What must be true for line EF to not intersect plane L?

What Must Be True For Line EF To Not Intersect Plane L?

Answers

Answer 1

Answer:

If line EF is parallel to line CD, it will not intersect plane L.


Related Questions

Which expression represents the
number of reams of paper the company
produced during the second year?

Answers

The expression that represents the number of reams of paper produced in the second year is 4.704 x [tex]10^{10}[/tex] (option d)

What is the expression that represents the reams produced in the second year.

The quantity of paper produced in the first year is written in scientific notation. Scientific notation is used to compress larger numbers into smaller numbers.  

In order to write a number in scientific notation, the number is written as a decimal number, between 1 and 10 and multiplied by a power of 10.

For example, The number 5 x 10³ is equivalent to 500

Paper produced in the second year = paper produced in the first year x 5.6

(8.4 x [tex]10^{9}[/tex] ) x 5.6 = 47.04 x [tex]10^{9}[/tex]

4.704 x [tex]10^{9 + 1}[/tex]

= 4.704 x [tex]10^{10}[/tex]

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What is the mean of 13, 7, 8 and 4

Answers

Answer:

16

Step-by-step explanation:

Mean is same as average. To find the average, add all items and divide the sum by the number of items in the list.

Avg = (13 + 7 + 8 + 4) / 2 = 32 / 2 = 16

Hi there,

please see below for solution steps :

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

To find the mean you first need to add all numbers and divide by how many there are :

  [tex]\sf{\dfrac{13+7+8+4}{4}}[/tex]

⨠ simplify

[tex]\sf{\dfrac{32}{4}}[/tex]

[tex]\boxed{\sf 8}[/tex]                                                                                              [tex]\tiny\pmb{\sf{Frozen \ melody}}[/tex]

‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗‗

The answer to this problem please and thank you

Answers

Answer:

C

Step-by-step explanation:

The red dotted line we see is the asymptote, which is a line that the functions will never cross.

The asymptotes we see currently is:

x = -3

and

x = 2

We can find the vertical asymptotes using the denominator of the function since the x value that makes the denominator 0 is the asymptote. Since -3 and 2 is the asymptote, the denominator of the function will be:

(x-2) (x+3)

If we look at the answer choices, we can see that C is the only option with a denominator of (x-2)(x+3), so that is our answer.

Answer:

C

Step-by-step explanation:

there are 2 vertical asymptotes at x = - 3 and x = 2

then the factors on the denominator will be (x + 3) and (x - 2)

then

f(x) = [tex]\frac{1}{(x-2)(x+3)}[/tex]

Type the correct answer in each box.
[3 x 6 1 -8 5] and -5A = [-15 35 -30 -5 40 y]
The value of x in A is ___ and the value of y in B is ___

Answers

The value of x in A is 7 and the value of y in B is -15

Functions and values

Functions are represented as a function of variable. Given the following sets of numbers.

A = [3 x 6 1 -8 5] and;

-5A = [-15 35 -30 -5 40 y]

Equate the individual values to have:

-5A= -15

Divide both sides by -5

-5A/-5 = -15/-5
A = 3

Determine the value of y

-5A = y

-5(3) = y

y = -15

Similarly;

5x = 35

x = 35/5

x = 7

Hence the value of x in A is 7 and the value of y in B is -15

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Answer:

The value of x in A is -7

The value of y in B is -25

Step-by-step explanation:

Everything in the first matrix can be multiplied by -5 to equal everything in the second matrix, since we are dealing with x and y, only the first and third rows matter.

In the first row, we know that 3 times -5 equals -15 and x times -5 equals 35

therefore, -5x=35, with basic algebra we find that X = -7

In the third row, we know that 8 times -5 is 40 and 5 times -5 equals y.

This takes just basic multiplication to find that Y = -25

Solve the inequality and enter your solution as an inequality in the box below.
Do not use spaces in your answer.
2+ x>-8

Answers

Answer:

x > -10

Step-by-step explanation:

2 + x > -8

x > -8 - 2

x > -10

Answer:

x>-10

Step-by-step explanation:

2+x-2>-8-2

x>-10

Mary walks from corner D to corner E to corner F on a city block that measures 264 feet wide and 900 feet long. Kate walks diagonally across the city block from corner D to corner F. How much less distance did Kate walk than Mary to get to corner F? Round your answer to the nearest whole foot. Enter only the number.

