The research is important for the students because it helps them to have a detailed analysis of everything. When you have a proper in-depth analysis of any topic, the result comes out to be fruitful and also the knowledge is enhanced.
The research is important for the students because it helps them to have a detailed analysis of everything. When you have a proper in-depth analysis of any topic, the result comes out to be fruitful and also the knowledge is enhanced.
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A line of best fit was drawn for the scatter plot below.
Determine the residuals associated with the following x-values.
The residuals which are associated with the given x values are as follows;
1). For x = 1; Residual = 0.2). For x = 2; Residual = 1.3). For x = 3; Residual = -1.4). For x = 4; Residual = 0.5.5). For x = 5; Residual = 0.What are residuals of a scatter plot?A residual is the difference between what is plotted on a scatter plot at a specific point, and what the regression equation (straight line) predicts "should be plotted" at this specific point.
Consequently, the residuals in each case are;
1). For x = 1; Residual = 1 - 1 = 0.
2). For x = 2; Residual = 3 - 2 = 1.
3). For x = 3; Residual = 2 - 3 = -1.
4). For x = 4; Residual = 4.5 - 4 = 0.5.
5). For x = 5; Residual = 5 - 5 = 0.
Ultimately, the residual values are as listed above.
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Mike paid $12 dollars for 3 hamburgers how much does each hamburger cost
the sides of a parallelogram are 11 feet and 17 feet. the longer diagonal is 22 feet. find the length of the shorter diagonal.
Length of the shorter diagonal of the parallelogram will be 18.46 feet
Let the Parallelogram ABCD with BD and AC as it’s diagonal
According to the question,
AB = 17 feet
AD = 11 feet
As the opposite sides of a parallelogram are parallel and equal
Therefore, AB = CD = 17 feet
AD = BC = 11 feet
Also the longer diagonal, BD = 22 feet
In triangle BCD, using cosine formula
[tex]BD^{2}[/tex] = [tex]CD^{2}[/tex] + [tex]BC^{2}[/tex]- 2BC.CD.CosC
[tex]22^{2}[/tex] = [tex]17^{2}[/tex] + [tex]11^{2}[/tex] - 2(11)(17)Cos C
484 = 289 + 121 - 374CosC
-0.197 = Cos C
C = arc Cos(-0.197)
Therefore, C = [tex]110^{0}[/tex]
Now ∠C + ∠D = [tex]180^{0}[/tex]
101+ ∠D = 180
∠D = [tex]79^{0}[/tex]
Now, in triangle ADC
[tex]AC^{2}[/tex] = [tex]AD^{2}[/tex] + [tex]CD^{2}[/tex] - 2AD.CD.CosD
[tex]AC^{2}[/tex] = [tex]11^{2}[/tex] + [tex]17^{2}[/tex] - 2(11)(17)Cos79
[tex]AC^{2}[/tex] = 121 + 289 - 374Cos79
[tex]AC^{2}[/tex] = 410 -364(.19)
[tex]AC^{2}[/tex] = 340.84
AC = sqrt(340.84)
AC = 18.46
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Barry wants to buy chickens. He has enough room for up to 12 chickens. Each hen costs $5 and each rooster costs $6. Barry doesn't want to spend more than $50. Write a system of inequalities to represent this scenario where x represents the number of hens and y represents the number of roosters.
The system of inequalities to represent this scenario for Barry will be:
x + y = 12
5x + 6y ≤ 50
What is an inequality?Inequalities are created through the connection of two expressions. It should be noted that the expressions in an inequality aren't always equal. Inequalities implies that the expressions are not equal. They are denoted by the symbols ≥ < > ≤.
Let x represents the number of hens.
Let y represents the number of roosters.
The inequality will be:
5(x) + 6(y) ≤ 50
5x + 6y ≤ 50
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if f(x) is an even function, which statement about the graph of f(x) must be true? it has rotational symmetry about the origin. it has line symmetry about the line y
If function f(x) is even then so the graph of this function has a line symmetry about y-axis. So the option 3 is correct.
In the given question we have to check which statement is correct.
If f(x) is an even function, which statement about the graph of f(x) must be true.
