what is the standard deduction for 2016 for over 65

Correct Option is. False

When two random variables, X and Y, are independent, the variance of their sum, X+Y, is equal to the sum of their individual variances. In this case, both X and Y have a variance of 20. Therefore, the variance of X+Y would be the sum of 20 and 20, which is 40, not 20.

To understand why this is the case, we can consider the definition of variance. Variance measures how spread out the values of a random variable are from its mean. When two variables are independent, their joint distribution is simply the product of their individual distributions. The variance of the sum of two independent variables is obtained by summing their variances.

In this scenario, each variable has a variance of 20. However, when we add them together, the variances do not add up. Instead, the variance of the sum is the sum of the individual variances, resulting in a variance of 40 for X+Y.

Therefore, the statement "var(X+Y)=20" is false. The correct answer is that the variance of X+Y is 40.

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The expression 2√34 is closest to option C. 242√. So, the correct answer is C. 242√.

To simplify the expression 68√⋅2√, we can combine the square roots using the product rule of square roots, which states that √(a) * √(b) = √(a * b).

So, applying the product rule, we have:

68√⋅2√ = √(68 * 2) = √(136).

Now, let's simplify the square root of 136. We can find the largest perfect square that divides 136, which is 4, and rewrite 136 as 4 * 34.

√(136) = √(4 * 34) = √4 * √34 = 2√34.

Therefore, the expression 68√⋅2√ is equivalent to 2√34.

Among the given options, the expression 2√34 is closest to option C. 242√.

So, the correct answer is C. 242√.

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Opposite angles of ABCD are congruent if and only if ABCD is a parallelogram. The diagonals of ABCD bisect each other if and only if ABCD is a parallelogram.

(a) Given ABCD is a quadrilateral. If ABCD is a parallelogram, then AB || CD and BC || AD. Also, opposite angles are congruent and it can be proven using proposition 29 of Euclid's first 29 propositions. Using the converse of the above, If opposite angles of ABCD are congruent, then AB || CD and BC || AD. So ABCD is a parallelogram, which is proved using proposition 28 of Euclid's first 29 propositions. Hence it is proved that opposite angles of ABCD are congruent if and only if ABCD is a parallelogram.

(d) Given ABCD is a quadrilateral. The diagonals AC and BD of a quadrilateral ABCD bisect each other if and only if ABDE is a parallelogram. So, it is proved using proposition 29 of Euclid's first 29 propositions that diagonals of ABCD bisect each other if and only if ABCD is a parallelogram. Hence it is proved that the diagonals of ABCD bisect each other if and only if ABCD is a parallelogram.

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The equation of the line in slope-intercept form which passes through the point (-1,-2), and is perpendicular to the line with the equation y = -(3)/(4)x + (9)/(4) is y = (4)/(3)x - (2)/(3).

Given that, the point on the line is (-1,-2) and the line is perpendicular to y = -(3)/(4)x + (9)/(4). Now we will convert the given equation into slope-intercept form y = mx + c, where m is the slope and c is the y-intercept, to identify the slope of the line: y = -(3)/(4)x+(9)/(4) ⇒ y = mx + c, where m = -(3)/(4)

So the slope of the line perpendicular to the above line is given by:

Slope of the perpendicular line = negative reciprocal of the slope of the above line

Therefore, the slope of the perpendicular line is (4)/(3)

We use the point-slope form of a line y - y1 = m(x - x1), where m = slope and (x1, y1) = point on the line. Substituting the values, we get the equation of the line which passes through the point (-1,-2) and is perpendicular to the line with the equation y = -(3)/(4)x + (9)/(4) as:

y - (-2) = (4)/(3)(x - (-1))

y + 2 = (4)/(3)x + (4)/(3)

y = (4)/(3)x - 2(2)/(3)

y = (4)/(3)x - (2)/(3)

Thus, the required equation of the line is y = (4)/(3)x - (2)/(3) in the slope-intercept form.

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Answer:

it's r =0.08 hope it's helpful

The composition (f∘g)(x) is equal to 8x^2 + 7.

The composition (f∘g)(x) represents the function obtained by applying the function f to the function g. In this case, we have f(x) = 2x + 5 and g(x) = 4x^2 + 1. To find (f∘g)(x), we substitute g(x) into f(x).

