Answer:
C. -1
Step-by-step explanation:
im not sure, but it's the one that makes sense to me, hope this helps!
does the table show a proportional relationship if so what is the value of y when X is 11
Answer:
1331
Step-by-step explanation:
since 11 cube is 1331
plz mark as brainliest
multiply the square root of 20 and the square root of 63
Answer:
36.0555
Step-by-step explanation:
Answer:
= square root of 7 i believe
Step-by-step explanation:
Consider the function y = acos(bx), where a > 0 and b > 0. Which change affects the locations of the x-intercepts of the graph?
Decrease a.
Decrease b.
Change the sign of a.
Change the sign of b.
Answer:
The correct option is;
Decrease b.
Step-by-step explanation:
The given information are;
The function in the question is given by the equation, y = a·cos(b·x)
Where;
a > 0 and b > 0
The location of the x-intercept is given by the values of x when y = 0 which are obtained as follows;
When y = 0, y = a·cos(b·x) = 0
Therefore;
cos(b·x) = 0/a = 0
∴ b·x = cos⁻¹(0) = π/2, 3·π/2, (4·n×π + π)/2
Therefore, as b decreases, x increases.
Answer: B
Decrease b.
Step-by-step explanation:
Solve 4(x+3)=4x+12 for x
Distribute 4 through the parentheses.
4x + 12 = 4x + 12
Subtract 12 from both sides.
4x + 12 - 12 = 4x + 12 - 12
Subtract twice.
4x = 4x
Subtract 4x again.
4x - 4x = 4x - 4x
The answer is 0.
On which interval is y = sin(x) strictly increasing?
Answer: 0, pi/2
Step-by-step explanation:
I guessed tbh
The interval in which the function y = sin( x ) will strictly increase is ( 0, π/2 ).
What is a function?A function is defined as the expression that set up the relationship between the dependent variable and independent variable.
The graph is attached with the answer below in the graph we can see the maximum and minimum values of the function y = sin ( x ).
In the graph the maximum limit of the function π/2 it means that the strict increment in the graph is in the interval of ( 0, π/2 ).
Therefore, the interval in which the function y = sin( x ) will strictly increase is ( 0, π/2 ).
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AP CAL AB HELP!
A plane flying with a constant speed of 14 km/min passes over a ground radar station at an altitude of 11 km and climbs at an angle of 25 degrees. At what rate is the distance from the plane to the radar station increasing 4 minutes later?
The distance is increasing at equation editorEquation Editor____ km/min.
Answer:
[tex]\frac{dc}{dt}\approx13.8146\text{ km/min}[/tex]
Step-by-step explanation:
We know that the plane travels at a constant speed of 14 km/min.
It passes over a radar station at a altitude of 11 km and climbs at an angle of 25°.
We want to find the rate at which the distance from the plane to the radar station is increasing 4 minutes later. In other words, if you will please refer to the figure, we want to find dc/dt.
First, let's find c, the distance. We can use the law of cosines:
[tex]c^2=a^2+b^2-2ab\cos(C)[/tex]
We know that the plane travels at a constant rate of 14 km/min. So, after 4 minutes, the plane would've traveled 14(4) or 56 km So, a is 56, b is a constant 11. C is 90+20 or 115°. Substitute:
[tex]c^2=(56)^2+(11)^2-2(56)(11)\cos(115)[/tex]
Evaluate:
[tex]c^2=3257-1232\cos(115)[/tex]
Take the square root of both sides:
[tex]c=\sqrt{3257-1232\cos(115)}[/tex]
Now, let's return to our law of cosines. We have:
[tex]c^2=a^2+b^2-2ab\cos(C)[/tex]
We want to find dc/dt. So, let's take the derivative of both sides with respect to t:
[tex]\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2+b^2-2ab\cos(C)][/tex]
Since our b is constant at 11 km, we can substitute this in:
[tex]\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-(11)^2-2a(11)\cos(C)][/tex]
Evaluate:
[tex]\frac{d}{dt}[c^2]=\frac{d}{dt}[a^2-121-22a\cos(C)][/tex]
Implicitly differentiate:
[tex]2c\frac{dc}{dt}=2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}[/tex]
Divide both sides by 2c:
[tex]\frac{dc}{dt}=\frac{2a\frac{da}{dt}-22\cos(115)\frac{da}{dt}}{2c}[/tex]
Solve for dc/dt. We already know that da/dt is 14 km/min. a is 56. We also know c. Substitute in these values:
[tex]\frac{dc}{dt}=\frac{2(56)(14)-22\cos(115)(14)}{2\sqrt{3257-1232\cos(115)}}[/tex]
Simplify:
[tex]\frac{dc}{dt}=\frac{1568-308\cos(115)}{2\sqrt{3257-1232\cos(115)}}[/tex]
Use a calculator. So:
[tex]\frac{dc}{dt}\approx13.8146\text{ km/min}[/tex]
And we're done!