The given statement are;
It has a rotational symmetry about the originIt has line symmetry about the line y=xIt has line symmetry about the y-axisIt has line symmetry about the x-axisAs we know that if function f(x) is even then so the graph of this function has a line symmetry about y-axis.
So the option 3 is correct.
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apply the karatsuba multiplication procedure for the product: 1234 x 4321. bring this 4-digit multiplication down to 1-digit multiplication and then multiply. use the method discussed in the class.
The solution of 1234 x 4321 using Karatsuba multiplication is 5332114
Given,
1234 x 4321
We have to find the solution using Karatsuba multiplication;
Karatsuba multiplication;
The first multiplication algorithm that was asymptotically quicker than the quadratic "grade school" technique was the Karatsuba algorithm. For sufficiently big n, the Schönhage-Strassen algorithm (1971) is even faster than the Toom-Cook algorithm (1963), which is a faster generalisation of Karatsuba's approach.
Here,
1234 x 4321
Lets see,
12 + 34 = 46
× × ×
43 + 21 = 64
2944 -
516 + 714 = 1230
1714
Now,
516 × 100² + 714 + 1714 x 100 = 5332114
That is,
The solution of 1234 x 4321 using Karatsuba multiplication is 5332114
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How do you know if a limit is infinity or negative infinity?.
the limit will go to infinity or negative infinity (depending on the sign of the function).
How do you know if a limit is infinity or negative infinity?
The limit as x approaches zero would be negative infinity, since the graph goes down forever as you approach zero from either side: As a general rule, when you are taking a limit and the denominator equals zero, the limit will go to infinity or negative infinity (depending on the sign of the function).
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determine whether the series is convergent or divergent. if it is convergent, find its sum. (if the quantity diverges, enter diverges.) 1/3+ 2/9+1/27+2 81+1/243+2/729+...
The series is convergent with sum 5/8
A series is said to be convergent, if it converges to a value as the terms of series tends to infinity.
A series is said to divergent, it it does not converge to a value but keeps on either increasing or decreasing as the terms of series tends to infinity.
In the question ,
[tex]\frac{1}{3} +\frac{2}{9} + \frac{1}{27} +\frac{2}{81}+..[/tex] is given series
dividing the series into two parts ,
[tex](\frac{1}{3} +\frac{1}{27} +\frac{1}{243}+..)[/tex] + [tex](\frac{2}{9} + \frac{2}{81} + \frac{2}{729}+...)[/tex]
Using infinite geometric series formula both the side ,
=> [tex]\frac{\frac{1}{3}}{1- \frac{1}{9}} + \frac{\frac{1}{2}}{1- \frac{1}{9}}[/tex]
=> [tex]\frac{1/3}{8/9}+ \frac{1/2}{8/9}[/tex]
=> [tex]\frac{3}{8} + \frac{1}{4}[/tex]
=> [tex]\frac{5}{8}[/tex]
Hence , the series is convergent.
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In triangle def, if m∠d is (2x)°, m∠e is (3x − 2)°, and m∠f is (x 8)°, what is the value of x? 29 31 34 59
In triangle def, if m∠d is (2x)°, m∠e is (3x − 2)°, and m∠f is (x + 8)°, then the value of x is 29.
What is Triangle?A triangle is a three-sided polygon that consists of three edges and three vertices.
Triangle is DEF
if m∠d is (2x)°, m∠e is (3x − 2)°, and m∠f is (x 8)°
We need to find the value of x.
We know that the sum of three angles of triangle is 180 degrees
m∠d + m∠e + m∠f=180°
2x+3x-2+x+8= 180°
6x+6=180
Subtract 6 on both sides
6x=174
Divide by 6 on both sides.
x=174/6
x=29
Hence, the value of x is 29.
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RESEARCH STUDY 8.1: Dr. Guidry conducts a study examining the relationship between the number of friends one has and the experience of daily stress and life satisfaction. She randomly samples 1,500 elderly men and women in Nashville, Tennessee (the state capital), located in the southern United States. Below are her findings.• Life satisfaction and experience of daily stress: r = −.57 (p = .01)• Number of friends one has and experience of daily stress: r = .09, not sig.• Number of friends one has and life satisfaction: r = .36 (p = .04) Comparing all three correlations, Dr. Guidry will be most able to accurately predict life satisfaction from the experience of daily stress because the relationship:
has the largest effect size.
