What is the pressure (in atm) of a 10.89 mol sample of helium gas at 19.3 degrees C if its volume is in 5.70 L?

Answer: Magnesium ribbon!

Explanation:

The only limiting reactant is the magnesium ribbon, as it is the only reactant that is consumed in the reaction. The other reactant, the oxygen in the air, is not consumed in the reaction.

Answer:

Cl-(aq) + 2Hg+(aq) + NO3-(aq) = Hg2Cl2(s)

Explanation:

Solubility Equation

Determine the state or phase of each substance (gas=g, liquid=l, solid/non-soluble=s, aqueous/soluble=aq) in its undissociated form by using the solubility rules or a solubility table.

2NaCl(aq) + Hg2(NO3)2(aq) = 2NaNO3(aq) + Hg2Cl2(s)

Balanced chemical equation

2NaCl(aq) + 2Hg2(NO3)2(aq) = 2NaNO3(aq) + Hg2Cl2(s)

Complete Ionic Equation

The complete (or total) ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions.

Na+(aq) + Cl-(aq) + 2Hg+(aq) + 2NO3-(aq) = Na+(aq) + NO3-(aq) + Hg2Cl2(s)

Net Ionic Equation

The balanced net ionic equation includes only species that are involved in the reaction. It can be found by removing ions that occur on both the reactant and product side of the complete ionic equation.

Cl-(aq) + 2Hg+(aq) + NO3-(aq) = Hg2Cl2(s)

Spectator Ions

Spectator ions are ions that do not take part in the reaction. They are removed from the complete ionic equation to get the net ionic equation.

Precipitates

Precipitates are the solid products that form in the net ionic reaction. Cl-(aq) + 2Hg+(aq) + NO3-(aq) = Hg2Cl2(s) has 1 precipitate.

The total mass of the products will equal the total mass of the reactants.

A calorimeter is a device used to measure the heat of chemical reactions or physical changes. It works by measuring the heat absorbed or released during a reaction or process by monitoring changes in temperature.

Calorimeters can be used to study a wide range of chemical reactions, including combustion, acid-base reactions, and reactions involving enzymes.

Calorimetry is an important technique in the study of thermodynamics, and it has many practical applications.

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As per the solubility graph shown, sodium nitrate is more soluble in water than potassium nitrate.

Solubility is defined as the ability of a substance which is basically solute to form a solution with another substance. There is an extent to which a substance is soluble in a particular solvent. This is generally measured as the concentration of a solute present in a saturated solution.

The solubility mainly depends on the composition of solute and solvent ,its pH and presence of other dissolved substance. It is also dependent on temperature and pressure which is maintained.

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Answer:

The empirical formula of ethylene glycol is CH3 O.

The net ionic equation for the precipitation of nickel(II) phosphate from aqueous solution is

Na3PO4 + NiCl2 ---> Ni3(PO4)2 + NaCl

Nickel(II) phosphate is an inorganic compound with the formula Ni3(PO4)2. It is a mint green magnetic force solid that is insoluble in water. The cause of nickel (II) phosphate is established when the nickel (II) ion from nickel (II) sulfate unites with the phosphate ion from sodium phosphate as shown in the net ionic equation given below.

Solutions of sodium sulfide and nickel (II) sulfate are assorted. Na2S+ NiSO4→ Na2SO4 + NiS Nickel (II) sulfide is the precipitate.

So we can conclude that Solid nickel (II) phosphate is formed, meaning it is called a precipitate.

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The answers rounded to the correct number of

significant figures are:

20+2.1= 2.21 x 10¹

3400/.25= 1.36 x 10⁴

30000 × .034= 1.02 x 10³

540.34 - 14= 5.26 x 10²

6.3 × 2.903= 1.84 x 10¹

Significant figures, also known as significant digits, are the meaningful digits in a number that are used to express the precision or accuracy of a measurement or calculation. The significant figures in a number are all the digits that are known with certainty plus the first uncertain or estimated digit.

For example, the number 123.45 has five significant figures, since all the digits are known with certainty, while the number 0.00432 has three significant figures, since the leading zeros are not significant and only the digits 4, 3, and 2 are known with certainty.

