Answer: It's D
Explanation:
A standing wave is created in a microwave oven by reflecting microwaves from the walls of the oven. The cold spots, the nodes in the microwave standing wave, are found to be 6 cm apart. What is the frequency of the microwaves? [Ans: 2.5 * 109Hz]
The frequency of the wave is given as 2.5 * 10^9 Hz.
What is wavelength?The term wavelength is the distance that is covered by a wave. It is also referred to as the distance between two successive crests or two successive troughs. It can also be defined as half of the distance between two nodes.
Now nodes are the points in which there is no movement while antinodes are the points in which there is movement.
Given that;
c = λf
c = speed of light = 3 * 10^8 m/s
λ = 2(6cm) = 12 cm or 12 * 10^-2 m
f = ??
Thus;
f = c/ λ
f = 3 * 10^8 m/s/12 * 10^-2 m
f = 2.5 * 10^9 Hz
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What is the de broglie wavelength of this electron? [ke[ke = 12mv2;12mv2; 1 electron volt (ev)(ev) = 1. 602×10−19j]
broglie wavelength of this electron is 107.5pm.
what is de broglie wavelength?
The wavelength (λ) that is associated with an object in relation to its momentum and mass is known as de Broglie wavelength.
Given:
de broglie wavelength of this electron? [ke[ke = 12mv2;12mv2; 1 electron volt (ev)(ev) = 1. 602×10−19j] is 107.5pm
[tex]h = 6.63 \times 10 { }^{ - 34} [/tex]
[tex]k = 120ev[/tex]
[tex]me = 9 \times 10 {}^{ - 31} kg[/tex]
[tex]1ev = 1.6 \times 10 {}^{ - 19} [/tex]
[tex]p = \sqrt{2mk} [/tex]
[tex] = \sqrt{2 \times 9 \times 10 { }^{ - 31} \times 1.6 \times 10 {}^{ - 19} } [/tex]
[tex] = 5.88 \times 10 {}^{ - 24} kgm/s[/tex]
de broglie wavelength
λ=h/p
[tex] = \frac{6.63 \times 10 {}^{ - 34} }{5.88 \times 10 {}^{ - 24} } [/tex]
Thus from the above calculation the de broglie wavelength comes out to be 107.5pm
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A car goes 122m at 30m/s How long did it travel?
Answer:
It took [tex]\bf 4.07 \space\ \mathrm{s}[/tex] to travel.
Explanation:
To calculate the time taken to travel a distance of 122 m at a speed of 30 m/s, we can use the formula for speed:
[tex]\boxed{speed = \frac{distance}{time}}[/tex].
We can substitute the known values, and then solve for time:
[tex]30 = \frac{122}{\mathrm {time}}[/tex]
⇒ [tex]\mathrm{time } = \frac{122}{30}[/tex]
⇒ [tex]\mathrm{time } \approx \bf 4.07 \space\ \mathrm{s}[/tex]
You are holding two balloons of the same shape and size. one is filled with helium, and the other is filled with ordinary air. On which balloon is the buoyant force greater?
Answer:
B (buoyant force) = weight of air displaced - weight of balloon
Both balloons will displace the same amount of air but the weight of the balloon filled with He is much less and will experience a greater buoyant force - actually if a balloon is filled with air its weight would be the same as the weight of the air displaced and there would be no buoyant force
Two point charges are brought closer together, increasing the force between them by a factor of 20. By what factor was their separation changed?
The separation between them is [tex]\frac{r}{\sqrt{20} }[/tex]
Concept :
If the force increases, distance between charges must decrease. Force is indirectly proportional to the distance squared.
Given,
Two point charges are brought closer together, increasing the force between them by a factor of 20.
