Considering the ideal gas law, the volume occupied by 3.25 moles of an ideal gas at a temperature of 18.00°C is 686.71 L.
Definition of ideal gas lawAn ideal gas is the behavior of those gases whose molecules do not interact with each other and move randomly. Under normal conditions and under standard conditions, most gases exhibit ideal gas behavior.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T), related by a simple formula called the ideal gas law:
P×V = n×R×T
Where:
P is the gas pressure.V is the volume that occupies.T is its temperature.R is the ideal gas constant. The universal constant of ideal gases R has the same value for all gaseous substances. n is the number of moles of the gas. Volume in this caseIn this case, you know:
P= 1.13 atmV= ?T= 18 C= 291 K (being 0 C= 273 K)R= 0.8205 L.atm/K.moln= 3.25 molReplacing in the ideal gas law:
1.13 atm×V = 3.25 mol× 0.8205 L.atm/K.mol× 291 K
Solving:
V = (3.25 mol× 0.8205 L.atm/K.mol× 291 K)÷ 1.13 atm
V= 686.71 L
Finally, the volume is 686.71 L.
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Animals inherit behaviors from their parents. describe an example of an inherited behavior of a bird ?
Answer:
Process of migration.
Explanation:
One example of an inherited behavior in birds is the process of migration. Many bird species have the innate ability to navigate long distances to migrate to warmer climates during the winter months. This behavior is passed down genetically from parents to their offspring, and young birds are able to migrate successfully without prior experience or training. This behavior is thought to be controlled by a combination of genetic and environmental cues, such as changes in daylight and temperature. Examples of migratory bird species include the Arctic Tern, which flies from the Arctic to the Antarctic each year, and the Monarch Butterfly, which migrates to Mexico for the winter.
HELP HELP HELP 40 POINTS
Option D is correct. If this reaction uses 6.55 MOLES of P4, it also needs 19.7 mol Mn.
What is Mole?In chemistry, a mole (mol) is a unit of measurement that is used to express how much a chemical substance is present. It is described as the volume of a substance containing 6.022 x 1023 individuals, or the Avogadro number, of entities.
In the reaction described, 5 moles of phosphorus and 12 moles of manganese combine to form 4 moles of Mn3P5. Therefore, 12 moles of Mn are required for every 5 moles of P4 employed in the reaction. Using the ratio of the reactant coefficients in the balanced chemical equation, we can determine how many moles of Mn are required if 6.55 moles of P4 are employed in the reaction:
6.55 moles P4 / 5 moles P4 = x moles Mn / 12 moles Mn
Solving for x, we get:
x = 12 * 6.55 / 5 = 19.7 moles Mn
So, 19.7 moles of Mn are needed if 6.55 moles of P4 is used in the reaction.
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Pair each cation on the left with an anion on the right that will form a soluble compound and write a formula for the soluble compound. Use each anion only once.Na+ NO3-Sr2+ SO4 2-C02+ S2-Pb2+ CO3 2-For Na+ Express your answer as an ion. Then express it as a chemical formula. You got to do the same thing for the other cations on the left.
Na+ and NO3- form NaNO3, a soluble compound.
Sr2+ and SO4 2- form SrSO4, a soluble compound.
CO2+ and S2- form CO2S, a soluble compound.
Pb2+ and CO3 2- form PbCO3, a non- soluble compound.
Na+ and NO3- form NaNO3:
This substance, sometimes known as "Chile saltpetre," is made up of a sodium cation (Na+) and a nitrate anion (NO3–). Sodium nitrate is a white, crystalline solid at ambient temperature that is very soluble in water.
Sr2+ and SO4 2- form SrSO4
Strontium sulphate is produced when the strontium ion reacts with the sulphate ion. This reaction falls under the category of an acid-base reaction. Cation and anion interaction. Cation and anion precipitation reaction
CO2+ and S2- form CO2S, a soluble compound.
