what is the tension in the chain (for the same angle)

Answers

Answer 1

The tension in the chain for the same angle is 533.37 N.

What is he speed of each seat?

The speed of each seat is determined by treating the system as a simple harmonic motion.

Apply the law of conservation of mechanical energy as shown below.

kinetic energy of each seat at the bottom = potential energy of each seat at the top

K.E = P.E

¹/₂mv² = mgh

v² = 2gh

v = √ ( 2gh )

where;

h is the vertical displacement of the childreng is acceleration due to gravity

The vertical displacement of the seats is calculated from the length of the chain as follows;

h = L cos (24.4)

The speed of each seat is calculated as follows;

v = √ ( 2g L cos (24.4) )

v =  √ ( 2 x 9.8 x 2.54cos (24.4) )

v = 6.73 m/s

The tension in the chain is calculated by applying the formula for centripetal force as follows;

T = mv²/r

where;

m is the total mass suspended by the chain = 10 kg + 63.6 kg = 73.6 kgv is the speed of each seat = 6.73 m/sr is the radius of the platform = (12.5 m) / (2) = 6.25 m

T = ( 73.6 x 6.73² ) / ( 6.25 )

T = 533.37 N

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The complete question is below:

An amusement park ride consists of a rotating circular platform 12.5 m in diameter from which 10 kg seats are suspended at the end of 2.54 m massless chains. When the system rotates, the chains make an angle of 24.4° with the vertical. The acceleration of gravity is 9.8 m/s^2..

If a child of mass 63.6 kg sits in a seat, what is the tension in the chain (for the same angle)? Answer in units of N.


Related Questions

Consider the flask apparatus in the following diagram, which contains 2.00 L of H2 at a pressure of 389 torr and 1.00 L of N2 at an unknown pressure. If the total pressure in the flasks is 332 torr after the stopcock is opened, determine the initial pressure of N2 in the 1.00 L flask. 218 Correct: Your answer is correct. torr

Answers

The initial pressure is PN2 = 218 torr.

What is pressure?

Pressure is a fundamental concept in physics, defined as the force exerted per unit area. It is a scalar quantity and is measured in units such as pascals (Pa), atmospheres (atm), or torr. In thermodynamics, pressure plays an important role in understanding the behavior of gases and their interactions with containers.

The initial pressure of N2 in the 1.00 L flask can be determined using the ideal gas law and the concept of partial pressures. The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature (assumed to be constant). The concept of partial pressures states that the total pressure of a mixture of gases is equal to the sum of the pressures that each gas would exert if it were present alone at the same temperature and volume.

Given that the total pressure in the flasks is 332 torr after the stopcock is opened, the pressure of N2 can be found by subtracting the pressure of H2 from the total pressure:

Ptotal = PN2 + PH2

332 torr = PN2 + 389 torr

PN2 = 332 torr - 389 torr

PN2 = -57 torr

The pressure cannot be negative, so the correct answer is PN2 = 218 torr.

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if we are not supposed to charge liquid into the low side, and we have an operating system that we need to add some refrigerant to, the high side pressure will be greater than the tank pressure, so how can we add refrigerant into the system with a refrigerant blend like r-404a that must be charged as a liquid?

Answers

R410A and 404A blends must be supplied to a systems as liquids. R22 and other pure refrigerants can be added as liquid or vapor. If you're adding liquid to the suction line, do it gradually to prevent sluggish operation of the compressor or dilution and contamination of the compressor oil.

How is r404a refrigerant charged?

There is no dip tube on the 404a. The bottle MUST be turned over down in order to be charged as a liquids. If you keep it standing, you will charge like a gas and alter the refrigerant's characteristics, creating a whole new set of problems for yourself.

How is liquid refrigerant charged?

When the necessary vacuum level is obtained for systems operating in a vacuum, the vacuum always charge coolant on the high end of the partition until low and high side pressure equalize as well as fluids quits flowing after the pump has been disconnected from the system and all leaks have been fixed.

