The intensity of sunlight at the Earth is about 1367 W/m^2. How many times further away would the Sun have to be from the Earth before solar radiation was only as intense as a 100W light bulb 10 meters away, assuming that all energy from the bulb goes into radiation and spreads out evenly in all directions?
The intensity of sunlight on the Earth is about 1367 W/m^2. The earth has to be 131 the distance farther away
This is further explained below.
What is the distance?Generally, bet the power emitted by the sun is P. so. at the distance of earth intensely where [tex]$r_E$[/tex] is the distance of the earth from the sun. were [tex]$I_1=1362 \frac{w}{m^2}$[/tex]
Therefore
p=4 [tex]\pi 1367 r_E^2[/tex]
let at distance [tex]\gamma r_E$[/tex] is a positive number) the intensity is the same as the intensity at 10m away from a 100w bulb. So.
In conclusion,
[tex]\begin{aligned}&\frac{P}{4 \pi\left(\gamma r_{\varepsilon}\right)^2}=\frac{100}{4 \pi 10^2}\\\\&\text { or, }\left(\gamma r_E\right)^2=P=4 \pi 1367 r_E^2\\\\&\therefore \gamma=\sqrt{4 \pi \times 1367}\\\\&=131.06\\\\ }\end{aligned}[/tex]
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is h20 an element, atom, compound, or molecule
2 If we want to test the strength of electrical forces between a pair of charged objects, which of the following questions should we ask? A B How much mass does each object have? D Are the objects made up of the same material? C Does each object sink or float in water? What happens when the objects are moved further apart?
Electric force is the attracting or repulsive interaction between any two charged things. Similar to any force, Newton's laws of motion describe how it affects the target body and how it does so. One of the many forces that affect objects is the electric force.
The electric force F, or Coulomb force, exerted per unit positive electric charge q at that place can be used to determine an electric field's strength, or E = F/q.
The amount of charge on the source charge (Q) and the distances from the source charge (d) both affect how strong the electric field is.
To test the strength of electrical forces we should ask the following questions:
What is the mass of each object?Is the substance the objects are made of the same?The volt per meter (V/m or Vm-1) is the common unit. A potential difference of 1 V between sites separated by 1 meter is represented by a field strength of 1 V/m. Electric field intensity is another name for electric field strength. An electric field is created by any electrically charged item.
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How do I solve this situation, If the normal force COULD BE greater than the force of gravity in this situation the object would be:a) Accelerating upwards b) moving at constant speed upwardsc) moving at constant speed downwards d) Accelerating downwards
a) Accelerating upwards
Explanations:[tex]\text{Let the force of gravity be represented by F}_g[/tex][tex]\text{Let the normal force be represented by F}_N[/tex]Consider the diagram drawn below
The force of gravity acts downward
The normal force acts upward
[tex]\text{If F}_N>F_g[/tex]That is, if the normal force is greater than the force of gravity, the object accelerates upwards
A force of 1 N is equal to which combination of SI units?
A force of 1 Newton is equal to 1 kgm/s^2 in the International System of units (SI)
Annular and penumbral refer, respectively, to which phenomenon?
O A.
OB.
O C.
O D.
spring and autumn tides
solstice and equinoxes
solar and lunar eclipses
elliptical and round orbits
Annular and penumbra are terms that are associated with Solar and lunar eclipses. Option C is the correct answer
What is an Eclipse ?An eclipse is a result of a shadow cast by one heavenly body on another. There are eclipse of the sun or solar eclipse and eclipse of the moon or lunar eclipse.
Annular and penumbra actually refer, respectively, to the phenomenon known as solar and lunar eclipses.
Penumbra is a region of outer light or grey area of a shadow cast by an object or heavenly body.
While Annular can be formed under condition where the extreme rays at the moon's edge intersect before reaching the earth.
Therefore, Annular and penumbra refer to the solar and lunar eclipses respectively.
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I need help with a physics worksheet about Newtons Laws.