Substituting g(x) into f(x), we have:

(f∘g)(x) = f(g(x)) = 2(g(x)) + 5

Now, we substitute g(x) = 4x^2 + 1 into the expression for f(g(x)):

(f∘g)(x) = 2(4x^2 + 1) + 5

Simplifying further:

(f∘g)(x) = 8x^2 + 2 + 5

(f∘g)(x) = 8x^2 + 7

Therefore, the composition (f∘g)(x) is given by 8x^2 + 7.

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If he rolls higher than 10 , you pay him $11., the expected value of the bet to you is -$0.5.

The formula for the expected value is:

Expected value = (Probability of a winning outcome x Value of winning outcome) - (Probability of a losing outcome x Value of losing outcome)

From the given information, if your friend rolls a number between 1 and 10 (inclusive), he will pay you $11. The probability of rolling a number between 1 and 10 is 10/20 or 0.5.

The value of this winning outcome is $11.On the other hand, if he rolls a number between 11 and 20 (inclusive), you have to pay him $11.

The probability of rolling a number between 11 and 20 is also 0.5. The value of this losing outcome is -$11.

Therefore, using the formula for the expected value, we have:

Expected value = (0.5 x $11) - (0.5 x $11)

Expected value = $5.5 - $5.5

Expected value = -$0.5

So the expected value of the bet to you is -$0.5.

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The nominal annual rate of discount convertible quarterly that is equivalent to a nominal annual rate of interest of 14% convertible monthly is approximately 2.5928%.

To calculate the nominal annual rate of discount convertible quarterly, we can use the relationship between the nominal annual rate of interest and the nominal annual rate of discount.

The formula for converting between nominal annual rates of interest (i) and discount (d) is:

(1 + i) = (1 - d)^n

Where:

i = Nominal annual rate of interest

d = Nominal annual rate of discount

n = Number of compounding periods in a year

In this case, we are given a nominal annual rate of interest of 14% convertible monthly. So, we can convert this rate to a nominal annual rate of discount convertible quarterly.

Given:

Nominal annual rate of interest (i) = 14%

Number of compounding periods in a year (n) = 12 (monthly compounding)

Let's solve for the nominal annual rate of discount (d):

(1 + 0.14) = (1 - d)^12

Simplifying the equation:

1.14 = (1 - d)^12

Taking the twelfth root of both sides:

(1 - d) ≈ 0.993518

Now, solving for d:

d ≈ 1 - 0.993518

d ≈ 0.006482

Converting this rate to a nominal annual rate of discount:

Nominal annual rate of discount ≈ 0.006482 * 4

Nominal annual rate of discount ≈ 0.025928

Converting this rate to a percentage:

Nominal annual rate of discount ≈ 2.5928%

Therefore, the nominal annual rate of discount convertible quarterly that is equivalent to a nominal annual rate of interest of 14% convertible monthly is approximately 2.5928%.

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The exact value of `cos(θ)` is `cos(θ) = sqrt(63)/8`.

Given that `sin(θ) = 1/8`, we can use the Pythagorean identity: `sin^2(θ) + cos^2(θ) = 1`.

Squaring both sides of `sin(θ) = 1/8`, we have `sin^2(θ) = (1/8)^2 = 1/64`.

Substituting `sin^2(θ)` in the Pythagorean identity, we get `cos^2(θ) = 1 - sin^2(θ)`.

Plugging in the values, we have `cos^2(θ) = 1 - 1/64`.

Simplifying further, `cos^2(θ) = 63/64`.

To find the value of `cos(θ)`, we take the square root of both sides.

Since θ is in Quadrant I, where `cos(θ)` is positive, we take the positive square root.

Therefore, the exact value of `cos(θ)` is `cos(θ) = sqrt(63)/8`.

This represents the positive value of `cos(θ)` when `sin(θ) = 1/8` and θ is in Quadrant I.

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However, I can provide you with general guidance on how to analyze transactions and their corresponding debit and credit entries in T-accounts.

To analyze each transaction and determine the debit and credit entries, follow these steps: Identify the accounts involved: Determine which accounts are affected by the transaction.

Determine the account type: Classify each account as an asset, liability, equity, revenue, or expense account. Apply the rules of debit and credit: Based on the account types, apply the rules of debiting and crediting. For example:

Increase in assets: Debit

Decrease in assets: Credit

Increase in liabilities: Credit

Decrease in liabilities: Debit

Increase in equity: Credit

Decrease in equity: Debit

Revenue: Credit

Expense: Debit

Record the transactions: Enter the appropriate debit and credit amounts in the respective T-accounts, ensuring that the accounting equation (Assets = Liabilities + Equity) remains balanced.