Answers

Step-by-step explanation:

we have a rectangle, that is then cut in half diagonally into 2 right-angled triangles.

in our problem it does not matter which side is the larger and which is the shorter one, because the distance calculation for both cases involve one short and one long side. the sequence does not matter.

Mary walks one short and one large side to get to the opposite corner (from D to F) :

264 + 900 = 1,164 ft

Kate walks diagonally. and that diagonal is the Hypotenuse of the right-angled triangle with a short and a long side of the rectangle.

so, Pythagoras applies :

c² = a² + b²

with c being the Hypotenuse (the side opposite of the 90° angle), and a and b are the legs.

in our case that means

diagonal² = 264² + 900² = 69,696 + 810,000 =

= 879,696

diagonal = sqrt(879,696) = 937.9211054... ft ≈ 938 ft

so, Kate walked

1,164 - 938 = 226 ft

less than Mary.

2. The sum to infinity of an exponential sequence with a positive common ratio is 25 and the first two terms is 16. find fifth term

Answers

Answer:

0

Step-by-step explanation:

hi

hi

haha

and

and

are doing

dog food

0 answer

(scroll to bottom for answer)The equation you want to be using is A(n)+1=(A(n))r because this is a exponential sequence

r represents the ratio, which you said was 25, so basically you said

A(n)

____     = 25

A(n)-1

rthe sum of the first 2 terms are 16, the first two terms being A1 and A2, they need to follow the equation:

A2

__  = 25

A1

lets give them variables to make this a bit easier-

A1 will be x and A2 will be y

x+y=16(1st equation)

y/x=25, 25x=y(2nd equation)

(if you multiply y/x=25 by x you will get that 25x=y, which is where that other equation came from)

going back to x+y=16

subtract y from both sides

x=16-y

use substitution and solve for the second equation

25(16-y)=y

distribute

400-25y=y

add 25y to both sides to get rid of the -25y on the left side while keeping the equation equal

400=26y

divide both sides by 26 and you get 400/26 which simplifies to 200/13

after all that you need to multiply 200/13 by 25, 3 separate times

200                              1875000

___ x 25 x 25 x 25= _________

13                                      13

pull it into a calculator and you get something like

142846.153846

If the vertex of a parabola is (-4,-7), what is the axis of symmetry?

Answers

Answer:

-4

Step-by-step explanation:

Given vertex, the axis of symmetry is x = h.

Simplify 4/16 to lowest terms and find an equivalent fraction that has a denominator of 32

Answers

lowest terms- 1/4
equivalent fraction- 8/32

What is 6 wholes divided by 2/3 ?

Answers

Answer:

9

Step-by-step explanation:

6 ÷ 2/3   =    6 /  (2/3 )   =  (6/1) / (2/3)  = 6/1  x  3/2 = 18/2 = 9

m∠1 =

✔ 131

degrees

m∠2 =

✔ 49

degrees

m∠3 =

✔ 112

degrees

Answers

Answer:

what is the question show the pic

This box plot represents the number of pages that several students in sixth grade have read in a month. Use the shape of the box plot to describe the data set. Select all that apply.





The total range of pages read is 20 .
The lowest quarter of data is more dispersed than the highest quarter of data.
One-half of the students have read between 72 and 86 pages.
The median number of pages of the sixth graders is 76.
One-fourth of the students have read weigh 72 and 76 pages.
One-fourth of the students read more than 76 pages.
One-fourth of the students have read less than 72 pages.

Answers

The true statements are:

The median number of pages of the sixth graders is 76.

One-fourth of the students have read less than 72 pages.

One-half of the students have read between 72 and 86 pages.

What are the true statements?

A box plot is used to study the distribution and level of a set of scores. The box plot consists of two lines and a box. the two lines are known as whiskers.

The end of the first line represents the minimum number and the end of the second line represents the maximum number. The difference between the minimum number and the maximum number is the range.

Range = 92 - 61 = 31

On the box, the first line to the left represents the lower (first) quartile. 1/4 of the score represents the lower quartile. The next line on the box represents the median. 1/2 of the score represents the median. The third line on the box represents the upper (third) quartile. 3/4 of the scores represents the upper quartile.

First quartile = 72

Third quartile = 86

Median = 76

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Peter and Blair recently reviewed their future retirement income and expense projections. They hope to retire in 29 years and anticipate they will need funding for an additional 20 years. They determined that they would have a retirement income of $54,000 in today's dollars, but they would actually need $75,017 in retirement income to meet all of their objectives. Calculate the total amount that Peter and Blair must save if they wish to completely fund their income shortfall, assuming a 2 percent inflation rate and a return of 6

Answers

Based on the number of years that Peter and Blair have till retirement, the total amount that they need to save to completely fund their income shortfall is $65,545.72.