The diagram of the object on the inclined plane is shown below
The mass of 7kg is exerted on the plane surface. It is acted upon by gravity. The force exerted on the surface is calculated by applying the formula,
F = mass x acceleration due to gravity
Assumme acceleration due to gravity is 9.8m/s^2, then
Force = 7 x 9.8 = 68.6N
The surface exerts an opposite force of the same magnitude with the force of the object but in opposite direction. Since it is inclined at an angle of 36.9 degrees,
Normal force = mgCosθ = 68.6Cos36.9 = 54.86N
Recall, frictional force = normal reaction x coefficient of friction
Given that coefficient of kinetic friction = 0.35,
Frictional force = 54.86 x 0.35 = 19.201N
This is the force that must be overcome to keep the object moving.
The force pulling the object upwards along the inclined plane is
mgSinθ = 7 x 9.8 x Sin36.9 = 41.19N
Since the velocity is constant, it means that there is no acceleration. The net force is zero. The force required to pull the mass and make it move at constant velocity must be equal to the sum of the exerted force and the the frictional force(Since it involves coeffricient of kinetic friction, it would cause the object to keep moving)
Thus,
Required force = 19.2 + 41.19 = 60.4N
Option E is correct
31. When water boils (or vaporizes)...Select one:a. water molecules become more free to move around.b. water molecules become less free to move around.c. water molecules are not affected.d. water molecules stay the same, but their temperature changes.
a. water molecules become more free to move around.
gases have a lower density and the molecules are free to move more and faster
Tony twirls a pizza dough overhead. It is rotating at 0.65 m/s. If the pizza dough has a radius of 0.10 m and a mass of 0.50 kg, what centripetal force is it experiencing?
Given,
The linear velocity of the pizza dough, v=0.65 m/s
The radius of the pizza dough, r=0.10 m
The mass of the pizza dough, m=0.50 kg
The centripetal force of an object is given by the equation,
[tex]F=m\frac{v^2}{r}[/tex]On substituting the known values in the above equation,
[tex]\begin{gathered} F=0.50\times\frac{0.65^2}{0.10} \\ =2.11\text{ N} \end{gathered}[/tex]Thus the centripetal force experienced by the pizza dough is 2.11 N
A plane takes off at 300 m/s at an angle of 25 degrees to the ground. Find the perpendicular components of the velocity vector. ASAPPP
Answer: The direction of the resultant can be determined by finding the angle that the resultant makes with either the north-south or the east-west vector. The diagram at the right shows the angle theta (Θ) marked inside the vector addition triangle. This angle theta is the angle that the resultant makes with west.
Explanation: hope this helps
Two objects, one of mass m and the other of mass 2m, are dropped from the top of a
building. When they hit the ground
a. they will have the same kinetic energy.
b. the heavier one will have twice the kinetic energy of the lighter one.
c. the heavier one will have four times the kinetic energy of the lighter one.
d. the heavier one will have times the kinetic energy of the lighter one.
Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground (b) The heavier one will have twice the kinetic energy of the lighter one.
For two object's, one of mass m and other of mass 2m , the kinetic energy is given by :
K.E = (1/2) mv² for mass m
K.E = (1/2) (2mv²) for mass 2m
It is clear that , the kinetic energy of mass 2m is twice that of the object of mass m. and their velocity are equal.
When the object dropped from top or from some height its acceleration is equal to acceleration due to gravity. initial velocity will be zero.
Thus, Two objects, one of mass m and the other of mass 2m, are dropped from the top of a building. when they hit the ground (b) The heavier one will have twice the kinetic energy of the lighter one.
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A pendulum is constructed by attaching a small metal ball to one end of a string of length =1.20 m that hangs from the ceiling, as shown in the figure. The ball is released when it is raised high enough for the string to make an angle of =20.0∘ with the vertical.
With what speed is the ball moving at the bottom of its swing?
The speed of the ball when released from the top will be 2.97m/s at the bottom of the swing.
The length L of the string of ball is 1.2 meter.
The angle made by the string while going up is 20°.
We know,
According to the law of conservation of energy,
Total energy remains constant at every point of the motion, because energy can neither be created nor be destroyed,
So,
Total energy at the top point = Total energy at the bottom point
MgH = 1/2Mv²
Where,
M is the mass of the ball,
g is the acceleration due to gravity,
v is the speed at the bottom point,
H is the height till it is raised.
