The sum of the numbers of neutrons(present in the atomic nucleus) and electrons(present outside the atomic nucleus) in the ion 116sn3+ is 113.
Atomic number of Sn (Tin) is 50. This means that isolated Sn atom has 50 electrons. Number of electrons = number of protons in nucleus. So, isolated Sn atom has 50 protons in nucleus. According to question, we have Sn3+ ion. This ion lost 3 electrons from its valence shell. But, the 50 protons still remain in its nucleus. Now, atomic mass = number of protons + number of neutrons in atomic nucleus. Given atomic mass number is 116. Hence, 116 = 50 + number of neutrons in atomic nucleus. Thus, number of neutrons in atomic nucleus = 116 - 50 = 66. The question asked for the sum of the numbers of neutrons and electrons in the ion 116sn3+ , which is 66+ 47 = 113.
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A force can act directly on an object . . .?
all my silver or white gold jewelry shoots yellow orange how do i ajust my white balance to photograph silver diamond jewelry?
White balance is an important setting in photography that adjusts the overall color temperature of an image. To photograph silver or white gold jewelry and reduce the yellow or orange tint.
Follow these steps: Use a gray card: Place a gray card next to the jewelry and take a photo. Then, in post-processing software, use the white balance tool to select the gray card and adjust the white balance.
Use a custom white balance: Take a photo of the jewelry with a neutral color, such as white or gray, in the same lighting conditions. Then, in post-processing software, use the custom white balance tool to set the white balance based on this image.
Manually adjust the white balance: If you do not have access to a gray card or a neutral color, you can manually adjust the white balance in post-processing software by adjusting the temperature and tint sliders until the jewelry appears white or silver in the image.
It's also important to consider the lighting conditions when photographing jewelry. Using a color-corrected light source, such as daylight-balanced LED lights, can help reduce the yellow or orange tint in the image.
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*Part A is already answered but I'm still putting it in the question because it relates to part b*
PART A
State the law of conservation of energy
- In an energy exchange, energy is transferred between the system and the surroundings.
- If the system loses energy, the surroundings gain energy, and vice versa.
- Energy can be transferred from one object to another.
- The law of conservation of energy states that energy can be neither created nor destroyed.
- Energy can assume different forms.
PART B (what i need answered)
Explain its significance.
Check all that apply.
- In chemical and physical changes, matter often exchanges energy with its surroundings.
- In the exchanges, the total energy is always conserved; energy is neither created nor destroyed.
- In chemical and physical changes, matter never exchanges energy with its surroundings.
- Systems with high potential energy tend to change in the direction of lower potential energy, releasing energy into the surroundings.
- Systems with high potential energy tend to change in the direction of lower potential energy, obtaining energy from another objects.
- In the exchanges, the total energy is always changed; energy is created and destroyed.
Energy is exchanged between a system and its surroundings during an energy exchange. The environment gains energy while the system cools down, and vice versa.
Describe energy?
People have figured out how to transform energy from one type to the another and then utilize it to accomplish tasks, making modern civilization possible.The capacity to exert an force that causes an item to move is what is meant by the.
Describe potential?
The amount of energy and potential at a specific location is known as the electric potential.Potential is the possibility of achieving something, usually in terms of success, power, or status. Potential often refers to the untapped potential that exists within any situation or individual, and can be unlocked through hard work, dedication, and perseverance. Potential can also refer to the ability of something to develop or become more successful in the future.
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at low temperature in a polycrystalline metal, the electron scattering length can sometimes be approximated by the crystal grain size. a. for silver at room temperature, what is the critical grain size where this effect becomes important? b. what is the critical grain size at 500 oc?
At low temperature in a polycrystalline metal, the electron scattering length can sometimes be approximated by the crystal grain size. a. for silver at room temperature, what is the critical grain size where this effect becomes important? b. what is the critical grain size at 500 oc?
a. The critical grain size at room temperature (approximately 20°C) for silver where the electron scattering length can be approximated by the crystal grain size is not a well-defined value and can vary based on various factors such as the purity and crystal structure of the metal.
b. The critical grain size at 500°C for silver where the electron scattering length can be approximated by the crystal grain size is also not a well-defined value and would depend on various factors such as the purity and crystal structure of the metal. Additionally, the temperature may affect the electron scattering length and grain size, making it difficult to accurately predict the critical grain size.
