What is the speed of the bullet?
Answer in units of m/s.

A ball is thrown upwards. Its acceleration is: C. downward during both ascent and descent

In physics vertical launch upwards is the motion described by an object that has been launched vertically upwards in which the height and the effect of the earth's gravitational force on the launched object are taken into account.

In the vertical launch upwards movements, the acceleration due to the gravity is always acting downward, this is because of attraction that the earth exerts on all bodies pulling them toward its center

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We can see that the new velocity of the 2 Kg ball is 6.4 m/s.

Momentum is a measure of an object's motion. It is defined as the product of an object's mass and velocity. In physics, momentum is a vector quantity, meaning it has both magnitude and direction.

The law of conservation of momentum states that in an isolated system, the total momentum of the system remains constant if no external forces are acting upon it.

Given that we know that;

Momentum before collision = Momentum after collision

(4 * 8) + (2 * 0) = (4 * 4.8) + (2 * v)

Let v be the new velocity

32 = 19.2 + 2v

v = 32 - 19.2/2

v = 6.4 m/s

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(a) The time spent by the player in the top of 10 cm of this jump is 0.14 second.

(b) The time spent by the player in the bottom 10 cm of this jump is 0.38 second.

(c) The result shows that the player spends more time during ascent and decent because of greater distance.

The time taken for the player to jump 80 cm and back to ground is calculated as follows;

t = 2 ( √ ( 2h / g ) )

where;

t = 2 ( √ ( 2 x 0.8 / 9.8 ) )

t = 0.4 s

t = 0.8 second

The time spent by the player in 10 cm jump is calculated as follows;

t =  √ ( 2h / g )

t = √ ( 2  x 0.1 / 9.8 )

t = 0.14 s

From 10 cm at the bottom, the player has travelled 70 cm, and the time of motion of this player is calculated as follows;

t = √ ( 2 x 0.7 / 9.8 )

t = 0.38 second

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1. Mass of the person is 91.84 kg

2. The scale reads 917.4 N

3. The scale reads 917.4 N

4. The scale reads 905 N

Since the gravity acceleration (g) is not stated, assume it is 9.8 m/s^2

1. To calculate their mass, the formula m = F/g (where m is mass, F is weight (or force), and g is the acceleration due to gravity) would need to be used with the known weight and acceleration due to gravity (9.8 m/s^2). So, m = 900 N / 9.8 m/s^2 = 91.84 kg.

2. When the elevator accelerates upward at 2.5 m/s^2, the scale reading will increase. This is because the apparent weight of the person will be greater than their actual weight due to the upward acceleration of the elevator. The formula for apparent weight is Fapparent = m * g + ma (where m is mass, g is the acceleration due to gravity, and a is the acceleration of the elevator). So, Fapparent = 91.84 kg * 9.8 m/s^2 + 91.84 kg * 2.5 m/s^2 = 917.42 N.

3. During the steady speed of 4m/s, the scale will still read 917.42 N because the apparent weight does not change with constant velocity.

4. When the elevator decelerates at 1.8 m/s^2, the scale reading will decrease. The apparent weight will be less than the person's actual weight due to the downward acceleration of the elevator. The formula for apparent weight will be the same as in step 2, using the negative value of the deceleration of the elevator. So, Fapparent = 91.84 kg * 9.8 m/s^2 - 91.84 kg * 1.8 m/s^2 = 905.00 N.

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The terminal velocity of the squirrel is approximately 29.5 m/s.

The terminal velocity of an object can be calculated using the equation:

[tex]V_t = \sqrt{(2mg / (C_d \times A \times p))[/tex]

where V_t is the terminal velocity,

m is the mass of the object (550 g = 0.550 kg),

g is the acceleration due to gravity ([tex]9.8 m/s^2[/tex]),

[tex]C_d[/tex] is the drag coefficient for a horizontal skydiver (approximately 0.75),

A is the surface area of the object, and p is the density of air (approximately 1.225 kg/m^3 at sea level).

