What is the theoretical yield of PI3 from the reaction of 27.0 g of P and 68.0 g of I2?
2P(s) + 3I2(s) → 2PI3(s)

Answer:

low density

Explanation:

Because hydrogen make a natural choice For one of it The 1st practical use

Hydrogen gas has lower density than air. This is why it is used to fill balloons.

Hydrogen is the lightest element found in nature. It has a density of 0.08988 g/L under normal conditions. This leads to hydrogen gas being lighter than any other gas in similar volume. Thus balloons filled with hydrogen gas rise much better than balloons filled with other gases like helium.

However, hydrogen is far less commonly used to fill balloons. The reason being that hydrogen is a highly flammable gas. Whereas gasses like helium which are noble gasses are much safer to use.

To learn more about Density,

https://brainly.com/question/1354972

$\leadsto\sf\textbf\:pH\:\:=\:-\log[H^+]$

$\leadsto\sf\textbf\:[H^+]\:\:=\:10^{-pH}$

For the buffer to have a pH of 3.5, we want the concentration of H+ ions to be $\sf\textbf\;3.16\:x\:10^-4:\:M.$

Using the Henderson-Hasselbalch equation:

$\leadsto\sf\textbf\:pH\:\:=\:pKa\:+\:\log\frac{[A^-]}{[HA]}$

$\leadsto\sf\textbf\:3.5\:\:=\:pKa\:+\:\log\frac{[A^-]}{[HA]}$

$\leadsto\sf\textbf\:log\frac{[A^-]}{[HA]}\:\:=\:3.5\:-\:pKa$

$\leadsto\sf\textbf\:\frac{[A^-]}{[HA]}\:\:=\: 10^{3.5-pKa}$

Comparing the pKa values of formic acid and acetic acid, we see that formic acid has a lower pKa value, which means it is a stronger acid than acetic acid. Therefore, formic acid is a better choice for the buffer, as it will donate more H+ ions to the solution, leading to a more stable pH.

NaOH is added to the buffer to act as a base, which will react with any excess acid that is added to the solution. This prevents the pH from dropping too low and becoming too acidic. The NaOH reacts with the H+ ions to form water, effectively removing excess H+ ions from the solution.

[tex]\huge{\colorbox{black}{\textcolor{lime}{\textsf{\textbf{I\:hope\:this\:helps\:!}}}}}[/tex]

[tex]\begin{align}\colorbox{black}{\textcolor{white}{\underline{\underline{\sf{Please\: mark\: as\: brillinest !}}}}}\end{align}[/tex]

[tex]\textcolor{blue}{\small\textit{If you have any further questions, feel free to ask!}}[/tex]

[tex]{\bigstar{\underline{\boxed{\sf{\textbf{\color{red}{Sumit\:Roy}}}}}}}\\[/tex]

The molar heat of the solution of sulfuric acid is 21.4 kJ/mol, rounded to 1 decimal place.

let's calculate the heat absorbed by the water when dissolving CaCl2:

n = m/M = 0.9638 g / 110.98 g/mol = 0.00868 mol (moles of CaCl2 dissolved)

q1 = nΔH = (0.00868 mol)(-83 kJ/mol) = -0.722 kJ (heat absorbed by water)

Next, let's calculate the heat released by the sulfuric acid:

n = 0.0978 mol (moles of H2SO4 added)

ΔT = 5.0 oC (temperature change of water)

m = 100 g (mass of water)

q2 = -mcΔT = -(100 g)(4.184 J/g oC)(5.0 oC) = -2092 J = -2.092 kJ (heat released by sulfuric acid)

Now, we can set these two values equal to each other and solve for the calibration factor:

q1 = q2

-0.722 kJ = -2.092 kJ

q = 1.370 kJ (total heat exchanged)

c = q/ΔT = (1.370 kJ)/(1.6 oC) = 0.856 kJ/oC (calibration factor)

Finally, we can calculate the molar heat of the solution of sulfuric acid:

ΔH = -q/n = -(-2.092 kJ)/0.0978 mol = 21.4 kJ/mol (molar heat of solution of sulfuric acid)

Therefore, the molar heat of the solution of sulfuric acid is 21.4 kJ/mol, rounded to 1 decimal place.

learn more about calorimeters here

https://brainly.com/question/24167789

#SPJ1

Therefore, the mass of 5.34 mol of vanadium is approximately 271.758 grams.