Typically, CO2, or carbon dioxide, is a gas. Both people and animals exhale it, while plants utilise it to make oxygen. It is dry ice when it is solid.
Such compounds are soluble in water at normal temperatures.
Pb2+ and CO3 2- form PbCO3, a soluble compound.
Pb2+ and CO3 2- do not form a soluble compound.
PbCO3 is a sparingly soluble compound, meaning it has low solubility in water.
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name one kind of subsituted hydrocarbon you would expet to find in artificially flavored grape flavor
Esters are substituted hydrocarbon that are found in artificially flavored grape flavor.
Esters are defined as the chemical compounds derived by reacting an oxoacid with a hydroxyl compound such as an alcohol or phenol. Esters are basically ubiquitous. Generally, most naturally occurring fats and oils are the fatty acid esters of glycerol.
Substituted hydrocarbons are made by removing 1 or more hydrogen (H) from a hydrocarbon and “popping on” another elements. Substituted hydrocarbons has a different atom or group of atoms in place of a hydrogen.
One kind of substituted hydrocarbons that is found in artificially flavored grapes is esters.
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A photon with an energy of 2.96×10^-19 J is absorbed by Li+ ion. What is the wave length of this photon 
The wavelength of the photon with an energy of 2.96×10-¹⁹J is 6.71 × 10-⁸m.
How to calculate wavelength?Wavelength is the length of a single cycle of a wave, as measured by the distance between one peak or trough of a wave and the next.
It is often designated in physics as λ, and corresponds to the velocity of the wave divided by its frequency.
E = hν = hc/λ
Where;
E = energyh = Planck's constant ν = frequencyc = the speed of lightλ = wavelength2.96 × 10-¹⁹ = 6.623 × 10-³⁴ × 3 × 10⁸/λ
2.96 × 10-¹⁹λ = 1.9869 × 10-²⁶
λ = 6.71 × 10-⁸m
Therefore, 6.71 × 10-⁸m is the wavelength of the photon.
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Suppose you need 7.5 m of Grade 70 tow chain, which has a diameter of 3/8" and weighs 2.16 kg/m, to tow a car. How would you calculate the mass of this much chain? Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.
The mass of 7m chain is 15.12 kg.
It states that in order to tow a car, 7m of grade 70 tow chain with a 3/8" diameter is needed.
Chain length is therefore 7m.
Given that the chain weighs 2.16 kg per meter,
Thus, the mass of 1 m of chain equals 2.16 kg of chain's weight.
In this case, weight and mass are equivalent because both are measured in kilograms (kg).
Therefore, we must increase the mass of a 1 m chain by the chain's length to obtain the mass of a 7 m chain.
Consequently, the weight of a 7-meter chain = 7 x 2.16 kilograms = 15.12 kilograms.
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A sample of metal has a mass of 20.11 g, and a volume of 6.03 mL. What is the density of this metal?
Density is a physical property of matter and is defined as the mass per unit volume of a substance. It can be calculated by dividing the mass of the substance by its volume.
To find the density of the metal, we can use the following formula:
Density = Mass/Volume
For the given sample, the mass is 20.11 g and the volume is 6.03 mL. So, we can plug in the values into the formula and get:
Density = 20.11 g / 6.03 mL
To get the final density of the metal, we need to convert the units of volume to cm^3 as the density is usually given in g/cm^3
1ml = 1cm³
So, 6.03 ml = 6.03 cm³
Density = 20.11 g / 6.03 cm³
Density = 3.344 g/cm³
Therefore the density of the metal is 3.344 g/cm³
The head of a golf club might contain 250 grams of titanium. How many atoms are present in this? (Show work please)
Answer:15.22
Explanation:
changing gloves often will minimize the spread of chemicals. to properly remove gloves, first, choose... , and then, choose... . then insert choose... between the interior edge of the second glove and the skin, and remove the second glove.