Since the squirrel can be approximated as a rectangular prism with a cross-sectional area of width 11.1 cm and length 22.2 cm,

We can calculate A as follows:

A = [tex]2 \times (11.1 cm) \times (22.2 cm)[/tex]

= [tex]484 cm^2[/tex]

Converting the surface area to square meters:

A = [tex]484 cm^2 \times (10^-4 m^2/cm^2)[/tex]

= [tex]0.0484 m^2[/tex]

Finally, calculate the terminal velocity:

[tex]V_t = \sqrt((2 \times 0.550 kg \times 9.8 m/s^2) / (0.75 \times 0.0484 m^2 \times 1.225 kg/m^3))[/tex]

= 29.5 m/s

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b) For the car to stay just in contact with loop, normal force from loop on car should be zero.

A force is an influence that can alter an object's motion in physics. A force can cause an object with mass to accelerate and change its velocity (for example, moving from a state of rest). Force can also be conceptualised as a push or a pull.

A force is a vector quantity since it has both magnitude and direction. It is calculated using newtons as the SI unit of measure (N). F stands for force (formerly P).

The net force acting on an object is equal to the rate at which its momentum changes over time, according to Newton's second law in its original form.

Balancing the forces on the car, centrifugal force = weight + normal force,

mv2/R = mg + 0

v2 = Rg

KE = 1/2*mv2 = 1/2*mRg

PE at the point = mg*(2R)

So, total energy = 1/2*mRg + mg*(2R) = 5/2*mgR

But total energy = mgH where H is inital height of fall.

Thus, mgH = 5/2*mgR

Thus, H = 5/2*R = 5/2*15 = 37.5 m

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This is 20 plus 6.5 squared, which equals.Nearly nine 478 is what this equates to.This system therefore has a 9.47 mechanical advantage.

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According to our knowledge, the distance that an object has gone or covered after five seconds is that distance.

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Intuition involves relying on assumptions and beliefs about the world, whereas empirical observation involves making direct observations of the world.

Intuition refers to the process of using past experiences, beliefs, and assumptions to make quick, unconscious judgments or decisions about the world.

It is often associated with feelings or gut reactions and can be influenced by factors such as emotions, biases, and prior knowledge.

Empirical observation, on the other hand, refers to the process of gathering information about the world through direct sensory experience, such as seeing, hearing, touching, and measuring.

Empirical observations are the foundation of scientific inquiry as they provide the raw data that can be used to test and refine hypotheses and theories.

Unlike intuition, empirical observations are objective and uninfluenced by personal biases or assumptions.

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The final speed of the Cheetah is 66.6607 miles per hour.

Acceleration is rate of change of velocity with time. Due to having both direction and magnitude, it is a vector quantity. Si unit of acceleration is meter/second² (m/s²).

If a body changes its velocity or direction of velocity, the physical quantity "acceleration" comes into play.

Initial speed of the Cheetah is = 20.0 m/s

Final speed of the Cheetah is = 29.8 m/s

Now 1 meter per second = 2.237 miles per hour

Hence, Final speed of the Cheetah is = 29.8 × 2.237 miles per hour

= 66.6607  miles per hour.

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The kinetic energy of an object increases as the mass and speed increases. Here, the truck weighs twice that of car and has a twice speed then it has a kinetic energy 8 times greater than the car.

Kinetic energy is form of energy generated by virtue of the motion of the object. It is related to the mass and velocity of the object by the expression below:

Ke = 1/2 mv²

Let the mass and velocity of the car be m and v. Then its kinetic energy is 1/2 mv²

The mass and velocity of the truck are being 2m and 2v.

Then, kinetic energy of the truck = 1/2 2m (2v)²

Ke = 1/2 8 m v²

Therefore, the  truck has 8 times the kinetic energy of the car. Hence, option  d is correct.