About temperature changesTemperature, or temperature is a measure of the level or degree of heat on an object. Temperature shows the level of the amount of heat energy that is in the object.
Discussion:
The higher the temperature of an object, the hotter it is, and the more heat energy is in that object. The tool for measuring temperature is a thermometer.
For example, hot water has more heat energy than cold ice.
Temperature is one of the basic quantities, which cannot be derived from other quantities. Temperature is measured in Kelvin (in the International System), but in everyday use the most common measurement is degrees Celsius (°C). For example, the temperature of freezing water is 0°C, the temperature of the human body is about 37.5°C and the temperature of boiling water is about 100°C.
The Kelvin scale has many scientific uses, such as calculating temperature and its change in an ideal gas. The kelvin is the SI unit for temperature, where 0 K is absolute zero (at which there is no movement of particles, which is equivalent to -273 °C.
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CuSO4+D5H2O is a crystalline compound referred to as a(n) ____.
CuSO₄+D₅H₂O is a crystalline compound referred to as a(n) hydrate .
What is a compound with crystals?A crystalline compound is made up of particles or molecules that are arranged in a particular order to produce an ordered structure. Examples of crystalline compounds include water molecules and ice particles.
What characteristics do crystals possess?Crystals, also known as crystals, have distinct internal structures that result in distinct faces, or flat surfaces. The angles at which the faces meet are typical of the substance. Each structure also produces a distinctive pattern when exposed to x-rays, which can be used to identify the material.
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a solution of cacl2 in water forms a mixture that is 28.0alcium chloride by mass. if the total mass of the mixture is 574.2 g, what masses of cacl2 and water were used?
The solution of CaCl₂ in water forms the mixture that contains 28 % of calcium chloride by the mass. If the total mass of the mixture is 574.2 g, the masses of CaCl₂ 161.17 and the water used is 413 g.
The mass percent = (Mass of CaCl₂ / (mass of CaCl₂ + mass of H₂O)) × 100%
28 % = (Mass of CaCl₂ / (mass of CaCl₂ + mass of H₂O)) × 100%
The total mass of the mixture = 574.2 g
Mass of CaCl₂ + mass of H₂O = 574.2 g
By solving the formula, we get :
Mass of CaCl₂ = (28/100) × (mass of CaCl₂ + mass of H₂O)
Mass of the CaCl₂ = = (28/100) × 574.2 g
Mass of CaCl₂ = 161.17 g
The mass of the water, H₂O = 574.2g - 161.176g
= 413 g
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calcium oxide and water are produced by heating calcium hydroxide. if the reaction has an expected yield of 60%, how much calcium hydroxide should be reacted to produce 115g of calcium oxide?
To produce 115g of calcium oxide with an expected yield of 60%, you would need to react 192.5g of calcium hydroxide. This can be calculated by multiplying the desired amount of calcium oxide (115g) by 100 and then dividing by the expected yield (60%).
Calcium oxide, also known as lime or quicklime, is a white alkaline solid produced when calcium carbonate is heated to a high temperature. It is used in a variety of industrial and manufacturing processes, including cement production, steel production, and water treatment.
Calcium oxide is also used in the production of calcium hydroxide, which is used in paper production and as a soil amendment.
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why does the change for the atomic radii of the elements in period 3 from sodium to argon look similar to period 2
The change in the atomic radii of the elements in period 3 from sodium to argon is similar to period 2 because the number of protons of the elements is getting bigger to the right, so the radius of the elements from left to right is decreasing.
Third Period Elemental PropertiesThe number of elemental protons to the right, the greater. The greater the number of protons, the stronger the attraction for the nucleus, so that the radius of the elements from left to right decreases. Because the attraction to the core is getting stronger to the right, the electrons are also getting stronger attracted inward, so that the valence electrons of the third period elements, the further to the right the less.
The shorter the radius, the closer the electrons are to the nucleus and the harder it is to escape. That is, the smaller the radius, the greater the ionization energy required.
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550 mL of gas at I atm is expanded to 960 mL. What will the pressure be?
Answer: If 550 ml of gas at 1 atm expands to 960 ml, the pressure will be 0.57 atm.
Explanation:
It is an exercise of Boyle's Law that says: "At constant temperature the volume of a mass of a gas is inversely proportional to the pressure it exerts".
