What is the value of this expression when x = -6 and y = — 1/2? 4(x^2+3) -2y A. -131 B. -35 C. 57 1/2 D. 157

Answer:

-4

Step-by-step explanation:

Replace g by -3.5

● 8- | 2g - 5 |

● 8 - | 2*(-3.5)-5 |

● 8 - |-7-5|

● 8 - | -12|

The absolute value turns the number inside the | | into a positive value

-12 is negative so |-12| = 12

●8 -12

● -4

Answer:

● The pythagorian theorem

The pythagorian theorem is used to find a missing side of a right triangle.

It states that the square of the hypotenus of a right triangle is equal to the sum of the squares of the two other sides.

Let a be the hypotenus, b and c are the othet sides:

☆☆☆☆☆ a^2 = b^2 + c^2☆☆☆☆☆

There are more than 350 way to prove this theorem.

■■■■■■■■■■■■■■■■■■■■■■■■■■

● Hippasus of Croton was a member of the highly-secretive school og Pythagoras in Croton. He is credited in history as the first person to prove the existence of irrational numbers.

Answer:

the nearest hundred is 50

Answer:

Linear, Quadratic, Radical, Absolute Value, Cubic, Cube Root

Step-by-step explanation:

To find:

Which functions have an intercept at (0, 0).

That means, when we put a value [tex]x=0[/tex] in the [tex]y =f(x)[/tex], value of [tex]y=0[/tex].

Let us discuss each parent function one by one:

1. Linear:

[tex]y = x[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

2. Quadratic:

[tex]y = x^2[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

3. Radical:

[tex]y = \sqrt x[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

4. Absolute Value:

[tex]y = |x|[/tex]

When we put x = 0, y = 0

Therefore, it has intercept at (0, 0).

5. Rational:

[tex]y = \dfrac{1}{x}[/tex]

When we put [tex]x = 0\Rightarrow y \rightarrow \infty[/tex]

Therefore, it does not have intercept at (0, 0).

6. Exponential:

[tex]y = b^x[/tex]

b is any base

When we put [tex]x = 0\Rightarrow y =1[/tex]

Therefore, it does not have intercept at (0, 0).

7. Logarithmic:

[tex]y = logx[/tex]

When we put [tex]x = 0 \Rightarrow y\rightarrow[/tex] Not defined

Therefore, it does not have intercept at (0, 0).

8. Cubic:

[tex]y = x^3[/tex]

When we put [tex]x = 0\Rightarrow y =0[/tex]

Therefore, it has intercept at (0, 0).

9. Cube Root:

[tex]y = \sqrt[3]x[/tex]

When we put [tex]x = 0\Rightarrow y =0[/tex]

Therefore, it has intercept at (0, 0).

Answer:

Given f(x)=8sin(x)+cot(x) for -pi<x<pi :

Note that:

f'(x)=8cos(x)-csc^2(x)

f''(x)=-8sin(x)+2csc^2(x)cot(x)

(1) To find the intervals where f(x) is increasing or decreasing we use the first derivative test; if the first derivative is positive on an interval the functio is increasing, negative implies the functio is decreasing.

Using technology we find the approximate zeros of f'(x) on -pi<x<pi :

x~~-1.443401

x~~-.3752857

x~~.3752857

x~~1.443401

Plugging in test values on the intervals yields:

f'(x)<0 on (-pi,-1.443401)

f'(x)>0 on (-1.443401,-.3752857)

f'(x)<0 on

Plz correct me if wrong

Answer:

7.5 < x≤10.5

Step-by-step explanation:

14<2x−1≤20

Add 1 to all sides

14+1<2x−1+1≤20+1

15<2x≤21

Divide each side by 2

15/2 <2x/2 ≤21/2

7.5 < x≤10.5

Steps to solve:

14 < 2x - 1 <= 20

~Add 1 to everything

15 < 2x <= 21

~Divide 2 to everything

7.5 < x <= 10.5

Best of Luck!