Choices:
grasp the exterior of one glove with a gloved hand grasp the exterior of one glove with a bare hand insert a gloved finger into one glove
Peel out the glove away from your body, pulling it inside out. Peel the glove away from your body by grasping the outside of one glove at the wrist. Don't touch your bare skin with that hand.
A chemical is defined as any substance that has a defined composition. We can also say that, a chemical is always made up of the same "stuff." Some chemicals occur in nature, such as water while most of them are man - made.
Steps required to remove gloves:
The first step includes grasping of the palm of one glove near your wrist. Carefully pull out the glove off, turning it inside out.
In the next step hold the glove in the palm of the still-gloved hand.
Now you must pull out the glove until it comes off inside out.
Always make sure to wash your hands after removing gloves and before touching any objects or surfaces.
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For which of the following species are the dispersion forces strongest?A) C4H10B) C5H12 C) C6H14 D) C7H16 E) C8H18
The most molar mass and largest dispersion forces are found in C8H18. As the molar mass is large, the dispersion force is strongest .
The least attractive intermolecular forces are dispersion forces. Dispersion forces are responsible for the liquification of low molecular weight, non-polar molecules including hydrogen (H2), neon (Ne), and methane (CH4).
It is crucial to think about the instantaneous distribution of electron density rather than the average distribution in order to visualise the source of dispersion forces.
Atoms and molecules that are bigger and heavier show larger dispersion forces than those that are smaller and lighter. The valence electrons are, on average, farther from the nucleus in a larger atom or molecule than in a smaller atom or molecule. They can more easily create transient dipoles because they are not held as tightly.
All molecular types exhibit London forces. A molecule's molar mass (higher MM = more electrons = more polarizable = stronger London forces) and, to a lesser extent, surface area (larger surface area = stronger London forces) determine the strength of the London forces.
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An infant weighing 17.5 lb has been exposed to the flu virus in the community. The recommended dose of a prophylactic Tamiflu treatment is 3.00 mg per kg b.i.d. How many times a day should Tamiflu be administered?
How many milligrams of Tamiflu should be given at every administration?
Answer:
11.97 mg.
Explanation:
divide the weight by 2.2046 to get the weight (in kilograms).
17.5 lb / 2.2046 = 7.98 kg
The dose of Tamiflu can be calculated by multiplying the weight of the infant in kilograms by the recommended dose of 3.00 mg/kg.
7.98 kg * 3.00 mg/kg = 23.94 mg
Tamiflu is recommended to be given twice a day, so the total dose of Tamiflu should be divided by 2.
23.94 mg / 2 = 11.97 mg per administration
Therefore, Tamiflu should be given to the infant twice a day, and each administration should be 11.97 mg.
Answer:
twice a day23.81 mgExplanation:
You want to know the dosage in milligrams for an infant weighing 17.5 lb when the prescription is 3.00 mg/kg b.i.d.
MassThe conversion factor for pounds to kilograms is ...
1 lb = 0.45359237 kg . . . exactly
This means that 17.5 lb corresponds to ...
17.5 lb × 0.45359237 kg/lb = 7.937866475 kg
DoseAt 3.00 mg/kg, the required dose is ...
(3.00 mg/kg)(7.937866475 kg) ≈ 23.81 mg
Each administration of the medicine should be 23.81 mg.
FrequencyThe abbreviation b.i.d. is for the Latin "bis in die", which means "twice a day."
The medicine should be administered 2 times a day.
The energy E of the electron in a hydrogen atom can be calculated from the Bohr formula: R₂ 2 E=-- 71 In this equation R, stands for the Rydberg energy, and stands for the principal quantum number of the orbital that holds the electron. (You can find the value of the Rydberg energy using the Data button on the ALEKS toolbar.) Calculate the wavelength of the line in the emission line spectrum of hydrogen caused by the transition of the electron from an orbital with n = 11 to an orbital with n=7. Round your answer to 3 significant digits.
the acidity of a compound is influenced by the electronegativity of the element bonded to h. this effect is more important when comparing elements in the same period than in the same group. for similar acids of general formula ha, electronegativity of a ______ across a period and acidity therefore ______.
