Answer:
5w^2 + 6w - 32
Step-by-step explanation:
Subtract as needed and combine like terms
(-2w^2 + 6w - 19) - (-7w^2 +13) dont forget to distribute the negative
so you get this:
-2w^2 + 7w^2 = 5w^2
6w
-19 - 13 = - 32
your answer is 5w^2 + 6w - 32
hope this helps :)
Hi :)
Let's solve by combining like terms
——————————Combining like terms means you add or subtract
terms with the same variable (if any)terms with the same exponentSolve by combining like terms
[tex]\implies\darkblue\sf{-2w^2+6w-19-(-7w^2+13)}\\\implies\darkblue\sf{-2w^2+6w-19+7w^2-13}\\\implies\darkblue\sf{-2w^2+7w^2+6w-19-13}\\\implies\darkblue\sf{\underline{5w^2+6w-32}}[/tex]
[tex]\tt{Learn\:More;Work\:Harder}[/tex]
:)
find derivative of y= sin x sin 3x
The derivative of y= sin x sin 3x is [tex]$=3 \cos x-3 \cos 3 x$[/tex]
What is a derivative?Futures contracts, options contracts, and credit default swaps are typical types of derivatives. Beyond this, a sizable number of derivative contracts satisfy the requirements of a wide range of counterparties.To find the derivative of y= sin x sin 3x:
[tex]$y=3 \sin (x)-\sin (3 x)$[/tex]
[tex]$y^{\prime}=3 \cos x-[\cos (3 x) \cdot 3]$[/tex]
[tex]$y^{\prime}=3(\cos x-\cos 3 x)$[/tex]
[tex]\frac{dx}{dy} =3 cosx - 3 cos x[/tex]
Differentiate [tex]sin 3x[/tex] using the chain rule
Given [tex]y=f^{'} (g(x))*g^{'}[/tex]←chain rule
y=[tex]y=3 sin x-sin 3x[/tex]
[tex]\frac{dx}{dy} =3 cos x - cos 3x*\frac{d}{dx} (3x)[/tex]
[tex]=3cosx-3cos3x[/tex]
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27. Identify the domain of the set (6,2), (-1,-5), (4,4), (9, 2) and tell if the relation is a function.
O {-1, 4, 6, 9); not a function
O {-5, 2, 4}; a function
O {-1,4,6,9}; a function
O {-5, 2, 4); not a function
Answer:
the third one
Step-by-step explanation:
it is function that contain four domain
ill give brainliest
Directions: Factor the following trinomials containing negative numbers. Follow the rules for operations with signed numbers to identify the correct binomial factors.
1. x2 + 6x - 7
2. x2 - 5x + 6
3. x2 - 6x - 7
4. x2 + 5x - 6
5. x2 + x - 12
6. x2 - 2x - 8
7. x2 - 4x - 5
8. x2 + 2x - 3
9. x2 - 16
10. x2 - x - 12
11. x2 -9x + 18
12. x2 -5x - 14
13. x2 - 7x + 10
14. x2 -11x + 24
15. x2 - x - 30
The aim of factorization to obtain the common factors that are present in the expression.
What are factors?When we factorize an expression, the aim is to obtain the common factors that are present in the expression.
Now we have trinomials numbered 1 - 15. Trinomial is an expression that is made up of three terms. Quadratic expressions are mostly found to appear as trinomial
The binomial factors that are associated with each are shown in the factorized expressions below. The binomials contain two terms in each bracket.
Given the trinomials, the correct binomial factors are;
(x−1)(x+7) (x−2)(x−3)(x+1)(x−7) (x−1)(x+6)(x−3)(x+4)(x+2)(x−4)(x+1)(x−5)(x−1)(x+3) (x+4)(x−4)(x+3)(x−4)(x−3)(x−6)(x+2)(x−7)(x−2)(x−5) (x−3)(x−8) (x+5)(x−6)Learn more about factorization:https://brainly.com/question/19386208
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Based on the family the graph below belongs to, which equation could represent the graph?
Considering the asymptotes of the function, the equation that represents the graph is:
[tex]y = \frac{1}{x + 2} + 3[/tex]
What are the asymptotes of a function f(x)?The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.This function, from the graph, has a vertical asymptote at x = -2, hence the denominator is given by:[tex]y = \frac{1}{x + 2} + 3[/tex]
x + 2, as x + 2 = 0 -> x = -2.