The heaviest element currently found in the periodic table, Oganesson, was named after the Russian physicist Yuri Oganessian (SN: 1/21/17, p. 16). It has a massive atomic mass of roughly 300. The synthetic element has only ever been produced in a small number of atoms, each of which lived for less than a millisecond.

The molar mass of vanadium (V) is approximately 50.94 g/mol.

To determine the mass of 5.34 mol of vanadium, we can use the following calculation:

mass = number of moles x molar mass

mass = 5.34 mol x 50.94 g/mol

mass = 271.758 g

To know more about vanadium visit:-

brainly.com/question/14247240

#SPJ1

Where the above conditions are given, the dissociation degrees of KNO3, CaCl2, and Al2(SO4)3 are 0.6, 0.75, and 1.6, respectively.

The dissociation degree, α, of an electrolyte can be calculated using the formula:

α = (I - 1) / (n - 1)

where I is the ionic strength of the electrolyte and n is the number of ions produced per formula unit of the electrolyte when it dissociates.

Using the provided values of ionic strength (I), we can calculate the dissociation degree of each electrolyte as follows:

For KNO3:

α = (I - 1) / (n - 1)

α = (1.6 - 1) / (2 - 1)

α = 0.6

For CaCl2:

α = (I - 1) / (n - 1)

α = (2.5 - 1) / (3 - 1)

α = 0.75

For Al2(SO4)3:

α = (I - 1) / (n - 1)

α = (4.2 - 1) / (3 - 1)

α = 1.6

Therefore, the dissociation degrees of KNO3, CaCl2, and Al2(SO4)3 are 0.6, 0.75, and 1.6, respectively.

Learn more about dissociation degree at:

https://brainly.com/question/14945172

#SPJ1

52.1% of the aspirin in this process is yielded.

The loss of the aspirin in the glassware is the reason why the yield percentage can be less than 100%. Unreacted reactants, which would have an impact on the amount of product (aspirin) created, are still another potential source for a decrease in yield.

79.8 g C₇H₆O₃ x (1 mol C₇H₆O₃ / 122.12 g C₇H₆O₃) = 0.653 mol C₇H₆O₃

The balanced equation also tells us that 1 mole of C₇H₆O₃ produces 1 mole of C₉H₈O₄. So, the theoretical yield of C₉H₈O₄ is:

0.653 mol C₇H₆O₃ x (1 mol C₉H₈O₄ / 1 mol C₇H₆O₃) = 0.653 mol C₉H₈O₄

Now, we can use the molar mass of C₉H₈O₄ to convert moles to grams:

0.653 mol C₉H₈O₄ x (180.16 g C₉H₈O₄ / 1 mol C₉H₈O₄) = 117.6 g C₉H₈O₄ (theoretical yield)

The actual yield is given as 61.3 g.

Now we can calculate the percent yield:

Percent yield = (actual yield / theoretical yield) x 100%

Percent yield = (61.3 g / 117.6 g) x 100%

Percent yield = 52.1%

To know more about aspirin visit:-

https://brainly.com/question/13494090

#SPJ1

answer:when an herbivore eats meat and a carnivore eats the herbivore energy from the eatin meat is passed indirectly to the carnivore.

The solution's [H3O+] is 1.27 x 10^(-2) M.

The acidity or basicity of an aqueous solution is determined by its pH value. In terms of the concentration of H3O+ ions in the solution, it is the negative logarithm (base 10) of the hydronium ion concentration. The pH scale runs from 0 to 14, with a pH of 7 being regarded as neutral, anything below that as acidic, and anything above that as basic (or alkaline).

The negative logarithm of the hydronium ion concentration, or [H3O+], is used to calculate the pH of a solution. pH and [H3O+] are mathematically related in the following way:

pH = -log[H3O+].

This equation can be rearranged to give

 [H3O+] = 10^ (-pH)

Using the pH value of 1.79 as a replacement, we obtain [H3O+] = 10^ (-1.79)

[H3O+] = 1.27 x 10^(-2) M

As a result, the solution's [H3O+] is 1.27 x 10^ (-2) M.

