What mass of oxygen gas, O2, from the air is consumed in the combustion of 702 g of octane, C8H18, one of the principal components of gasoline?
Select one:
A. 13.22 g
O B. 25.0 g/mol
O C. 32.0 g
O D. 33.22 g/mol
O E. 39.0 g

Answers

Answer 1

The principal components of gasoline is 702 g of octane.

Thus, Crude oil and other petroleum liquids are used to create gasoline, a fuel. The majority of gasoline is utilized in car engines.

For retail sale at gas stations, finished motor gasoline is produced at petroleum refineries and blending facilities.

In order to create finished motor gasoline, petroleum refineries primarily produce gasoline blendstocks, which must be blended with other liquids. In order to create finished motor gasoline in various grades and formulas, gasoline blendstocks, finished gasoline, and fuel ethanol are combined at blending terminals.

Thus, The principal components of gasoline is 702 g of octane.

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Related Questions

Change the following word equations into formula equations AND balance them using the tally method.

*The answers have been provided under each equation, all you have to do is show your work using the tally method!*

a. copper(I) iodate + potassium carbonate → potassium iodate + copper(I)carbonate

2Cu(IO3) + K2(CO3) → 2K(IO3) + Cu2(CO3)

b. iron(III) carbonate + cesium → cesium carbonate + iron

Fe2(CO3)3 + 6Cs → 3Cs2(CO3) + 2Fe

c. sodium chlorate → sodium chloride + oxygen

2Na(ClO3) → 2NaCl + 3O2

Answers

The balanced  chemical equations with suitable coefficients are 2 Cu(IO₃) + K₂(CO₃) → 2 KIO₃ + Cu₂CO₃, Fe₂(CO₃)₃ + 6 Cs → 3 Cs₂(CO₃) + 2 Fe,

2 NaClO₃ → 2 NaCl + 3 O₂.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3 , is

Answers

The total number of atoms in 3.75 mol of ammonium nitrate, NH4NO3, is equal to the Avogadro's number, which is 6.022 x 10^23, times the number of moles, which is 3.75 in this case.

Thus, the total number of atoms in 3.75 mol of ammonium nitrate is equal to 2.26 x 10^24 atoms.

This number can be further broken down into the number of atoms of each element present in the compound. Ammonium nitrate is composed of two elements, nitrogen (N) and hydrogen (H). For each mole of ammonium nitrate, there are 4 moles of hydrogen atoms and 2 moles of nitrogen atoms.

Therefore, in 3.75 moles of ammonium nitrate, there are 15 moles of hydrogen atoms and 7.5 moles of nitrogen atoms, which is equal to 9 x 10^24 hydrogen atoms and 4.05 x 10^24 nitrogen atoms.

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I am trying to utilize an acid-base neutralization reaction to remove limescale (CaCO3) from my faucet using hydrochloric acid (HCl). Which would help make this reaction go faster?


There is no way to speed up the reaction

Use less concentrated HCl solution

Using something abrasive to grind the limescale into smaller pieces

Cooling down the faucet by running cold water

Answers

Using a more concentrated HCl solution would help make the acid-base neutralization reaction go faster in removing limescale (CaCO₃) from your faucet.

What would help make this reaction go faster?

The rate of the reaction generally increases with the concentration of the reactants, so a more concentrated HCl solution will react more quickly with the limescale than a less concentrated one.

Using something abrasive to grind the limescale into smaller pieces might help expose more surface area of the limescale to the acid, but it would not directly affect the rate of the acid-base neutralization reaction.

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Can anyone help me with this??

Answers

In the region labelled as H, weather fronts are most likely to be located. A weather front comprises a line dividing air masses with various differences in their attributes,

A weather front comprises a line dividing air masses with various differences in their attributes, including air density, winds, temperatures, or humidity. These variations frequently result in disturbed or unstable weather at the boundary.

For instance, although warm fronts usually arrive accompanied by stratiform precipitation with fog, cold fronts can bring belts of thunderstorms with cumulonimbus precipitation and be preceded by squall lines. Dry lines, which are softer humidity gradients, can cause severe weather in the summer. In the region labelled as H, weather fronts are most likely to be located.

