What is the perimeter of a rectangle with side lengths of 12in and 8in?

The mode, on the other hand, would not be a useful measure in this case, as it represents the most commonly occurring salary value.

In statistics, the mean (also known as the arithmetic mean or average) is a measure of central tendency that represents the sum of a set of numbers divided by the total number of numbers in the set.

For the salary of players on a professional baseball team, I would be more interested in looking at the mean.

The reason for this is that salaries of professional baseball players are typically not evenly distributed, with a few highly paid players at the top end and many players with lower salaries. The mean salary would provide an average value that takes into account the full range of salaries on the team, including the highly paid players.

The median salary would also be a reasonable measure to use in this case, as it represents the middle value of the distribution when the salaries are arranged in order from lowest to highest. However, it may not be as informative as the mean in capturing the full range of salaries and the distribution of highly paid players.

The mode, on the other hand, would not be a useful measure in this case, as it represents the most commonly occurring salary value, and it is unlikely that there would be many identical salaries among the players.

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Complete question is

For the following type of data set, would you be more interested in looking at the mean, median, or mode? state your reasoning.

The salary of players on a professional baseball team.

The correlation between x₁ + x₂ and x₂ + x₃ is 1

The correlation between x₁ +x₂ and x₃ + x₄ is 0

Correlation is a measure of the strength and direction of the linear relationship between two random variables.

It is a statistical concept that is widely used in data analysis and research to explore and quantify the association between two variables.

Here  we have

x₁ x₂ x₃ and x₄ are (pairwise) uncorrelated random variables, each having to mean of 0 and variance of 1,

(a) x₁ + x₂ and x₂ + x₃.

We have

Cov(x₁+ x₂, x₂ + x₃) = Cov(x₁, x₂) + Cov(x₁, x₃) + Cov(x₂, x₂) + Cov(x₂, x₃)

= 0 + 0 + Var(x₂) + 0 = 1.

Since, Var(x₁ + x₂) = Var(x₁) + Var(x₂) + 2 Cov(x₁, x₂) = 1 + 1 + 2 · 0 = 2.

Similarly Var(x₂ + x₃) = 0.

So the correlation between x₁ + x₂ and x₂+ x₃ is

ρ(x₁ + x₂, x₂ + x₃) = Cov(x₁ + x₂, x₂ + x₃)

p = Cov(x₁ + x₂, x₂ + x₃)/ √Var(x₁ + x₂) Var(x₂ + x₃) = 1/√2× 2 = 1/2

(b) x₁+ x₂ and x₃ + x₄.

Cov(x₁ + x₂, x₃+ x₄) = Cov(x₁, x₃) + Cov(x₁, x₄) + Cov(x₂, x₃) + Cov(x₂, x₄)

= 0 + 0 + 0 + 0 = 0

The correlation between x₁ +x₂ and x₃ + x₄ is 0

Therefore,

The correlation between x₁ + x₂ and x₂ + x₃ is 1

The correlation between x₁ +x₂ and x₃ + x₄ is 0

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The length of the curve is [tex]e^ \pi[/tex] - 1 units.

To find the length of the curve [tex]x = e^t cos(t), y = e^tsin(t)[/tex], where 0 ≤ t ≤ π.

In this case, the curve is defined by the equations [tex]x = e^t cos(t)[/tex] and [tex]y = e^t sin(t)[/tex], where t is the variable that represents the parameter along the curve.

To find the length of this curve, we can use a formula known as the arc length formula.

L = ∫[a,b] √〖[dx/dt]〗² + 〖[dy/dt]² dt

where L represents the length of the curve, a and b are the starting and ending values of the parameter, dx/dt and dy/dt are the derivatives of x and y with respect to t.

To find the derivatives dx/dt and dy/dt. Using the product rule and chain rule of differentiation, we get:

[tex]dx/dt = e^tcos(t) - e^t sin(t) dy/dt = e^t sin(t) + e^t cos(t)[/tex]

Substituting these expressions into the arc length formula and simplifying, we get: L = ∫[0,π] [tex]e^tdt[/tex]

Integrating this expression with respect to t, we get: L = [tex]e^\pi[/tex]- 1

So the length of the curve is [tex]e^ \pi[/tex] - 1 units.