What amount do Peter and Blair need to save?

First, find the income shortfall:

= 75,017 - 54,000

= $21,017

The amount they need to save to cover this shortfall is the future value of this amount at retirement. The rate will be the real rate which is:

= 6% - 2% inflation

= 4%

The future value is:

= Income shortfall x future value interest factor, 4%, 29 years

= 21,017 x 3.1187

= $65,545.72

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10005²³ x + cos x = 11 sin²x = 9​

Answers

/$/$3)37Aionenejiaiaiahdhsusus

If 2/3x − 1 = 4, then x=

Answers

Answer: 15/2 or 7.5

Step-by-step explanation:

2/3x = 5

5 divided by 2/3 or 5 x 3/2

= 15/2 or 7.5

Answer: 15/2

Step-by-step explanation:

[tex]\frac{2}{3} x-1=4\\\\\frac{2}{3}x=5\\ \\x=5(\frac{3}{2})\\\\x=\frac{15}{2}[/tex]

Write the following number in scientific notation. 788,000

Answers

Answer:

7.88 x 10^5 is 788,000 is scientific notation

Sue has sourced four wholesalers from where she will buy most of her stock, including arrangements with two suppliers for 30 days credit, while the others are Cash on Delivery (COD).

She has purchased her store fittings and has $15000 of stock (Stock at Valuation - or SAV), with a further $10000 on 30-day credit). The business has an operating cash reserve of $20000.



How many wholesalers require terms of cash on delivery?

Answers

The difference between the total number of wholesalers and those that supply on 30-day credit, gives the number that require cash on delivery as 2

How can the question be analyzed to find the required number of wholesalers?

The number of wholesalers Sue has sourced = 4

Terms of two suppliers = 30 days credit

Amount of stock Sue has = $15000

Amount of stock on credit = $10000

Operating cash reserve of the business = $20000

Required:

The number of wholesalers that require terms of cash on delivery

Solution:

Given that the number of wholesalers = 4

The number number of suppliers (wholesalers) that supply on 30-day credit = 2

Therefore;

The number of wholesalers that require terms of cash on delivery = 4 - 2 = 2

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Need help please thank you

Answers

Answer:

  D.  x = -7/3

Step-by-step explanation:

A graphical solution is often easier when the problem is written in the form f(x) = 0. That way, the x-intercept(s) of the function f(x) will be the solution.

F(x) = 0

The desired form can be found by subtracting 16 from both sides of the equation:

  [tex]\left(\dfrac{1}{64}\right)^{-x-3}=16\qquad\text{given}\\\\\left(\dfrac{1}{64}\right)^{-x-3}-16=0\quad\Longrightarrow\quad f(x)=\left(\dfrac{1}{64}\right)^{-x-3}-16[/tex]

A graph is attached, showing x=-7/3 is the solution.

Algebraic solution

Using powers of 4, the equation can be rewritten ...

  [tex]\left(\dfrac{1}{4^3}\right)^{-x-3}=4^2\qquad\text{given}\\\\4^{3(x+3)}=4^2\\\\3(x+3)=2\qquad\text{equating exponents, or taking base-4 logs}\\\\x=\dfrac{2}{3}-3=\boxed{-\dfrac{7}{3}}\qquad\text{divide by 3, subtract 3}[/tex]

find the x-intercept of the graph of the equation y=(x+2)(x-1)

Answers

Answer:-2,0 & 1,0

Step-by-step explanation:

Substitute them in with zero product property

A bird flies 50km everyday to collect food for his offspring and 20km to drink water. To fly this distance takes him 1 hour and 40 minutes. What’s his average speed over the whole day?

Answers

Answer:

42km/h

Step-by-step explanation:

70km=100 minutes

7km= 10min

42km=60min

42km/h

If F(x) = 3x² - 8x + C and F(1) = -6, what is the value of C?

Answers

Answer:

The value of C will be -1.

Step-by-step explanation:

Greetings !

