what rule changes input to output numbers

Answer:

3/10

Step-by-step explanation:

The question asks for the probability of finding 4 or more, so first, you must add up all of the teenagers that have 4 or more shoes. Both the 4 and 5 categories fit, so add 20 and 10. Then, find the total number of people in the sample size. Overall, 100 teenagers are represented. Finally, put the number of people that have 4 or more shoes, 30, over the sample size, 100. This equals 30/100 which should be simplified to 3/10.

Answer:

£1837.5

Step-by-step explanation:

Given data

Cost of car P=  £2100.

Rate r= 2.2%

Time t= 6 years

Now we want to find the  worth after 6 years, let us apply the compound interest expression but this time for depreciation

A= P(1-r)^t

Substitute

A= 2100(1-0.022)^6

A= 2100*(0.978)^6

A= 2100*0.875

A= £1837.5

Hence the amount of the car after 6 years is £1837.5

Answer:

1, 3, 4

Step-by-step explanation:

Points N and K are on plane A and plane S

Point P is the intersection of the line n and line g

Points M, P, and Q are noncollinear

Answer:

Option (d), (e) and (f) are correct.

Step-by-step explanation:

In triangle MNP, angle P = 90 degree

Cos M = 7 / 12

Now according to the right angle triangle

[tex]NP^2 = NM^2 - PM^2\\\\NP^2 = 12^2 - 7^2\\\\NP = \sqrt95[/tex]

Now

[tex]Sin M = \frac{sqrt95}{12}\\\\Cos N = \frac{95}{12}[/tex]

Answer:

Step-by-step explanation:

This is an even function (because it has an exponent that is an even number), and even functions have the end behavior of both tails going in the same direction. Because this is a positive even function, both of the tails are going up.

Answer:

105 inventions

Step-by-step explanation:

Find how many inventions Inventor B had by dividing 630 by 6:

630/6

= 105

So, Inventor B had 105 inventions

Answer:

khgygygiugug

Step-by-step explanation:

Dr black is standing 13 feet from a streetlamp. The lamp is making his shadow 9 feet long. He estimates that the angle of elevation from the tip of his shadow to the top of the streetlamp is 50° to the nearest foot the streetlamp is about  26 feet tall.

I hope this helps!

Answer:

z=4x

=14y10

Step-by-step explanation:

this is the answer

Answer:

Step-by-step explanation:

The equation of the growth is:

Since the target number is 76 we get:

Answer: 46 months

Step-by-step explanation:

Answer:

-60x

Step-by-step explanation:

We simply open up the bracket and collect similar terms

So we have;

4(-15x-2) + 8 as:

4(-15x) -2(4) + 8

-60x -8 + 8

= -60x

Answer: 60x

Step-by-step explanation: -60x-8+8=-60x

Answer:

Hope you find it helpful and usef

Answer:

A.

Step-by-step explanation:

To find the inverse of a function, first make f(x) a y

So,

y = [tex]\frac{12}{x}[/tex] -18

Then switch the x and the y

x = [tex]\frac{12}{y}[/tex] - 18

Solve, for y

Answer:

[tex]volume = 2304\pi \ mm^3\\\\volume = 7234.56 \ mm^3[/tex]

Step-by-step explanation:

Radius , r = 12mm

[tex]Volume = \frac{4}{3} \pi r^3 = \frac{4}{3} \pi (12^3)\\\\[/tex]

                      [tex]=\frac{4}{3} \pi \times 1728\\\\= 4\pi \times 576\\\\= 2304 \pi \ mm^3\\\\or \\\\= 7234.56 \ mm^3[/tex]

Answer:.

Step-by-step explanation:

Given:

The fees for a day student are $600 a term.

The fees for a boarding student are $1200 a term.

The school needs at least $720000 a term.

To show:

That the given information can be written as [tex]x + 2y\geq 1200[/tex].​

Solution:

Let x be the number of day students and y be the number of boarding students.

The fees for a day student are [tex]\$600[/tex] a term.

So, the fees for [tex]x[/tex] day students are [tex]\$600x[/tex] a term.

The fees for a boarding student are [tex]\$1200[/tex] a term.

The fees for [tex]y[/tex] boarding student are [tex]\$1200y[/tex] a term.

Total fees for [tex]x[/tex] day students and [tex]y[/tex] boarding student is:

[tex]\text{Total fees}=600x+1200y[/tex]

The school needs at least $720000 a term. It means, total fees must be greater than or equal to $720000.

[tex]600x+1200y\geq 720000[/tex]

[tex]600(x+2y)\geq 720000[/tex]

Divide both sides by 600.

[tex]\dfrac{600(x+2y)}{600}\geq \dfrac{720000}{600}[/tex]

[tex]x+2y\geq 1200[/tex]

Hence proved.

Answer:  

11.0.0035

12.39×10^-4

13.)0.00031

14.59800

15.3.6×10^9

Step-by-step explanation:

Answer:

During that time, math symbols (like the division and multiplication sign) and numbers weren't invented yet, so they used words because that was the only choice either than verbally speaking.

Step-by-step explanation:

This is open-ended question, so you can write something similar to the answer I wrote or add on to it :-)

I searched online for the answer and found it on Brainly just to let you know because I was unsure about it loll

Credit: Edufirst

Hope it helps (●'◡'●)

Answer:

1/3 more pounds of string beans.

Step-by-step explanation:

Amount of string beans: 5/12 of a lbs(pound)

Amount of lima beans: 1/12 of a lbs

Amount of string beans - Amount of lima beans = 5/12-1/12 =4/12 which simplifies down to 1/3.

Answer:

36

Step-by-step explanation:

63/(7/4) 63 divided by 7/4

63* 4/7 63 multiplied by 4/7

=36 answer is 36

Answer:

The answer is D.

Step-by-step explanation:

Answer:

A 180° rotation of then a dilation by a scale factor of one-third

Step-by-step explanation:

The coordinates of the vertices of ΔABC are;

A(-9, 3), B(-9, 6), and C(0, 3)

The coordinates of the vertices of ΔA'B'C' are;

A'(3, -1), B'(3, -2), and C'(0, -1)

We note that for a 180° rotation transformation about the origin, we get;

Coordinates of preimage = (x, y)

Coordinates of image after 180° rotation about the origin = (-x, -y)

Therefore, a 180° rotation of ΔABC about the origin, would give ΔA''B''C'' as follows;

A(-9, 3), B(-9, 6), and C(0, 3) = A''(9, -3), B''(9, -6), and C''(0, -3)

The formula for a dilation of a point about the origin is given as follows;

[tex]D_{O, \, k} (x, \, y) = (k\cdot x, \, k\cdot y)[/tex]

Where;

k =The scale factor = 1/3, (one-third) we have;

A dilation of ΔA''B''C'', by a scale factor of 1/3, we get ΔA'B'C' as follows;

[tex]D_{O, \, \frac{1}{3} } A''(9, \, -3) = A'(\frac{1}{3} \times 9, \, \frac{1}{3} \times -3) = A'(3, -1)[/tex]

[tex]D_{O, \, \frac{1}{3} } B''(9, \, -6) = B'(\frac{1}{3} \times 9, \, \frac{1}{3} \times -6) = A'(3, -2)[/tex]

[tex]D_{O, \, \frac{1}{3} } C''(0, \, -3) = C'(\frac{1}{3} \times 0, \, \frac{1}{3} \times -3) = C'(0, -1)[/tex]

The coordinates of the vertices of ΔA'B'C' are A'(3, -1), B'(3, -2), and C'(0, -1), which is the same as the required coordinates of the image;

Therefore, the transformation that can be performed to show that ΔABC and ΔA'B'C' are similar are rotating ΔABC by 180°  then a dilating the image derived after rotation by a scale factor of one-third (1/3) we get ΔA'B'C'.

Answer:

D

Step-by-step explanation:

Answer:

Option no. D is right. Because the congruence presented is more congruent

Answer:

d)

Step-by-step explanation:

>The domain are all the values of x , so you can graph on the calculator that on the x-axis the graph starts at 9 and keeps going to the right so the domain is x≥9 or [9,∞)

or

>Solve for x in the given equation when f(x) =y = 0 to find the roots

√(x-9) = 0 , square both sides

x-9 = 0 , add 9 to both sides

x= 9

from this root the graph moves to the right to ∞

the domain is [9, ∞)

Answer:

for question B

2A 3C = 70

70-15 = 55/5 = 11.

so each child is 11

while adult 11 + 7.50 = 18.50

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]

[tex]y-620=\dfrac{749-620}{70-30}(x-30)[/tex]

[tex]y-620=\dfrac{129}{40}(x-30)[/tex]

[tex]y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)[/tex]

[tex]y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}[/tex]

Adding 620 on both sides, we get

[tex]y=\dfrac{129}{40}x-\dfrac{387}{4}+620[/tex]

[tex]y=\dfrac{129}{40}x+\dfrac{2480-387}{4}[/tex]

[tex]y=\dfrac{129}{40}x+\dfrac{2093}{4}[/tex]

We need to find the y-value for [tex]x=57[/tex].

[tex]y=\dfrac{129}{40}(57)+\dfrac{2093}{4}[/tex]

[tex]y=183.825+523.25[/tex]

[tex]y=707.075[/tex]

[tex]y\approx 707.1[/tex]

Therefore, the required linear equation for the given situation is [tex]y=\dfrac{129}{40}x+\dfrac{2093}{4}[/tex] and the average score for persons taking a 57-hour review course is 707.1.

The equation will be:

25 + d = t

where t is total money