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Your question is incomplete. But your complete question probably was:

A truck weighs twice as much as a car, and is moving at twice the speed of the car. Which statement is true about the truck's kinetic energy compared to that of the car?

a. All that can be said is that the truck has more kinetic energy.

b. The truck has twice the kinetic energy of the car.

c. The truck has 4 times the kinetic energy of the car.

d. The truck has 8 times the kinetic energy of the car.

Metamorphism occurs when rocks experience conditions significantly different from those under which they were formed.

Metamorphism is the process by which existing rocks are transformed into new forms by temperature, pressure, and chemically active fluids. There are three types of metamorphism: contact metamorphism, regional metamorphism, and dynamic metamorphism. Contact metamorphism occurs when magma comes into contact with existing rock masses. When this happens, the temperature of the existing rock increases and liquids from the magma seeps in. The word metamorphosis is of Greek origin and means "change of shape". Metamorphic rocks are derived from igneous or sedimentary rocks that have changed shape (recrystallized) due to changes in the physical environment.

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The wheel's moment of inertia is a sizable 3.0-kg disk with a radius of 0.60 m and a mass of 0.54 kg/m².

In physics, a body's inertial moment is a numerical representation of its resistance to having overall speed of its movement about an axis changed by that of the deployment of a torque. The axis could be local or exterior, fixed or not.

All materials share the attribute of force of inertia, which keeps them in their states—whether they are at rest and in motion an outside force is applied to cause them to change. Except when someone changes their state, bodies do not exhibit this force.

Moment of inertia,

solid disc of mass = M

radius = R

I = 1/2 MR²

= 1/2 * 3 * 0.60²

= 0.54 kg.m²

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The direction of the force on a charge due to an electric field depends on the sign of the charge and the direction of the electric field. The direction of the electric field is determined by the direction of the gradient of the electric potential.

In general, the direction of the electric field can be found using Coulomb's law, which states that the force between two point charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. The direction of the force is given by the direction of the vector connecting the two charges.

Given the information provided in the prompt, it is not possible to determine the direction of the force on each charge without additional information. Please provide more details.

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Before the ball hits the ground, it is 2.8 seconds in the air. The result is obtained by using the equations in uniformly accelerated straight motion.

The equations apply in uniformly accelerated straight motion in vertical dimension are

v₁ = v₀ + gt

v₁² = v₀² + 2gh

h = v₀t + ½ gt²

Where

A student standing on the ground throws a ball straight up with

Find the time it takes for the ball to reach the ground!

We use g = 9.8 m/s². See the illustration picture in the attachment!

The ball will go upward and stop at a certain height with v₁ = 0. The time needed is

v₁ = v₀ - gt₁

0 = 13.0 - 9.8t

13.0 = 9.8t

t₁ = 13.0/9.8

t₁ = 1.3 s

The height above the hand when the ball stops is

v₁² = v₀² - 2gh₂

0 = 13.0² - 2(9.8)h₂

13.0² = 2(9.8)h₂

169 = 19.6h₂

h₂ = 8,62 m

The ball stops at a height of

h₃ = h₁ + h₂

h₃ = 2.50 + 8.62

h₃ = 11.12 m

The ball goes downward and reach the ground. Initial velocity in this condition is v₁ = 0. The time needed is

h₃ = v₁t + ½ gt₂²

11.12 = 0 + ½ (9.8)t₂²

11.12 = 4.9t²

t₂² = 2.27

t₂ ≈ 1.5 s

The time that the ball in the air is

t = t₁ + t₂

t = 1.3 + 1.5

t = 2.8 s

Hence, the ball is in the air for 2.8 seconds.

Your question is incomplete, but most probably your full question was

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the hand is 2.50 m above the ground. How long is the ball in the air before it hits the ground? (The student moves her hand out of the way).

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You should discover that, regardless of their exact mass or diameter, a solid object will always roll down the ramp quicker than a hollow object of the same shape (sphere or cylinder).

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Answer:

They can go through humans damaging their tissue.