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Help with number 17 please

Answers

The partial pressure of O₂ is 0.954 atm

The moles O₂ that formed is 0.000859 moles

The mass of NaNO₃ that reacted is 0.146 g.

What is Dalton's law of partial pressures?

The balanced chemical equation for the reaction is given below:

2 NaNO₃ (s) → 2 NaNO2 (s) + O₂(g)

Using Dalton's Law of partial pressures:

The partial pressure of O₂ = Total pressure - Partial pressure of water vapor

The partial pressure of O₂ = (0.98 atm) - (0.026 atm)

The partial pressure of O₂ is 0.954 atm

b. Using the ideal gas law to determine the moles of oxygen gas formed:

PV = nRT

Making subject of the formula:

n = PV/RT

n = (0.954 * 0.0230)/(0.0821 * 295.15)

n = 0.000859 moles

Moles of O₂ formed = 0.000859 moles

c. the mass of NaNO₃ that reacted is calculated as follows:

mass NaNO₃ = moles NaNO₃ x molar mass NaNO₃

molar mass NaNO = 84.99 g/mol

From the mole ratio of the reaction, moles of NaNO₃ = 0.000859 moles * 2

moles of NaNO₃ = 0.001718 moles

mass NaNO3 = 0.001718 * 84.99

mass NaNO3 = 0.146 g NaNO₃

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How many grams of KNO3 should be used to prepare 554.49 mL of a/an 4.85 M solution?

Answers

The mass (in grams) of KNO₃ needed to prepare 554.49 mL of 4.85 M KNO₃ solution is 271.69 grams

How do i determine the mass of KNO₃ needed?

First, we shall determine the mole of KNO₃. Details below:

Volume = 554.49 mL = 554.49 / 1000 = 0.55449 LMolarity = 4.85 MMole of KNO₃ =?

Molarity = Mole / Volume

Cross multiply

Mole = molarity × volume

Mole of KNO₃ = 4.85 × 0.55449

Mole of KNO₃ = 2.69 moles

Finally, we shall determine the mass of KNO₃ needed. Details below:

Mole of KNO₃ = 2.69 molesMolar mass of KNO₃ = 101 g/molMass of KNO₃ = ?

Mass = Mole × molar mass

Mass of KNO₃ = 2.69 × 101

Mass of KNO₃ = 271.69 grams

Therefore, the mass of KNO₃ needed to prepare the solution is 271.69 grams

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A 200 g sample including calcium (Ca), reacts with the excess of hydrochloric acid
(HCl). If 4 g of hydrogen gas (H2) is produced, calculate the Ca% of sample?
Ca + HCl → CaCl2 + H2 (Ca: 40 g/mol and H: 1 g/mol)

Answers

A 200 g sample including calcium (Ca), reacts with the excess of hydrochloric acid.  If 4 g of hydrogen gas (H2) is produced, 36.3% is mass percent of calcium of sample.

The term mass percent is sometimes referred to as weight percent or w/w%. The total mass of every one of the atoms in a mole that makes up the compound is the molar mass. The total of all the individual percentages ought to equal 100 percent.

Check the last important number for rounding errors to ensure that the percentage add up. The relative amounts of the components in a compound of chemicals are described by their mass percent composition. Mass composition in percent is also referred to as mass percent. The symbol for it is w/w%.

Ca + HCl → CaCl[tex]_2[/tex]+ H[tex]_2[/tex]

moles of calcium = 200/ 40= 5 moles

moles of CaCl[tex]_2[/tex] = 5moles

mass of CaCl[tex]_2[/tex] = 5× 110.98= 550g

mass % of Ca = (200/550g )×  100=36.3%

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The combustion of octane, C8H18, proceeds according to the reaction shown.

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)

If 354 mol of octane combusts, what volume of carbon dioxide is produced at 15.0 ∘C
and 0.995 atm?

Answers

The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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What has a higher boiling point C2H4O or CH3OH

Answers

Answer:

Explanation:

i wish i can help

If a sulfuric acid (H₂SO₄, MM = 98.09 g/mol) solution is completely neutralized with 61.37 mL of the NaOH solution above (from question 2) what was the mass in grams of sulfuric acid in the solution. Remember, you need a balanced chemical reaction for stoichiometry. (do not forget about SF)

Answers

Taking into account the reaction stoichiometry, 3.00713 grams of H₂SO₄ is completely neutralized with 61.37 mL of the NaOH.

