What is the relationship between chlorofluorocarbons and
fluorine? Does fluorine store heat ? And how does it affect the
Earth

Answers

Answer 1

Chlorofluorocarbons (CFCs) are synthetic compounds that contain carbon, chlorine, and fluorine atoms. The relationship between CFCs and fluorine is that CFCs incorporate fluorine atoms in their chemical structure.

Fluorine is a highly reactive element and is used in the production of CFCs due to its ability to enhance their stability and non-reactivity.

Fluorine itself does not store heat. It is an element and does not have inherent heat storage properties. However, fluorine-containing compounds like CFCs can contribute to the greenhouse effect and affect the Earth's climate.

CFCs have been found to have a detrimental impact on the Earth's ozone layer. When CFCs are released into the atmosphere, they can rise to the stratosphere where they undergo photodissociation by ultraviolet (UV) radiation. This process releases chlorine atoms, which are highly reactive and can catalytically destroy ozone molecules. The depletion of the ozone layer allows more harmful UV radiation to reach the Earth's surface, leading to various negative effects such as increased risk of skin cancer, damage to marine ecosystems, and potential disruption of global climate patterns.

Due to the environmental concerns associated with CFCs and their ozone-depleting properties, their production and use have been significantly restricted or phased out under international agreements such as the Montreal Protocol. This has led to a reduction in the atmospheric concentration of CFCs and gradual recovery of the ozone layer.

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Related Questions

Which best explains what happens to energy when we see a spark on the van der graaf generator?
a. chemical energy is being stored

b. electrical potential energy is being converted into kinetic energy

c. electrical kinetic energy is being stored

d. chemical energy is being released

Answers

When we see a spark on the Van de Graaff generator, the best explanation is that electrical potential energy is being converted into kinetic energy. The Van de Graaff generator uses a belt and metal comb to transfer electrical charges. It creates a high voltage difference between the metal dome and the ground.

This buildup of electrical potential energy is released when a spark occurs. The spark is the result of the electrical charges overcoming the resistance between the dome and the ground. As the charges move from the dome to the ground, they gain kinetic energy and create a visible spark.

So, in this case, electrical potential energy is being converted into kinetic energy. This process happens due to the buildup and release of electrical charges.

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if this atom has one valence electron, what kind of bond is it most likely to form with another atom? how many valence electrons might an atom that it bonds to have?

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If an atom has one valence electron, it is most likely to form an ionic bond with another atom. The atom that bonds to the atom with one valence electron might have either seven or eight valence electrons.

Ionic bonds occur when one atom transfers its valence electron to another atom. In this case, the atom with one valence electron will likely donate it to the other atom.

The atom that bonds to the atom with one valence electron might have either seven or eight valence electrons. This is because atoms tend to gain or lose electrons in order to achieve a stable electron configuration.

If the atom with one valence electron bonds with an atom that has seven valence electrons, the atom with one valence electron will donate its electron to the other atom, resulting in both atoms achieving a stable configuration.

If the atom with one valence electron bonds with an atom that has eight valence electrons, the atom with one valence electron will transfer its electron to the other atom, resulting in the atom with eight valence electrons achieving a stable configuration.

In both cases, the formation of an ionic bond between these atoms allows them to achieve a stable electron configuration.

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alkenes are hydrocarbons containing a carbon-carbon double bond. each carbon of the double bond is -hybridized, has geometry, and all bond angles are degrees.

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Alkenes are hydrocarbons that contain a carbon-carbon double bond. Each carbon of the double bond is sp2 hybridized and has trigonal planar geometry.

The bond angles around each carbon atom in an alkene are approximately 120 degrees. Alkenes can have different numbers of carbon atoms and can form a variety of structural isomers.

Alkenes are hydrocarbons that contain a carbon-carbon double bond, and each carbon of the double bond is sp2 hybridized, giving rise to trigonal planar geometry. The bond angles around each carbon atom in an alkene are approximately 120 degrees.