Explanation:

Gamma rays are very dangerous in comparison to other rays such as radio waves as gamma rays have a higher frequency. This higher frequency gives them an immense about of energy in comparison to other waves. They have more penetrating power and are able to damage human tissue... which is dangerous.

Answer:

Explanation:

The magnitude of the force that the space ship exerts on the astronaut is 1300 N.

This can be calculated by using the formula: force = mass x acceleration.

The astronaut's mass is 700 N / 10 m/s² = 70 kg

The acceleration of the ship is 5 m/s².

So the force on the astronaut is 70 kg x 5 m/s² = 350 N.

Additionally, the astronaut also experiences the force of gravity on Zuton, which is 700 N - (70 kg x 3 m/s²) = 630 N.

So the total force on the astronaut is 630 N + 350 N = 980 N.

Answer:

Explanation:

1meter equals 100cm mt and cm are measure the distance.

1second, 60seconds equals 1minute second minute and hour meansures time.

1kg is equals 1000g and measures weight.  

Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to 0.50 to be able to spray her friend.

The fraction f of the cross-sectional area of the hose hole that Isabella needs to cover depends on the desired range of the water. The range is determined by the speed of the water, which is related to the pressure of the water. Pressure is determined by the amount of water flowing through the hose, which is determined by the size of the hose opening.

To increase the range of the water, Isabella needs to decrease the size of the hose opening. This can be done by partially covering the hose hole with her thumb. The fraction f of the cross-sectional area of the hose hole that she needs to cover can be calculated using the following equation:
f = 1 - (A/A₀)
where A is the area of the partially covered hose hole and A₀ is the area of the fully opened hose hole.
For a circular hose hole with a radius of 1.5 centimeters (A₀ = 7.07 cm²), the area of the partially covered hose hole (A) can be calculated using the following equation:
A = πr²(1 - f)
where r is the radius of the hose hole (1.5 cm) and f is the fraction of the cross-sectional area of the hose hole that Isabella needs to cover.
Substituting the equation for A into the equation for f, we get:
f = 1 - (πr²(1 - f))/A₀
Solving for f, we get:
f = 1 - (πr²/A₀)
Therefore, for a circular hose hole with a radius of 1.5 centimeters, Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to:
f = 1 - (π × (1.5 cm)²)/(7.07 cm²)
f = 0.50
Isabella needs to cover a fraction f of the cross-sectional area of the hose hole equal to 0.50 to be able to spray her friend.

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The normal derivative of the electric field is given by [tex]\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )[/tex].

The Gauss law is really applied in integral form, E da = 0.

then there is no contained charge. prior to thinking about the three-dimensional issue. Think about the similar circumstance in two dimensions.

Gauss laws therefore state that if you place a curve Gaussian box adjacent to the charged conductor's surface at a position where the radius of curvature is R.

[tex]0=\int {E.x} \, da=E_{top}\triangle a_{top} -E_{bottom}\triangle a_{bottom}[/tex]

[tex]\triangle a_{top}[/tex] and [tex]\triangle a_{bottom}[/tex] are the top and bottom portions of the box, respectively.

using [tex]\triangle a_{top}[/tex] =(R+E)d∅× dz and,

[tex]\triangle a_{bottom}[/tex]=Rd∅× dz gives

[tex]E_{bottom}=E_{top}(1+\frac{E}{R})[/tex]

This enables us to compute.

[tex]\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(\frac{-E_{top}}{R})= \frac{-E_{top}}{R}[/tex]

Taking into consideration that Flop is the same as E ,this may be written as

[tex]\frac{1}{E}\times\frac{dE}{dn}=-\frac{1}{R}[/tex]

This is a two-dimensional expression analogue.