The horizontal asymptote is of y = 3, hence:
[tex]\lim_{x \rightarrow \infty} f(x) = 3[/tex]
Which means that the function is described by the following rule:
[tex]y = \frac{1}{x + 2} + 3[/tex]
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A cylinder has radius of 4 inches and height 10inches.There’s a small cylinder inside the previous cylinder of radius of 2 inches with the same height and same centre.What is total surface area?
The surface area of the cylinder is 48π inches².
How to find the Surface area of a cylinder?Surface area of a cylinder = 2πr(r + h)
where
r = radiush = heightTherefore,
Surface area of the smaller cylinder = 2 × π × 2(2 + 10)
Surface area of the smaller cylinder = 4π(12)
Surface area of the smaller cylinder = 48π
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(3x+1)^2-2(3x+1)(3x+5)^2+(3x+5)^2
Answer:
soln,
write the question
=9x^2+1-6x-2×9x^2+25+9x^2+25
=9x^2+1-6x-18x^2+25+9x^2+25
=9x^2-18x^2+9x^2+1+25+25-6x
=51-6x
if(3x+1)^2 mean that (3x+1)has power of 2 and u don't have to use the formula this is the answer
Step-by-step explanation:
it's just BODMAS method
I need help with this question:
Simplify
The simplified form of the given expression as a fraction is 7x/x-7
Simplification of fractionsFractions are written as a ratio of two integers. For instance a/b is a fraction where a and b are integers.
Given the expression below;
(1/7+1/x)/(1/49+1/x²)
Find the LCM to have:
(x+7/7x)/(x²-49)/49x²
Divide to have:
x+7/7x * 49x²/(x²-49)
(x+7) * 7x/(x+7)(x-7)
Cancel out the like terms to have:
1 * 7x/x-7
= 7x/x-7
Hence the simplified form of the given expression as a fraction is 7x/x-7
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1. What is the chance of landing on a number divisible by 2?
6
1
2
4
3
The chance or probability of landing on a number divisible by 2 is 1/2.
The likelihood of an event occurring is defined by probability. By simply dividing the favorable number of possibilities by the entire number of possible outcomes, the probability of an occurrence can be determined using the probability formula. Because the favorable number of outcomes can never exceed the entire number of outcomes, the chance of an event occurring might range from 0 to 1.
According to the question,
Total number of outcomes = 6
Favorable number of outcomes = 3
Thus, the required Probability = 3/6 =1/2
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The controller of MingWare Ceramics Inc. wishes to prepare a cost of goods sold budget for September. The controller assembled the following information for constructing the cost of goods sold budget: Direct materials: Enamel Paint Porcelain Total Total direct materials purchases budgeted for September $35,870 $7,530 $139,890 $183,290 Estimated inventory, September 1 1,730 4,150 6,920 12,800 Desired inventory, September 30 2,980 2,710 7,150 12,840 Direct labor cost: Kiln Department Decorating Department Total Total direct labor cost budgeted for September $51,550 $149,500 $201,050 Finished goods inventories: Dish Bowl Figurine Total Estimated inventory, September 1 $5,810 $3,310 $2,730 $11,850 Desired inventory, September 30 3,720 4,590 4,360 12,670 Work in process inventories: Estimated inventory, September 1 $3,540 Desired inventory, September 30 1,980 Budgeted factory overhead costs for September: Indirect factory wages $80,400 Depreciation of plant and equipment 10,550 Power and light 5,110 Indirect materials 3,390 Total 99,450 Use the preceding information to prepare a cost of goods sold budget for September. For those boxes in which you must enter subtracted or negative numbers use a minus sign. MingWare Ceramics Inc. Cost of Goods Sold Budget For the Month Ending September 30 Finished goods inventory, September 1 $Finished goods inventory, September 1 Direct labor $Direct labor Direct materials: $- Select - - Select - $- Select - - Select - $- Select - Direct labor fill in the blank 15 - Select - - Select - $- Select - Work in process inventory, September 30 fill in the blank 22 - Select - $- Select - - Select - $- Select - 4,100
The preparation of the Cost of Goods Sold Budget for MingWare Ceramics Inc. in September is as follows:
Cost of Goods Sold Budget:Beginning inventory of finished goods $11,850
Cost of goods manufactured 485,310
Ending inventory of finished goods (12,670)
Cost of Goods Sold $484,490
What is the cost of goods sold budget?The cost of goods sold budget sums the costs of the beginning inventory of finished goods with the cost of goods manufactured and subtracts the ending inventory of finished goods.