Original force is
F = [tex]\frac{kq_{1} q_{2} }{r^{2} }[/tex] -------- ( 1 )
Here, [tex]q_{1} , q_{2}[/tex] are charges and r is the distance between them
New force F' = [tex]\frac{kq_{1q_{2} } }{r'^{2} }[/tex] ----------- (2 )
Divide ( 1 ) and ( 2 )
[tex]\frac{F'}{F}[/tex] = [tex]\frac{\frac{kq_{1}q_{2} }{r'^{2} } }{\frac{kq_{1}_{2} }{r^{2} } }[/tex]
20 = [tex]\frac{r^{2} }{r'^{2} }[/tex]
r' = [tex]\frac{r}{\sqrt{20} }[/tex]
Given that force between them are increasing and therefore distance between them decrease by [tex]\frac{r}{\sqrt{20} }[/tex]
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Consider annaca 2412 airfoil with a 2m chord in an airstream with a velocityof 50m/s at standard sealevel conditions([infinity]=1. 233⁄). ifthe lift per unit span is 1353n/m,what is the angle of attack?
The angle of attack of airfoil with a 2m chord in an airstream with a velocity of 50m/s, and the lift per unit span is 1353n/m will be 4 degrees.
To find the answer, we have to know more about the dynamic pressure.
How to find the angle of attack of the airstream?Given that[tex]l=2m\\v=50m/s\\L=1353N/m\\d_{infinity}=1.233Kg/m^3[/tex]
We have the expression for dynamic pressure as,[tex]P_d=\frac{1}{2} dv^2=\frac{1}{2}*1.233*50^2=1541.25 Pascals.[/tex]
We have the expression for lift coefficient in terms of lift per unit span, dynamic pressure and the chord length l as,[tex]k=\frac{L}{P*l} =\frac{1353}{1541.25*2}=0.438[/tex]
We have to find the angle of attack, and which can be defined in terms of k as,[tex]\alpha =sin^{-1}(\frac{k}{2\pi } )\\\alpha =sin^{-1}(\frac{0.438}{2\pi } )\\\alpha =4.007 degrees.[/tex]
Thus, we can conclude that, the angle of attack of airfoil with a 2m chord in an airstream with a velocity of 50m/s, and the lift per unit span is 1353n/m will be 4 degrees.
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When the red light is on, the pigeon does not peck on the disk because it has learned that food will only be presented when the green light is on. this demonstrates the concept of:________
When the red light is on the pigeon does not peck on the disk and picks on green light, this demonstration is Stimulus reinforcement.
Fantastic reinforcement refers to the introduction of a perfect or quality stimulus after a conduct. The acceptable stimulus reinforces the conduct, making it more likely that the conduct will reoccur.
Reinforcement can consist of anything that strengthens or increases a behavior. three In a lecture room setting, for example, varieties of reinforcement would possibly include giving praise, letting college students out of undesirable work, or presenting token rewards, sweet, greater playtime, or a laugh sports.
Disclaimer:-your question is incomplete, please see below for complete question
A pigeon has learned that pecking a key when a red light is on is sometimes reinforced with access to food. The first time a green light is turned on, the pigeon begins to peck at the key. This illustrates the process of__
a. Stimulus discrimination
b. Stimulus discrimination
c. Stimulus reinforcement
d. Observational learning
Hence the answer is option c Stimulus reinforcement.
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When the red light is on the pigeon does not peck on the disk and picks on green light, this demonstrates the concept of Stimulus reinforcement.
Stimulus reinforcement is a stimulation that strengthens or weakens the behavior that has produced it.
Reinforcement is an action to encourage something. Stimulus is something that produces a sensory or behavioral response in a species.
A Positive stimulus reinforcement is referring to the introduction of desirable stimulus. It makes the stimulus reinforcement more likely that the behavior will be reoccurring. For example, In a classroom, praises act like a reinforcement. When the red light is on the pigeon does not peck on the disk and picks on green light, demonstrating Stimulus Reinforcement.
Fantastic reinforcement refers to the introduction of a perfect and a quality stimulus after a conduction.
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Very low temperature molecular clouds emit most of their light in which part of the electromagnetic spectrum?