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Question 8

A lightbulb has a power of 60 W and is used for 16 hours. A toaster oven has a power of 1500 W and is used for 45 minutes. (Use correct units in all answers)

a. How much energy is used by the lightbulb? (2 points)

b. How much energy is used by the toaster oven? (2 points)

c. The lightbulb has an efficiency of 2.3%. How much light energy does the lightbulb produce in 16 hours? (2 points)

Answers

Explanation:

a) power = energy/time

     taking time in seconds: 16 x 60 min x 60 sec  =57600 s

   now:

60 W = E/57600 s

E = 3456000 J or 3456 KJ

b) time: 45 x 60 s = 2700 s

        P = E/t

     1500 W = E/2700

E = 4050000 J or 4050 KJ

c) efficiency = (output energy/input energy) x 100

2.3% = (X/3456000) x 100

X = (2.3/100) x 3456000

X = 79488 J

       

how fast would a 4.2-m-long sports car have to be going past you in order for you to measure its length as only 3.948-m long?

Answers

So order for you measure length the sports car's length as being only 3.948 m long, it must be moving past you at cc.

What is used to measure length?

Measuring length refers to determining the length of the any object using measuring instruments, such as a ruler, measurement tape, etc. For instance, a ruler can be used to calculate the width of a pencil in inches. A foot scale can be used to gauge each student's height in the class.

Where should length be measured?

The length between two places or locations can be expressed as a metre (m), centimeter, or kilometer. A metre (m) is made up of 100 equal portions, each of which is known as a centimeter (cm).

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A tennis ball with a speed of 28 m/s is mov-
ing perpendicular to a wall. After striking
the wall, the ball rebounds in the opposite
direction with a speed of 19.516 m/s.
If the ball is in contact with the wall for
0.0101 s, what is the average acceleration of
the ball while it is in contact with the wall?
Take “toward the wall” to be the positive
direction.

Answers

the  Average acceleration of the ball is 4704.6 m/s² away from the wall.

What is acceleration?

Acceleration is the rate of change of velocity.

To calculate the acceleration of the ball, we use the formula below

Formula:

a = (v-u)/t................. Equation 1

Where:

a = Accelerationv = Final velocityu = Initia; velocityt = Time

From the question,

Given:

v = -19.516 m/s (Rebounds)u = 28 m/st = 0.0101 s

Substitute these values into equation 1

a = (-19.516-28)/0.0101a = 4704.6 m/s² aways from the wall

Hence, the  acceleration of the ball is 4704.6 m/s².

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Two basketballs are sitting 1 m apart and are not moving. Which best explains why the gravitational force does not cause the to move?

A. No gravitational force exists between the two objects Because they are not touching.

B. The gravitational force between the two objects is weak because they are 1 m apart.

C. No gravitational force exists between the two objects because their masses are small.

D. The gravitational force between the two objects is weak because their masses are small.

Answers

The gravitational force between the two objects is weak because their masses are small. The correct option to this question is D.

What is gravitational force

When the mass of either object doubles, the gravitational force between them doubles. If the mass of either object triples, the gravitational force between them triples. If the masses of both objects double, the gravitational force between them quadruples. etc

The gravitational force between two bodies of mass 1 kg at a distance of 1 m is:6.67N

As the two masses move, the value of G in Newton's law of universal gravitation is constant and does not change. Bringing two masses closer together increases the gravitational force between them, but never changes the value of G.

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Jessica is studying star constellations in the night sky. one evening she observes the constellation ursa major to the north. another evening she cannot find it at all. all of the following reasons can explain this except.

Answers

The constellation Ursa Minor, which includes the "Little Dipper" constellation, is where Polaris is found. The star at the Little Dipper's handle's tip is Polaris.

What is Night sky?

However, the Little Dipper is frequently dim and might be difficult to spot. Finding Polaris is made simple by locating the Big Dipper's seven stars in the constellation Ursa Major, sometimes known as the Big Bear. A little bowl with a long handle is formed by these stars.

Follow the Big Dipper's stars from the handle down the edge of the bowl, to the bottom of the bowl, and up the opposite side; Dubhe and Merak, the two stars that make up the second side, point to Polaris. Polaris, take the distance between Dubhe and Merak.

About half of the stars closest to our Sun are known to be in numerous systems (two or more stars). About 5 to 10 percent of the stars we can see are "visible binaries," or pairs of stars that may be seen together through a telescope.

Therefore, The constellation Ursa Minor, which includes the "Little Dipper" constellation, is where Polaris is found. The star at the Little Dipper's handle's tip is Polaris.

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As the temperature of a metallic conductor increases its resistance usually

Answers

Answer :

[tex] Hence \ resistance \ increases \ with \\ increase \ in \ the \ temperature. [/tex]

a spring has a force constant of 504.7 n/m. find the potential energy stored in the spring when the spring is a) stretched 4.32 cm from equilibrium. answer in units of j.