The cost of goods sold budget is based on the cost of goods manufactured budget.
Data and Calculations:Direct materials: Enamel Paint Porcelain Total
Total direct materials purchases
budgeted for September $35,870 $7,530 $139,890 $183,290
Estimated inventory, September 1 1,730 4,150 6,920 12,800 Desired inventory, September 30 (2,980) (2,710) (7,150) (12,840)
Materials used in production $183,250
Direct labor cost: Kiln Department Decorating Department Total
Total direct labor cost
budgeted for September $51,550 $149,500 $201,050
Finished goods inventories: Dish Bowl Figurine Total
Estimated inventory, September 1 $5,810 $3,310 $2,730 $11,850
Desired inventory, September 30 3,720 4,590 4,360 12,670
Cost of goods manufactured budget:Work in process inventories:
Estimated inventory, September 1 $3,540
Direct materials used in production $183,250
Direct labor costs $201,050
Total factory overhead costs $99,450
Desired inventory, September 30 (1,980)
Cost of goods manufactured $485,310
Budgeted factory overhead costs for September:Indirect factory wages $80,400
Depreciation of plant and equipment 10,550
Power and light 5,110
Indirect materials 3,390
Total 99,450
Thus, to prepare the cost of goods sold, as above, MingWare Ceramics, requires to determine the cost of goods manufactured for September.
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An airplane is heading north at an airspeed of 640 km/hr, but there is a wind blowing from the southwest at 90 km/hr. How many degrees off course will the plane end up flying, and what is the plane's speed relative to the ground? Round your answers to 2 decimal places.
An airplane is heading north at an airspeed of 640 km/hr, but there is a wind blowing from the southwest at 90 km/hr. degrees off course will be 6.25°
How many degrees off course will the plane end up flying, and what is the plane's speed relative to the ground?Generally, the equation for the velocity of the plane with reference to the ground is mathematically given as
Vp= velocity of the plane with reference to wind+ velocity of the wind with reference to ground
Therefore
Vp=Vp'+Vw
[tex]mVp=\sqrt{(640)^2+(90)^2-2*640*90cos45}[/tex]
mVp=579.8km/h
where
[tex]\frac{sintheta}{90}=\frac{sin45}{Vp'}[/tex]
[tex]sin \theta=\frac{90}{579.8}*sin45[/tex]
sin[tex]\theta=0.109[/tex]
[tex]\theta=sin^{-1}(0.109)=6.25[/tex]
In conclusion, degrees off course will be 6.25
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please help me im begging you help me i beg u :(
which expression gives the value of QR?
a. 67 sin 80 degrees over sin 52 degrees
b. 67 sin 52 degrees over sin 80 degrees
c. 51 tan 52 degrees
d. 51 sin 80 degrees over cos 52 degrees
Answer:
B
Step-by-step explanation:
using the Sine Rule in Δ QRS
[tex]\frac{QR}{sinS}[/tex] = [tex]\frac{RS}{sinQ}[/tex] ( substitute values )
[tex]\frac{QR}{sin52}[/tex] = [tex]\frac{67}{sin80}[/tex] ( cross- multiply )
QR × sin80° = 67 × sin52° ( divide both sides by sin80° )
QR = [tex]\frac{67sin52}{sin80}[/tex]
Find f. f ″(x) = x^−2, x > 0, f(1) = 0, f(6) = 0
If you do in fact mean [tex]f(1)=f(6)=0[/tex] (as opposed to one of these being the derivative of [tex]f[/tex] at some point), then integrating twice gives
[tex]f''(x) = -\dfrac1{x^2}[/tex]
[tex]f'(x) = \displaystyle -\int \frac{dx}{x^2} = \frac1x + C_1[/tex]
[tex]f(x) = \displaystyle \int \left(\frac1x + C_1\right) \, dx = \ln|x| + C_1x + C_2[/tex]
From the initial conditions, we find
[tex]f(1) = \ln|1| + C_1 + C_2 = 0 \implies C_1 + C_2 = 0[/tex]
[tex]f(6) = \ln|6| + 6C_1 + C_2 = 0 \implies 6C_1 + C_2 = -\ln(6)[/tex]
Eliminating [tex]C_2[/tex], we get
[tex](C_1 + C_2) - (6C_1 + C_2) = 0 - (-\ln(6))[/tex]
[tex]-5C_1 = \ln(6)[/tex]
[tex]C_1 = -\dfrac{\ln(6)}5 = -\ln\left(\sqrt[5]{6}\right) \implies C_2 = \ln\left(\sqrt[5]{6}\right)[/tex]
Then
[tex]\boxed{f(x) = \ln|x| - \ln\left(\sqrt[5]{6}\right)\,x + \ln\left(\sqrt[5]{6}\right)}[/tex]
Find tan 0.