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Following are the results from the liquid limit and plastic limit tests for a soil. Liquid Limit (LL) =49.14 Plastic Limit (PL) test result: - Weight of can=16 g - Weight of can and wet soil =52 g - Weight of can and dry soil =45 g 1. Determine the Plastic Limit. Please round to the nearest hundredth (i.e., 0.01). PL= 2. Determine the Plasticity Index. P=

Answers

The Plastic Limit (PL) is 29 g.

The Plasticity Index (P) is 20.14.

To determine the Plastic Limit (PL), we need to subtract the weight of the can and dry soil from the weight of the can.

Weight of can and dry soil = 45 g

Weight of can = 16 g

PL = Weight of can and dry soil - Weight of can

PL = 45 g - 16 g

PL = 29 g

To determine the Plasticity Index (P), we subtract the Plastic Limit (PL) from the Liquid Limit (LL).

Liquid Limit (LL) = 49.14

P = LL - PL

P = 49.14 - 29

P = 20.14

The moisture content at which a fine-grained soil can no longer be remoulded without splitting is known as the Plastic Limit (PL).

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If glucose (c6h12o6) was the solute, would it disassociate in water? explain (and include if disassociation means the same as solubility).

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Glucose does not dissociate in water but exhibits solubility.

Glucose, with the chemical formula C6H12O6, is a molecular compound and does not disassociate into ions when dissolved in water. Dissociation refers to the process in which ionic compounds break down into their constituent ions when dissolved in a solvent like water. In contrast, solubility refers to the ability of a substance to dissolve in a given solvent, forming a homogeneous mixture.

Since glucose is a covalent compound composed of nonmetallic elements (carbon, hydrogen, and oxygen), it does not readily ionize or dissociate into charged particles when dissolved in water. Instead, glucose molecules remain intact and interact with water molecules through hydrogen bonding and other intermolecular forces.

Solubility, on the other hand, refers to the ability of a substance to dissolve in a particular solvent, forming a homogeneous mixture. Glucose is highly soluble in water, meaning it can readily dissolve in water to form a homogeneous solution. However, solubility and dissociation are not the same concepts. While glucose readily dissolves in water, it does not dissociate into ions like ionic compounds do.

In summary, glucose does not dissociate in water, but it exhibits solubility, meaning it can dissolve in water to form a homogeneous solution.

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a neutral solution of water at a particular temperature has a concentration of ohâ» of 2.3 Ãâ€"" 10âÂȉ· m. what is kw at this temperature?

Answers

A neutral solution of water at a particular temperature has a concentration of OH⁻ of 2.3×10⁻⁷ M. The Kw at this temperature is 5.3×10⁻¹⁴.

Kw (the ion product constant of water) represents the equilibrium constant for the self-ionization of water. It can be calculated using the concentration of hydroxide ions (OH⁻) and hydronium ions (H₃O⁺) in a neutral solution. Since water is neutral, the concentration of OH⁻ is equal to the concentration of H₃O⁺.

Given that the concentration of OH⁻ is 2.3×10⁻⁷ M in the neutral solution, we can assume that the concentration of H₃O⁺ is also 2.3×10⁻⁷ M.

The equation for Kw is as follows:

Kw = [H₃O⁺] * [OH⁻]

Substituting the given concentration:

Kw = (2.3×10⁻⁷ M) * (2.3×10⁻⁷ M)

Calculating the product:

Kw = 5.29×10⁻¹⁴

Therefore, at this particular temperature, Kw (the ion product constant of water) is 5.3×10⁻¹⁴.

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The question was Incomplete, Find the full content below:

A neutral solution of water at a particular temperature has a concentration of OH⁻ of 2.3×10⁻⁷ M. What is Kw at this temperature?

A second concern was discovered when a chemical dosing machine in the bottling line had a minor release during a change out of the chemical dimethyl dicarbonate (DMDC). The employees were evacuated without injury.

These two incidents led the winery to determine the level of risk and potential solutions. A risk assessment team was formed, and an assessment was performed. The team determined that the SO2 and DMDC exposure risks both presented multiple fatality – level risk and required immediate risk treatment.