Reaction stoichiometry

In first place, the balanced reaction is:

H₂SO₄ + 2 NaOH  → Na₂SO₄ + 2 H₂O

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

H₂SO₄: 1 moleNaOH: 2 moles  Na₂SO₄: 1 moleH₂O: 2 moles

The molar mass of the compounds is:

H₂SO₄: 98 g/moleNaOH: 40 g/moleNa₂SO₄: 142 g/moleH₂O: 18 g/mole

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

H₂SO₄: 1 mole× 98 g/mole= 98 gramsNaOH: 2 moles× 40 g/mole= 80 gramsNa₂SO₄: 1 mole× 142 g/mole= 142 gramsH₂O: 2 moles× 18 g/mole= 36 grams

Mass of H₂SO₄ required

A sulfuric acid solution is completely neutralized with 61.37 mL (0.06137 L) of the NaOH solution. Assuming the concentration of the NaOH solution is 1.0 M, the moles of NaOH that react is calculated as:

Moles of NaOH reacting = concentration× volume in liters

Moles of NaOH reacting = 1 M× 0.06137 L

Moles of NaOH reacting = 0.06137 moles

Now, the following rule of three can be applied: If by reaction stoichiometry 2 moles of NaOH react with 98 grams of H₂SO₄, 0.06137 moles of NaOH react with how much mass of H₂SO₄?

mass of H₂SO₄= (0.06137 moles of NaOH× 98 grams of H₂SO₄)÷2 moles of NaOH

mass of H₂SO₄= 3.00713 grams

Finally, 3.00713 grams of H₂SO₄ is required.

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Calculate the volume in mL of 0.727 M Ca(OH)2 needed to neutralize 22.8 mL of 0.390 M H3PO4 in a titration.

Answers

51.4 mL is the  volume in mL of 0.727 MCa(OH)₂  needed to neutralize 22.8 mL of 0.390 M H₃PO₄  in a titration.

A measurement of three-dimensional space is volume. It is frequently expressed in numerical form using SI-derived units or different imperial or US-standard units (such the gallon, quart, and cubic inch). Volume and length (cubed) have a symbiotic relationship.

The volume much a container is typically thought of as its capacity, not as the amount of space it takes up. In other words, the volume is the volume of fluid (liquid or gas) that the container may hold.

2H₃PO₄ + 3Ca(OH)₂ —> Ca₃(PO₄)₂ + 6H₂O

MaVa / MbVb = nA / nB

( 0.390  ×  22.8) / (0.727 × Vb) = 2/3

Vb = 51.4 mL

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Select the correct answer.

What is a nonpolar covalent bond?

A.
a bond between two nonmetal atoms
B.
a bond in which electrons are shared unequally
C.
a bond with ΔEN greater than 0.5
D.
a bond between two atoms that have equal electronegativities

Answers

Answer:

D. a bond between two atoms that have equal electronegativities

Explanation:

Covalent bonds involve 2 atoms sharing electrons.

Covalent Bonds

There are 3 types of bonds: metallic, ionic, and covalent. Metallic bonds occur between 2 metals that exist in a "sea of electrons." Ionic bonds have high electronegativity differences and occur between a metal and a nonmetal. Finally, as stated above, covalent bonds occur when 2 atoms share their electrons. Covalent bonds usually occur between two nonmetals. However, there are 2 types of covalent bonds: polar and nonpolar.

Nonpolar Bonds

Both polar and nonpolar bonds involve the sharing of electrons; however, polar bonds share electrons unequally. This is caused by an electronegativity difference greater than 0.5. When two atoms have equal electronegativities, they share the electrons equally. This creates a nonpolar bond.  

In addition to pH meter, what other methods and/or experimental devices may be used to determine the Ksp values of sparingly soluble electrolytes? Please give at least three examples.

What factor(s) may change Ksp values? Please elaborate your answer.

Answers

The solubility product of a sparingly soluble salt is defined as the product of molar concentrations of its ions in a saturated solution of it at a given temperature. The two important factors that affect the solubility product are pressure and temperature.