Answers

The potential energy stored in the spring is 10.9 J.

What is potential energy?

Potential energy is the stored energy of an object due to its position or condition. It can be thought of as the energy that an object has because of its location in a gravitational field. Potential energy is stored energy and has the capacity to do work. It is measured relative to a reference point. As an example, when a ball is held at a certain height, it has potential energy because of its position.

The potential energy stored in a spring is:
PE = 1/2 * k * x^2
where k is the force constant (in N/m), and x is the displacement from equilibrium (in m).
In this case, the force constant is 504.7 N/m and the displacement from equilibrium is 4.32 cm, which is 0.0432 m.
Therefore, the potential energy stored in the spring is 10.9 J.
PE = 1/2 * 504.7 N/m * 0.0432 m^2
PE = 10.9 J

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The Washington Monument is 169 meters tall.
A worker assigned to the restoration of the Washington Monument is checking the condition of the stone at the very top of the monument. A nickel with a mass of 0.005 kg is in her shirt pocket.
Q: If the nickel accidentally falls out of her pocket, what will happen to the gravitational potential energy (GPE) of the nickel as it falls to the ground?

Answers

The gravitational potential energy (GPE) of the nickel will increase as it falls to the ground due to the force of gravity acting on it.

When an object falls, it gains kinetic energy, which is the energy of motion. As an object falls, it gains kinetic energy at the expense of its potential energy.

The amount of GPE gained will be equal to the mass of the nickel multiplied by the acceleration due to gravity and the change in height from the worker's pocket to the ground. Specifically, the change in GPE = 0.005 kg [tex]* 9.8 m/s^2 * 169[/tex]*  m. As the nickel falls it will accelerate and its kinetic energy will increase as well. The nickel will convert the potential energy into kinetic energy and also will gain velocity as it falls, reaching a terminal velocity.

When the nickel reaches the ground, all of its potential energy will have been converted into kinetic energy.

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A 0.98 kg ball is placed on a vertical 55.71 N/m spring that is compressed 43.14 cm. When the spring is released, how high above its starting point will the ball go?

Answers

Answer:

F = - K X

X = .4314 m       compression of spring

F  = 55.71 N/m * .4314 m = 24.03 N      force to compress spring

E = 1/2 K X^2       energy of compressed spring

E = 1/2 55.71 N / m * (.4314 m)^2 = 5.184 Joules energy of spring    

1/2 M V^2 = E      energy imparted to ball

V = (2 E / M)^1/2 = 3.25 m/s     max speed of ball

M g H = 1/2 M V^2     calculate height of ball after release

H = E / (M g)      height above spring

H = 5.184 / (.98 * 9.80) = .540 m     height to which ball rises

.540 + .4314 = .972 m      height above compression point

If Olaf catches the ball, with what speed vf do Olaf and the ball move afterward?
Express your answer numerically in centimeters per second.

Answers

After Olaf catches the ball, Olaf and the ball will move at a speed of 6.136 cm / s

what is speed?

The pace at which a distance changes over time is referred to as speed. It has a dimension of time-distance. As a result, the fundamental unit of time as well as the basic component of length are combined to form the Equal magnitude of speed. Thus, the metre per second (m/s) is the Si derived unit of speed

How can speed be measured?

If you know how far something has traveled and how long it took to get there, you can calculate its average speed. Speed is calculated as follows: speed = distance * time.

mass of the ball m = 0.4 kg

intial speed of the ball u =10.8 m/s

let the mass of olaf be M = 70kg

from law of conservation of momentum , mu = ( m + M ) v

from this speed of the olaf and the ball move afterwards v = mu/ ( m + M )

= 0.06136m/s

= 6.136 cm/s

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two identical bodies with a mass of 2.0 x 104 kg are 2.0 m apart (center to center). what is the gravitational force between them?

Answers

The gravity attraction force between the two is directly related to the product of respective weights and is inversely related to the square of their masses, according to Newton's Inverse Square Law.

A gravitational field is what?

Learn the vocabulary you need to speak with assurance. The region where gravity acts, such as the space surrounding a planet, is known as the gravitational field. Gravity and gravitational force are the same thing. The power that an item has because it is located in a position where gravity could effect it is known as gravitational potential energy.

Exists gravitation, or not?

Furthermore, although the influence of gravity is weaker as objects are moved away, its range is infinite. Sir Isaac Newton was the first to notice this force of attraction, and his discovery became known as Newton's law.