Returning to the 3D issue, we will use the aforementioned methods. However, this time around, the top and bottom

[tex]\triangle a_{top}[/tex]=[tex](R_{1}+E)\times(R_{2}+E)\times[/tex]dФ

[tex]\triangle a_{bottom}[/tex]=[tex]R_{1}R_{2}[/tex]dФ

Now putting these in equation

[tex]E_{bottom}=E_{top}(1+\frac{E}{R_{1} })(1+\frac{E}{R_{2} })[/tex]

which gives,

[tex]\frac{dE}{dn}= \lim_{E \to 0} \frac{E_{top}-E_{bottom}}{E} =\lim_{E \to 0}(-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} }+\frac{E}{R_{1} R_{2} })=-E_{top}(\frac{1}{R_{1} }+\frac{1}{R_{2} })[/tex]

Rearranging the equation gives,

[tex]\frac{1}{E}\times\frac{dE}{dn}=-(\frac{1}{R_{1}}+\frac{1}{R_{2}} )[/tex]

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The magnitude and direction of a fourth force on the engine that will make the vector sum of the forces equal zero is 193.1 N with direction is 57.7° counter-clockwise from the positive x axis.

The magnitude or size of a mathematical object is a property which determines whether the object is larger or smaller than other objects of the same kind.

We find the x and y components of each force:

A = 100 N, θ = 53.0° => Ax = 100 N * cos (53.0°) = 70.7 N; Ay = 100 N * sin (53.0°) = 50.0 N

B = 40.0 N, θ = 30.0° => Bx = 40.0 N * cos (30.0°) = 34.0 N; By = 40.0 N * sin (30.0°) = 20.0 N

C = 80.0 N, θ = 30.0° => Cx = 80.0 N * cos (30.0°) = 68.0 N; Cy = 80.0 N * sin (30.0°) = 40.0 N

We will find the total x and y components:

Net x = Ax + Bx + Cx = 70.7 N + 34.0 N + 68.0 N = 172.7 N

Net y = Ay + By + Cy = 50.0 N + 20.0 N + 40.0 N = 110.0 N

Finally, let's find the magnitude and direction of the fourth force, P:

P = sqrt (Net x^2 + Net y^2) = sqrt (172.7 N^2 + 110.0 N^2) = 193.1 N

θ = tan^-1 (Net y / Net x) = tan^-1 (110.0 N / 172.7 N) = 57.7°

In conclusion,  if the angle is negative, the direction is clockwise from the negative x axis. In this example, the angle is positive, so the direction is 57.7° counter-clockwise from the positive x axis.

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Of the choices shown, sound wave is classified as a longitudinal wave (A)

A longitudinal wave is a type of wave that travels in a direction that is perpendicular to the motion of the particles that make up the medium in which the wave is traveling. Similar to light waves, sound waves oscillate in a direction parallel to the direction in which they propagate, producing compressions and rarefactions. Because of this, we refer to sound waves as longitudinal waves.

The particles that make up the wave do not move in the same direction as the wave; rather, they merely move back and forth in relation to their own equilibrium. Additional examples of longitudinal waves are the sound wave, the principal waves that are produced by an earthquake, ultrasound, the vibration of a spring, the fluctuation in gas, and the waves that are produced by a tsunami.

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The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

the formula to determine the magnitude of a vector (in two dimensional space) v = (x, y) is: |v| =√(x2 + y2). This formula is derived from the Pythagorean theorem. the formula to determine the magnitude of a vector (in three dimensional space) V = (x, y, z) is: |V| = √(x2 + y2 + z2)

The magnitude of a vector formula is used to calculate the length for a given vector (say v) and is denoted as |v|. So basically, this quantity is the length between the initial point and endpoint of the vector.

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The magnitude of the force on the booster unit can be calculated using the principle of conservation of momentum. According to this principle, the momentum of a system is conserved before and after an interaction, as long as no external forces act on the system.

