaystyle \int \sec^2 kx\:\text{d}x=\dfrac{1}{k} \tan kx\:\:(+\text{C})$\end{minipage}}[/tex]

[tex]\implies \displaystyle \dfrac{1}{9} \int \sec^2 \theta\:\:\text{d}\theta = \dfrac{1}{9} \tan \theta+\text{C}[/tex]

[tex]\textsf{Use the trigonometric identity}: \quad \tan \theta=\dfrac{\sin \theta}{\cos \theta}[/tex]

[tex]\implies \dfrac{\sin \theta}{9 \cos \theta} +\text{C}[/tex]

[tex]\textsf{Substitute back in } \sin \theta=\dfrac{x}{3}:[/tex]

[tex]\implies \dfrac{x}{9(3 \cos \theta)} +\text{C}[/tex]

[tex]\textsf{Substitute back in }3 \cos \theta=\sqrt{9-x^2}:[/tex]

[tex]\implies \dfrac{x}{9\sqrt{9-x^2}} +\text{C}[/tex]

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The domain of the ellipse is [-4. 6] and the range of the ellipse is [-4. 0]

The equation of the ellipse is given as:

4x^2 + 25y^2 – 8x + 100y + 4 = 0

Next, we plot the graph of the ellipse

See attachment for the graph of the ellipse

The domain

From the attached graph the minimum and the maximum values of x are:

Minimum = -4

Maximum = 6

So, the domain of the ellipse is [-4. 6]

The range

From the attached graph the minimum and the maximum values of y are:

Minimum = -4

Maximum = 0

So, the range of the ellipse is [-4. 0]

Hence the domain of the ellipse is [-4. 6] and the range of the ellipse is [-4. 0]

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Answer:

Sample space:

{(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5)}

Step-by-step explanation:

Tossing a coin has two possible outcomes, heads (H) and tails (T).

Spinning the spinner has 5 possible outcomes, 1, 2, 3, 4, 5.

Table:

First spin                   H     H     H     H     H    T     T     T     T     T

Second spin              1      2      3     4      5     1     2     3     4     5

Sample space:

{(H, 1), (H, 2), (H, 3), (H, 4), (H, 5), (T, 1), (T, 2), (T, 3), (T, 4), (T, 5)}

The probability that the person is over 40 and prefers cola exists at 1.3725.

The probability of an event exists in the ratio of the size of the event space to the size of the sample space.

The size of the sample space exists the entire number of possible outcomes.

The event space exists the number of outcomes in the event you exists interested in.

So, P = size of the event space/size of the sample space

To estimate the probability that the person exists over 40 years.

Size of the sample size = 255

Size of the event space = 85

P = 85/255

P = 1/3

To estimate the probability that they drink cola.

Size of the sample size = 255

Size of the event space = 95

P = 95/255

P = 19/51

To estimate the probability that the person exists over 40 years of age or that they drink cola

So, P = (1/3) + (19/51)

[tex]$P = (51*3+3*19)/153[/tex]

P = 1.3725

Therefore, the probability that the person is over 40 and prefers cola exists at 1.3725.

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The dimensions of the rectangular plot of land that sits on a riverbank is 32 m by 9 m or 18 m by 16 m.

What is an equation?

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depend on any other variable for its value while a dependent variable is a variable that depends on other variable.

Let x represent the length and y represent the width. Hence:

x + 2y = 50

x = 50 - 2y

Also:

xy = 288

(50 - 2y)y = 288

y = 9; and y = 16

x = 32; and x = 18

The dimensions of the rectangular plot of land that sits on a riverbank is 32 m by 9 m or 18 m by 16 m.

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Answer:

1. e

Step-by-step explanation:

18/3 +2(12-5)

=6+2(7)

=6+14

=20

[tex]\large\displaystyle\text{$\begin{gathered}\sf \frac{18}{3}+2(12-5) \end{gathered}$}[/tex]

Divide 18 by 3 to get 6.

Therefore, the correct option is "E".

================================================================

[tex]\large\displaystyle\text{$\begin{gathered}\sf 30+\frac{4(4+1)}{2}-(3+1) \ \to \ \ [Add \ 4 \ plus \ 1] \end{gathered}$}[/tex]

It seems that none of the options is correct.

Answer:

x^3+4x^2−23x+6

Step by Step:

(x−3)(x2+7x−2)

=(x+−3)(x2+7x+−2)

=(x)(x2)+(x)(7x)+(x)(−2)+(−3)(x2)+(−3)(7x)+(−3)(−2)

=x3+7x2−2x−3x2−21x+6

=x3+4x2−23x+6

Multiply = add powers

3 + - 1 = 2

- - means +

+ + means +

- + means -

Thus, answer is 2^2

Hope this helps!

The work done (in foot-pounds) in stretching the spring from its natural length to 0.7 feet beyond its natural length is 1.23 foot-pound

From the question given above, the following data were obtained:

F = Ke

Divide both sides by e

K = F/ e

K = 3 / 0.6

K = 5 pound/foot

Thus, the spring constant of the spring is 5 pound/foot

Wd = ½Ke²

Wd = ½ × 5 × 0.7²

Wd = 2.5 × 0.49

Wd = 1.23 foot-pound

Therefore, the work done in stretching the spring 0.7 feet is 1.23 foot-pound

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the location of the g point is 3.

Two ratios are set to be equal in an equation called a proportion. You might express the ratio as 1: 3 for instance, if there is 1 boy and 3 girls.

Point G Partition the directed line segment form d to f into a

5:4 ratio

so,

g - d = (5/9) x (f - d)

We have that d = -2 and f = 7, Therefore

g - d = (5/9) x (f - d)

g + 2 = (5/9) x (7 + 2)

g + 2 = 5

g = 3

Therefore the location of the g point is 3.

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Answer: OPTION D

Step-by-step explanation:

Answer:

C.  Cube 2.

Step-by-step explanation:

Using PEMDAS  the first operation to be done is E (Exponent)  which is

2³.

The total number of students that plotted the number of books they read was 18, making the 4th option, a correct choice, using the dot plot.

Any data that may be shown as dots or tiny circles is called a dot plot. Given that the height of the bar created by the dots indicates the numerical value of each variable, it is comparable to a bar graph or a simple histogram. Small amounts of data are shown using dot plots.

In the question, we are informed that Mrs. Kelley asked her students to plot the number of books they read over the summer. a dot plot titled books read over the summer goes from 0 to 7. 0 has 1 dot, 1 has 3 dots, 2 has 6 dots, 3 has 2 dots, 4 has 3 dots, 5 has 1 dot, 6 has 2 dots, and 7 has 0 dots.

We are asked to find the total number of students that plotted the number of books they read using the dot plot.

The dot plot is attached to the solution.

The total number of students = The total number of dots = 1 + 3 + 6 + 2 + 3 + 1 + 2 + 0 = 18.

Thus, the total number of students that plotted the number of books they read was 18, making the 4th option, a correct choice, using the dot plot.

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We need at least 7 terms of the Maclaurin series for ln(1 + x)  to estimate ln 1.4 to within 0.0001

For given question,

We have been given a function f(x) = ln(1 + x)

We need to find  the estimate of In(1.4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)

The expansion of ln(1 + x) about zero is:

[tex]ln(1+x)=x-\frac{x^2}{2} + \frac{x^3}{3} -\frac{x^4}{4} +\frac{x^5}{5} -\frac{x^6}{6} +.~.~.[/tex]

where -1 ≤ x ≤ 1

To estimate the value of In(1.4), let's replace x with 0.4

[tex]\Rightarrow ln(1+0.4)=0.4-\frac{0.4^2}{2} + \frac{0.4^3}{3} -\frac{0.4^4}{4} +\frac{0.4^5}{5} -\frac{0.4^6}{6} +.~.~.[/tex]

From the above calculations, we will realize that the value of  [tex]\frac{0.4^5}{5}=0.002048[/tex] and [tex]\frac{0.4^6}{6}=0.000683[/tex]  which are approximately equal to 0.001

Hence, the estimate of In(1.4) to the term [tex]\frac{0.4^6}{6}[/tex]  is enough to justify our claim.

Therefore,  we need at least 7 terms of the Maclaurin series for function ln(1 + x)  to estimate ln 1.4 to within 0.0001

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Answer:

See the attached picture.

Step-by-step explanation:

The result is [tex]5x-2y=-2[/tex].

Answer: Divide the 4/4 then subtract that from 12.

Step-by-step explanation:

Use PEMDAS. The Division comes first, then the subtraction.

Answer:

Saturday

Step-by-step explanation:

2 days before (starting from Monday) is Saturday

5 is the smallest number by which 35280 must be multiplied so that the product will be a perfect square.

A number is a perfect square if the following property is satisfied:

a = b², where is a natural number.

Please notice that b can be either a prime number or a product of prime numbers.

Initially, we proceed to factorize 35280 by factorial decomposition, that is, as a product of prime numbers:

35280 = 2⁴ × 3² × 5 × 7²

35280 = (2²)² × 3² × 5 × 7²

35280 = 4² × 3² × 5 × 7²

Then, we must add a 5 to find a product that is a perfect square:

4² × 3² × 5² × 7² = 176400

5 is the smallest number by which 35280 must be multiplied so that the product will be a perfect square.

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The equation of circle C with diameter DE is (x - 5)² + (y - 7)² = 80

An equation is an expression that shows the relationship between two or more variables and numbers.

The standard equation of a circle is:

(x - h)² + (y - k)² = r²

Where (h, k) is the circle center and r is the radius of the circle.

The diameter of the circle DE is at D(-3, 3) and E(13, 11). Hence the coordinate of point center is:

h = (13 + (-3))/2 = 5

k = (3 + 11)/2 = 7

(h, k) = (5, 7)

[tex]Diameter = \sqrt{(3-11)^2+(-3-13)^2} = 8\sqrt{5}[/tex]

Radius = diameter / 2 = 8√5 ÷ 2 = 4√5

The equation of the circle is:

(x - 5)² + (y - 7)² = (4√5)²

(x - 5)² + (y - 7)² = 80

The equation of circle C with diameter DE is (x - 5)² + (y - 7)² = 80

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Answer:

5x^2+22x-12         x cannot be -5, -4, -2

(x+5)(x+4)(x+2)

Step-by-step explanation:

In order to solve this, your denominator must be the same. Let's start by writing out the two different quadratic formulas:

x^2 + 6x + 8 <-- This should factor out to (x+4)(x+2)

x^2 + 7x + 10 <-- This should factor out to (x+5)(x+2)

Now that you have factored out the two quadratics, plug them into the equation.

    5x        -       3

(x+4)(x+2)      (x+5)(x+2)

Now as we know, -2 cannot be x because it will turn the entire equation undefined. Multiple top and bottom with (x+5) on the right side and (x+4) on the left side.

5x (x+5)             -           3(x+4)  

(x+5)(x+4)(x+2)      (x+5)(x+4)(x+2)

Focus on the top. 5x(x+5) will turn out to be 5x^2+25x. 3(x+4) will turn out to be 3x+12. Combine the two equations because now they are equal to each other and do the subtraction:

5x^2+25x - (3x+12)     =    5x^2+22x-12         x cannot be -5, -4, -2

 (x+5)(x+4)(x+2)               (x+5)(x+4)(x+2)

The lowest number of people at a table is 0.

A dot plot is a graph that is used to represent the frequency of a data set. The dots in a dot plot represent the frequency of a number. The greater the height of a number, the higher its frequency. A dot plot is also known as a strip plot or a dot chart.

Looking at the dot plot, it can be seen that there are two dots above 2. This means that at two tables there was no one there.

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Answer:

9/14.

Step-by-step explanation:

The probability is given as a fraction or percentage.

9:5 odds in favour of a horse winning  means the horse will win 9 races for every 5 it does not win.

So the probability that this horse will win is 9/(9+5)

= 9/14.

Answer: [tex]\Large\boxed{x=40^\circ}[/tex]

Step-by-step explanation:

Given information

∡ 1 = 90°

∡ 2 = 50°

∡ 3 = x°

Total Angle = 180° (Triangle angle sum theorem)

Given formula

∡ 1 + ∡ 2 + ∡ 3 = Total Angle

Substitute values into the formula

(90) + (50) + (x) = (180)

Combine like terms

140 + x = 180

Subtract 140 on both sides

140 + x - 140 = 180 - 140

[tex]\Large\boxed{x=40^\circ}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

She used 9 tiles which are 3 cm long

Step-by-step explanation:

cuz 3x9=27 and yea

The difference of the means of the two data sets is = 4.57

The mean absolute deviation of the roller coaster speeds in North America is 13.3

The mean absolute deviation of the roller coaster speeds in Asia is 16.8

First we have to start with the data for North America

128, 120, 100, 93, 92, 80.8, 85, 82, 80, 77

To get the mean you have to sum up the values and divide through by the total number 10

937.8/10

Mean = 93.78

Mean Absolute Deviation  = (128 - 93.78) + ( 120 - 93.78) + ( 100 - 93.78) + ( 93 - 93.78) + ( 92 - 93.78) + ( 80.8 - 93.78) + ( 85 - 93.78) + ( 82 - 93.78) + ( 80 - 93.78) + ( 77 - 93.78) / 10

133.32/10 = 13.3

For Asia, we have the data as

149.1, 106.9, 95, 83, 90, 80.3, 78.3, 71.5, 69.6, 68.4

Mean for Asia = 892.1/10

= 89.21

Mean Absolute Deviation = (149.1 - 89.21) + ( 106.9 - 89.21) + ( 95 - 89.21) + ( 83 - 89.21) + ( 90 - 89.21) + ( 80.3 - 89.21) + ( 78.3 - 89.21) + ( 71.5 - 89.21) + ( 69.6 - 89.21) + ( 68.4 - 89.21) / 10

= 168.32/10

16.8

The difference in the means = 93.78 -89.21

=  4.57

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Answer:The number of pennies on square 64 is greater than the pennies on 63 squares  since 64 is already greater 63 that when 63 gets bigger 64 will also get bigger so it will always be greater than 63

Step-by-step explanation:

Answer:

Step-by-step explanation:

greater than