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Why is it important to keep the temperature and the
amount of water the same when testing surface area?

Answers

The temperature and the amount of water need to be kept the same so that the only variable that changes is surface area. If you allow the temperature and/or the amount of water to change too, you will not know which variable is causing the changes that you observe.

A 10cm×10cm×10cm wood block with a density of 750 kg/m3 floats in water. What is the distance from the top of the block to the water if the water is fresh?If it's seawater? Suppose that rho=1030kg/m3.Express your answer to two significant figures and include the appropriate units.

Answers

In fresh water the block will float at Height of 2.5cm above water.

In salt water the block will float at Height of 2.72cm above water.

Density is defined as the mass per unit volume. It is an intensive property, which is mathematically defined as mass divided by volume:

ρ = m/V

In words, the density (ρ) of a substance is the total mass (m) of that substance divided by the total volume (V) occupied by that substance. The standard SI unit is kilograms per cubic meter (kg/m3). The Standard English unit is pounds mass per cubic foot (lbm/ft3). The density (ρ) of a substance is the reciprocal of its specific volume (ν).

ρ = m/V = 1/ρ

In fresh water (density of Ig/cc.), the block will float with [tex]$10-(10 \times 0.75)=2.5 \mathrm{~cm}$[/tex]. above water.

The salt water one is tougher.

Block density is [tex]$750 \frac{kg}{m^3}$[/tex], which equates to [tex]$0.75 \mathrm{~g} / \mathrm{cc}$[/tex].

Block volume [tex]$=\left(10^3\right)=1,000$[/tex]

Its mass is. [tex]$(1,000 \times 0.75)=750$[/tex] grams

It will displace its own mass of water when it floats.

The volume of water displaced. [tex]$=(750 / 1.030)=728.16 \mathrm{cc}$[/tex]

The block area [tex]$=(10 \times 10)=100 \mathrm{~cm}^2$[/tex].

Height out of water [tex]$=10 \mathrm{~cm}-(728.16 / 100)=2.72 \mathrm{~cm}$[/tex]

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± A Superball Collides Inelastically with a Table
As shown in the figure (Figure 1) , a superball with mass m equal to 50 grams is dropped from a height of hi=1.5m . It collides with a table, then bounces up to a height of hf=1.0m . The duration of the collision (the time during which the superball is in contact with the table) is tc=15ms . In this problem, take the positive y direction to be upward, and use g=9.8m/s2 for the magnitude of the acceleration due to gravity. Neglect air resistance.
Part A Find the y component of the momentum, pbefore,y, of the ball immediately before the collision. Express your answer numerically, to two significant figures.
Part B Find the y component of the momentum of the ball immediately after the collision, that is, just as it is leaving the table. Express your answer numerically, to two significant figures.
Part C Find Jy, the y component of the impulse imparted to the ball during the collision. Express your answer numerically, to two significant figures.
Part D Find the y component of the time-averaged force Favg,y, in newtons, that the table exerts on the ball. Express your answer numerically, to two significant figures.
Part E Find Kafter−Kbefore, the change in the kinetic energy of the ball during the collision, in joules. Express your answer numerically, to two significant figures.
Please show your work in detail, I'm posting because I need to know how to get to the answer, I'm studying for an exam.

Answers

Part A

The momentum of the ball right before the collision is given by the equation

$p_{before,y} = mv_{before,y}$

But we know the initial velocity of the ball before the collision is just the velocity due to gravity, which is given by

$v_{before,y} = gt_0$

where $t_0$ is the time taken for the ball to fall from the initial height to the table.

This is given by

$t_0 = \sqrt{\frac{2h_i}{g}}$

Substituting this into the equation for the momentum gives

$p_{before,y} = mg\sqrt{\frac{2h_i}{g}}$

The final answer is

$p_{before,y} = m\sqrt{2gh_i} \approx 88.5 \,\text{kg m/s}$

Part B

The momentum of the ball right after the collision is given by the equation

$p_{after,y} = mv_{after,y}$

But we know the final velocity of the ball after the collision is just the velocity due to gravity, which is given by

$v_{after,y} = gt_f$

where $t_f$ is the time taken for the ball to fall from the final height to the table.