[tex]f(1) = - 6 \\ thus \: substitute \: in \: the \: equation \: \\ f(x) = 3x {}^{2} - 8x + c \\ - 6 = 3(1) {}^{2} - 8(1) + c \\ - 6 = 3 - 8 + c \\ - 6 = - 5 + c \\ - 1 = c \\ c = - 1 \\ therefore \: f(x) = 3x {}^{2} - 8x - 1 \\ f(1) = 3(1) {}^{2} - 8(1) - 1 \\ f(1) = 3 - 8 - 1 \\ f(1) =3 - 9 \\ f(1) = - 6[/tex]

Again I need help, If you tell me the answer that would be very nice! ,



Find the surface area of the composite figure :

Answers

The surface area of the given two rectangular prism is given as follows:

498 cm².

What is the surface area of a rectangular prism?

The surface area of a rectangular prism of length l, width w and height h is given as follows:

S = 2(lw + wh + hl).

For this problem, there are two prisms, with dimensions given as follows:

l = 12 cm, w = 7 cm, h = 7 cm.l = 2 cm, w = 7 cm, h = 2 cm.

Hence the surface area of the figure is the combined surface area of each figure, hence:

S = 2(7 x 7 + 12 x 7 + 12 x 7) + 2(2 x 7 + 2 x 2 + 7 x 2) = 498 cm².

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A string of 254cm from a ball of string measuring 4m.Calculate the string left on the ball

Answers

Answer:

1.46m or 14600cm are left over

Step-by-step explanation:

Assuming you mean that there were 4m of string and 254cm were used/removed.

Z+1 3. Given that Z & W are complex numbers. Prove that |Z + W|² - |z − w|² = 4Re(Z)Re(W)​

Answers

Let z=a+bi, w=c+di

[tex]|z+w|^2 -|z-w|^2 \\ \\ = |(a+c)+i(b+d)|^2 -|(a-c)^2 +i(b-d)|^2\\\\=(a+c)^2 +(b+d)^2-(a-c)^2 -(b-d)^2\\\\=a^2 +2ac+c^2 +b^2 +2bd+d^2 -a^2 +2ac-c^2 -b^2+2bd-d^2\\\\=4ac+4bd\\\\=4Re(z)Re(w)+4Im(z)Im(w)[/tex]

Whats the increace if you go from $90 to $108

Answers

Answer:

The increase is $18.

(In case you are asked about the percent increase,

percent increase = 20%)

Step-by-step explanation:

To find an increase, subtract.

$108 - $90 = $18

The increase is $18.

Answer: The increase is $18.

If you are asked about the percent increase, then use this formula:

percent change = (new number - old number)/(old number) × 100%

Here, the new number is $108. The old number is $90.

percent change = ($108 - $90)/($90) × 100%

percent change = $18/$90 × 100%

percent change = 0.2 × 100%

percent change = 20%

Since the percent change is a positive number, it is a percent increase.

Answer: percent increase = 20%

A fish can swim at 14m/s with the current and at 6m/s against it. Find the speed
of the current and the speed of the fish in still water.

Answers

Answer:

10 m/s

Step-by-step explanation:

Let x = speed of fish and y = speed of current. When swimming with current, the fish's speed is x + y. When swimming against it, the speed is x - y. Therefore, we can set up a system of linear equations to solve for x, the speed of fish.

x + y = 14

x - y = 6

2y = 8

y = 4

x - 4 = 6

x = 10

The speed of fish in still water is 10 m/s, and the speed of current is 4 m/s.

Answer:

Speed of fish in still water = 10 m/s

Speed of current = 4 m/s

Step-by-step explanation:

Let the speed of the fish in still water = x m\s

Let the speed of the current  = y m/s

Speed of the fish with the current = x + y

 x +y = 14 m/s ------------------(I)

Speed of the fish against current = x -y

 x - y = 6 m/s ----(II) &

Add the equations (I) & (II) and 'y' will be eliminated and we can find the value of 'x'.

     x + y = 14

     x - y =  6      {Now, add)

     2x    = 20

           x = 20/2

          x = 10

[tex]\sf \boxed{\text{\bf Speed of fish in still water = 10 \ m / s}}[/tex]

Plugin x = 10 in equation (I)

    10 + y = 14

            y = 14 - 10

           y = 4

[tex]\sf \boxed{\text{\bf Speed of the current = 4 \ m/s}}[/tex]

rearrange the equation a = 1/2 b to make b the formula

Answers

Answer:

b = 2a

Step-by-step explanation:

a = [tex]\frac{1}{2}[/tex] b ( multiply both sides by 2 to clear the fraction )

2a = b

Answer: b = 2a

Step-by-step explanation:

Original equation

a = (1/2) b

Multiply 2 on both sides

a * 2 = (1/2) b * 2

[tex]\Large\boxed{b=2a}[/tex]

Hope this helps!! :)

Please let me know if you have any quesitons

Let A, B, C be three points on a circle

with AB = BC. Let the tangents at A and

B meet at D. Let DC meet again

at E. Prove that the line AE bisects the segment

BD. (Hint: Why do we care about a chord bisecting a tangent line?)​

Answers

The proof that the line AE bisects the segment can be seen below.