Using an electrical conductivity measurement, determine the ion concentration in a saturated solution and use this number to compute the solubility product.

Using a colorimetric technique, determine the ion concentration in a saturated solution and use this number to compute the Ksp.

It is the pressure which affects the solubility of gases only.

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A certain bimolecular reaction at 40 °C at an activation energy of 30 kJ/mol. The addition of a catalyst reduces the activation energy by a factor of 2. How much faster does the catalyzed occur?
Select one:
OA. 318.63
OB. 358.63
C. 338.63
OD. 378.63

Answers

To find the rate enhancement due to the catalyst, we can use the Arrhenius equation:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/mol·K), and T is the temperature in Kelvin.

First, we need to convert the temperature from Celsius to Kelvin:

40°C + 273.15 = 313.15 K

Now, let's find the ratio of the rate constants for the catalyzed and uncatalyzed reactions:

k_catalyzed / k_uncatalyzed = e^((Ea_uncatalyzed - Ea_catalyzed) / RT)

Since the catalyst reduces the activation energy by a factor of 2:

Ea_catalyzed = 30 kJ/mol / 2 = 15 kJ/mol

Convert the activation energies to J/mol:

Ea_uncatalyzed = 30,000 J/mol
Ea_catalyzed = 15,000 J/mol

Now, plug in the values:

k_catalyzed / k_uncatalyzed = e^((30,000 J/mol - 15,000 J/mol) / (8.314 J/mol·K × 313.15 K))

k_catalyzed / k_uncatalyzed ≈ 358.63

The catalyzed reaction occurs approximately 358.63 times faster. So, the correct answer is OB. 358.63.

At which time does this reaction reach equilibrium?

T1
T2
T3
It does not reach equilibrium


Which is true when a reaction is in equilibrium?

The reaction has stopped entirely
Only products are present
The forwards and reverse reactions are occurring at the same rate, and no change in concentration is observed
Only reactants are present

Answers

Equilibrium in the reaction occurs at time, T2 (option B)The statement that is true when a reaction is in equilibrium is the forwards and reverse reactions are occurring at the same rate, and no change in concentration is observed (option B).

What is equilibrium in a chemical reaction?

Equilibrium in a chemical reaction is the state of a system in which the rate of the forward reaction is equal to the rate of the reverse reaction.

In a chemical reaction, chemical equilibrium is the state in which both the reactants and products are present in concentrations which have no further changes.

According to this question, the reactants (blue line) equates the products (red line) in the time, T2.

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04.05 Ecological Tolerance Lab Worksheet Student Name: Annalise Clark Time Estimate: 60 minutes Pre-Activity Questions: Use information from the lesson to answer these questions. Answer in complete sentences. What conditions can impact the ecological tolerance of a species? How does island biogeography decrease ecological tolerance? Data: Trial Blue Island Red Island Green Island Yellow island 1 2 3 4 5 Calculations: Calculate the mean value for each island and record it in the data table. To calculate mean, add all the values of the trials and divide the value by the number of trials, which is five. Please show your work. Example: Trial One: 3 beans Trial Two: 4 beans Trial Three: 5 beans Trial Four: 7 beans Trial Five: 2 beans Mean = 3 + 4 + 5 + 7 + 2 = 21/5 = 4.2 Blue Island Red Island Green Island Yellow Island Unless Otherwise Noted All Content © 2021 Florida Virtual School Mean Making Connections: Use your lesson and the results of your activity to answer the questions. Answer questions in complete sentences. Which islands had the most successful migrations? Explain why. How does a successful immigration rate impact the biodiversity of an island? How would the migration of generalist species onto the green island affect specialist species living on the island? Based on your data, which islands would you select as wildlife refuges? Explain your reasoning. Did the lab activity follow the island biogeography model? Why or why not?

Answers

The islands with the most successful migration were the blue island and the yellow island with mean values ​​of 4.6 and 4.4. A successful rate of immigration affects the island's biodiversity by introducing new species into the environment, which increases the diversity of organisms living on the island.

Migration of generalist species to a green island would affect specialized species living on the island by competing for resources, as generalist species are better adapted to different environments.

Based on the data, the blue and yellow islands would be the best choice for wildlife refuges because they had the highest mean values ​​and would be more likely to have higher immigration success.