Given the above condition, the result may translate to "Sample size and effect size."
What is Effect Size in Research?
Increasing the sample size always increases the likelihood of finding a statistically significant impact, regardless of how tiny the effect is in the actual world. In contrast, effect sizes are not affected by sample size. To compute effect sizes, just the data is utilized.
In contrast to significance tests, the effect size is not affected by sample size. Statistical significance, on the other hand, is determined by both the sample size and the effect size.
The greater the impact size, the greater the difference between the typical person in each group. A d of 0.2 or less is regarded a minor impact size, a d of roughly 0.5 is considered a medium effect size, and a d of 0.8 or above is considered a high effect size.
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In a certain fraction, the denominator is 4 larger than the numerator. If 2 is added to both the numerator and the denominator, the result is 3/5. Find the original fraction.
The value of the original fraction is found as 4/8.
Explain the term fraction?A number that is stated mathematically as a quotient, where the numerator and denominator are divided. Both are integers in a simple fraction. A fraction appears in the numerator and denominator of a complex fraction. The numerator of a proper fraction is less than denominator.Let a be the numerator.
Let b be the denominator.
B = A + 4 has a denominator 4 times larger than a numerator.
Both the numerator as well as the denominator receive an addition of 2: (a + 4 + 2) and a + 2.
The following algebraic equation is created from the provided statement:
(a + 2)/(a + 4 + 2) = 3/5
(a + 2)/(a + 6) = 3/5
5(a + 2) = 3(a + 6)
5a - 3a = 18 - 10
a = 4
Put the value of a in the original fraction;
a/ (a + 4) = 4/(4 + 4)
= 4/8
Thus, the value of the original fraction is found as 4/8.
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Ali’s soccer practice begins at 8:05 a.m. It takes him 25 minutes to get to practice.
Which clock shows the time Ali should leave his house to get to practice on time?
The time that Ali should leave his house to get to practice on time is 7:40 am.
How to calculate the time?Fron the information given, it was stated that Ali’s soccer practice begins at 8:05 a.m and that it takes him 25 minutes to get to practice.
In this case, it should be noted that the time that he will leave the house will be the minutes subtracted from 8:05.
This will be illustrated thus:
= 8:05 a.m - 25 minutes
= 7:40am
Therefore, Ali should leave at 7:40 am.
Note that the clock wasn't given by you but the appropriate time is calculated.
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suppose follows the standard normal distribution. use the calculator provided, or this table, to determine the value of so that the following is true. p (z>c)
The value of c for the statement P(Z>c) = 0.1379 in the standard normal distribution is 1.09.
How to calculate the value of c in standard normal distribution?Φ is symbol for cumulative distribution function (CDF) for standard normal distribution with mean equal to 0 and standard deviation equal to 1.
Z follow standard normal distribution. So,
Z ∼ N(0,1)
Since,
P(Z>c) = 0.1379
1 - P(Z≤c) = 0.1379
P(Z≤c) = 1 - 0.1379
P(Z≤c) = 0.8621
or
Φ(c) = 0.8621
Next, we know Φ(Z) is equal to P(Z≤z) with z∈R is CDF for N(0,1). So,
P(Z≤z) = 0.8621
From standard normal distribution table or z table, we get z = 1.09. So,
P(Z≤1.09) = 0.8621
Φ(1.09) = 0.8621
Since, Φ(c) = 0.8621. So, c = 1.09
Thus, the value of c is 1.09 for statement P(Z>c) in standard normal distribution is equal to 0.1379.
Your question is incomplete, but most probably your full question is
Suppose Z follows the standard normal distribution. Use the calculator provided, or this table, to determine the value of c so that the following is true.
P(Z>c)=0.1379
Round your answer to two decimal places.
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A number line is drawn left to right with integers spaced 1 centimeter apart. An ant crawls onto the number line at +2. It then crawls 3.5 centimeters left, 4.8 centimeters right, and 7.9 centimeters left.
What is the total distance the ant crawled along the number line?
HELP PLEASE
The total distance the ant crawled on the number line is 16.2 centimeters
How to find the total distanceThe distance the ant crawled is all added to minding if it were positive or negative.