Management sets the expectations, context, and objectives of the assessment. The risk assessment team was established that included the consultant as facilitator, the winemaker, assistant winemaker, cellar manager, operations manager, bottling

department manager, maintenance manager, and Health and Safety Executive (HSE) manager.

Data were collected regarding the SO2 and DMDC operations, equipment and instruments used, instructions, chemicals, and their SDSs, operator training, procedures, and available incident information. A search for similar events involving SO2 and DMDC were also conducted. Employees were interviewed to learn from their experiences, concerns, and suggestions.

The two procedures were observed to document and understand the sequence of tasks and potential risks associated with tasks. Photographs, tank quantities, room dimensions and configurations, distances to exits, means of egress, and other physical attributes were collected.

After reviewing the information, the potential concerns of fatalities or serious incidents were discussed. Workplace exposures such as pure SO2 releases and DMDC releases which present a potential for fatalities or serious incidents must be given the highest priority and controlled to an acceptable level. As a side note, the consultant explained that unlike like less-serious workplace incident rates, fatality, and serious incident/injury rates have not declined and do require serious attention. FSI exposures that can result in environmental releases, explosions, and disasters have been found to involve some of the following factors (14):

• Unusual and nonroutine work

• Nonproduction tasks
• Facility modification or construction activities
• Shutdowns and startups for repair and maintenance tasks
• Exposure to high-energy sources (e.g. electrical, steam, pneumatic, chemical) • Upsets (situations going from normal to abnormal).

Answers

The risk assessment team, consisting of various members from different departments within the winery, conducted a comprehensive assessment of the potential risks associated with sulfur dioxide (SO2) and dimethyl dicarbonate (DMDC) operations.

Data was collected regarding the equipment, chemicals, procedures, training, incident history, and physical attributes of the workplace. The team also interviewed employees to gather their experiences, concerns, and suggestions.

After reviewing the collected information, the team identified the potential risks of fatalities or serious incidents related to workplace exposures of SO2 and DMDC. These risks were considered of utmost priority and required immediate control to ensure an acceptable level of safety. The consultant highlighted the importance of addressing these serious risks, as fatality and serious incident rates have not shown a decline and demand serious attention.

Factors contributing to the potential for environmental releases, explosions, and disasters were identified, including unusual and nonroutine work, nonproduction tasks, facility modification or construction activities, shutdowns and startups for repair and maintenance tasks, exposure to high-energy sources (such as electrical, steam, pneumatic, chemical), and situations transitioning from normal to abnormal (upsets).

Based on the assessment and the identified risks, it is crucial for the winery to implement effective control measures to minimize the potential for fatalities, serious incidents, and environmental disasters. These measures may include improving procedures, enhancing operator training, implementing stricter safety protocols, and ensuring proper handling and storage of chemicals.

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it was observed that the particles of an unknown substance slide past one another. what is the state of matter of the substance? solid liquid gas plasma

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Based on the observation that the particles of an unknown substance slide past one another, the state of matter of the substance can be determined as a liquid.(option b)

In a liquid state, the particles are closely packed together but still have the ability to move past each other. This allows the substance to flow and take the shape of its container. Liquids have definite volume, meaning they maintain a constant amount of substance, but they do not have a definite shape.

For example, think of pouring water from one container to another. The water molecules can easily slide past each other, allowing the water to flow. This behavior is characteristic of liquids.

In contrast, in a solid state, particles are tightly packed together and do not move freely. In a gas state, particles are far apart and move rapidly in all directions. Plasma, on the other hand, consists of charged particles and is not commonly found in everyday substances.

Therefore, based on the observation of particles sliding past one another, the substance can be identified as a liquid (option b is correct).

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you analyze a sample of a meteorite that landed on earth and find that 3 4 of the uranium-238 radioactive atoms have decayed into lead-206. what is the age of the sample (in years) if the half-life of uranium-238 is 4.5 billion years?

Answers

The age of  the sample of a meteorite that landed on earth is approximately 9 billion years.

To determine the age of the sample, we can use the concept of radioactive decay and the half-life of uranium-238.

Given that 3/4 of the uranium-238 atoms have decayed into lead-206, this means that only 1/4 of the original uranium-238 atoms remain.