12x - 3x + 90 = 12x + 57
X = ?
What is x ?
Answer:
x = 11
Step-by-step explanation:
12x - 3x + 90 = 12x + 57
simplify both sides
12x - 3x + 90 = 12x + 57
9x + 90 = 12x + 57
inverse operations
9x + 90 = 12x + 57
-9x -9x
90 = 3x + 57
-57 -57
33 = 3x
/3 /3
11 = x
Answer:
x = 11
General Formulas and Concepts:
Order of Operations: BPEMDAS
Step-by-step explanation:
Step 1: Write equation
12x - 3x + 90 = 12x + 57
Step 2: Solve for x
Combine like terms: 9x + 90 = 12x + 57Subtract 9 on both sides: 90 = 3x + 57Subtract 57 on both sides: 33 = 3xDivide 3 on both sides: 11 = xRewrite: x = 11Step 3: Check
Plug in x to verify it's a solution.
Substitute: 12(11) - 3(11) + 90 = 12(11) + 57Multiply: 132 - 33 + 90 = 132 + 57Subtract: 99 + 90 = 132 + 57Add: 189 = 189The sales taken in for tickets to an ice-skating rink is recorded on a quarterly basis, for a period of 8 quarters. 1 2 3 4 5 6 7 8 Quarter Sales (£) 7555 6695 5415 4150 7310 7015 5435 3885 (a) Describe any short term, seasonal or cyclical trends in the data. (b) Calculate the 3 period moving averages for the data. (c) Plot your moving averages on the graph below. (d) Make a prediction for the sales taken in for the following 2 quarters.
(a) Based on the given data, there appear to be short-term fluctuations in the sales of the ice-skating rink. The sales figures vary from quarter to quarter, with some quarters showing higher sales and others showing lower sales. This suggests the presence of short-term or seasonal trends in the data. For example, there is a notable increase in sales in quarters 1, 5, and 6, followed by a decrease in quarters 3, 4, and 8. This pattern indicates a possible seasonal or cyclical trend in the sales of the ice-skating rink.
(b) To calculate the 3-period moving averages, we take the average of the sales data over a window of three consecutive quarters and compute the average for each subsequent quarter. The moving averages smooth out the fluctuations in the data and provide a clearer picture of the underlying trend.
Quarter 1: (7555 + 6695 + 5415) / 3 = 6555
Quarter 2: (6695 + 5415 + 4150) / 3 = 5420
Quarter 3: (5415 + 4150 + 7310) / 3 = 5625
Quarter 4: (4150 + 7310 + 7015) / 3 = 6158.33
Quarter 5: (7310 + 7015 + 5435) / 3 = 6586.67
Quarter 6: (7015 + 5435 + 3885) / 3 = 5445
Quarter 7: (5435 + 3885 + 0) / 3 = 3106.67
Quarter 8: (3885 + 0 + 0) / 3 = 1295
(c) The moving averages can be plotted on a graph with the x-axis representing the quarters and the y-axis representing the sales figures. Each moving average value is plotted in the corresponding quarter.
(d) Based on the calculated moving averages, we can make a prediction for the sales taken in the following two quarters. The prediction will be the average of the sales figures for the last three quarters.
Prediction for Quarter 9: (7015 + 5435 + 3885) / 3 = 5445
Prediction for Quarter 10: (5435 + 3885 + 0) / 3 = 3106.67
Therefore, the prediction for the sales taken in the following two quarters is £5,445 for Quarter 9 and £3,107 for Quarter 10.
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IT'S DUE TODAY! IT'S EASY I SWEAR!
If I told you the length of one side of the triangle below was 5. What is the perimeter of the triangle?
Answer:
15
Step-by-step explanation:
Since it's an isosceles triangle, all the sides are the same. Since one side is 5 all the other sides are 5 as well. 5 × 3 = 15
What are the solution(s) to the quadratic equation 9x^2=4?
Answer:
x = 2/3 or x = -2/3
Step-by-step explanation:
Solve for x over the real numbers:
9 x^2 = 4
Hint: | Divide both sides by a constant to simplify the equation.
Divide both sides by 9:
x^2 = 4/9
Hint: | Eliminate the exponent on the left-hand side.