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Step 1: A↽−−⇀B+C equilibrium Step 2: C+D⟶E slow Overall: A+D⟶B+E
Determine the rate law for the overall reaction, where the overall rate constant is represented as

Answers

The rate law for the reaction can be written as -

rate= k[C] [D]

The rate of reaction or reaction rate is the speed at which reactants are converted into products.

When we talk about chemical reactions, it is a given fact that rate at which they occur varies by a great deal. Some chemical reactions are nearly instantaneous, while others usually take some time to reach the final equilibrium.

The rate of the reaction is governed by the slow step.

This gives the rate equation-

rate= k[C] [D]

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If a jar of saltwater sits in the sun, the liquid level steadily decreases, and finally, crystals appear. Explain what is happening.​

Answers

When a jar containing saline solution is exposed to sunlight, its liquid content gradually diminishes and eventually forms crystals as a result of the evaporation process.

What is the saltwater  about?

The energy from the sun's heat accelerates the movement of molecules in saltwater, which leads to their subsequent release from the liquid surface as water vapor. As a result of this process, the moisture transforms into gas and ascends, scattering throughout the atmosphere.

The concentration of salt in the remaining liquid increases as water evaporates from saltwater, as salt is unable to evaporate like water. As time passes, the salt concentration within the water triples to a point where it becomes incapable of remaining dissolved and commences the process of crystal formation.

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Determine whether each of the following will increase or decrease the rate of a chemical reaction

Answers

Lowering the temperature/cooling the system: Decreases the rate of a chemical reaction.Decreasing the volume of the system: Increases the rate of a chemical reaction.Increasing the pressure of the system: Increases the rate of a chemical reaction.Decreasing the surface area of the reactants: Decreases the rate of a chemical reaction.Increasing reactant concentration: Increases the rate of a chemical reaction.Adding a catalyst: Increases the rate of a chemical reaction.

Lowering the temperature slows down the motion of molecules, leading to fewer effective collisions between reactant molecules, thus decreasing the rate of the reaction.

Decreasing the volume of the system or increasing the pressure of the system can increase the frequency of collisions between reactant molecules, thus increasing the rate of the reaction. This is because a decrease in volume or an increase in pressure leads to an increase in the concentration of reactants in the system.

Decreasing the surface area of the reactants decreases the number of collision sites available, leading to a decrease in the rate of the reaction.

Adding a catalyst lowers the activation energy required for the reaction to take place, leading to an increase in the rate of the reaction.

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Which are true of a catalyst (select multiple)?

A catalyst lowers the activation energy of a reaction


A catalyst raises the activation energy of a reaction


The concentration of the catalyst will increase during the chemical reaction


The concentration of the catalyst will decrease during the chemical reaction


The concentration of the catalyst will remain constant during the chemical reaction

Answers

The following statements are true of a catalyst:

- A catalyst lowers the activation energy of a reaction
- The concentration of the catalyst will remain constant during the chemical reaction

Therefore, the correct answer is:

- A catalyst lowers the activation energy of a reaction
- The concentration of the catalyst will remain constant during the chemical reaction

Balance the following formula equations using the tally method and show your work:

*I have provided the answers for these equations, all you need to do is show your work using the tally method!*

_____ Zn3(PO4)2 + ___2__ AlCl3 → ___3__ ZnCl2 + ___2__ Al(PO4)
___2__ Cr(OH)3 → _____ Cr2O3 + ___3__ H2O
___3__ Na(OH) + _____ H3(PO4) → _____ Na3(PO4) + ___3__ H2O
___2__ Li + ___2__ H2O → ___2__ Li(OH) + ______ H2

Answers

The balanced chemical equations using suitable coefficients are  Zn₃(PO₄)₂+ 2 AlCl₃ → 3 ZnCl₂ + 2 Al(PO₄),2 Cr(OH)₃ → Cr₂O₃ +3 H₂O,3 NaOH+ H₃PO₄ → Na₃PO₄+ 3 H₂O,2 Li + 2 H₂O → 2 LiOH+ H₂.

Chemical equation is a symbolic representation of a chemical reaction which is written in the form of symbols and chemical formulas.The reactants are present on the left hand side while the products are present on the right hand side.

