what number must you add to complete the square x^2+12x=40

Answers

Answer 1

Step-by-step explanation:

x²+12x=40

(x+6)²-6²-40=0

(x+6)²-76 = 0


Related Questions

Find the volume (in cubic yards) of a cylinder with radius 1.2 yards and height 2.9 yards. (Round your answer to one decimal place.)

Answers

Answer:

11.8 yd³

Step-by-step explanation:

Lolz please help me I would gladly appreciate it

Answers

Pentagon has sum of 540°

Has the sum of 540 degrees

Write the equations for a line parallel to the line:
y=-4/3x-4
That goes through the point (-7,-6)
Write your equation in slope intercept form, using reduced fractions for the slope and intercept if necessary.

Answers

Answer:

y = -4/3x -46/3

Step-by-step explanation:

The question tells us to write an equation that is:

- parallel to the given line

- goes through the point (-7, -6)

Parallel lines will have the same slope, because if the slope was different, they would eventually intersect and not be parallel lines anymore.

We are going to use the point-slope form to find the other line.

Point-slope form uses a point that the graph will cross through and the slope of the graph to find the graph in y = mx + b form (also called slope-intercept form).

(I attached the point-slope form as an image below)

m = slope

x1 = x coordinate of the point

y1 = y coordinate of the point

We are going to substitute our slope into the form first:

y - y1 = (-4/3)(x - x1)

Next let's put in our point (-7, -6):

(Remember! -7 is our x coordinate & -6 is our y coordinate :-) )

y - (-6) = -4/3(x - (-7))

(cancel out the negatives to make them positive)

y + 6 = -4/3 (x +7)

Now solve for x using basic algebra:

y + 6 = -4/3 (x +7)

(distribue the -4/3)

y + 6 = -4/3x - 28/3

(subtract 6 from both sides)

y = -4/3x -46/3

That's your answer!

Hope it helps (●'◡'●)

Answer:

Step-by-step explanation:

y + 6 = -4/3(x + 7)

y + 6 = -4/3x - 28/3

y + 18/3 = -4/3x - 28/3

y = -4/3x - 46/3

can anyone help me and explain

Answers

Answer:

cf

=41

5 f-46

Step-by-step explanation:

thiis is the answer

Answer:

To find the inverse, switch the y(F(C)) and the x(C) variables.

So this function:

[tex]y=\frac{9}{5}x+32 \\[/tex]

Will become this function:

[tex]x=\frac{9}{5}y+32 \\[/tex]

You will then solve for y:

[tex]x=\frac{9}{5}y+32 \\x-32=\frac{9}{5}y\\5(x-32)=5(\frac{9}{5}y)\\5x-160=9y\\y=\frac{5x-160}{9}\\y=\frac{5x}{9}-\frac{160}{9}[/tex]

Substitute in the variables of this problem:

[tex]C(F)=\frac{5C}{9}-\frac{160}{9}[/tex]

hlw guys plz help me which set is this.for examples: A u B , A u B u C...like that..plz help me​

Answers

Answer:

answer is;

AnBnC ( common place for all)

HAVE A NİCE DAY

in the diagram below, BD is parallel to XY. what is the value of y?
a. 70
b. 130
c. 110
d. 20

Answers

I can't see the diagram sorry.

Step-by-step explanation:

Is there supposed to be a picture attached?

someone please help!!<3



Question 4 of 10
If f(x) = 5x – 2 and g(x) = 2x + 1, find (f - g)(x).
A. 3 - 3x
B. 7x-3
O C. 7x-1
D. 3x - 3

Answers

Answer:

the answer is c

Step-by-step explanation:

the answer is c

A cat is running away from a dog at a speed of 3m/s. originally, the distance between them was 48 meters. What should be the speed of the dog to catch with the cat in 1 minute?

Answers

Answer:

[tex]3.8\:\mathrm{m/s}[/tex]

Step-by-step explanation:

Use the formula [tex]d=rt[/tex] (distance is equal to rate/speed multiplied by time) to solve this problem.

We know that one minute is equal to 60 seconds. Therefore, the distance travelled by the cat in 1 minute is equal to [tex]d=3\cdot 60=180\text{ meters}[/tex].

To catch the cat, the dog needs to also cover an additional 48 meters, because the cat was initially 48 meters away from the dog and it ran away from the dog. Hence, the dog will need to cover [tex]180+48=228[/tex] meters in one minute.