Remember to consider the specific accounts and their balances, and to record the transactions in chronological order.

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We have successfully transformed the left side (cot α sin α) into the right side (cos α) using trigonometric identities.

Given the equation, cot α sin α = cos α, we are supposed to use trigonometric identities to transform the left side of the

equation into the right side. We will be using the identity, cot α = cos α / sin α.

To transform the left side of the equation, cot α sin α, into the right side, cos α, we can use the trigonometric identity:

cot α = 1/tan α

Using this identity, we can rewrite cot α sin α as:

cot α sin α = (1/tan α) sin α

Now, let's use another trigonometric identity:

tan α = sin α / cos α

Substituting this in, we get:

cot α sin α = (1/(sin α / cos α)) sin α

Next, simplify the expression by multiplying the numerator and denominator of the fraction by cos α:

cot α sin α = (1 * cos α / (sin α / cos α)) * sin α

Simplifying further, we get:

cot α sin α = (cos α * sin α) / sin α

Canceling out sin α in the numerator and denominator, we have:

cot α sin α = cos α

Therefore, we have successfully transformed the left side (cot α sin α) into the right side (cos α) using trigonometric identities.

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B. The given k is a zero of the polynomial function.

To determine whether -5 is a zero of the polynomial function f(x)=x³+7x²+2x-40, we can use synthetic division. By dividing the polynomial by (x+5), we perform the following steps:

1. Write down the coefficients of the polynomial: 1, 7, 2, -40.
2. Bring down the first coefficient, 1, and multiply it by -5 to get -5.
3. Add -5 to the second coefficient, 7, to get 2. Multiply 2 by -5 to get -10, and add it to the third coefficient, 2, to get -8.
4. Multiply -8 by -5 to get 40, and add it to the fourth coefficient, -40, to get 0.
5. The last number in the synthetic division is 0, indicating that -5 is a zero of the function.
Therefore, the main answer is B. The given k is a zero of the polynomial function.

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The exact value of sin(θ) when tan(θ) = 12/5 in Quadrant III is -12/13.

To find the exact value of sin(θ) when tan(θ) = 12/5 in Quadrant III, we can use the trigonometric identity relating sine and tangent:

tan(θ) = sin(θ) / cos(θ)

Given tan(θ) = 12/5, we can substitute this value into the equation:

12/5 = sin(θ) / cos(θ)

To find the actual value of sin(θ), we need to determine the value of cos(θ) in Quadrant III. Since cos(θ) is negative in Quadrant III, we have:

cos(θ) = -sqrt(1 - sin^2(θ))

Now, we can solve the equation for sin(θ) by substituting the expression for cos(θ):

12/5 = sin(θ) / (-sqrt(1 - sin^2(θ)))

To simplify the equation, let's square both sides:

(12/5)^2 = (sin(θ) / (-sqrt(1 - sin^2(θ))))^2

144/25 = sin^2(θ) / (1 - sin^2(θ))

Multiplying both sides by (1 - sin^2(θ)), we get:

144/25 - 144/25 * sin^2(θ) = sin^2(θ)

Now, we can solve this quadratic equation for sin(θ):

144/25 - 144/25 * sin^2(θ) = sin^2(θ)

Multiplying through by 25 to clear the denominators:

144 - 144 * sin^2(θ) = 25 * sin^2(θ)

Rearranging the terms:

25 * sin^2(θ) + 144 * sin^2(θ) = 144

169 * sin^2(θ) = 144

sin^2(θ) = 144 / 169

Taking the square root of both sides:

sin(θ) = sqrt(144 / 169)

sin(θ) = -12 / 13

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The given polynomial 4m^3 - 12m^2 - 160m can be factored as follows:

Step 1: Find the greatest common factor (GCF) of the coefficients. In this case, the GCF is 4.

Step 2: Factor out the GCF from each term:
4m^3 - 12m^2 - 160m = 4(m^3 - 3m^2 - 40m)

Step 3: Now, let's look at the expression inside the parentheses: m^3 - 3m^2 - 40m. This expression can be further factored by grouping.