The electronegativity of an element affects the acidity of a compound. This effect is more important when comparing elements in the same period than in the same group.
The acidity and the element's long-term electronegativity differ for similar acids with the general formula HA. How drawn an atom is to the bonding electrons in molecules as opposed to other atoms is referred to as its "electronegativity."
The electronegativity values were created by American chemist Linus Pauling and range from a little under one for alkali metals to a maximum of four for fluorine. Large electronegativity levels display a stronger attraction for electrons when compared to smaller values.
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You are asked to help design a bimetallic temperature sensor. You are given five metal alloys to work with; their thermal expansion coefficients are listed below. Assuming the elastic properties for each alloy are identical, which combination of alloys would give you the largest temperature-sensitive deflection for your sensor design?
Thermal Expansion Coefficients of Alloys
Alloy 1: 15 m/m-K
Alloy 2: 10 m/m-K
Alloy 3: 10 m/m-K
Alloy 4: 8 m/m-K
Alloy 5: 5 m/m-K
Alloy 1 and Alloy 2
Alloy 1 and Alloy 4
Alloy 1 and Alloy 5
Alloy 2 and Alloy 3
Alloy 4 and Alloy 5
Alloy 1 / Alloy 2 and Alloy 1 / Alloy 3 would give equally large deflections.
Alloy 1 and Alloy 5
The combination of alloys 1 and 5 would give the largest temperature-sensitive deflection for your bimetallic temperature sensor design. Thus, the correct option is C.
A bimetallic temperature sensor works by using two different metals with different thermal expansion coefficients that are bonded together. When the temperature changes, one metal will expand more than the other, causing the bond to bend. To achieve the largest temperature-sensitive deflection, it is important to use two metals with the largest possible difference in thermal expansion coefficients.
In this case, alloys 1 and 5 have the largest difference, with thermal expansion coefficients of 25 m/m-K and 2 m/m-K respectively, resulting in the largest deflection and making it the most suitable combination for a temperature sensor design.
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Methylation, which is the addition of-CH, groups to a larger structure, is common in certain RNA molecules. One common pattern of methylation is the double methylation of nitrogen number 2 in guanine to form N2, N2-dimethylguanine, shown below. NH Nitrogen 2 a. In a typical guanine cytosine base pair, does nitrogen number 2 typically act as a hydrogen bond donor or acceptor? b. In terms of H-bonds that are broken and formed, explain why the formation of a base pair between N2 N2-dimethyluanine and cytosine is less favorable than the formation of a typical guanine-cytosine base pair
a. Nitrogen number 2 in guanine typically acts as a hydrogen bond acceptor.
b. N2, N2-dimethylguanine (N2-meG) is less favorable in forming base pairs with cytosine than typical guanine-cytosine (G-C) base pairs because the methylation at nitrogen number 2 changes its properties, causing a decrease in the number of hydrogen bonds and stability of the base pair.
The methyl group disrupts the hydrogen bonding potential of nitrogen number 2, reducing the number of hydrogen bonds formed between N2-meG and cytosine. This leads to a decrease in the stability of the N2-meG: cytosine base pair compared to a typical G-C base pair.
Methylation is the addition of a methyl group (-CH3) to a molecule, and is a common pattern of modification in RNA molecules. One specific pattern of methylation is the double methylation of nitrogen number 2 in guanine to form N2, N2-dimethylguanine (N2-meG). In a typical guanine-cytosine (G-C) base pair, nitrogen number 2 acts as a hydrogen bond acceptor, forming two hydrogen bonds with the nitrogen atoms in the cytosine ring.