Significant figures are important because they indicate the level of precision of a number or measurement, and they are used to ensure that calculations and measurements are reported accurately and consistently. When performing calculations with numbers that have different numbers of significant figures, the answer should be rounded to the appropriate number of significant figures to maintain the same level of precision.

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The final energy level of the electron is calculated to be equal to n=2

Wavelength is the spatial period of periodic wave, that is the distance over which the shape of the wave repeats.

As E = hc/λ

E is the energy of the photon, h is Planck's constant (6.626 x 10⁻³⁴ J s), c is the speed of light (2.998 x 10⁸ m/s), and λ is the wavelength of the photon.

E = hc/λ = (6.626 x 10⁻³⁴ J s) x (2.998 x 10⁸ m/s) / (1005 x 10⁻⁹ m) = 1.986 x 10⁻¹⁹ J

E = -13.6 eV / n²

E is the energy of electron, n is principal quantum number, and -13.6 eV is  ionization energy of hydrogen.

1.986 x 10⁻¹⁹ J = (-13.6 eV / 7²) - (-13.6 eV / n²)

n² = (13.6 eV / 1.986 x 10⁻¹⁹ J) x (1/7²) - 1

n² = 3.665

n = 1.915

Therefore, the final energy level of the electron is n=2.

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As the temperature increases the solubility of most compounds also increases. The rate of reaction increases as the concentration of solute increases.

The term "solubility" describes how easily a solute (the thing to be dissolved) can dissolve in a solvent. Temperature, pressure, and the chemical makeup of the solute and solvent are all factors that influence how soluble a given solute is in a given solvent.

If a solute can dissolve in the solvent to create a homogenous solution, it is said to be soluble. Solubility is the measure of a solute's ability to dissolve in a given volume of solvent.

In summary, different compounds have very varying solubilities, which is a characteristic of a particular solute-solvent pair.

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The law of conservation of mass states that in a chemical reaction mass is neither created nor destroyed.

The Law of Conservation of Mass dates from Antoine Lavoisier's 1789 discovery that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

Explanation:

The ion OH⁻ consists of one oxygen atom (O) and one hydrogen atom (H), with an overall charge of -1 due to the extra electron.

To determine the number of lone pairs of electrons on the oxygen atom, we need to know its valence electron configuration. Oxygen has 6 valence electrons, and in the OH⁻ ion, it has gained one extra electron to form a single covalent bond with the hydrogen atom.

To form this bond, the oxygen atom uses two of its valence electrons, leaving it with four valence electrons that are not involved in bonding. These four valence electrons are arranged in two lone pairs of electrons around the oxygen atom.

Therefore, there are two lone pairs of electrons on the oxygen atom in the OH⁻ ion. The hydrogen atom does not have any lone pairs of electrons.

We need 17.2 g of sulfur to react with 30 g of iron to produce 40 g of iron (II) sulfide.

The balanced chemical equation for the reaction between iron and sulfur to form iron (II) sulfide is:

Fe + S → FeS

To determine the amount of sulfur required to produce 40 g of iron (II) sulfide from 30 g of iron, we need to use stoichiometry.

The molar mass of iron is 55.845 g/mol, and the molar mass of sulfur is 32.06 g/mol.

First, we need to calculate the number of moles of iron in 30 g:

30 g Fe / 55.845 g/mol = 0.537 mol Fe

Since the stoichiometric ratio of iron to sulfur is 1:1, the number of moles of sulfur required is also 0.537 mol.

Next, we can calculate the mass of sulfur needed:

0.537 mol S x 32.06 g/mol = 17.2 g S

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Answer: 4.4 × 10^20 mol

Explanation:

First step, is to find the molar mass of the compound by finding each molar mass of each element in the compound and if they have a number of moles next to the element symbol you have to make sure to multiply that specific element by that number of moles and then add all of the elements molar masses together to find the molar mass of the compound ( molar masses of elements are found on the periodic table).

H3 = 1.01 g × 3 = 3.03 g,

P = 30.97 g,

O4 = 16.00 g × 4 = 64.00 g



3.03 g + 30.97 g + 64.00 g = 98.00 g

H3PO4 = 98.00 g/mol

Second step, is to find the moles of the compound by multiplying the molar mass by Avogadro's number (6.022 × 10^23 g/mol) so that the grams canceled and leaves you with the moles.