We can find H,
Total length minus vertical component of the length,
H = L - LcosA
H = 1.2(1-cos20°)
H = 1.2(1-0.93)
H = 1.2(0.37)
H = 0.444 meters.
Now, putting all the values, to find the value of v,
MgH = 1/2Mv²
gH = 1/2v²
v = √2gH
v = √2x10x0.444
v = 2.97m/s
Speed of the ball at the bottom is 2.9m/s.
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a ball is thrown horizontally from a height of 1 m and lands 5 m away
Answer:
it's from gravity because when you throw something up it goes forward a certain distance
an object is thrown downward with initial (t=0) speed of 10m/s from a height of 60m above the ground.at the same instant (t=0), a second object is propelled vertically upward from the ground level with a speed of 40m/s . at what height above the ground will the two objects pass each other.
The two objects pass each other at a height of 41 m above the ground.
What are equations of motion?The equations of motion are the set of equations that describe the relationship between the velocity, acceleration, time, and distance traveled by the object.
The equation used to calculate the distance or height covered by an object is:
S = ut + 1/2 at²
Given, the first object has speed downward, u₁ = -10 m/s
The height of the first object from the ground, S₁ = 60 m
The initial speed of the second object, u₂ = 40 m/s
The distance S for the first object thrown downward:
S = S₁ + u₁t -(1/2)gt²
S = 60 - 10t - (1/2)gt² ...........(1)
The distance S for the second object thrown upward:
S = u₂t -(1/2)gt²
S = 40 t - (1/2)gt² ............(2)
The equation (1) and (2) solve to find the value of 't':
60 - 10t - (1/2)gt² = 40 t - (1/2)gt²
60 = 50 t
t = 6/5 sec
Substitute the value of 't' in equation (2) to find the value of S:
S = (40) (6/5) - (1/2)× (9.81) ×(6/5)²
S = 41 m
Therefore, both objects pass each other at a height of 41 m above the ground.
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In the absence of air resistance, a projectile launched at an angle of 33° above the horizontal will have the same range as a projectile launched at which of the following angles?a.)57°b.)38° c.)45°
ANSWER
[tex]a)\text{ }57\degree[/tex]EXPLANATION
We want to find the angle at which the range for the projectiles will be the same.
The range for a projectile is given by:
[tex]R=\frac{u^2\sin2\theta}{g}[/tex]where u = initial velocity
θ = angle of the projectile
g = acceleration due to gravity
For a projectile to have the same range as one with an angle of 33° (given that other values are constant), the value of sin(2θ) must be equal for both projectiles.
Let us find the value of sin(2(33°)):
[tex]\sin(2*33)=\sin66=0.9135[/tex]Let us find the same for the angles in the options:
[tex]\begin{gathered} \sin(2*57)=\sin114=0.9135 \\ \\ \sin(2*38)=\sin76=0.9703 \\ \\ \sin(2*45)=\sin90=1 \end{gathered}[/tex]As we can see, the angle that will result in the same range as 33° is 57°.
The answer is option a.
A ceramic container used for melting metals (called a crucible) contains 1.30 kg of a molten metal. The liquid metal cools until it reaches its melting point of 1,749°C. A scientist then measures that 2.99 ✕ 10^4 J of heat is transferred out of the metal before it completely solidifies. What is the latent heat of fusion of this metal, in J/g? (Be careful with units!)
Answer:
23 J/g
Explanation:
The heat transferred in a phase change like this case is calculated as:
[tex]Q=mH_f[/tex]Where m is the mass and Hf is the latent heat of fusion. We can solve the equation for Hf
[tex]H_f=\frac{Q}{m}[/tex]Now, replacing Q = 2.99 x 10⁴ J and the mass = 1300 g, we get:
[tex]H_f=\frac{2.99\times10^4J}{1300\text{ g}}=23\text{ J/g}[/tex]We use 1300 g instead of 1.30 kg because we want the units in J/g.