This is given by

$t_f = \sqrt{\frac{2h_f}{g}}$

Substituting this into the equation for the momentum gives

$p_{after,y} = mg\sqrt{\frac{2h_f}{g}}$

The final answer is

$p_{after,y} = m\sqrt{2gh_f} \approx 73.6 \,\text{kg m/s}$

Part C

The impulse imparted to the ball during the collision is given by

$J_y = p_{after,y} - p_{before,y}$

Substituting the values from Parts A and B gives

$J_y = 73.6 \,\text{kg m/s} - 88.5 \,\text{kg m/s} \approx -14.9 \,\text{kg m/s}$

Part D

The average force exerted on the ball during the collision is given by

$F_{avg,y} = \frac{J_y}{t_c}$

Substituting the value from Part C gives

$F_{avg,y} = \frac{-14.9 \,\text{kg m/s}}{15 \,\text{ms}} \approx -0.99 \,\text{N}$

Part E

The change in kinetic energy of the ball during the collision is given by

$K_{after} - K_{before} = \frac{p_{after,y}^2 - p_{before,y}^2}{2m}$

Substituting the values from Parts A and B gives

$K_{after} - K_{before} = \frac{73.6^2 - 88.5^2}{2 \cdot 50} \approx -3.3 \,\text{J}$

What is kinetic energy?

Kinetic energy is the energy of a moving object, equal to the work done to accelerate the object from rest to its current velocity. It is dependent on the object's mass and velocity.

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if you wish to store a large amount of energy in a capacitor bank, would you connect capacitors in series or parallel? explain.

Answers

It implies that as the capacitance value increases, so will the quantity of the energy. Therefore, the capacitors should be connected together in parallel in order to store more power in a capacitor bank.

What are the uses of a capacitor bank?

Capacitors are used in the distribution of electric power to rectify power factor. These banks are required to offset inductive loading caused by components like electric motors & transmission lines, which causes the load to seem to be primarily resistive.

Where are the banks of capacitors?

banks of distribution capacitors. Distribution capacitors are put in place at substations, on the poles, or adjacent to the load. Even though these capacitors units serve the local demand with reactive power, they might not be able to lower feeder & transformer losses.

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suppose the mass of a fully loaded module in which astronauts take off from the moon is 13,800 kg. the thrust of its engines is 28,500 n. (assume that the gravitational acceleration on the moon is 1.67 m/s2.) (a) calculate (in m/s2) its magnitude of acceleration in a vertical takeoff from the moon. (enter a number.)

Answers

The rocket will shoot from the moon at a velocity of 0.39 m/s, in accordance with the question.

What is a massive example?

The mass of matter that makes up every item or body is the simplest way to understand mass. Every that we can see has mass.

F=ma

First Law of Motion (remember this equation)

28500 = 13800 * a

(Kg is the measurement of mass, while N is a measure of force.)

calculate a

In empty space, the velocity would be at a = 2.06 m/s2, but the moon is pulling it down.

We deduct it from acceleration because downward motion is the direction in which the item is traveling.

2.06-1.67 = 0.39

Consequently, the rocket will ascend at 0.39 m/s.

A)Find the net electric flux passing through the surface S1.
B) Find the net electric flux passing through the surface S2.
C) Find the net electric flux passing through the surface S3.
D) Find the net electric flux passing through the surface S4.
E) Find the net electric flux passing through the surface S5.

Answers

gh the surface S1.

B) Find the net electric flux passing through the surface S2.

C) Find the net electric flux passing through the surface S3.

D) Find the net el

Using Gauss Law, the flux through a surface, \phi = charge enclosed inside the surface/ \epsilono. So, for surface S2 net electric flux is 2.25*10^5 Wb.

for surface s2 - phi = (q1 + q2 - q5)/(8.854*10^-12) = (4.6+10 - 8)*10^-6/(8.854*10^-12) = 7.45*10^5 Wbc). flux = (q2+q3 -q6)/(8.854*10^-12) = ( 10 + 1 - 9)*10^-6/(8.854*10^-12) = 2.25*10^5 Wb

d)flux = (q4-q5)/(8.854*10^-12) = (8-8)/(8.854*10^-12) = 0

e) flux = (q1+q2+q3+q4 - q5 - q6)/(8.854*10^-12) = (4.6 + 10 + 1 + 8 - 8 - 9)*10^-6/(8.854*10^-12) = 7.45*10^5 Wb. Gauss's Law is a fundamental principle in physics, particularly in the study of electromagnetism. It states that the total electric flux through a closed surface is equal to the electric charge enclosed within the surface, divided by the permittivity of free space. Mathematically, it can be written as: Φ = ∫ E . dA = Q/ε. Where Φ is the electric flux, E is the electric field, dA is an infinitesimal surface element, Q is the total electric charge enclosed within the surface, and ε is the permittivity of free space.