16
20
12
0
The value of tan 0 as given in question is 0
What are trigonometry identity?Trigonometric identities are equations involving the trigonometric functions that are true for every value of the variables involved. They are written in terms of sine, cosine and tangent.
According to the question, we are to find the value of tan0. This is as shown below;
tan 0 = 0
Note that the tangent angle is positive in the first and third quadrant. Hence the result of the given tangent expression will also be positive.
Hence the value of tan 0 as given in question is 0
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Manufacturers of tires report that car tires should be able to last an average of 50,000 miles. A new tire company produces a different type of tread and tests 100 randomly selected tires. This sample of 100 tires lasted an average of 51,500 miles. Assuming the new type of tread does not improve the mileage of the tire, 200 sample means were simulated and displayed on the dotplot.
Using the dotplot and the sample mean mileage, is there convincing evidence that the new type of tread improves the mileage of the tire?
Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
Yes, because a mean mileage of 51,500 or less occurred 186 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
No, because a mean mileage of 51,500 or less occurred 186 out of 200 times, the mean mileage is not statistically significant. There is not convincing evidence the new type of tire tread improves mileage of the tire.
No, because a mean mileage of 51,500 or more occurred 14 out of 200 times, the mean mileage is not statistically significant. There is not convincing evidence the new type of tire tread improves mileage of the tire.
There is convincing evidence the new type of tire tread improves mileage of the tire.
How to interpret the mean mileage?The given parameter is:
Average = 50000 miles
New average = 51500 miles
The dot plot is added as an attachment
From the dot plot, we can see that the mean value of 51500 or more occurred 14 times out of the 200 samples
So, the conclusion is that: (a) Yes, because a mean mileage of 51,500 or more occurred only 14 out of 200 times, the mean mileage is statistically significant. There is convincing evidence the new type of tire tread improves mileage of the tire.
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There are three novels on Sam's reading table: Light, Zami, and Money.
. On his next trip, he can choose to take some, none, or all of these novels. In the braces below, list all the possible sets of novels that Sam can take.
Write each set in your list in roster form. If there is more than one set in your list, separate them with commas. If you need the empty set in your list, use the symbol Ø.
The subsets of the set of novels is given as follows:
{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.
How to find the subsets of a set?Suppose we have a set with cardinality n, that is, with n elements. This set will have 2^n subsets, which are all the possible combinations with the elements of the set, including the empty set.
In this problem, the novels are given as follows:
Light, Zami, and Money.
Hence the possible subsets are given as follows:
{Ø, {Light}, {Zami}, {Money}, {Light, Zami}, {Light, Money}, {Zami, Money}, {Light, Zami, Money}}.
With is the list that is asked for this problem, which are the subsets of the set of novels.
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Hi! i really need help on this question tell me if u think u know TYSSSM!!!
pila the woodpecker can drill a small hole in a tree trunk with 25 pecks, which is only 1/4% the average number of pecks that she can make each day. How many times per day can pila peck a tree?
well, we know that 25 pecks is 1/4% or namely 0.25%, less than 1%, and let's say the amount of pecks per day will be "x", which is 100% of that.
[tex]\begin{array}{ccll} pecks&\%\\ \cline{1-2} 25 & \frac{1}{4}\\[1em] x& 100 \end{array} \implies \cfrac{25}{x}~~=~~\cfrac{ ~~ \frac{1}{4} ~~ }{100}\implies 2500=x\cfrac{1}{4} \\\\\\ 2500=\cfrac{x}{4}\implies 10000=x[/tex]
Pila can peck a tree approximately 10,000 times per day.