Therefore, we have:

[tex]228=60r,\\r=\frac{228}{60}=\boxed{3.8\:\mathrm{m/s}}[/tex]

Answer:

[tex] \boxed{3.8 \: m/s} [/tex]

Explanation

The first step is to set the speed and the distance equal to the unknown rate of the dog.

3 m/s + 48 m = x m/60s.

Then substitute 60s in for both rates to get distance.

180m + 48m = x m/60

228m = 60x m

÷60 ÷60

3.8m = x m/s.

x = 3.8m/s

I need help on this graphing question if anyone can, please help me

Answers

Answer/Step-by-step explanation:

Given:

f(x) = 2x + 2

Domain = {-5, -1, 2, 3}

To write the range of f using set notation, substitute each domain value into f(x) = 2x + 2 to get each corresponding range value that will make up the set.

Thus:

✔️f(-5) = 2(-5) + 2

= -10 + 2

f(-5) = -8

✔️f(-1) = 2(-1) + 2

= -2 + 2

f(-1) = 0

✔️f(2) = 2(2) + 2

= 4 + 2

f(-1) = 6

✔️f(3) = 2(3) + 2

= 6 + 2

f(3) = 8

Range of f using set notation = {-8, 0, 6, 8}

✔️Graph f by plotting the domain values on the x-axis against the corresponding range values on the y-axis as shown in the attachment below:

*See attachment for the graph of f

find the exact value of 6cos(105°)​

Answers

Answer:

[tex]-\frac{3(\sqrt{6}-\sqrt{2})}{2}\text{ or } \frac{-3\sqrt{6}+3\sqrt{2}}{2}}\text{ or }\frac{3(\sqrt{2}-\sqrt{6})}{2}[/tex]

Step-by-step explanation:

There are multiple ways to achieve and even express the exact answer to this problem. Because the exact value of [tex]6\cos(105^{\circ}})[/tex] is a non-terminating (never-ending) decimal, it does not have a finite number of digits. Therefore, you cannot express it as an exact value as a decimal, as you'd either have to round or truncate.

Solution 1 (Cosine Addition Identity):

Nonetheless, to find the exact value we must use trigonometry identities.

Identity used:

[tex]\cos(\alpha +\beta)=\cos \alpha \cos \beta-\sin \alpha \sin \beta[/tex]

Notice that [tex]45+60=105[/tex] and therefore we can easily solve this problem if we know values of [tex]\cos(45^{\circ})[/tex], [tex]\cos(60^{\circ})[/tex], [tex]\sin (45^{\circ})[/tex], and [tex]\sin(60^{\circ})[/tex], which is plausible as they are all key angles on the unit circle.

Recall from either memory or the unit circle that:

[tex]\cos(45^{\circ})=\sin(45^{\circ})=\frac{\sqrt{2}}{2}[/tex] [tex]\cos(60^{\circ})=\frac{1}{2}[/tex] [tex]\sin(60^{\circ})=\frac{\sqrt{3}}{2}[/tex]

Therefore, we have:

[tex]\cos(105^{\circ})=\cos(45^{\circ}+60^{\circ}}),\\\cos(45^{\circ}+60^{\circ}})=\cos 45^{\circ}\cos 60^{\circ}-\sin 45^{\circ}\sin 60^{\circ},\\\cos(45^{\circ}+60^{\circ}})=\frac{\sqrt{2}}{2}\cdot \frac{1}{2}-\frac{\sqrt{2}}{2}\cdot \frac{\sqrt{3}}{2},\\\cos(105^{\circ})=\frac{\sqrt{2}}{4}-\frac{\sqrt{6}}{4},\\\cos(105^{\circ})={\frac{-\sqrt{6}+\sqrt{2}}{4}}[/tex]

Since we want the value of [tex]6\cos 105^{\circ}[/tex], simply multiply this by 6 to get your final answer:

[tex]6\cdot {\frac{-\sqrt{6}+\sqrt{2}}{4}}=\frac{-3\sqrt{6}+3\sqrt{2}}{2}}=\boxed{\frac{3(\sqrt{2}-\sqrt{6})}{2}}[/tex]

Solution 2 (Combination of trig. identities):

Although less plausible, you may have the following memorized:

[tex]\sin 15^{\circ}=\cos75^{\circ}=\frac{\sqrt{6}-\sqrt{2}}{4},\\\sin 75^{\circ}=\cos15^{\circ}=\frac{\sqrt{6}+\sqrt{2}}{4}[/tex]

If so, we can use the following trig. identity:

[tex]\cos(\theta)=\sin(90^{\circ}-\theta)[/tex] (the cosine of angle theta is equal to the sine of the supplement of angle theta - the converse is also true)

Therefore,

[tex]\cos (105^{\circ})=\sin (90^{\circ}-105^{\circ})=\sin(-15^{\circ})[/tex]

Recall another trig. identity:

[tex]\sin(-\theta)=-\sin (\theta)[/tex] and therefore:

[tex]\sin (-15^{\circ})=-\sin (15^{\circ})[/tex]

Multiply by 6 to get:

[tex]6\cos (105^{\circ})=-6\sin (15^{\circ})=-6\cdot \frac{\sqrt{6}-\sqrt{2}}{4}=\boxed{-\frac{3(\sqrt{6}-\sqrt{2})}{2}}[/tex] (alternative final answer).

Sixty-five percent of men consider themselves knowledgeable soccer fans. If 10 men are randomly​ selected, find the probability that exactly seven of them will consider themselves knowledgeable fans. Round to the nearest thousandth.

0.700

0.65

0.252

0.021

Answers

Answer:

.252

Step-by-step explanation:

[tex]{10\choose7}*.65^7*(1-.65)^3=.252219625[/tex]

Is f(x)=4x^2 linear,quadratic,or exponential

Answers

Answer:

Step-by-step explanation:

it is a quadratic function.

Need help please....

Answers

Answer:

-14 x²

Step-by-step explanation:

10 x² - 24 x² = -14 x²

The answer is 14

if you multiply both P(x) and Q(x), the third part becomes 14x², so the coefficient of x² becomes 14.

Answered by GAUTHMATH

Tourism is extremely important to the economy of Florida. Hotel occupancy is an often-reported measure of visitor volume and visitor activity (Orlando Sentinel, May , ). Hotel occupancy data for February in two consecutive years are as follows. Current Year Previous Year Occupied Rooms 1,400 1,309 Total Rooms 1,750 1,700 a. Formulate the hypothesis test that can be used to determine whether there has been an increase in the proportion of rooms occupied over the one-year period. Let population proportion of rooms occupied for current year population proportion of rooms occupied for previous year - Select your answer - - Select your answer - b. What is the estimated proportion of hotel rooms occupied each year (to decimals)

Answers

Answer:

H1 : P1 - P2 = 0

H1 : P1 - P2 > 0

Step-by-step explanation:

The test to be performed on the given data is ; difference in proportion ;

P1 = proportion od rooms in current year

P2 = proportion of rooms

The null hypothesis ``, H0 : p1 - p2 (this onstage null hypothesis and it is the initial truth, representing the notion that no difference in proportion exists.

H1 : P1 - P2 = 0

The alternative hypothesis takes takes the side that there is an increase on proportion of rooms occupied :

H1 : P1 - P2 > 0

factor the GCF out of the polynomial ​

Answers

Answer:

1. Find the GCF of all the terms in the polynomial.

2. Express each term as a product of the GCF and another factor.

3. Use the distributive property to factor out the GCF.

When P(x) is divided by (x - 1) and (x + 3), the remainders are 4 and 104 respectively. When P(x) is divided by x² - x + 1 the quotient is x² + x + 3 and the remainder is of the form ax + b. Find the remainder.

Answers

Answer:

The remainder is 3x - 4

Step-by-step explanation:

[Remember] [tex]\frac{Dividend}{Divisor} = Quotient + \frac{Remainder}{Divisor}[/tex]

So, [tex]Dividend = (Quotient)(Divisor) + Remainder[/tex]

In this case our dividend is always P(x).

Part 1

When the divisor is [tex](x - 1)[/tex], the remainder is [tex]4[/tex], so we can say [tex]P(x) = (Quotient)(x - 1) + 4[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x - 1) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x - 1 = 0\\x - 1 + 1 = 0 + 1\\x = 1[/tex]

When [tex]x = 1[/tex],

[tex]P(x) = (Quotient)(x - 1) + 4\\P(1) = (Quotient)(1 - 1) + 4\\P(1) = (Quotient)(0) + 4\\P(1) = 0 + 4\\P(1) = 4[/tex]

--------------------------------------------------------------------------------------------------------------

Part 2

When the divisor is [tex](x + 3)[/tex], the remainder is [tex]104[/tex], so we can say [tex]P(x) = (Quotient)(x + 3) + 104[/tex]

In order to get rid of "Quotient" from our equation, we must multiply it by 0, so [tex](x + 3) = 0[/tex]