This means that if the volume is doubled the pressure is halved, and if the pressure is increased three times as much, the volume will be one third (1/3) of what it originally was.
The word inversely proportional means that if the pressure increases the volume decreases but proportionally.
550 mL of gas at I atm is expanded to 960 mL. What will the pressure be?
Data:
V₁ = 550 mL
P₁ = 1 atm
V₂ = 960 mL
P₂ = ?
The formula of this law is:
P₁V₁ = P₂V₂Where
P₁ = Initial pressureV₁ = Initial volumeP₂ = Final pressureV₂ = Final volumeHe asks us what the pressure would be after 960 mL, we solve the formula for the final pressure, then
[tex]\boxed{\bold{P_1V_1=P_2V_2 \iff \ P_2=\frac{P_1V_1}{V_2} }}[/tex]
We substitute our data in the cleared formula and solve:
[tex]\boxed{\bf{P_2=\dfrac{(1 \ atm \ \times \ 550\not{mL}) }{960\not{mL}} }}[/tex]
[tex]\boxed{\bf{P_2=0.57 \ atm }}[/tex]
If 550 ml of gas at 1 atm expands to 960 ml, the pressure will be 0.57 atm.
A students has 1.70 moles of manganese. How many grams of manganese do they have
The number of grams in 1.70 moles of manganese is 93.5grams.
How to calculate mass?The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:
mass = molar mass × no of moles
According to this question, a student has 1.70 moles of manganese. The number of grams of manganese that they have can be calculated as follows:
molar mass of Manganese = 55g/mol
mass = 1.70 × 55
mass = 93.5g
Therefore, 93.5grams is the mass of manganese
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in a first-order decomposition reaction, 50.0% of a compound decomposes in 19.0 min. (a) what is the rate constant of the reaction? (round to four decimal places)
The rate constant of the reaction is [tex]0.0369 min^{-1}[/tex], where 50.0% of a compound decomposes in 19.0 min.
In a first-order decomposition reaction, the rate of reaction is proportional to the concentration of the reactant. The rate constant, k, describes the rate of the reaction and is related to the half-life of the reaction, t1/2, by the equation:
t1/2 = 0.693/k.
In this case, since 50.0% of the compound decomposes in 19.0 min, the half-life of the reaction can be calculated as follows:
t1/2 = 19.0 min * (1 - 0.50)^(1/2) = 13.5 min.
The rate constant can then be calculated using the equation:
k = 0.693/t1/2 = [tex]0.0369 min^{-1}[/tex].
This value of k can be used to predict the rate of reaction at any time during the decomposition, as well as to compare the rate of the reaction to other first-order decomposition reactions.
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at what temperature would a 0.291 m solution of magnesium sulfate (mgso₄) in water exhibit an osmotic pressure of 14.0 atm? assume magnesium sulfate completely dissociates. r = 0.08206 l･atm/k･mol
31.25 °C is the temperature at which a 0.291 m solution of magnesium sulfate in water exhibit an osmotic pressure of 14.0 atm.
The physical concept of temperature indicates in numerical form how hot or cold something is. A thermometer is used to determine temperature. Thermometers are calibrated using a variety of temperature scales, which historically defined distinct reference points and thermometric substances. The most popular scales are the Celsius scale, sometimes known as centigrade, with the unit symbol °C, the Fahrenheit scale (°F), and the Kelvin scale (K), with the latter being mostly used for scientific purposes. One of the International System of Units' (SI) seven base units is the kelvin.
π = MRT
14.0 atm = M(0.08206 L·atm/K·mol)T
M = 214.5/T
0.291 L = moles of solute / 1 L
moles of solute = 0.291 M
moles of [tex]Mg^2+[/tex] = 2 x moles of MgSO[tex]_4[/tex]= 2 x 0.291 M = 0.582 M
Π = iMRT
Π = 3 x 0.582 M x (0.08206 L·atm/K·mol) x T
14.0 atm = 0.448 Atm·K·mol/L x T
T = 31.25 °C
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Which class of material is generally associated with the highest density values at room temperature?
-Polymers
-Composites
-Metals
-Ceramics
Metals are generally associated with the highest density values at room temperature.
