What is the value of h in the figure below? In this diagram, ABAD ~ ACBD.
Д.
С
0
20
А. 80
В. 16
ОО ооо
С. 60
D. 5
Е. 8
о
Е.

Answer:

The postage per ounce would be of $2.02.

Step-by-step explanation:

Exponential model:

The postage, in t years after 1963, follows the following format:

[tex]P(t) = P(0)(1+r)^t[/tex]

In which P(0) is the initial value and r is the growth rate, as a decimal.

In 1963, postage was 5 cents per ounce.

This means that [tex]P(0) = 5[/tex]

So

[tex]P(t) = P(0)(1+r)^t[/tex]

[tex]P(t) = 5(1+r)^t[/tex]

In 1981, postage was 18 cents per ounce.

This means that [tex]P(1981 - 1963) = P(18) = 18[/tex]. We use this to find r. So

[tex]P(t) = 5(1+r)^t[/tex]

[tex]18 = 5(1+r)^{18}[/tex]

[tex](1+r)^{18} = \frac{18}{5}[/tex]

[tex]\sqrt[18]{(1+r)^{18}} = \sqrt[18]{3.6}[/tex]

[tex]1 + r = (3.6)^{\frac{1}{18}}[/tex]

[tex]1 + r = 1.0738[/tex]

So

[tex]P(t) = 5(1.0738)^t[/tex]

If the trend had continued through to 2015, what would the postage per ounce be?

2015 - 1963 = 52, so this is P(52).

[tex]P(52) = 5(1.0738)^{52} = 202[/tex]

202 cents, so $2.02.

If the confidence level will increase, the margin of error will also increases.

The margin of error is defined a range of values below and above the sample statistic in a confidence interval.

The confidence interval is a way to show what is uncertainty is with a certain statistic.

According to the given question

Environmentalist estimating true mean weight or all cars.

For the true mean weights of 2.8 to 3.4 tons the confidence level is 90%.

Since, the confidence level increases, the critical value increases and hence the margin of error increases.

Therefore, if the confidence level will increase, the margin of error will also increases.

Find out more information about confidence interval and margin error here:

https://brainly.com/question/15079850

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Answer: 24 ft I think

Step-by-step explanation:

Answer:

The volume is maximum when the height is 3 cm.

Step-by-step explanation:

let the side of the removed potion is x.

length of the box = 18 - 2 x

width of the box = 18 - 2 x

height = x

Volume of box

V = Length x width x height

[tex]V = (18 - 2 x)^2 \times x\\\\V = x(324 + 4x^2 - 72 x)\\\\V = 4 x^3 - 72 x^2 + 324 x \\\\\frac{dV}{dx} = 12 x^2 - 144 x + 324 \\\\So,\\\\ \frac{dV}{dx} =0\\\\x^2 - 12 x + 27 = 0 \\\\x^2 -9 x - 3 x + 27 =0\\\\x (x - 9) - 3 (x -9) = 0\\\\x = 3, 9[/tex]

Now

[tex]\frac{d^2V}{dx^2}=24 x - 144 \\\\Put x = 3 \\\\\frac{d^2V}{dx^2}=24\times 3 - 144 = - 72\\\\Put x = 9\\\\\frac{d^2V}{dx^2}=24\times 9 - 144 = 72\\[/tex]

So, the volume is maximum when x = 3 .

Answer: 0.2

Step-by-step explanation: 20/100=1/5

and 1/5 equals 1 divided by five so it is 0.2

Answer:

20

Step-by-step explanation:

4 + 2 + 5 + 4 + 0 + 1 + 1 + 3 = 20

Answer:

a) 11670-0.09%

b)11670-1.8%=11459

Step-by-step explanation:

Answer:

(1,7), (2,2), (3,5) (4,8)

(2,6), (6,5), (3,2) (5,3)

(4,3), (3,3), (2,3) (1,3)

Step-by-step explanation:

those represent functions b/c the domain of the relation is not written twice

Hope that'll help!

Step-by-step explanation:

The Answer Is Provided Below ➳

(2²)² = 2⁴/2⁴ = 2⁰ × 2⁰ = 2⁰/2⁰

Solution :

From the given equation :

E[ E (X|Y) ] = E (X)

a). Then,

   E[ E [ X|Y,Z] | Z] = E [ X|Z ]

     ----  True

   E [ E [ X|Y ] | Z ] = E [ X|Z ]

    ---- False

  E [E [X | Y,Z ]] = E [X|Y ]

    ----  False

b). Th quantity E [ g (X,Y) | Y,Z ] is ,

The low of iteration tell the following statement are true E[ E [ X|Y,Z] | Z] = E [ X|Z ] . A random variable y . A function of (Y,Z)

From the given equation the law of iterated expectations

[tex]E[ E (X|Y) ] = E (X)[/tex]

Therefore We have to find a)

Iteration is the repetition of a process in order to generate a sequence of outcomes.