When solving for [tex]x[/tex], we get

[tex]x + 3 = 0\\x + 3 - 3 = 0 - 3\\x = -3[/tex]

When [tex]x = -3[/tex],

[tex]P(x) = (Quotient)(x + 3) + 104\\P(-3) = (Quotient)(-3 + 3) + 104\\P(-3) = (Quotient)(0) + 104\\P(-3) = 0 + 104\\P(-3) = 104[/tex]

--------------------------------------------------------------------------------------------------------------

Part 3

When the divisor is [tex](x^2 - x + 1)[/tex], the quotient is [tex](x^2 + x + 3)[/tex], and the remainder is [tex](ax + b)[/tex], so we can say [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

From Part 1, we know that [tex]P(1) = 4[/tex] , so we can substitute [tex]x = 1[/tex] and [tex]P(x) = 4[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]4 = (1^2 + 1 + 3)(1^2 - 1 + 1) + a(1) + b\\4 = (1 + 1 + 3)(1 - 1 + 1) + a + b\\4 = (5)(1) + a + b\\4 = 5 + a + b\\4 - 5 = 5 - 5 + a + b\\-1 = a + b\\a + b = -1[/tex]

We will call [tex]a + b = -1[/tex] equation 1

From Part 2, we know that [tex]P(-3) = 104[/tex], so we can substitute [tex]x = -3[/tex] and [tex]P(x) = 104[/tex] into [tex]P(x) = (x^2 + x + 3)(x^2 - x + 1) + (ax + b)[/tex]

When we do, we get:

[tex]104 = ((-3)^2 + (-3) + 3)((-3)^2 - (-3) + 1) + a(-3) + b\\104 = (9 - 3 + 3)(9 + 3 + 1) - 3a + b\\104 = (9)(13) - 3a + b\\104 = 117 - 3a + b\\104 - 117 = 117 - 117 - 3a + b\\-13 = -3a + b\\(-13)(-1) = (-3a + b)(-1)\\13 = 3a - b\\3a - b = 13[/tex]

We will call [tex]3a - b = 13[/tex] equation 2

Now we can create a system of equations using equation 1 and equation 2

[tex]\left \{ {{a + b = -1} \atop {3a - b = 13}} \right.[/tex]

By adding both equations' right-hand sides together and both equations' left-hand sides together, we can eliminate [tex]b[/tex] and solve for [tex]a[/tex]

So equation 1 + equation 2:

[tex](a + b) + (3a - b) = -1 + 13\\a + b + 3a - b = -1 + 13\\a + 3a + b - b = -1 + 13\\4a = 12\\a = 3[/tex]

Now we can substitute [tex]a = 3[/tex] into either one of the equations, however, since equation 1 has less operations to deal with, we will use equation 1.

So substituting [tex]a = 3[/tex] into equation 1:

[tex]3 + b = -1\\3 - 3 + b = -1 - 3\\b = -4[/tex]

Now that we have both of the values for [tex]a[/tex] and [tex]b[/tex], we can substitute them into the expression for the remainder.

So substituting [tex]a = 3[/tex] and [tex]b = -4[/tex] into [tex]ax + b[/tex]:

[tex]ax + b\\= (3)x + (-4)\\= 3x - 4[/tex]

Therefore, the remainder is [tex]3x - 4[/tex].

Given right angle ABC, what the value of tan(A)?
5/13
12/13
12/5
13/12
need answer asap

Answers

Hi there!

[tex]\large\boxed{12/5}}[/tex]

tan (angle) = Opposite side / Adjacent side, so:

Tan (A) = opposite side / adjacent side

= 24 / 10

Simplify:

= 12 / 5

p{x:x is a natural number x (9​

Answers

Answer:

you need a photo my dude

Step-by-step explanation:

SOMEONE PLS HELP ME I WILL MAKE U BRAINLIST ! In a survey sample of 83 respondents, about 30.1 percent of the samplework less than 40 hours per week. What is the estimated standard error for the group of respondents who work 40 hours or more per week?
(*round to two decimal places)

Answers

Answer:

Answer = √(0.301 × 0.699 / 83) ≈ 0.050

A 68 percent confidence interval for the proportion of persons who work less than 40 hours per week is (0.251, 0.351), or equivalently (25.1%, 35.1%)

Step-by-step explanation:

√(0.301 × 0.699 / 83) ≈ 0.050

We have a large sample size of n = 83 respondents. Let p be the true proportion of persons who work less than 40 hours per week. A point estimate of p is  because about 30.1 percent of the sample work less than 40 hours per week. We can estimate the standard deviation of  as . A  confidence interval is given by , then, a 68% confidence interval is , i.e., , i.e., (0.251, 0.351).  is the value that satisfies that there is an area of 0.16 above this and under the standard normal curve.The standard error for a proportion is √(pq/n), where q=1−p.