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6. How long must a 800 N net force act to produce a change in momentum of 400 kg·m/s? The force Fx acting on a 5kg particle varies in time as shown in the fig. below. F(N) 40 t(s) 4 8 12 16 20 a. What is impulse of the force? b. The average force exerted on the particle.

Answers

For part A. The impulse of the force is the area under the force-time graph. The figure you provided is not accessible to me, but if the graph is of a constant force over time, the impulse can be calculated as:

[tex]Impulse = force x time = (40 N) (20 s) = 800 N*s[/tex]

For part B. The average force exerted on the particle is the impulse divided by the time, it can be calculated as:

[tex]Average force = impulse / time = 800 N*s / 20 s = 40 N[/tex]

What is momentum?

Momentum is a concept in physics that describes the tendency of an object to continue moving in the same direction at the same speed. It is a vector quantity, meaning it has both a magnitude and a direction. The momentum of an object is equal to its mass multiplied by its velocity.

In the context of finance, momentum refers to the rate of acceleration of price or volume changes in a security or market. It is often used by investors to identify trends and make investment decisions.

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if the tension on the string is halved and the string is replaced by another with twice the linear density, by what factor will the speed of a wave on the string change?

Answers

The factor by which the speed of a wave on the string change is halved (1/2).

What is a string of mass's tension?

The pull that is designated as tension is in that direction. As a result, the tension will point toward the string or rope and away from the mass. When a mass is hanging, the string pulls it upward, applying an upper force, which causes the tension to be on the upper side.

Tension= T' = 1/2T

Linear density = (m/L) final = 2 (m/L)

Speed of the wave = v => sqrt(T/(m/L)

                            => sqrt(T/2 x 2(m/L) )

                          V final = 1/2sqrt(T/(m/L)

                                => 1/2 times V

What does linear density mean?

Mass per unit length of a strand or along the flow route of a stream of fibres is referred to as linear density.

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a 1.50-kg cannon is mounted on top of a 2.00-kg cart and loaded with a 57.7 gram ball. the cannon, cart, and ball are moving forward with a speed of 1.17 m/s. the cannon is ignited and launches a 57.7 gram ball forward with a speed of 53.8 m/s. determine the post-explosion velocity (in m/s) of the cannon and cart. enter a negative value for a backward velocity and a positive value for an forward velocity.

Answers

the post-explosion velocity (in m/s) of the cannon and cart, is u = -o.9m/s

The displacement that an object or particle experiences with respect to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of velocity magnitude (also known as speed). Alternately, the magnitude of velocity can be expressed in centimeters per second (cm/s).

Let u be the cannon and cart's post-explosion velocities.

The law of conservation of momentum states that

(m₁ + m2)u + m3v = 0

Thus

u = - M3 /m1 + m₂ v =

Consequently, u = -(0.057 / 1.50 + 2.00) 53.8 = 0.876

u = -0.9m/s

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Why do Balmer lines of hydrogen get closer together as you go towards shorter wavelengths?

Answers

Balmer lines of hydrogen get closer together as you go towards shorter wavelengths due to lesser wavelength and high frequency of blue light, the lines get closer together on going bluer.

How do Balmer lines originate?

However, the visible hydrogen lines or Balmer series are brought about by electron transitions within atoms in the second energy level, or first excited state, which is significantly more energetic than the ground level.

As electrons move between atoms or ions, spectral lines are created. Energy in the form of light (or other radiation) is emitted or absorbed depending on how close or far the electrons are from the nucleus of an atom (or of an ion).

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a heat engine operates in a carnot cucl4 between 80 c and 350 c it absorbs 21000 heat per cycle from a hot reservoir. the duration of each cycle is 1s what is the maximum power output of this engine how miuch heat does it expel in eeach cycle

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a heat engine operates in a carnot cucl4 between 80 c and 350 c it absorbs 21000 heat per cycle from a hot reservoir.

Maximum power output of the engine = (21000 J/s) / (350-80) C) = 215.79 W.

What is engine?

An engine is a machine designed to convert one form of energy into mechanical energy. It is most commonly used to convert energy produced from burning fuel into rotational energy used to power a vehicle, machine, or device.