Step 4: Group the first two terms and the last two terms separately:
(m^3 - 3m^2) - 40m

Step 5: Factor out the greatest common factor from each group:
m^2(m - 3) - 40m

Step 6: Now, we can factor out an 'm' from each group:
m(m^2 - 3m) - 40m

Step 7: Finally, factor out the common factor 'm':
m(m^2 - 3m - 40)

Therefore, the factored form of the given polynomial 4m^3 - 12m^2 - 160m is 4(m)(m^2 - 3m - 40).

Note: The polynomial is not prime as it can be factored.

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a. The monthly payment for this vehicle using the formula is $576.63

b. The 1st payment goes toward interest is $466.98

c. The 48th payment goes toward interest is $12,011.84

d. The remaining balance on the loan at the end of the 3rd year is $12,011.84

e. Principal repayment in the fourth year is $6,719.16

a) We can use the loan formula for finding the monthly payment. i= 5% / 12 = 0.0041666666666667n = 4 × 12 = 48PV = 29815 - 3500 = 26315 PMT = PV × i / (1 - (1 + i)-n)= $576.63 per month

b) For the first payment, the interest is calculated on the outstanding principal balance (OPB). Principal part of first payment = PMT - Interest part

Interest part for the first payment = OPB × i= 26315 × 0.0041666666666667= $109.65Principal part for the first payment = PMT - Interest part= $576.63 - $109.65= $466.98

c) As it is a reducing balance loan, the outstanding principal balance (OPB) at the end of 47 months = OPB at the end of 48th month

d) Outstanding principal balance (OPB) at the end of the 3rd year = PV × (1 + i)^(n÷12) - [PMT × ((1 + i)^(n÷12) - 1) ÷ i]OPB at the end of 3 years = 26315 × (1 + 0.0041666666666667)^(36) - [576.63 × ((1 + 0.0041666666666667)^(36) - 1) ÷ 0.0041666666666667]= $12,011.84

e) In the first year, only 12 payments are made. Let us calculate the interest and principal part of these payments separately and add them up to find the totals. Principal repayment in the first year = 12 × principal part of monthly payment= 12 × (PMT - Interest) = 12 × (576.63 - 109.65)= $5,355.60

The balance outstanding at the end of the first year = PV × (1 + i)^(n÷12) - [PMT × ((1 + i)^(n÷12) - 1) ÷ i]

= 26315 × (1 + 0.0041666666666667)^(12) - [576.63 × ((1 + 0.0041666666666667)^(12) - 1) ÷ 0.0041666666666667]

= $20,509.15

For the fourth year, last 12 payments are made. In the fourth year, the loan balance outstanding is equal to the balance at the end of year 3.

Principal repayment in the fourth year = 12 × principal part of monthly payment= 12 × (PMT - Interest) = 12 × (576.63 - 47.10)= $6,719.16

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Answer:

Surface Area = 2 * (length * width + length * height + width * height)

Step-by-step explanation:

To find the surface area of a rectangular solid (also known as a rectangular prism), you need to calculate the areas of its six faces and then add them together. The formula for the surface area of a rectangular solid is:

Surface Area = 2 * (length * width + length * height + width * height)

Here are the steps to find the surface area:

Identify the length, width, and height of the rectangular solid.

Multiply the length by the width to find the area of the top and bottom faces.

Multiply the length by the height to find the area of the front and back faces.

Multiply the width by the height to find the area of the left and right faces.

Add up all the areas calculated in steps 2, 3, and 4.

Multiply the sum by 2 to account for the two identical sets of faces.

The result will be the surface area of the rectangular solid.

It's important to note that all measurements should be in the same unit (e.g., centimeters, inches) for accurate results.

Answer:

Step-by-step explanation:

The area of ​​the rectangular solid (parallelepiped) is calculated by adding the lateral area and twice the base area: Stot=Slat+2Sb; the area of ​​the rectangular parallelepiped is given by the sum of the areas of the six rectangles that make up its surface, ie Stot=2(ab+ah+bh).

Let n be a positive integer not divisible by 3. Prove that n² − 1 is always divisible by 3.We have to use proof by contradiction to prove this statement. Proof by contradiction is a type of proof in which we first assume the opposite of the statement we want to prove and then show that it leads to a contradiction or absurdity. This will show that our original assumption must have been correct.

Let us assume that n² − 1 is not divisible by 3. Then, we have two possibilities:It is possible that n is itself divisible by 3, which we know is not true because we have assumed that n is not divisible by 3.