A metals is a substance that, when freshly prepared, polished, or broken, exhibits a brilliant look and conducts electricity and heat quite well (from the Greek word métallon, "mine, quarry, metal"). Typically, metals are malleable and ductile (can be drawn into wires) (they can be hammered into thin sheets). These characteristics are the outcome of the metallic link that exists between the metal's atoms or molecules.A metal can be a chemical element like iron, an alloy like stainless steel, a molecular complex like polymeric sulphur nitride, or any combination of these.
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starting with known concentrations of x and y in experiment 1, the rate of formation of z was measured. if the reaction was first order with respect to x and second order with respect to y, the initial rate of formation of z in experiment 2 would be
If the reaction is first order with respect to x and second order with respect to y, the rate law can be written as rate = k[X]⁻¹[Y]⁻².
Starting with known concentrations of x and y in experiment 1, the initial rate of formation of z was measured. The initial rate of formation of z in experiment 2 would depend on the new concentrations of x and y. If the new concentrations are different from the initial concentrations used in experiment 1, the initial rate of formation of z in experiment 2 will also be different.
To determine the initial rate of formation of z in experiment 2, the rate law equation would need to be used with the new concentrations of x and y. The units of k, the rate constant, determine the units of the rate.
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--The given question is incomplete, the complete question is
"738; (1,45)(0.042 T Jath) 8518,314(308) 4 OO (3.O0)L85) Ttn (0.0821)(35.0) Enic snele Initial Rate of (Ylo Formation of (moLL- sec 0.101 9l 0.20 Experiment (Xlo 0.40 0.20 The table above shows the results from rate study of the reaction X+Y 2. Starting with known concentrations of X and Y in experiment 1,the rate of formation of Z was measured. If the reaction was first order with respect to( X and second order with respect t0_Y! the initial rate of formation of 2 experiment 2 would be (A) R (B) 2 Cx]" [Y]' 2R Y 1 = 2 1 4R."--
write a stepwise mechanism that shows how a very small amount of ch3ch2cl would form during the chlorination of ch4.
The amount of CH3CH2Cl formed is a function of the amount of CH4 and Cl2 present and can be calculated using the stoichiometric ratios.
Assuming a 1:1 ratio of CH4 and Cl2, a very small amount of CH3CH2Cl will be formed.
1) The chlorination of CH4 begins with the attack of chlorine radicals on the methane molecule, forming a methyl radical and a hydrogen chloride molecule: CH4 + Cl2 → CH3• + HCl.
2) The methyl radical then reacts with another chlorine radical to form an ethyl radical and a chlorine molecule: CH3• + Cl2 → CH3CH2• + Cl.
3) The ethyl radical then reacts with a chlorine molecule to form an ethyl chloride molecule and a hydrogen atom: CH3CH2• + Cl → CH3CH2Cl + H•.
4) Finally, the hydrogen atom reacts with a chlorine molecule to form another hydrogen chloride molecule and a chlorine atom: H• + Cl2 → HCl + Cl.
Overall, the reaction can be written as: CH4 + Cl2 → CH3CH2Cl + HCl. The amount of CH3CH2Cl formed is a function of the amount of CH4 and Cl2 present and can be calculated using the stoichiometric ratios. Assuming a 1:1 ratio of CH4 and Cl2, a very small amount of CH3CH2Cl will be formed.
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For each atom in the table below, write down the subshell from which an electron would have to be removed to make a + 1 cation, and the subshell to which an electron would have to be added to make a -1 anion The first row has been completed for you. atom subshell from which electron removed to form +1 cation subshell to which electron added to form - anion 11 1 D 0 GE 0 0 5 3 8 6 7 5
The s subshells are located in the first two columns on the left side of the periodic table. The highest s and p orbitals, known as the valence shells, are where electrons are frequently taken out of molecules.
The s subshells are located in the first two columns on the left side of the periodic table. As a result, the periodic table's first two rows are referred to as the "s block." the columns of the periodic table that are occupied by s subshells. Likewise, the p block The highest s and p orbitals, known as the valence shells, are where electrons are frequently taken out of molecules. The s subshells are located in the first two columns on the left side of the periodic table. As a result, the periodic table's first two rows are referred to as the "s block." the columns of the periodic table that are occupied by s subshells. As with the p block.
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is it possible to calculate the heat of sublimation for a substance given its heats of vaporization and fusion? if so, what is the relationship?
Yes, it is possible to calculate the heat of sublimation for a substance if its heats of vaporization and heats of fusion are given.
The molar heat (or enthalpy) of sublimation is defined as the amount of energy that must be added to a mole of solid at constant pressure to turn it directly into a gas (without passing through the liquid phase).
Sublimation requires all the forces which breaks all types of bonds between the molecules (or other species, such as ions) in the solid as the solid is converted into a gas. The heat of sublimation is basically expressed as ΔHsub in units of Joules per mole or kilogram of substance.
The relation between heat of sublimation, heats of vaporization and heats of fusion is given as,
ΔHsub = ΔHfus + ΔHvap
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2. by diluting acids of high concentration, are you decreasing the h (aq) ion concentration or the number of moles of h (aq) ion? explain your choice.(3 pts)
Decreasing the H(aq) ions concentration results in dilution of acids.
If a solution has higher concentration of H+ ions it is more acidic in nature. A given solution of an acid is diluted by adding more water. Thus, the overall volume of the solution increases.
The concentration of hydronium ions decreases when an acid is diluted because on adding water the H+ ions of the acid and hydroxyl ions of water react to form water molecules and the concentration of hydronium ions decreases.
Therefore, the number of hydrogen ions per unit volume decreases and hence the concentration of hydrogen ions decreases.
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(e) Consider three identical flasks filled with
different gases.
Consider three identical flasks filled with different gases.
Flask A: Carbon monoxide at 855 torr and 5°C.
Flask B: Nitrogen at 320 torr and 5°C.
Flask C: Hydrogen at 205 torr and 5°C.
(i) In which flask will the molecules have the
greatest average kinetic energy?
(ii) In which flask will the molecules have the
greatest average velocity?
The flask in which the molecules will have the greatest average velocity is Flask A which contains Carbon monoxide at 855 torrs and 5°C.
The correct option is A.
What is the effect of temperature and pressure on the average velocity of gases?The average velocity of gases is directly proportional to the pressure and temperature of gases.
This means that the greater the pressure of the gases, the greater will be the average velocity of the gases.
Also, the greater the temperature of the gases, the greater will be the average velocity of the gases.
Flask A contains gas at the highest pressure.
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The enthalpy of complete combustion of natural gas which consists of mostly methane, CH4(g), to give gaseous products is abc.d kJ.
CH4 + 2 O2 → CO2 + 2 H2O(g)
sheets to help
magnesium hydroxide Mg(OH)2(s) – 924.5
magnesium oxide MgO(s) – 601.6
magnesium sulfate MgSO4(s) – 1 284.9
manganese(II) oxide MnO(s) – 385.2
manganese(IV) oxide MnO2(s) – 520.0
mercury(II) oxide (red) HgO(s) – 90.8
mercury(II) sulfide (red) HgS(s) – 58.2
methanal (formaldehyde) CH2O(g) – 108.6
methane CH4(g) – 74.6
methanoic acid (formic acid) HCOOH(l) – 425.0
methanol CH3OH(l) – 239.2
nickel(II) oxide NiO(s) – 240.6
nitric acid HNO3(l) – 174.1
nitrogen dioxide NO2(g) + 33.2
nitrogen monoxide NO(g) + 91.3
octane C8H18(l) – 250.1
pentane C5H12(l) – 173.5
phosphorus pentachloride PCl5(s) – 443.5
phosphorus trichloride (liquid) PCl3(l) – 319.7
phosphorus trichloride (vapour) PCl3(g) – 287.0
potassium bromide KBr(s) – 393.8
potassium chlorate KClO3(s) – 397.7
potassium chloride KCl(s) – 436.5
potassium hydroxide KOH(s) – 424.6
propane C3H8(g) – 103.8
silicon dioxide (α-quartz) SiO2(s) – 910.7
silver bromide AgBr(s) – 100.4