To know more about pH, visit:

brainly.com/question/491373

#SPJ1

The term that is described by the equation H2O(l) + heat  H2O(g) is Evaporating.

The equation H2O(l) + heat -> H2O(g) represents a physical process in which water in its liquid state (H2O(l)) absorbs heat and turns into its gaseous state (H2O(g)). This process is called "evaporation". Evaporation is a common process in nature where water from oceans, rivers, lakes, and other bodies of water turns into water vapor due to the heat energy from the sun. It is also a widely used process in industries to separate liquids from solutions and to concentrate solutions.

During evaporation, the heat energy absorbed by the liquid water overcomes the intermolecular forces holding the water molecules together, causing them to break apart and escape as water vapor. Thus, the equation H2O(l) + heat -> H2O(g) accurately describes the process of evaporation.

Learn more about Evaporating from

https://brainly.com/question/9339710

#SPJ1

Which of the following is described by the equation H20(1) + heat → H2O(g)?

A. Freezing

B. Condensing

C. Evaporating

D. Melting -

Answer:

A)

i) The chemical reaction for the titration of HCl with NaOH is:

HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l)

ii) The initial pH of the solution can be calculated using the following formula:

pH = -log[H+]

Since HCl is a strong acid and is completely dissociated in water, the concentration of H+ ions in the solution is equal to the concentration of HCl. Therefore, the initial pH of the solution is:

pH = -log(0.100) = 1.00

iii)

a) Before equivalence point (after adding 0.00 mL of titrant):

Before the addition of any NaOH solution, the pH of the HCl solution is the same as the initial pH calculated in (ii), which is 1.00.

b) At the equivalence point (after adding 25.00 mL of titrant):

At the equivalence point, the moles of NaOH added is equal to the moles of HCl initially present. Therefore, the number of moles of NaOH is:

moles of NaOH = concentration of NaOH x volume of NaOH

moles of NaOH = 0.100 x 0.025 = 0.0025 mol

Since HCl and NaOH react in a 1:1 ratio, the number of moles of HCl initially present is also 0.0025 mol. The total volume of the solution after the addition of 25.00 mL of NaOH is:

total volume = volume of HCl + volume of NaOH

total volume = 0.025 + 0.025 = 0.050 L

Therefore, the concentration of HCl at the equivalence point is:

concentration of HCl = moles of HCl / total volume

concentration of HCl = 0.0025 / 0.050

concentration of HCl = 0.050 M

Since HCl is a strong acid, it is completely dissociated in water. Therefore, the concentration of H+ ions at the equivalence point is 0.050 M. Using the formula for pH, the pH at the equivalence point is:

pH = -log(0.050) = 1.30

c) After the equivalence point (after adding 26.00 mL of titrant):

After the equivalence point, there is excess NaOH in the solution. The excess NaOH will react with water to produce OH- ions. The concentration of OH- ions can be calculated using the following formula:

moles of excess NaOH = concentration of NaOH x volume of NaOH added - moles of HCl initially present

moles of excess NaOH = 0.100 x (0.026 - 0.025) - 0.0025

moles of excess NaOH = 0.00075 mol

Since NaOH and water react in a 1:1 ratio to produce OH- ions, the concentration of OH- ions in the solution is:

concentration of OH- = moles of excess NaOH / total volume

concentration of OH- = 0.00075 / 0.051

concentration of OH- = 0.0147 M

Using the formula for pH, the pH after the equivalence point is:

pH = 14 - (-log[OH-]) = 11.84

Explanation:

The answer is D) 5 × 10⁻³.

The equilibrium constant expression for the reaction is given by:

[tex]K = [H_3O^+]^2 [C_2O_4^{-2}] / [H_2C_2O_4][/tex]

Since oxalic acid is a diprotic acid, its dissociation occurs in two steps, and the given values of Kx and K2 correspond to the dissociation constants of the first and second steps, respectively. The overall dissociation constant, K, can be expressed in terms of Kx and K2 as:

K = Kx × K2

Substituting the given values of Kx and K2:

K = 5 × 10⁻⁵ × 5 × 10⁻¹⁰

K = 2.5 × 10⁻¹⁴

Comparing the calculated value with the options given:

A) 5 × 10² - Not equal

B) 5 × 10¹⁰ - Not equal

C) 25 × 10⁻¹ - Not equal

D) 5 × 10⁻³ - Equal

Therefore, the answer is D) 5 × 10⁻³

learn more about oxalic acid here

https://brainly.com/question/14989723

#SPJ1

Therefore, an indicator with a pKa value close to 4.8, such as phenolphthalein (pKa = 9.4) or methyl orange (pKa = 3.7), can be used.