98.00 g × 1 mol ÷ 6.022 × 10^23 g = 1.62736632 × 10^-22 mol of H3PO4

Third step, is to find the moles of the molecules by multiplying Avogadro's number again to the given molecules

(4.3 × 10^22 molecules).

4.3 × 10^22 molecules × 1 mol ÷ 6.022 × 10^23 molecules = 0.0714048489 mol

Fourth step, you divide the moles of the molecules by the moles of the compound, to find the moles of the molecules in the compound.



0.0714048489 mol ÷ 1.62736632 × 10^-22 mol H3PO4 = 4.387755112 × 10^20 mol



Fifth step, depending on the significant figures you have, you round the final answer to the significant figures you need in this case 2 significant figures found by the first number given which was the molecules.

4.4 × 10^20 mol

A. The energy used in KJ for 30 days period is 4878000 KJ

B. The energy used in KJ/day is 162600 KJ/day

C. Your electric bill for the month is $ 101.4895

The energy used in KJ for 30 days period can be obtained as follow:

1 KWh = 3600 KJ

Therefore,

1355 KWh = 1355 × 3600

1355 KWh = 4878000 KJ

Thus, the energy used in KJ for 30 day is 4878000 KJ

The energy used in KJ/day can be obtained as follow:

30 day = 4878000 KJ

1 day = 4878000 / 30

1 day = 162600 KJ

Thus, the energy used in KJ/day is 162600 KJ/day

The electric bill for 30 days can be obtained as shown below:

Cost = energy × Cost per KWh

Electric bill for 30 days = 1355 × 0.0749

Electric bill for 30 days = $ 101.4895

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Answer:First we will find the volume of the tank.

Volume of right cylinder = pi * r² * h

⇒  3.14 * 6 ² * 4

⇒ 3.14 * 36 * 4

⇒452 . 16 feet³

Now as  1 cubic foot of water is about 7.5 gallons we will and rate 10 gallons per minute.

So, every minute 10/ 7.5 ≅ 1.34 cubic foot is getting filled.

Time taken = 452.16/ 1.34  ≅ 337.43 minutes

Which means 5.62 hours approximately and when rounding to the nearest tenth 5.6 hours.

Explanation:That is the answer

The concentration of chloride ions in seawater is approximately 18,437.5 ppm.

To convert the concentration of chloride ions from molarity to parts per million (ppm), we need to know the molar mass of chloride ions, which is 35.45 g/mol. We can use this information to convert the concentration from moles per liter to grams per liter:

0.53 mol/L x 35.45 g/mol = 18.7865 g/L

Since the density of seawater is 1.02 g/mL, we can convert the concentration from grams per liter to grams per milliliter:

18.7865 g/L ÷ 1.02 g/mL = 18.4375 g/mL

18.4375 g/mL x 10^6 = 18,437.5 ppm

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These molecules and atoms move more quickly when something is heated, providing it with additional thermal energy. Compared to cold water, hot water has higher thermal energy.

Water loses volume as its density rises when heated above 0°C; this effect is visible up to 4°C. Since ice has a maximum density at 4 degrees Celsius, as the temperature drops, the volume grows. The primary cause of this is the ice's melting, which causes the hydrogen bond in the ice to break.

Water loses volume when heated from zero degrees Celsius due of its density. increases, and until the temperature hits 4°C, this effect continues. This is due to the fact that ice has its highest density at 4°C. Ice continues to expand in volume and lose density after this.

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With a bomb calorimeter with 2000 grams of water inside, burning 2.0 grams of methane raises the water's temperature by 13.300C.

The equation q = mcT, where m is the mass of the sample, c is the specific heat, and T is the temperature change, can be used to determine how much heat is gained or lost by a sample (q).

The heat generated by the sample is compared to the heat generated by the combustion of a reference substance, such as benzoic acid, to determine the calorific value using an oxygen bomb calorimeter.

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The answer to the question depends on the specific solubility test being performed and the characteristics of the compound being tested.

option A or B.