However, the formation of a base pair between N2-meG and cytosine is less favorable than the typical G-C base pair due to the effect of the added methyl groups. The methyl groups disrupt the hydrogen bonding potential of nitrogen number 2, reducing the number of hydrogen bonds that can be formed between N2-meG and cytosine. As a result, the stability of the N2-meG: cytosine base pair is lower compared to the G-C base pair.
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5. Lea's chemistry teacher gave her two 100-ml samples of clear liquid and instructed
her to mix the samples together in a large Erlenmeyer flask, shown below.
500 ml
500
400
200
After vigorously shaking the combined samples, Lea immediately concluded that
each sample contained a different chemical. Which of the following observations
would justify Lea's conclusion?
O
CLEAR ALL
Bubbles formed on the surface of the liquid after it was shaken.
The temperature of the liquid increased slightly as it was shaken.
The liquids mixed together completely and remained clear.
The liquids separated into two distinct layers after they were
shaken.
F
The observation that would justify Lea's conclusion is that the liquids separated into two distinct layers after they were shaken.
The correct option is D.
What is a chemical reaction?A chemical reaction is a procedure that causes one group of chemical components to change chemically into another.
Chemical reactions, which can frequently be described by a chemical equation, traditionally include changes that only affect the locations of electrons in the formation and dissolution of chemical bonds between atoms, with no change to the nuclei (no change to the elements present.
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When montiring stream quality, scientists use macroinvertebrates. What does their presence or absence tell us? Lesson 1.09
Question 20
It is used to indicate clean or polluted water
It is used to indicate the type of rocks found in the area
It is used to indicate how fast the stream is moving
It is used to indicate how blue the water is. Wetlands are an important part to watersheds.
Question 19
True
False Why are rain gardens helpful? Lesson 1.07
Question 18
They help bring rain to places that need water to grow plants
They help deliver fresh water to the grocery store
They are not helpful
They help reduce storm water polution and improve overall water quality Question 12 (1 point)
Saved
This picture shows different amounts of space in between the particles of two different soil samples. Which word best describes what we are seeing?
Question 12
porosity
permeability
precipitation
the water cycle All of these are ways that humans impact the water cycle EXCEPT __________.
Question 5
irrigating crops and lawns
hiking in the woods and boating on lakes
building dams and buildings
cutting down trees and forests Match each word with the correct definiton. Lesson 1.02
Question 6 options:
rain, snow, sleet or hail that falls to the ground
water from plants evaporating
Liquid changes to a gas
cooling of water molecules, gas changes to a liquid
1.
Evaporation
2.
Condensation
3.
Precipitation
4.
Transpiration All of the water we have on Earth is all of the water Earth has EVER had.
Question 7
True
False An increase in demand for water is caused by an increase in __________.
Question 8
pollution
population
climate change
urbanization
1. macroinvertebrates is used to indicate clean or polluted water
2. They help reduce stormwater pollution and improve overall water quality
3. porosity
4. hiking in the woods and boating on lakes
5. Precipitation, Transpiration, Evaporation, Condensation
6. True
7. population
Why does the presence of macroinvertebrates affect water quality?Different types of macroinvertebrates are present in different streams and levels of pollution. Their presence or absence is used to show clean or polluted water.
Planted with grasses and perennials, rain gardens can be a beautiful way to reduce runoff from your area. Rain gardens can also help to filter out pollutants from water in runoff and also provide food and shelter for wildlife.
As our economy grows, so does the demand for domestic water-consuming appliances increases. An increase in population contributes to an increase in water use and increase demand.
So we can conclude that macroinvertebrates are used to indicate clean or polluted water.
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A computer monitor has a width of 14.68
inches and a height of 11.01
inches. What is the area of the monitor display in square meters?
Answer: 161.6268 square inches
Explanation: Area of a rectangle is length (or width) times the height. So, 14.6 * 11.01 is 161.6268 square inches. Area is always in square units.
Which of the following seal designs are commonly used to keep oil inside the transmission while keeping water and dirt out? Lip seals.