Answer:

$106

Step-by-step explanation:

You have 100$ in savings account

Interest rate =3%

Time = 2 years

Total in 2 years:

The interest formula is as follows:

Amount Invested · Rate = Interest Earned

If we invest $100 at 3% interest per year,

how much do we earn that year?

Well based on our formula, we can simply multiply 100 · 3%.

Think of the 3% as 3/100.

So we have 100 · 3/100 and the 100's cancel and we're left with 3.

So $3 is earned in 1 year.

So after two years, you will have double that or $6.

Answer:

The second graph is a function.

Step-by-step explanation:

This is the only one that passes the vertical line test.

(If there exits a vertical line which passes through more than one point, then the relation is NOT a function).

[tex]A \cap B=\{10,30\}[/tex]

Answer:

Option A is the correct option

Step-by-step explanation:

[tex] \mathrm{Given}[/tex]

A = { 10 , 30 }

B = { 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , 90 }

Now, let's find A ∩ B

A ∩ B = { 10 , 30 } ∩ { 10 , 20 , 30 , 40 , 50 , 60 , 70 , 80 , 90 }

The intersection of sets A and B is the set of all elements which belong to both A and B

A ∩ B = { 10 , 30 }

The intersection of sets A and B is denoted by ( A ∩ B ) and read as A intersection B.

Hope I helped!

Best regards!

Step-by-step explanation:

Hey, there!!

It's so simple,

Given,

length (l)= 2/3cm

Breadth (b) = 1/4cm

and height (h)=5/6cm

now, we use the formula for volume of rectangular prism is,

v = l× b× h

or, v= (2/3 × 1/4 × 5/6)^3

By simplifying it we get,

The volume is 5/36cm^3.

Hope it helps...

Answer:

x

Step-by-step explanation:

probability is the branch of mathematics concerning numeral descriptions of how likely an event is to occur or how likely it is that a proposition is true

Answer:

number 3

Step-by-step explanation:

Looks like either [tex]f''(x)=4x^2[/tex] or [tex]f''(x)=\frac4{x^2}[/tex]...

In the first case, integrate both sides twice to get

[tex]f''(x)=4x^2\implies f'(x)=\dfrac43x^3+C_1\implies f(x)=\dfrac13x^4+C_1x+C_2[/tex]

Then the initial conditions give

[tex]f'(1)=2\implies 2=\dfrac43\cdot1^3+C_1\implies C_1=\dfrac23[/tex]

[tex]f(1)=5\implies 5=\dfrac13\cdot1^4+C_1\cdot1+C_2\implies C_2=4[/tex]

so that the particular solution is

[tex]f(x)=\dfrac{x^4}3+\dfrac{2x}3+4[/tex]

If instead [tex]f''(x)=\frac4{x^2}[/tex], we have

[tex]f''(x)=\dfrac4{x^2}\implies f'(x)=-\dfrac4x+C_1\implies f(x)=-4\ln|x|+C_1x+C_2[/tex]

[tex]f'(1)=2\implies 2=-\dfrac41+C_1\implies C_1=6[/tex]

[tex]f(1)=5\implies 5=-4\ln|1|+C_1\cdot1+C_2\implies C_2=-1[/tex]

[tex]\implies f(x)=-4\ln|x|+6x-1[/tex]

Answer: 25 years

Step-by-step explanation:

t = I / Pr

t = 5700 / ( 3800 × 0.06 ) = 25

t = 25 years

Answer:

1.

d. (-14) + (-8)

2.

a. (-14) + 8

Step-by-step explanation:

(-14) - 8 is equal to (-14) + (-8) because we still add two negative values so the result wouldn't change.

(-14) - (-8) is equal to (-14) + 8 because there's two negative sign in front of 8 and two negative values multiplied makes a positive result.