The volume of solvent used in a solubility test may vary depending on the specific protocol or procedure being followed. However, a common guideline is to use a minimal amount of solvent that is just enough to dissolve the compound being tested.

Typically, a small amount (e.g., a few milligrams) of the compound is added to a test tube, and a small volume (e.g., 1-2 mL) of solvent is added. The mixture is then shaken or stirred to promote dissolution, and the result is observed (e.g., clear solution, precipitate formation, etc.).

Therefore, the answer to the question depends on the specific solubility test being performed and the characteristics of the compound being tested. A general guideline is to use a minimal amount of solvent, but the exact volume may vary depending on the specific circumstances.

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The standard enthalpy change of the reaction is -1093.66 kJ/mol.

The standard enthalpy change of the reaction is determined from the sum of the enthalpy changes of the intermediate steps that give the overall reaction.

The equation of the reaction is given below as follows:

2 C₄H₁₀ + 13 O₂ ----> 8 CO₂ + 10 H₂O

The enthalpy changes of the intermediate reactions are as follows:

1. 4 C + 5 H₂ ---> C₄H₁₀    ;ΔH₁ = -124.73 kJ/mol

2. C + O₂ ---> CO₂    ;ΔH₂ = -393.50 kJ/mol

3. 2 H₂ + O₂ --->  2 H₂O   ;ΔH₃ = -483.64 kJ/mol

The enthalpy change of the reaction, ΔH = 2 * ΔH₁ + (-4 * ΔH₂) + 5 * ΔH₃

ΔH = {2 * -124.73 + (-4 * -393.50) + 5 * -483.64}kJ/mol

ΔH = -1093.66 kJ/mol

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Theoretically, we would lose 0.588 g of CO2 in this reaction.

The balanced equation for the reaction between iron (III) carbonate and hydrochloric acid is:

Fe2(CO3)3 + 6 HCl → 2 FeCl3 + 3 CO2 + 3 H2O

From the equation, we can see that one mole of iron (III) carbonate reacts with 6 moles of hydrochloric acid, and produces 3 moles of carbon dioxide.

First, we need to calculate the number of moles of iron (III) carbonate in 1.3 g. The molar mass of Fe2(CO3)3 is:

2 x (55.845 g/mol Fe) + 3 x (12.011 g/mol C) + 9 x (15.999 g/mol O) = 291.441 g/mol

Number of moles of Fe2(CO3)3 = mass / molar mass

= 1.3 g / 291.441 g/mol

= 0.004455 mol

To ensure an excess of hydrochloric acid, we need to provide at least 6 times the number of moles of HCl as the number of moles of Fe2(CO3)3. So, the number of moles of HCl required is:

Number of moles of HCl = 6 x number of moles of Fe2(CO3)3

= 6 x 0.004455 mol

= 0.02673 mol

Now, we can use the molarity of the HCl solution to calculate the volume required:

Molarity of HCl = number of moles / volume

Volume of HCl = number of moles / molarity

Volume of HCl = 0.02673 mol / 1.0 M

= 26.73 mL

Therefore, we need 26.73 mL of 1.0 M HCl solution to ensure an excess of HCl.

Finally, we can calculate the theoretical amount of CO2 produced:

Number of moles of CO2 = 3 x number of moles of Fe2(CO3)3

= 3 x 0.004455 mol

= 0.013365 mol

Mass of CO2 = number of moles x molar mass

= 0.013365 mol x 44.01 g/mol

= 0.588 g

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We need to add 100.0 mL of 2.00 M NaOH to the 200.0 mL of 1.00 M glycolic acid solution to make a buffer solution with pH = 4.15.

To make a buffer solution with pH = 4.15 using glycolic acid and sodium hydroxide, we need to calculate the amount of NaOH needed to react with the glycolic acid and form the corresponding buffer.