Lip seal designs are commonly used to keep oil inside the transmission while keeping water and dirt out.
Rubber lip seals have been recognized for decades as the single most significant component in the design of rotary shaft seals.
Radial lip seals see the widespread application in wet environments, including water pumps, ships, and tidal turbines, among other places. The lip seals prevent the entry of water and debris while also retaining any oil or grease lubricant that may be present within the application.
Lip seals are available in a variety of designs, ranging from those with a single lip seal to those with numerous lips on a cartridge. Regardless of the design, they serve the purpose of preventing the entry of water and dirt while also preserving lubricants.
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A copper wire is 39.57 cm long and weighs 1.863 g. The density of copper is 8.933 g/cm3.
What is the radius of the wire in millimeters?
What is the diameter of the wire?
The radius of the copper wire is approximately 0.23 millimeters and the diameter is approximately 0.46 millimeters.
Explanation:To solve this problem, we need to apply some physics concepts together with a bit of geometry. We can use the formula for the volume of a cylinder, which is V = πr²h, where V is the volume, r is the radius, and h is the height (or in this case, the length of the wire). Also, we know that the density (ρ) of an object is mass (m) divided by volume (V), so ρ = m/V. We can use this information and the given data to solve for the radius of the wire.
First, rearrange the density equation to solve for the volume: V = m/ρ. Substituting the given values, we get V = (1.863 g) / (8.933 g/cm³) ≈ 0.208519 cm³.
Next, we substitute V = 0.208519 cm³ and h = 39.57 cm into our volume formula and solve for r: r = sqrt(V/πh) = sqrt(0.208519 cm³/(π*39.57 cm)) ≈ 0.023 cm. Because 1 cm = 10 mm, our answer is about 0.23 mm. The diameter is then simply twice the radius, or about 0.46 mm.
So, the copper wire has a radius of approx. 0.23 mm and a diameter of approx. 0.46 mm.
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Aqueous sodium hydroxide reacts with nitric acid according to the following equation. From this it can be deduced that 114 kJ of energy would be released when
1 mol NaOH reacts with 2 mol nitric acid
2 mol NaOH reacts with 1 mol nitric acid
2 mol NaOH reacts with 2 mol nitric acid
3 mol NaOH reacts with 2 mol nitric acid
Aqueous sodium hydroxide reacts with nitric acid according to the following equation. From the reaction it can be deduced that 114 kJ of energy would be released when 1 mol NaOH reacts with 2 mol nitric acid.
What do you know about nitric acid?
Nitric acid (HNO3) is an odorless liquid that gives out yellow or red odors. Nitric acid exposure can irritate the eyes, skin, and mucous membranes. It can also lead to dental erosion, delayed pulmonary edema, pneumonitis, and bronchitis. The acid nitric is quite corrosive.
A nitrogen oxoacid with the formula HNO3 is nitric acid, in which the nitrogen atom is linked to a hydroxyl group and the other two oxygen atoms by analogous bonds. It serves as a reagent and a protic solvent. It is a nitrate's conjugate acid.
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Calculate the standard enthalpy change for the reaction at 25 ∘
C. Standard enthalpy of formation values can be found in this list of thermodynamic properties.
H2O(g)+C(graphite)(s)⟶H2(g)+CO(g)
The standard enthalpy change for the thermodynamic properties of this reaction is 131.33 kJ/mol.
How to find enthalpy change?The standard enthalpy change for the reaction can be calculated using the standard enthalpies of formation of the reactants and products. The standard enthalpy of formation is the change in enthalpy that occurs when one mole of a substance is formed from its constituent elements in their standard states.