How to get the proof

Let us have

Γ1  and 2 are the two intersecting circles. to be the circumcircle of the shape ADE. Then we can see that  Γ1 is tangent to the line DB.

A common tangent would have to touch T1 at A and also touch T2 at B

Such that what we would have would be

<ADB = 180◦ − 2<ABD = <ABC = <AEC

This would then tell us that the line is tangent to the segment.

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Rhombus BCDE is shown below. Give the coordinates of C and D.

Answers

The coordinates of C - (2n, 0) and the coordinates of D - (n, -p). The diagonals of a rhombus are perpendicular and bisect each other.

What are the properties of a rhombus?

The properties of a rhombus are:

All the sides of a rhombus are congruent and equalOpposite sides are parallelOpposite angles are equalThe adjacent angles add up to 180°Diagonals perpendicularly bisect each otherDiagonals bisect opposite angles

Calculation:

The given rhombus BCDE has B(n, p) and E(0, 0).

Since the diagonals of a rhombus are perpendicular bisectors,

EO = OC or BO = OD

Where O is the midpoint of EC and BD.

In the given diagram, points B and D are opposite each other. They are reflecting each other over the x-axis.

So, if B has coordinates (n, p) then its reflection over the x-axis is (x, -y) i.e., (n, -p).

Thus, we have B(n, p), D(n, -p), and E(0, 0)

Consider the coordinates of C as (x, y).

The midpoint of BD = ([tex]\frac{n+n}{2}[/tex], [tex]\frac{p-p}{2}[/tex])

⇒ coordinates of O = (n, 0)

So,

The midpoint of EC = ([tex]\frac{0+x}{2}[/tex], [tex]\frac{0+y}{2}[/tex])

⇒ coordinates of O = (x/2, y/2)

⇒ (n, 0) = (x/2, y/2)

∴ x = 2n and y = 0

Then, the coordinates of C are (2n, o)

Therefore, the required coordinates of the given rhombus are C(2n, 0) and D(n, -p).

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Multiply each of the following(2a-3b)and(a^2+2b^2)​

Answers

Answer: [tex]\Large\boxed{2a^3+4ab^2-3a^2b-6b^3}[/tex]

Step-by-step explanation:

Given expression

(2a - 3b) (a² + 2b²)

Apply the FOIL method (First Outer Inner Last)

Please refer to the attachment below for a graphical understanding

= 2a · a² + 2a · 2b² - 3b · a² - 3b · 2b²

Simplify by multiplication

=2 (a · a²) + 4 (a · b²) - 3 (b · a²) - 6 (b · b²)

[tex]\Large\boxed{=2a^3+4ab^2-3a^2b-6b^3}[/tex]

Hope this helps!! :)

Please let me know if you have any questions

Answer:

Your answer is 2a³ + 4ab² - 3a²b - 6b³.

Step-by-step explanation:

(2a - 3b) (a² + 2b²)

=2a (a² + 2b²) -3b (a² + 2b²)

=2a.a² + 2a.2b² - 3b.a² - 3b.2b²

=2a³ + 4ab² - 3a²b - 6b³        ans.

Hope its helpful :-)