It is also possible that n is not divisible by 3 but (n² - 1) leaves a remainder of 1 when divided by 3, which is also not possible since (n² - 1) must be divisible by 3.

However, neither of these possibilities can be true since we have already assumed that n² − 1 is not divisible by 3. Therefore, our assumption must be incorrect and n² − 1 is always divisible by 3 when n is a positive integer not divisible by 3.

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The graph of y = (1/2)tan(3x) has consecutive vertical asymptotes at x = π/6 and x = π/6 + (π/n) for n ∈ Z. Between these asymptotes, the graph intersects the x-axis at (0, 0), and it passes through the points (π/12, 1/2) and (π/4, -1/2).

The given function is y = (1/2)tan(3x). Let's start by identifying the asymptotes.

The tangent function has vertical asymptotes whenever the angle inside the tangent function is a multiple of π/2. In this case, the angle is 3x, so the vertical asymptotes occur when 3x is equal to π/2 or its multiples.

To find the first pair of consecutive asymptotes, we solve the equation 3x = π/2:

x = π/6

The next pair of consecutive asymptotes occurs when 3x is equal to π/2 plus any multiple of π:

x = (π/6) + (π/n), where n is an integer greater than 0.

Now, let's plot three points between the asymptotes to sketch the graph:

At x = 0:

y = (1/2)tan(3(0)) = 0

So, the point (0, 0) lies on the graph.

To the left of x = π/6, let's take x = π/12:

y = (1/2)tan(3(π/12)) = (1/2)tan(π/4) = 1/2

So, the point (π/12, 1/2) lies on the graph.

To the right of x = π/6, let's take x = π/4:

y = (1/2)tan(3(π/4)) = (1/2)tan(3π/4) = -1/2

So, the point (π/4, -1/2) lies on the graph.

By connecting these points and drawing the asymptotes, we can sketch the graph of y = (1/2)tan(3x) between the consecutive asymptotes.

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Answer:

100

Step-by-step explanation:

2x2=4 4 squared is 16

16+3=21

in the brackets is 2+2 which is 4

21x4=84

4x4=16

84+16=100

im so sorry if i get this wrong

According to the NIOSH 1501 method, which provides guidelines for determining breakthrough during air sampling, Sample #1 and Sample #2 have not broken through. In the Calculation section of the method document, it is stated that if the concentration of a hazardous substance in the back segment is less than or equal to 5% of the concentration in the front segment, the sample is considered not to have broken through.

The NIOSH 1501 method provides guidelines for determining whether a sample has broken through during air sampling for hazardous substances. In this case, we will analyze the samples based on the Calculation section of the method document.

According to the method, to determine if a sample has broken through, we need to compare the concentrations of the hazardous substance in the front and back segments of the sampling media. If the concentration in the back segment is less than or equal to 5% of the concentration in the front segment, then the sample is considered not to have broken through.

For Sample #1, the concentration of Benzene in the front segment is 100 µg, and in the back segment, it is 15 µg. To determine if it has broken through, we calculate:

(15 µg / 100 µg) * 100% = 15%

Since the back segment concentration (15%) is greater than 5% of the front segment concentration, Sample #1 has not broken through.

For Sample #2, the concentration of Toluene in the front segment is 75 µg, and in the back segment, it is 5 µg. We calculate:

(5 µg / 75 µg) * 100% ≈ 6.67%

Again, the back segment concentration (6.67%) is greater than 5% of the front segment concentration, indicating that Sample #2 has not broken through.

In both cases, the back segment concentrations are above the threshold of 5% of the front segment concentration, so we can conclude that neither Sample #1 nor Sample #2 have broken through according to the NIOSH 1501 method.

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The equation of the line with a slope of 7/11 that passes through the point (11, 13) is y = (7/11)x + 6.

The slope-intercept form of a linear equation is given by y = mx + b, where m represents the slope and b represents the y-intercept.

In this case, the slope (m) is 7/11, and the point (11, 13) lies on the line. We can use this information to find the equation.

Substituting the values into the slope-intercept form, we have:

13 = (7/11)(11) + b

Simplifying the equation:

13 = 7 + b

To solve for b, we subtract 7 from both sides:

b = 13 - 7

b = 6

Therefore, the equation of the line with slope 7/11 that passes through the point (11, 13) is:

y = (7/11)x + 6

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The given periodic function, g(x), can be transformed by multiplying each value of g(x) by 2 and shifting the argument by 1 unit to the right. This can be represented by the expression 2g(x - 1).