The radio region of the electromagnetic spectrum is where molecular clouds with extremely low temperatures emit the majority of their light.
To find the answer, we need to know more about the molecular clouds.
What is molecular clouds?Only within molecular clouds can stars actually form. Because the internal forces operating "outward" to prevent a collapse must be greater than the gravitational force acting to collapse the cloud, this is a natural result of their high densities and low temperatures.At 10 K, molecular clouds are extremely cold. Clouds that are diffuse are usually 100 K. Depending on the abundances of heavy elements that provide the cooling radiation, HII areas have T 8000 K.Thus, we can conclude that, the radio region of the electromagnetic spectrum is where molecular clouds with extremely low temperatures emit the majority of their light.
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B. the hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, how far does he travel while stopping? (2 points)
The hockey player is moving at a speed of 9. 5 m/s. if it takes him 2 seconds to come to a stop under constant acceleration, will be s = 9.5 m.
The branch of physics that defines motion with respect to space and time, ignoring the cause of that motion, is known as kinematics. Kinematics equations are a set of equations that can derive an unknown aspect of a body’s motion if the other aspects are provided.
These equations link five kinematic variables:
Displacement (denoted by Δx)
Initial Velocity v0
Final Velocity denoted by v
Time interval (denoted by t)
Constant acceleration (denoted by a)
These equations define motion at either constant velocity or at constant acceleration. Because kinematics equations are only applicable at a constant acceleration or a constant speed, we cannot use them if either of the two is changing.
v = u + at
0 = 9.5 + a (2)
a = - 9.5 /2 m/[tex]s^{2}[/tex]
[tex]v^{2}[/tex] = [tex]u^{2}[/tex] + 2as
0 = [tex](9.5)^{2}[/tex] + 2* (- 9.5 /2) * s
- [tex](9.5)^{2}[/tex] = - 9.5 s
s = 9.5 m
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Given two different resistances, how does the rate of joule heating in them differ if they are connected to a fixed voltage source in series and in parallel?
In series combination less rate of joule hating should be observed as compared to when connected in parallel combination .
Joule heating, also known as resistive, resistance, or Ohmic heating, is the process by which the passage of an electric current through a conductor produces heat.
Joule's first law states that the power of heating generated by an electrical conductor equals the product of its resistance and the square of the current:
When two or more resistors are connected end to end consecutively, they are said to be connected in series combination. The combined resistance of any number of resistances connected in series is equal to the sum of the individual resistances.
When two or more resistances are connected between the same two points, they are said to be connected in parallel combination. The reciprocal of the combined resistance of a number of resistances connected in parallel is equal to the sum of the reciprocals of all the individual resistances.
Rate of joule heating can be calculated by the formula
Power = [tex]V^{2}[/tex] / R
V = voltage
R = resistance
When both are connected in series than their equivalent resistance will be more as compared to when they are connected in parallel.
Power is inversely related to resistance , if voltage is constant
In series combination less rate of joule hating should be observed as compared to when connected in parallel
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A piano string of density 0. 005 0 kg/m is under a tension of 1 350 n. Find the velocity with which a wave travels on the string?
A piano string of density 0.005 0 kg/m is under a tension of 1350 N, then the velocity with which a wave travels on the string would be 519.61 m/s
What is a sound wave?It is a particular variety of mechanical waves made up of the disruption brought on by the movements of the energy. In an elastic medium like the air, a sound wave travels through compression and rarefaction.
As given in the problem a piano string of density 0.005 0 kg/m is under a tension of 1350 N,
V= √F/μ
V=√(1350/0.005)
V = 519.61 m/s
Thus, the velocity with which a wave travels on the string comes out to be 519.61 m/s
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Wolfgang pauli hypothesized an exclusion principle. This principle says two electrons in an atom cannot have the same what?.
No two electrons can have the same set of quantum numbers .