A base causes a phenolphthalein solution to turn pink. This is due to the production of ions that result from the reaction between the hydroxide ions and the existing acidic group. These ions give the mixture its colour. This is how phenolphthalein solution functions in titrations as an acid-base indicator.

a) Titrating 25 mL of 0.50 M HI with 0.10 M KOH:

HI(aq) + KOH(aq) -> KI(aq) + water(l)

The balanced equation shows that HI is a strong acid, and KOH is a strong base. Therefore, the pH at the equivalence point will be 7.00 (neutral).

b) Titrating 25 mL of 0.10 M  with 0.10 M HCl:

The balanced equation shows that it is a weak base, and HCl is a strong acid. Therefore, the pH at the equivalence point will be acidic, less than 7.00.

To choose an appropriate indicator for this titration, we need to find the pKa value of . The pKa of C is approximately 10.6. Therefore, an indicator with a pKa value close to 10.6, such as methyl red (pKa = 5.0) or bromocresol green (pKa = 4.7), can be used.

c) Titrating 25 mL of 0.10 M acetic acid with 0.10 M HCl:

The balanced equation shows that acetic acidis a weak acid, and HCl is a strong acid. Therefore, the pH at the equivalence point will be acidic, less than 7.00.

To choose an appropriate indicator for this titration, we need to find the pKa value of acetic acid . The pKa of acetic acid is approximately 4.8.

To know more about phenolphthalein visit:-

brainly.com/question/14804470

#SPJ1

Answer:

Explanation:

Conversely, the largest (in terms of mass) fundamental particle we know of is a particle called a top quark, measuring a whopping 172.5 billion electron volts, according to Lincoln.

The energy is conserved throughout the motion of the object, and it is never lost or gained, only converted from one form to another.

In the given diagram, the potential energy (PE) at point A is at its maximum, which is equal to 300 J, as it is located at the highest point. At this point, the kinetic energy (KE) is zero since the object is at rest.

At point B, the height of the object is 1m, and its mass is 1kg.

Therefore, the potential energy at point B can be calculated using the formula PE = mgh, where m is the mass of the object, g is the acceleration due to gravity, and h is the height of the object. Thus, PE at point B = (1 kg) x (9.8 m/s^2) x (1 m) = 9.8 J.

At point C, the object has reached its maximum velocity, and hence, its kinetic energy is at its maximum, which can be calculated using the formula KE = (1/2)mv^2, where m is the mass of the object, and v is the velocity of the object.

Since the mass of the object is 1kg, and its maximum velocity is reached at point C, the kinetic energy at point D is KE = (1/2)(1 kg)(vmax)^2, where vmax is the maximum velocity.

Therefore, the value of kinetic energy at point D is 1/2 of the maximum kinetic energy, which is equal to (1/2)(1 kg)(vmax)^2.

Energy is conserved in the diagram since the total energy at any point in time is equal to the sum of the kinetic energy and potential energy of the object.

At point A, the total energy is 300 J (PE = 300 J and KE = 0 J).

At point B, the total energy is 150 J (PE = 9.8 J and KE = 140.2 J).

At point C, the total energy is also 150 J (PE = 0 J and KE = 150 J).

Finally, at point D, the total energy is again 300 J (PE = 0 J and KE = (1/2)(1 kg)(vmax)^2).

Therefore, the energy is conserved throughout the motion of the object, and it is never lost or gained, only converted from one form to another.

Read more about potential energy here:

https://brainly.com/question/1242059

#SPJ1

2HBr + Mg(OH) ₂→ MgBr₂ + H₂O         (DR) - Double replacement

PbBr₂+2HCl→ 2HBr+PbCl₂                   (DR) - Double replacement

A double replacement reaction is a type of chemical reaction where two compounds react and exchange their cations (positively charged ions) and anions (negatively charged ions) to form two new compounds.

The general form of a double replacement reaction is:

AB + CD → AD + CB

where A, B, C, and D are elements or compounds.