ΔH° = ΔH°f (products) - ΔH°f (reactants)
The standard enthalpies of formation for H2O(g), C(graphite)(s), H2(g) and CO(g) are:
ΔH°f (H2O(g)) = -241.83 kJ/mol
ΔH°f (C(graphite)(s)) = 0 kJ/mol
ΔH°f (H2(g)) = 0 kJ/mol
ΔH°f (CO(g)) = -110.5 kJ/mol
Substituting these values into the equation for ΔH°, we have:
ΔH° = ΔH°f (H2(g)) + ΔH°f (CO(g)) - ΔH°f (H2O(g)) - ΔH°f (C(graphite)(s))
= 0 + (-110.5 kJ/mol) - (-241.83 kJ/mol) - 0
= 131.33 kJ/mol
Therefore, the standard enthalpy change for the reaction at 25°C is 131.33 kJ/mol.
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Ethyl chloride, CH3CH2Cl, used to produce tetraethyllead gasoline additive, decomposes when heated, to give ethylene and hydrogen chloride.
CH3CH2Cl(g) → C2H4(g) + HCl(g)
The reaction is first order. In an experiment, the initial concentration was 0.00100 M. After heating at 500ºC for 155 seconds, the concentration of ethyl chloride was reduced to 0.00083 M. What is the concentration of ethyl chloride consumed after a total of 400 seconds?
The amount of the ethyl chloride is 7.8 * 10^-4 M.
What is the first order reaction?A first order reaction is a type of chemical reaction in which the reaction rate is proportional to the concentration of only one reactant. The rate law for a first order reaction is given by the equation: rate = k[reactant]
Given that;
ln[A] = ln[A]o - kt
[A] = concentration at time t
[A]o = Initial concentration
k = Rate constant
t = time taken
Then;
k =ln[A] - ln [A]o/t
k = ln(0.00083 ) - ln(0.00100)/155
k = -(-7.1 - (-6.9)/155)
k = 6.45 * 10^-4
Then;
ln[A] =ln(0.00100) - (6.45 * 10^-4 * 400)
= -6.9 - 0.258
= -7.158
[A] = e^(-7.158)
= 7.8 * 10^-4 M
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which of the following describe weathering of the sea floor? (choose all that apply.) multiple select question. both chemical and physical weathering occur. weathering is more rapid along coastlines. weathering occurs more slowly than on land. only physical weathering occurs. only chemical weathering occurs. need help? review these concept resources.
A: "Both chemical and physical weathering occur" and B: "weathering is more rapid along coastlines" describe weathering of the sea floor.
Weathering is the breaking down and alteration of rocks, soils and minerals at or near the Earth's surface, through physical and chemical processes.
Physical weathering involves mechanical processes such as freeze-thaw, abrasion and erosion, which cause rocks and soils to physically break apart into smaller pieces. While chemical weathering involves chemical reactions between the minerals in rocks and soils and the surrounding environment, altering their chemical composition and causing them to break down into new minerals.
In the sea floor, both physical and chemical weathering occur as a result of the exposure to the ocean and its many processes such as wave action, currents and temperature changes. Weathering is more rapid along coastlines due to the increased exposure to these processes and because these areas often experience more severe weather conditions than other parts of the sea floor.
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The following reaction takes place in a 1.00 liter container at 750.0 °C.
H2(g) + CO2(g) ⇌ H2O(g) + CO(g)
At equilibrium there are 0.106 moles of H2, 0.106 moles of CO2, 0.094 moles of water and 0.094 moles of CO. What is the Keq for this reaction?
The Keq for this reaction is 0.857.
What is keq?The equilibrium constant Keq of a chemical reaction is described as the value of its reaction quotient at chemical equilibrium, a state approached by a dynamic chemical system after sufficient time has elapsed at which its composition has no measurable tendency towards further change.
The Keq can be calculated using the ratio of the product concentrations to the reactant concentrations at equilibrium:
Keq = (H2O)(CO) / (H2)(CO2) = (0.094 mol) (0.094 mol) / (0.106 mol) (0.106 mol) = 0.857.