What is Wolfgang Pauli hypothesized an exclusion principle?Pauli made a significant advance when he proposed the notion of adding a fourth quantum number to the three that were previously used to represent the quantum state of an electron. Physically speaking, the first three quantum numbers made sense since they had to do with how the electron moved about the nucleus.
The following rule was developed by Austrian physicist Wolfgang Pauli. The quantum numbers of any two electrons cannot be identical.
To put it another way, no two electrons can be in the same state. The Pauli exclusion principle is the name given to this proposition since it forbids electrons from being in the same state.
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Explain the relation between Joule and Erg.
Answer:
Both erg and Joule are units of Energy in the CGS and S.I system respectively.
Joule and erg can also be written as (kg m2/s2) and (g cm2/s2) respectively.
Explanation:
1 Joule = 107 erg ⇒ 107 kg m2/s2.
==> One erg of energy is the amount of work done when one dyne of force acts through a distance of one centimeter.
==> One Joule of energy is the amount of work done when one Newton of force (100,000 dynes) acts through a distance of one meter (100 centimeters).
==> That makes one Joule the same amount of energy as 10 million (10⁷) dynes.
When unpolarized light is incident on a sheet of polarizing material with a transmission axis oriented vertically, what percentage of the light is transmitted through the material
Answer:
If the light were incident upon two polarizers at right angles, no light would get thru - thus each polarizer must block 50% of the light.
One polarizer would allow 50% of the light to pass.
An object weighs 7. 84 n when it is in air and 6. 86 n when it is completely immersed in water. what is the density of the object?
Answer:
The density of the object is 8000 kg/m^3
Explanation:
Weight in air = 7.84 n
Weight in water = 6.86 N
density of water = 1000 kg/m^3
Let d be the density of the object
According to the Archimedes principle, when a body is immersed in a liquid partly or wholly, it experiences an upward force which is called buoyant force. The buoyant force is equal to the loss in weight of the body.
Loss in weight of the object = Weight of object in the air - the weight of an object in the water
Loss in weight = 7.84 - 6.86 = 0.98 N
The volume of body x density of water x g = 0.98
Let V be the volume of the body
V x 1000 x 9.8 = 0.98
V = 10^-4 m^3
Weight in air = Volume of body x density of body x g
7.84 = 10^-4 x d x 9.8
d = 8000 kg/m^3
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The density of the object is ([tex]\rho_{ob}[/tex])= 80,000 [tex]kg/m^3[/tex]
How can we calculate the value of the density of the object?To calculate the density, we have to calculate the buoyancy force that the water exerts on the object. To calculate the buoyancy force we use the formula,
[tex]B= W_{air}- W_{water}[/tex]
Here we are given,
[tex]W_{air}[/tex] = The weight of the object in air = 7.84 N
[tex]W_{water}[/tex]= The weight of the object in water= 6.86 N
We have to calculate the buoyancy force =B
Now we put the known values in the above equation, we get
[tex]B= 7.84-6.86[/tex] = 0.98 N.
We know that the buoyant force depends on the volume of water displaced by the Volume of the object, so the formula stands,
[tex]B= \rho_{water} \times V_{ob}\times g[/tex]
Or, [tex]V_{ob}=\frac{B}{g\times \rho_{water}}[/tex]
Here we are given,
B= The buoyancy force = 0.98N.
[tex]\rho_{water}[/tex]= The density of water = 1000 [tex]Kg/m^3[/tex]
g= gravitational acceleration= 9.81[tex]m/s^2[/tex]
We have to calculate the volume of the object= [tex]V_{ob}[/tex]
Now we put the known values in the above equation, we get
[tex]V_{ob}=\frac{B}{g\times \rho_{water}}[/tex]=[tex]\frac{0.98}{9.81\times 1000}[/tex]=[tex]1.0\times 10^{-5} m^3[/tex].
So, now the volume of the object ([tex]V_{ob}[/tex])= [tex]1.0\times 10^{-5} m^3[/tex]
The weight of the object in the air can be calculated using the following formula, [tex]W_{ob}= m_{ob} \times g[/tex]
[tex]m_{ob}[/tex]=the mass of the object.