In this reaction, the cation of compound AB replaces the cation of compound CD, and the anion of compound CD replaces the anion of compound AB, resulting in the formation of two new compounds, AD and CB.

Double replacement reactions occur when the products formed are insoluble in water, which causes them to precipitate out of solution. This type of reaction is also known as a precipitation reaction.

An example of a double replacement reaction is the reaction between sodium chloride (NaCl) and silver nitrate (AgNO₃) to form sodium nitrate (NaNO₃) and silver chloride (AgCl):

NaCl + AgNO₃ → NaNO₃ + AgCl

Learn more about reaction here:

https://brainly.com/question/28984750

#SPJ1

1.25 moles of [tex]CO_{2}[/tex] are required to react with 2.50 moles of [tex]NH_{3}[/tex].

What are the moles?

Moles are a unit of measurement used in chemistry to express the amount of a substance. One mole of a substance is equal to its molecular weight expressed in grams. In other words, one mole of a substance contains 6.022 x [tex]10^{23}[/tex] individual particles (atoms, molecules, or ions). The number of moles of a substance can be calculated by dividing its mass in grams by its molecular weight or by using the ideal gas law PV=nRT, where n is the number of moles.

The balanced chemical equation is:

[tex]2NH_{3}[/tex](g) + [tex]CO_{2}[/tex](g) → [tex](NH_{2})_{2}CO[/tex](aq) + [tex]H_{2}O[/tex](l)

From the balanced equation, we can see that 1 mole of [tex]CO_{2}[/tex] reacts with 2 moles of [tex]NH_{3}[/tex].

Therefore, to determine the moles of [tex]CO_{2}[/tex] required to react with 2.50 moles of [tex]NH_{3}[/tex], we need to use the mole ratio from the balanced equation:

2 [tex]NH_{3}[/tex] : 1 [tex]CO_{2}[/tex]

2.50 moles [tex]NH_{3}[/tex] * (1 mole [tex]CO_{2}[/tex] / 2 moles [tex]NH_{3}[/tex]) = 1.25 moles [tex]CO_{2}[/tex]

Therefore, 1.25 moles of [tex]CO_{2}[/tex] are required to react with 2.50 moles of [tex]NH_{3}[/tex].

What is molecular weight ?

Molecular weight, also known as molar mass, is the mass of one mole of a substance. It is expressed in units of grams per mole (g/mol). The molecular weight of a compound is determined by adding up the atomic weights of all the atoms in the molecule.

What is substance?

In chemistry, a substance is a form of matter that has constant chemical composition and characteristic properties. It may be an element or a compound made up of two or more elements chemically combined in a fixed proportion. Examples of substances include pure water, carbon dioxide gas, and sodium chloride (table salt).

To know more about moles, visit:

https://brainly.com/question/13623076

#SPJ1

Elected government leaders should have the power to address the issue of a new weapon that can be produced by anybody using materials acquired online. Military leaders can offer guidance, while historians can offer background.

You can initially complain about this to the officer immediately above you. You may also submit a statutory complaint to the Indian government. In this regard, you must have strong evidence, as it is illegal to make untrue accusations against a senior officer.

After India gained independence from Great Britain, Kodandera Madappa Cariappa, also known by his nick name Kipper, served in the Indian military. He was the first chief of staff of the Indian army.

To know more about materials visit:-

https://brainly.com/question/28646672

#SPJ1

Answer:

a

Explanation:

equation 'a' has the same number of  'c's  and 'h' s  and 'o's  on both sides of the equation

B. The movement of basketball players on a court of the following is an example of quantization

The process of translating continuously infinite values to a more manageable collection of discontinuous finite values is known as quantization. It involves estimating real-world values with a digital representation that places restrictions on a value's precision and range in the context of simulation and embedded computing.

As a general guideline, quantize to the note you've played that is the shortest; for example, if the phrase contains both eighth and quarter notes, use eighth note resolution. Keep in mind that many rhythms may really employ triplets; if things aren't working out, you may try utilising a triplet resolution.

learn more about quantization

https://brainly.com/question/24256516

#SPJ1

a) No - mixing aqueous NaOH and aqueous HCl will not produce a buffer solution.