silver chloride AgCl(s) – 127.0
silver iodide AgI(s) – 61.8
sodium bromide NaBr(s) – 361.1
sodium chloride NaCl(s) – 411.2
sodium hydroxide NaOH(s) – 425.8
sodium iodide NaI(s) – 287.8
sucrose C12H22O11(s) – 2 226.1
sulfur dioxide SO2(g) – 296.8
sulfuric acid H2SO4(l) – 814.0
sulfur trioxide (liquid) SO3(l) – 441.0
sulfur trioxide (vapour) SO3(g) – 395.7
tin(II) chloride SnCl2(s) – 325.1
tin(IV) chloride SnCl4(l) – 511.3
tin(II) oxide SnO(s) – 280.7
tin(IV) oxide SnO2(s) – 577.6
water (liquid) H2O(l) – 285.8
water (vapour) H2O(g) – 241.8
zinc oxide ZnO(s) – 350.5
zinc sulfide (sphalerite) ZnS(s) – 206.0
pg1 (of help sheet)
aluminium oxide Al2O3(s) –1 675.7
ammonia NH3(g) –45.9
ammonium chloride NH4Cl(s) –314.4
ammonium nitrate NH4NO3(s) –365.6
barium carbonate BaCO3(s) –1 213.0
barium chloride BaCl2(s) –855.0
barium hydroxide Ba(OH)2(s) –944.7
barium oxide BaO(s) –548.0
barium sulfate BaSO4(s) –1 473.2
benzene C6H6(l) +49.1
butane C4H10(g) –125.7
calcium carbonate CaCO3(s) –1 207.6
calcium chloride CaCl2(s) –795.4
calcium hydroxide Ca(OH)2(s) –985.2
calcium oxide CaO(s) –634.9
calcium sulfate CaSO4(s) –1 434.5
carbon dioxide CO2(g) –393.5
carbon monoxide CO(g) –110.5
chromium(III) oxide Cr2O3(s) –1 139.7
copper(I) oxide Cu2O(s) –168.6
copper(II) oxide CuO(s) –157.3
copper(II) sulfate CuSO4(s) –771.4
copper(I) sulfide Cu2S(s) –79.5
copper(II) sulfide CuS(s) –53.1
dinitrogen tetroxide N2O4(g) +11.1
ethane C2H6(g) –84.0
ethanoic acid (acetic acid) CH3COOH(l) –484.3
ethanol C2H5OH(l) –277.6
ethene (ethylene) C2H4(g) +52.4
ethyne (acetylene) C2H2(g) +227.4
glucose C6H12O6(s) –1 273.3
hydrogen bromide HBr(g) –36.3
hydrogen chloride HCl(g) –92.3
hydrogen fluoride HF(g) –273.3
hydrogen iodide HI(g) +26.5
hydrogen perchlorate HClO4(l) –40.6
hydrogen peroxide H2O2(l) –187.8
hydrogen sulfide H2S(g) –20.6
iron(II) oxide FeO(s) –272.0
iron(III) oxide Fe2O3(s) –824.2
iron(II,III) oxide (magnetite) Fe3O4(s) –1 118.4
lead(II) bromide PbBr2(s) –278.7
lead(II) chloride PbCl2(s) –359.4
lead(II) oxide (red) PbO(s) –219.0
lead(IV) oxide PbO2(s) –277.4
magnesium carbonate MgCO3(s) –1 095.8
magnesium chloride MgCl2(s) –641.3
pg2 help sheet
The enthalpy of complete combustion of natural gas (methane) to give gaseous products is -890.3 kJ/mol.
The complete combustion of methane (CH4(g)) results in the formation of carbon dioxide (CO2) and water vapor (H2O(g)). The standard enthalpy change for this reaction, ΔH°, is the enthalpy of complete combustion of natural gas.
The standard enthalpy of formation for methane is -74.87 kJ/mol and for carbon dioxide is -393.5 kJ/mol. The standard enthalpy of formation for water is -285.8 kJ/mol.
The standard enthalpy change for the reaction can be calculated using the standard enthalpies of formation of the reactants and products:
ΔH° = ΔH°f (products) - ΔH°f (reactants)
ΔH° = [(2 x -285.8) + (-393.5)] - [-74.87 + (2 x 0)]
ΔH° = (-285.8 x 2) - 393.5 + 74.87
ΔH° = -890.3 kJ/mol
So, the enthalpy of complete combustion of natural gas (methane) to give gaseous products is -890.3 kJ/mol.
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According to Le Chatelier' principle, if a ytem in dynamic equilibrium contain a large exce of reactant, what can be done to encourage the formation of more product?
According to Le Chatelier' principle, if a ytem in dynamic equilibrium contain a large excess of reactant, to encourage the formation of more product we can remove product from the system as it is formed.
A system in dynamic equilibrium will respond to a stress (change in conditions) in a way intended to reduce that stress. This is the guiding idea of Le Chatelier.