Therefore, the latent hear of fusion of this metal is 23 J/g
A truck travels up a hill with a 6.9" incline.
The truck has a constant speed of 24 m/s.
What is the horizontal component of the
truck's velocity?
Answer in units of m/s.
With the application of resolution of vectors, the horizontal velocity is 23.99995 m/s
What is Uniform Speed ?Uniform speed is also known as constant speed. This can be defined when the distance travel by an object per time taken is constant.
Given that a truck travels up a hill with a 6.9" incline. The truck has a constant speed of 24 m/s.
First convert minute to degree.
1 minute = 0.0166667
6.9 minute = 6.9 × 0.016667 = 0.115 degree
The formula for the horizontal component of the truck's velocity will be UcosФ, while the vertical component is UsinФ
Substitute all the parameters into the equation.
Horizontal velocity = 24cos 0.115 = 23.99995 m/s
Therefore, the horizontal component of the truck's velocity will be 23.99995 m/s which can be approximated to 24 m/s
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Is more mass weaker gravity or stronger gravity
According to the law of universal gravitation:
gravitational force is directly proportional to the mass of the object as shown in the equation below
[tex]F=\frac{Gm_1m_2}{r^2}[/tex]Since the force of gravity varies directly with the mass, as the mass incr
1) A thin converging lens of focal length 11.9 cm
forms an image of an object placed 27.7 cm
from the lens.
Find the image distance.
Answer in units of cm.
2) What is the magnification for an object dis-
tance of 27.7 cm?
3) Find the location of the image for an object
distance of 4.46 cm.
Answer in units of cm.
4) Calculate the magnification for an object dis-
tance of 4.46 cm.
Answer:
Explanation:
Focal length
f
=
10.8
c
m
Object distance
d
o
=
35.7
c
m
Part A:
The image distance would be
1
f
=
1
d
o
+
1
d
i
1
10.8
c
m
=
1
35.7
c
m
+
1
d
i
d
i
≈
15.5
c
m
Part B:
The magnification would be
m
=
−
d
i
d
o
=
−
15.5
c
m
35.7
c
m
≈
−
0.43
Part C:
The image distance if the object distance
d
o
=
5.59
c
m
, would be
1
f
=
1
d
o
+
1
d
i
1
10.8
c
m
=
1
5.59
c
m
+
1
d
i
d
i
≈
−
11.6
c
m
Part D:
Its magnification would be
m
=
−
d
i
d
o
=
−
−
11.6
c
m
5.59
c
m
≈
2.08
The speed of a moving bullet can be determined by allowing the bullet to pass throughtwo rotating paper disks mounted a distance75 cm apart on the same axle. From theangular displacement 33.9◦of the two bullet holes in the disks and the rotational speed1209 rev/min of the disks, we can determinethe speed of the bullet.33.9◦v1209 rev/min75 cmconroy (klc4842) – Homework 7, rotation 21-22 – dowd – (TorresLPHY1 3) 2What is the speed of the b
Answer:
160.49 m /s
Explanation:
We know that the angular speed of the disks is 1209 rev/min.
[tex]\omega=1209\text{rev}/\min [/tex]Let us convert this into degrees / s.
Now
1 rev = 360 degreees and 1 min = 60 s; therefore,
[tex]\omega=\frac{1209\cdot360^o}{60s}[/tex][tex]\boxed{\omega=7254^o/s\text{.}}[/tex]Now, we know that the angular separation of the holes in the two disks is 33.9 degrees. How long did it take the paper disk to rotate by this amount? The answer is
[tex]33.9=(7254^o/s)t[/tex]where t is the time needed.
Solving for t gives
[tex]t=\frac{33.9}{7254}s[/tex][tex]\boxed{t=4.67\times10^{-3}s}[/tex]This means 4.67 * 10^-3 seconds passed before the bullet hit the second disk after hitting the first.