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Ni^2+ (NH3)m BrnpH2O where m, n, and p represent the coefficients in the formula. An analysis of the salt can be obtained if a sample is dissolved by an acid-base reaction in excess acid and then the excess is titrated with NaOH. That is, excess HCI+OH-H20 A 0.185-g sample of the nickel salt was dissolved in 30.00 mL of 0.1013 N HCI. The excess HCl required 6.30 mL of 0.1262 N NaOH to reach the end point. Calculate the weight of the salt that contains one mole of NH3 (that is the equivalent weight of the salt)
Salt equivalent weight = (0.185 g) / (Moles of salt)
The results from the acid-base titration may be used to compute the equivalent weight of the nickel salt.
To begin, determine the number of moles of HCl utilized in the reaction:
HCl moles = 0.1013 N * (0.0630 L) = 0.006426 moles
Next, compute the moles of OH- ions that interacted with the HCl:
OH- moles = 0.006426 moles
We now understand how one mole of OH- interacts with one mole of H+. As a result, the number of moles of H+ in the reaction equals the number of moles of OH-.
Finally, the moles of nickel salt present in the sample may be estimated as follows:
(Moles of H+) / (n + p) = Moles of salt
By dividing the mass of the salt sample by the number of moles of salt, the equivalent weight of the salt (mass of salt containing one mole of NH3) may be calculated:
Salt equivalent weight = (0.185 g) / (Moles of salt)
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3. How many ml of volume are in 1.0 cm³?
Answer:
1
Explanation:
just multiply it by 1
Answer the following questions using principles of chemical bonding and molecular structure. (1) Consider the carbon dioxide molecule, CO,, and the carbonate ion, CO2- (1) Draw the complete Lewis electron-dot structure for each species. (ii) Account for the fact that the carbon-oxygen bond length in CO, - is greater than the carbon-oxygen bond length in CO, (h) Consider the molecules CF, and SF, (1) Draw the complete Lewis electron-dot structure for each molecule. (11) In terms of molecular geometry, account for the fact that the CF, molecule is nonpolar, whereas the SF, molecule is polar
The fact is the carbon-oxygen bond length in CO₃²⁻ is greater than the carbon-oxygen bond length in CO₂ because of its bond order. CF4 has a tetrahedral geometry, so the bond dipoles cancel, leading to a nonpolar molecule. SF4 exhibits a trigonal bipyramidal electronic geometry, with the lone pair of electrons so SF₄ is polar.
Due to resonance, the bond character of CO₃²⁻ lies between a single and a double bond, whereas CO₂ has two double bonds (linear structure with carbon as the central atom, O=C=O). Bond length is inversely proportional to bond order, and bond order depends on the number of bonds. Therefore, CO will have triple bonds, while CO₂ will have two double bonds. Therefore, the order of bond length will be CO₃²⁻>CO₂ >CO.
Due to the tetrahedral geometry of CF₄, the bond dipoles cancel and the molecule becomes nonpolar. The core S atom is surrounded by five pairs of electrons, and SF₄ displays a trigonal bipyramidal electronic geometry.
The molecule is polar because the bond dipoles in this configuration do not cancel.
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The half life for a first-order reaction is 148 minutes. What is the rate constant of this reaction if the concentration is 1.10M after 50 minutes has elapsed?
Answer:
The rate constant for the first-order reaction can be calculated by using the equation: k = 0.693 / t1/2. In this case, the half life is 148 minutes, so the rate constant is calculated as 0.0047 per minute. This means that, after 50 minutes have elapsed, the concentration of the reaction should be 1.10M * e^(-0.0047 * 50) = 0.962M.
write the principle involved in the manufacture of steel by open health process
Answer:
The open-hearth furnace will use the heat of combustion of gaseous or liquid fuels to convert a charge of scrap and liquid blast-furnace iron to liquid steel. The high flame temperature required for melting is obtained by preheating the combustion air and, sometimes, the fuel gas.
Explanation:
