Answer:
I think it involves the use of extractive distillation but I'm not sure.
Still hope it helps:-)
The physical property is used to separate cyclohexanone from any unreacted cyclohexanol is distillation.
The process for separating cyclohexanone from cyclohexanol comprises the following steps
1. reacting a mixture of ketone and alcohol with an organometallic compound M(X)n to form compound HX, wherein M is chosen from aluminium, titanium and boron, where n is the valance of a M, X denotes equal or different organic group chosen from alkyl group and electric group having up to 10 carbon atom
2. liberating the newly formed compound HS from the reaction mixture by distillation
3. separating the ketone from the organometallic compound formed by reaction between M(X)n and the alcohol in the mixture.
Thus, we concluded that above compound is seprated by forming organometallic compound.
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What is the expected markovnikov addition product from the addition of hi to 2-methyl-2-butene?.
Markovnikov addition product from the addition of hi to 2-methyl-2-butene is 2-iodo-2-mehtylbutane.
What is Markonikov rule?
In natural science, Markovnikov's standard or Markownikoff's standard portrays the result of some expansion responses. The standard was formed by Russian scientist Vladimir Markovnikov in 1870.Markovnikov's standard is an exact rule used to foresee regioselectivity of electrophilic expansion responses of alkenes and alkynes.Markovnikov predicts the results of an electrophilic expansion of hilter kilter reagents (for example hydrogen halides, water and alcohols) to hilter kilter alkenes.To learn more about Markonikov rule from the given link
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90cm3 of 1 m hcl solution and 10cm3 of 0.5 m naoh solution are mixed together. the concentration of hcl contained in the final solution
The concentration of HCl contained in the final solution is 0.95 M.
Calculation:Here, we use the dilution formula, which is,
M (V₁ + V₂) = M₁V₁ + M₂V₂
where,
M = resultant concentration
M₁ = concentration of HCl
V₁ = volume of HCl
M₂ = concentration of NaOH
V₂ = volume of NaOH
Given,
M₁ = 1 M
V₁ = 90 cm³ = 90 mL
M₂ = 0.5 M
V₂ = 10 cm³ = 10 mL
To find,
M =?
Put the values in the above formula,
M (V₁ + V₂) = M₁V₁ + M₂V₂
M (90 + 10) = (1 × 90) + (0.5 × 10)
M × 100 = 90 + 5
M × 100 = 95
M = 95/100
M = 0.95 M
Therefore, the concentration of HCl contained in the final solution is 0.95 M.
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Why do you add hydroxide to your hexanediamine solution? what would occur if you did not add it?.
In the polymerization reaction, the lone pair electrons on the NH₂ groups of hexanediamine attack the C=O groups of the dicarboxylic acid in a nucleophilic substitution reaction as shown in the image.
Hydroxide is added to remove any H⁺ ions present and keep the hexanediamine in the deprotonated form, so that the NH₂ lone pair electrons are available for reaction.
What if you don't add it ?If hydroxide is not added, the NH₂ groups will get protonated by H⁺ ions present to give NH₃⁺ groups, which cannot react.
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how small atom partical are?
Atoms of particles are so small that they cannot be divided further by any physical means.
What are atoms?According to John Dalton, atoms are the smallest, indivisible particles of elements.
However, it was later found out that chemically, atoms consist of protons, neutrons, and electrons.
Thus, the indivisibility of atoms that John Dalton was referring to must be that of physical division.
In other words, the particles of atoms are so small that dividing them further using physical means is absolutely impossible.
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Nitrogen-13 has a half-life of 10 minutes. How much of a 128 mg sample would remain after 40 minutes?
The amount of nitrogen-13 sample that remained after 40 minutes has been 8 mg.
Half-life can be defined as the time required by the substance to reduce half of its initial concentration.
The half-life of Nitrogen-13 has been 10 minutes. In 10 minutes, the sample will be reduced to
of its concentration,
The total time has been 40 minutes.
The number of half-life experienced by the sample has:
Number of half-life = {Total-time}/{Half-life}
Number of half life cycles = {40}/{10}
The number of half-life cycles = 4
The sample has been reduced to 50% in the first half-life cycle,reduced to 25% in the 2nd half-life cycle, then 12.5% in 3rd half cycle and finally 6.25% by the end of 4th half cycle.
The sample remained = 6.25% of the initial concentration.
The sample remained = (6.25/100)
×128mg
The sample remained = 8 mg
Thus from above we concluded that the amount of nitrogen-13 sample that remained after 40 minutes has been 8 mg.
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What is the "average atomic mass" of this set of pennies.
(can you guys also include a formula on how i can solve future problems like this, please.)
Answer:
A. 2.74g is the correct answer
Explanation:
Greetings![tex]average \: mass = \frac{(mass \: pre - 1982 \times abundance) + (mass \: post - 1982 \times abundance}{100 } \\ ave = \frac{ (3.1g \times 40.0) + (2.5g \times 60.0)}{100} \\ ave = \frac{124 + 150}{100} \\ ave = \frac{274}{10} = 2.74g[/tex]
where, the sum of abundance always have to be 100%
Thus, 40.0 +60.0= 100.0
Write the henderson-hasselbalch equation for a propanoic acid solution (ch3ch2co2h, pa=4. 874)
The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.
What is Henderson Hasselbalch Equation ?It is expressed as:
pH = pKa + log([A-]/[HA].
where,
[A-] is molar concentration of conjugate base and
[HA] is molar concentration of weak acid.
Given,
pH = 5.30
Substitute the value in the Henderson Hasselbalch equation
5.30 = 4.874 + log[A-]/ [HA]
log[A-]/[HA] = 5.30 - 4.874
[A-]/[HA] = 10^ 0.426
[A-]/[HA] = 2.7
Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.
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The _______________________________ css3 property can be used to create multiple columns of text within a single element.
The column count property can be used to create multiple columns of text within a single element.
20. 10 in the molecular orbital model of benzene, the six p atomic orbitals combine to form how many molecular orbitals?
The six p atomic orbitals combine to form 6 molecular orbitals. The correct option is A.
What is molecular orbital?Molecular orbitals are the functions that tell the position of an electron in the orbital and the wave like property of the electron. This function is used to find the chemical and physical property of the element.
The six p atomic electrons will combine to constitute 6 molecular pi electrons. Because in benzene there are 6 pi orbitals. As benzene is planar, hexagonal and have sp2 hybridization. The remaining cyclic orbitals overlap to create 6 pi molecular orbitals.
Thus, the correct option is A. 6.
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The question is incomplete. Your complete question is given below:
A. 6
B. 5
C. 4
D. 3
E. 2
Why do night bird have extraordinary night vision
Answer:
The low light eye sight depends on the rod cells of the eye,and the birds have more amount of rod cell in their eyes, that's why they have an extraordinary night vision
A piece of wood near a fire is at 23°c. it gains 1,160 joules of heat from the fire and reaches a temperature of 42°c. the specific heat capacity of wood is 1.716 joules/gram degree celsius. what is the mass of the piece of wood?
The mass of the piece of wood is 35.58 g.
Joule = M × T × C
Where, M = mass
T = change in temperature(42C-23C=19 C)
C = specific heat capacity = 1.716 joules/gram
Substituting the values in the equation,
1160 = M × 19 × 1.716
M = 1160/32.604 = 35.58 g
Therefore, the mass of the piece of wood = 35.58 g
What is meant by specific heat capacity?A material's specific heat capacity, which is defined as its heat capacity divided by its mass, determines how much energy is required to increase a gram's temperature by one degree Celsius (or one Kelvin)
What is mass?Mass is the quantity of matter in a physical body.
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which of the following equations is ballanced
4Na + O₂ → 2Na₂O is balanced equation.
Hence, Option (B) is correct answer.
What is Balanced Chemical Equation ?The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now check all the options one by one:
Option (A): 2H₂ + O₂ → 4H₂O
Reactant Side Product Side
H = 4 H = 8
O = 2 O = 4
Here number of atoms of H on the reactant side is 4 and number of atom on product side is 8. H atoms are not balanced in this equation. Hence the given equation is not balanced.
Option (B): 4Na + O₂ → 2Na₂O
Reactant Side Product Side
Na = 4 Na = 4
O = 2 O = 2
Here all the atom on reactant side and product side are equal. Hence the given equation is balanced.
Option (C): Fe₂O₃ + H₂ → 2Fe + 3H₂O
Reactant Side Product Side
Fe = 2 Fe = 2
O = 3 O = 3
H = 2 H = 6
Here number of atoms of H on the reactant side is 2 and number of atom on product side is 6. H atoms are not balanced in this equation. Hence the given equation is not balanced.
Option (D): CH₄ + O₂ → CO₂ + H₂O
Reactant Side Product Side
C = 1 C = 1
H = 4 H = 2
O = 2 O = 3
Here H atoms on the reactant and product side is not equal and O atoms are also not equal on the reactant side and product side. Hence, the given equation is not balanced.
Thus from the above conclusion we can say that The balanced equation from the given options is 4Na + O₂ → 2Na₂O
Hence, Option (B) is correct answer.
Disclaimer: The question was given incomplete on the portal. Here is the complete question.
Question: Which of the following equations is balanced?
(A) 2H₂ + O₂ → 4H₂O
(B) 4Na + O₂ → 2Na₂O
(C) Fe₂O₃ + H₂ → 2Fe + 3H₂O
(D) CH₄ + O₂ → CO₂ + H₂O
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Treatment of tetrahydrofuran with excess hbr results in the formation of what major organic product?
The treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .
THF which is tetrahydrofuran is reated with excess of HBr at 373 K .The product is 1,4-dibromobutane as a major organic product .
In the mechanism proton having positive charge is attack on electron rich oxygen and protonated it then bromine anion attack at adjacent carbon and break carbon - protonated oxygen bond and in he final step the hydroxyl group is protonated and remove as a water with attack at bromine anion .
Therefore , on treatment of tetrahydrofuran with excess HBr results in the formation of 1,4-dibromobutane as a major organic product .
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Dosage calculation order: 3 mg available: 2 mg per 6 ml how many ml will be given?
9ml will be given for the case of dosage calculation order: 3 mg available: 2 mg per 6 ml
Conversion factors are necessary for dosage calculation, such as when translating from pounds to kilograms or liters to milliliters. This approach, which is straightforward in design, enables physicians to deal with different units of measurement and convert factors to arrive at the solution.
dosage calculation techniques serve as a second or third check on the accuracy of the previous computation techniques. Dimensional Analysis, Ratio Proportion, and Formula or Desired Over Have Method are the three main approaches for dosage calculation. dosage calculations are frequently prescribed and labeled based on their weight or, for solutions, their strength, which is the amount of weight dissolved or suspended in a given volume.
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Why is the vapor pressure of a warm lake higher than the vapor pressure of a cold lake?
Answer:
Explanation:
Warm lake vapor pressure is higher than cold lake vapor pressure because it evaporates more quickly. In other words, as the temperature of warm water increases, the kinetic energy of the warm water molecule also increases. As the kinetic energy of the warm water molecule increases, the number of molecules conversion into a vapor also increases, thereby increasing the vapor pressure of warm water.
Answer:
B.
Warm water evaporates more quickly.
Explanation:
i got it right on edmentum!!
If 38. 2 ml of a 0. 163 m KOH solution is required to neutralize 25. 0 ml of H2SO4 solution. Calculate the morality of the H2SO4 solution.
Answer:
.24 mol / liters
Explanation:
38. 2 ml = .0382 liters
.0382 liters times ( 0. 163 m KOH/1 liter) times ( 1 mol H2SO4/ 1 mol koh) =
.006/.025 liters = .24 mol / liters
chegg
How many moles of sodium bromide can be produced from the reaction of 1. 03 moles of bromine gas with 0. 650 moles of sodium? 2 na(s) br2(g) ® 2 nabr(s)
There are 0. 650 moles of sodium bromide can be produced from the reaction of 1. 03 moles of bromine gas with 0. 650 moles of sodium .
Calculation ,
To find the number of moles of sodium bromide we have to write balanced chemical equation first .
[tex]2Na (s)+ Br_{2}(g)[/tex] → 2NaBr (s)
from the equation we can conclude that 2 moles sodium react with one mole of bromine to form 2 mole of sodium bromide .
But 1. 03 moles of bromine gas ( that is equal to the number of moles required in the equation) with 0. 650 moles of sodium ( that is half of required mole ) is given .
So, sodium is present as limiting reactant .
So , the number of sodium bromide formed is equal to the number of moles of sodium atom.
Hence , the number of sodium bromide formed = 0. 650 moles
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If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, how many isomers would result?
One isomer is formed
1,1- Dichloroethane is the isomer.
If another hydrogen of c2h5cl is replaced by a chlorine atom to yield c2h4cl2, it would result in one isomer.
In contrast to 1,2-dichloroethane, which has two chlorine atoms connected to distinct carbon atoms, 1,1-dichloroethane has two chlorine atoms bound to the same carbon atom.Isomers are each of two or more compounds having the same formula but various atom arrangements in the molecule and unique characteristics.What three types of isomers are there?Chain isomersFunctional group isomersPositional isomers
These are the three different categories of structural isomers.
How is an isomer recognized?Their bonding patterns and the way they occupy three-dimensional space can be used to distinguish them. Determine the bonding patterns of structural (constitutional) isomers. Although the atoms in the compounds are the same, their connections create various functional groups.What makes isomers significant?Because two isomers might have the same chemical formula but different chemical structures, they are significant. The molecule's properties are influenced by its structure.To learn more about isomers visit:
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The reaction of 75.0 g p4 with excess chlorine gas produces 110 g pcl3 in lab. calculate the percent yield for the reaction.
The reaction of 75.0 g p4 with excess chlorine gas produces 110 g pcl3 in lab. The percent yield for the reaction is 32.7%.
P4+ 6 Cl2 — 4PCl3
moles of P4 in 75 g
n=m/M
where n = moles; m= mass; M = molar mass
M(P4) = 4× 30.974 g/ mol
P = 123.896g/mol
n can be given as
n(P4) = (75) / 123.896
= 0.60535 mol
Total=
0.60535 mol P4 × 4 mol/1 mol P4
= 2.4214 mol PCl3
mass of PCl3
m= n×M
M = 30.974 g/mol P+(3× 35.45g/mol Cl)
= 137.32g/mol
m= 2.4212 mol× 137.32g/mol
=333 g
The yield of PCl3 is 333 g.
The theoretical yield of PCl3 is 110 g.
percent yield can be given as
(percent yield/ theoretical yield) × 100
%yield = (333/110) ×100
Thus, the percent yield of PCl3 is 32.7%.
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What is the rate of a reaction if the value of kis 3 and [A] and [B] are each 2
M?
Rate = K[A]²[B]
OA. 12 (mol/L)/s
OB. 24 (mol/L)/s
OC. 2 (mol/L)/s
о D. 36 (mol/L)/s
The rate of reaction of the value of KIS 3 and [A] and [B] are each 2M is: 24 (mol/L)/s (Option B)
What is rate of reaction?
In chemistry, the rate of reaction describes how quickly a chemical reaction develops.
It is frequently described in terms of either the concentration of a reactant that is spent in a unit of time or the concentration of a product that is generated in a unit of time (amount per unit volume).
What is the calculation that supports that above answer?
Recall that the rate equation is:
Rate = K[A]²[B]
Hence:
Concentration of A = 2M
Concentration of B = 2M
K = 3
Taking the values and substituting them, we have:
Rate = 3 (mol/L)⁻³/s×[2]² ×[2]
Rate = 24 (mol/L)⁻³/s
The rate of reaction can be used as a valuable diagnostic tool. We may devise strategies to increase production by learning how quickly things are created and what slows down reactions.
This knowledge is necessary for the industrial production of various chemicals, such as:
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Prove the following:V=U + AT
We know that,
acceleration (a) = final velocity(V)-initial velocity(U)/ Time taken(T)
Which is an aspect of the kinetic-molecular theory and can be used to explain the compressibility of plasma
The answer choice which represents an aspect of the kinetic-molecular theory and can be used to explain compressibility of plasma is; Particles move independently of one another and are widely spaced.
What is the kinetic-molecular theory?The kinetic-molecular theory in discuss postulates about the states of matter.
Also, it is built upon the idea that matter is composed of tiny particles that are constantly in motion.
Hence, the theory is explanatory of the observable properties and behaviours of solids, liquids and gases and hence, explains the compressibility of plasma.
Remarks;
Particles move independently of one another and are widely spaced. Particle kinetic energy increases with increasing temperature. Particles exert no attractive or repulsive force on one another. Particles always move even when they have fixed positions.Read more on kinetic molecular theory;
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The empirical formula of the sugar glucose is ch2o. if the relative molecular mass of glucose is measured to be 180.16 g/mol then what is the molecular formula for glucose?
Answer:
18016
Explanation:
(empirical formula)n=molar mass
Answer: C_6 H_12 O_6
Explanation: The molar mass of glucose is given as 180.16 gm/mol.
It is 40% carbon, so the weight of the carbon is 40% of 180.16 =72.06 gm. The molar weight of the carbon is 12.011 gm, so the total number of the moles of carbon are 72.06/12.011 = 6 moles.
It is 6.719% of hydrogen, so the weight of the hydrogen is 6.719% of 180.16 = 12.105 gm. The molar weight of the hydrogen is 1.008 gm, so the total number of the moles of hydrogen are 12.105/1.008 = 12 moles.
It is 53.27% of oxygen, so the weight of the oxygen is 53.27% of 180.16 = 95.97 gm. The molar weight of the oxygen is 16 gm, so the total number of the moles of oxygen are 95.97/16 = 6 moles.
What happens to the kinetic energy of the particles in a sample of gas as
the temperature of the sample increases?
Answer:
See below
Explanation:
Temperature is basically a measure of the average kinetic energy of the particles in the sample ....so as temp goes up, kinetic energy increases
What is the molar mass of a protein if a 0. 30 l of solution containing 0. 45 g of the protein has an osmotic pressure of 0. 80 torr at 25∘c?