The amount of heat expelled in each cycle = 21000 J - (215.79 W x (350-80) C) = 20,838.21 J

The maximum power output of the Carnot cycle engine is determined by the temperature difference between the hot and cold reservoirs. The power output of the engine is equal to the amount of heat absorbed by the engine (21000 J) divided by the temperature difference (350-80 C).

The amount of heat expelled in each cycle is calculated by subtracting the power output (215.79 W x (350-80) C) from the amount of heat absorbed (21000 J).

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alana drew a diagram to compare the life cycles of low-mass and high-mass stars. a venn diagram with 2 intersecting circles. the left circle is labeled low-mass stars and the right circle is labeled high-mass stars. there is an x in the low-mass stars circle, z in high-mass stars circle and y in the intersecting areas. which labels belong in the areas marked x, y, and z?

Answers

Low mass stars vary in that they have longer life cycles and develop into white dwarfs. Supernova explosions occur in high mass stars, which also have shorter life cycles.

What should be said about a Venn diagram?

Circles are used in a Venn diagram to depict the relationships between individual items or small groups of things. Circles that overlap have certain qualities, but circles that do not overlap do not. Venn diagrams help you to more easily see the relationships and differences between two ideas.

What should be said about a Venn diagram?

Circles are used in a Venn diagram to depict the relationships between individual items or small groups of things. Circles that overlap have something in common, but circles that don't share nothing.

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A longitudinal wave ha a compreion to compreion ditance of 10 m it take the wave of 5 to pa a point what i the wavelength of the longitudinal wave

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The longitudinal wave has a 2 m per second wavelength if it covers a distance of 10 m.

How can you determine a longitudinal wave's wavelength?

By calculating the distance between two identical locations on adjacent waves, the wavelength is always found. When determining the wavelength of the a longitudinal wave, the distance from one compression to another or from one rarefaction to a next is measured.

What does wavelength mean?

A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places subsequent crests in the consecutive cycles. This length is typically defined in wireless systems in meters m, centimeters cm, or millimeters mm.

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if a thin thread is placed between a screen and a bright source of light, a pattern of parallel dark and bright fringes appears on the screen. the phenomenon best explaining the formation of this pattern is:

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If a thin thread is placed between a screen and a bright source of light, a pattern of of parallel light and dark strips appears on the screen. This phenomenon is called the diffraction of light.

When a thin thread comes in the path of light waves, it obstructs the upfront of the light wave causing the change in the phase difference of the wave. Overlapping of these different waves of different phase differences cause the dark and light pattern appearance on the wall.  On the other hand, thin thread also cast a thin shadow due to the obstruction in the path of light. Pattern on the wall depends on the phase difference in the wave-upfront.

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a space shuttle is in orbit about the earth at an altitude where the acceleration due to gravity is 8.70 m/s2. what is the shuttle's speed at this altitude?

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The speed of the space shuttle is in orbit about the earth at an altitude is calculated to be 7.68 × 10³ m/s.

Given that,  

Satellite's centripetal acceleration a = 8.7 m/s²

Mass of the Earth M = 5.98 × 10²⁴ kg

Gravitational constant G = 6.67 × 10⁻¹¹ m³ kg⁻¹ s⁻²

R is radius of satellite's orbit

v be satellite's velocity

The satellite's centripetal acceleration a = v²/R must be equated to gravitational acceleration GM/R²

v²/R = GM/R²

v² = GM/R

R = GM/ v²

v² = GM/ (v²/a)

v = (GM a)^ 1/4

Putting in the values, we have,

v = (6.67 × 10⁻¹¹ × 5.98 × 10²⁴ × 8.7)^ 1/4 = 7.68 × 10³ m/s

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Time Dilation Ranking Task
Five identical quintuplets leave earth when they reach the age of 21, in the year 2121. Each quintuplet goes on a spaceship journey that takes T years, as measured by a clock in each spaceship. During the journey they travel at a constant speed v, as measured on earth, except during the relatively short acceleration phases of their journey.

Part A
Rank these quintuplets on the basis of the year on earth when they return from their journey.
Rank from largest to smallest. To rank items as equivalent, overlap them.

A: T=20years, v=0.4c
B: T= 5years, v=0.2c
C: T=10years, v=0.8c
D: T=10years, v=0.4c
E: T=20years, v=0.8c

Part B
Rank these quintuplets on the basis of their age when they return from their journey.
Rank from largest to smallest. To rank items as equivalent, overlap them.

A: T=20years, v=0.4c
B: T= 5years, v=0.2c
C: T=10years, v=0.8c
D: T=10years, v=0.4c
E: T=20years, v=0.8c

Answers

Ranking these quintuplets on the basis of the year Part A: E > A > C > D > B.

Ranking these quintuplets on the basis of their age when they return from their journey Part B: E > A > C > D > B

What are quintuplets?

A set of five infants called quintuplets is born all at once. A baby who is one of these sets is known as a quintuplet and occasionally goes by the nickname "quint."

Even though quintuplets and other higher-order multiple births, also known as super twins, are uncommon, there has been an increase in these pregnancies due to the increased use of fertility medications and assisted reproductive technologies.

Using on the time dilation formula we can rank the quintuplets. if [tex]$T^{\prime}$[/tex] is the time measured by Earth and [tex]$T$[/tex] is the time measured on space ship, then

[tex]$ T^{\prime}=\frac{T}{\sqrt{1-\frac{v^2}{c^2}}} $Here, $v$ is the speed of the journey by the earth and $c$ is the speed of the light.Part A:$A: T=20$ years, $v=0.4 c$$$\begin{aligned}T_A^{\prime} & =\frac{T}{\sqrt{1-\frac{v^2}{c^2}}} \\& =\frac{20 \text { years }}{\sqrt{1-\frac{(0.4 c)^2}{c^2}}} \\& =21.82 \text { years }\end{aligned}$$[/tex][tex]$$B: $T=5$ years,$v=0.2 c$$$\begin{aligned}T_B^{\prime} & =\frac{T}{\sqrt{1-\frac{v^2}{c^2}}} \\& =\frac{5 \text { years }}{\sqrt{1-\frac{(0.2 c)^2}{c^2}}} \\& =5.10 \text { years }\end{aligned}$$$C: T=10$ years, $v=0.8 c$$$\begin{aligned}T_C^{\prime} & =\frac{T}{\sqrt{1-\frac{v^2}{c^2}}} \\& =\frac{10 \text { years }}{\sqrt{1-\frac{(0.8 c)^2}{c^2}}} \\& =16.67 \text { years }\end{aligned}$$[/tex]

[tex]$\mathrm{D}: T=10$ years, $v=0.4 \mathrm{c}$$$\begin{aligned}T_C^{\prime} & =\frac{T}{\sqrt{1-\frac{v^2}{c^2}}} \\& =\frac{10 \text { years }}{\sqrt{1-\frac{(0.4 c)^2}{c^2}}} \\& =10.91 \text { years }\end{aligned}$$$\mathrm{E}: T=20$ years, $v=0.8 \mathrm{c}$$$\begin{aligned}T_A^{\prime} & =\frac{T}{\sqrt{1-\frac{v^2}{c^2}}} \\& =\frac{20 \text { years }}{\sqrt{1-\frac{(0.8 c)^2}{c^2}}} \\& =33.33 \text { years }\end{aligned}$$Hence, the rank from largest to smallest is$$E > A > C > D > B[/tex]

Part B: A 11 the five quintuplets have same age when they leave the earth. Hence, the order from largest to smallest on the basis of their age is al so same as the part A.

                                              E > A > C > D > B

Thus, PART A:  20 yrs ,0.8 c then 20yrs, 0.4c then 10yrs, 0.8c then 10 yrs, 0.4c then 5yrs, 0.2c.

PART B: 20yrs=20yrs, 10yrs=10yrs, 5yrs

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At which sporting event would you most likely see balls traveling at over 180 mph?

Answers

The sporting event at which you would most likely see balls traveling at over 180 mph would be a Formula One race.

What is Formula One?

Formula One, also known as F1, is the highest class of single-seater auto racing sanctioned by the Fédération Internationale de l'Automobile (FIA). Races take place on purpose-built circuits, and they feature open-wheel, open-cockpit cars. These cars are purpose-built, with the sole purpose of racing in the Formula One world championship. The cars are designed with aerodynamics in mind, featuring wings, diffusers and aero devices to help them achieve maximum downforce and speed. Formula One drivers need to be in peak physical condition, as the cars are very demanding to drive. F1 is considered the pinnacle of motorsport, with some of the world's best drivers competing in it.

Formula One racing is an international auto racing sport where cars race around a track at incredibly high speeds. These cars can reach speeds of around 200 mph, and the balls that are used to help the cars navigate the track (such as the tires) can reach speeds of over 180 mph.

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