Summation of this nature gives absolute values
Hence using addition the total distance is calculated
= 3.5 centimeters + 4.8 centimeters + 7.9 centimeters
= 16.2 centimeters
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Find the measure of angle 1 in a triangle if angle 2 and angle 3 both have a measure of 75⁰.
Answer:
30 degrees
Step-by-step explanation:
(75 degrees x 2) = 150 degrees
180 degrees - 150 degrees = 30 degrees
angle 1 = 30 degrees
What are the solutions of the equation x4 + 6x2 + 5 = 0? use u substitution to solve. X = i and x = i i and x = i and x = and x = -.
The given equation's solution is x = 5i or x = i.
An equation has been provided.
x⁴+6x²+5 = 0
We to settle it utilizing replacement.
If u = x2, then u2 = x4 In the above equation, we find that u2+6u+5 = 0. Now, use the factorization method.
Divide the middle term of the previous equation as follows: u2+5u+u+5 = 0; u(u+5)+1(u+5) = 0; u(u+5)(u+1) = 0 Using the zero-product property, we can determine that u+5 or u+1 equals 0; u = -5 or u = -1; x2 equals -5 or x2 equals -1; taking the square root of both sides of.
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FILL IN THE BLANK. the ___ niche is the entire niche that an organism is capable of occupying if there was no competition. whereas, the ___ niche is the niche occupied by the organism in the presence of competitors.
The fundamental niche is the entire niche that an organism is capable of occupying if there was no competition. whereas, the realized niche is the niche occupied by the organism in the presence of competitors.
What is a niche?
This refers to the role an organism plays in an ecosystem/community.
Types of niches
.The fundamental niche: This refers to the organism that is capable of occupying if there were no competitors.
. The realized niche: This refers to organisms that exist in the presence of competitors. They are perceived to be less effective due to the presence of competitors.
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The position vector r describes the path of an object moving in space. Find the velocity v(t), speed s(t), and acceleration a(t), of the object. r(t) = ti + t2j + t2 2 k
The velocity v(t), speed s(t), and acceleration a(t), of the object are explained below.
What is a vector?A vector is an amount or peculiarity that has two free properties: greatness and bearing. The term likewise means the numerical or mathematical portrayal of such an amount. Instances of vectors in nature are speed, energy, force, electromagnetic fields, and weight.
According to given data in the question:
We have given,
r(t) = ti+t^2j+t^2k/2 at t = 4
For velocity = dr(t)/dt=d( ti+t^2j+t^2k/2)/dt
v(t) = i+2tj+tk
put t = 4
velocity= i+8j+4k
And speed =[tex]\sqrt{(1)^2+(8)^2+(4)^2}[/tex]= [tex]\sqrt{81}[/tex]= 9 unit/second
acceleration =dv(t)/dt=d( i+2tj+tk)/dt = 2j+k
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kelly earns $288 during her first 8 hour shift. how much would kelly earn on a full paycheck of 36 hours? interpret your answer.
Answer:
$1,296
Step-by-step explanation:
kelly earns $288 during her first 8 hour shift. how much would kelly earn on a full paycheck of 36 hours? interpret your answer.
288/8 = $36 per hour
If she worked 36 hours at $36 per hour:
36* $36 = $1,296
at the end of module 35b, you were asked to note and discuss why the double slit interference pattern did not extend over the entire view screen. the reason is that interference can only occur where there is intensity from each of the single slit sources. these slit sources are not point sources, and the width of the intensity pattern due to one slit is governed by diffraction. diffraction is the word used to describe the interference between the infinite number of infinitesimal (huygens) sources that make up the slit itself. you can find a relationship in the
Therefore, the intensity pattern due to each single slit only extends over a finite region, and the double slit interference pattern can only be observed within this region.
What is interference?In mathematics, interference is a phenomena that happens when two or more waves interact with one another. Depending on the waves' respective frequency to reinforce or cancel. Interference can be constructive, where the waves combine to generate a bigger wave, or destructive, where the waves cancel each other out. This phenomena is widely observed in light waves, sound waves, and water waves. The superposition principle, which asserts that the total wave at any place in space equals the sum of all the individual waves existing at that point, is a mathematical concept that describes interference. In disciplines including physics, engineering, and signal processing, this idea is frequently applied.