Each half-life represents the time it takes for half of the radioactive atoms to decay. Since the half-life of uranium-238 is 4.5 billion years, we can use this information to calculate the number of half-lives that have passed.

Let's represent the number of half-lives as "n." Since 1/4 of the original uranium-238 atoms remain, we can express this mathematically as:

(1/2)^n = 1/4

Taking the logarithm base 2 of both sides of the equation, we get:

n * log2(1/2) = log2(1/4)

n * (-1) = -2

n = 2

Therefore, 2 half-lives have passed.

Now, we can calculate the age of the sample by multiplying the number of half-lives by the half-life of uranium-238:

Age = n * half-life

Age = 2 * 4.5 billion years

Age = 9 billion years

Thus, the age of the sample is approximately 9 billion years.

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the percent yield of ammonia synthesized from its elements is 20% under certain conditions. which process may increase the yield? chegg

Answers

One possible process that may increase the yield of ammonia synthesis is adjusting the reaction conditions. By changing the temperature and pressure, it is possible to optimize the reaction to achieve a higher yield.

For example, increasing the temperature can increase the rate of reaction, while increasing the pressure can shift the equilibrium towards the product side, resulting in a higher yield. Another process that may increase the yield is using a catalyst. Catalysts can speed up the reaction and lower the activation energy, allowing the reaction to proceed more efficiently. By using a catalyst, it may be possible to achieve a higher yield of ammonia. Additionally, improving the purity of the reactants and removing any impurities can also increase the yield.

Overall, adjusting reaction conditions, using a catalyst, and ensuring the purity of reactants are potential processes that may increase the percent yield of ammonia synthesis.

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calcium hydroxide, ca(oh)2, is used as a calcium nutritional supplement in some foods and beverages, such as orange juice. what is the ph of a solution of 0.0012m calcium hydroxide at 25.0∘c? round the answer to two decimal places.

Answers

Calcium hydroxide, Ca(OH)2, is a compound that can be used as a calcium nutritional supplement in certain foods and beverages, such as orange juice. To determine the pH of a solution of 0.0012 M calcium hydroxide at 25.0°C, we can use the following steps:

1. Calcium hydroxide dissociates into calcium ions (Ca2+) and hydroxide ions (OH-) in water.
2. The concentration of hydroxide ions can be calculated using the molarity of the calcium hydroxide solution, which is 0.0012 M.
3. Since calcium hydroxide is a strong base, we can assume complete ionization, meaning all of it dissociates.
4. The concentration of hydroxide ions is equal to the concentration of calcium hydroxide, so [OH-] = 0.0012 M.
5. The pOH of the solution can be calculated by taking the negative logarithm of the hydroxide ion concentration: pOH = -log([OH-]).
6. Finally, the pH can be determined using the equation pH = 14 - pOH.

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how long will it take for the 1.35 mgmg sample of pu-236pu-236 to decay to 0.100 mgmg ? (plutonium-236 is an alpha emitter with a half-life of 2.86 years.)

Answers

The 1.35 mg sample of plutonium-236 (Pu-236) will take approximately 38.61 years to decay to 0.100 mg, based on its half-life of 2.86 years.

To calculate the time it will take for the 1.35 mg sample of plutonium-236 (Pu-236) to decay to 0.100 mg, we can use the concept of half-life.
First, we need to determine the number of half-lives required for the decay. We can do this by dividing the initial amount of Pu-236 (1.35 mg) by the amount it decays each half-life (0.100 mg).
1.35 mg / 0.100 mg = 13.5 half-lives
Since the half-life of Pu-236 is 2.86 years, we can calculate the total time it will take by multiplying the number of half-lives by the half-life duration:
13.5 half-lives * 2.86 years = 38.61 years
Therefore, it will take approximately 38.61 years for the 1.35 mg sample of Pu-236 to decay to 0.100 mg.

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draw the major product of each synthetic sequence in the box provided. show your work to be considered for partial credit. indicate stereochemistry as appropriate.

Answers

It's worth mentioning that discussing the stereochemistry of a product requires information about the reactants, reagents, and reaction conditions.