Hope this answer helps you :)

Have a great day

Mark brainliest

What is the solution to the system of linear equations?
(-3,0)
(-3,3)
(0,2)
(3,1)

Answers

(0,2) that’s the point in which they connect or meet

Approximately 10% of all people are left-handed. Consider a grouping of fifteen people.

Write the probability distribution

Answers

Answer:

Step-by-step explanation:

Answer:

15*.1=1.5

so either one or two people of the 15 would be left handed

Which of the following represents the ratio of the hypotenuse to the given
side?

Answers

Answer:

D. √2 : 1

Step-by-step explanation:

The hypotenuse = 4√2 (longest side of a right triangle)

The given side = 4

Ratio of the hypotenuse to the given side = 4√2 : 4

Simplify by dividing both numbers by 4

√2 : 1

Using the graph below, if f(x) = 4, find x.

Answers

3 I think is the answer

Using the Fenske equation, calculate the number of theoretical plates for a fractional distillation set up used to separate Ethyl acetate (the more volatile component) from hexane (less volatile component) in a mixture with the following experimental data:
n=log(X/Xb) -log(Y a/Yb)/ log α Fenske Equation
Experimental data: l
The following are the data optained from injection of a 1-microliter sample of the equimolar stock solution used in the distillation experiment into a GČ. The percent of the area under the appropriate peak is idicated.
a = 1.6
GC results of the stock mixture used in the experiment
Component Rt (retention time) Percent Area
Ethyl acetate 1.09 53 82
Hexane 1.58 47 18
GC results of a 1-microliter sample after 3 mL had been collected:
Component Rt (retention time) Percent Area
Ethyl acetate 1.09 82
Hexane 1.58 18
a. 3.9
b. 7.2
c. 7.0
d. 3.0

Answers

c


The answer would be C

A meteorologist preparing a talk about global warming compiled a list of weekly low temperatures (in degrees Fahrenheit) he observed at his southern Florida home last year. The coldest temperature for any week was 36°F, but he inadvertently recorded the Celsius value of 2°. Assuming that he correctly listed all the other temperatures, explain how this error will affect these summary statistics:a) measures of center: mean and median.b) measures of spread: range, $IQR,$ and standard deviation.

Answers

Answer:

nr.herkyrsfdlufshfsyfs

Step-by-step explanation:

dsfsyfksutryrysyrslufzmfyzydzufmzmhfzl

hdhfuthfzhkrskyrsgj

what is the formula for perimeter of a square​

Answers

Answer: P = 4s

Step-by-step explanation:

P = 4s where s = the length of each side.  

Since each side of a square is the same length, the side length is multiplied by 4.

$2900 at 13% for 30 years. i need simple interest and compounding interest

Answers

Answer:

Step-by-step explanation:

simple:

2900(1+.13*30)=14210

Compounding

[tex]2900(1+.13)^{30}=113436.1041[/tex]

Answer:

113436.1041

Step-by-step explanation:

2900 ( 1 +0.13 ) ^ 30

Formula : amount ( 1 + percentage ) ^ years

Sumas y restas w+y=9 3w-y=11

Answers

Answer:

w = 5

y = 4

Step-by-step explanation:

w+y=9

3w-y=11

4w = 20

w = 5

y = 4

3 coins are flipped.

Answers

Answer:

just keep writing down outcome on a sheet of paper then count total

Step-by-step explanation:

Suppose the figure KLMN is dilated using a scale factor of 1/3 with the center of dilation at the origin. Which are the ordered pairs for the image?

1. K’(-1,3), L’(-3,0), M’(⅔, -8/3), N’(2, 4/3)

2. K’(-9,27), L’(-27,0), M’(6, -24), N’(18, 12)

3. K’(0,6), L’(-6,-3), M’(-1, -5), N’(3, 1)

4. K’(3,-1), L’(0,-3), M’(-8/3, ⅔), N’(4/3,2)

Answers

Answer:

K’(-1,3), L’(-3,0), M’(⅔, -8/3), N’(2, 4/3)

Step-by-step explanation:

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