Given that Pila can drill a small hole in a tree trunk with 25 pecks, which is only 1/4 % the average number of pecks that she can make each day.
We need to determine how many times per day can pila peck a tree.
Let's denote the average number of pecks Pila can make in a day as "x."
According to the information given, Pila can drill a small hole in a tree trunk with 25 pecks, which is only 1/4% (0.25%) of the average number of pecks she can make each day.
We can set up the following equation to represent the relationship:
0.25% of x = 25
To solve for x, we first convert 0.25% to decimal form by dividing by 100:
0.25% = 0.25/100 = 0.0025
Now, we can rewrite the equation:
0.0025x = 25
To isolate x, we divide both sides of the equation by 0.0025:
x = 25 / 0.0025
Simplifying the right side gives us:
x = 10,000
Therefore, Pila can peck a tree approximately 10,000 times per day.
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It takes Natalie's mother 20 minutes to drive to work. She works 6 miles away.
If she drives the same speed to pick up Natalie at a friend's house that is 14 miles
away, about how long will the drive take?
A 8.7 minutes
B 2.4 minutes
C 45.7 minutes
D 705 minutes
Answer:
B. 45.7
Step-by-step explanation:
20/6=3.33
3.33*14=46.62
46.62 is closest to 45.7
Therefore, 45.7 is the best answer.
Evaluate each expression if A=2
B=-3. C=-1. D=4
2d-a/b
Answer:
2 × 4 - 2 / -3
8-2/-3
6/-3
-2
ONE HUNDRED LOTTERY TICKETS ARE SOLD FOR $5.00 EACH. ONE PRIZE OF $300
WILL BE AWARDED. STEVE PURCHASES ONE TICKET. FIND HIS EXPECTATION.
i need help with these 2
Answer:
Step-by-step explanation: Hey for the second one I got y = -3/4x -0.5 I'm not sure if its correct though sorry if not
ill try my best to explain my solution though
1. From the parallel equation (3x + 4y = 12) all we need to do is find the slope
So the easiest way to do so is to put the said equation in y-intercept form
y=mx +b
m= slope
b= y intercept
so 1. 3x + 4y = 12
=
4y = 12-3x
divide that by 4 to get only y
y=3-3/4x
-3/4 is our slope
y=-3/4x+b
than we have a point -2, -2
if we put -2 for y
-2=-3/4x+b
and then we put our -2 for x
-2 = -3/4 * -2 + b
=
-2 = -1.5 +b
b=-0.5
Answer : y=-3/4x-0.5
On Wednesday, the temperature changes -3
∘
each hour for 10 hours. If the temperature was 12
∘
to begin with on Wednesday, what was the temperature after the 10 hours.
Answer:
-24 would be the temperature
Answer:
-24 BECAUSE I did all the math.
find the area of a triangular shaped land having the length of three sides 20,34 M and 42 respectively in metre square Anna and ropani
Step-by-step explanation:
if I understand you correctly, then the 3 sides are
a = 20 m
b = 34 m
c = 42 m
under this assumption the best is to use Heron's Formula to get the area :
s = (a + b + c)/2
area = sqrt(s(s - a)(s - b)(s - c))
in our case
s = (20 + 34 + 42)/2 = 96/2 = 48
area = sqrt(48(48-20)(48-34)(48-42)) =
= sqrt(48×28×14×6) = sqrt(112,896) =
= 336 m²
Answer:
sorry i didnt know this D: <3
Step-by-step explanation:
Rachel is a stunt driver. One time, during a gig where she escaped from a building about to explode(!), she drove to get to the safe zone at 242424 meters per second. After 444 seconds of driving, she was 707070 meters away from the safe zone.
Let yyy represent the distance (in meters) from the safe zone after xxx seconds.
Complete the equation for the relationship between the distance and number of seconds.
The distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone. This can be obtained by converting the conditions to equations.
Find the equation for the relationship between the distance and number of seconds:A linear function containing one dependent and one independent variable.
It can be represented using the equation,
y = mx + c
where m is the slope
It is given in the question that,
Rachel is a stunt driver and one time during a gig where she escaped from a building about to explode she drove to get to the safe zone at 24 meters per second.
After 4 seconds of driving, she was 70 meters away from the safe zone.