Answer:

1. D  

2. A

Step-by-step explanation:

1.  It asks you what expression has the same value as (-14)-8.  All you need to do is find other equations that have the same value as that.  So the equation is -14-8.  IF a negative is outside a parenthesis with a positive number inside like -(+5), it is going to be -5.  If it's both negative: -(-5), it will be +5.  If it is both positive: +(+5), it is going to be +5.  

IMPORTANT!

- and + = -

- and - = +

+ and + = +

What we are looking for: -14-8

So choice A is (-14)+8 which is simplified to -14+8.  So, this one isn't right.

Choice B: 14-(-8)= 14+8.  So, it's incorrect.

Choice C: 14+(-8)= 14-8.  Again, it's not -14-8 so it's not right.

Choice D: (-14)+(-8)= -14-8.  This equation matches the one we are looking for!  So it's correct!

2. Same thing as number 1.  Let's simplify the equation it wants us to find first.  

(-14)-(-8)= -14+8

So -14+8 is what we are looking for.

Choice A: (-14)+8= -14+8.  It matches!  So it is correct.  Let's look at the other options anyway.

Choice B: 14-(-8)= 14+8.  Nope.  Not right.

Choice C: 14+(-8)= 14-8 because - always beats +.  So, this one is also incorrect.

Choice D: (-14)+(-8)= -14-8.  Oops, this is also wrong.  So choice A is the right answer.

Keep in mind, when you start getting questions like this with numbers inside the parenthesis as well, you want to remember the same rules for positive and negative, but also multiply the numbers together:

(When there is a number outside and inside a parentheses, multiply them.)

2(5)=10, CORRECT!    2+(5) is not 2 times 5.  It's whatever is closest to the parentheses, in this case being the positive sign.  So + and 5 is just 5!

IMPORTANT!

-2(-5)= - and - is positive, so positive (2 times 5).  Positive 10.

-2(+5)= - and + is negative, so negative (2 times 5). Negative 10.

+2(+5)= + and + is positive, so positive (2 times 5).  Positive 10.

Answer:

Step-by-step explanation:

We will use the set notation to solve this question.

let n(U) be the total number of students surveyed = 100

n(M) be the number of student that took math = 34

n(E) be the number of student that took English = 59

n(M∩E) be the number of student that took both classes= 12

n(M∪E)' be the number of student that took neither class = ?

Using the formula n(U) = n(M∪E) + n(M∪E)'

n(M∪E)' = n(U)-n(M∪E)

Before we can get the number of student that took neither class i.e n(M∪E)'  we need to  get n(M∪E).

n(M∪E) = n(M)+n(E)- n(M∩E)

n(M∪E) = 34+59-12

n(M∪E)  = 81

Since n(M∪E)' = n(U)-n(M∪E);

n(M∪E)' = 100-81

n(M∪E)' = 19

Hence 19 students took neither class as a freshmen.

Answer:

-9p -4q + 69

Step-by-step explanation:

5p +4q + (-9p +69)

=> 5p + 4q -9p +69

=> -4p +4q +69

Now, we need to subtract 5p +8q from -4p + 4q +69

=> -4p +4q +69 - (5p +8q)

=> -4p + 4q +69 - 5p -8q

=> -9p -4q + 69

Answer:

Solution : ( - 8, - 5π/3 )

Step-by-step explanation:

There are four cases to consider here, the first two with respect to r > 0, the second two with respect to r < 0. For r < 0 we have the coordinates ( - 8, 60° ) and ( - 8, - 300° ) . - 300° in radians is - 5π/3, and hence our solution is option d. But let me expand on how to receive the coordinates. Again r is the directed distance from the pole, and theta is the directed angle from the positive x - axis.

So when r is either negative or positive, we can tell that this point is 8 units from the pole. Therefore - r = - 8 in both our second cases ( we are skipping the first two cases for simplicity ). For r < 0 the point will lay on the ray pointing in the opposite direction of the terminal side of theta.