Before the separation, the total momentum of the system is:

m_total * v_initial = (7.18 x 10^3 kg) * (369.66 m/s)

After the separation, the momentum of the space vehicle is:

m_vehicle * v_final = (7.18 x 10^3 kg) * (444.57 m/s)

And the momentum of the booster unit is:

m_booster * v_final = (6.32 x 10^2 kg) * v_final

Since the total momentum is conserved, the initial momentum must equal the final momentum:

m_total * v_initial = m_vehicle * v_final + m_booster * v_final

Solving for v_final, we find:

v_final = (m_total * v_initial - m_vehicle * v_final) / m_booster

Now we can find the magnitude of the force on the booster unit using Newton's Second Law, which states that the force acting on an object is equal to its mass times its acceleration:

F = m_booster * a = m_booster * (dv/dt)

where dv/dt is the change in velocity over time, which can be approximated as (v_final - v_initial) / time.

Substituting the values we have found into this equation, we find:

F = (6.32 x 10^2 kg) * ((v_final - v_initial) / (2.81 s))

This equation can be evaluated to find the magnitude of the force on the booster unit.

Answer:

a. Not have to back out

When you perpendicular-park, if possible, you should select a space that lets you drive into the facing space so that when you leave, you will not have to back out. This will make it easier and safer for you to exit the parking spot and get back on the road.

1 (a) The vertical height upto which the ball reaches will be 4.608 meters

a) We may use the theory of conservation of energy to compute the vertical height reached by the ball.

The ball's original total mechanical energy equals its ultimate potential energy.

The potential energy formula is mgh,

where m is the ball's mass,

g is the acceleration due to gravity (9.8 m/s2), and

h is the height.

The initial total mechanical energy equals the initial kinetic energy, which may be computed using the formula 1/2 * m * v2,

where v represents the beginning velocity.

By equating the two, we get:

1/2 * m * v^2 = mgh

Rearranging and solving for h:

h = v^2 / (2g)

= (9.6 m/s)^2 / (2 * 9.8 m/s^2)

= 4.608 m

b) If the ball glides up the hill without rolling, its final height will be lower than if it rolls.

As the ball slows down, part of its original kinetic energy is converted into frictional warmth, sound, and other types of internal energy.

To calculate the moment of inertia, we must first know the skater's mass distribution and the axis along which the moment of inertia is being computed.

Assuming the skater's arms are dragged inward and may be considered as cylinders with radius 0.125 m and mass m_a, the moment of inertia can be calculated as follows:

I = I_cm + m_a * r^2

where I_cm is the moment of inertia of the skater's body (assuming it can be treated as a point mass),

r is the distance from the axis of rotation to the center of mass of the cylinder (0.125 m), and

m_a is the mass of the cylinder (unknown).

To calculate I_cm, we need to know the skater's body's mass and shape. Without more information, we cannot calculate the moment of inertia.

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Initially the sound waves are in phase and they overlap to form the constructive interference pattern. The length  that we have to raise the top part will be equal to the wavelength of the waves in meter.

A wave of greater, lower, or the same amplitude is created when two waves merge through interference by combining their displacements at all points in space and time.

The interaction of waves that are coherent or correlated with one another, either because they originate from the same source or because their frequencies are similar or almost identical, leads to both constructive and destructive interference.

All sorts of waves, including light, radio, acoustic, surface water waves, gravity waves, and matter waves, can exhibit interference effects. In constructive interference, the waves are in single phase forms a resultant wave with higher amplitude.

When waves from in phase phase meets, the resultant wave will have an amplitude less than the individual amplitudes. Here

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The impulse on the mass is equal to the area under the force -time graph. The area under the plot in the graph is 6 N.s thus the impulse is 6 Ns.

Impulse of a moving object is its change in momentum. It is equal to the product of force and time. The force- time plot of a moving object can be used to determine the impulse.

From the given force- time graph, the area  under the curve is :

area = area of the two triangles + area of the rectangle.

area of the triangle  = 1/2 (2 N × 2s )= 2N s

area of the rectangle = 2 N × 1s = 2N s.

The second triangle have the area equal to the first one that is 2 N s.

then the total area of the curve = 2 Ns × 3 = 6 Ns.

Therefore, the impulse on the mass is 6 Ns.

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