To calculate the values of 2g(x - 1), we need the values of g(x) provided in the table. Let's assume the table consists of two columns: x and g(x). We will add a third column for the values of 2g(x - 1).

Here's a step-by-step process to calculate the values of 2g(x - 1):

1. Start with the given table of x and g(x).

2. For each row in the table, subtract 1 from the value of x to get x - 1.

3. Use the value of x - 1 to find the corresponding value of g(x - 1) in the g(x) column.

4. Multiply the value of g(x - 1) by 2 to obtain 2g(x - 1).

5. Record the values of 2g(x - 1) in the third column of the table.

Following this process, you can populate the third column with the values of 2g(x - 1) based on the given function g(x).

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The value of B is 90° and the values of a, b, c, A, and B are 18.8 cm, 37.95 cm, 45.7 cm, 65.06°, and 90° respectively.

Given that, the right triangle ABC, where C=90° and a=18.8 cm, c=45.7 cm. We need to find the value of b, A, and B.Step 1:As we know that `a^2 + b^2 = c^2`Plugging the values in the above equation 18.8^2 + b^2 = 45.7^2b^2 = 45.7^2 - 18.8^2b^2 = 1794.89 - 353.44b^2 = 1441.45Taking square root on both the sidesb = 37.95 cmStep 2:Finding value of sin AUsing the formula `sin A = a/c`sin A = 18.8/45.7sin A = 0.411 = 24.94°Step 3:Finding value of AAs we know that, A + 90° + 24.94° = 180°A + 114.94° = 180°A = 180° - 114.94°A = 65.06°Therefore, the value of B is 90° and the values of a, b, c, A, and B are 18.8 cm, 37.95 cm, 45.7 cm, 65.06°, and 90° respectively.

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The correct expression to solve for ΔH_f(H_2O)∘ for the given reaction is option (C) [ΔH_f(CO_2)∘ + 2(ΔH_f(H_2O)∘)] - ΔH_f(CH_4)∘

According to the given equation, ΔH_rxn∘ = ΔH_f(products)∘ - ΣΔH_f(reactants)∘, we can use the known enthalpies of formation (ΔH_f) of the products and reactants to calculate the enthalpy change of reaction.

In the reaction CH_4(g) + 2O_2(g) → CO_2(g) + 2H_2O(g), we want to solve for the enthalpy of formation of water, ΔH_f(H_2O)∘.

From the equation, we know that CO_2 is a product and CH_4is a reactant.

Therefore, we need to subtract the enthalpy of formation of CH_4from the sum of the enthalpy of formation of CO_2 and twice the enthalpy of formation of H_2O.

Hence, the correct expression is [ΔH_f(CO_2)∘ + 2(ΔH_f(H_2O)∘)] - ΔH_f(CH_4)∘, which is option C.

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The distance from point A to point B is approximately 480 meters.

To find the distance from point A to point B, we can use the law of cosines in triangle ABC. The law of cosines states that the square of one side of a triangle is equal to the sum of the squares of the other two sides minus twice the product of their lengths and the cosine of the included angle.

Let's denote the distance from A to B as x. Using the law of cosines, we have:

x^2 = 574^2 + d^2 - 2 * 574 * d * cos(31°)

Now, we can substitute the known values:

x^2 = 574^2 + d^2 - 2 * 574 * d * cos(31°)

x^2 = 574^2 + x^2 - 2 * 574 * x * cos(230°)

Simplifying the equation:

574^2 + d^2 - 2 * 574 * d * cos(31°) = 574^2 + x^2 - 2 * 574 * x * cos(230°)

Canceling out the common terms and solving for x:

d * cos(31°) = x * cos(230°)

x = (d * cos(31°)) / cos(230°)

Substituting the given values:

x = (574 * cos(31°)) / cos(230°)

Using a calculator, we find that x ≈ 480 meters.

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To paint the inside of the hemispherical pool, you need to find the surface area of the pool. The formula for the surface area of a hemisphere is 2πr^2, so the surface area of the pool is 2π(40)^2.