Take the square root of both sides:
Answer:x = 2/3 or x = -2/3
Write the equation of a line with the slope of -3 and through the point (2,-2).
Answer:
y +2 = -3(x -2)
Step-by-step explanation:
The point-slope form of the equation of a line is useful for this:
y -k = m(x -h) . . . for a line of slope m through point (h, k)
__
y +2 = -3(x -2) . . . . fill in the given values. Note that -(-2) = +2
A factory has two bottle filling machines, which run at the same time. Machine B fills bottles at a rate of x, which is 1.5 times the rate of Machine A. The factory is considering buying a new machine that would replace the other two machines. It can fill at a rate of 3x.
If the factory buys the new machine to replace the other two, which of the following expressions show the increase in rate?
HELP plz answer this!
Answer:
see explanation
Step-by-step explanation:
The equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
Given
y = [tex]\frac{2}{3}[/tex] x + 3 ← in slope- intercept form
with slope m = [tex]\frac{2}{3}[/tex]
Given a line with slope m then the slope of a line perpendicular to it is
[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{2}{3} }[/tex] = - [tex]\frac{3}{2}[/tex]
His error was in missing the negative sign from [tex]\frac{3}{2}[/tex]
Luke weight 90 pounds on earth and when he recheas the moon he weight twice lesser, why?
Answer:
he doesn't weight as much because he doesn't have gravity helping keep him to the ground
6 Kyle is creating a frame for a model car. He begins by plecing two rods together, as shown in the diagram. Justify why AB- 10. O Segment Addition Postulate O Addition Property O Definition of Collinear Points O Definition of Midpoint
According to the diagram provided, Kyle is creating a frame for a model car by placing two rods together. To justify why AB equals 10, we can use the Segment Addition Postulate.
The Segment Addition Postulate states that if three points A, B, and C are collinear (meaning they lie on the same line), then point B is between points A and C if and only if the sum of the lengths of segments AB and BC is equal to the length of segment AC. In this case, the diagram shows points A, B, and C on a line, where A is the left endpoint, B is the midpoint, and C is the right endpoint. Since point B is the midpoint of segment AC, it divides the segment into two equal parts. Therefore, the length of segment AB is equal to the length of segment BC, and since the lengths are equal, we can conclude that AB is equal to 10 units. Hence, the justification for AB being 10 is based on the Segment Addition Postulate, as it guarantees that point B is the midpoint of segment AC.
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Complete question:
Kyle is creating a frame for a model car. He begins by plecing two rods together, as shown in the diagram. Justify why AB- 10. O Segment Addition Postulate O Addition Property O Definition of Collinear Points O Definition of Midpoint
What is the best method to separate a mixture of staples and salt?
Answer:
A filter.
Step-by-step explanation:
a developer wants to develop a 16-acre subdivision. he figures that the streets and common area will take up about 30% of this overall area. if the minimum lot size is to be 12,000 sf, how many lots can the developer have on this property?
The developer can have a maximum of 40 lots on the 16-acre subdivision.
To calculate the number of lots the developer can have on the 16-acre subdivision, we need to subtract the area occupied by streets and common areas from the total area and then divide it by the minimum lot size.
1 acre is equal to 43,560 square feet, so 16 acres is equal to 16 * 43,560 = 696,960 square feet.
The streets and common areas will take up 30% of this overall area:
30% of 696,960 = 0.3 * 696,960 = 209,088 square feet.
Now we subtract the area occupied by streets and common areas from the total area to find the area available for the lots:
696,960 - 209,088 = 487,872 square feet.
Since the minimum lot size is 12,000 square feet, we divide the available area by the minimum lot size to find the number of lots:
487,872 / 12,000 = 40.656.
Since we cannot have a fraction of a lot, the developer can have a maximum of 40 lots on this property.
As a result, the 16-acre subdivision may only accommodate a maximum of 40 lots from the developer.
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How to find LATERAL SURFACE AREA and SURFACE AREA of a Triangular and rectangular prism? (Need both) STEP BY STEP. (7th grade)
To find the Lateral Surface Area and Surface Area of a Triangular and Rectangular Prism, follow the below steps:
Lateral Surface Area of a Triangular Prism:
Step 1: Draw a net of the triangular prism
Step 2: Identify the height of the prism, which is perpendicular to the triangular base.
Step 3: Calculate the perimeter of the base by adding all the sides of the triangle.