So by using the low of iteration we can say that,

E[ E [ X|Y,Z] | Z] = E [ X|Z ]     ----  True

E [ E [ X|Y ] | Z ] = E [ X|Z ]  ---- False

E [E [X | Y,Z ]] = E [X|Y ]   ----  False

b). Th quantity E [ g (X,Y) | Y,Z ] is ,

For a random variable y this is  -----  True

For a number ----- False

For a function of (X,Y)  -----   False

For a function of (Y,Z) -----   True

For function of Z only  -------   False

Therefore,The low of iteration tell the following  statement are true E[ E [ X|Y,Z] | Z] = E [ X|Z ] . A random variable y . A function of (Y,Z)

To learn more about the iteration visit:

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Answer:

Is it anual or monthly?

Step-by-step explanation:

Answer:

Choosing a card randomly and noting its suit

Step-by-step explanation:

Choosing a card randomly and noting its suit

This is because binomial distributions only work for bernoulli trials (a trail in which there are only two outcomes)

Answer:

I think the answer is 12:16 because my brother told me

Step-by-step explanation:

I dont know the answer my brother told me this answer. HOPE THIS HELPS

Answer:

Step-by-step explanation:

Since you have this categorized under college math, I'm going to go out on a limb here and assume you're in calculus. We will solve using the position function and its first derivative (velocity) to solve. Remember that at an object's max height, the velocity is 0.

If the position function is

[tex]s(t)=-16t^2+24t+7[/tex] the first derivative, velocity, is

v(t) = -32t + 24. Set this equal to 0 to find the time when the object is at its max height:

0 = -32t + 24 and

-24 = -32t so

t = .75 seconds. Now we can plug that time into the position function to find where it is at that time. This "where" will be the max height:

s(.75) = [tex]-16(.75)^2+24(.75)+7[/tex] so

s(.75) = 16 feet

Answer: The rise and run is the two point between each other on a line for example 1/2 rise over run. 1 is rise and 2 is run so y=mx +b the slope is m and the y int is b so

Y= 1/2x + 3 the 3 is going to be on the Y acis not the X its important not to mix the two. In other words go to 0,0 make a line go up.. the from 0,0 go doen the same length

Step-by-step explanation:

Answer:

a. The friend is incorrect.

2(x) is the same as x(2). PEMDAS does not apply to the same order of operation under normal conditions and both are directly proportional functions.

b. The parentheses are the only thing making the functions different. After you simplify from the parentheses, both values have the same priority.

Step-by-step explanation:

Answer:

A = 16 ft^2

P = 20 ft

Step-by-step explanation:

P = perimeter

A = area

STEP 1: divide the shape into rectangles

Rectangle 1: 2ft*3ft

Rectangle 2: 2ft*5ft

STEP 2: Find the area of each rectangle

Equation for area of a rectangle = bh

Rectangle 1: b = 2, h = 3

Rectangle 2: b = 2, h = 5

(2 * 3) + (2 * 5)

6 + 10

16 ft^2

Now, we have to find the perimeter

STEP 1:  Find the unknown side lengths.

To find the lengths of the sides not labeled, you have to use the lengths of the sides we already know.

The length of one parallel side is 5, and the length of another parallel side is 2. The length of the unknown side starts at the same place as the top of the side length that is 5, and ends at the top of the side length that is 2. This means that we have to subtract 2 from 5 in order to find the unknown side length.

STEP 2: Add up all the side lengths

P = 2 + 5 + 5 + 2 + 3 + 3

P = 20 ft

Don't forget to label your answers!!

I hope this made sense, it's is a little hard to explain in simple terms without being able to draw, but I hope it helped.

Answer:

2x 2 - y + 5 + 3

Step-by-step explanation:

2ggfdfguutffyreryyrrrrrrrr

Step-by-step explanation:

D(.10) + Q(.25) = 4

I think

Answer:

D(.10) + Q(.25) = 4

Step-by-step explanation:

Answer:

-90.625

Step-by-step explanation:

Answer:

[tex]-90~5/8\\[/tex]

[tex]Decimal=-90.625[/tex]

-------------------------------

~HOPE IT HELP....~

~HAVE A GREAT DAY!!~

Answer:

I have not been able to answer it sorry

Answer:

he rate it 16%

Step-by-step explanation:

64-80\100=16

Given:

Size of a red blood cell = 0.000007 m

Size of a plant cell = 0.0000127 m

To find:

The comparison of these two values.

Solution:

We have,

Size of a red blood cell = 0.000007 m

Size of a plant cell = 0.0000127 m

Clearly, [tex]0.0000127>0.000007[/tex]. Now, the difference between these two values is:

[tex]0.0000127-0.000007=0.0000057[/tex]

Therefore, the size of a plant cell is 0.0000057 m more than the size of a red blood cell.

Answer:

[tex] C = 2 \pi \sqrt{113} [/tex]

[tex] C \approx 66.79 [/tex]

Step-by-step explanation:

[tex] C = 2 \pi r [/tex]

[tex] r^2 = 113 [/tex]

[tex] r = \sqrt{113}} [/tex]

[tex] C = 2 \pi \sqrt{113} [/tex]

[tex] C \approx 66.79 [/tex]

Answer:

(1) -10, 34 and 3105

(2) 0

Step-by-step explanation:

Solving (a): Select all integers

The integers are numbers without decimal.