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A researcher is following the growth of a particular type of flower. She writes the given equation to show the height of the flower g(n), in inches, after ndays. g (n) = 10(1.02)n. What is the average rate of change of the function g (n) from n=1 to n=5 ? Please show all work. HINT: average rate of change ; = slope.
The average rate of change of function is 10.2 inches per day
The equation to show the height of the flower is
g(n) = 10(1.02)n
Where g(n) is the height of the flower
n is the number of days
The value of n is from n = 1 to n = 5
The average rate of change of the function = f(5) - f(1) / 5 -1
Then,
f(5) = 10(1.02)(5)
= 51 inches
f(1) = 10(1.02)(1)
= 10.2 inches
Substitute the values in the equation
The average rate of change of function = 51 - 10.2 / 5 - 1
= 40.8 / 4
= 10.2 inches per day
Hence, the average rate of change of function is 10.2 inches per day
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find the missing side of each triangle GIVE STEP BY STEP PLEASE!!!
When you see a right triangle and need to solve for one side, use the Pythagorean Theorem. This states that the square of the hypotenuse is equal to the sum of the squares of the adjacent sides. In algebraic terms:
[tex]a^2+b^2=c^2[/tex]
In triangle 1, we are given c and b, we need to find a.
[tex]a^2+8.7^2=9.4^2\\a^2+75.69=88.36\\a^2+75.69-75.69=88.36-75.69\\a^2=12.67\\\sqrt{a^2}=\sqrt{12.67}\\a=3.56[/tex]
In triangle 2, we have a and c, we need to find b.
[tex]6^2+b^2=14^2\\36+b^2=196\\36-36+b^2=196-36\\b^2=160\\\sqrt{b^2} = \sqrt{160}\\b=4\sqrt{10}[/tex]
The correlation coefficient r between the values assumed by two variables, X
and Y is .75, the standard deviations of X and Y are Sx=1.88 and Sy=2.45
respectively, and the point (13, 9) is on the line of best fit.
A. Find the slope of the line of best fit to the raw-score scatterplot.
B. Find the equation of the line of best fit.
C. Find y given that . x = 12
The slope of the line of best fit to the raw-score scatter plot is 0.98
The equation is y = 0.98x - 3.74The value of y given that x = 12 is 8.02How to determine the slope of the line?From the question, we have the following parameters that can be used in our computation:
Standard deviations of X, Sx = 1.88Standard deviations of Y, Sy =2.45Correlation coefficient, r between X and Y = 0.75The slope (b) of the line is calculated as
b = r * Sy/Sx
Substitute the known values in the above equation, so, we have the following representation
b = 0.75 * 2.45/1.88
Evaluate
b = 0.98
The equation of the line of best fitA linear equation is represented as
y = bx + c
Where
Slope = b
y-intercept = c
In (a), we have
b = 0.98
So, we have
y = 0.98x + c
Recall that the point (13, 9) is on the line of best fit.
So, we have
9 = 0.98 * 13 + c
This gives
9 = 12.74 + c
Evaluate
c = -3.74
So, we have
y = 0.98x - 3.74
The value of y from xHere, we have
x = 12
So, we have
y = 0.98 x 12 - 3.74
Evaluate
y = 8.02
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A political researcher takes a survey of 300 randomly selected registered voters in atlanta, and each person was asked who they plan on voting for in the 2020 mayoral election. 101 said they plan on voting for candidate a, 184 said they plan on voting for candidate b, and 15 were unsure or plan to vote for another candidate. In question 8, the political researcher estimated p, the population proportion of all registered voters in atlanta who plan to vote for candidate a, with a 95% confidence interval. The researcher now wants to estimate p with a margin of error of 3%. What is the minimum sample size needed?.
we are 99% confident that the population proportion lies between the confidence interval.
What is confidence interval?In statistics, a confidence interval describes the likelihood that a population parameter would fall between a set of values for a given percentage of the time.
Confidence ranges that include 95% or 99% of anticipated observations are frequently used by analysts. Therefore, it can be concluded that there is a 95% probability that the true value falls within that range if a point estimate of 10.00 is produced from a statistical model with a 95% confidence interval of 9.50 - 10.50.
margin of error =E
=0.03p
=101/300
=0.337
For 95% CI, alpha is 5% and z=1.96
Sample size n=(z/E)² × (p(1-p)
=(1.96/0.03)² × (0.337(1-0.337))
=953.7
=954(approximately)
confidence interval is interpreted as that we are 99% confident that the population proportion lies between the confidence interval.