Now, we know that in those 4.67 * 10^-3 seconds, the bullet certainly travelled 75 cm = 0.75 m; therefore, its speed must be given by
[tex]\begin{gathered} d=vt \\ \Rightarrow0.75=v(4.67\cdot10^{-3}s) \end{gathered}[/tex]dividing both sides by 4.67 * 10^-3 s gives
[tex]v=\frac{0.75m}{4.67\cdot10^{-3}s}[/tex][tex]v=160.49m/s[/tex]rounded to the nearest hundredth.
Hence, the velocity of the bullet (rounded to the nearest hundredth) is 160.49 m/s.
Two students hang a magnet just above a paper clip.Which action would make the magnetic force between the magnet and thepaper clip stronger?A. Add electrons to the magnet.B. Move the magnet farther away from the paper clip.C. Add protons to the paper clip.D. Move the magnet closer to the paper clip.the
The magnetic field lines are more around the magnet. In this magnetic field lines, the magnetic force are observed. When the paper clip comes under these magnetic field lines, it will experience more force.
By the decreasing the distance between the magnet and paper clip, more force will act on the paper clip. The magnet will attract the paper clip with the magnetic force towards itself and also adjust the direction the direction of clip depending upon the direction of north pole and south pole of the magnet.
Thus, the option D is the correct option.
Answer: d
Explanation:
i took the quiz.
A copper block of mass 0.75 g is removed from a furnace and quickly transferred into a glass beaker of mass 300.0 g containing 200.0 g of
water. The temperature of the water rises from 12 0 °C to 27 0 °C. What was the temperature of the furnace?
The furnace has a temperature of 585 degrees Celsius.
Temperature is an expression denoting hotness or coolness on any scale, including Fahrenheit and Celsius. According to temperature, heat energy will naturally move from a hotter (body with a higher temperature) to a colder (body with a lower temperature) (one at a lower temperature).
Agriculture, food production, and medical care—for both humans and animals—all rely largely on
A spring pushes a block with 120 N of force for 0.250 m. Solve for the energy given by the spring. (ans: 30 j)
Answer:
Energy = 30J
Explanation:
Energy = Force x Distance
Energy = 120 x 0.250m
Energy = 30J
Many people are looking for ways to “go green” in their life, to reduce their impact on the environment. Solar appliances, such as ovens, are one way to do this. *What do you think would be the advantages of solar appliances?any disadvantages?
Since solar appliances uses solar power, the advantages of using them are
1) Green house effect is minimised since fuels are not burnt to power them.
2) The source of power is renewable. This means that the power for the appliances is readily available.
3) Pollution is reduced
4) They are safer than traditional powered appliances
The disadvantages include
1) The availability of power varies with time. It is reduced at night, winter periods because of lack of sunshine. This means that the usage of solar appliances would be limited during these periods.
2) High cost of installing solar power and batteries might be required to store power and this makes it to be more expensive.
3) The appliances may not be as efficient as traditionally powered appliances.
George is trying to move a heavy bookshelf across the classroom. He pushes on the bookshelf with a force of 57 N to the right Friction is resisting his movement with a force of78 N. The bookshelf does not move. A friend comes to help George, The friend pushes the bookshelf in the same direction as George with a force of 25 N. What will happen tothe bookshelf?The bookshelf will not move,0000The bookshelf will move to the left with a force of 25 NThe bookshelf will move to the right with a force of 82 NThe bookshelf will move to the right with a force of 4 N.
Given data:
* The force applied on the bookshelf towards the direction of motion by George is,
[tex]F_1=57\text{ N}[/tex]* The force applied on the bookshelf towards the direction of motion by the friend of George is,
[tex]F_2=25\text{ N}[/tex]* The force of friction opposite to the direction of motion is,
[tex]F=78\text{ N}[/tex]Solution:
Thus, the net force acting on the bookshelf is,
[tex]F_{net}=F_1+F_2-F[/tex]Here, the negative sign before the friction force indicates the direction of friction force is oppoiste to the direction of motion,
Substituting the known values,
[tex]\begin{gathered} F_{net}=57+25-78 \\ F_{net}=4\text{ N} \end{gathered}[/tex]Here, the positive value of net force indicates the net force is acting in the direction of motion of the bookshelf.
Thus, the bookshelf will move to the right with a force of 4 N.
Hence, 4th option is the correct answer.
Is it possible for an object to be in motion and yet have zero net force acting onit? Explain.
Answer:
Yes, it is possible for an object to be in motion without,no net force acting on it.
Explanation:
Answer:
Its is not possible for a object to be in motion with zero net force
Explanation:
This means that an object thats has no net force WILL BE IN REST AND CANT BE IN MOTION
What amount of force is required to accelerate a 1,264 kg car at a rate of 13 m/s²?
(Round you answer to the nearest whole number. Do not use units or decimals in your answer.)
16432 N force is required to accelerate a 1,264 kg car at a rate of 13 m/s²
What is force?Force is an external agent that may change the condition of rest or motion of a body. It has a magnitude as well as a direction. The direction of the force is the place where force is applied, and the application of force is the location where force is applied. Newton (N) is the SI unit of force.
Given that,
Mass of the car (m) = 1264 kg
Acceleration (a) = 13 m/s²
Now calculate how much force (F) is required,
F = m × a
F = 1264 × 13 kg m/s²
F = 16432 N
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A circuit consists of one resistor connected to a battery. How will adding another resistor in series to the first resistor change the current of the circuit? Briefly justify your answer. (2 Points)
When two resistors are connected in series, their action is equivalent to a single resistor with an equivalent resistance which is the sum of the individual resistances:
[tex]R_{eq}=R_1+R_2[/tex]This means that the equivalent resistance must always be greater than any of the resistances that the series association is made of.
Since the current I, the resistance R and the voltage V are related through the following equation:
[tex]I=\frac{V}{R}[/tex]If we increase the value of R, then the value of I will decrease.
Therefore, adding another resistor in series will decrease the current through the circuit.
A uniform board 6.2 m long with a mass of 65 kg is attached to a wall with a pivot. A wooden crate sits in the board 2 m from the left edge. A rope with a tension of 800 N that makes an angle of 45 degrees with the horizontal is attached 0.3 m from the left end of the beam and connects the beam to the same wall as the pivot to keep the system balanced. What is the mass of the wood crate?
ANSWER:
92.09 kg.
STEP-BY-STEP EXPLANATION:
Mass board (M) = 65 kg
Length board (L) = 6.2 m
Left edge wooden (l) = -2 m
Tension (T) = 800 N
There are a total of 3 forces acting on the board, they are the following:
[tex]\begin{gathered} W_{board}=M\cdot g=65\cdot9.8=637\text{ N} \\ \\ W_{wooden}=mg=m(9.8)=9.8m\text{ N} \\ \\ T_y=T\cdot\sin\theta=800\cdot\sin45\degree=565.7\text{ N} \end{gathered}[/tex]Since the board is balanced, the net torque acting up will be equal to the net torque acting down.
So we can establish the following balance:
[tex]\begin{gathered} \tau_{tension}=\tau_{board}+\tau_{wooden} \\ \\ T_y\cdot d=W_{board}\cdot\frac{L}{2}+W_{wooden}\cdot l \\ \\ \text{ We replacing:} \\ \\ 565.7\cdot0.3=637\cdot\frac{6.2}{2}+9.8m\cdot-2 \\ \\ 169.71=1974.7-19.6m \\ \\ m=\frac{1974.7-169.71}{19.6} \\ \\ m=92.09\text{ kg} \end{gathered}[/tex]The mass of the wooden crate is 92.09 kg.
Describe an example of each one of Newton’s Laws during Usain’s race. Did you make use of these same laws in the same places in your race? Why or why not?
We will have the following:
Newton's first law: If a body is in motion it will remain in motion and if a body is still it will remain still until an external force acts upon it.
The example would be if Usain is still at the beginning of the race, he will remain still until he uses enough force to move.
Newton's second law: F = m*a
The example would be that in order to move his own mass he will need to apply enough force so he can start running, and the change in velocity he will experience will then be greater than 0.
Newton's third law: Every action has an equal and opposite reaction.
The example would be when Usain is running he is pushing the Earth so he gains movement, and so the Earth pushes Usain with the same magnitude but in opposite direction.