Our first coordinate is ( - 8, 60° ). Theta will be 2 / 3rd of 90 degrees, or 60 degrees, for - r. Respectively the remaining degrees will be negative, 360 - 60 = 300, - 300. Our second point for - r will thus be ( - 8, - 300° ) . - 300° = - 5π/3 radians, and our coordinate will be ( - 8, - 5π/3 ).

Answer:

Attachment 1 : Option C

Attachment 2 : Option A

Step-by-step explanation:

( 1 ) Expressing the product of z1 and z2 would be as follows,

[tex]14\left[\cos \left(\frac{\pi \:}{5}\right)+i\sin \left(\frac{\pi \:\:}{5}\right)\right]\cdot \:2\sqrt{2}\left[\cos \left(\frac{3\pi \:}{2}\right)+i\sin \left(\frac{3\pi \:\:}{2}\right)\right][/tex]

Now to solve such problems, you will need to know what cos(π / 5) is, sin(π / 5) etc. If you don't know their exact value, I would recommend you use a calculator,

cos(π / 5) = [tex]\frac{\sqrt{5}+1}{4}[/tex],

sin(π / 5) = [tex]\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}[/tex]

cos(3π / 2) = 0,

sin(3π / 2) = - 1

Let's substitute those values in our expression,

[tex]14\left[\frac{\sqrt{5}+1}{4}+i\frac{\sqrt{2}\sqrt{5-\sqrt{5}}}{4}\right]\cdot \:2\sqrt{2}\left[0-i\right][/tex]

And now simplify the expression,

[tex]14\sqrt{5-\sqrt{5}}+i\left(-7\sqrt{10}-7\sqrt{2}\right)[/tex]

The exact value of [tex]14\sqrt{5-\sqrt{5}}[/tex] = [tex]23.27510\dots[/tex] and [tex](-7\sqrt{10}-7\sqrt{2}\right))[/tex] = [tex]-32.03543\dots[/tex] Therefore we have the expression [tex]23.27510 - 32.03543i[/tex], which is close to option c. As you can see they approximated the solution.

( 2 ) Here we will apply the following trivial identities,

cos(π / 3) = [tex]\frac{1}{2}[/tex],

sin(π / 3) = [tex]\frac{\sqrt{3}}{2}[/tex],

cos(- π / 6) = [tex]\frac{\sqrt{3}}{2}[/tex],

sin(- π / 6) = [tex]-\frac{1}{2}[/tex]

Substitute into the following expression, representing the quotient of the given values of z1 and z2,

[tex]15\left[cos\left(\frac{\pi \:}{3}\right)+isin\left(\frac{\pi \:\:}{3}\right)\right] \div \:3\sqrt{2}\left[cos\left(\frac{-\pi \:}{6}\right)+isin\left(\frac{-\pi \:\:}{6}\right)\right][/tex] ⇒

[tex]15\left[\frac{1}{2}+\frac{\sqrt{3}}{2}\right]\div \:3\sqrt{2}\left[\frac{\sqrt{3}}{2}+-\frac{1}{2}\right][/tex]

The simplified expression will be the following,

[tex]i\frac{5\sqrt{2}}{2}[/tex] or in other words [tex]\frac{5\sqrt{2}}{2}i[/tex] or [tex]\frac{5i\sqrt{2}}{2}[/tex]

The solution will be option a, as you can see.

Answer:

C) 3/2x-1/8

Step-by-step explanation:

We can see that it has a generally positive slope, which rules out B and D.

Plugging in a few numbers for x, we can quickly see that 6 is too high of a slope. (If we plug in 6 for x, the y value would be almost 35, not 10).  This rules out A.

While it doesn’t fit perfectly, C is by far the closest.