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Consider the number of blocked intrusions below:
Before firewall change: 56, 47, 49, 37, 38, 60, 50, 43, 43, 59, 50, 56, 54, 58
After firewall change: 53, 21, 32, 49, 45, 38, 44, 33, 32, 43, 53, 46, 36, 48, 39, 35, 37, 36, 39, 45
(a) Construct a 95% confidence interval for the difference between the average number of intrusion attempts per day before and after the change of firewall setting (assume equal variance)
(b) Can we claim significant reduction in the rate of intrusion attempts? The number of intrusion each day has approximately normal distribution. Compute P-values and state your conclusions under the assumption of equal variances and without it. Does this assumption make a difference?
a)The 95% confidence interval are
0-44,44-88
b))Yes, we can claim significant reduction in the rate of intrusion attempts
The p-value is 0.067No, the given assumption does not make a difference.We have firewall change of 14 people.
We need to compute total sum before firewall change which can be done by
(56+47+49+37+38+60+50+43+59+50+56+54+58)/14
=657/14
=46.92
Now, similarly, after firewall change total sum is
(53+21+32+49+45+38+44+33+32+43+53+46+36+48+39+35+37+36+39+45)/20
=756/20
=37.8
Now the difference between average number of intrusion attempts before and after firewall change is
(46.92-37.8)
=9.12
Now, we need to make confidence interval to only 95% of this difference=
(95×9.12)/100
=44.196=44(approx)
It means our interval range varies from 0-44,44-88 with a difference of 44.
b)Yes, we can easily claim that rate of intrusion attempts decreases.
Before firewall change, we can see average number of intrusion attempt is =46.92
After firewall change, we can see average number of intrusion attempt is
37.8
So, we can see rate of intrusion decreases on increasing the number of blocked intrusions.
For computing z-value, we just need to take square root of the difference of average number of intrusions attempst
=>Z-value= √9.12=3.01
Using the z-table, we get that for the above z-value, corresponding p-value is 0.067
Hence, the interval range is 0-44,44-88 and b)Yes we can claim, p-value is 0.067.No, this assumption does not make a difference.
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suppose you have a normal distribution with mean 11. if you are given a data value of 9, would you expect the corresponding z-score to be positive or negative?
According to the given information for the normal distribution, we can expect that the corresponding z-score may be negative.
It is given to us that -
The normal distribution has mean 11
The normal distribution has data value of 9
We have to find out if the corresponding z-score is to be positive or negative.
The z-score calculates the number of standard deviations higher or lower the mean, the data point is present.
The formula for z-score is given by -
[tex]z=\frac{data point - mean}{standard deviation}[/tex]
Although we do not have the value of standard deviation in the question, we can see that the value of
data point - mean = 9-11 = -2
So, we can see that the numerator of the z-value formula is already negative.
Thus, we can expect that the corresponding z-score may be negative according to the information provided for the normal distribution.
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Child Health and Development Studies (CHDS) has been collecting data about expectant mothers in Oakland, CA since 1959. One of the measurements taken by CHDS is the weight increase (in pounds) for expectant mothers in the second trimester. In a fictitious study, suppose that CHDS finds the average weight increase in the second trimester is 14 pounds. Suppose also that, in 2015, a random sample of 40 expectant mothers have mean weight increase of 16 pounds in the second trimester, with a standard deviation of 6 pounds. At the 5% significance level, we can conduct a one-sided T-test to see if the mean weight increase in 2015 is greater than 14 pounds. Statistical software tells us that the p-value = 0.021.Which of the following is the most appropriate conclusion?There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds.There is a 2.1% chance that mean second trimester weight gain for all expectant mothers is 14 pounds in 2015.There is a 2.1% chance that mean second trimester weight gain for all expectant mothers is 16 pounds in 2015.There is 2.1% chance that the population of expectant mothers will have a mean weight increase of 16 pounds or greater in 2015 if the mean second trimester weight gain for all expectant mothers was 14 pounds in 1959.Find the p-value for the hypothesis test. A random sample of size 50 is taken. The sample has a mean of 420 and a standard deviation of 81.H0: µ = 400Ha: µ > 400The p-value for the hypothesis test is
There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds
Given:
In the question;
Suppose that CHDS finds the average weight increase in the second trimester is 14 pounds. Suppose also that, in 2015, a random sample of 40 expectant mothers have mean weight increase of 16 pounds in the second trimester, with a standard deviation of 6 pounds. At the 5% significance level, we can conduct a one-sided T-test to see if the mean weight increase in 2015 is greater than 14 pounds. Statistical software tells us that the p-value = 0.021.