From this equation we can calculate the mass of the object,
[tex]m_{ob}=\frac{W_{ob}}{g}[/tex]= [tex]\frac{7.84}{9.81}[/tex]=0.80Kg.
(We know that the weight of the object in the air is the original weight of the object, so [tex]W_{ob} = W_{air}[/tex]=7.84N )
So, the mass of the object is ([tex]m_{ob}[/tex])= 0.80 Kg.
Now, let us consider the density of the object is [tex]\rho_{ob}[/tex]
From the definition of the density we can simply know that,
[tex]\rho_{ob}=\frac{m_{ob}}{ V_{ob}}[/tex]
Or,[tex]\rho_{ob}=\frac{0.80 }{1.0\times 10^{-5} }[/tex]
Or.[tex]\rho_{ob}=8\times 10^{4} Kg/m^3[/tex]
Or, [tex]\rho_{ob}=80,000 Kg/m^3[/tex]
From the above calculation we can define that the density of the object is 80,000 [tex]kg/m^3[/tex]
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The difference between the observed points and the regression line points is equal to the:________
The difference between the observed points and the regression line points is equal to the correlation.
The strength and direction of a relationship between two or more variables are described by the statistical measure of correlation, which is given as a number. However, a correlation between two variables does not necessarily imply that a change in one variable is the reason for a change in the values of the other.
Regression expresses the relationship as an equation, whereas correlation assesses the strength of the linear link between two variables. The square of the correlation coefficient, also known as Pearson's r, between the observed and predicted values in a regression is sometimes referred to as R2.
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Two skateboarders collide and grab onto one
another. The first skateboarder has a momentum of 525 kg • m/s, and the second skateboarder had a momentum of -576 kg•m/s immediately before they collide
The magnitude of their final momentum immediately after the collision is 51 Kgm/s and their direction immediately after the collision will be in the direction of the second skateboarder.
What is Momentum ?Momentum is the product of mass and velocity. Momentum can also be the product of force and time.
Given that two skateboarders collide and grab onto one another. If the first skateboarder has a momentum of 525 kg • m/s, and the second skateboarder had a momentum of -576 kg•m/s immediately before they collide, that means their collision was head - on - collision.
According to the conservation of linear momentum, the magnitude of the sum their final momentum immediately after the collision will be the same with the sum of the magnitude of their momentum before collision. That is,
Final momentum = 525 - 576
Final momentum = - 51kg•m/s
And their direction immediately after the collision will be in the direction of the second skateboarder.
Therefore, the magnitude of their final momentum immediately after the collision is 51 Kgm/s and their direction immediately after the collision will be in the direction of the second skateboarder.
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Answer:
-51
Explanation:
Khan Academy
A particle moving in a straight line with uniform deceleration has a velocity of 40m/s at point P, 20m/s at point Q
and comes to rest at point R where QR=50m .Calculate the
1.Distance PQ
2.Time taken to cover PQ
3.Time taken to cover PR
The distance between PQwill be 10,time taken to cover PQ will be 0.25sec and time taken to cover PR will be 3sec.
What is uniform deceleration?
Uniform deceleration is when velocity decrease by equal intervals of time .
Given ,
Velocity at P is 40 m/ s,
Velocity at Q is 20 m/ s
Distance between QR will be 50m.
let the whole distance between PR will be x,
so time taken of PQ, equating both times of PQ and QR we will get this,
x-50/40 = 50/ 20
after calculating ,
x = 60m , this the distance of whole straight line
60-50=. 10 m
the distance between PQ will be 10
2) time taken to cover PQ
. V= d/ t
t= 0.25s
3) time taken to cover PR
20=60/ t
t= 3sec.
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1. PQ=150m.