Divide this area by the coverage of one gallon of paint (350 square feet) to find the number of gallons needed. To paint the inside of the hemispherical pool, you need to find the surface area of the pool. The formula for the surface area of a hemisphere is 2πr^2, so the surface area of the pool is 2π(40)^2.

Divide this area by the coverage of one gallon of paint (350 square feet) to find the number of gallons needed. The result is approximately 29.01 gallons. If you wanted to fill the pool with paint, you would need to find the volume of the pool. The formula for the volume of a hemisphere is (2/3)πr^3.

Plugging in the radius of 40 feet, the volume is (2/3)π(40)^3. Multiply this volume by the conversion factor of 7.48 gallons per cubic foot to find the number of gallons needed. The result is approximately 952328.48 gallons.

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The normalization constant A for the given wavefunction ψ(r,θ,ϕ) is A = √(5/πa₀³), where a₀ is the Bohr radius.

To normalize the wavefunction, we need to find the normalization constant A that ensures the probability density integrated over all space equals 1. We begin by calculating the integral of the square of the wavefunction:

∫∫∫ ψ(r,θ,ϕ)² r²sinθ dr dθ dϕ

Expanding the square of the wavefunction and simplifying the trigonometric terms, we get:

∫∫∫ [e^(-r/a₀) (a₀r cosθ + 2/a₀ e^(-iϕ) sinθ - 2/a₀ e^(iϕ) sinθ + 2(1-2a₀r))^2] r²sinθ dr dθ dϕ

After evaluating the integral, we find:

∫∫∫ |A|^2 r²sinθ dr dθ dϕ = 1

Simplifying further and using the fact that the integral of sin²θ and cos²θ over the full range of θ is π/2, we arrive at the expression for A:

|A|^2 ∫(0 to ∞) [e^(-2r/a₀) (a₀r + 2/a₀)^2 r² dr] ∫(0 to π) (sin²θ) dθ ∫(0 to 2π) dϕ = 1

Evaluating the integrals, we obtain:

|A|^2 (5/πa₀³) = 1

Solving for A and expressing the answer with three significant figures, we find:

A = √(5/πa₀³)

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The quotient of `√(-315)` and `√45` is `i√7`What is a complex number?Complex numbers are numbers that are formed by adding a real number and an imaginary number together. i is used to denote the imaginary unit, which is equal to the square root of -1. For example, 5 + 2i is a complex number because it contains a real number (5) and an imaginary number (2i).What is a quotient?A quotient is the result of dividing one quantity by another. For example, the quotient of 10 divided by 5 is 2. To find the quotient of `√(-315)` and `√45`, we need to simplify each square root first.Solution:√(-315) can be written as √(-1*315) = √(-1)*√315 = i*√(9*35) = 3i√35√45 can be written as √(9*5) = 3√5Now we can substitute our simplified square roots into the quotient and simplify:(`√(-315)`)/(`√45`) = (3i√35)/(3√5) = i(√35)/(√5) = i(√7) = i√7The quotient of `√(-315)` and `√45` is `i√7`.Therefore, the answer is option B.

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The total surface area of North America is approximately 9.54 × 10^6 square miles in scientific notation. The signal from a certain satellite takes approximately 0.0013 seconds to reach Earth in standard notation.

To convert a number into scientific notation, we express it as a product of a decimal number greater than or equal to 1 but less than 10, and a power of 10. In this case, we move the decimal point to the left until there is only one nonzero digit to the left of the decimal point, resulting in 9.54. The exponent represents the number of places the decimal point was moved, which is 6 in this case since the original number had six digits.

Regarding the signal from a certain satellite taking approximately 1.3 × 10^(-3) seconds to reach Earth, we can write this number in standard notation as 0.0013 seconds.

To convert a number from scientific notation to standard notation, we multiply the decimal number by 10 raised to the power of the exponent. In this case, multiplying 1.3 by 10 raised to the power of -3 gives us 0.0013.

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To find the freshman enrollment of 2018, we need to determine the original enrollment figure before the 13.2% increase.

Let's assume the freshman enrollment of 2018 is represented by "x."

According to the information given, the freshman enrollment in 2019 was a 13.2% increase over the previous record in 2018. This can be expressed as:

x + 0.132x = 1060

Combining like terms:

1.132x = 1060

Dividing both sides by 1.132:

x = 1060 / 1.132

x ≈ 937.26

Rounded to the nearest whole number, the freshman enrollment of 2018 at Howard University was approximately 937.

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