Now, According to the question:
Since we have to test that whether the mean weight is greater than 14 pounds, so test is right tailed and if ta is the value of test static then p-value is P(t> t_a ) . Where t_a={16-14\over 6/\sqrt {40}} .
Now p-value is 0.021.
So, the correct conclusion is:
There is a 2.1% chance that a random sample of 40 expectant mothers will have a mean weight increase of 16 pounds or greater if the mean second trimester weight gain for all expectant mothers is 14 pounds
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What are three examples of functions?.
F(x) = sin x, F(x) = x2 + 3, F(x) = 1/x, F(x) = 2x + 3, etc. are a few further instances of functions.
Polynomial functions include functions like the identity function, linear function, quadratic function, and cubic function. Therefore, it is useful to define the type of function using the function equation y = f(x).
Algebraic, exponential, logarithmic, and trigonometric functions are available depending on the domain. Modulus, rational, signum, even and odd, periodic, biggest integer, smallest integer, inverse, and composite functions are the functions based on the range.
For instance: It is declared that the polynomial function with degree zero is a constant function. One-degree polynomial functions are referred to as linear functions. Quadratic function is the name given to the degree two polynomial function.
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What is the solution set to the inequality 5 x 2 )( x 4 0 ?.
The intervals in the solution set are those that make the inequalities 5(x – 2)(x + 4) > 0 true is (-∞, -4) U (2,∞).
Given that,
The inequality is 5(x – 2)(x + 4) > 0
We need to address the inequality and find a solution.
We know that,
Take the inequality
5(x – 2)(x + 4) = 0
Divide the equation both sides by 5
(x – 2)(x + 4) = 0
Now, we take each factor equal to 0
x-2 =0 , so x= 2
x+4 =0, so x= -4
Now we get
First interval (-∞,-4)
Second interval (-4,2)
Third interval (2,∞)
Now,
We take each interval with our inequality
First interval (-∞,-4), pick a number in this interval and check with our inequality.
Lets pick -5
5(-5 – 2)(-5 + 4) > 0
35>0 is true
Second interval (-4,2), pick a number in this interval and check with our inequality.
Lets pick 0
5(0– 2)(0 + 4) > 0
-40>0 is false
Third interval (2,∞), pick a number in this interval and check with our inequality.
Lets pick 3
5(3 – 2)(3 + 4) > 0
35>0 is true
The intervals in the solution set are those that make the inequalities true is (-∞, -4) U (2,∞).
Therefore, The intervals in the solution set are those that make the inequalities 5(x – 2)(x + 4) > 0 true is (-∞, -4) U (2,∞).
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Solving by factoring which equation is equivalent to f(x) = 16x4 – 81 = 0?
(4x² - 9)(4x² + 9) = 0 equation is equivalent to the given equation.
What is factorization?
Factorization in mathematics is the process of dividing a large number into smaller ones that, when multiplied together, give you the original number.
Here, we have
Given equation,
f(x) = 16x⁴ – 81 = 0
The difference of squares is used to solve this equation. There are three perfect squares: 16, x⁴, and 81. ( which means that it is a number multiplied by itself, 16 is 4 x4 for example).
We solve this equation by formula: (a² - b²) = (a - b)(a + b)
= 16x⁴ – 81 = 0
Now, we determine the square root of 16 which is 4, and of x⁴ which is x², and 81 which is 9.
Now we write the equation in the (a - b)(a + b) form :
⇒ (4x² - 9)(4x² + 9) = 0
Hence, the (4x² - 9)(4x² + 9) = 0 equation is equivalent to the given equation.
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