I'm sorry, but the question you provided is incomplete and does not specify the specific synthetic sequences or reactions. To provide an accurate and informative answer, I would need more details about the synthetic sequences you are referring to. Please provide the specific reactions or steps involved in the synthetic sequence, and I'll be happy to assist you further.

Additionally, it's worth mentioning that discussing the stereochemistry of a product requires information about the reactants, reagents, and reaction conditions. If you could provide more specific information, I can help you understand the stereochemistry aspects of the synthetic sequence as well.

Please feel free to provide more details, and I'll do my best to assist you.

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associations between methylenetetrahydrofolate reductase (mthfr) c677t/a1298c polymorphisms and essential hypertension: a systematic review and meta-analysis

Answers

This systematic review and meta-analysis aimed to explore the potential associations between methylenetetrahydrofolate reductase (MTHFR) C677T and A1298C polymorphisms and essential hypertension. The results could contribute to a better understanding of the genetic factors involved in the development and pathogenesis of hypertension, potentially paving the way for personalized approaches to prevention, diagnosis, and treatment.

This systematic review and meta-analysis aimed to explore the potential associations between methylenetetrahydrofolate reductase (MTHFR) C677T and A1298C polymorphisms and essential hypertension. The study followed a comprehensive approach to collect relevant research articles, assess their quality, and extract data for analysis.

By analyzing the pooled data from multiple studies, the researchers evaluated the strength and significance of the associations between MTHFR polymorphisms and essential hypertension. The review employed statistical methods to calculate pooled odds ratios (ORs) and confidence intervals (CIs) to determine the overall effect sizes and the level of association between the polymorphisms and hypertension risk.

The findings of the meta-analysis provided insights into the potential relationships between MTHFR C677T and A1298C polymorphisms and essential hypertension. The results could contribute to a better understanding of the genetic factors involved in the development and pathogenesis of hypertension, potentially paving the way for personalized approaches to prevention, diagnosis, and treatment.

It is important to note that further research and replication studies are necessary to validate and confirm the findings of this systematic review and meta-analysis.

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at the equivalence point of a titration of the [h ] concentration is equal to: group of answer choices 7 1 x 107 m 1 x 10-7 m [oh-]

Answers

At the equivalence point of a titration, the concentration of [H+] is equal to 1 x 10^-7 M.

At the equivalence point of a titration, the [H+] concentration is equal to 1 x 10^-7 M. This is because at the equivalence point, the stoichiometric ratio between the acid and base has been reached, resulting in complete neutralization. In an acid-base titration, the equivalence point is the point at which the moles of acid are equal to the moles of base.

At the equivalence point, all the acid has been reacted with the base, resulting in the formation of water and a salt. In the case of a strong acid and strong base titration, such as HCl and NaOH, the neutralization reaction is complete, and the resulting solution contains only water and the corresponding salt. The concentration of [H+] at this point is determined by the autoionization of water, which is approximately 1 x 10^-7 M at 25 degrees Celsius.

Therefore, at the equivalence point of a titration, the [H+] concentration is equal to 1 x 10^-7 M, indicating a neutral pH.

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9.0 mol 11.0 molnitrogen dioxidegasand liquid water react to form aqueous nitric acid and nitrogen monoxidegas. suppose you have of and of in a reactor. suppose as much as possible of the reacts. how much will be left? round your answer to the nearest

Answers

The amount (in mole) of the excess reactant that will be left after the reaction is 8 moles

How do i determine the mole of excess reactant that will be left?

First, we shall determine the limiting reactant. Details below

3NO₂ + H₂O -> 2HNO₃ + NO

From the balanced equation above,

3 moles of NO₂ reacted with 1 mole of H₂O

Therefore,

9 moles of NO₂ will react with = (9 × 1) / 3 = 3 mole of H₂O

Since only 3 moles of H₂O is required to react completely with 9 moles of NO₂.