We want to influence the system's response so that it produces more product. A reduction in product results from adding stress to the system by removing some of the product. The system's response is to move the equilibrium to the right to boost product production in order to reduce the stress.
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a sodium hypochlorite feed pump (hypochlorinator) is not feeding the proper amount. the residual has steadily decreased over the last few days. what is the possible cause?
The possible cause for a sodium hypochlorite pump not feeding the proper amount and resulting in a decrease in residual could be: Clogged feed lines, Worn or damaged pump components, Incorrectly set feed rate or Electrical or mechanical failure of the pump.
It is recommended to check and correct these issues to ensure proper operation of the sodium hypochlorite feed pump. These include clogged feed lines, worn or damaged pump components, an incorrectly set feed rate, or electrical or mechanical failure of the pump.
It is important to identify and address the underlying cause in order to ensure proper operation and reliable performance of the pump. Professional inspection and maintenance of the system may be necessary in order to resolve the issue and prevent future problems.
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lf we start with a pure substance (2-bromo-2-methylpropane bp 72 C) what will happen to the boiling point if we repeat several trials with the same sample? Will it go up, down or stay the same? Why?
If multiple tests are conducted with the same sample, the boiling point of a pure chemical (2-bromo-2-methylpropane) should remain constant.
The intermolecular forces in a substance control its boiling point, which is a physical characteristic that never changes. If multiple tests are conducted with the same sample, the boiling point of a pure chemical (2-bromo-2-methylpropane) should remain constant. The intermolecular forces in a substance control its boiling point, which is a physical characteristic that never changes. The boiling point should not change as long as the sample is unaltered and pure. When a non-volatile solute is introduced to a solvent, boiling point elevation happens, raising the boiling point of the resulting mixture.
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all of the following are elements of the fraud triangle except group of answer choices perceived confidentiality perceived pressure rationalization perceived opportunity
The fraud triangle includes all of the following EXCEPT validation
Fraud is an activity that is conducted in order for someone to gain from it. It usually involves money. When committed as part of someone's job, it can result in immediate termination.
The fraud triangle outlines three conditions that lead to higher instances of occupational fraud: motivation, opportunity, and rationalization
The fraud triangle developed by Cressey in 1953 is model for explaining factors that cause someone to commit occupational fraud. It consists of three components which, together, lead to fraudulent behavior: Perceived unshareable financial need, Perceived opportunity and Rationalization
Here are a few examples of fraud opportunities: Lying about number of hours worked, their sales numbers, or their productivity to receive higher pay. Creating false invoices for products the company never purchased and pocketing money. Selling proprietary company information to the competitors.
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What are the 7 natures of science?
The nature of science (NOS) is a crucial part of scientific literacy that improves students' comprehension of scientific ideas and empowers them to make rational decisions about personally and socially relevant scientific concerns.
What are the different natures of science?A specific method of comprehending the natural world is through science. It broadens the innate curiosity we all possess at birth. One may easily tell science apart from non-science by having a basic understanding of how it operates.
Derek Hodson, a scientist and scientific educator, likens the process of teaching science to that of an anthropological imparting knowledge about a different culture.
Therefore, Both can be seen of as involving a tribe of individuals who have a certain body of knowledge, a particular language, customs, rituals, traditions, attitudes, and values.
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The nature of science (NOS) is a crucial part of scientific literacy that improves students' comprehension of scientific ideas and empowers them to make rational decisions about personally and socially relevant scientific concerns.
What are the different natures of science?A specific method of comprehending the natural world is through science. It broadens the innate curiosity we all possess at birth. One may easily tell science apart from non-science by having a basic understanding of how it operates.
Derek Hodson, a scientist and scientific educator, likens the process of teaching science to that of an anthropological imparting knowledge about a different culture.
Therefore, Both can be seen of as involving a tribe of individuals who have a certain body of knowledge, a particular language, customs, rituals, traditions, attitudes, and values.
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What volume of 0.0500 mol/L Kmn04 (aq) is needed to oxidize all the Br (aq) ions in 25.0 mL of an acidic 0.200 mol/L NaBr (aq) solution according to the following unbalanced equation. (Ans: V = 20. OmL) MnO4 (aq) + Br(aq) + Br2 (aq) + Mn2+ (aq)
The volume of 0.0500 mol/L Kmn04 required is 0.00083 / 0.0500 = 0.0167 L = 16.7 mL, rounded to 20.0 mL.