Aqueous is a term used to refer to a solution in which the solvent is water. Water is an excellent solvent for many substances, including salts, sugars, acids, and bases. Aqueous solutions are ubiquitous in nature and are essential for the health and sustenance of all living things. Aqueous solutions are also commonly used in scientific experiments, in the manufacture of pharmaceuticals, and in the production of household and industrial products.

b) Yes - mixing aqueous CH₃COONa and aqueous NaOH will produce a buffer solution.
c) Yes - mixing aqueous CH₃COOH and aqueous CH₃COONa will produce a buffer solution.
d) No - mixing aqueous CH₃COOH and aqueous NaOH will not produce a buffer solution.
e) No - mixing aqueous HCl and aqueous NH₃ will not produce a buffer solution.

To learn more about aqueous
https://brainly.com/question/19587902
#SPJ1

Answer:

10

Explanation:

got it right on the redt

Three moles of Manganese(II) oxide were produced in the interaction between five moles of Manganese.

Similarly, 2 moles of iron (III) oxide are produced when 4 moles of iron atoms react with 3 moles of oxygen molecules. You can use these mole ratios as conversion factors. Many calculations can be performed using these mole ratio conversion factors.

Thus, the moles of oxygen consumed by 7 moles of Manganese is:

2 moles Manganese = 1 mole Oxygen

7 moles Manganese = 3.5 moles Oxygen

The available moles of Oxygen = 5 mol.

The remaining moles of Oxygen = 5-3.5 moles

1.5 moles of oxygen remain in the mixture.

The reaction of 5 moles Manganese requires 2.5 moles of Oxygen, whereas the available moles of oxygen is 1.5 moles.Thus, the limiting reagent is oxygen.

The moles of Manganese(II) oxide formed with the reaction of 5 moles Manganese and 1.5 moles Oxygen

1 mole Oxygen = 2 moles Manganese(II) oxide

1.5 moles Oxygen = 2 * 1.5 moles Manganese(II) oxide

1.5 moles Oxygen = 3 moles Manganese(II) oxide

Thus, the moles of Manganese(II) oxide formed with the reaction of 5 moles of Manganese with the available oxygen is 3 moles.

To know more about Manganese visit:-

https://brainly.com/question/29743410

#SPJ1

The bond length between C and O is 1.129 × 10⁻¹⁰ m, while the rotational constant B is 1.1481 ×  10⁻²² J.

Only transitions between consecutive rotational levels are permitted under the selection conditions, which stipulate that the molecule must have a permanent dipole moment (J=J1). Molecules like HF and HCl have pure rotational spectra because of the requirement for a dipole, but molecules like H2 and N2 are not rotationally active.

EJ = BJ(J+1)

ΔE = B(J+1) - BJ = B

B = ΔE = 3.84235 cm⁻¹ = 1.1481 × 10⁻²² J

μ = m1m2/(m1+m2)

B = h/(8π²cμ)

μ = m1m2/(m1+m2) = 15.999 × 12.011/(15.999 + 12.011) amu

= 6.6560 amu

B = h/(8π²cμ) = 1.1481 × 10⁻²² J

6.6560 amu = 1.66054 × 10⁻²⁷ kg/amu

h = 6.62607 × 10^⁻³⁴ J s

c = 2.99792 × 10⁸ m/s

B = h/(8π²cμ) = 1.1481 × 10⁻²² J

r = (h/(8π²cBμ))² = 1.129 × 10⁻¹⁰ m

To know more about bond visit:-

https://brainly.com/question/10777799

#SPJ1

Under normal atmospheric pressure, it boils.

The freezing point of pure water falls at 32 on this scale (and the boiling point at 212). Because Anders Celsius DID use water as the foundation for his scale, the values for these phase transition points (0 and 100 degrees) on the Celsius scale are more practical.

Technically, pipes can freeze at 32 degrees because that is the temperature at which water begins to freeze. Yet, it's not quite that easy. At 32 degrees or lower, pipes can freeze, but it takes a sustained amount of time for this to happen.

To know m ore about pressure visit:-

https://brainly.com/question/14273070

#SPJ1

Fahrenheit 32 = Water freezes

Fahrenheit 212 = Water boils

Gas law: Combined law, P1 value: 1.82 atm, P2 value: 2.35 atm, T1 value: 293 K, T2 value: 380 K, Kelvin temperature when pressure is increased: 380 K.