2. PQ: [tex]t=5s[/tex]
3. QR: [tex]t=5s[/tex]
What is velocity?The vector quantity velocity (v), denoted by the equation v = s/t, quantifies displacement (or change in position, s) over the change in time (t). Speed (or rate, r) is a scalar number, denoted by the equation r = d/t, that quantifies the distance traveled (d) over the change in time (t).
QR=50m.
[tex]V_{Q} (u)=20ms^{-1} ,V_{R} v[/tex]
[tex]v^{2} =u^{2}+2as[/tex]
[tex]0=20^{2} +2a*50[/tex]
100a=-400
[tex]a=-4ms^{-2}[/tex]
1. Distance PQ:
[tex]u_{p} (u)=40msx^{-1} , v_{Q (v)=20ms^{-1}[/tex]
[tex]v^{2} =u^{2} +2as[/tex]
[tex]20^{2} =40^{2} -2*4s[/tex]
400=1600-400
8s=1600-400
[tex]s=\frac{1200}{8} =150m[/tex]
PQ=150m
2.Time taken to cover PQ:
v=u+at
20=40-4t
4t=40-20
[tex]t=\frac{20}{4}=5s[/tex]
3. Time taken to cover PR:
v=u+at
0=20-4t
[tex]t=\frac{20}{4}=5s[/tex]
1. PQ=150m.
2. PQ: [tex]t=5s[/tex]
3. QR: [tex]t=5s[/tex]
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Mass m moves to the right with speed =v along a frictionless horizontal surface and crashes into an equal mass m initially at rest. upon colliding, the two masses stick together and move with speed v to the right. notice that v and v denote different speeds. after the collision the magnitude of the momentum of the system is:
After the collision the magnitude of the momentum of the system is Mv
Given:
mass of 1st object = M
speed of 1st object = v
mass of 2nd object = M
speed of 2nd object = 0
To Find:
magnitude of the momentum after collision
Solution: Product of the mass of a particle and its velocity. Momentum is a vector quantity; i.e., it has both magnitude and direction. Isaac Newton's second law of motion states that the time rate of change of momentum is equal to the force acting on the particle.
Applying conservation of linear momentum
Mv + M(0) = 2MV
Mv = 2MV
V = v/2
So, after collision momentum is
p = 2MV = 2xMxv/2 = Mv
So, after collision momentum is Mv
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What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C test charge placed here?
The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
Electric field on the master chargeE = kq/r²
where;
q is magnitude of master charger is distance of separationk is Coulomb's constantE = (9 x 10⁹ x 0.63)/(0.75²)
E = 1.008 x 10¹⁰ N/C
Force on the test chargeF = Eq
where;
E is electric fieldq is the test chargeF = (1.008 x 10¹⁰) x (0.5)
F = 5.04 x 10⁹ N
Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.
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Calculate the resistance 50 feet of awg no. 12 solid copper wire round to nearest 0. 01 ohms.
The resistance of the conductor is 0.07940 Ohms.
What is the relation between resistance and area of wire?The wire's resistance is inversely related to its cross-sectional area; as the area drops, so does the resistance.
and it is formulated as:
[tex]R=p\frac{l}{s}[/tex]
where,
p - resistivity of the conductor (0.0214-ohm mm²/m)
R - resistance
l- length of conductor (50 feet) (15.24 m)
s - the area of the wire
Thus the resistance can be calculated as
R = 0.07940 Ohms.
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why does mars jupiter and earth not have the same gravitational force on a 150kg object
According to the Newton's law of universal gravitation 2.4, the force between any more than two or three types of heavier mass which really involves with mass falling to the ground is proved by the distance, the mass's rotational speed and the rotating direction. It happens the changes in space and time, and also in the diameter of it's own mass.
A pump lifts 200 kg of water to a water tank placed at a height of 25m in 20 s. Find its power. g = 10 m/s² [Ans: 2500 W]
Answer:
2500W
Explanation:
P = W/t
As we know that
W = mgh
so:
P = mgh/t
put values
P = (200)(10)(25) / 20
P = 2500W
A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?