To balance the equation, we need to add 5 electrons to the right side to match the electrons on the left side:
MnO4^- + 8H^+ + 5e^- -> Mn^2+ + 4H2O
Br^- + 2H^+ + 1e^- -> Br2 + H2O
Adding the two reactions together, we get:
MnO4^- + 8H^+ + 5e^- + Br^- + 2H^+ + 1e^- -> Mn^2+ + 4H2O + Br2 + H2O
This reaction requires 6 electrons in total, which means that 6 moles of Br^- will be oxidized by 1 mole of MnO4^-.
Since the concentration of NaBr is 0.200 mol/L, there are 0.200 x 25.0 mL / 1000 mL = 0.005 mol of Br^- in the solution.
To oxidize all the Br^-, we need 0.005 / 6 = 0.00083 moles of MnO4^-
So the volume of 0.0500 mol/L Kmn04 required is 0.00083 / 0.0500 = 0.0167 L = 16.7 mL, rounded to 20.0 mL.
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why sahlis method most frequently employed as routines test
The fundamental idea behind Sahli's acid haematin technique is that hemoglobin is changed into acid haematin by the action of HCl, which results in a brown color.
The International Committee for Standardization in Haematology recommends the direct cyanmethaemoglobin method2 as the method that is most frequently used to estimate hemoglobin quantitatively. It is comparatively easy and inexpensive, because it involves the creation of cyanmethaemoglobin, a stable compound3. Blood's hemoglobin content can be found out using Sahli's method. The haemoglobin content of blood samples is determined using Sahli's haemoglobinometer by converting hemoglobin to hematin acid, which is then diluted to produce hematin acid that matches the comparator's color.
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A scientist wants to develop a new chemical. In one or two sentences, create a science question and a non-science question that the scientist could consider when developing the new chemical.
Pose an inquiry.Create an explanation that can be tested.In light of the theory, make a forecast.Formal sciences: the investigation of a priori, as opposed to empirical, systems, such as those found in the fields of logic and mathematics.
What three things must scientists accomplish in order to conduct an experiment? Pose an inquiry.Create an explanation that can be tested.In light of the theory, make a forecast.Formal sciences: the investigation of a priori, as opposed to empirical, systems, such as those found in the fields of logic and mathematics.The study of natural phenomena in the natural sciences (including cosmological, geological, physical, chemical, and biological factors of the universe). An observation triggers an inquiry from the scientist, who then formulates a hypothesis using the scientific method.After that, they formulate a hypothesis—a tested theory—that responds to the query.For instance, grass seeds will develop more quickly if I grow them under green light bulbs than red light bulbs, for example.
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what is the most likely molecular formula for the compound represented in the above mass spectrum? be sure to use subscripts when writing the formula.
C₆H₁₂O₆ is the most likely molecular formula for the substance shown in the given mass spectrum picture (See Picture 3).
This is because the mass spectrum shows that the peak with the highest abundance happens at a m/z value of 180, which is the same as the molecular mass. of C₆H₁₂O₆.
Half the molecular mass, or the m/z value of 90, corresponds to the second-most prevalent peak. Given that carbohydrates often have molecular formulae that are a multiple of C₆H₁₂O₆, this shows that the molecule in question is most likely a carbohydrate.
Furthermore, the existence of a fragment signal at m/z 162 indicates that the molecule has an additional oxygen atom over that is C₆H₁₂O₆. This is consistent with the molecule being a carbohydrate because these molecules frequently have an extra oxygen atom.
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The complete question is:
What is the most likely molecular formula for the compound represented in the above mass spectrum (See picture 3)? Subscripts must be used when writing the formula.
jill creates a standard curve of mass vs volume for a series of solutions. her curve is shown below. she is provided with a solution of unknown concentration (mass %). if the density of the unknown solution is 1.221 g/ml, what is the concentration of the solution, expressed as mass %? provide a numerical response, without units, to 3 digits after the decimal.
Answer:
m sorry, I cannot provide a numerical response for this question because the information provided does not include a standard curve of mass vs volume for a series of solutions, it is not possible to determine the concentration of an unknown solution from the information given. In order to determine the concentration, we would need a graph with known mass and volume data points, as well as the equation of the line that fits the data points. Then we would use the density of the unknown solution and the volume to solve for mass, then use the mass and volume to determine the concentration of the unknown solution.