The pKa of glycolic acid is 3.83. Therefore, we need to use the Henderson-Hasselbalch equation to calculate the ratio of the concentrations of the conjugate base (glycolate) to the acid (glycolic acid) needed to achieve the desired pH:

pH = pKa + log([A-]/[HA])

4.15 = 3.83 + log([A-]/[HA])

0.32 = log([A-]/[HA])

10^0.32 = [A-]/[HA]

2.04 = [A-]/[HA]

Now we can use the equation for the balanced chemical reaction between glycolic acid and sodium hydroxide:

HOCH2COOH + NaOH → HOCH2COO-Na+ + H2O

We can see that one mole of glycolic acid reacts with one mole of NaOH, so we need to calculate the number of moles of glycolic acid in the 200.0 ml of 1.00M solution:

n(HA) = C(HA) x V(HA)

n(HA) = 1.00 mol/L x 0.200 L

n(HA) = 0.200 mol

Since we need a 2.04:1 ratio of [A-]/[HA], we need to calculate the number of moles of glycolate (A-) needed:

n(A-) = 2.04 x n(HA)

n(A-) = 2.04 x 0.200 mol

n(A-) = 0.408 mol

Now we can calculate the volume of 2.00 M NaOH needed to react with this amount of glycolic acid:

n(NaOH) = n(HA) = n(A-)

n(NaOH) = 0.200 mol

V(NaOH) = n(NaOH) / C(NaOH)

V(NaOH) = 0.200 mol / 2.00 mol/L

V(NaOH) = 0.100 L = 100.0 mL

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Answer:

15.94 Mols

Explanation:

An electron in the 1s of a hydrogen atom

The lowest energy level of an atom is called the ground state. The ground state represents the state of lowest energy that an atom can have, and it is the state in which the electrons in the atom occupy the lowest available energy levels.

When an atom absorbs energy, its electrons can move to higher energy levels, but they will eventually fall back to the ground state and release the energy they absorbed in the form of light or heat. The energy levels of electrons in an atom are quantized, which means that they can only occupy certain discrete energy levels, rather than any energy level in between. The ground state is the state in which the electrons occupy the lowest possible energy level or orbit, which is closest to the nucleus.

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Large magnetic moments can be found in iron atoms. This is due to the fact that iron is a ferromagnetic substance, meaning that its magnetic moments align with one another in the same direction to produce a potent magnetic field.

The first element in the periodic table's eighth column is iron. It is under the transition metal category. Iron atoms contain 26 protons, 26 electrons, and 30 neutrons in their most common isotope.

A silver-gray metal with lustre, ductility, and malleability is iron (group VIII of the periodic table). Four different crystalline forms are known to exist for it. In moist air, iron rusts, but not in dry air. In weak acids, it dissolves easily.

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According to the Boyle's law, the pressure of the gas  if the cylinder is compressed to 2.0 liters is 2.5 atmospheres.

Boyle's law is an experimental gas law which describes how the pressure of the gas decreases as the volume increases. It's statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.

According to the equation the unknown pressure and volume of any one gas can be determined if two gases are to be considered.That is,

P₁V₁=P₂V₂ substitution in formula gives P₂= 1×5/2=2.5 atmosphere

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Answer:

the pressure of the gas in container A will remain constant as the temperature is lowered

Explanation:

To answer the question, we need to consider the gas laws and how they relate to changes in temperature, pressure, and volume of a gas.

Based on the information given, we know that the temperature of the gas in container A is being lowered from 298 K to 100 K, while the container is kept rigid, meaning its volume cannot change.

The gas law that applies to this scenario is Charles's Law, which states that at constant pressure, the volume of a gas is directly proportional to its temperature. Since the volume is constant in this case, we can conclude that the pressure of the gas must also remain constant.

Therefore, the answer to the question is: the pressure of the gas in container A will not change.

The following changes will occur to the gas in container A as the temperature is lowered from 298 K to 100 K:

In summary, the pressure of the gas in container A will remain constant as the temperature is lowered, while the other properties of the gas will change.

Answer:

Percent solutions Describe how vou would prepare 100 g of a solution that is 0.5% phenolphthalein by mass 1100 mLiof solution that is 22% acetic = acid [ by volume_ Describe how you would prepare 3 . Dilutions sulfuric = acid from 3.0 M solution of 1.0 L ofa0.10 M solution of= Describe how you would prepare sulfuric acid. hydroxide from 5.0 M of a 0.25 M solution of sodium would prepare 500 mL Describe how vow solution of sodium hydroxide.