The molar mass of a protein if a 0. 30 l of solution containing 0. 45 g of the protein has an osmotic pressure of 0. 80 torr at 25∘c is 0.348 g/mol
Here we can apply the formula ∏ = iMRT, where ∏ = osmotic pressure = 0.80 - ( given ). This is only one part of the information we are given / can conclude in this case ....
i = van’t Hoff factor = 1 for a protein molecule,
R = gas constant = 62.36 L torr / K-mol,
T ( temperature in Kelvin ) = 25 + 273 - conversion factor C° + 273 = 298K
( Known initially ) ∏ = osmotic pressure = 0.80 torr
besides the part " M " in the formula, which we have no information on whatsoever, as we have to determine it's value.
_____
Substitute derived / known values to solve for M ( moles / liter ) -
∏ = iMRT
⇒ 0.80 = ( 1 )( M )( 62.36 )( 298 )
⇒ 0.80 = M( 18583.28 )
⇒ M = 0.80 / 18583.28 ≈ 4.3049 ....
_____
We know that M = moles / liter, so we can use this to solve for moles, and hence calculate the molar mass by the formula molar mass = g / mol -
M = mol / l
⇒ 4.3049 = 0.045 / 25 mL ( 0.030 L ),
0.045 / 0.030 = 1.5 g / L
⇒ 1.5 g = 4.3049 moles,
molar mass = 1.5 g = 4.3049 moles = 0.348 g / mol
Thus the concluded that the molar mass of protein is 0.348 g / mol.
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In an electric current, the ___ particles flow or are pushed along a path
positive
negative
neutral
What is the milliosmolarity of a 0. 2 m glucose solution, assuming that the atoms in a glucose molecule are held together by covalent bonds?
There is 200 milliosmolarity of a 0. 2 m glucose solution, assuming that the atoms in a glucose molecule are held together by covalent bonds .
Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution. Dilution is a process of decreasing the concentration of a solution by adding a number of solvents
Calculation ,
The molarity of the glucose = 0.2 M
the mili means [tex]10^{-3}[/tex] of any unit.
So , the 1mM = 1 × [tex]10^{-3}[/tex] M
So , 0.2 M = 0.2/ [tex]10^{-3}[/tex] M = 0.2 × [tex]10^{3}[/tex] = 200 mM
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When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 600 k is equal to 1. 4×10^5j/mol. Calculate the equilibrium constant at 600 k.
The standard free energy change ΔG° at 600 K is equal to 1. 4×[tex]10^5[/tex]J/mol then the equilibrium constant at 600K is 0 .
Calculation ,
ΔG° = - RT㏑Kp
Where ΔG° = standard free energy change = 1. 4×[tex]10^5[/tex]J/mol
R = universal gas constant = 8.3 J / K mol
T = temperature = 600K
Kp = equilibrium constant
Now putting the value of all data in equation (i) we get ,
1. 4×[tex]10^5[/tex]J/mol = - 8.3 J / K mol × 600K ㏑Kp
- 1. 4×[tex]10^5[/tex]J/mol /8.3 J / K mol × 600K = ㏑Kp
㏑Kp = - 6972×[tex]10^5[/tex]
Kp = 0
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What mass of cu(s)cu(s) is electroplated by running 14. 5 aa of current through a cu2 (aq)cu2 (aq) solution for 4. 00 hh?
Mass of copper would be=92.46 g
I = Current = 19.5 A
t = 4 hours =4×60×60=14400 s
F = Faraday constant = 96485.33 C/mol
Molar mass of copper = 63.546 g/mol
A charge is given by
Q=19.5×14400=280880 C
Moles of electrons are given by Q/F=280880/96485.33=2.91 mol
Moles of copper is=1/2×2.91=1.455 mol
Mass of copper would be=1.455×63.546=92.46 g
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The mass of Copper electroplated is 68.76 g
What is electroplating?The process of plating a metal onto another is known as electroplating.
It is often used to prevent corrosion of metal or for the decorative purposes
In this process, electric current is passed through an aqueous solution containing dissolved cations.
The dissolved cations are reduced developing a thin metal coating on the electrode.
At cathode,
[tex]Cu^{2+}(aq) + 2e^-\rightarrow Cu(s)[/tex]
Current, I = 14.5 A
Time, t = 4 hrs = 4×60×60 = 14400 sec
Charge, q = It = 14.5×14400= 208800 C
Copper metal deposited by 2×96487 C = 63.55 g
Copper metal deposited by 208800 C = [tex]\frac{63.55 \times208800}{2\times96487}[/tex]
= 68.76g
Hence, The mass of Copper electroplated is 68.76 g
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Describe the principle. Involved in Gas chromatography.