A plus sign is present between reactants and products if they are more than one in any case and an arrow is present pointing towards the product side which indicates the direction of the reaction .There are coefficients present next to the chemical symbols and formulas .

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How many moles of O2 are needed to combine with 6.2 moles of phosphorus

Answers

The number of moles of O₂ are needed to combine with 6.2 moles of phosphorus is 7.75 moles.

How to calculate number of moles?

The number of moles of a substance can be calculated using stoichiometry. Stoichiometry is the quantitative relationship between the reactants and products of a specific reaction or equation.

According to this question, phosphorus reacts with oxygen gas as follows:

4P + 5O₂ → 2P₂O5

Based on the above equation, 4 moles of phosphorus reacts with 5 moles of oxygen.

If 6.2 moles of P reacts, 7.75 moles of oxygen gas will be produced.

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The specific heat of a certain type of metal is 0.128 J/(g-°C). What is the final temperature if 305 J of heat is added to 91.2 g of
This metal, initially at 20.0 °C?
T final = __ °C
Can someone please help if you know the topic I’ll mark brainliest, if not please do not answer.

Answers

Answer:  46.07 °C.

Explanation:

What is the minimum concentration of fluoride ions necessary to precipitate CaF2 from a 5.25 x 10-3 M solution of Ca(NO3)2? Ksp of CaF2 = 3.9 x 10-11

Answers

The minimum concentration of fluoride ions necessary to precipitate CaF₂ from a 5.25 x 10⁻³ M solution of Ca(NO₃)₂ is 2.02 x 10⁻⁶ M.

Balanced equation for the precipitation of CaF₂ from Ca(NO₃)₂ is:

Ca(NO₃)₂ + 2NaF → CaF₂ + 2NaNO₃

The solubility product expression for CaF₂ is;

Ksp = [Ca²⁺][F⁻]2

We can assume that all of the Ca(NO₃)₂ will dissolve in water since it is a highly soluble salt. Therefore, we need to determine the minimum concentration of fluoride ions ([F⁻]) necessary to exceed the solubility product constant (Ksp) and precipitate CaF₂.

Let x be the concentration of fluoride ions that will react with the calcium ions from the Ca(NO₃)₂ solution to form CaF₂.

According to stoichiometry, the [Ca²⁺] concentration will be equal to the initial concentration of Ca(NO₃)₂, which is 5.25 x 10⁻³ M.

The [F⁻] concentration will be equal to 2x, since two fluoride ions are required for each Ca²⁺ ion to form CaF₂.

Using the Ksp expression, we can write;

Ksp = [Ca²⁺][F⁻]2

Substituting the known values, we get:

3.9 x 10⁻¹¹ = (5.25 x 10⁻³)(2x)²

Solving for x, we get;

x = 2.02 x 10⁻⁶ M

Therefore, the minimum concentration of fluoride ions necessary is 2.02 x 10⁻⁶ M.

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on (1 point)
The vapor pressure of carbon disulfide is 355.6 torr at 25°C. What is the vapor pressure of a solution prepared by dissolving 11.60 g naphthalene
(C₁0H, Molar Mass-128.2 g/mol) in 155 ml. CS₂ liquid (Molar Mass - 76.14 g/mol, density-1.261 g/ml)? Assume the solution obeys Raoult's law.
and treat naphthalene as a nonvolatile solute.

____ torr

Answers

According to Raoult's law, the vapor pressure of a solution is proportional to the mole fraction of the solvent present in the solution. Since naphthalene is a nonvolatile solute, its mole fraction is negligible, and we can assume that the vapor pressure of the solution is equal to the vapor pressure of pure carbon disulfide, which is given as 355.6 torr.
To find the mole fraction of CS₂, we need to first calculate the moles of CS₂ present in the solution. The mass of CS₂ present in 155 ml of solution is:
mass of CS₂ = volume of solution x density of CS₂ = 155 ml x 1.261 g/ml = 195.76 g
The moles of CS₂ can be calculated as:
moles of CS₂ = mass of CS₂ / molar mass of CS₂ = 195.76 g / 76.14 g/mol = 2.569 mol
The mole fraction of CS₂ is then:
mole fraction of CS₂ = moles of CS₂ / total moles of solute and solvent = 2.569 mol / (2.569 mol + 0.0905 mol) [since weight of napthalene =11.60g, molar mass=128.2 g/mol, moles of napthalene=11.60/128.2=0.0905 mol] = 0.966
Finally, using Raoult's law, the vapor pressure of the solution is:
vapor pressure = mole fraction of CS₂ x vapor pressure of pure CS₂ = 0.966 x 355.6 torr = 343.2 torr
Therefore, the vapor pressure of the solution is 343.2 torr.