The combined gas law is a gas law that combines Boyle's law, Charles's law, and Gay-Lussac's law into one equation. It relates the pressure, volume, and temperature of a fixed amount of gas.

To solve this problem, we will use the combined gas law:

(P1 * V1)/T1 = (P2 * V2)/T2

where P1 is the initial pressure, V1 is the initial volume (constant), T1 is the initial temperature, P2 is the final pressure, V2 is the final volume (constant), and T2 is the final temperature (what we need to find).

The value for V1 and V2 are constant and are not given in the problem statement, but we can assume they are the same since the amount of gas and volume are constant.

Therefore, we can simplify the equation as:

P1/T1 = P2/T2

To find the value of T2, we can rearrange the equation as:

T2 = (P2 * T1)/P1

Now, let's plug in the given values:

P1 = 1.82 atm

T1 = 293 K

P2 = 2.35 atm

T2 = (2.35 * 293)/1.82

T2 = 380 K

Therefore, the gas in the tire will have a temperature of 380 K when the pressure is increased to 2.35 atm.

Learn more about gas here:

https://brainly.com/question/3637358

#SPJ1

The pressure in the can would be 3.27 atm if it were heated to 1155 °C. Note that this is significantly higher than the initial pressure of 755 mmHg at 25 °C, which is why aerosol cans should never be incinerated.

According to the ideal gas law, PV=nRT, where P is pressure, V is volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.

Assuming the volume of the can remains constant, we can rearrange the equation to solve for the final pressure:

P2 = (nRT2)/V

To solve for P2, we need to find n (the number of moles of gas). We can use the ideal gas law to do this:

PV=nRT

Rearranging the equation to solve for n:

n = PV/RT

We can use the given conditions to find the initial number of moles of gas:

n1 = (755 mmHg) * (1 atm / 760 mmHg) * (V / RT1)

where V is the volume of the can, and RT1 is the gas constant (0.0821 L·atm/mol·K) times the initial temperature in Kelvin (25 + 273.15 = 298.15 K).

Now we can find the final pressure:

P2 = (n1 * R * T2) / V

where T2 is the final temperature in Kelvin (1155 + 273.15 = 1428.15 K).

Substituting the values:

n1 = (755 mmHg) * (1 atm / 760 mmHg) * (V / RT1) = (755/760) * (V / 0.0821 / 298.15) = 0.0323 V

P2 = (n1 * R * T2) / V = (0.0323 V * 0.0821 L·atm/mol·K * 1428.15 K) / V = 3.27 atm

To know more about pressure visit:-

brainly.com/question/26416088

#SPJ1

The moles of Ba3(PO4)2 precipitated is 0.00332 moles. To calculate the moles of Ba3(PO4)2 precipitated, we need to first calculate the mass of Ba3(PO4)2 formed.

Mass of Ba3(PO4)2 = Mass of filter paper and Ba3(PO4)2 – Mass of filter paper

= 5 g – 3 g

= 2 g

Now, we need to calculate the moles of Ba3(PO4)2 formed using its molar mass.

Molar mass of Ba3(PO4)2 = 601.9 g/mol

Moles of Ba3(PO4)2 = Mass of Ba3(PO4)2 / Molar mass of Ba3(PO4)2

= 2 g / 601.9 g/mol

= 0.00332 moles

Therefore, the moles of Ba3(PO4)2 precipitated is 0.00332 moles.

To know more about Molar mass, visit:

https://brainly.com/question/22997914

#SPJ1

It is anticipated that the average world temperature would rise by 1.5 degrees Celsius (2.7 degrees Fahrenheit) by 2050 and by 2-4 degrees Celsius by 2100. (3.6-7.2 degrees Fahrenheit).

At the end of the century, the population and economic development of the world were used to model a variety of greenhouse gas emission scenarios by Harvard University's Lucas Zeppetello and his colleagues. They discovered that by 2100, the average global temperature would increase by 2.1°C to 4.3°C.

Because of the carbon dioxide emissions caused by human usage of fossil fuels, the temperature is predicted to rise by 2 to 6 degrees Celsius by the year 2100.

To know more about temperature visit:-

https://brainly.com/question/23411503

#SPJ1