The sphere’s Electric potential energy is 1.6*[tex]10^{-6}[/tex]J
Given,
q=6. 5 µc, V=240 v,
We know that sphere’s Electric potential energy(E) = qV=6.5*[tex]10^{-6} *240[/tex]=1.6*[tex]10^{-6}[/tex]J
Electric potential energyThe configuration of a certain set of point charges within a given system is connected with the potential energy (measured in joules) known as electric potential energy, which is a product of conservative Coulomb forces. Two crucial factors—its inherent electric charge and its position in relation to other electrically charged objects—can determine whether an object has electric potential energy.
In systems with time-varying electric fields, the potential energy is referred to as "electric potential energy," but in systems with time-invariant electric fields, the potential energy is referred to as "electrostatic potential energy."
A tiny sphere carrying a charge of 6. 5 µc sits in an electric field, at a point where the electric potential is 240 v. what is the sphere’s potential energy?
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What was the possible impact of the maunder minimum on earth?
a) lower temperatures
b) higher temperatures
c) more hours of daylight
d) less hours of daylight
The possible impact of the maunder minimum on earth is a) lower temperatures
The Maunder Minimum, also known as the "prolonged sunspot minimum", was a period around 1645 to 1715 during which sunspots became exceedingly rare. During a 28-year period (1672–1699) within the minimum, observations revealed fewer than 50 sunspots.
The most recent grand solar minimum occurred during Maunder Minimum (1645–1710), which led to reduction of solar irradiance by 0.22% from the modern one and a decrease of the average terrestrial temperature by 1.0–1.5°C
During the Maunder Minimum, the Sun emitted less strong ultraviolet light, and so less ozone formed. The decrease in ozone affected planetary waves, the giant wiggles in the jet stream that we are used to seeing on television weather reports
correct option is
a) lower temperatures
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What theory of mercury's origin can best explain the fact that its core is made of such dense materials?
Answer:
Giant impacts in its early history may have torn away much of its original crust and mantle.
So Mercury has a giant iron core, but why?
There are three general ideas.
1. Mercury was once the core of a gas giant that vaporized when the Sun became a fully-fledged star. This gas giant was probably more like Uranus or Neptune than Jupiter or Saturn.
There are significant issues here, especially that Mercury's existing surface has been exposed to space since the solar system's initial beginnings. On Mercury, remnants of the first massive bombardment have been found.
2. Mercury formerly had a deeper mantle and was a bigger terrestrial planet. During the early history of the solar system, a dwarf planet made a massive impact that robbed the planet of its mantle.
The existing surface of Mercury has been exposed to space since the very beginning of the solar system, which raises major issues once more.
Due to the factors in explanation 1, characteristics from the first significant bombardment have been found on Mercury. The quantity of low temperature volatiles that are trapped and sometimes sublimate out of the crust, causing hollows, is also a major issue. By such an impact, these low temperature volatiles—such as sodium, sulphur, magnesium, etc.—would have been completely pushed out.
3. A mostly iron-rich body developed, and "rock steam"—a gaseous mixture of atomic oxygen and silica—condensed and accreted onto it from the protoplanetary disk near the Sun. Small rock particles with lower temperature volatiles were subsequently formed into a crust. Additionally, it appears that iron was concentrated in the inner region of the protoplanetary disk by the Sun's early, extremely powerful magnetosphere.
Whilst there are a few minor issues with this, this appears by far the most likely scenario.
Its crust and mantle may have been significantly altered during its early history by massive collisions.
What is Core?The extremely hot and dense core of Earth is called the core. Under the mainly solid mantle and the chilly, brittle crust is the ball-shaped core. The radius of the core is about 3,485 kilometers, and it can be located around 2,900 kilometers (1,802 miles) beneath the surface of the Earth (2,165 miles). Earth is more ancient than the core.