Assign the oxidation numbers of each element given bold in the following chemical species: HCI, NH3, NO3, K₂Cr₂O7, Hg₂Cl2, HgCl2, Al(OH)3, Na3PO4​

Answers

Answer:

HCI: H has an oxidation number of +1 and Cl has an oxidation number of -1.

NH3: N has an oxidation number of -3 and each H has an oxidation number of +1.

NO3: N has an oxidation number of +5 and each O has an oxidation number of -2.

K₂Cr₂O7: K has an oxidation number of +1, Cr has an oxidation number of +6, and each O has an oxidation number of -2.

Hg₂Cl2: Each Hg has an oxidation number of +1 and each Cl has an oxidation number of -1.

HgCl2: Hg has an oxidation number of +2 and each Cl has an oxidation number of -1.

Al(OH)3: Al has an oxidation number of +3, each O has an oxidation number of -2, and each H has an oxidation number of +1.

Na3PO4: Na has an oxidation number of +1, P has an oxidation number of +5, and each O has an oxidation number of -2.

If you mix 20.0 mL of 0.010 M MgCl2with 20.0 mL of 0.0020 M Na2CO3, will magnesium carbonate, MgCO3, precipitate out from the solution? Explain. Given: Ksp(MgCO3) = 4.0 × 10-5.

If you add AgCl to a 0.10 M solution of NaCl(aq), will the solubility of AgCl be greater than, less than, or equal to its solubility in water? Justify your answer.

Answers

.85 because of the number added too AgCl of each solution

help What is the bestmethod for the preservation of water quality?

Answers

In an ecosystem, the best method  for the preservation of water quality is  that humans should cease all recreational and agricultural uses of water resources.

Ecosystem is defined as a system which consists of all living organisms and the physical components with which the living beings interact. The abiotic and biotic components are linked to each other through nutrient cycles and flow of energy.

Energy enters the system through the process of photosynthesis .Animals play an important role in transfer of energy as they feed on each other. Components present include air, water, soil,etc.

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What happens in a Brønsted-Lowry acid-base reaction?

Answers

A proton transfer from one molecule or ion to another., hence option D is the correct answer.

What is a proton?

The proton is an electrically charged subatomic particle. They can be present in every element's atomic nucleus. Protons are always accompanied by neutrons in practically every element.

The nucleus of the simplest element, hydrogen, is the sole exception. Hydrogen has only one proton and no neutrons.

A proton is commonly represented by the symbols p or p+. A proton is the nucleus of a hydrogen atom or an H+ ion.

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6. On a cold day a person takes in a breath of 450.0 mL of air
at 756 mmHg and -10.0°C. Assuming that amount and pressure
remain constant, what is the volume of the air when it warms to
body temperature (37.0°C) in the lungs?

Answers

The volume of the air when the breath is warm to body temperature (37.0°C) in the lungs is 530.4 mL

How do I determine the volume at 37 °C?

First, we shall list out the given parameters from the question. This is given below:

Initial volume (V₁) = 450 mLPressure = 756 mmHg = ConstantInitial temperature (T₁) = -10 °C = -10 + 273 = 263 KNew temperature (T₂) = 37 °C = 37 + 273 = 310 KNew volume (V₂) =?

The volume of the breath when it is warm to body temperature (37.0°C)    can be obtained by using Charles' law equation as shown below:

V₁ / T₁ = V₂ / T₂

450 / 263 = V₂ / 310

Cross multiply

263 × V₂ = 450 × 310

263 × V₂ = 139500

Divide both side by 263

V₂ = 139500 / 263

V₂ = 530.4 mL

Thus, the volume is 530.4 mL

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