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An equation to describe the relationship between a and b is b = (3/8)a.

In Mathematics and Geometry, a proportional relationship refers to a type of relationship that produces equivalent ratios and it can be modeled or represented by the following mathematical equation:

y = kx

Where:

Next, we would determine the constant of proportionality (k) by using various data points as follows:

Constant of proportionality, k = y/x

Constant of proportionality, k = 3/8 = 9/24 = 15/40

Constant of proportionality, k = 3/8.

Therefore, the required linear equation is given by;

y = kx

y = 3/8(x) ≡ b = 3/8(a)

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

b= 3/8a

Step-by-step explanation:

The average value of the function [tex]f(x) = x^{(1/2)[/tex] on the interval [0, 25] is 50.

An input and an output are connected by a function. It functions similarly to a machine with an input and an output. Additionally, the input and output are somehow connected. The traditional format for writing a function is f(x) "f(x) =... "

To find the average value fave of the function [tex]f(x) = x^{(1/2)[/tex] on the interval [0, 25], we need to use the following formula:

fave = (1/(b-a)) * ∫(a to b) f(x) dx

where a and b are the endpoints of the interval [0, 25].

Substituting the values for a, b, and f(x), we get:

fave = (1/(25-0)) * ∫(0 to 25) [tex]x^{(1/2)[/tex] dx

Using the power rule of integration, we can simplify the integral:

fave = (2/50) * [[tex]x^{(3/2)/(3/2)[/tex]] from 0 to 25

fave = (4/50) * [[tex]25^{(3/2)[/tex] - [tex]0^{(3/2)[/tex]]

fave = (4/50) * ([tex]25^{(3/2)[/tex])

fave = 10√25

fave = 10(5)

fave = 50

Therefore, the average value of the function [tex]f(x) = x^{(1/2)[/tex] on the interval [0, 25] is 50.

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Answer:

3:1

Step-by-step explanation:

(i) T-interval

(ii) F. Because I don't have a large number of professors and I don't know the standard deviation of all FSU professors' heights.

What is standard deviation?

Standard deviation is a measure of the amount of variation or dispersion of a set of data values from the mean value.

When constructing a confidence interval for the mean of a population using a sample, we use either a Z-interval or a T-interval based on the sample size and whether we know the population standard deviation.

If the sample size is large (usually taken to be greater than or equal to 30) and/or we know the population standard deviation, then we can use a Z-interval.

However, if the sample size is small (usually less than 30) and/or we don't know the population standard deviation, we should use a T-interval.

In this case, we don't have a large sample size (just the professors the student has this term), and we don't know the standard deviation of all FSU professors' heights, so we would use a T-interval.

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As per the inequality -0.4 < 0 which indicates that the low tide on Wednesday is also less than the typical low tide on Monday.

In this case, we can use the symbol < to indicate that the low tide on Tuesday morning is less than the low tide on Monday morning. This can be written as:

-0.8 < 0

The left-hand side of this inequality represents the low tide on Tuesday morning (-0.8 feet) and the right-hand side represents the typical low tide level on Monday morning (0 feet). The inequality indicates that the low tide on Tuesday is less than the typical low tide on Monday.

Similarly, we can compare the low tide on Wednesday morning to the low tide on Monday morning using the same inequality:

-0.4 < 0

In summary, we can use inequalities to compare the low tides on different days relative to a reference point. By using the typical low tide on Monday morning as the reference point, we can see that the low tides on Tuesday and Wednesday mornings are both lower than the typical low tide.

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The margin of error associated with the 95% confidence interval for the population mean volume is: D. 5.62.

To calculate the 95% confidence interval for the population mean volume, we can use the formula:

CI = x ± (t * (s/√n))

Where CI represents the confidence interval, x is the sample mean, t is the t-score associated with the desired confidence level (95%), s is the sample standard deviation, and n is the sample size.

In this case, x = 64 cc, s = 12 cc, and n = 20 orangutans. We need to find the t-score for a 95% confidence interval with 19 degrees of freedom (n-1). Using a t-table, we find that the t-score is approximately 2.093.

Now we can calculate the margin of error:

Margin of Error = t * (s/√n) = 2.093 * (12/√20) ≈ 5.62

Therefore, the margin of error associated with the 95% confidence interval for the population mean volume is: D. 5.62.

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Answer:

84

Step-by-step explanation:

A= Bh

Base is 12

Height is 7

= 84

Answer:

84

Step-by-step explanation:

The slope-intercept form for Angela's total cost of a pedicure and a massage as per the given data is equal to y = $0.75x + $35.

The slope of the line that represents the cost of the massage as a function of the number of minutes.

We know that a 20 minute massage costs $50, so the slope is,

slope = change in cost / change in minutes

         = ($50 - $35) / (20 - 0)

         = $15 / 20

         = $0.75 per minute

Now, let us use point-slope form to write the equation of the line,

y - $35 = $0.75(x)

where y is the total cost of the pedicure and massage,

$35 is the cost of the pedicure alone,

x is the number of minutes for the massage,

and $0.75 is the slope of the line.

Simplify this equation to slope-intercept form by adding $35 to both sides.

y = $0.75x + $35

Therefore, the equation in slope-intercept form for Angela's total cost of a pedicure and a massage is y = $0.75x + $35.

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The above question is incomplete, the complete question is:

Angela is getting a pedicure at a spa that also offers massages where customers pay by the minute. If Angela only gets a pedicure, it will cost her $35. If she pays for a 20 minute massage, it will cost her $50.

Write an equation in slope-intercept form where x represents the number of minutes for a massage and y represents Angela's total cost of a pedicure and a massage.

the approximation of the number of people who leave the building during the first 15 minutes of the evacuation drill using a right Riemann sum with three subintervals is 375 people.

To approximate the number of people who leave the building during the first 15 minutes of the evacuation drill using a right Riemann sum with three subintervals, we can divide the interval [0, 15] into three subintervals of equal width:

[0, 5], [5, 10], [10, 15]

The right Riemann sum is then given by:

Δt [f(5) + f(10) + f(15)]

where Δt is the width of each subinterval (Δt = 5), f(t) is the rate of people leaving the building at time t (in people per minute), and the values of f(t) are given in the table.

Plugging in the values, we get:

Δt [f(5) + f(10) + f(15)]

= 5 [20 + 25 + 30]

= 5 [75]

= 375

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Step-by-step explanation:

Every year you get 3 % of 1800 pounds added to the account

  what is 3% of 1800 ?         3 % is .03 in decimal form

     1800 * .03 = 54  pounds interest per year

in TWO years you will have   54 * 2   added to 1800 = 1908 pounds

Answer:

A). increase by 54  per year.

B). After two years the account has 1908

Step-by-step explanation:

A). 800 * 3% * 1 = 54

B). 1800 + 1800 * 3% * 2  = 1908

Hope this helps

Answer: 75%

Step-by-step explanation:

To find out what percent of daisies she gave away, we can use this formula: [tex] \textsf{(Number of Daisies she gave away  / Total number of Daisies) x 100} [/tex]

So, the fraction of daisies she gave away is:

[tex]\frac{15}{20}[/tex]

We can simplify this fraction by dividing both the numerator and denominator by 5:

[tex]\frac{15}{20} = \frac{3}{4}[/tex]

This means that Felicia gave away 3 out of every 4 daisies she picked.

To find the percentage, we multiply this fraction by 100:

[tex]\frac{3}{4}[/tex] [tex] \textsf{x 100 = 75} [/tex]

So, Felicia gave away 75% of the daisies she picked.

The expressions are as follows:

A' = {0,2,6,8,9}

B' = {0,1,7,8,9}

C' = {1,3,5,7}

(A ∩ B)' = {0,1,2,6,7,8,9}

A' ∩ B' = {0,8,9}

A' U B' = {0,1,2,6,7,8,9}

A U (B ∩ C) = {1,2,3,4,5,6,7}

Set theory is a branch of mathematical logic that studies set, which informally are collections of objects. Although any type of object can be collected into a set, set theory is applied most often to objects that are relevant to mathematics. The language of set theory can be used to define nearly all mathematical objects.

Let's break down the given expressions using set theory and the provided sets:

U = {0,1,2,3,4,5,6,7,8,9} (Universe)

A = {1,3,4,5,7}

B = {2,3,4,5,6}

C = {0,2,4,6,8,9}

A' denotes the complement of A, which means all the elements that are not in set A but are in the universe U.

A' = {0,2,6,8,9}

B' denotes the complement of B, which means all the elements that are not in set B but are in the universe U.

B' = {0,1,7,8,9}

C' denotes the complement of C, which means all the elements that are not in set C but are in the universe U.

C' = {1,3,5,7}

(A ∩ B)' denotes the complement of the intersection of sets A and B, which means all the elements that are not common in sets A and B but are in the universe U.

(A ∩ B) = {3,4,5}

(A ∩ B)' = {0,1,2,6,7,8,9}

A' ∩ B' denotes the intersection of sets A' and B', which means all the elements that are in both set A' and set B'.

A' ∩ B' = {0,8,9}

A' U B' denotes the union of sets A' and B', which means all the elements that are in either set A' or set B' or both.

A' U B' = {0,1,2,6,7,8,9}

A U (B ∩ C) denotes the union of set A and the intersection of sets B and C, which means all the elements that are in either set A or in the intersection of sets B and C or both.

(B ∩ C) = {2,4,6}

A U (B ∩ C) = {1,2,3,4,5,6,7}

Therefore, the expressions are as follows:

A' = {0,2,6,8,9}

B' = {0,1,7,8,9}

C' = {1,3,5,7}

(A ∩ B)' = {0,1,2,6,7,8,9}

A' ∩ B' = {0,8,9}

A' U B' = {0,1,2,6,7,8,9}

A U (B ∩ C) = {1,2,3,4,5,6,7}

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It takes the seagull less time to travel a longer distance.

The owl has a speed of 11 1/9 miles per hour.

The seagull has a speed of 18 3/4 miles per hour.

18 3/4 miles per hour is greater than 11 1/9 miles per hour, so the seagull is faster.

In Mathematics and Science, speed is the distance covered by a physical object per unit of time. In Mathematics and Science, the speed of any a physical object can be calculated by using this formula;

Speed = distance/time

Next, we would determine the speed of the owl as follows;

Speed of owl = (8 1/3)/(3/4)

Speed of owl = (25/3)/(3/4)

Speed of owl = 25/3 × 4/3

Speed of owl = 100/9 or 11 1/9 miles per hour.

For the speed of the seagull, we have:

Speed of seagull = (12 1/2)/(2/3)

Speed of seagull = (25/2)/(2/3)

Speed of seagull = 25/2 × 3/2

Speed of seagull = 75/4 or 18 3/4 miles per hour.

In conclusion, we can reasonably infer and logically deduce that the seagull is faster because it took less time to travel a longer distance.

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Missing information:

The question is incomplete and the complete question is shown in the attached picture.

Answer:

It takes the seagull LESS time to travel a LONGER distance.

A result is called statistically significant whenever it is unlikely to have occurred by chance alone, meaning that there is strong evidence to support the presence of a true effect or relationship.

This is often determined by a p-value less than a predetermined threshold, commonly set at 0.05, which indicates a less than 5% probability that the result is due to chance.

A result is called statistically significant whenever it is unlikely to have occurred by chance alone. This is typically determined by conducting a hypothesis test and calculating a p-value, which represents the probability of obtaining the observed result or a more extreme result if the null hypothesis (i.e. no difference between groups or no relationship between variables) is true.

If the p-value is below a predetermined significance level (often set at 0.05), then the result is considered statistically significant, meaning there is evidence to reject the null hypothesis and support the alternative hypothesis (i.e. there is a difference between groups or a relationship between variables).

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A numerical description of the outcome of an experiment is called a descriptive statistic.

Descriptive statistics are used to summarise and describe the data collected from an experiment, such as measures of central tendency (mean, median, mode) and measures of variability (range, standard deviation). These statistics help researchers understand the characteristics of their data and make inferences about the larger population from which the sample was taken. A random variable is a variable that takes on different values based on the outcome of a probability experiment. The probability function describes the likelihood of each possible outcome of the random variable. Variance measures how spread out the data is from the mean and is used in statistical analyses such as hypothesis testing and regression analysis.

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The total cost for the glass needed to replace the circular window with a diameter of 5 ft using double strength glass costing $3 per square foot will be $58.89.

The total cost for the glass needed to replace the circular window with a diameter of 5 ft can be calculated by finding the area of the circular window first. The formula for the area of a circle is A=πr^2, where r is the radius of the circle. In this case, the diameter is given as 5 ft, so the radius will be half of that, which is 2.5 ft.

Using the formula, we can calculate the area of the circular window as follows:

A = πr^2
A = π(2.5 ft)^2
A = 19.63 sq ft

Therefore, the total cost of double strength glass for the circular window will be:

Total cost = Cost per sq ft x Area
Total cost = $3 x 19.63 sq ft
Total cost = $58.89

So, the total cost for the glass needed to replace the circular window with a diameter of 5 ft using double strength glass costing $3 per square foot will be $58.89.

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The approximate area of the trapezoid is determined as  13.95 unit².

The approximate area of the trapezoid is calculated as follows;

Area = ¹/₂(b₁ + b₂)h

Where;

The y-coordinates of the points on the curve at x=3/2 and x=4 is calculated as follows;

y(3/2) = - (3/2)²/2 + 3/2 + 5

y(3/2) = -9/8 + 3/2 + 5

y(3/2) = 5.375

y(4) = -4²/2 + 4 + 5

y(4) = -8 + 9

y(4) = 1

h = 5.375 - 1 = 4.375

The approximate area of the trapezoid is calculated as;

Area = ¹/₂(5.375 + 1) x 4.375

Area = 13.95 unit²

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The standard deviation of the sampling distribution of the sample means will be equal to the standard deviation of the population divided by the square root of the sample size. Therefore, if the population standard deviation is 50 and the sample size is 25, then the standard deviation of the sampling distribution of the sample means will be 10.

The Central Limit Theorem (CLT) states that the sampling distribution of the sample means will approach a normal distribution as the sample size increases, regardless of the shape of the population distribution. This means that even if the population distribution is not normal, the distribution of the sample means will still be approximately normal as long as the sample size is sufficiently large (usually, a sample size greater than or equal to 30 is considered large enough).

Additionally, according to the CLT, the mean of the sampling distribution of the sample means will be equal to the mean of the population from which the samples are drawn. In this case, since the population mean is 150, the mean of the sampling distribution of the sample means will also be 150.

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Let's call the greater number "x" and the lesser number "y". According to the problem, we know that:

x - y = 48  (since the difference between the two numbers is 48)

y = (1/3)x   (since the lesser number is one third of the greater number)

Now we can substitute the second equation into the first equation:

x - (1/3)x = 48

Simplifying this equation, we get:

(2/3)x = 48

Multiplying both sides by 3/2, we get:

x = 72

Now that we know x, we can use the second equation to find y:

y = (1/3)x = (1/3)(72) = 24

So the two positive numbers are 72 and 24.

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The missing coordinates are:

K = (10, 10)

L = (20, 10)

M = (30, 10)

Given the graph is a straight line on coordinate plane.

We know that in Cartesian Coordinate plane if the points are on a straight line parallel to any Axis that is X axis or Y axis then the ordinate or the y-value of the coordinates of that points are equal for all.

Here we can see that the given graph has a line parallel to X axis and it is 10 units upwards from the X axis.

And it is clear from the graph that the coordinates of the point on the graph are given by,

K = (10, 10)

L = (20, 10)

M = (30, 10)

Hence the missing coordinates are 10, 10, 10.

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The question is incomplete. The complete question will be -

"K = (10,?) L = (?,20) M = (30,?) are on that line, too. Write their missing coordinates."

Answer:

Step-by-step explanation:

24/6 = 4

24/0.6 = 0.4?

24/6/10

24: 6/10

24 * 10/6

240/6 =40

False

1. The surface areas of the cones are;

1)  56.52 in²  2) 565.20ft²  3) 235.50 yd² 4) 898.04ft²   5) 942.00yd²

6) 75.36 in²   7) 1306.24yd²   8) 405.04in²  9. 339.12 ft²

2. The volumes of the cones are;

1) 84.78 in³  2). 564.15ft³  3) 4710yd³  4) 2712.96in³  5) 20.93ft³  6) 870.82yd³  7)  7846.86in³

3.  The volume of the cone-shaped Santa hat is 75.36in³.

For the normal cones, we use the formula  πr² + πrl to calculate the surface area.

(3.14 x 25) + (3.14x10x5) =  235.50 yd²

(3.14 x 121) + (3.14x15x11) = 898.04ft²

However, for cones like the ones in 6 and 8, we use a slightly different formula. √H² + r² = L first and then  π x r x (r + L).

For example  6.  H= 4in r=3in

⇒ √(4^2 + 3^2) =5

⇒  3.14 x 3 x (3 + 5) =75.36

To calculate the volume, we use the formula (V) = (1/3) x π x r² x H

For example,  H= 9in   r=3in ⇒

(1/3) x 3.14 x 3² x 9 = 84.78in³

The answers provided are based on the information in the picture;

1. Find the surface area of each cone. Round your answer to two decimal places ( use π = 3.14)

1. L = 7in  r=2in   2. L=11ft  r=9ft   3. L=10yd r=5yd   4. L=15ft  r=11ft

5. L=20yd  r=10yd   6.  L= 4in r=3in   7. L=19yd  r= 13yd   8. H=14in  r= 8in

9. L=12ft  r=6ft

2. Find the volume of each cone. Round to 2 decimal places. ( use π = 3.14).

1. H= 9in   r=3in     2. H= 11ft   r= 7ft     3. H=20yd   r=15yd  4. H=18in  r= 12in 5. H=5ft  r=2ft    6. H=13yd  r=8yd  7. H= 17in  r= 21

3. For Christmas, Lily make paper cones santa hat. If the height and radius of the cone are 8 inches and 3 inches respectively, what is the volume of the hat? ( use π = 3.14)

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The equations that are true for x = -2 and x = 2 are x² – 4 = 0 and 4x² = 16. So, correct options are A and D.

The solutions for the equations when x = -2 and x = 2 can be found by substituting these values of x into the equations and simplifying.

For x² – 4 = 0, substituting -2 and 2 for x gives (-2)² – 4 = 0 and (2)² – 4 = 0, which are both true. Therefore, this equation is true for x = -2 and x = 2.

For x² = –4, substituting -2 and 2 for x gives (-2)² = –4 and (2)² = –4, which are both false. Therefore, this equation is not true for x = -2 and x = 2.

For 3x² + 12 = 0, substituting -2 and 2 for x gives 3(-2)² + 12 = 0 and 3(2)² + 12 = 0, which are both false. Therefore, this equation is not true for x = -2 and x = 2.

For 4x² = 16, substituting -2 and 2 for x gives 4(-2)² = 16 and 4(2)² = 16, which are both true. Therefore, this equation is true for x = -2 and x = 2.

For 2(x – 2)² = 0, substituting -2 and 2 for x gives 2(-2 – 2)² = 0 and 2(2 – 2)² = 0, which are both true. Therefore, this equation is true for x = -2 and x = 2.

Therefore, correct options are A and D.

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If the alternative hypothesis is that the proportion of items in population 1 is larger than the proportion of items in population 2, then the null hypothesis should be that there is no significant difference in the proportion of items between population 1 and population 2.

Based on the information provided, the null hypothesis should be:

The null hypothesis is that the proportion of items in population 1 is less than or equal to the proportion of items in population 2.

This is denoted as H₀: P₁ ≤ P₂. The alternative hypothesis, as you mentioned, is that the proportion of items in population 1 is larger than the proportion of items in population 2, which is represented as H₁: P₁ > P₂.

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Part A: Sky View - median = 5.5, Riverside - median = 5.5

Part B: Sky View - range = 99, Riverside - range = 78

Part C: Sky View has a larger class size on average (12 vs 10), so it may be a better choice if a larger class size is desired.

Part A: Measures of Center

For Sky View School:

Mean: sum of values / number of values [tex]= (5 + 6 + 99 + 7 + 2 + 0) / 6 = 119 / 6 = 19.83[/tex]

Median: arrange the values in ascending order: 0, 2, 5, 6, 7, 99. The median is 6.5.

Mode: there is no mode as all values occur only once.

For Riverside School:

Mean: sum of values / number of values [tex]= (1 + 0 + 2 + 4 + 5 + 6 + 78 + 7 + 6 + 5 + 5 + 5 + 4 + 3 + 1 + 0) / 16 = 133 / 16 = 8.31[/tex]Median: The median is equal to the average of each of the middle values [tex](5 + 5 / 2 = 5)[/tex], which is 5.

Mode: the mode is 5 as it occurs most frequently.

Part B: Measures of Variability

For Sky View School:

Range: maximum value - minimum value = 99 - 0 = 99

Variance: [tex]((5-19.83)^2 + (6-19.83)^2 + (99-19.83)^2 + (7-19.83)^2 + (2-19.83)^2 + (0-19.83)^2) / (6-1) = 2134.4[/tex].

Standard deviation: approximately 46.2.

For Riverside School:

Range: maximum value - minimum value = 78 - 0 = 78

Variance: [tex]((1-8.31)^2 + (0-8.31)^2 + (2-8.31)^2 + (4-8.31)^2 + (5-8.31)^2 + (6-8.31)^2 + (78-8.31)^2 + (7-8.31)^2 + (6-8.31)^2 + (5-8.31)^2 + (5-8.31)^2 + (5-8.31)^2 + (4-8.31)^2 + (3-8.31)^2 + (1-8.31)^2 + (0-8.31)^2) / (16-1) = 422.3.[/tex]

Standard deviation: approximately 20.55.

Part C: Answer with Explanation

If you are interested in a larger class size, Riverside School may be a better choice. This is because the mean and median class sizes at Riverside School are both smaller than those at Sky View School, indicating that the typical class size is smaller at Riverside. Additionally, the range and standard deviation of class sizes at Riverside School are smaller than those

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The probability of rolling a higher number on the second roll is 15/36 or approximately 0.42.

When rolling a die, each roll has an equal chance of landing on any of the six possible outcomes. Therefore, the probability of rolling any specific number on the first roll is 1/6, and the probability of rolling a number higher than the first on the second roll is also 1/6.

To find the probability of both events happening, we can use the multiplication rule of probability, which states that the probability of two independent events occurring together is equal to the product of their individual probabilities.

So, the probability of rolling a number on the first roll and then rolling a higher number on the second roll is:

P = (1/6) x (1/6)

However, since the question doesn't specify a particular number for the first roll, we need to consider all the possible outcomes for the first roll. These outcomes are mutually exclusive and have an equal chance of happening, so we can add their probabilities to find the overall probability of rolling a higher number on the second roll:

P = (1/6) x (5/6) + (1/6) x (4/6) + (1/6) x (3/6) + (1/6) x (2/6) + (1/6) x (1/6) + (1/6) x 0

Simplifying this expression, we get:

P = 15/36

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