Approximately 4.5 billion years ago, Earth was a uniform ball of hot rock. The ball warmed up considerably more due to radioactive decay and residual heat during planetary formation. After roughly 500 million years, the temperature of our new planet reached 1,538 degrees Celsius (2,800 degrees Fahrenheit), which is the temperature at which iron melts. The iron catastrophe refers to this critical moment in Earth's history.
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Three resistors of 4. 0, 6. 0, and 10. 0 ω are connected in parallel. if the combination is connected in series with a 12. 0-v battery and a 2. 0-ω resistor, what is the current through the 10. 0-ω resistor
The current through the 10 Ω resistor is 0.586A which is connected with a resistor in series combination.
Voltage divides in a Series combination and current divides in a parallel combination.
Let the three resistors joined in parallel be R₁, R₂, R₃
where, R₁= 4 Ω
R₂ = 6 Ω
R₃ = 10 Ω
Given, a battery of 12V and a 2Ω resistor say r is series with the parallel combination.
Equivalent resistance(R) in parallel combination is:
1/R = 1/R₁ + 1/R₂ + 1/R₃
1/R = 1/4 + 1/6 + 1/10
On solving, R = 1.9 Ω
Now, the Equivalent resistance(R) of parallel combination is in series with r = 2Ω
Let Equivalent resistance of Series combination be R'
R' = R + r
R' = 1.9 + 2 Ω
R' = 3.9 Ω
Now let's calculate the voltage drop in the resistor r = 2Ω
v = i × r where, i is the current in r and v is the voltage drop across r
v = 3.07 × 2
v = 6.14V
Voltage drop, V' across the Equivalent resistance(R) in parallel combination = Total voltage - voltage drop in the resistor r
V' = 12 - 6.14 V
V' = 5.86V
Now, the Voltage drop, V' across the Equivalent resistance(R) in parallel combination is same for all the three resistors R₁, R₂, R₃
So, Voltage is same in a parallel combination.
V' = I × R₃
5.86 = I × 10
I = 0.586A
Hence, The current through the 10 Ω resistor is 0.586A
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A disk rotates with constant angular acceleration of 5. 45~\text{rad/s}^25. 45 rad/s 2. starting from rest, it turns through 220 rad. how much time elapses while it turns through the 220 radians?
The time elapsed is 8.98 sec when it turns through the 220 radians.
given:
initial angular velocity (ω°) = 0 rad/secangular acceleration (α) =5.45 [tex]rad/sec^{2}[/tex]total angular displacement (Ф) = 220 radusing second equation of motion for rotation
we get ,
[tex]220=0.t + \frac{1}{2}.5.45.t^{2}[/tex]
t^2 =80.98
t=8.98sec
therefore time elapsed is 8.98sec .
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A company has been hired to perform environmental remediation on an area of marshland. what would they most likely do? remove pollutants and use technology to monitor the health of the marshland install a new recycling plant in the area recommend burning the marshland and replanting it convert the marshland to residential areas
Answer:
answer is make marshland better
Explanation:
so if they made marshland better then as a result of that action of making marshland better then marshland would be better!
hopefully i helped dawg
A proton is placed in an electric field of intensity 800 n/c. what are the magnitude and direction of the acceleration of the proton due to this field? (e = 1. 60 × 10-19 c, mproton = 1. 67 × 10-27 kg)
The acceleration of the proton is 7.66*10^10m/s^2 in the direction of the electric field.
To find the answer, we have to know more about the electric field.
How to find the acceleration of the proton?We have the expression for electric field due to a accelerating particle as,[tex]E=\frac{F}{q}[/tex] , where q is the charge of the proton and F is the force.
We have the expression for force as,[tex]F=ma[/tex]
Combining both and rearranging, we get,[tex]ma=Eq\\\\a=\frac{Eq}{m} =\frac{800*1.60*10^{-19}}{1.67*10^{-27}} \\\\a=7.66*10^{10}m/s^2[/tex]
Thus, we can conclude that, the acceleration of the proton is 7.66*10^10m/s^2 in the direction of the electric field.
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