Thus, the limiting reactant is NO₂ and the excess reactant is H₂O

Finally, we shall obtain the mole of excess reactant that is left. Details below:

Excess reactant => H₂OMole of excess reactant given = 11 molesMole of excess reactant that reacted = 3 molesMole of excess reactant left =?

Mole of excess reactant left = mole given - mole that reacted

= 11 - 3

= 8 moles

Thus, the mole of the excess reactant that will be left is 8 moles

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what is meant bt absolute 0 temperature?​

Answers

Answer:

Absolute zero is an idea in thermodynamics that describes the lowest energy system.

Explanation:

Thermodynamics

Thermodynamics is the study of thermal energy and heat. One of the most important ideas in thermodynamics is entropy. Entropy is defined as the chaos within a system. Chaos is the movement or different orientations of molecules in a system. Entropy is related to temperature; the higher the temperature, the higher the entropy. High entropy means there is a large amount of chaos in a system, while low entropy is low chaos.

Absolute zero

Absolute zero occurs when the temperature of a system is 0 kelvin or -273.15 °C. Zero kelvin is the theoretical temperature in which entropy equals 0. This means that there is no movement or energy within a system. Absolute zero is the lowest energy a system can possibly have.

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The cheapest data backup strategy, which uses the least amount of storage space: 4. The middle ground of backup strategies: 5. The data strategy used in the father backup cycle: Determine both the regular and overtime wage rates for each of the following employees. All are paid an overtime wage rate 1.5 times their respective regular wage rates.NOTE: For simplicity, all calculations throughout this exercise, both intermediate and final, should be rounded to two decimal places at each calculation.1:Alice Rhoades earns a weekly wage of $1,200. During the most recent week, she worked 48 hours.Regular Wage Rate = $Overtime Wage Rate = $2:Hank Long earns a biweekly wage of $3,400. During the most recent week, she worked 45 hours.Regular Wage Rate = $Overtime Wage Rate = $ Companies regularly review the locations where they offshore activities to and the associated costs. Some decide to reshore or nearshore. Referring to the world map at the start of the book, how do the various trends in offshoring impact the major logistics hubs in the world, and will there be a need for more and/or different hubs? In answering this it is a good idea to review some of the content of Chapter 2 on trends in globalization and international trade, and Chapters 6 and 7 on transport and containerization. The location of the various nodes depicted on the map is dictated by two factors viz. demand for transport to Ifrom those locations, and the hub and spoke nature of many transport networks. As we saw in earlier chapters, hub locations can be independent of local transport demand i.e. the hub location is dictated by overall network structure and not local transport demand. In reality, the global transport map is continuously evolving as transport demand changes - and of course we know that the latter is a derived demand so that in turn changes as the nature and location of both manufacturing and demand for products changes. So, what is the distinction between outsourcing and offshoring? Offshoring is not the same as outsourcing because outsourcing involves handing process ownership over to a third party, whereas with offshoring the company may still own and control the process itself in the lower cost location. It is also important to note that a company can if it wishes outsource and offshore a process at the same time. Furthermore, another important distinction we should make in the context of this module is between integration and collaboration. Supply chain integration is a term that embodies various communication channels and linkages within a supply chain network. Supply chain collaboration refers to how the relationship between supply chain partners develops over time. Integration is possible without collaboration. But if collaboration is required then integration is an enabler. Moreover, understanding the meaning of procurement as an 'umbrella term' that includes sourcing and purchasing and incorporates the activities involved in specifying requirements, identifying appropriate sources, evaluating options and then arranging the purchase of products and/or services from those sources that are fit for purpose, costeffective and sustainable is key. Procurement is thus concerned with more than just purchasing, with the latter in effect just a transactional activity. Finally, it is important for our well-rounded understanding of this module, to be able to describe and differentiate the various LSCM costing approaches and concepts. The following concepts are important in this context: - Opportunity costs - Landed costs - Activity-based costing - Total costs of ownership - Through / full life costs - Generalized costs What issues should a procurement manager for a large aerospace manufacturer with a global presence consider in appointing an LSP? qin a, musket a, musich pr, schweitzer jb, xie q. receptor tyrosine kinases as druggable targets in glioblastoma: do signaling pathways matters?