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How was the native American political structure different from the other groups.HURRY5 stars a question In the early 16th century, fishermen were attracted to what part of north america? In the water cycle shown below, which process is happening at step 3? precipitationmeltingevaporationsublimation Because of their economies of size, large food processors typically spend a smaller percentage of sales on promotion than do small processors. a. true b. false The percentage of the battery's capacity that is charged as a function of time (in minutes) is graphed.A first quadrant coordinate plane. The horizontal axis is from zero to thirty-two-point-five with a scale of two point five and is titled Time in minutes. The vertical axis is from zero to one hundred with a scale of five and is titled Capacity, percent charged. The graph of the line is y equals two x plus forty. The graph ends at thirty minutes.A first quadrant coordinate plane. The horizontal axis is from zero to thirty-two-point-five with a scale of two point five and is titled Time in minutes. The vertical axis is from zero to one hundred with a scale of five and is titled Capacity, percent charged. The graph of the line is y equals two x plus forty. The graph ends at thirty minutes.At what rate is the battery charged?Choose 1 answer:Choose 1 answer:(Choice A)A111 percent per minute(Choice B)B202020 percent per minute(Choice C)C101010 percent per minute(Choice D)D222 percent per minute After a long day as an intern, cassie had dull, steady pain on both sides of her head. Cassie is most likely experiencing a? Adapted from The Vicar of Wakefield by Oliver Goldsmith (1766)The temporal concerns of our family were chiefly committed to my wife's management; as to the spiritual, I took them entirely under my own direction. The profits of my living, which amounted to but thirty-five pounds a year, I made over to the orphans and widows of the clergy of our diocese; for having a sufficient fortune of my own, I was careless of temporalities, and felt a secret pleasure in doing my duty without reward. I also set a resolution of keeping no curate, and of being acquainted with every man in the parish, exhorting the married men to temperance and the bachelors to matrimony, so that in a few years it was a common saying, that there were three strange wants at Wakefield, a parson wanting pride, young men wanting wives, and ale-houses wanting customers. Matrimony was always one of my favorite topics, and I wrote several sermons to prove its happiness; but there was a peculiar tenet that I made a point of supporting; for I maintained with Whiston, that it was unlawful for a priest of the church of England, after the death of his first wife, to take a second, or to express it in one word, I valued myself upon being a strict monogamist. I was early initiated into this important dispute, on which so many laborious volumes have been written. I published some tracts upon the subject myself, which, as they never sold, I have the consolation of thinking are read only by the happy Few. Some of my friends called this my weak side; but alas! they had not like me made it the subject of long contemplation. The more I reflected upon it, the more important it appeared. I even went a step beyond Whiston in displaying my principles: as he had engraved upon his wife's tomb that she was the only wife of William Whiston; so I wrote a similar epitaph for my wife, though still living, in which I extolled her prudence, economy, and obedience till death; and having got it copied fair, with an elegant frame, it was placed over the chimney-piece, where it answered several very useful purposes. It admonished my wife of her duty to me, and my fidelity to her; it inspired her with a passion for fame, and constantly put her in mind of her end.It was thus, perhaps, from hearing marriage so often recommended, that my eldest son, just upon leaving college, fixed his affections upon the daughter of a neighboring clergyman, who was a dignitary in the church, and in circumstances to give her a large fortune: but fortune was her smallest accomplishment. Miss Arabella Wilmot was allowed by all, except my two daughters, to be completely pretty. Her youth, health, and innocence, were still heightened by a complexion so transparent, and such an happy sensibility of look, as even age could not gaze on with indifference. As Mr Wilmot knew that I could make a very handsome settlement on my son, he was not averse to the match; so both families lived together in all that harmony which generally precedes an expected alliance. Being convinced by experience that the days of courtship are the most happy of our lives, I was willing enough to lengthen the period; and the various amusements that the young couple every day shared in each other's company, seemed to increase their passion. We were generally awaked in the morning by music, and on fine days rode a hunting. The hours between breakfast and dinner the ladies devoted to dress and study: they usually read a page, and then gazed at themselves in the glass, which even philosophers might own often presented the page of greatest beauty. At dinner my wife took the lead; for as she always insisted upon carving everything herself, it being her mother's way, she gave us upon these occasions the history of every dish. When we had dined, to prevent the ladies leaving us, I generally ordered the table to be removed; and sometimes, with the music master's assistance, the girls would give us a very agreeable concert. Walking out, drinking tea, country dances, and forfeits, shortened the rest of the day, without the assistance of cards, as I hated all manner of gaming, except backgammon, at which my old friend and I sometimes took a two-penny hit. Nor can I here pass over an ominous circumstance that happened the last time we played together: I only wanted to fling a quatre, and yet I threw deuce ace five times running. Some months were elapsed in this manner, till at last it was thought convenient to fix a day for the nuptials of the young couple, who seemed earnestly to desire it.The opposite of the underlined word temperance as it is used in the first paragarph would be __________. Which scheduling technique should be employed when due dates are important for a job order? Clinicians treating paraphilic disorders based on the biological perspective may:_____. On a coordinate plane, a parabola opens to the left. It has a vertex at (0, 0), a focus at (negative 2, 0), and a directrix at x = 2.Which equation represents the parabola shown on the graph? y2 = 2xy2 = 8xx2 = 2yx2 = 8y The neurotransmitters that are partially responsible for the ""high"" that is associated with passionate love are chemically similar to?