Step 4: Multiply the perimeter by the height to get the Lateral Surface Area.Lateral Surface Area = Perimeter of the Base × Height Surface Area of a Triangular Prism:
Step 1: Identify the base and height of the triangle.
Step 2: Use the formula to find the area of the triangle: Area of the Triangle = (1/2) × Base × Height.
Step 3: Multiply the result of step 2 by 2 and add it to the Lateral Surface Area.Surface Area = 2(Area of the Triangle) + Lateral Surface Area.
Surface Area of a Rectangular Prism:
Step 1: Identify the length, width, and height of the rectangular prism.
Step 2: Find the areas of each face of the rectangular prism.
Face 1: Length × Width
Face 2: Length × Height
Face 3: Width × Height
Step 3: Add up the area of all faces of the rectangular prism.
Surface Area = 2(LW + LH + WH)
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what is the y-value of this function when x=-6
Answer:
3
Step-by-step explanation:
A point on the graph is at (-6, 3). Hope this helps!
Which statement compares the two numbers correctly? (2 points) 7 x 10 + 3 x 1 + 3 x 0.1 + 8 x 0.01 + 5 x 0.001 ________ 73.293 Group of answer choices 7 x 10 + 3 x 1 + 3 x 0.1 + 8 x 0.01 + 5 x 0.001 < 73.293 7 x 10 + 3 x 1 + 3 x 0.1 + 8 x 0.01 + 5 x 0.001 = 73.293 73.293 > 7 x 10 + 3 x 1 + 3 x 0.1 + 8 x 0.01 + 5 x 0.001 7 x 10 + 3 x 1 + 3 x 0.1 + 8 x 0.01 + 5 x 0.001 > 73.293
Answer:
7 × 10 + 3 × 1 + 3 × 0.1 + 8 × 0.01 + 5 × 0.001 > 73.293
Step-by-step explanation:
Given: Numbers are 7 × 10 + 3 × 1 + 3 × 0.1 + 8 × 0.01 + 5 × 0.001 and 73.293
To compare: the two given numbers
Solution:
7 × 10 + 3 × 1 + 3 × 0.1 + 8 × 0.01 + 5 × 0.001 is equal to [tex]73.385[/tex]
Compare the numbers [tex]73.385[/tex] and 73.293
Digits at the ones pace and tens place in both the numbers are same.
Observe the digit at the tenth place in both the numbers.
Digit at the tenth place in 73.385 is 3
Digit at the tenth place in 73.293 is 2
As [tex]3>2[/tex],
73.385 > 73.293
So,
7 × 10 + 3 × 1 + 3 × 0.1 + 8 × 0.01 + 5 × 0.001 > 73.293
Answer: 7 x 10 + 3 x 1 + 3 x 0.1 + 8 x 0.01 + 5 x 0.001 > 73.293
Step-by-step explanation: ik this bc i have this same quiz so gl on the rest of the questions
Solve for x. Show your work with proper statements and notation.
Answer:
x = 26
Step-by-step explanation:
The sum of the angles around point O = 360°, thus
x + 3x + 256 = 360 , that is
4x + 256 = 360 ( subtract 256 from both sides )
4x = 104 ( divide both sides by 4 )
x = 26
If a vehicle averages 23 mi/h on a 138 mi trip and then returns over the same 138 mi at the rate of 69 mi/h, what is your average speed for the trip? Give reasons for your answer. A vehicle averages 23 mi/h on a 138 mi trip. Write the integral that represents this information. f(x)dx = 0
The correct answer is the average speed for the entire trip is 34.5 miles per hour and The integral that represents this information is as follows: f(x)dx = ∫23 dx + ∫69 dx Where x represents the distance travelled in miles.
To find out the average speed for the entire trip, we will use the formula for average speed which is given as follows: Average speed = Total distance/Total time
Let's calculate the time taken to travel 138 miles at 23 mi/h
Speed = 23 mi/h
Distance = 138 mi
Time taken = Distance/Speed = 138/23 = 6 hours
Now, let's calculate the time taken to return back to the starting point, which is again 138 miles away but this time at 69 mi/h.
Speed = 69 mi/h
Distance = 138 mi
Time taken = Distance/Speed = 138/69 = 2 hours
Now, the total time taken for the entire trip is 6 + 2 = 8 hours.
The total distance travelled for the entire trip is 2 x 138 = 276 miles.
Now we can use the formula for average speed to calculate the average speed of the entire trip.
Average speed = Total distance/Total time = 276/8 = 34.5 miles per hour
Therefore, the average speed for the entire trip is 34.5 miles per hour.