So, we have: -10, 34 and 3105

Other options are not integers

Solving (b): Select all integers between -3 and 4

Using the same explanation in (1) but with the range of -3 and 4. the integer is 0.

Other options are not integers

Answer:

Line 3

Step-by-step explanation:

→ Calculate gradient

[tex]\frac{6-3}{4-2} =1.5[/tex]

Answer:

Line 3

Step-by-step explanation:

(0,0) & ( 4 , 6)

[tex]Slope = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}\\\\=\frac{6-0}{4-0}\\\\=\frac{6}{4}\\\\=\frac{3}{2}\\\\=1\frac{1}{2}[/tex]

9514 1404 393

Answer:

  (11, 3)

Step-by-step explanation:

That point is ...

  P = a + (1/6)(b -a) = (5a +b)/6

  P = (5(14, -1) +(-4, 23))/6 = (70-4, -5+23)/6 = (11, 3)

The point of interest is (11, 3).

Answer:

The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)

Step-by-step explanation:

Let's look first at the x coordinates of the two given points:  14 and -4.  From 14 to -4 is a decrease of 18.  Similarly, from y = -1 to y = 23 is an increase of 24.

Starting at a(14, -1) and adding 1/6 of the change in x, which is -18, we get the new x-coordinate 14 + (1/6)(-18), or 14 - 3, or 11.  Similarly, adding 1/6 of the increase in y of 24 yields -1 + 4, or 3.

The coordinates of the point that is 1/6 of the way from a to b is thus (11, 3)

Answer:

Parallelogram.

Step-by-step explanation:

Because parallelogram has its opposite sites equal.

The tangent to the curve at a point P (x, y) has slope dy/dx at that point. By the chain rule,

dy/dx = (dy/dθ) / (dx/dθ)

We're in polar coordinates, so

y (θ) = r (θ) sin(θ)   ==>   dy/dθ = dr/dθ sin(θ) + r (θ) cos(θ)

x (θ) = r (θ) cos(θ)   ==>   dx/dθ = dr/dθ cos(θ) - r (θ) sin(θ)

We're given r (θ) = 1 - sin(θ), so that

dr/dθ = -cos(θ)

Then the slope of the tangent to the curve at P is

dy/dx = (dr/dθ sin(θ) + r (θ) cos(θ)) / (dr/dθ cos(θ) - r (θ) sin(θ))

dy/dx = (-cos(θ) sin(θ) + (1 - sin(θ)) cos(θ)) / (-cos²(θ) - (1 - sin(θ)) sin(θ))

dy/dx = - (cos(θ) - sin(2θ)) / (sin(θ) + cos(2θ))

The tangent is horizontal if dy/dx = 0 (or when the numerator vanishes):

cos(θ) - sin(2θ) = 0

cos(θ) - 2 sin(θ) cos(θ) = 0

cos(θ) (1 - 2 sin(θ)) = 0

cos(θ) = 0   or   1 - 2 sin(θ) = 0

cos(θ) = 0   or   sin(θ) = 1/2

[θ = π/2 + 2nπ   or   θ = 3π/2 + 2nπ]   or   [θ = π/6 + 2nπ   or   θ = 5π/6 + 2nπ]

where n is any integer.

In the interval 0 ≤ θ ≤ 2π, we get solutions of θ = π/6, θ = 5π/6, and θ = 3π/2. (We omit π/2 because the denominator is zero at that point and makes dy/dx undefined.) So the points where the tangent is horizontal are themselves (√3/4, 1/4), (-√3/4, 1/4), and (0, -2), respectively.

The tangent is vertical if 1/(dy/dx) = 0 (or when the denominator vanishes):

sin(θ) + cos(2θ) = 0

sin(θ) + (1 - 2 sin²(θ)) = 0

2 sin²(θ) - sin(θ) - 1 = 0

(2 sin(θ) + 1) (sin(θ) - 1) = 0

2 sin(θ) + 1 = 0   or   sin(θ) - 1 = 0

sin(θ) = -1/2   or   sin(θ) = 1

[θ = 7π/6 + 2nπ   or   θ = 11π/6 + 2nπ]   or   [θ = π/2 + 2nπ]

Then for 0 ≤ θ ≤ 2π, the tangent will be vertical for θ = 7π/6 and θ = 11π/6, which correspond respectively to the points (-3√3/4, -3/4) and (3√3/4, -3/4). (Again, we omit π/2 because this makes dy/dx non-existent.)

Answer:

A proportion is an equality of two ratios.

Example : [tex]\frac{1}{3}[/tex] = [tex]\frac{x}{9}[/tex]

​

We write proportions to help us find equivalent ratios and solve for unknown quantities.

A rate is the quotient of a ratio where the quantities have different units.

Example : [tex]\frac{distance}{time}[/tex]

A ratio is a comparison of two quantities.

Example : 1 : 3 or [tex]\frac{1}{3}[/tex]