Let, D(t) be the distance to the safe zone (measured in meters) and t be the time (measured in seconds)
After 4 seconds of driving, she was 70 meters away from the safe zone.
⇒ This means that at t = 4 seconds, D(4) = 70 meters
Rachel's rate is the slope of the function D(t). Since the distance is decreasing when the time is increasing, the slope must be negative
⇒ m = - 24
y = mx + c
⇒ D(t) = (-24)t + c
Put t = 4,
D(4) = (-24)4 + c
70 = -96 + c ⇒ c = 166
⇒ D(t) = 166 - 24t
Hence the distance from the safe zone after t seconds is D(t) = 166 - 24t given that drove to get to the safe zone at 24 meters per second and after 4 seconds of driving, she was 70 meters away from the safe zone.
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can you answer this question
Based on the given entries that Jonathan Shaw owes and owns, the Balance Sheet can be drawn below.
What is Jonathan Shaw's balance sheet?The assets will go to the right side of the sheet and the liabilities and equity will go to the left.
Jon's Shop of Gifts Balance Sheet
Assets Liabilities
Cash $2,556 Bank loan $19,000
Accounts Receivable: $450 Accounts Payable - $900
R. Gregory Ceramic supply
Accounts Receivable: $1,860 Accounts Payable - $2,900
R. Gregory Jose's Art Co.
Supplies $1,000 Total liabilities $22,800
Furniture $10,300 Equity
Equipment $20,000 Jonathan Shaw capital $51,166
Automobiles $37,800 Total equity $51,166
Total assets $73,966 Total liabilities and $73,966
equity
The equity can be found as:
= Assets - liabilities
= 73,966 - 22,800
= $51,166
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Two trains leave towns 664 miles apart at the same time and travel toward each other. One train travels 16 mih faster than the other. If they meet in 4 hours, what is the rate of each train?
Answer:
I think that I am right. One train is traveling at 75 mph and the other train is traveling at 91 mph
Step-by-step explanation:
If 4 out of 7 students at
Johnson High play sports,
about how many of the 504
students at the school play
sports?
[tex]\frac{4}{7}(504)=\boxed{288}[/tex]
Jennifer has 25 coins with a total value of $4.25. The coins are quarters and nickels. How many of each does she have?
Answer:
15 quarters and 10 nickels
Step-by-step explanation:
[tex]q+n=25[/tex]
[tex]0.25q+0.05n=4.25[/tex]
multiply the first equation by -0.25 and add the second equation to it
[tex]-0.25q-0.25n=-6.25\\0.25q+0.05n=4.25[/tex]
________________
[tex]-0.2n=-2[/tex]
[tex]n=\frac{-2}{-0.2} =10[/tex] has 10 nickels
[tex]q=25-n=25-10=15[/tex] has 15 quarters
10(.05) +15(0.25) = 0.5 + 3.75 = 4.25
Hope this helps
Find the value of y.
answer choices
A. 118
B. 32.5
C. 65
D. 130
The value of 'y' is 32. 5 degrees . Option B
How to determine the valueIt is important to note that If two chords intersect inside a circle,
The measure of the angle formed is half the sum of the measure of the arcs intercepted by the angle and its vertical angle
From the diagram, it is shown that the both the chords at 'y' and the angle '65' intersect in the circle
We then have that;
[tex]y = 65[/tex] × [tex]\frac{1}{2}[/tex]
[tex]y = 65[/tex] × [tex]0. 5[/tex]
y = 32. 5 degrees
We can see that the value of 'y' in the given figure is 32. 5 degrees which is half the angle at the vertex of the intersecting chords.
Thus, the value of 'y' is 32. 5 degrees . Option B
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Ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table given below. General Knowledge Math Science Acel Barek Carlin Acton Bay Acton Anael Max Anael Max Kai Kai Carl Anael Dario Dario Carlin Barek Let G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. Find G n M and G u S .
The computation shows that:
G n M = Anael and Max
G u S = Acel, Action, Anael, Max, Carl, Dario, Catlin, Kai, and Barek.
How to illustrate the information?From the information, ten students from a school appear in one or more subjects for an inter school quiz competition as shown in the table.
The subjects include general Knowledge Math Science.
Therefore, G represents the set of students appearing for General Knowledge, M represents the set of students appearing for Math, and S represents the set of students appearing for Science. The intersection is illustrated above.
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