The integral that represents this information is as follows: f(x)dx = ∫23 dx + ∫69 dx Where x represents the distance travelled in miles.
The limits of integration are from 0 to 138 for both integrals, representing the forward and backward journeys.
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How do you determine where to place the decimal point in the product?
Let's look at an example:
2.24 x 21.6
[tex]2.24\\ 21.6\\ ______[/tex]
Do normal multiplication and get
48384 This is not correct, until we put the decimals in. To know how to do this, count the number of decimal spaces from the factors. In 2.24, there are 2, because .24. In 21.6 there are 1 because of .6. This mean three places, so 48384 becomes
48.384
~theLocoCoco
2. The coach of a cricket team buys 3 bats and 6 balls for 3900. Later, she buys another
bat and 3 more balls of the same kind for 1300. Represent this situation algebraically
and geometrically
Step-by-step explanation:
variable x = bats
variable y = balls
3x + 6y = 3900
1x + 3y = 1300
I believe this is what they meant by represent it algebraically, but I'm not sure exactly what your class is learning right now. Geometrically, I do not know what they mean. I hope this helps you in some way
3[tex]\sqrt{x} 9\\[/tex]
Answer: x^4X\sqrt{x}
Step-by-step explanation: x9" was replaced by "x^9".
Rules for simplifing variables which may be raised to a power:
(1) variables with no exponent stay inside the radical
(2) variables raised to power 1 or (-1) stay inside the radical
(3) variables raised to an even exponent: Half the exponent taken out, nothing remains inside the radical. examples:
(3.1) sqrt(x8)=x4
(3.2) sqrt(x-6)=x-3
(4) variables raised to an odd exponent which is >2 or <(-2) , examples:
(4.1) sqrt(x5)=x2•sqrt(x)
(4.2) sqrt(x-7)=x-3•sqrt(x-1)
Applying these rules to our case we find out that
SQRT(x9) = x4 • SQRT(x)
Simplified Root :
x4 • sqrt(x)
Solve for r.
K= 2r-35
Answer:
r = k/2 + 35/2
The ratio of girls to boys in one of Mr. Pryslak's grade 9 Mathematics dasses is 4:3. If there are 9
boys in the class, how many girls are there?
Help me
Answer:
12 girls
Step-by-step explanation:
So the ratio of girls to boys is 4:3 and if there are 9 boys you multiply the number 3 by 3 to get 9 and do the same to the other side to get 12
the scores on a collegiate mathematics readiness assessment are approximately normally distributed with a mean of 680 and a standard deviation of 120. determine the percentage of scores between 690 and 900, to the nearest percent.
43.36% of the scores fall between 690 and 900 on the collegiate mathematics readiness assessment.
To determine the percentage of scores between 690 and 900, we need to calculate the area under the normal distribution curve between these two values.
First, we need to standardize the scores using the formula z = (x - μ) / σ, where x is the score, μ is the mean, and σ is the standard deviation.
For the score 690:
z1 = (690 - 680) / 120 = 0.0833
For the score 900:
z2 = (900 - 680) / 120 = 1.8333
Next, we need to find the area between these two standardized scores. We can use a standard normal distribution table or a statistical calculator to find the corresponding probabilities.
From the standard normal distribution table, we find that the area to the left of z1 is approximately 0.5328 and the area to the left of z2 is approximately 0.9664.
To find the area between z1 and z2, we subtract the smaller area from the larger area:
Area = 0.9664 - 0.5328 = 0.4336
Finally, we convert the area to a percentage by multiplying by 100:
Percentage = 0.4336 * 100 ≈ 43.36%
Therefore, approximately 43% of the scores fall between 690 and 900 on the collegiate mathematics readiness assessment.
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tiana is a member of the school swim team, and she specializes in distance events. today at practice, she plans to swim for 20 minutes at a constant speed of 75 meters per minute. the function d(m) represents the total distance tiana has swum, in meters, during m minutes of practicing. what is the domain of d(m)?
Answer:
domain can be from 0 to 20
Step-by-step explanation:
if she doesn't swim, it will be 0 but she can swim up to 20 minutes which will be our x value and our max domain value
g(x) = -2x -9 what is g(-7)?
Answer:
g(-7) = 5
Step-by-step explanation:
Step 1: Define
g(x) = -2x - 9
g(-7) is x = -7
Step 2: Substitute and Evaluate
g(-7) = -2(-7) - 9
g(-7) = 14 - 9
g(-7) = 5
Answer:
g(-7)=5
Step-by-step explanation:
-2 (-7) - 9 =
14 - 9 =
5