Answer:

(-25)+(-12)+(-34) = -71

so when you add negative numbers you simply add them such as -2+-2 -4

so same conditions

so it will be -25+-12+-34 and it will simply be 25+12+34 so -71

Answer:

A. 5:4

Step-by-step explanation:

Since the question mentions twelfths of a pie, it is easier to say each pie has 12 pieces or 36 total pieces ordered from the 3 pies. Ty ate 5 and Rob ate 15 which is 3 times more than Ty. A total of 20 pieces have been eaten from the 36 you started with. Eaten = 20 and Remaining = 16. So the ratio is 20:16 which is simplified to 5:4.

Answer:

Linear

Step-by-step explanation:

Given

Height of a tree grows by 2.5 feet

Required

Determine the type of relationship

Take for instance, the height of the tree at year 1 is x

At year 2, it will be x + 2 * 1

At year 3, it will be x + 2 * 2

At year 4, it will be x + 2 * 3

Following same pattern

At year n, it will be x + 2 *(n - 1)

Hence, growth rate = x + 2(n -1)

From the list of given options, the correct answer is Linear because the derived formula above is an example of a linear equation

let the function be [tex]y=ax^2+bx+c[/tex]

put $x=0, \, y=6$ , to get $c=6$

put $x=2, \, y=16$ , $16=4a+2b+6\implies 2a+b=5$

put $x=3, \, y=33$ , $33=9a+3b+6\implies 3a+b=9$

subtract the two equation, to get $a=4$

now substitute $a$ in first equation, to get $b=5-2\cdot4=-3$

so, $f(x)=4x^2-3x+6$

Answer:

a² + b² = c²

13² + 13² = c²

169 + 169 = c²

338 = c²

c = √338 or 18.385 or 13√2

Answer:

18.4

Step-by-step explanation:

13² + 13² = x²

169 + 169 = x²

338 = x²

x = 18.38477....

Answer:

The answer is 68 6/11

Step-by-step explanation:

If you enter the number into a calculator it shows you the exact decimal, therefore you can identify the answer.

Answer:

It is 68 6/11

Step-by-step explanation:

First I made all of the improper fractions into whole numbers and fractions and just saw which one was in the middle .

Answer:

A. A sequence of statements that demonstrates the truth of an assertion.

Step-by-step explanation:

Mathematical proofs are a series of statements in order that help prove that something is true.

Proofs do not prove that something is false, they are not always 3 parts, and they are not in any order, because they have to be in an organized sequence.

So, A is correct.

Answer:

A sequence of statements that demonstrates the truth of an assertion.

Step-by-step explanation:

Question options :

A. There is sufficient evidence to reject the claim

u < 99.

B. There is sufficient evidence to support the claim

u < 99.

C. There is not sufficient evidence to reject the claim

u < 99.

D. There is not sufficient evidence to support the claim

u< 99.

Answer:

B. There is sufficient evidence to support the claim

u < 99.

Step-by-step explanation:

We construct the n*ll and alternative hypotheses to support our claim

The n*ll hypothesis :H0

The alternative hypothesis : Ha

N*ll hypothesis =H0: u=99

Alternative hypothesis =Ha: u<99

So if n*ll hypothesis (H0) u=99 is rejected, then we accept the alternative hypothesis that u<99

we can therefore have sufficient evidence to support our claim that u<99

Answer:

Even set = {HTT, THT, TTH, TTT}

Step-by-step explanation:

We are given that three coins are tossed; the result is at most one head.

And we have to find the sets of elements that are included in the sample space.

Firstly, as we know that when three coins are tossed, the total number of cases formed is 8.

Let Head on the coin be represented by 'H' and the Tail on the coin be represented by 'T'.

So, the sample space so formed is;

S = {HHH, HTH, HHT, THH, THT, TTH, HTT, TTT}

Now, our event is at most one head. So, the sample space for the favorable event is given by;

Even set = {HTT, THT, TTH, TTT}

In this, three cases are of head occurring only once and one case is of head not appearing in three tosses of a coin.